PHP - Warning: Implode() [function.implode]: Invalid Arguments Passed In

My error is 'Warning: implode() [function.implode]: Invalid arguments passed in /home/definiti/public_html/contact.php on line 73'

Im not sure how to fix this error, as I looked online and it says that my implode() has the right layout too it..

Line 73 in my code (I took the HTML code out) is this line;

Code: [Select]
$message = implode("<br>\n", $messages);

My whole code is;

Code: [Select]
<?php
# PHP Copyright 2007, Thomas Boutell and Boutell.Com, Inc.
# Edited by Definition Designs.

$recipient = 'defenitiondesigns@googlemail.com';
$serverName = 'www.definition-designs.co.uk';


if ($_POST['send']) {
sendMail();
} elseif (($_POST['cancel']) || ($_POST['continue'])) {
redirect();
} else {
displayForm(false);
}

function displayForm($messages)
{
global $login;
$escapedEmail = htmlspecialchars($_POST['email']);
$escapedRealName = htmlspecialchars($_POST['realname']);
$escapedSubject = htmlspecialchars($_POST['subject']);
$escapedBody = htmlspecialchars($_POST['body']);
$returnUrl = $_POST['returnurl'];
if (!strlen($returnUrl)) {
$returnUrl = $_SERVER['HTTP_REFERER'];
if (!strlen($returnUrl)) {
$returnUrl = '/';
}
}
$escapedReturnUrl = htmlspecialchars($returnUrl);
?>


<?php
    
if (count($messages) > 0) {
$message = implode("<br>\n", $messages);
echo("<h4>$message</h4>\n");
}
?>

<form method="POST" action="<?php echo $_SERVER['DOCUMENT_URL']?>">
<p>
<b>Your</b> Email Address   
<input
name="email"
size="35"
maxlength="35"
value="<?php echo $escapedEmail?>"/>
</p>
<p>
Your <b>Real</b> Name   
<input
name="realname"
size="35"
maxlength="35"
value="<?php echo $escapedRealName?>"/>

</p>
<p>
Subject Of Your Message   
<input
name="subject"
size="35"
maxlength="35"
value="<?php echo $escapedSubject?>"/>

</p>
<p>
<i>Please enter the text of your message in the field that follows.</i>
</p>
<textarea
name="body"
rows="10"
cols="60"><?php echo $escapedBody?></textarea>
<p>
<input type="submit" name="send" value="Send Your Message"/>
<input type="submit" name="cancel" value="Cancel - Never Mind"/>
</p>
<input
type="hidden"
name="returnurl"
value="<?php echo $escapedReturnUrl?>"/>
</form>

<?php
}

function redirect()
{
global $serverName;
$returnUrl = $_POST['returnurl'];
$prefix = "http://$serverName/";
if (!beginsWith($returnUrl, $prefix)) {
$returnUrl = "http://$serverName/"; 
}
header("Location: $returnUrl");
}

function beginsWith($s, $prefix)
{
return (substr($s, 0, strlen($prefix)) === $prefix);
}

function sendMail()
{
global $recipient;

$messages = array();

$email = $_POST['email'];
if (!preg_match("/^[\w\+\-\.\~]+\@[\-\w\.\!]+$/", $email)) {
$messages[] = "That is not a valid email address. In format: You@something.com";
}
$realName = $_POST['realname'];
if (!preg_match("/^[\w\ \+\-\'\"]+$/", $realName)) {
$messages[] = "The real name field must contain only alphanumeric characters, spaces and + or - signs.";
}
$subject = $_POST['subject'];
if (preg_match('/^\s*$/', $subject)) {
$messages[] = "Please specify a subject for your message.


";
}
$body = $_POST['body'];
        if (preg_match('/^\s*$/', $body)) {
$messages[] = "Your message was blank. Fill out a message or Click Cancel to cancel message.";
}
   if (count($messages)) {
displayForm($messages);
return;
}

mail($recipient, 
 $subject, 
 $body) or die("unable to send the mail!");
 
$escapedReturnUrl = htmlspecialchars($_POST['returnurl']);
?>

<form method="POST" action="<?php echo $_SERVER['DOCUMENT_URL']?>">
<input type="submit" name="continue" value="Click Here To Continue"/>
<input
type="hidden"
name="returnurl"
value="<?php echo $escapedReturnUrl?>"/>
</form>

<?php
}
?>

This topic has been moved to Third Party PHP Scripts.

http://www.phpfreaks.com/forums/index.php?topic=315384.0

I get this error on my homepage  :
Warning: implode() [function.implode]: Invalid arguments passed in /home/shqip1/peqini.com/wp-content/themes/sportpress/functions/wpzoom-widgets.php on line 1469

This is the code to modify

http://pastebin.com/RiBsyG3c



Thanks

Hi guys,

I have a problem with the print out method. I have got a warning implode, I have tried to get passed with the invalid arguments, but I keep getting this in nowhere I can find any situations.


however I am still getting this:

Warning: implode() [function.implode]: Invalid arguments passed in /home/mysite/public_html/mysite.com/members.php on line 82
Error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'where username='test' and passwd='test'' at line 1

here's line 82:


  if ($names = implode(',',$insert)) {


And here's the update code:


<?php
session_start();
    define('DB_HOST', 'localhost');
    define('DB_USER', 'myuser');
    define('DB_PASSWORD', 'mypass');
    define('DB_DATABASE', 'mydbname');

$errmsg_arr = array();
    $errflag = false;

    $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD);
    if(!$link) {

die('Failed to connect to server: ' . mysql_error());
    }

    $db = mysql_select_db(DB_DATABASE);
    if(!$db) {

die("Unable to select database");
    }

   function clean($var){

return mysql_real_escape_string(strip_tags($var));
    }
  $username = clean($_GET['user']);
    $password = clean($_GET['pass']);
    $firstname = clean($_GET['firstname']);  //variable in the url you posted was firstname, not value.
    $lastname = clean($_GET['lastname']);
    $email = clean($_GET['email_address']);
    if($username == '') {
  $errmsg_arr[] = 'username ID missing';
  $errflag = true;
    }
    if($password == '') {
  $errmsg_arr[] = 'PASSWORD ID missing';
  $errflag = true;
    }

    if($errflag) {
  $_SESSION['ERRMSG_ARR'] = $errmsg_arr;
  echo implode('<br />',$errmsg_arr);
   }
   else {
  $query  = "SELECT firstname, lastname, email_address FROM members WHERE username='$username' AND passwd='$password'";
  $result=mysql_query($query) or die('Error:<br />' . $qry . '<br />' . mysql_error());

while ($row = mysql_fetch_array($result)) { 
  echo "<p id='myfirstname'>";
  echo $row['firstname'] . "</p>";
  echo "<p id='mylastname'>";
  echo $row['lastname'] . "</p>";
  echo "<p id='email_address'>";
  echo $row['email_address'] . "</p>";
  }

  $qry="SELECT * FROM members WHERE username='$username' AND passwd='$password' AND firstname='$firstname' AND lastname='$lastname'";
  $result=mysql_query($qry) or die('Error:<br />' . $qry . '<br />' . mysql_error());

  if(mysql_num_rows($result) > 0) {
    $row = mysql_fetch_row($result);
  // echo "The information have already been updated in the database";
   }
  else {

if(isset($_GET['firstname'])) {
    $insert[] = 'firstname = \'' . clean($_GET['firstname']) .'\'';    
   }
  if(isset($_GET['lastname'])) {
    $insert[] = 'lastname = \'' . clean($_GET['lastname']) . '\'';
   }
  if(isset($_GET['email_address'])) {
    $insert[] = 'email_address = \'' . clean($_GET['email_address']) . '\'';
   }
  if ($names = implode(',',$insert)) {
  // $names = implode(',',$insert);
   }
  else {
   $sql="UPDATE members SET {$names} where username='{$username}' and passwd='{$password}'";
if (!mysql_query($sql,$link))
  {
  die('Error: ' . mysql_error());
  }
echo "The information have been updated";
  }
 }
}
?>



Can someone help me how to ignore the warning implode when I did not included the $name method??

Hello all

I've been using implode function of php and suddenly i encounter a problem regarding it..
Code: [Select]
<?php 
$insertValues[] = "(default,'{$y}', '{$p}', '{$o}', '{$i}', '{$u}','AMM-40','test')"; 

$query_status = "INSERT INTO `mobile1_mn1`.`logs_inbound` (`log_id`, `originator`, `sender`, `date`, `time`, `message`, `company_id`, `keyword`) VALUES". implode(',',$insertValues);
?>

When the information on $y,$p,$o,$i and $u does not have any single 'quotations' and commas it can save my information on database but when i have a string say for example the string is "he's good" and "Im, good" having a comma and quote it can't save my information anymore...

can someone tell me why i have this problem?

thanks in advance

Can  anyone help me complete this script I can get it working with using an implode function, but for the purpose of knowledge I want to not use it.

I just want it to echo back the corresponding checkboxes, but I can't get the echoing correct, it echoes back array not the value?

Code: [Select]
<html>
<title>What do you want on your Tombstone?</title>

<body>

<?php

$Output_form = true;
if (isset($_POST['submit'])) 
{
if (empty($_POST['toppings'])) 
{ 

echo '<b>You forgot the toppings for your Tombstone.</b>';
echo '<br>';
echo '<br>';

} else {

echo '<p><b>This is what you are getting on your Tombstone: ';
(array)$_POST['toppings'];
echo $toppings;
echo '!';
echo '</p></b>';
$Output_form = false;
}
}

if ($Output_form)
{ 
?>

<form action="ProcessToppings.php" method="post">
<p><i><h2>What do you want on your Tombstone?</h2></i></p>
<p>
<input type="checkbox" name="toppings[]" value="pepperoni" /> Pepperoni<br />
<input type="checkbox" name="toppings[]" value="sausage" /> Sausage<br />
<input type="checkbox" name="toppings[]" value="mushrooms" /> Mushrooms<br />
<input type="checkbox" name="toppings[]" value="cheese" /> Cheese<br />
<input type="checkbox" name="toppings[]" value="olives" /> Olives</p>
<p>
<input type="submit" value="Make that Peet-Za!" name="submit" /></p>

</form>

<?php 
} 

?>

</body>
</html>

Not sure if this is right.  I can't get it to insert my record.  Can someone please tell me if I'm doing it right?   cus_functions.php

function dbRowInsert($table_name, $form_data)
{
global $conn;
   
    $fields = array_keys($form_data);

    $sql = "INSERT INTO ".$table_name."
    (`".implode('`,`', $fields)."`)
    VALUES('".implode("','", $form_data)."')";

       return mysqli_query($sql);
}

process.php

 include("new_db.php");
 include("cus_functions.php");
 
 $do=$_GET['do'];
 
 if($do=='addpro'){
 
if(isset($_POST['submit'])){

$input = $_POST['title'];
$comp = '0';

$form_data = array('title' => $input, 'completed' => $comp);
 dbRowInsert('projects', $form_data);

}}

I am having trouble with passing the results of this first query into the next. I first query the db to get the sub id's that belong to the cat id coming through the url. This query gives me the correct results.

//query for subcat id

$var1_getCAT = "-1";
if (isset($_GET['cat'])) {
  $var1_getCAT = (get_magic_quotes_gpc()) ? $_GET['cat'] : addslashes($_GET['cat']);
}
mysql_select_db($database_conntest, $conntest);
$query_getCAT = sprintf("SELECT subs.subcat_id, subs.subcategory FROM subs WHERE subs.cat_id = %s ORDER BY subcat_id", GetSQLValueString($var1_getCAT, "int"));
$getCAT = mysql_query($query_getCAT, $conntest) or die(mysql_error());
$row_getCAT = mysql_fetch_assoc($getCAT);
$totalRows_getCAT = mysql_num_rows($getCAT);

Then, I use the array $subCATS in the next query to search the results that are in that array:

//set var for subs
$subCATS = array();
while ($row = mysql_fetch_assoc($getCAT)) {
$subCATS[] = $row['subcat_id'];
}
$subCATS = implode( ', ', $subCATS);


$query_rsSearch = "SELECT advs.adv_id, cinfo.c_id, FROM cinfo LEFT JOIN advs USING (adv_id) WHERE (cinfo.subcat_id IN ($subCATS) OR cinfo.subcat_id2 IN ($subCATS)) ORDER BY RAND()";

If I put exit in front of the second query, I see that the array is dropping the first result. For example, if the first query returns (2, 3, 4, 6, 9, 52), the value of the $subCATS array in the second query is only searching in (3, 4, 6, 9, 52).

I hope this makes sense. I am not sure why it would only drop the first result. I figured it would either work or not work, not just partially work - it has thrown my brain into a do while loop that is making me dizzy!  What am I doing wrong?

I keep getting the "Invalid arguments passed in..." error when trying to use implode. Here's the code:

Code: [Select]
$getPilots = "SELECT * FROM users WHERE emailOption = '1' AND status = '1'";
$runGetPilots = mysql_query($getPilots);
while ($info = mysql_fetch_array($runGetPilots)) {
$emails = $info['email'];
$to = implode(', ', $emails);
The ending bracket is there, i just didn't include it in the code. Any suggestions? Thanks.

when i echo count($words) it is 1.

 but when i print_r($itemid)   it displays this..  Code: [Select]
Array ( [2] => 17 [3] => 15 [4] => 17 )
when i count($words) it should echo 3.

Code: [Select]
print_r($itemid);
$words = implode(" ", $itemid);

echo count($words);

Hi All,

After a query runs, I want to grab the ID's and separate them with a comma because they will be used in the next query.  What I currently have does not work, although the query is correct.

Code: [Select]
$sql = "SELECT a.app_id FROM applications a LEFT JOIN tenants t ON a.app_id = t.app_id WHERE t.tenant_id IN (".implode(",", $checked).")";

$result = mysqli_query($connect, $sql);

$checked1 = array();

while($row = mysqli_fetch_array($result))
{
foreach($row['app_id'] as $value1) {$checked1[] = $value1;}
}

echo implode(",", $checked1);

I want to store an array in a mysql table.  all of the values in the array are numbers.
Should I serialize or implode?  What's the difference?
Thanks!

Hi All,
Just now I had a thought in mind for using regular expression in implode.
I know I can get the solution using foreach loop but just trying whether can we do it without using foreach.

I have an array

here I want  to create a table with array. I can do it using for or foreach loop but just a thought came in my mind doing it without using loop.


$arr = array(1,2,3,4,5);
echo "<table border='2'>";
echo "<tr>".implode("<td>[u]I WANT MY VALUES HERE[/u]</td>",$arr)."</tr>";
echo "</table>";


can we pass regular expression in implode() so that i will get record something like this
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
<td>5</td>

Code: [Select]
$birthday = implode(",",$_POST['BirthDay']);

$bday = array(
"1",
"2",
"3",
"4",
"5",
"6",
"7",
"8",
"9",
"10",
"11",
"12",
"13",
"14",
"15",
"16",
"17",
"18",
"19",
"20",
"21",
"22",
"23",
"24",
"25",
"26",
"27",
"28",
"29",
"30",
"31"
);
echo $birthday['0'];
exit;
//var_dump($colorarrays);
if (!in_array($birthday['0'], $bday)) {
message("Please select a Correct Birthday, or u trying to hack");
}
Okay, if I enter "55325" for my first birthday POST, it only shows "5"

and thus making the in_array not work correctly

how can i implode my data correctly ty