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PHP - Mysql_query With Php
Hey guys, I've been playing around with this open source php game, I'm having problems with the registration system. For some reason the script is echoing back that there is no password in the password fields. When in fact there is:
Add_player.php: Code: [Select] <?php session_start(); session_register("pid"); include("common.inc"); include("date.inc"); include("header.inc"); dbConnect(); $res = mysql_query("select id from $dbName.pdm_players where name=\"$name\"") or die(mysql_error()); if ($name == "" || $password1 == "") { echo "<center><div class=\"sheader\">Oh dear me!</div> You have to actually enter a name and password!"; $name = ""; include("character_form.inc"); echo "</center>"; include("footer.inc"); return 0; } if ($name == $password1) { echo "<center><div class=\"sheader\">Oh dear me!</div> You can't make the password the same as the name. People will guess your password!"; include("character_form.inc"); echo "</center>"; include("footer.inc"); return 0; } if (strlen($password1) < 6) { echo "<center><div class=\"sheader\">Oh dear me!</div> Passwords must be at least 6 characters, otherwise they are easy to guess!"; include("character_form.inc"); echo "</center>"; include("footer.inc"); return 0; } if (mysql_fetch_row($res)) { echo "<center><div class=\"sheader\">Oh dear me!</div> Player $name already exists, try a different name."; $name = ""; include("character_form.inc"); echo "</center>"; include("footer.inc"); return 0; } if ($password1 != $password2) { echo "<center><div class=\"sheader\">Oh dear me!</div>"; echo "The two passwords didn't match - type carefully now!."; include("character_form.inc"); echo "</center>"; include("footer.inc"); return 0; } echo "<div class=\"sheader\">Registration for $name successful</div>"; $cp = crypt($password1); $dateArray = getdate(time()); $likeNowScoob = $dateArray["year"] . "-" . $dateArray["mon"] . "-" . $dateArray["mday"]; if ($character < 1 || $character > 9) { die("you are an idiot"); } pdm_characters(); $res = mysql_query("select type from $dbName.pdm_characters where cid = $character") or die(mysql_error()); $t = mysql_fetch_row($res); pdm_stuff(); $specRes = mysql_query("select sid from $dbName.pdm_stuff where sid >= 28 and sid <= 33 and type like \"%$t[0]%\"") or die(mysql_error()); $res = mysql_query("BEGIN") or die(mysql_error()); $res = mysql_query("insert into $dbName.pdm_players (name, used, dob, cpass, char_id, roundswon, evo, aWeapon, dWeapon) VALUES (\"$name\", 1, \"$likeNowScoob\", \"$cp\", $character, 0,0,0,0)") or die(mysql_error()); $res = mysql_query("select id from $dbName.pdm_players where name=\"$name\" for update") or die(mysql_error()); $row = mysql_fetch_row($res); $pid = $row[0]; $res = mysql_query("insert into $dbName.pdm_league (id, highest, days_no_1, yesterday, longPoints) VALUES ($pid, 16777215, 0, 16777215, 0)") or die(mysql_error()); $res = mysql_query("insert into $dbName.pdm_stats (id, level, attack, defence, health, speed, exp, ko, healthpercent, fights) VALUES ($pid, 1, 100, 100, 100, 100, 0, 0, 10, 0)") or die(mysql_error()); $res = mysql_query("insert into $dbName.pdm_clanmembers2 (id, clanTag, applyTag, utype) VALUES ($pid, NULL, NULL, '')") or die(mysql_error()); $res = mysql_query("insert into $dbName.pdm_money (id, bank, wallet, bankdate) VALUES ($pid, 0,0, '0000-00-00')") or die(mysql_error()); while ($row = mysql_fetch_row($specRes)) { $res = mysql_query("insert into $dbName.pdm_specials (id, sid, qty, switch) values ($pid, $row[0], 0, 1)") or die(mysql_error()); } $res = mysql_query("COMMIT") or die(mysql_error()); session_register("playerName"); $playerName = stripper($name); echo "<P><diV>Welcome $playerName, click the Fight link down the left to fight your first opponent.</div>"; include("main_screen.inc"); include("footer.inc"); ?> Character_form.inc: Code: [Select] <center> <form method="post" action="add_player.php"> <P> <table cellpadding="0" cellspacing="0"><tr><td align="center"> <?php dbConnect(); pdm_characters();#check HEAP table exists $res = mysql_query("select cid, name, type from $dbName.pdm_characters order by type") or die(mysql_error()); $marker = "X"; $firstOne = 1; $cTypes["A"] = "Alien"; $cTypes["M"] = "Magic"; $cTypes["S"] = "Spirit"; while ($row = mysql_fetch_row($res)) { if ($marker != $row[2]) #new type (alien/magic etc) { if ($marker != "X") { echo "</table>\n"; } $cn = $cTypes[$row[2]]; echo "\n<table cellpadding=\"0\" cellspacing=\"0\" border=1> <tr><td colspan=\"3\" align=\"center\"><div class=\"sheader\"> $cn characters</div></td></tr><tr bgcolor=\"#efefef\">"; $marker = $row[2]; } echo "\n<td><table><tr><td align=center>$row[1]</td></tr><tr><td align=center> <img alt=\"Pick me!\" src=\"images/$row[0]0.gif\"></td></tr><tr> <td align=center><input type=\"radio\" name=\"character\" value=\"$row[0]\""; if ($firstOne and $character == "") { $firstOne = 0; echo " CHECKED "; } if ($character == $row[0]) { echo " CHECKED "; } echo "></td></tr></table></td>"; } echo "</tr></table> <table width=\"551\" cellpadding=0 cellspacing=0><tr><td colspan=\"3\"><div class=\"sheader\">character details</div></td></tr> <tr><td align=\"center\">Name<br><input size=20 maxlength=20 type=text name=\"name\" value = \"$name\"></td>"; ?> <td align="center">Password<br><input type="password" name="password1" size=20 maxlength=20></td> <td align="center">Password again<br><input type="password" name="password2" size=20 maxlength=20></td></tr> <tr><td colspan="3" align="center"><input type="submit" value="Register my character"></td></tr></table> </td></tr></table> <hr> </form> </centER> Anyone able to offer up any advice or where its going wrong, If I remove the validation stuff, it still doesn't insert the user into the database. Cheers Similar TutorialsI am getting a "mysqli_query() expects parameter 1 to be mysqli, null given" error. the code I am using is below but simplified. connect() does connect to the database without throwing any errors but when I get down to query() I get the above error. public function connect() { mysqli_connect(self::DBHOST, self::DBUSER, self::DBPASS, self::DBNAME); } public function query($query) { mysqli_query(self::connect(), $query); } below is what I am using to call the function. I am not sure if I have to pass the $link in the query function too. I have tried but it didn't seem to do any better. $link = db::connect(); $query = "SELECT name FROM plugins"; db::query($query); I am sure this is something simple that I have overlooked but I am new to this and still learning. Thank you for any help you can provide. Hi, why won't this work, there is no error messages so it gets to this point, but won't redirect??? (Obviously a lot is missed out here) $query = mysql_query("SELECT * FROM `users` WHERE `username`='$username'"); if ($username==$dbusername&&$password==$dbpassword) { $_SESSION['user'] = $username; while($row = mysql_fetch_array($query)){ $type = $row['Type']; if ($type=="0") { header("Location: chefpanel.php"); }else{ header("Location: restpanel.php"); } } } else $errors[] = 'Password Incorrect'; } else $errors[] = 'Username Incorrect'; OK So I have a quick question... how would I go about making a query like: mysql_query("SELECT * FROM users WHERE username='$username' AND password='$password' AND key='$key' "); You see, theres an error: Quote You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ' key='1234' LIMIT 1' at line 1 I know this is a simple issue, and I know you cant keep creating AND's inside the query, but how would I do it? I've never attempted to use more than one AND before, so its new to me even though I'm a experienced PHP Developer. Thanks in advance! Hey Guys, Im having problems with my code. What im trying to do is run a mysql query and show the results, but if the query returns no data, echo out "No incoming requests!" Here is my code: <? $check = "SELECT * FROM requests WHERE club='" . $_SESSION['club'] . "' AND team='" . $_SESSION['team'] . "' AND accepted='0'"; $result=mysql_query($check); if (mysql_num_rows($result) == 0) { while ($getinfo = mysql_fetch_array($result)) { $time = $getinfo["time"]; $who = $getinfo["player_name"]; $whofor = $getinfo["toplayfor"]; $from = $getinfo["team"]; $idp = $getinfo["player_id"]; echo "<a href='profile.php?id=".$idp."&team=".$from."'>".$who." </a><div style='float:right;'>(".$from.")</div><br />"; echo "<div style='margin-top: 2px;'></div>"; echo date('l, F jS, g:ia',$time); echo "<br /><div style='margin-top: 2px;'></div><a href='accept.php?playerid=".$idp."&toplayfor=".$whofor."'>Accept</a> | Decline"; echo "<div id='newsline'></div>"; } } else { echo 'No incoming requests'; } ?> Could someone help me out here? Thanks Heaps! I'm hoping someone can help me cos my hair's going white with this one. I'm trying to put together a script that acts as web-based interface to an SQL server. There are actually two parts, admin.htm and admin.php. The first part is just a form that passes login credentials to the PHP file. That part seems to work fine, but I'll post the source anyway: - Code: [Select] <!DOCTYPE HTML> <html lang="en"> <head> <title>SQL admin login</title> <meta charset="iso-8859-1" /> </head> <body> <form action="admin.php" method="post"> <label for="username">Username: -</label> <br /> <input type="text" name="username" id="username" /> <br /> <br /> <label for="password">Password: -</label> <br /> <input type="password" name="password" id="password" /> <br /> <br /> <label for="server">Server: -</label> <br /> <input type="text" name="server" id="server" /> <br /> <br /> <label for="database">Database: -</label> <br /> <input type="text" name="database" id="database" /> <br /> <br /> <input type="submit" value="Login" /> <input type="reset" value="Reset" /> </form> </body> </html> Following is the content of admin.php. By this point I can see the connection in MySQL Workbench, and when I submit the query 'SELECT * FROM subscribers' it's being stored in '$_POST['query']', but 'mysql_query($_POST['query'],$_SESSION['con']);' is returning nothing. There is definitely a record in that table, and the user I'm logging on with has permission to run the 'SELECT' command against this database, so I can't figure out why mysql_query(); is returning nothing: - Code: [Select] <!DOCTYPE HTML> <?php session_start(); if(!$_SESSION['con']) { if(!($_POST['username'] || $_POST['password'])) { if(!($_SESSION['username'] || $_SESSION['password'])) { $error="Username and password variables empty."; } } else { $_SESSION['username']=mysql_real_escape_string($_POST['username']); $_SESSION['password']=mysql_real_escape_string($_POST['password']); $_SESSION['server']=mysql_real_escape_string($_POST['server']); $_SESSION['database']=mysql_real_escape_string($_POST['database']); $_SESSION['con']=mysql_pconnect($_SESSION['server'],$_SESSION['username'],$_SESSION['password']); if(!$_SESSION['con']) { $error="Failed to connect to server."; } else { $database=mysql_select_db($_SESSION['database'],$_SESSION['con']); if(!$database) { $error="Failed to connect to database."; } } } } if(!$_POST['query']) { $error="No query submitted."; } else { $result=mysql_query($_POST['query'],$_SESSION['con']); if(!$result) { $error="Query returned nothing."; } } ?> <html lang="en"> <head> <title>SQL admin interface</title> <meta charset="iso-8859-1" /> </head> <body> <form action="admin.php" method="post"> <textarea name="query" rows="10" cols="50">SELECT * FROM subscribers</textarea> <br /> <br /> <input type="submit" value="Submit query" /> </form> <?php if($error) { echo $_POST['query']."<br /><br />".$result."<br /><br />".$error; die(); } else { while($row=mysql_fetch_assoc($result)) { echo $row['name']." ".$row['email']; echo "<br />"; } } ?> </body> </html> Can anyone help? MOD EDIT: [code] . . . [/code] tags added. hey I am still little new in php can you help me in this one func.php function confirm_query($result_set){ if(!$result_set){ die(mysql_error()); } function get_subjects_all() { global $connection ; $sub_query = "SELECT * FROM subjects ORDER BY position ASC"; $subject_query = mysql_query($sub_query,$connection); confirm_query($subject_query) ; return $subject_query; } function get_pages_all($subject_id) { global $connection; $query = "SELECT * FROM pages WHERE subject_id = '$subject_id' ORDER BY position ASC"; $page_set = mysql_query($query, $connection); confirm_query($page_set); return $page_set; } test.php require_once("config.php"); require_once("func.php"); $subject_query = get_subjects_all(); while($subject = mysql_fetch_array($subject_query)) { echo "<a href= \"test.php?subj=" . urlencode($subject["id"]) . "\">{$subject['menu_name']} <br />"; } $an = $subject["id"] ; $page_set = get_pages_all($an); while($page = mysql_fetch_array($page_set)) { echo "<a href = \"test.php?page=" . urldecode($page["id"]) . "\">{$page['menu_name']} </a><br />" ; // echo "<b> <a href= '1.php?page={$page['id']}' >{$page['menu_name']} </a></b> <br />"; } in this line WHERE subject_id = '$subject_id' the query don't work and gives me sql error i tried with this one ' ".$subject_id." ' but not worked but if i changed $subject_id to a number it work and read the data from the table thanks in advanced . I've got a very simple script that records IP address of every page view. Here is the script: $ip = $_SERVER['REMOTE_ADDR']; $query = "INSERT INTO tracking VALUES ('', '1', '$ip')"; echo $query; echo ("<hr>"); if (mysql_query($query)) { echo ("INSERT OK"); } else { echo ("INSERT failed"); } FYI: the 1st value is "auto_increment" in the DB, therefore blank ('') in the query string, and the 2nd value "1" is just for the page number 1, as this script will be on other pages, with different numbers. Now, when I go to this page, it outputs the query, and hr, and then "INSERT failed" and sure enough, no record gets added to the DB. The strangest thing is, is that when I copy the query that the page shows, and paste it into mysqlPHPadmin's "SQL" section and run it, it executes fine, and a record gets added to the DB, however the page is unable to do that. Any ideas? PS: the connection (which I didn't paste in here) is fine, that's definitely not the problem. This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=328375.0 Is there something wrong this? If so, I'm not seeing it...I keep getting this error: Quote ( ! ) Parse error: syntax error, unexpected T_STRING in C:\Program Files\wamp\www\register.php on line 1059 Here's my code for registering a member: Code: [Select] <?php mysql_query (INSERT INTO fans (id, username, email, password, country, region, gender, status, account, subscription, time_registered, date_registered, birthdate, name, website, age, activation_key) VALUES ('', '{$_SESSION["user"]["username"]}', '{$_SESSION["user"]["email"]}', '{$_SESSION["user"]["password"]}', '{$_SESSION["user"]["country"]}', '{$_SESSION["user"]["region"]}', '{$_SESSION["user"]["gender"]}', 'Offline', 'Inactive', 'Unsubscribed', '{$_SESSION["user"]["time"]}', '{$_SESSION["user"]["date"]}', '{$_SESSION["user"]["birthdate"]}', '{$_SESSION["user"]["name"]}', '{$_SESSION["user"]["website"]}', '{$_SESSION["user"]["age"]}', '{$_SESSION["user"]["activation_key"]}')) or die ("Could not register member"); ?> Help, please and thank you! I'm pretty new to PHP and I'm having trouble inserting data into my database from a webpage. Here is the code. The error is on the lines with $query and $result. The error comes back: Warning: mysql_query(): supplied argument is not a valid MySQL-Link resource in /home/content/76/5697876/html/corbinreynolds/insert.php on line 39 Lost connection to MySQL server at 'reading initial communication packet', system error: 111 I've been working at this for hours and can't seem to figure this out. Any ideas? <?php $first=$_POST['first']; $last=$_POST['last']; if (!$first || !$last) { echo 'Error: Enter the required data.'; exit; } if (!get_magic_quotes_gpc()) { $first = addslashes($first); $last = addslashes($last); } $hostname = '127.0.0.1'; $username = 'root'; $password = 'root'; $dbname = 'phonebook'; @ $db = mysql_connect($hostname,$username.$password,$dbname); if (mysqli_connect_errno()) { echo 'Errer: Could not connect to database'; echo '<br>'; echo mysqli_connect_error(); exit; } $query = "INSERT INTO contact (first,last) VALUES ('$first','$last')"; $result = mysql_query($query,$db) or die(mysql_error()); if ($result) { echo $db->affected_rows." contact inserted into the database"; echo 'Contact Entered: '.$first.' '.$last.''; } else { echo 'Error: Contact not added.'; exit; } echo 'Closing Database'; $db->close(); ?> Ok so here's my code first the ajax/javascript, secondly the php. Issue i'm having is that first it wasn't entering any data into my database then eventual through much troubleshooting I figured out that if I add more then 10 variables in my INSERT INTO query it wont work. Ten or less and it works perfect. I CAN NOT figure this out?! Note, at the bottom of the php script I have the script that I would like to work, commented out, and the script that is currently working, active. You can see it only has 10 working entries. Code: [Select] function entervehicle(){ var stk = document.getElementById("stk").value var my = document.getElementById("my").value var mak = document.getElementById("mak").value var mod = document.getElementById("mod").value var mil = document.getElementById("mil").value var pri = document.getElementById("pri").value var bst = document.getElementById("bst").value var len = document.getElementById("len").value var eng = document.getElementById("eng").value var dor = document.getElementById("dor").value var tra = document.getElementById("tra").value var gvw = document.getElementById("gvw").value var inc = document.getElementById("inc").value var exc = document.getElementById("exc").value var cfo = document.getElementById("cfo").value var titl = document.getElementById("titl").value var desc = document.getElementById("desc").value var vin = document.getElementById("vin").value var pic1 = document.getElementById("pic1").value var pic2 = document.getElementById("pic2").value var pic3 = document.getElementById("pic3").value var pic4 = document.getElementById("pic4").value var pic5 = document.getElementById("pic5").value var pic6 = document.getElementById("pic6").value var pic7 = document.getElementById("pic7").value var pic8 = document.getElementById("pic8").value var pic9 = document.getElementById("pic9").value var linksubmit ="../php/entervehicle.php?stk=" + stk +"&my=" + my +"&mak=" + mak +"&mod=" + mod +"&mil=" + mil +"&pri=" + pri +"&bst=" + bst +"&len=" + len +"&eng=" + eng +"&dor=" + dor +"&tra=" + tra +"&gvw=" + gvw +"&inc=" + inc +"&exc=" + exc +"&cfo=" + cfo +"&titl=" + titl +"&desc=" + desc +"&vin=" + vin +"&pic1=" + pic1 +"&pic2=" + pic2 +"&pic3=" + pic3 +"&pic4=" + pic4 +"&pic5=" + pic5 +"&pic6=" + pic6 +"&pic7=" + pic7 +"&pic8=" + pic8 +"&pic9=" + pic9 alert(linksubmit); var entrequest = getHTTPObject(); if(entrequest) { entrequest.open("GET",linksubmit,true); entrequest.onreadystatechange = function(){ entveh(entrequest); }; entrequest.send(null); } } function entveh(entrequest){ if(entrequest.readyState == 4){ if(entrequest.status == 200){ var myPHP = entrequest.responseText; document.getElementById("adminmain").innerHTML = myPHP; } } } <?php $stk = $_GET['stk']; $my = $_GET['my']; $mak = $_GET['mak']; $mod = $_GET['mod']; $mil = $_GET['mil']; $pri = $_GET['pri']; $bst = $_GET['bst']; $len = $_GET['len']; $eng = $_GET['eng']; $dor = $_GET['dor']; $tra = $_GET['tra']; $gvw = $_GET['gvw']; $inc = $_GET['inc']; $exc = $_GET['exc']; $cfo = $_GET['cfo']; $titl = $_GET['titl']; $desc = $_GET['desc']; $vin = $_GET['vin']; $pic1 = $_GET['pic1']; $pic2 = $_GET['pic2']; $pic3 = $_GET['pic3']; $pic4 = $_GET['pic4']; $pic5 = $_GET['pic5']; $pic6 = $_GET['pic6']; $pic7 = $_GET['pic7']; $pic8 = $_GET['pic8']; $pic9 = $_GET['pic9']; require("database.php"); $tresult = mysql_query("INSERT INTO automobile_stat (stock_number,model_year, make, model, miles, price, body_style, length, description, trans) VALUES ('$stk', '$my', '$mak', '$mod', '$mil', '$pri', '$bst', '$len', '$desc', '$tra')"); /*$tresult = mysql_query("INSERT INTO automobile_stat (stock_number, model_year, make, model, miles, price, body_style, length, description, engine, doors, trans, gvw, int_color, ext_color, car_fax_owner, title_desc, main_picture_src, vin) VALUES ('$stk', '$my', '$mak', '$mod', '$mil', '$pri', '$mpri', '$bst', '$len', '$desc', '$eng', '$dor', 'tra', '$gvw', '$inc', '$exc', '$cfo', '$titl', 'img', '$vin')");*/ /*$tresult=mysql_query("SELECT * FROM automobile_stat" ); $countrows = mysql_num_rows($tresult); while($row = mysql_fetch_array($tresult)){ echo $row[stock_number]; }*/ mysql_close($linkID); ?> Okey, after hours and hours of googling...all i found was some snippet that works so far that it displays the success and error message, however doesn't do any queries. Basically, what i need is this: I have a textarea where a user submits he's status a.k.a what he's doing, but then the page refreshes (you know, the oldschool plain php/html). However, I know this is doable via jQuery / Ajax ... all i need is a proper code that actually works. Hi, I am a little confused on the difference the mysql_fetch_array and mysql_query? Whats the difference between those two? Thanks Hoping someone can help me, ive spent the last hour looking up examples of mysql_query(Insert) and changing my query but im still gettin a syntax error and I cant understand where. Ive tried removing apostrophies and putting the longest variable string outside of the speach marks without any joy. mysql_query("INSERT INTO $QA_table (SUB_CATEGORY, QUESTION, FROM, FROM_EMAIL, DISPLAY) VALUES ('$sub_cat','$message','$from','$from_email','2')") or die(mysql_error()); I get the following error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'FROM, FROM_EMAIL, DISPLAY) VALUES ('Range','test question bla bla bla','Phil','phi' at line 1 What I am trying to do is I am making a Event page and I would like to have it list the events in 2 sections. One being "On" or "Before" current date and the next being "Past" current date so I can list the events in "Upcoming Events" and "Past Events" the code im showing here is for the listing of my event page I just need help turning this query into two separate querys with the date function im looking for. Code: [Select] <?php $result = mysql_query("SELECT * FROM event ORDER by eventdate DESC"); if (!$result) { die("query failed: " . msql_error()); } while ($row = mysql_fetch_array($result)) { list($id, $eventdate, $header, $description, $image, $location) = $row; $description = nl2br($description); $eventdate = date("M j, Y",strtotime("$eventdate")); print(' <table width="680" border="0" cellpadding="14" cellspacing="0"> <tr> <td> <div class="myFont"><font size="+1" color="#4e8baf">'.$eventdate.' - </font><font size="+1"><b>'.$header.'</b></font></div> <font size="+1"><a href="event.php?list=true&eventid='.$id.'">Details</a></font><br /> <hr color="#FFFFFF" width="100" align="left" size="1"> </td> </tr> </table> '); } ?> Hello, I am still new to PHP, but am getting better. The Problem is, I have read all the tutorials and everything and successfully accomplished this at other places so I don't know what the issue is. I bet it is small, as it always seems to be an oversight that causes issues. I am trying to do a MySQL Update Query with variables and I keep getting this error message: Quote You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'LastName = 'Smith' BirthDate = '1993-12-05' Gender = 'Male' De Here is the code: Code: [Select] mysql_query("UPDATE orphans SET FirstName = '$firstname' LastName = '$lastname' BirthDate = '$birthdate' Gender = '$gender' Description = '$decrip' SponsorCount = '$sponsorcount' Created_On = 'createdon' Changed_On = '$changedon' PictureOne = 'pictureone' PictureTwo = 'picturetwo' PictureThree = '$picturethree' PictureFour = $picturefour' PictureFive = '$picturefive' WHERE IDa = '$IDa'") or die(mysql_error());The variables seem to be working, I just don't know what the issue is. Thanks for the help in advance! Edited to Fix Stupid Mistakes Hi everyone, On my website people can add their domain names in a text box. I then use a foreach to validate each domain the text box. The code is similar to: foreach($lines as $line){ $count_query = mysql_query("SELECT * FROM domains WHERE domain='$line'"); $count = mysql_num_rows($count_query); if ($count > 0){ $error[] = $line . " already exists!<br />"; } } I was wondering if anybody knows a way to use the mysql_query outside of the foreach loop, as if the person has entered 100 domains for example, thats 100 queries accessing my database. Im not too sure if its possible or not. Anybody have any ideas? Many thanks This works: $result = mysql_query("SELECT * FROM mydatabase WHERE username = 'billybob'"); This does not: $user = "billybob" $result = mysql_query("SELECT * FROM mydatabase WHERE username = $user"); Shouldn't these be identical? If I echo $user, I get, of course, "billybob", so does anyone know why the variable isn't working in the query itself? |
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