PHP - Retrieving Full Data From A Mysql Database By Clicking On A Single Cell

Hello,

I want to export data from php-mysql to excel in a particular cell.

1. Get the data from php-Mysql and export data to excel sheet. I already create a template excel sheet format.I want to export data from mysql to a particular cell. Sorry I can't able to attach my template excel sheet.
2. Is it possible to export image?


Thanks in advance

Hello to all,

I have problem figuring out how to properly display data fetched from MySQL database in a HTML table.

In the below example I am using two while loops, where the second one is nested inside first one, that check two different expressions fetching data from tables found in a MySQL database. The second expression compares the two tables IDs and after their match it displays the email of the account holder in each column in the HTML table.

The main problem is that the 'email' row is displayed properly while its while expression is not nested and alone(meaning the other data is omitted or commented out), but either nested or neighbored to the first while loop, it is displayed horizontally and the other data ('validity', 'valid_from', 'valid_to') is not displayed.'

Can someone help me on this, I guess the problem lies in the while loop?
Here is part of the HTML code:

<thead>
 <tr>
 <th data-column-id="id" data-type="numeric">ID</th>
 <th data-column-id="email">Subscriber's Email</th>
 <th data-column-id="validity">Validity</th>
<th data-column-id="valid_from">Valid From</th>
 <th data-column-id="valid_to">Valid To</th>
</tr>
</thead>

Here is part of the PHP code:

 

    <?php
    while($row = $stmt->fetch(PDO::FETCH_ASSOC))
    {
        echo '
            <tr>
                <td>'.$row["id"].'</td>
        ';
        while ($row1 = $stmt1->fetch(PDO::FETCH_ASSOC)) {
        echo '
                <td>'.$row1["email"].'</td>
        ';
        }
        if($row["validity"] == 1) {
            echo '<td>'.$row["validity"].' month</td>';
        }else{
            echo '<td>'.$row["validity"].' months</td>';
        }
        echo '  <td>'.$row["valid_from"].'</td>
                <td>'.$row["valid_to"].'</td>
        </tr>';
    }
    ?>

P.S. Please know that I have purposely omitted the connection part and the methods in the class that are used in this code to keep the spot of the problem as clean as possible. If you need me to rephrase the question, please ask.

Thank you.

Hey guys. I just recently started learning php and I like to learn hands on. So, my first project involves the Google Calendar. I found a script on github that is basically a Google calendar feed and I've been manipulating it to meet my personal needs and expectations, but the only thing I am struggling with is the xml part. All I want to do in this case is get the value from ###TITLE###   (after it is sorted by newest date which is done automatically in the script) and store it in a new variable but no matter what I try or do and after reading a bunch of material on xml and php, I still cannot get it to work. If anyone knows how to do this and provide an explanation so I can actually learn I would really really appreciate it. Here is the github script   https://github.com/m...ter/gcalphp.php   Thank you and I am looking forward to any suggestions or anything.

hi guys, im new to this forum

I'm new also to php, I need help from you guys:

I want to display personal information from a certain person (the data is on the mysql database) using his name as a link:

example:
               (index.php)
               names
                          1. Bill Gates
                          2. Mr. nice Guy
           
i want to click Bill Gates
 
   (output.php)
     Name: Bill Gates
     Country:xxxx
     Age: xx   
                 etc.

How can i make this or how to learn this?
   
                 

             
               

   
       

I am trying to insert data from a mysql in a table. I want the data to appear with the image on the left, item name on the top right followed by description underneath.


<?php
$sql = 'SELECT * FROM tbl_products ORDER BY id';
$result = $db->query($sql);
$output[] = '<ul>';
$output[] = '<table border="3" bordercolor="#000000">';
while ($row = $result->fetch()) {

         $output[] = '<tr>';
         $output[] = '<td><img src="images/'.$row['pic'].'" width="67" height="100" /></td>';
         $output[] = '<td class="style10"><strong>'.$row['item_name'].'</strong></td>';
         $output[] = '<td>'.$row['item_description'].'</td>';
         $output[] = '</tr>';

}
$output[] = '</table>';
echo join('',$output);
?>

I would like the items to appear the same way as this page

http://aafcollection.info/items/list.php

hello friends,
actually i am trying to insert data in mysql
database.
here is my code

<?php
	include_once("../includes/database.php");
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Insert Product</title>
</head>

<body>
	<form action="insert_product.php" method="post" enctype="multipart/form-data">
    	<table align="center" width="600">
        <tr align="center">
        	<td colspan="8"><h2> Insert New Post</h2></td>
        </tr>
        <tr>
        	<td align="right"><b>Product Title :</b></td>
            <td><input type="text" name="product_title"  size="50" style="background-color:#06C; color:#FFF"  /></td>
        </tr>
         <tr>
        	<td align="right"><b>Product Category :</b></td>
            <td>
            	<select name="product_cat" style="background-color:#06C; color:#FFF" >
                	<option>Select A Category </option>
                    <?php 
						$get_cats = "SELECT * FROM categories";	
						$run_cats = mysqli_query($con, $get_cats);
						while($row_cats = mysqli_fetch_array($run_cats)){
							$cat_id = $row_cats['cat_id'];
							$cat_title = $row_cats['cat_title'];
							echo "<option value='$cat_id'>$cat_title</option>";
						}
					?>
                </select>
            </td>
        </tr>
         <tr>
        	<td align="right"><b>Product Platform :</b></td>
            <td>
            	<select name="product_brand" style="background-color:#06C; color:#FFF" >
                	<option>Select A Platform </option>
                    <?php 
						$get_brands = "SELECT * FROM brands";	
						$run_brands = mysqli_query($con, $get_brands);
						while($row_brands = mysqli_fetch_array($run_brands)){
							$brand_id = $row_brands['brand_id'];
							$brand_title = $row_brands['brand_title'];
							echo "<option value='$brand_id'>$brand_title</option>";
						}
					?>
                </select>
            </td>
        </tr>
         <tr>
        	<td align="right"><b>Product Image :</b></td>
            <td><input type="file" name="product_image"  /></td>
        </tr>
         <tr>
        	<td align="right"><b>Product Price :</b></td>
            <td><input type="text" name="product_price" style="background-color:#06C; color:#FFF"  /></td>
        </tr>
         <tr>
        	<td align="right" valign="top"><b>Product Description :</b></td>
            <td><textarea name="product_desc" cols="50" rows="10" style="background-color:#06C; color:#FFF"  ></textarea></td>
        </tr>
         <tr>
        	<td align="right"><b>Product Keywords :</b></td>
            <td><input type="text" name="product_keywords" size="50" style="background-color:#06C; color:#FFF" /></td>
        </tr>
         <tr align="center">
            <td colspan="8"><input type="submit" name="insert_post" value="Submit Now" /></td>
        </tr>
        </table>
    </form>
</body>
</html>

<?php
	if(isset($_POST['insert_post'])){
		$product_title = $_POST['product_title'];
		$product_cat = $_POST['product_cat'];
		$product_brand = $_POST['product_brand'];
		$product_price = $_POST['product_price'];
		$product_desc = $_POST['product_desc'];
		$product_keywords = $_POST['product_keywords'];
		$product_image = $_FILES['product_image']['name'];
		$product_image_tmp = $_FILES['product_image']['tmp_name'];
		move_uploaded_file($product_image_tmp,"product_image/$product_image");
		
		$sql = "INSERT INTO products (product_cat,product_brand,product_title,product_price,product_desc,product_image,product_keywords) VALUES ('$product_cat','$product_brand','$product_title','$product_price','$product_desc','$product_image','$product_keywords')";
		$query = mysqli_query($con, $sql);
		if($query){
			echo "<script>alert('Product Has Been Inserted')</script>";	
			echo "<script>windoow.open('insert_product.php','_self')</script>";
			exit();
		}else{
			echo "<script>alert('errror')</script>";	
		}
	}
?> 
 

but somehow its not inserting
data into my table can somebody tell wherre
m i doing mistake.

the categories and brands are displaying from database. But its not inserting data

here is my database script.

 <?php
 $con = mysqli_connect("localhost","root","","sg");
?>    

I need to display the last 30 days entries from database in PHP and here is the code that i am currently using, but its not working.

While entering the data in database, the date format that i am using is this...
Code: [Select]
$subon = date("F j, Y, g:i a");
And to display the code i am using this query...
Code: [Select]
$start_date = date("F j, Y, g:i a", strtotime('-30 days'));
$curr_date = date("F j, Y, g:i a");
$sql = "SELECT * FROM table WHERE status = 'approved' AND subon BETWEEN '$start_date' AND '$curr_date' ORDER BY ID DESC LIMIT 0, 5";
And then i am using the usual stuff to display the data but its not working.

Somebody please help me... Thanks in advance.

Hello, I'm new to this forum and I need some help. I'm creating a simple database that it submits data from a user input. Unfortunatly, it's not sending any data to mysql also the form is not validating each field.

Code: [Select]
<?php

if (isset($_POST['submitted'])){

$fields = array(
'email',
'state',
'district',
'gender',
'age',
'profession',
'survey',
);

foreach($fields as $fieldName) {
if(isset($_POST[$fieldName]) and trim($_POST[$fieldName]) !==''){
$fieldName = trim($_POST[$fieldName]);
}else {

$errors[] = "Please enter your". $fieldName .""; //code to validate fields
}
}
if(isset($errors)){

require_once('Connections/encourage.php');

$query = "INSERT INTO participants (email, state, district, gender, age, profession, survey) 
VALUES ('$email', '$state', '$district', '$gender', '$age', '$profession','$survey')"; //databasse connection
   
$result = mysql_query ($query); 

if ($result){

echo '<h1 id="mainhead">Thanks for submitting</hl>
<p>You are now registered</p>';
exit();

}else{

echo '<h1 id="mainhead">System Error</hl>
<p>Your registration could not be completed due to a system error We apologize for any incovience</p>';//gives system error
echo 'p' . mysql_error(). '<br /><br />Query: ' . $query . '</p>';
exit();

}
mysql_close();

} else { 

echo '<h1 id="mainhead">Error!</h1>
<p class="error">The following error(s) occurred:<br />';
foreach($errors as $msg) {
echo " - $msg<br/>\n";
}
echo '</p><p>Please try again.</p><p><br/></p>';
}

}
?>
  <form id="form1" name="form1" method="post" action"registration.php">
  <fieldset class="first">
  <label class="lableone" for="email">Email:* </label>
  <input name="email" value="<?php if(isset($_POST['email'])) echo $_POST['name'];?>"/>
 
  <label for="state"/>State:* </label>
  <input name="state" value="<?php if(isset($_POST['state'])) echo $_POST['state'];?>"/>
 
  <label for="schooldistrict"/>School District:* </label>
  <input name="schooldistrict" value="<?php if(isset($_POST['district'])) echo $_POST['district'];?>" />
 
  <label for="gender">Gender:* </label>
 <select name="gender">
   <option>Choose Your Gender</option>
   <option value="male" <?php echo ($form['gender'] == 'male' ? ' selected' : ''); ?>>Male</option>
   <option value="female"<?php echo ($form['gender'] == 'female' ? ' selected' : ''); ?>>Female</option>
 </select>
 
    <label for="age"/>Your Age:* </label>
  <input name="age" type="text" class="age" maxlength="2" value="<?php if(isset($_POST['age'])) echo $_POST['age'];?>"  />
 
  <label for="profession"/>Profession:* </label>
  <input name="profession" value="<?php if(isset($_POST['age'])) echo $_POST['age'];?>" />
 
  <label for="surveys"/>Willingness to participate in future surveys: </label>
  <input name="surveys" type="checkbox" id="surveys" value="yes" <?php echo ($form['survey'] == 'yes' ? 'checked' : '');?>/>
 
  </fieldset>
<fieldset>
  <input class="btn" name="submit" type="submit" value="Submit" />
<input class="btn" name="reset" type="reset" value="Clear Form" />
<input type="hidden" name="submitted" value="TRUE" />
</fieldset>

  </form>


Can someone help me out? Thanks in advanced! 

Hi,

I'm having trouble adding data to the database (test) that i created. I just can't see where I'm going wrong. need some other peoples opinions.

I have tried taking the id out of the SQL statement completely as it is an auto increment, but that doesn't seem to work either.

Thanks in advance...


<?php

$fname = $_POST['fname'];
$sname = $_POST['sname'];
$email = $_POST['email'];
$pword = $_POST['password'];
$gender = $_POST['gender'];
   
$user_name = "root";
$password = "";
$database = "test";
$server = "127.0.0.1";

$db_handle = mysql_connect($server, $user_name, $password);

$db_found = mysql_select_db($database, $db_handle);

if ($db_found)
{
$SQL = "INSERT INTO members (id, fname, sname, email, password, gender) VALUES (NULL, $fname, $sname, $email, $pword, $gender);";
$result = mysql_query($SQL);

mysql_close($db_handle);

print "Thanks for joining us ".$fname.".";
print "<br /><br />";
print $fname . "<br />";
print $sname . "<br />";
print $email . "<br />";
print $pword . "<br />";
print $gender . "<br />";
}
else
{
print "Database NOT Found";
mysql_close($db_handle);
}

?>

I am trying to display data from mysql. Each row from the mysql database shows up under rows.

I want the rows of data from mysql  to appear in colums of 4.

can some one help please.

<?php
$sql = 'SELECT * FROM dbtable ORDER BY id';
$result = $db->query($sql);
$output[] = '<ul>';
while ($row = $result->fetch()) {
      $output[] = '<table>';
         $output[] = '<tr>';
         $output[] = '<td class="style10"><strong>'.$row['item'].'</strong></td>';
         $output[] = '</tr>';
         $output[] = '<tr>';
         $output[] = '<td><img src="images/'.$row['pic'].'" width="100" height="150" /></td>';
         $output[] = '</tr>';
         $output[] = '<tr>';
         $output[] = '<td>'.$row['description'].'</td>';
         $output[] = '</tr>';
      $output[] = '</table>';
}
echo join('',$output);
?>

Ugh. Ive been asking so many questions, betcha already know my name. Hahah.
Anyways, I know I already asked a question like this, but this is different.
One of the values I am trying to insert into a database is simply not working.
Here is the columnes in my mysql database:

c_id   commet       story   user      date_added   star
Every value but 'commet' is getting inserted into database.  NO error, no mysql errror. I have racked my brain trying to figure out what is wrong with the script.
Here is my code:
Code: [Select]
<?php
$idget = $_GET['id'];
mysqlConnect();
//submit story
if(isset($_POST['submit']))
{
   $com_form = mysql_real_escape_string(bb($_POST['commet']));
   $rat_form = $_POST['rat'];
   $story_form =  $idget;
   $user = $_SESSION['user'];
   $date = date("Y-m-d");
   $query1 = "
   INSERT INTO story_commets(star, story, user, date_added, commet)
   VALUES($rat_form, '$story_form', '$user', '$date', '$com_form')
   ";
   mysql_query($query1) or die(mysql_error());


      
      
   //}
}

// desplay reviews


$query3 = "
SELECT * FROM story_commets
WHERE story = '$idget'
ORDER BY date_added
";
$select3 = mysql_query($query3) or die(mysql_error());
//$x=1;
$ratav = array();
//if(mysql_num_rows($select3) == 0)
//{
   echo '<div id="message"> No Reviews Yet.... <>';
   
//}
//else
//{
while($rows3 = mysql_fetch_assoc($select3))
{
   
   
   $commetdb = $rows3['commet'];
   $user_com_db = $rows3['user'];
   $datedb = $rows3['date_added'];
   $stardb = $rows3['star'];
   //get profile picture
   $query4 = "
   SELECT * FROM login_info
   WHERE user = '$user_com_db'
   ";   
   $select4 = mysql_query($query4) or die(mysql_error());
   
   $rows4 = mysql_fetch_assoc($select4) or die(mysql_error());
      $profile_pic = $rows4['profile_picture'];
      $user_id = $rows4['id'];
   echo "
   <div class='rev_cont'>
   <div class='info'>
   <img src='$profile_pic' /> 
   <a href=?p=profile&id=$user_id> $user_com_db </a> 
   

   
   <> <br /> 
   <div class='rev'>
   <strong> $stardb/10 </strong> <br />
   $commetdb
   <> 
   <div id='date'>  <em> Date Added: $datedb </em> <> 
   <>
   <hr />
   
   
     ";
   
   $ratav[]=$stardb; 
   
     
     
}




$sum = array_sum($ratav);

$count = count($ratav);
$av = $sum / $count;
$avf = round($av, 1);
echo"<div id='message'> Rating Avarage: $avf /10 <>";
//}
if (isset($_SESSION['user']))
{
   echo"
   <p> Did you like this story? Did you hate it? Give it a rating and let the author know!</p>
<form action='?p=review&id=$idget' method='post'  target='_self'> 
 
 <label> Your rating is on a scale of 1-10 </label>
 <select name='rat'>
    <option> 1 </option>
    <option> 2 </option>
    <option> 3 </option>
    <option> 4 </option>
    <option> 5 </option>
    <option> 6 </option>
    <option> 7  </option>
    <option> 8 </option>
    <option> 9 </option>
    <option> 10 </option>
 </select>
 <label> Commets: </label>
 
 <textarea name='commet' cols='70' rows='9'></textarea>
 <input name='story' type='hidden' value='$idget' /> <br />
 <input type='submit' value = 'Post' name='submit' />
</form>

   ";
}
else 
{
   echo "<div id='message'> Sign in to post a review! <>";
}

?>



Here are the specifics if you want it.

Here is the response part of the code:
Code: [Select]
<?php
if(isset($_POST['submit']))
{
   $com_form = mysql_real_escape_string(bb($_POST['commet']));
   $rat_form = $_POST['rat'];
   $story_form =  $idget;
   $user = $_SESSION['user'];
   $date = date("Y-m-d");
   $query1 = "
   INSERT INTO story_commets(star, story, user, date_added, commet)
   VALUES($rat_form, '$story_form', '$user', '$date', '$com_form')
   ";
   mysql_query($query1) or die(mysql_error());


      
      
   //}
}
?>
Here is the form part of my code:
Code: [Select]
<?php
if (isset($_SESSION['user']))
{
   echo"
   <p> Did you like this story? Did you hate it? Give it a rating and let the author know!</p>
<form action='?p=review&id=$idget' method='post'  target='_self'> 
 
 <label> Your rating is on a scale of 1-10 </label>
 <select name='rat'>
    <option> 1 </option>
    <option> 2 </option>
    <option> 3 </option>
    <option> 4 </option>
    <option> 5 </option>
    <option> 6 </option>
    <option> 7  </option>
    <option> 8 </option>
    <option> 9 </option>
    <option> 10 </option>
 </select>
 <label> Commets: </label>
 
 <textarea name='commet' cols='70' rows='9'></textarea>
 <input name='story' type='hidden' value='$idget' /> <br />
 <input type='submit' value = 'Post' name='submit' />
</form>

   ";
}
else 
{
   echo "<div id='message'> Sign in to post a review! <>";
}
?>
Its probably something really mundane. HelP!

I am having difficulty inserting the following codes values into my database. I know that the variables contain a value as I am displaying them on the output screen.


Code: [Select]
$link = mysql_connect($db_host,$db_user,$db_pass) or die('Unable to establish a DB connection');

mysql_select_db($db_database,$link);
mysql_query("SET names UTF8");
$usr = $userid;
$golfer = $_REQUEST['golfer'];
$tourney = $_REQUEST['tournament'];
$backup = $_REQUEST['backup'];
date_default_timezone_set('US/Eastern');
$time = date("Y-m-d H:i:s");
$t_id=1;



mysql_query("INSERT INTO weekly_picks (t_id, tournament, user, player, backup, timestamp) VALUES ('$t_id', '$tournament', '$usr', '$golfer', '$backup', '$time') or die('Error, insert query failed')");

echo $t_id; echo "<br />";
echo $tourney; echo "<br />";
echo $usr; echo "<br />";
echo $golfer; echo "<br />";
echo $backup; echo "<br />";
echo $time; echo "<br />";
echo $userdetail['email']; echo "<br />";

$to = $userdetail['email'];
$subject = "Weekly Tournament Pick for: $tourney";
$message = "This email is to confirm your pick for $tourney has been received.
Your pick is: $golfer.
Your backup pick is: $backup
The time it was submitted was $time
Do not reply to this email, the mailbox does not exist.
Contact me with any issues at xxxxxxx@xxxxxxx.com";

$from = "noreply@chubstersgcc.com";
$headers = "From:" . $from;
mail($to,$subject,$message,$headers);
?>

<div>
<p>This is to confirm that your pick has been submitted for the following tournament: <?php echo $tourney; ?>. A confirmation of your pick as also been emailed to you.</p>
<p>Your golfer: <?php echo $golfer; ?></p>
<p>Your backup: <?php echo $backup; ?></p>
<p>Your pick was submitted at: <?php echo $time; ?></p>
</div>

I'm a beginner to PHP and am stuck as to how I can fetch data from a MYSQL database and output that information in html to the website. Currently I get the information from the database using normal php:

$result = mysql_query("SELECT * FROM truffleProducts");

Then I assign each field from the database to a php variable in a while loop:
 

while ($row = mysql_fetch_array($result)) {
$id = $row{'id'};
$name = $row{'name'};
$price = $row{'Price_per_kg'};
$season = $row{'Season'};
$country = $row{'Country'};
$image = $row{'image'};
$review = $row{'review'};
}

Then I just print each variable in a table using simple html and php. My problem is that it only outputs the latest element or row from my database. I want to output the database within a HTML template so that it is professional and tidy, but i cant figure out how to do that. Any help?
Edited by louiscb, 22 October 2014 - 07:58 AM.

I have got connection to the the mysql database, how do I get the data from the database to display on the webpage