PHP - Trouble Using Insert Into
Hi all
I'm working on a form, i've gotten all the values from the form to the process.php page and it is assigning the correct variables but i can't get it to insert into the database, i know the connection info is correct as i have other page connecting and i can create a recordset on that page. i guess my sql is wrong any help much appreciated. the following is the sql from the database and attached is the process.php page. -- Table structure for table `details` -- CREATE TABLE `details` ( `id` int(6) NOT NULL auto_increment, `first_name` varchar(20) NOT NULL, `sur_name` varchar(20) NOT NULL, `sex` varchar(6) NOT NULL, `age` varchar(3) NOT NULL, `house_no` varchar(5) NOT NULL, `street` varchar(150) NOT NULL, `town` varchar(50) NOT NULL, `bro_sis_cous_friend1` varchar(50) default NULL, `bscf_name1` varchar(150) default NULL, `and` varchar(4) NOT NULL, `bro_sis_cous_friend2` varchar(50) default NULL, `bscf_name2` varchar(150) default NULL, `his_her` varchar(4) default NULL, `him_her` varchar(4) default NULL, `from_name` varchar(150) NOT NULL, `photo_link` varchar(255) default NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=36 ; [attachment deleted by admin] Similar Tutorialscould someone help me with this. here is what I have: <?php require_once('dbinfo.php'); ?> <?php mysql_connect($dbaddress,$username,$password); mysql_select_db($db) or die("Cannot find database!"); /* $query = "SELECT * FROM contacts"; $result = mysql_query($query); $numRows = mysql_numrows($result); $i = 0; while ($i < $numRows) { echo mysql_result($result, $i, "first") . " " . mysql_result($result, $i, "last"); $i++; } */ $fname = 'WrdScramble()'; $ftype = 'DAO'; $fdesc = 'Randomly rearranges the characters in a string or word.'; $fcode = ''; $query = "INSERT INTO functions VALUES ('','$fname','$fcode','$ftype','$fdesc')"; mysql_query($query); print($query); //$query = "SELECT fcode FROM contacts WHERE first = 'code'"; //$result = mysql_query($query); //$numRows = mysql_numrows($result); //$fcode = mysql_result($result, 0, "fcode"); ?> <? //close connection mysql_close(); ?> It is not inserting the data into the database, and if I use: mysql_error() and print it out, I get nothing with that either. I am not sure where to go! I also have used this: (fid, fname, fcode, ftype, fdesc) preceeding the 'VALUES' word in the statement just to see if it would take. No luck! Do I not see the obvious? Any help appreciated! thanks! (I have checked my field types and max length in PHPmyadmin and they are not an issue.) I am trying to create a query to insert data into a table in my Access database. I have the following query:
INSERT INTO Issues (DateRequested, CustomerID, ComputerID, Issue, ItemsIncl, ImageName) VALUES (#1/14/2015#, 1, 1, "Computer freezes while I'm on the internet.", "AC Adapter", "none.gif")which should be performed from within my PHP page. However, when I check the database afterward, the new record isn't there. I then tried performing the query directly in Access and it worked fine. Why would it work in Access, but not when I run the same query in PHP? Chris I want to remove the HTTP:// or HTTPS:// from the insert into the DB. The Viewer may put just www, or copy the entire URL with the HTTP:// or HTTPS://
I tried using the preg-replace but couldn't seem to get it to work.
Any other recommendation?
Thanks in advance,
Mike
I'm missing something here. I have a form, and when the submit is pressed, the relevant post data inserts into table one, then I want the last insert id to insert along with other form data into a second table. The first table's still inserting fine, but I can't get that second one to do anything. It leapfrogs over the query and doesn't give an error. EDIT: I forgot to add an error: I get: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'usage, why VALUES ('14', '', '123', '','1234', '', '')' at line 1 query:INSERT INTO tbl_donar (donar_fname, donar_name, donar_address, donar_address2, donar_city, donar_state, donar_zip, donar_email, donar_phone, donar_fax, donar_company) VALUES ('test 14', 'asdfa', 'asdf', 'adf','asdf', '', '', '', '123', '', '') Code: [Select] if (empty($errors)) { require_once ('dbconnectionfile.php'); $query = "INSERT INTO tbl_donar (donar_fname, donar_name, donar_address, donar_address2, donar_city, donar_state, donar_zip, donar_email, donar_phone, donar_fax, donar_company) VALUES ('$description12', '$sn', '$description4', '$cne','$description5', '$description6', '$description7', '$description8', '$description9', '$description10', '$description11')"; $result = @mysql_query ($query); if ($result) { $who_donated=mysql_insert_id(); $query2 = "INSERT INTO tbl_donation (donor_id, donor_expyear, donor_cvv, donor_cardtype, donor_authorization, amount, usage, why) VALUES ('$who_donated', '$donate2', '$donate3', '$donate4','$donate5', '$donate6', '$donate7')"; $result2 = @mysql_query ($query2); if ($result2) {echo "Info was added to both tables! yay!";} echo "table one filled. Table two was not."; echo $who_donated; //header ("Location: http://www.twigzy.com/add_plant.php?var1=$plant_id"); exit(); } else { echo 'system error. No donation added'; Can anyone tell me why this is not INSERTing? My array data is coming out just fine.. I've tried everything I can think of and cannot get anything to insert.. Ahhhh! <?php $query = "SELECT RegionID, City FROM geo_cities WHERE RegionID='135'"; $results = mysqli_query($cxn, $query); $row_cnt = mysqli_num_rows($results); echo $row_cnt . " Total Records in Query.<br /><br />"; if (mysqli_num_rows($results)) { while ($row = mysqli_fetch_array($results)) { $insert_city_query = "INSERT INTO all_illinois SET state_id=$row[RegionID], city_name=$row[City] WHERE id = null" or mysqli_error(); $insert = mysqli_query($cxn, $insert_city_query); if (!$insert) { echo "INSERT is NOT working!"; exit(); } echo $row['City'] . "<br />"; echo "<pre>"; echo print_r($row); echo "</pre>"; } //while ($rows = mysqli_fetch_array($results)) } //if (mysqli_num_rows($results)) else { echo "No results to get!"; } ?> Here is my all_illinois INSERT table structu CREATE TABLE IF NOT EXISTS `all_illinois` ( `state_id` varchar(255) NOT NULL, `city_name` varchar(255) NOT NULL ) ENGINE=MyISAM DEFAULT CHARSET=latin1; Here is my source table geo_cities structu CREATE TABLE IF NOT EXISTS `1` ( `CityId` varchar(255) NOT NULL, `CountryID` varchar(255) NOT NULL, `RegionID` varchar(255) NOT NULL, `City` varchar(255) NOT NULL, `Latitude` varchar(255) NOT NULL, `Longitude` varchar(255) NOT NULL, `TimeZone` varchar(255) NOT NULL, `DmaId` varchar(255) NOT NULL, `Code` varchar(255) NOT NULL ) ENGINE=MyISAM DEFAULT CHARSET=latin1; Hello, I'm having a bit of a problem here, all help to this issues would be much appreciated I am trying to use text boxes to insert numbers into the database based on what is inputed. If I have a string, like this for example: $variable = 09385493; And I want to insert it into the database like this: mysql_query("INSERT INTO integers(number) VALUES ('$variable')"); When checking the integers table in my database, looking at the number field, the $variable that was inserted is outputted as 9385493 Notice the number zero was taken out of the front of the number. If the number is double 0's (009385493), both of those zero's would disappear, too. Thanks Hi Chaps, I have a PHP FTP App, where users can log in using a unique code and a password. Their unique code corresponds to an FTP folder, e.g. Quote \FTP_Root\Customer A & Co\ So when the user logs in, they can see their FTP directory and contents, in this case an Inbox and an Outbox. This works as the FTP folder contains both an Inbox and an Outbox. The problem I am having is when I try browsing within this directory (say the Inbox), ftp-chdir fails. I have a hyperlink that sends a 'dir' parameter to the same ftp.php page, and if set, will attempt to change to the given directory. So even though the URL Hyperlink reads: Quote ....server.co.uk/ftp.php?dir=/FTP_Root/Customer A & Co/Inbox When you click on this link, the page tries to load: Quote ....server.co.uk/ftp.php?dir=/FTP_Root/Customer A So my question is what do I need to change, the Hyperlink to read something like: Quote ....server.co.uk/ftp.php?dir=/FTP_Root/Customer%20A%20&%20Co/Inbox Do something to the ftp-chdir function, where I encode/decode/whatever to make sure it tries to change to the correct FTP directory? Or exclude all ampersand entirely? Building a website for work. I am struggling with the login for some reason. I`m using a lot of the same code as I did for my personal site and a few other websites I`ve programmed which has always worked. But for some reason, it isn`t working now. I`ve already told it to display to me the information that`s being processed and that is all correct (it even updates the database like it`s supposed to). It just won`t show the person being logged in, which defeats the purpose of logging in, yanno? Here are all the files in question. login.php <?php include "file_calls.php"; $title = "Business Name (Beta): Log In"; include "functions.php"; session_start(); echo "$title"; echo "<p>"; echo "Log into the Business Name website. Only authorized members of the Business Name Staff can log into the website."; echo "<p>"; include "login_form.php"; ?> login_form.php <?php echo "<form action='logging.php' method='post'>"; echo "E-Mail Address:"; echo "<br><input type='text' name='email' size=60 maxlength=100>"; echo "<p>"; echo "Password:"; echo "<br><input type='password' name='pass' size=60 maxlength=25>"; echo "<p>"; $buttonlabel = "Log In"; include "formbutton_format.php"; echo "</form>"; ?> logging.php <?php include "file_calls.php"; $title = "Business Name (Beta): Logging In"; include "functions.php"; session_start(); echo "$title"; echo "<p>"; echo "Logging into the Business Name website. Only authorized members of the Business Name Staff can log into the website."; echo "<p>"; $email = $_POST['email']; $pass = $_POST['pass']; $entry_date = strftime("%B\ %e\,\ %Y %I:%M:%S %p", time()); $res = mysql_query("SELECT id, memlev, pwd1, pwd2, email, name FROM user_data WHERE email='$email'"); $by = mysql_fetch_row($res); mysql_free_result($res); $log = $by[4]; $pas = $by[2]; $pas2 = $by[3]; if ($email && $pass) { if ($by[0]) { if ($by[1] == 2) { $passwd = crypt($_REQUEST['pass'],$by[5]); if ($pass == $pas2) { mysql_query("UPDATE user_data SET lastlogin='$entry_date' WHERE email='$email'"); mysql_close($con); header("Location: index.php"); } elseif ($passwd != $pas) { header("Location: nolog.php?logout=1&m=4"); } } elseif ($by[1] == 1) { header("Location: nolog.php?logout=1&m=2"); } elseif ($by[1] == 0) { header("Location: nolog.php?logout=1&m=3"); } } elseif (!$by[0]) { header("Location: nolog.php?logout=1&m=1"); } } elseif (!$email || !$pass) { echo "<b>Error:</b> Both username and password must be entered in order to log in."; echo "<p>"; include "login_form.php"; } ?>[/php index.php [php]<?php include "file_calls.php"; $title = "Business Name (Beta)"; include "functions.php"; session_start(); echo "$title"; echo "<p>"; echo "This website is currently under construction. Thank you for your patience."; echo "<p>"; if ($lev > 1) { echo "Hello, $loggeduser !"; } elseif ($lev < 2) { echo "Not logged in."; } echo "<p>"; echo "$lev"; echo "<br>$loggeduser<br>$email"; ?> auth.php <?php // Defines DEFINE('SESSION_MAGIC','sadhjasklsad2342'); // Initialization @session_start(); @ob_start(); /* Redirects to another page */ function Redirect($to) { @session_write_close(); @ob_end_clean(); @header("Location: $to"); } /* Deletes existing session */ function RemoveSession() { $_SESSION = array(); if (isset($_COOKIE[session_name()])) { @setcookie(session_name(), '', time()+(60*60*24*365), '/'); } } /* Checks if user is logged in */ function isLoggedIn() { return(isset($_SESSION['magic']) && ($_SESSION['magic']==SESSION_MAGIC)); } /* read message count */ function CountMessages($id) { if ($res=mysql_query("SELECT * FROM user_data WHERE email='$email'")) { $count=mysql_num_rows($res); mysql_free_result($res); return($count); } return 0; } /* Go login go! */ function Login($email,$pass) { global $nmsg, $rows; $ok=false; if ($res=mysql_query("SELECT id, email, name, pwd1, pwd2, memlev FROM user_data WHERE email='$email' AND pwd2='$pass'")) { if ($rows=mysql_fetch_row($res)) { $_SESSION['sess_name'] = $rows[2]; $_SESSION['pass'] = $pass; $_SESSION['gal'] = $rows[0]; $_SESSION['level2'] = $rows[5]; $_SESSION['email'] = $rows[1]; $_SESSION['magic'] = SESSION_MAGIC; $nmsg = CountMessages($rows[0]); $ok=true; } else { include('login_failed.php'); } mysql_free_result($res); } return($ok); } /* Terminates an existing session */ function Logout() { @RemoveSession(); @session_destroy(); } /* Escape array using mysql */ function Escape(&$arr) { if (Count($arr)>0) { foreach($arr as $k => $v) { if (is_array($v)) { Escape($arr[$k]); } else { if (function_exists('get_magic_quotes')) { if(!get_magic_quotes_gpc()) { $arr[$k] = stripslashes($v); } } $arr[$k] = mysql_real_escape_string($v); } } } } // ----------------------------------------------- // Main // ----------------------------------------------- Escape($_POST); Escape($_GET); Escape($_COOKIE); Escape($_REQUEST); Escape($_GLOBALS); Escape($_SERVER); ?> file_calls.php <?php include "info_con.php"; include "auth.php"; ?> functions.php <?php echo "<title>$title</title>"; $lev=isset($_SESSION['level2'])?$_SESSION['level2']:0; $logged=isset($_SESSION['gal'])?$_SESSION['gal']:0; $loggeduser=$_SESSION['sess_name']; $nmsg = 0; $rows = isset($_SESSION['rows'])?$_SESSION['rows']:array(); $email = isset($_SESSION['email'])?$_SESSION['email']:''; $pass = isset($_SESSION['pass'])?$_SESSION['pass']:''; function rand_chars($c, $l, $u = FALSE) { if (!$u) for ($s = '', $i = 0, $z = strlen($c)-1; $i < $l; $x = rand(0,$z), $s .= $c{$x}, $i++); else for ($i = 0, $z = strlen($c)-1, $s = $c{rand(0,$z)}, $i = 1; $i != $l; $x = rand(0,$z), $s .= $c{$x}, $s = ($s{$i} == $s{$i-1} ? substr($s,0,-1) : $s), $i=strlen($s)); return $s; } function ShowLoggedInBar() { global $email,$pass,$rows,$logid; $nmes=""; if($nmsg){ $nmes="($nmsg New)"; } echo "Hello, $loggeduser !"; } /* check if we are logging out */ if (isset($_REQUEST['logout'])) { Logout(); } /* check if already logged in */ if (isset($_SESSION['magic']) && ($_SESSION['magic']==SESSION_MAGIC)) { ShowLoggedInBar(); } else { /* not logged in, is it a form post? */ if (isset($_REQUEST['email']) && isset($_REQUEST['pass'])) { $email = $_REQUEST['email']; $pass = crypt($_REQUEST['pass'],$email); Login($email,$pass); } else { } } ?> Can anyone see why it works on everything but getting the person logged in? Hello everyone, I am new to this forum and PHP world. Doing my first project, a pretty complicated one to start with. I will be needing your help a lot to accomplish it. Here is the first one. 1. I have a certain field called 'country' 2. I have small flag icons for every country. WHAT DO I WANT TO DO? Example - If the country is U.S.A., the U.S. flag shows up and is a link to www.domain.com/usa If the country is Germany, the German flags shows up and is a link to www.domain.com/germany If the country is not set, no flag shows up. END. How do I execute this? This is what I am doing to get the image <img src="images/flags/<?php echo $row_rsPilots['country']; ?>.gif" alt="" name="Flag" width="20" height="20" id="Flag" /> How do make it a link to www.domain.com/'country' Thanks in advance This topic has been moved to CSS Help. http://www.phpfreaks.com/forums/index.php?topic=342058.0 I created an array using the array_diff function and it worked fine. My resulting array has lots of keys/values (like teamid, teamname, teamcity). I want to now display the teamid and teamcity as options in an HTML SELECT menu. I thought I would do something like this below, but it's only giving me the teamid (NOTE, I left out the Select tags because I'm good with that part of it ). How do I write the code to get the teamcity to show as well? Obviously doing something very wrong Code: [Select] $remainingteams = array_diff($allteams, $chosenteams); foreach($remainingteams as $teamid => $value){ echo "<option>" . $teamid . "-" . $remainingteams['teamcity'] . "</option>"; } Don't have a huge deal of experience with this side of things, well php as a whole really but really struggle with this side, ive coded up a cron but it only works for 1 user, unsure as to why, i want it to do the action for every player that has item 17, the codes below any help would be appreciated, Thanks guys Code: [Select] <?php include("server.php"); $sql = "SELECT * FROM player_inventory WHERE item_id = 17"; $que = mysql_query($sql) or die(mysql_error()); $res = mysql_fetch_array($que); $sql2 = "SELECT * FROM players WHERE id = $res[player_id]"; $que2 = mysql_query($sql2); while($res2=mysql_fetch_array($que2)) { $Weight = 8 / 100 * (100 + $res2['ProductionWeight']); $Quality = 75 / 100 * (100 + $res2['ProductionWeight']); $StreetCred = $Weight * $Quality / 10; $update = "UPDATE players SET StreetCred = StreetCred + $StreetCred WHERE id = $res[player_id]"; mysql_query($update) or die(mysql_error());; $update2 = "INSERT INTO drug_inventory (player_id,quality,weight) VALUES('$res[player_id]',$Quality,$Weight)"; mysql_query($update2) or die(mysql_error());; echo "Grow Completed."; } ?> I don't get why this fails. date() is meant to be a string, so why does it not concatenate correctly? Code: [Select] date_default_timezone_set('UTC'); $inputTime = date('c'); $inputTime = $inputTime . ' (UTC)'; // or $inputTime = date('c') . ' (UTC)'; Thanks. hi, i am pulling data from a database, a picture and some text, i am able to have the records display vertically but i want them to display across the screen rather than downwards, but because of the page size, i only want 2 results per line. does any one know how i can do this? thanks in advance. Des This is the code i am currently using $result = mysql_query("select * from staff'"); echo "<table border='0' cellpadding='10' cellspacing='0'>"; echo "<tr>"; while($row = mysql_fetch_array($result)) { echo "<td><img src=../upload/".$row['Pic']." border='0' width='140' height='105' /></td>"; echo "<td>".$row['Name']."</br><b>".$row['Role']."</b></td>"; } echo "</tr>"; echo "</table>"; Is it just me or is anyone else having problems with the site? When I make a reply to a post and submit it, my post is added but it also appears as an edit window still below my just-posted post. Also - when I try and edit my post the edit window opens up but the text of my post flashes by and does not show. If I re-type the entire post with my edits and save it, the edits do not appear. This has been happening for 3-4 days now. Edited by ginerjm, 30 December 2014 - 01:33 PM. Hi, My mother-in-law asked me to check on her laptop (win8) and I tried but was unable to find a solution. The problem is that the hard-drive is at a constant 100% which makes the laptop really slow except in safe mode. Process list shows no process using 100% of the hdd, I already did a chkdsk and it returned no errors. I suspect it's due to the task scheduler and stopping the active tasks indeed lowers the hdd usage to 6-11% but it does not remain there probably because new tasks are started. I also removed several software which I suspected were the ones creating the tasks to no avail. It appears as if Windows itself is running tasks that slow down the laptop to a crawl, but disabling task scheduler does not seem a good idea. Any ideas? Hello people I'm having some trouble, and I kind think I know what it is, but for some reason I just can't figure it out. I think I need an isset function, but I'm not sure where to put it? Here is my code followed by my errors. <?php echo"<?xml version=\1.0\"encoding=\UFT-8\"\x3f>"; echo"\n"; ?> <!DOCTYPE html PUBLIC"-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtmll/DTD/xhtmll-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en"lang="en"> <head> <title>My Second PHP Generated Document</title> </head> <body> <?php if (isset($_POST['submit'])) { if ($_POST['submit'] == "Clear") { $workValue = ""; $workType = ""; } elseif ($_POST['submit'] == "Calculate") { $workValue = $_POST['vfld']; $workType = $_POST['tfld']; $calcValue = (float) $workValue; if (empty($_POST['vfld'])) { echo "<h3>Error</h3>"; echo "<p>You must enter a value!</p>\n"; } elseif ($calcValue == 0) { echo "<h3>Error</h3>"; echo "<p>You must enter a number!</p>\n"; } elseif ($calcValue < 0) { echo "<h3>Error</h3>"; echo "<p>You must enter a positive number!</p>\n"; } elseif (empty($_POST['tfld'])) { echo "<h3>Error</h3>"; echo "<p>You must select a calculation type!</p>\n"; }} else { switch ($workType) { case "circle": $areaValue = $calcValue * $calcValue * pi(); break; case "square": $areaValue = $calcValue * $calcValue; // echo "The area of a square whose sides are" break; case "triangle": $halfSide = $calcValue/2; $otherSide = sqrt(($calcValue * calcValue) - ($halfSide * halfSide)); $areaValue = $otherSide * $halfSide; echo "The area of an equilateral triangle whose sides are $calcValue} is {areaValue}."; break; }} } ?> <form method="post" action="hw04.php" id="form1" name="form1"> <p> Enter a number here : <input type="text" id="vfld" name="vfld" value="<?php echo $workValue; ?>"/> </p> <p> This number is a: <br /> <input type="radio" name="tfld" value="circle" <?php if ($workType == "circle") { echo 'checked="checked"'; } ?> /> : the radius of a circle <br /> <input type="radio" name="tfld" value="square" <?php if ($workType == "square") { echo 'checked="checked"'; } ?> /> : the length of one side of a square <br /> <input type="radio" name="tfld" value="triangle" <?php if ($workType == "triangle") { echo 'checked="checked"'; } ?> /> : the length of one side of an equilateral triangle </p> <p> <input type="submit" name="submit" value="Calculate" /> <input type="submit" name="submit" value="Clear" /> </p> </form> <div id="footer"> <pre>This page written by: <cite>James Cozzy</cite> ©2011 and beyond</pre> </div> </body> </html> And my errors Enter a number here : This number is a: Notice: Undefined variable: workType in /studfs1/j-cozzy/homepage/CISS-225/hw04.php on line 69 /> : the radius of a circle Notice: Undefined variable: workType in /studfs1/j-cozzy/homepage/CISS-225/hw04.php on line 74 /> : the length of one side of a square Notice: Undefined variable: workType in /studfs1/j-cozzy/homepage/CISS-225/hw04.php on line 79 /> : the length of one side of an equilateral triangle any help would be much appreciated? I am trying to put the tree of an XML file into an array. sample.xml Code: [Select] <?xml version='1.0' encoding='UTF-8'?> <getHistogramsResponse xmlns="http://www.ebay.com/marketplace/search/v1/services"> <ack>Success</ack> <version>1.7.0</version> <timestamp>2010-09-01T12:13:31.480Z</timestamp> <aspectHistogramContainer> <domainName>UK_CamerasPhoto_DigitalCameras_DigitalCameras_JN</domainName> <domainDisplayName>Digital Cameras</domainDisplayName> <aspect name="Brand"> <valueHistogram valueName="Canon"> <count>4323</count> </valueHistogram> <valueHistogram valueName="Sony"> <count>2210</count> </valueHistogram> </aspect> </aspectHistogramContainer> </getHistogramsResponse> $this->cXmlToArray->m_arr = GetXMLTree('sample.xml') if (isset($this->cXmlToArray->m_arr['getHistogramsResponse']['aspectHistogramContainer'][0])) { $this->m_arrResult = $this->cXmlToArray->m_arr['getHistogramsResponse']['aspectHistogramContainer']; } else if (count($this->cXmlToArray->m_arr['getHistogramsResponse']['aspectHistogramContainer']) > 0) { $this->m_arrResult[] = $this->cXmlToArray->m_arr['getHistogramsResponse']['aspectHistogramContainer']; } However my output is showing as: Array ( [0] => Array ( [domainName] => UK_CamerasPhoto_DigitalCameras_DigitalCameras_JN [domainDisplayName] => Digital Cameras [aspect] => Array ( [0] => Array ( [valueHistogram] => Array ( [0] => Array ( [count] => 4311 ) [1] => Array ( [count] => 2209 ) ) ) ) So how do I get it to return the attributes name and valueName? Any help will be greatly appreciated. Hi Chaps, I've created a web-based FTP site, but having trouble with PHP's FTP_PUT function. I've tried: // FTP access parameters $host = 'ftp.example.org'; $usr = 'example_user'; $pwd = 'example_password'; // file to move: $local_file = './example.zip'; $ftp_path = '/data/example.zip'; // connect to FTP server (port 21) $conn_id = ftp_connect($host, 21) or die ("Cannot connect to host"); // send access parameters ftp_login($conn_id, $usr, $pwd) or die("Cannot login"); // turn on passive mode transfers (some servers need this) // ftp_pasv ($conn_id, true); // perform file upload $upload = ftp_put($conn_id, $ftp_path, $local_file, FTP_BINARY); // check upload status: print (!$upload) ? 'Cannot upload' : 'Upload complete'; print "\n"; // close the FTP stream ftp_close($conn_id); And also Net_FTP's FTP_PUT function: require_once 'Net/FTP.php'; $test = new Net_FTP('www.domain.co.uk', 21); $test->connect('www.domain.co.uk', 21); $test->login('username', 'password'); $file_tmp = $_FILES["file"]["tmp_name"]; $file_name = $_FILES["file"]["name"]; $test->put($file_tmp, 'Uploads/'.$file_name, FTP_BINARY); I've tested this with a very small text file and it works OK, but when I try with a zip file of around 9Mb it takes FOREVER, and sometimes doesn't upload at all, or if it does, it has a size of 0kb. I need the script to handle big files up to 150Mb in size. What can I do to speed up the process and is there something I have missed (current config settings > ini_set('max_upload_filesize', 150000000)) ? I'm new to php and having some trouble with debugging a piece of code. Could someone please help me understand what's the error. I'm using Code Lobster for debugging and attempting to validate input for a simple sign in form. The error is and code is shown below. If I can understand this, I think I can continue with the rest of the checking. Parse error: syntax error, unexpected T_FOREACH, expecting ')' in C:\wamp\www\login_check_blank.php on line 20 <php // Program name - login_check_Blank.php // Description - checks form for blank fields // Date - 10/26/10 // Programer - R. Langevin ?> <html> <head> <title>Checking for empty fields</title> </head> <body> <?php // set up array for all fields $labels = array( "userName" => "username", "passWord" => "password", // Check each field for blanks foreach ($_POST as $field => $value) { } if ($value =="") { $blank_array[] = $field; } // end of foreach loop for $_post // if any fields were blank, display error message and redisplay form if (@sizeof ($blank_array) >0 { echo "<strong>One or more requied fields were found to be blank</strong>" // display list of blank fields foreach($blank_array as $value) { echo " $nbsp; {$labels[$value] } <br>"; } } echo "$userName "welcome back to the Taft Union High School class of 65 website." exit() ?> </body> </html> |