PHP - Problems Executing Multiple If Statements.

I'm tired and want to sleep so my mistakes are getting lots now. Anybody awake that can explain my problem with the code below. 

<?

function directoryToArray($directory, $recursive) {
        $array_items = array();
        $i = "0";
        if ($handle = opendir($directory)) {
                while (false !== ($file = readdir($handle)) && $i < "3") {
                        if ($file != "." && $file != "..") {
                                if (is_dir($directory. "/" . $file)) {
                                        if($recursive) {
                                                $array_items = array_merge($array_items, directoryToArray($directory. "/" . $file, $recursive));
                                        }
                        } else {
                                        $file = $directory . "/" . $file;
                                        $array_items[] = preg_replace("/\/\//si", "/", $file);
                                        $i++;
                                }
                        }
                }
                closedir($handle);
        }
        natsort($array_items);
        return array_reverse($array_items);
}
$data = directoryToArray('images/screenshot/', TRUE);
print_r($data);
?>


What I want is for the while loop to stop after 4 hits and exit and give me the return results. But now it continue until readdir end.

I am trying to use some php code inside of an html document and it does not work. I have a script.php file that executes perfectly when I try and use it. Here is the code I am currently using:

Code: [Select]
<?php
 echo "<title>";
 echo "the Homepage!";
 echo "</title>";
?>
Any suggestions would be great.

I have the following query where $userid is about 100,000 userids separated by commas.

Code: [Select]
<?
$getpostid=mysql_query("SELECT DISTINCT post.username,post.threadid,thread.threadid,thread.forumid from post,thread WHERE post.username='$username' AND post.threadid=thread.threadid AND post.userid IN ($userid) AND thread.forumid IN ($forumids)") or die (mysql_error());
?>can i just print all the usernames from above result separated by ';' without looping it multiple times?
 
Could someone help me out how to do above in an efficient manner?

Hi everyone,

I have a page that i use to upload images to my website, i got a bit fed up of uploading one at a time so i decided to add multiple file fields to the form to upload multiple images at the same time.

Im having a few problems, iv read up he http://www.php.net/manual/en/features.file-upload.multiple.php and it seems all i have to do is add [] to the form names to turn them into arrays. However when i come to upload the images, i keep getting the "$error[] = "Incorrect format!...." error from the code below. I cant seem to figure out what the problem is.

Could anybody please point me in the right direction?


<?php 
session_start();

$id = $_SESSION['id'];

$connect = mysql_connect("localhost","leemp5_admin","p7031521");
mysql_select_db("leemp5_database");

$query = mysql_query("SELECT * FROM users WHERE id='$id'");
$row = mysql_fetch_assoc($query);

$username = $row['username'];

$submit = $_POST['submit'];

$type = $_FILES['image']['type'];
$size = $_FILES['image']['size'];
$max_size = "1000"; 
$width = "100"; 
$height = "100";
 
$error = array();

function make_thumb($image_name,$filename,$new_width,$new_height) 
{

$ext=getExtension($image_name); 

if(!strcmp("jpg",$ext) || !strcmp("jpeg",$ext)) 

$source_image=imagecreatefromjpeg($image_name);   

if(!strcmp("png",$ext)) 

$source_image=imagecreatefrompng($image_name);

if(!strcmp("gif",$ext)) 

$source_image=imagecreatefromgif($image_name); 

$old_x=imageSX($source_image);

$old_y=imageSY($source_image);   

$ratio1=$old_x/$new_width; 

$ratio2=$old_y/$new_height; 

if($ratio1>$ratio2)

{ 

$thumb_width=$new_width; 

$thumb_height=$old_y/$ratio1; 

} 

else 

{ 

$thumb_height=$new_height;

$thumb_width=$old_x/$ratio2; 

} 
  

$destination_image=ImageCreateTrueColor($thumb_width,$thumb_height);   

imagecopyresampled($destination_image,$source_image,0,0,0,0,$thumb_width,$thumb_height,$old_x,$old_y);   

if(!strcmp("jpg",$ext) || !strcmp("jpeg",$ext))

{

imagejpeg($destination_image,$filename); 

}

if(!strcmp("png",$ext)) 

{

imagepng($destination_image,$filename); 

}

if(!strcmp("gif",$ext)) 

{

imagegif($destination_image,$filename); 

}

imagedestroy($destination_image); 

imagedestroy($source_image); 
}   


function getExtension($str)
{ 

$i = strrpos($str,"."); 

if (!$i) { return ""; } 

$l = strlen($str) - $i; 

$ext = substr($str,$i+1,$l); 

return $ext; 
}   

if($submit) 
{ 

$image=$_FILES['image']['name']; 

if ($image) 

{ 

$filename = stripslashes($_FILES['image']['name']);   

$extension = getExtension($filename); 

$extension = strtolower($extension); 

if (($extension != "jpg") && ($extension != "jpeg") && ($extension != "png") && ($extension != "gif"))

{ 

$error[] = "Incorrect format! Please make sure your image is a .jpg, .jpeg, .png or .gif file.";

} 

else

{ 

$size=getimagesize($_FILES['image']['tmp_name']); 

$sizekb=filesize($_FILES['image']['tmp_name']); 
  

if ($sizekb > $max_size*1024) 

{ 

$error[] = "Your image is too big! The maximum upload size is 1MB.";

}   

else

{

$image_name=time().'.'.$extension; 
 

$newname="uploads/" . $username . "/images/".$image_name; $copied = copy($_FILES['image']['tmp_name'], $newname); 

if (!$copied) 

{ 

$error[] = "There was an error uploading your image. Please try again!";

} 

else 

{ 

$thumb_name='uploads/' . $username . '/images/thumbs/thumb_'.$image_name; 
 

$thumb=make_thumb($newname,$thumb_name,$width,$height); 

}

}

}

}

else

{

$error[] = "Please select an image to upload!";

}

if(empty($error))

{

echo "Upload Successfully!<br />"; 

echo '<img src="'.$thumb_name.'">';

mysql_query("INSERT INTO images VALUES ('','$username','$image_name','','','','','uploads/$username/images/$image_name','uploads/$username/images/thumbs/thumb_$image_name','$type','$size')");

}

else

{
    

echo implode($error);

}
}
?>
<form method="post" enctype="multipart/form-data" action="upload_images.php">
<input type="file" name="image[]" /><br />
<input type="file" name="image[]" /><br />
<input type="file" name="image[]" /><br />
<input type="file" name="image[]" /><br />
<input type="file" name="image[]" /><br />
<input type="file" name="image[]" /><br />
<input type="submit" name="submit" value="Upload">
</form>


Thanks

OK, so I have the following file that has database functions:

<?php

function dbDelete($param){
$conDelete = mysql_connect($url,'username','password',true);
mysql_select_db('my_db',$conDelete);
mysql_query($param,$conDelete);
mysql_close();
   if(isset($conDelete)){
   mysql_close($conDelete);
   }
}
?>

I include the above file in a session handling file.  But for some reason the new file can't call the above function as follows:
<?php
include_once 'the above stated file';
function timeOut(){
        dbDelete("DELETE FROM acctussessi WHERE acctussessi_usid = '$sessius[0]'");
   $_SESSION = array();
   setcookie(session_name(),'',time()-4200);
   session_destroy();
}
//CHECK FOR TIMEOUT REQUEST
switch($_GET['xyz']){
   case 'timeout':
   timeOut();
   header("Location: /?xyz=timedout");
   break;
   case 'logout':
   timeOut();
   header("Location: /?xyz=loggedout");   
   break;
   case 'refresh':
   dbUpdate("UPDATE acctussessi SET acctussessi_time = ".time()." WHERE acctussessi_unid ='".$token."'");   
   break;
}
?>

dbDelete isn't being called inside of the TimeOut() function.  The only way it works is by doing the following:

<?php
function timeOut(){
   $_SESSION = array();
   setcookie(session_name(),'',time()-4200);
   session_destroy();
}
//CHECK FOR TIMEOUT REQUEST
switch($_GET['xyz']){
   case 'timeout':
      dbDelete("DELETE FROM acctussessi WHERE acctussessi_usid = '$sessius[0]'");
   timeOut();
   header("Location: /?xyz=timedout");
   break;
   case 'logout':
      dbDelete("DELETE FROM acctussessi WHERE acctussessi_usid = '$sessius[0]'");
   timeOut();
   header("Location: /?xyz=loggedout");   
   break;
   case 'refresh':
      dbUpdate("UPDATE acctussessi SET acctussessi_time = ".time()." WHERE acctussessi_unid ='".$token."'");   
   break;
}
?>
But this is annoying and repetitive.  What is going on?

Thanks in advance.

I am playing around with php but the script doesnt execute to the last point and with no error... 

 

What i am trying to do is checking the input of the user and comparing it what is in db and then applying conditions. So i have 2 files. update.php and home.php. 

home.php is my html form page and i included 'update.php' in it

In my update.php, i have these codes

 

<?php

error_reporting(E_ALL);


include_once('database.php');

if(isset($_POST['submit']))

{

$q = $_GET['q'];

$next = $q + 1;

if($q == 26)
{
echo '<h2>You have Completed the Exam.Congrats!!</h2>';


}
elseif($q <= 25){
    
$sql = "SELECT * FROM Students WHERE Email=?";
$stmt = $conn->prepare($sql); 
$stmt->bind_param('s', $_SESSION['login']);
$stmt->execute();
$result = $stmt->get_result(); $row = $result->fetch_assoc();

$Mark = $row['Mark'];


$Correct = $Mark + 1;


$Fail = $Mark + 0;

  
$sqlb = "SELECT * FROM Answers WHERE qid = ?";
$stmtb = $conn->prepare($sqlb); 
$stmtb->bind_param('s', $q);
$stmtb->execute();
$resultb = $stmtb->get_result();

$rowb = $resultb->fetch_assoc();

$Answer = $rowb['Answer'];

$Pick = $_POST['ans'];

if($Pick ==  $Answer)

{
  
  
    
  $sqld = "UPDATE Students SET Mark=? WHERE Email = ?";
$stmtd = $conn->prepare($sqld); 
$stmtd->bind_param('ss', $Correct,$_SESSION['login']);
$stmtd->execute();
$resultd = $stmtd->get_result();  


   echo "correct" ;
}

}
else

{
    
    echo 'Ate';
echo "<script type='text/javascript'>document.location.href='home.php?q='.$next.';</script>";
}

}//post submit

?>

The else statement doesnt run. so it keeps reloading the same page.   

  Also i want to ask why i keep getting the value of 2 for my $Correct variable stored on the database into column Mark for a single correct question instead of 1. What could be wrong?

Lastly, i dont want the script to run if the browser is edited by the user by changing the value of $q from the browser, because i am using get method, is there a way to do that.

Please be nice with your comments. Thanks in advance.!!!

Hey guys!
My current employer contracted someone to create a script for him. (The script itself is to create a serial number for a piece of software) It's just a PHP script that executes a file and retrieves its output.
Now I've never worked with exec() in PHP, and I don't have a reliable environment to test it in. I compiled apache2 and php 5.0.4 and set them to run on a Macintosh (10.3.9) in the office, but I'm sure I've missed some crucial setup stage (mainly, I'm missing php.ini. I did a php -i | grep php.ini to find it, and it says it is in /etc/, but when I look in my PHP/etc folder, only pear.conf is there!). PHP and apache both appear to be working fine, though.

When I try and run the PHP script that executes the .ELF file, I get a blank page. Is this because I'm running it in OS X?  should I be running it in Linux?
Also, I don't know how to Enable exec() on my server, or to see if it's enabled. Basically, I just need someone to walk me through the basics of this. The script and executable SHOULD work fine because the contractor got it working fine.
Below is the script, and attached is the executable.
Thanks! :3

<?php

/*
inUID = 456890
inSerialNumUID = 123456
inMachineID_s = &6dA-8P@K-Xsq
*/

$p1 = "456890";
$p2 = "123456";
$p3 = "\&6dA-8P@K-Xsq";

exec("./create_activation_code.elf $p1 $p2 $p3", $output);

foreach ($output as $output_str)
{
echo $output_str."<br>";
}

?>

Hey there, I recently started working on a PHP calculator, I tryed testing it out and the script is not executing... *NOTE* I found the error, I forgot to assign values to the options, all is good now

Code: [Select]
<?php
/*
Script Created by: Far Cry
Started: August 20th, 2010 10:51 PM PST
Completed
*/

$title = "Calculator";

$form = "<form action='calculator.php' method='POST'>
<table> 
    <tr>
    <td><input name='firstnumber' type='text'></td>
</tr>

<tr>
   <td><input name='secondnumber' type='text'></td>
</tr>

<tr>
   <td><select name='operation'>
       <option name='multiply'>*</option>
   </select></td>
</tr>

<tr>
<td><input name='submitbtn' type='submit' value='Calculate!'></td>
</tr>
</table>
</form>";


if ($_POST['submitbtn']){

$first = ($_POST['firstnumber']);
$last = ($_POST['secondnumber']);
$operation = ($_POST['operation']); 
}
if ($operation == 'multiply'){
echo"The answer is " . $first * $last . $form;
}
echo $form;
?>
Thanks in advance.

Hello,

PowerShell script stored locally can never be executed after I click on button:

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<title>Testing PowerShell</title>
</head>
<body>
<?php
 
// If there was no submit variable passed to the script (i.e. user has visited the page without clicking submit), display the form:
if(!isset($_POST["submit"]))
{
    ?>
    <form name="testForm" id="testForm" action="get-process.php" method="post" />
        Your name: <input type="text" name="username" id="username" maxlength="20" /><br />
        <input type="submit" name="submit" id="submit" value="Do stuff NowNew" />
    </form>
    <?php    
}
// Else if submit was pressed, check if all of the required variables have a value:
elseif((isset($_POST["submit"])) && (!empty($_POST["username"])))
{
   // Display the alert box 
   echo '<script>alert("Welcome to Geeks for Geeks")</script>';
   
   // Get the variables submitted by POST in order to pass them to the PowerShell script:
    $username = $_POST["username"];
    // Best practice tip: We run out POST data through a custom regex function to clean any unwanted characters, e.g.:
    // $username = cleanData($_POST["username"]);
         

$psPath = "C:\\Windows\\SysWOW64\WindowsPowerShell\\v1.0\\powershell.exe";
$psDIR = "C:\\TestNew\\";
$psScript = "pscripta.ps1";
$runScript = $psDIR. $psScript;
$runCMD = $psPath." ".$runScript." 2>&1"; 

echo "\$psPath  $psPath <br>";
echo "\$psDIR  $psDIR <br>";
echo "\$psScript  $psScript <br>";
echo "\$runScript  $runScript <br>";
echo "\$runCMD   $runCMD  <br>";

exec( $runCMD,$out,$ret);

echo "<pre>";
print_r($out);
print_r($ret);
echo "</pre>";

}
// Else the user hit submit without all required fields being filled out:
else
{
    echo "Sorry, you did not complete all required fields. Please go back and try again.";
}
?>
</body>
</html>

 

Thank you for your help!

Hi guys, im having a problem, in my phpfile were is generated the action code form the contacts form is giving me a lot of trouble, im receiving a lot of blank emails, first i thiked was bots,im usign a captcha, but then i notice another thing, when i put the name of the file that generates the action in the browser this loads it and send it the black email.
How can i prevent for my php action file to dont be loadit in the browser?
Here is the code to you guys have a idea

<?php 

$datahora = "DATA: <B>" . date("d/m/y - H:i:s") . "</B><BR><BR>";

foreach ($_POST as $campo => $valor) {
if (($campo == 'imageField2_x') or ($campo == 'imageField2') or ($campo == 'imageField2_y') or ($campo == 'distrito') or ($campo == 'subimit_y') or ($campo == 'codigo') or ($campo == 'seguranca')) {}else {
if ($valor <> '') {
$campo = str_replace("_", " ",$campo);
$campos .= strtoupper($campo) . ": <b>" . $valor . "</b><Br>";
}
}
}

  
$www = "WWW.USA.COM";
$assunto = "CONTACT - USA - " . $www;

$conteudo = "CONTACT - USA<br><br>" . $datahora . ($campos) . "<br>" . $www;

$para = "madness@hotmail.com";

$headers = "MIME-Version: 1.0\n"; 
$headers .= "Content-type: text/html; charset=iso-8859-1\n"; 
$headers .= "From: USA <info@usa.com>\r\n";
$headers .= "Reply-To: ".$_POST['email']."\r\n";

if ($_POST['codigo'] == $_POST['seguranca']) {
if (mail($para,$assunto,$conteudo,$headers) == true){ ?>

<script>
alert('Sent sucess!');
window.location = 'contact.php';
</script>
<? }} ?>



Hope for some help

Hi all,     This is just an experiment to make sure that I can get data from a Stored Proc 'IF' and when I need to, so it's basically a THOUGHT EXERCISE.   MSSQL 2014     I'm a noobie and need a hand, I've managed to get my Instance connected to the internet and I can query it using PHP and SQL, I can also look at views with no problem.     I have it working as an "ADODB.Connection" and like I said it connects and I can query data and display results.     Now I have coded a Stored Proc "GetMonthDays" in Sql Server:   Which returns days 1 through xxx in a given month and also returns the Day name  eg... Sat for each date     2014-01-01 Thurs   2014-01-02 Fri   etc...     It works perfectly and very fast so All cool with that side BUT...     I want to be able to query the Database through a Stored Proc, I've spent all day trying to find a way to get this to work and I've hit a wall   Can anyone please tell me IF it's A. possible and B. maybe if they are really really nice and share with me a code example that I can change to fit my needs ?     This T-SQL returns what it needs to     Begin
  EXEC dbo.qselGetMonthDays '2015-01-01'
  End
      Cheers     JD
Edited by juddadredd, 02 January 2015 - 04:55 PM.

hey guys im sure this is possible im wondering how a user can execute a mysql query by a click of a button but without the page reloading...thanks guys

Hi All

Basically I have 4 fields in my database

image2, image3, image4, image5

I have an image uploader to upload the files but I need what I need is if image2 is empty put in image3, if image3 is empty put in image4

so far I have this


//so first is the query to find the right row which gives the variable $row

//now here is what im doing

if($row['image2']!==""){
 //run this code
}

elseif($row['image3']!==""){
//run this code
}

elseif($row['image4']!==""){
//run this code
}

elseif($row['image5']!==""){
//run this code
}


Now the problem I'm having is the code that is always executing is the first one of $row['image2']

even if image2 has a value in the database it still runs that code and over writes the field in the database. It never moves on to field 3 or 4.  Can someone please tell me if I've done something wrong.


I'm not storing the image in the database just the name.

Thanks

Danny

   In my php web program I'm trying to execute a bash shell script on the web server passing to it some parameters gathered within the program.  Ideally I wouldl ike to run this script as another user.  However, I get only a return code of "1" and no other error messages that I can see.

I tried using system and passthru as well and I'm sure the script is executable by anyone.  I've also tried the sticky bit on the target shell script.

Can someone/anyone please provide some gotcha pointers about doing this?  As can be expected, after playing with this for a week now I'm extremely frustrated and nearly exhausted my resources (except for this forum).

Ideas/suggestions please?

Thanks 

In a PHP file [php_one.php], I wrote some PHP code that contained a form.  I used ECHO to write the HTML inside of the PHP tags.

On another PHP page [php_two.php], I wanted to show the code that was used to create the first page [php_one.php].

My first effort provided an interesting result, since the PHP code was readable.  However, all HTML code was visible in its executed form.

There was an actual input field and a submit button (not the code used to produce them) in the context of my coding.

I have tried using:

file_get_contents("FILE")
$array = file("FILE")
readfile("FILE")

All results were similar and carried the same problem.

How can I view code so that even the HTML is visible as code?