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PHP - Add To Array If Value Doesnt Exist
I have an array like so
Array (14) ( | ['0'] => Array (5) | ( | | ['name'] = String(7) "Pikemen" | | ['hp'] = Integer(1) 0 | | ['atk'] = Integer(1) 5 | | ['def'] = Integer(1) 5 | | ['rng'] = Integer(2) 15 | ) | ['1'] => Array (5) | ( | | ['name'] = String(7) "Pikemen" | | ['hp'] = Integer(1) 0 | | ['atk'] = Integer(1) 5 | | ['def'] = Integer(1) 5 | | ['rng'] = Integer(2) 15 | ) | ['2'] => Array (5) | ( | | ['name'] = String(7) "Pikemen" | | ['hp'] = Integer(1) 0 | | ['atk'] = Integer(1) 5 | | ['def'] = Integer(1) 5 | | ['rng'] = Integer(2) 15 | ) | ['3'] => Array (5) | ( | | ['name'] = String(7) "Pikemen" | | ['hp'] = Integer(1) 0 | | ['atk'] = Integer(1) 5 | | ['def'] = Integer(1) 5 | | ['rng'] = Integer(2) 15 | ) | ['4'] => Array (5) | ( | | ['name'] = String(7) "Pikemen" | | ['hp'] = Integer(1) 0 | | ['atk'] = Integer(1) 5 | | ['def'] = Integer(1) 5 | | ['rng'] = Integer(2) 15 | ) | ['5'] => Array (5) | ( | | ['name'] = String(7) "Pikemen" | | ['hp'] = Integer(1) 0 | | ['atk'] = Integer(1) 5 | | ['def'] = Integer(1) 5 | | ['rng'] = Integer(2) 15 | ) | ['6'] => Array (5) | ( | | ['name'] = String(7) "Pikemen" | | ['hp'] = Integer(1) 0 | | ['atk'] = Integer(1) 5 | | ['def'] = Integer(1) 5 | | ['rng'] = Integer(2) 15 | ) | ['7'] => Array (5) | ( | | ['name'] = String(7) "Pikemen" | | ['hp'] = Integer(1) 0 | | ['atk'] = Integer(1) 5 | | ['def'] = Integer(1) 5 | | ['rng'] = Integer(2) 15 | ) | ['8'] => Array (5) | ( | | ['name'] = String(7) "Pikemen" | | ['hp'] = Integer(1) 0 | | ['atk'] = Integer(1) 5 | | ['def'] = Integer(1) 5 | | ['rng'] = Integer(2) 15 | ) | ['9'] => Array (5) | ( | | ['name'] = String(7) "Pikemen" | | ['hp'] = Integer(1) 0 | | ['atk'] = Integer(1) 5 | | ['def'] = Integer(1) 5 | | ['rng'] = Integer(2) 15 | ) | ['10'] => Array (5) | ( | | ['name'] = String(7) "Pikemen" | | ['hp'] = Integer(1) 0 | | ['atk'] = Integer(1) 5 | | ['def'] = Integer(1) 5 | | ['rng'] = Integer(2) 15 | ) | ['11'] => Array (5) | ( | | ['name'] = String(7) "Pikemen" | | ['hp'] = Integer(1) 0 | | ['atk'] = Integer(1) 5 | | ['def'] = Integer(1) 5 | | ['rng'] = Integer(2) 15 | ) | ['12'] => Array (5) | ( | | ['name'] = String(7) "Pikemen" | | ['hp'] = Integer(1) 0 | | ['atk'] = Integer(1) 5 | | ['def'] = Integer(1) 5 | | ['rng'] = Integer(2) 15 | ) | ['13'] => Array (5) | ( | | ['name'] = String(7) "Pikemen" | | ['hp'] = Integer(1) 0 | | ['atk'] = Integer(1) 5 | | ['def'] = Integer(1) 5 | | ['rng'] = Integer(2) 15 | ) ) what i want to do is add the details to a new multi dimensional array but only add one each like so array( ['units'] = array( ['name'] => 'Pikemen', ['lost'] => 14 ) ) basically where the HP is 0 in the first array i need to add them to the second if the name is unique. I have tried array unique but it didnt seem to work. Any ideas? All i get it a loop of each Pikemen Similar TutorialsHey, I have this code below which seems to completely fail sending my laptop cpu fan on a frenzy. All I am wanting to do is find whether the id in the url is located inside the array below else state its not in an error saying its not a valid id (for people who change the url shown below). At the moment it doesnt like the else statement if the isset clause it not true. (I have also tried, array_key_exists) All I can think is that it get stuck looking for an id that doesnt exist inside the array but keeps searching though I dont know much about arrays etc. Besides this when a id is inside the array the script works like I want it to. Any ideas would be much appreciated as this is hold me back at the moment Code: [Select] //url: http://localhost/website/shop.php?id=10197 // Array is built from table prior to this as it will grow in size $_SESSION['storesProducts'] = Array ( [10197] => 0 [10198] => 0 [10199] => 1 [10200] => 1 [10201] => 1 [10202] => 1 [10205] => 0 [10206] => 1 [10207] => 1 ) if(isset($_SESSION['storesProducts'][$id])){ $storesProducts = $_SESSION['storesProducts'][$id]; if($storesProducts == 0){ $list = $this->displayCategories($id); }else{ $createProducts = new constructProducts(); $products = $createProducts->pagination($id); } }else{ $list = "ITS NOT HERE"; } $output = new outputShop(); $output->display($list, $products); hello, i am having an issue with tables using incorrect data. i have 2 columns, first is employee name, second is location if the employee doesnt have a location for the current day, it is telling me he is at the same location as the guy in the row above him. i need this to be blank. is this possible? hi, i have a select which gets todays schedule for each user. sometimes that user doesnt have anything for todays date and it will display the info from the user above him. how can i make it so it stays blank if there is no record? hello all, i have a quick question. i have a select all from toolout with toolid = $tid. the problem is, if there isnt an entry yet in toolout, it is giving me the info from the row above. is there any way that i can do a (if it doesnt exist, set $status to 1, rather than using the previous rows code) my code is below. Code: [Select] if(isset($_POST['search'])) { $tool=$_POST['tool']; echo "<table border='1' style='border-collapse: collapse' bordercolorlight='#000000' bordercolordark='#000000' width='98%' align='center'>"; echo "<tr><td width='100%' colspan='5' align='center'><b>Tool List - $tool</b></td></tr>"; echo "<tr> <th align='center'>Tool</th> <th>Location</th> <th>Status</th> </tr>"; $result = mysql_query("SELECT * FROM tools WHERE toolgroup LIKE '%$tool%' ORDER BY tool"); while($row = mysql_fetch_array($result)) { $id=$row['id']; $tool=$row['tool']; $barcode=$row['barcode']; $location=$row['location']; $result2 = mysql_query("SELECT * FROM toolout WHERE toolid = '$id' ORDER BY id ASC"); while($row2 = mysql_fetch_array($result2)) { $status=$row2['status']; $who=$row2['who']; $datechanged=$row2['datechanged']; $datechanged1 = date( 'M j, Y', strtotime($datechanged) ); if("$status" == "1") { $statusout="<font color='#0000FF' size='4'>IN</font><br /><a href='toolout.php?tool=" . $id . "' target='action'>SIGN OUT</a>"; } if("$status" == "2") { $statusout="<font color='#FF0000' size='4'>OUT</font><br />$who - $datechanged1"; } if("$status" == "3") { $statusout="<font color='#00FF00' size='4'>PENDING OUT</font><br />$who - $datechanged1"; } if("$status" == "4") { $statusout="<font color='#00FF00' size='4'>PENDING IN</font><br />$who - $datechanged1"; } } echo "<tr>"; echo "<td align='center'>" . $tool . "</td>"; echo "<td align='center'>" . $location . "</td>"; echo "<td align='center'>"; if (isset($status)) { echo "$statusout"; } else { echo "<font color='#0000FF' size='4'>IN</font><br /><a href='toolout.php?tool=" . $id . "' target='action'>SIGN OUT</a>"; } echo "</td>"; echo "</tr>"; } echo "</table>"; } Thank you so much. Code: [Select] $arr = array('../', 'j/', 'AcidBB/', 'fileBOMB/', 'OurHome', 'up'); foreach ($arr as $value) { // echo "Value: $value<br /><br />"; if (is_dir($value)) { echo "<tr> <td>{$value}</td> <td><font color='#66FF33'>Exists</font></td></tr><br />"; } else { echo "<tr> <td>{$value}</td> <td><font color='#FF0000'>Does Not Exist</font></td></tr><br />"; } } ~~~ Solved after posting. Sorry. ~~~ Ok i have an Array of directories i need to check before the script installs itself, I know how to check for directories but i dont know how to scan each array in the list without calling each one seperately in Code: [Select] If() { } Else If { } Else If { } And so on and so on... My Question is, If a For Statement is neaded, How would i go about checking each string in the Array List? As the title says, how can i check if multiple arrays exist inside an array or not? Any help is greatly appreciated!
Hi all, hope some can help because this is giving me more grey hairs than I allready have.
I am trying to solve the following: I'm pulling in JSON data, decoding it to a array which I write to a database. However in the array are social security numbers that I don't want to store (privacyregulations). So I need to check if a row has a social security number and if it has one I want to replace it with 'anonymized'. I have got it to work successfully on a local Xampp test environment using the following script (extract off course): //first anonymize the social security number (ssn) if exists $data = json_decode($jsondata, true);
// then fill the tables foreach($data as $row) {
$insertstatement = mysqli_query($link,"INSERT INTO $tablename (personid, type, ssn) VALUES ('".$row["personid"]."', '".$row["type"]."', '".$row["ssn"]."') ON DUPLICATE KEY UPDATE type = VALUES(type), bsn = VALUES(ssn)");
This leads to a filled table where the ssn's are filled with 'anonymized' if they exist in the array and empty if it does not exist for that row. This is exactly what I want ;-).
Personid type ssn
However, when I run the same script on a Lamp production environment (lamp stack on an Azure server) it does not work. Then the scripts results in totally ignoring the whole row that contains a ssn??
Personid type ssn Hope someone can help to get this working on my production environment as well.
Richard
i have error where my code should update existing data where id exist, it get updated ..but the others data is disappeared .only the data updated is remained $sql1 ="select*from semakan_dokumen where email='$stdEmail'";
$sqlsearch1 = mysqli_query($dbconfig,$sql1);
$resultcount1 = mysqli_num_rows($sqlsearch1);
if($resultcount1 > 0){
$query1=("UPDATE semakan_dokumen set student_id='$noMatrik', email= '$stdEmail', surat_tawaran='$fileName', ic='$fileName1',sijil_lahir='$fileName2',sijil_spm= '$fileName3',sijil_sekolah= '$fileName4', sijil_dip= '$fileName5',sej_julai='$fileName6',bm_julai='$fileName7',muet='$fileName8', mid1='$fileName9',yuran= '$fileName10',umpa_bend1= '$fileName11',umpa_bend2='$fileName12',bpkp='$fileName13', penaja='$fileName14',kesihatan= '$fileName15', jhepa='$fileName16' where email= '$stdEmail' ");
}else{
//filezip
$query1 = "INSERT INTO semakan_dokumen (email,surat_tawaran,ic,sijil_lahir,sijil_spm,sijil_sekolah,sijil_dip,sej_julai,bm_julai,muet,mid1,yuran,umpa_bend1,umpa_bend2,bpkp,penaja,kesihatan,jhepa) VALUES ('$stdEmail','$fileName','$fileName1','$fileName2','$fileName3','$fileName4','$fileName5','$fileName6','$fileName7','$fileName8','$fileName9','$fileName10','$fileName11','$fileName12','$fileName13','$fileName14','$fileName15','$fileName16')";
}
if so how would they be used in a mysql query? Hi all, I want to make a script that identifies if an image JPG file exists. Would somthing like this work? <?php $file = "images/image.jpg"; if ($file > 0) { echo "file exists"; } else { echo "no file"; } ?> Hi.. So what i want to do is basicly to check if id XX exist in my database. How can this be done? Im thinking of something like: if(xx exist){do this} else{do this} Iv'e tried google etc before i posted here, but couldent really find anything where i found a soutable answer.. Hope someone can help! (: Basically this gets a number from a table on my DB, and displays the content relevent to that number...the second part checks for that number and gets other information according to that number... what i want to do is make sure that the number from the first query exists in the table from the query, and if it doesn't print out and error saying "there is no information" or whatever.. anyone have an idea? hopefully this makes sense Code: [Select] <?php require_once('Connections/myConnect.php'); $detnum = $_GET['Details']; $detinfo = mysql_query("SELECT* FROM `Agency Stores - Table 1` WHERE F11=".$detnum); $det = mysql_fetch_array($detinfo); $salesnum = $det['F3']; $salesinfo = mysql_query("SELECT* FROM `By Agency Store _` WHERE store_store=".$salesnum); $sales = mysql_fetch_array($salesinfo); if(mysql_query("SELECT* FROM `By Agency Store _` WHERE store_store=".$salesnum)){ } ?> Hi all - I have a form that let's a user upload an image to their specified folder. The folder is determined by the "password" the user inputs. The "password" is really just the folder name on my server, so if "michael83" was entered as a password, the directory would be "images/uploaded/michael83". That works great now, thanks to a forum user, litebearer. Thanks again. Here's my second question: I'm working on a "history" page so that a user can input their "password" and view their upload history. The form works right now. If you enter a "password" (folder name) that exists, the code will spit out the contents / files. So, now I'm looking for two things: (1) if a user enters a "password" (folder name) that exists, but there are no files in the folder, "There are no files in the $dir directory." will be echoed; and (2) if a "password" (folder name) is entered that does NOT exist, "The directory $dir does not exist." will be echoed. Here's my code so far (minus the if statements I'm looking for): $dir = $_POST['password']; $path = "images/uploaded/". $dir; $dir_handle = @opendir($path); while ($file = readdir($dir_handle)) { if($file == "." || $file == ".." ) continue; if(isset($_POST['Submit'])) $url = "http://www.mysite.com/". $path . "/" . $file; { echo "<a href=\"$url\">$url</a><br />"; }} closedir($dir_handle); As always, many thanks in advance for any help on this. Does the concept of a "Namespace" exist in PHP? If so, how do you use them? This is a snippet from ASP.NET that made me ask this question... Quote <%@ Import Namespace="System.Data" %> <%@ Import Namespace="System.Data.SqlClient" %> TomTees Gud pm!! So i made this script to check if a username and password exist but it kinda fails me. It gives me a database connection error from my confirm_query() which means it returned false? so here's my code: Code: [Select] function check_if_exist($username, $password) { global $connection; $query = "SELECT username, hashed_password"; $query .= "FROM users "; $query .= "WHERE username = '$username' "; $query .= "AND hashed_password = '$password' "; $query .= " LIMIT 1"; $result_set = mysql_query($query, $connection); confirm_query($result_set); if(mysql_num_rows($result_set) == 1) { return true; } else { return false; } } my confirm_query(): Code: [Select] function confirm_query($result) { if(!$result) { die("Database connection failure ". mysql_error()); } } I have a another script to check if the email exist and it works perfectly, i dunno why this won't work properly.. maybe another simple mistake.. Any ideas or Violent reaction? Thanks! hi, im having trouble adding a get variable to a url if one already exists. eg current url = http://www.example.com/index.php?var1=something i want to be able to change this to new url = http://www.example.com/index.php?var1=something&var2=another even so i can have a few get variable there. I can add the first var through a form or link, but how would i add more through a link or through the header function? I am positivly stuck. Thanks Is it possible to check if multiple rows exist at the same time. For example, if a row with the id "1" and another row with id "2" exists, and return something like true then false if only the first exists?
I have a file that provides tens of thousands to check and it takes forever. I know this sounds bad off the start, but it's not something that is run normally. Only to update my database with new additions.
Is there any good way to check a lot at once? I know you can insert many at a time and save a lot of time.
I have a field in a table named flights I hope to find a 1 line statement to bypass inserting a new row if $flight_no is already in the field flight_no btw flight_no is the primary key and won't allow a duplicate anyway but I want to avoid the error message this is what I tried but doesn't work if(SELECT * FROM flights WHERE flight_no !LIKE %$flight_no%) { This topic has been moved to Third Party PHP Scripts. http://www.phpfreaks.com/forums/index.php?topic=357281.0 hi, im getting the error Quote Fatal error: Call to undefined function notification() in C:\xampp\htdocs\xampp\index.php on line 21 after including the functions.php file i wrote. It does include it but the data isnt being recognised from it. If i copy/paste the notification() function into index.php it works. Can someone tell me why so i can fix it? |
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