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PHP - How To Show Every Single Thang ??
Hay wut's happening forum?
so i am currently working on a mailing list and its function is to send EVERY single user a notification email once an entry they are looking for on a database is available below is the mailing_list.php which sets up database connection and deals with the fields of the table: <?php include('view_function.php'); global $connect; $connect = mysqli_connect("localhost", "", "") or die(mysqli_error($connect)); $error = mysqli_error($connect); $db_select = mysqli_select_db($connect, ""); $select5 = "SELECT LS_CELL_TYPE FROM link_specificities INNER JOIN links ON link_specificities.LS_LINK = links.L_ID WHERE links.L_ID = $LinkID"; $get5 = mysqli_query($connect, $select5) or die(mysqli_error($connect)); while ($row5 = mysqli_fetch_array($get5)){ extract($row5); $cellType = $row5['LS_CELL_TYPE']; } $select6 = "SELECT CT_NAME FROM cell_type WHERE CT_ID = '$cellType'"; $get6 = mysqli_query($connect, $select6) or die(mysqli_error($connect)); $i = 0; while ($row6 = mysqli_fetch_array($get6)){ extract($row6); $query[$i] = $row6['CT_NAME']; $check = "select first_name, email from mailing_list WHERE query = '$query[$i]'"; $i++; echo $query; } update($check); ?> And below is the view_function.php that's included above: <?php function update($check){ global $query; global $connect; global $LinkID; $result = mysqli_query($connect, $check) or die(mysqli_error($connect)); while ($row3 = mysqli_fetch_array($result)){ extract($row3); $fname = $row3['first_name']; $email = $row3['email']; $to = "$fname <$email>"; $subject = "The query is updated."; $headers = "From: asdfasdfasdf"; $body = " Hello $fname,\r\n\nThis is to inform you that $query is updated, please go to this link to search for it:\r\n\nhttp:/asdfasdfasdfasdf/view/View.php?LinkID=$LinkID \r\n\nRegards,\r\n\"; if(send_email($to,$subject,$body,$headers)){ //there are no errors, return empty array $errors = array(); } else { $errors[] = "Server error, mail could not be sent."; } } } ?> As you can c in mailing_list.php, i echoed out $query, but it only echoed ONE result of that entire array so wut i am trying to do is to make a while loop with a counter in it, but still only one result shows up Basically, i want the $query to output all items in an array so that following SELECT statement can choose the item which matches the required query and send the users the notification email bout such particular query How should i fix it in order to do just that? thanks Similar TutorialsPHP script return 20 UL LIST values like, < ul >
A < /ul > How to display UL LIST into row wise 5 columns like
A B C D Hi, I've been scratching my head for a while now about how to do this, I'm relatively new to php and mysql and perhaps foolishly taking on creating a user area for a website. I have everything else working, all of my register account functions and confirmations and all of the login scripts etc. I have created a profile page which returns various information to the user (this bit works fine) and I've got some nice show/hide toggles running with some javascript/css but my intention is to allow the user to change thier information (e-mail address, contact phone number and also whether they are subscribed to the e-mail list), it also displays any support tickets or messages. So after the long intro, here's what I'm struggling with... I have a form in a visibility toggled <div> which submits a 'change_email' script, so a user wants to change their e-mail, clicks on change, the <div> appears, they bang in the new e-mail and hit submit. My php script appears to work (because it doesn't throw up any errors), until you realise that actually it's not updated the record in the db... I'm using mysql_query("UPDATE users SET email='$new_email' WHERE username='$user'"); Do I need to setup variables for all of the information in the db (name, username, password, email, contno etc etc) and include them in the command to get it to work or should that just pick the correct record and then update it? If that is the case is there a way I can include 'blank' variables so I don't have to set them all up... e.g. mysql_query("UPDATE users SET user='',password='',email='$new_email', etc WHERE username='$user'"); Many thanks in anticipation I want to show a cookie of a referral's username on a sign up page. The link is like this, www.mysite.com/signup?ref=johnsmith. The cookie doesn't show if I go to that url page. But it does show up once I reload the page. So I'm wondering if it's possible to show the cookie the first time around, instead of reloading the page? Here is my code.
// This is in the header
$url_ref_name = (!empty($_GET['ref']) ? $_GET['ref'] : null);
if(!empty($url_ref_name)) {
$number_of_days = 365;
$date_of_expiry = time() + 60 * 60 * 24 * $number_of_days;
setcookie( "ref", $url_ref_name, $date_of_expiry,"/");
} else if(empty($url_ref_name)) {
if(isset($_COOKIE['ref'])) {
$user_cookie = $_COOKIE['ref'];
}
} else {}
// This is for the sign up form
if(isset($_COOKIE['ref'])) {
$user_cookie = $_COOKIE['ref'];
?>
<fieldset>
<label>Referred By</label>
<div id="ref-one"><span><?php if(!empty($user_cookie)){echo $user_cookie;} ?></span></div>
<input type="hidden" name="ref" value="<?php if(!empty($user_cookie)){echo $user_cookie;} ?>" maxlength="20" placeholder="Referrer's username" readonly onfocus="this.removeAttribute('readonly');" />
</fieldset>
<?php
}
I am displaying rows from a database onto a page using: while($row=mysql_fetch_array($query)){ echo $row['name']; } I need to figure out how to limit the rows shown to the page to 100. And if there are 100 rows on the page, a link will be displayed at the bottom, that says "Next 100". Then this will display the next 100 rows. Can you give an example how to do this please? Thanks Hi , I know my code sucks but i'm learning fast!! I'm trying to show a form if the qty value in a database == 10 or a different form if the value ==20. I tried but failed. Any help really appreciated. Code: [Select] <?php require_once('Connections/book.php'); ?> <?php $colname_cardpayment = "-1"; if (isset($_GET['orderid'])) { $colname_cardpayment = (get_magic_quotes_gpc()) ? $_GET['orderid'] : addslashes($_GET['orderid']); } mysql_select_db($database_book, $book); $query_cardpayment = sprintf("SELECT * FROM cards WHERE orderid = '%s' ORDER BY qty ASC", $colname_cardpayment); $cardpayment = mysql_query($query_cardpayment, $book) or die(mysql_error()); $row_cardpayment = mysql_fetch_assoc($cardpayment); $totalRows_cardpayment = mysql_num_rows($cardpayment); // Database connect $con = mysql_connect("mysql1.myhost.ie","admin_book","root123"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("book_test", $con); //Parse Values from Coupon.php Form $orderid = mysql_real_escape_string(trim($_POST['orderid'])); $name = mysql_real_escape_string(trim($_POST['name'])); $surname = mysql_real_escape_string(trim($_POST['surname'])); $add1 = mysql_real_escape_string(trim($_POST['add1'])); $add2 = mysql_real_escape_string(trim($_POST['add2'])); $town = mysql_real_escape_string(trim($_POST['town'])); $county = mysql_real_escape_string(trim($_POST['county'])); $postcode = mysql_real_escape_string(trim($_POST['postcode'])); $phone = mysql_real_escape_string(trim($_POST['phone'])); $email = mysql_real_escape_string(trim($_POST['email'])); $letterstyle = mysql_real_escape_string(trim($_POST['letterstyle'])); $sql="INSERT INTO custdetails (orderid, name, surname, add1, add2, town, county, postcode, phone, email, letterstyle) VALUES ('$orderid','$name','$surname','$add1','$add2','$town','$county','$postcode','phone','$email','$letterstyle')"; if (!mysql_query($sql)) { die('Error: ' . mysql_error()); } ?> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" /> <title>Digital Scribe Books</title> <link href="style.css" rel="stylesheet" type="text/css" /> <script type="text/javascript"> function MM_preloadImages() { //v3.0 var d=document; if(d.images){ if(!d.MM_p) d.MM_p=new Array(); var i,j=d.MM_p.length,a=MM_preloadImages.arguments; for(i=0; i<a.length; i++) if (a[i].indexOf("#")!=0){ d.MM_p[j]=new Image; d.MM_p[j++].src=a[i];}} } function MM_swapImgRestore() { //v3.0 var i,x,a=document.MM_sr; for(i=0;a&&i<a.length&&(x=a[i])&&x.oSrc;i++) x.src=x.oSrc; } function MM_findObj(n, d) { //v4.01 var p,i,x; if(!d) d=document; if((p=n.indexOf("?"))>0&&parent.frames.length) { d=parent.frames[n.substring(p+1)].document; n=n.substring(0,p);} if(!(x=d[n])&&d.all) x=d.all[n]; for (i=0;!x&&i<d.forms.length;i++) x=d.forms[i][n]; for(i=0;!x&&d.layers&&i<d.layers.length;i++) x=MM_findObj(n,d.layers[i].document); if(!x && d.getElementById) x=d.getElementById(n); return x; } function MM_swapImage() { //v3.0 var i,j=0,x,a=MM_swapImage.arguments; document.MM_sr=new Array; for(i=0;i<(a.length-2);i+=3) if ((x=MM_findObj(a[i]))!=null){document.MM_sr[j++]=x; if(!x.oSrc) x.oSrc=x.src; x.src=a[i+2];} } </script> </head> <body onload="MM_preloadImages('images/buttons/home_over.png','images/buttons/books_over.png','images/buttons/cards_over.png','images/buttons/letters_over.png')"> <div id="snow"> <div id="wrapper"> <div id="header"> <div id="logo"><img src="images/digital_scripe.png" width="218" height="91" /></div> <div id="menu"><a href="index.php" onmouseout="MM_swapImgRestore()" onmouseover="MM_swapImage('Home','','images/buttons/home_over.png',1)"><img src="images/buttons/home_act.png" name="Home" width="131" height="132" border="0" id="Home" /></a><a href="books.php" onmouseout="MM_swapImgRestore()" onmouseover="MM_swapImage('Books','','images/buttons/books_over.png',1)"><img src="images/buttons/books_act.png" name="Books" width="131" height="132" border="0" id="Books" /></a><a href="cards.php" onmouseout="MM_swapImgRestore()" onmouseover="MM_swapImage('Cards','','images/buttons/cards_over.png',1)"><img src="images/buttons/cards_act.png" name="Cards" width="131" height="132" border="0" id="Cards" /></a><a href="letters.php" onmouseout="MM_swapImgRestore()" onmouseover="MM_swapImage('Letters','','images/buttons/letters_over.png',1)"><img src="images/buttons/letters_act.png" name="Letters" width="131" height="132" border="0" id="Letters" /></a></div> </div> <div id="content"> <?php echo 'Order ID is : '. $orderid . '.<br />'; if ($row2['qty'] == 10) echo "<div> <form action="https://www.paypal.com/cgi-bin/webscr" method="post"> <input type="hidden" name="cmd" value="_xclick"> <input type="hidden" name="business" value="accounts@agraphics.ie"> <input type="hidden" name="lc" value="IE"> <input type="hidden" name="item_name" value="10 Christmas Cards"> <input type="hidden" name="item_number" value="<? echo $orderid; ?>"> <input type="hidden" name="amount" value="12.99"> <input type="hidden" name="currency_code" value="EUR"> <input type="hidden" name="button_subtype" value="services"> <input type="hidden" name="shipping" value="2.99"> <input type="hidden" name="return" value="http://www.digitalscribe/thanks.php"> <input type="hidden" name="bn" value="PP-BuyNowBF:btn_buynowCC_LG.gif:NonHosted"> <input type="image" src="https://www.paypalobjects.com/en_US/i/btn/btn_buynowCC_LG.gif" border="0" name="submit" alt="PayPal - The safer, easier way to pay online!"> <img alt="" border="0" src="https://www.paypalobjects.com/en_US/i/scr/pixel.gif" width="1" height="1"> </form> </div>"; if ($row2['qty'] == 20) echo "<div> <form action="https://www.paypal.com/cgi-bin/webscr" method="post"> <input type="hidden" name="cmd" value="_xclick"> <input type="hidden" name="business" value="accounts@agraphics.ie"> <input type="hidden" name="lc" value="IE"> <input type="hidden" name="item_name" value="20 Christmas Cards"> <input type="hidden" name="item_number" value="<? echo $orderid; ?>"> <input type="hidden" name="amount" value="21.99"> <input type="hidden" name="currency_code" value="EUR"> <input type="hidden" name="button_subtype" value="services"> <input type="hidden" name="shipping" value="2.99"> <input type="hidden" name="return" value="http://www.digitalscribe/thanks.php"> <input type="hidden" name="bn" value="PP-BuyNowBF:btn_buynowCC_LG.gif:NonHosted"> <input type="image" src="https://www.paypalobjects.com/en_US/i/btn/btn_buynowCC_LG.gif" border="0" name="submit" alt="PayPal - The safer, easier way to pay online!"> <img alt="" border="0" src="https://www.paypalobjects.com/en_US/i/scr/pixel.gif" width="1" height="1"> </form> </div>"; ?> </div> <div id="footer" class="clear"><div id="sign"><div id="sign_text">Personalised<br /> Books</div> </div></div> </div></div> </body> </html> <?php mysql_free_result($cardpayment); ?> Hi, I would like to do the following but not sure how. If the you/user is on index.php of http://www.domain.com/ show one page If not show another How would I do this? Thanks So I'm rebuilding an existing joomla component in laravel and this time I want to get it right. Hopefully my explanation is not too complicated.
I have this situation:
I have an order. The order has many products. The product has many parameters in the form of input fields such as radio, select list and text (think of color, size, engraving, logo select). An order also has some parameters such as address etc.
My question is how I should structure this considering the following:
1. The parameters of either an order itself or a product can change from time to time. Sometimes I need to add several fields for a certain amount of time.
2. Each product has 1 or more production pages (production steps) where some of the parameters set by the order need to be visible. Each production step has its own set of parameters (3d model, logo file). This means that the step1 page should show its own parameters INCLUDING a predetermined set of product parameters. So the columns could look like this: color - engraving - logo select - 3d model - logo file.
3. Each production page lists all the products belonging to that step.
4. Each product can belong to 1 or more production steps.
5. A product is only visible at 1 step at a time. The steps have a specific ordering.
A little note: it's not a usual webshop, but rather we sell custom sports products. Currently we have 3 products where 1 product has 2 production steps and another has 3 production steps.
Don't get me wrong, I have a working application for this, but currently it's just a database mess. The application kept growing as per bosses request so thinking it through was not possible at the time.
Hi, I'm trying to delete a string that's single quoted. From: Cyto's to Cyto, but doesn't work. It works when I add 's to the string with stripslashes, but I can't seem to delete a quote from a string. Does someone know how? My $_post code: Code: [Select] $name=mysql_real_escape_string(stripslashes($_POST["ename"])); Cheers How to pull just I record of a column out of the 20 columns? This is not showing the results. $SomeVar = 'pets'; $query = "SELECT field1 FROM db1 WHERE id1 = '".$SomeVar."'"; $results=mysql_query($link); echo $link; I was talking to some friends, who are just as new as me in programming, and they think it would be better to use a single navigation file for every link in a web site. Something like this: Code: [Select] <a href="nav.php?id=home&otherparams" >Home</a> <a href="nav.php?id=products&otherparams" >Products</a> <a href="nav.php?id=contact&otherparams" >Contact</a> I told them I think this might be easier to maintain, but also might take up on loading time, as the site viewer will have to go through an extra node to get where he wants. Is this single navigation file a good practice or should it be avoided? Thanks for any comments... Greetings, I'm trying to execute a shell command with a user-supplied password as input. The password may contain apostrophes and and virtually any other character. Unfortunately, when using escapeshellarg(), the password argument is interpreted as two separate arguments, as escapeshellarg() will handle apostrophes (single quotes) by breaking out of the already quoted text and using a backslash escape. $password = escapeshellarg("ex'ample!%"); // The password will actually be supplied by an HTML form. $command = ('echo '.$password); echo "$command"; // Returns 'ex'\''ample!%' Does anyone have any input on how to accomplish what I'm trying to do? I'd like to allow obscure passwords without disallowing specific characters, while still being "safe" in passing the information to a shell command. Double quotes would work for passing single quotes, but I'm afraid I might break other characters there. Thanks. I can use the first while loop, but there is no data in the second while loop. Is there a better way as I have never done this before... Code: [Select] <?php $featured_results = mysql_query("SELECT * FROM products LEFT JOIN product_images ON products.product_id=product_images.product_id WHERE products.product_featured='1' AND products.product_active='1' AND thumb='1'"); $fa=0; while($featured_row = mysql_fetch_assoc($featured_results)) { $fthumb_result = mysql_query("SELECT image_name FROM product_images WHERE product_id='".$featured_row['product_id']."' AND thumb='1'"); $fthumb = mysql_fetch_row($fthumb_result); if ($fa==0) { echo "\n<img id=\"home-slider-photo-".$fa."\" class=\"home-slider-photo preload\" src=\"/includes/getimage.php?img=".$fthumb[0]."&w=370&h=370\" alt=\"\" />"; } else { echo "\n<img id=\"home-slider-photo-".$fa."\" class=\"home-slider-photo preload home-slider-photo-unsel\" src=\"/includes/getimage.php?img=".$fthumb[0]."&w=370&h=370\" alt=\"\" />"; } $fa++; } echo "<div id=\"home-slider-photo-price\">"; $fb=0; while($featured_row2 = mysql_fetch_assoc($featured_results)) { if ($fb==0) { echo "\n<div id=\"home-slider-photo-price-".$fb."\" class=\"home-slider-photo-price\">\n<span>only</span>$".$featured_row2['product_price']."\n</div>"; } else { echo "\n<div id=\"home-slider-photo-price-".$fb."\" class=\"home-slider-photo-price home-slider-photo-price-unsel\">\n<span>only</span>$".$featured_row2['product_price']."\n</div>"; } $fb++; } echo "</div>"; ?> how do I call only a single column in a MySQL? This is not working. $SomeVar = $_POST['finco']; $query = "SELECT * FROM idb WHERE name = '".$SomeVar."'"; $results = mysql_query($query); $psend = $results["fincos"]; echo($psend); Hi, learning as I go here, and I appreciate the help in advance .. I have some working php code that retrieves sql results using php. I assign the resutls to an array by doing this $bobreport = array(); while ($row=db2_fetch_array($querystmt)) { array_push($bobreport, $row); } i can then write the rows of returned data after some column headers using this... foreach ($bobreport as $value) { echo "<tr><td>$value[0]</td><td>$value[1] ..... } The particular report I'm working on now has a redundant date and time in every row that I omit in the foreach loop because I just want to show it once above the table somewhere. This doesn't seem to work in accomplishing that... echo "This data was updated ".$bobreport[0][9]." at ".$bobreport[0][10] ; All I seem to get in the report is "This data was updated at". Please help. Greetings, I'm looking for a way to pass a query string (from page1) as part of a query string (to page2) as a single key=>value pair. The idea is the use the query string to return the user to the previous page after the action has been completed. query results[page1]->view record/action selection[page2]->back to results[page1] I'm sure someone has been down this path before. P.S. the script is all contained within one file, thus the filename.ext is already known. Thanks Hi all, Just to check if it is possible to have 2 while loops in a single code? Below are my codes. SQL code $tutor_id = mysqli_real_escape_string($dbc, $_GET['tutor_id']); $query = "SELECT tl.level_id, tl.level_name, ts.subject_id, ts.subject_name, tsl.subject_level_id, IF(tosl.tutor_id='{$tutor_id}', 1, 0) as checked FROM tutor_level AS tl INNER JOIN tutor_subject_level AS tsl USING (level_id) INNER JOIN tutor_subject AS ts USING (subject_id) LEFT JOIN tutor_overall_level_subject AS tosl ON tosl.subject_level_id = tsl.subject_level_id AND tosl.tutor_id = '{$tutor_id}' ORDER BY tl.level_id, ts.subject_name"; $sql = mysqli_query($dbc, $query) or die(mysqli_error($dbc)); $query1 = "SELECT tl.level_id, tl.level_name, IF(tslvl.tutor_id='{$tutor_id}', 1, 0) as checked FROM tutor_level AS tl LEFT JOIN tutor_selected_level AS tslvl ON tslvl.level_id = tl.level_id AND tslvl.tutor_id='{$tutor_id}' ORDER BY tl.level_id, tl.level_name"; $sql1 = mysqli_query($dbc, $query1) or die(mysqli_error($dbc)); PHP code (2 while loops) //Process the results $checkboxes = ''; //Create variable for output $current_level_id = false; //Flag to check when records change level while($data = mysqli_fetch_array($sql)) //Iterate throug the DB results { if($current_level_id != $data1['level_id']) //Determine if this level is different from the last { print_r ($data); $checkboxes .= createLevelCheckboxes($subject_data, $level_data, 5); $current_level_id = $data['level_id']; $subject_data = array(); } //Add the current record to the $level_data array $subject_data[] = $data; } //$checkboxes .= createLevelCheckboxes($subject_data, $level_data, 5); while($data1 = mysqli_fetch_array($sql1)) { print_r ($data1); $checkboxes .= createLevelCheckboxes($subject_data, $level_data, 5); $level_data = array(); $level_data[] = $data1; } //Call the createLevelCheckboxes() function to generate the HTML for the LAST level records $checkboxes .= createLevelCheckboxes($subject_data, $level_data, 5); I want to use all five results separately in order to use in a Jquery slider. Code: [Select] <?php $a = "SELECT * FROM blog_posts ORDER BY id DESC LIMIT 5"; $query = mysql_query($a) or die (mysql_error()); $query_results = mysql_fetch_array($query); ?> I know if i was going to grab vars from an normal array i would just use... Code: [Select] <?php echo $array_reults['0'] ?> Can any one help me with this problem? Hello, I have a simple multiple-step form and I use sessions to save the data. Now i have 1 single checkbox and i would like to know how i can save that data (if one checked it or not). I am not very advanced with sessions, nor PHP, thus i tried the following: Code: [Select] if (isset($_POST['newsletter'])) { $_SESSION['newsletter']=$_POST['newsletter']; } $newsletter = $_SESSION['newsletter']; // do not really know what if statement to use if($newsletter == 'yes') { $newsl = '1'; } //checkbox html here <input type="checkbox" class="styled" name="newsletter" value="yes" /> Obviously the above won't work. Can explain to me how to save checkbox data in a session? Thanks a lot in advance. Hi All Sorry my first post is a help one... I'm developing a small fault logging application I need a little help with. This is my code at the moment Client Table Columns contractid, company, branch, addressline1, addressline2, addressline3, addressline4, postcode, contactname, telephone, email Addressbook2 Table Columns nameid, namecompany, namecontactname, nameaddressline1, nameaddressline2, nameaddressline3, nameaddressline4, namepostcode, nametelephone1, nametelephone2, nameemail, <?php $NodeTitles = mysql_query("SELECT * FROM faults, users, clients, addressbook2 WHERE faults.client = clients.contractid AND faults.referredby = addressbook2.nameid AND faults.openedby = users.userid ORDER by dateopened DESC, timeopened DESC") or die (mysql_error()); while ($row = mysql_fetch_assoc($NodeTitles)) { ?> <tr id="entryRow2358" onMouseOver="this.style.cursor='pointer'" onclick="window.location.href='job.php?faultid=<?php echo $row['faultid'];?>';"> <td class="n" colspan="1"><div title=""><?php echo $row['faultid'];?></div></td> <td class="" colspan="1"><div title="Company"><?php echo $row['clientcompany'];?></div></td> <td class="" colspan="1"><div title="Referrer"><?php echo $row['referrercompany'];?></div></td> <td class="" colspan="1"><div title="Branch"><?php echo $row['clientbranch'];?></div></td> <td class="" colspan="1"><div title="Fault"><?php echo $row['fault'];?></div></td> <td class="" colspan="1"><div title="Opened By"><?php echo $row['fullname'];?></div></td> <td class="" colspan="1"><div title="Date Created"><b><?php $date = date_create($row['dateopened']); echo date_format($date, 'j F Y');?></b> <span><?php echo $row['timeopened'];?></span></div></td> </tr> <?php } ?> QUESTION TIME I want to make this much cleaner and tidier (and also more future proof) by removing the clients table so that I only have one 'addressbook' (this will contain clients, referrers, engineers ... and any other correspondents) Naturally I will have a column in the address book to tell me what type of correspondent the name is. ie. 1 = Client, 2 = Referrer, 3 = Engineer. So.......will I have to do many MYSQL queries within a while statement or will I be complicating the entire process by doing this? Can I write a single SQL statement to do this? Any advise or help with my code would be great! Thanks Andrew Could somebody please point me in the right direction.... I want to block the US, AUS, NZ, CAN, IRE from the index.php of my site. But not the rest of the site. The following site (like many others) provides a pretty neat list for the htaccess http://www.ipinfodb.com/ip_country_block.php I did a test. I got the list for blocking the UK. After copying the UK list to my htaccess i couldn't view my site. The thing i don't get is... my ip address was not in the list but i was still blocked, The 1st 2 sets from my ip are '2.100' The only ip's in the list starting with 2 a deny from 2.24.0.0/13 deny from 2.96.0.0/13 deny from 2.120.0.0/12 deny from 2.136.0.0/13 How exactly is this all working? And what's the best way of blocking the above countries from just my index.php? Any links to manuals or anything here would be great... Thank You. John |
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