PHP - Adding A Where To This Query
Hi,
This is probably very easy for someone who knows how but I cant seem to get it working. Can someone please tell me how I can alter this query to select a 'WHERE gender = female' so instead of picking a random user it picks a random female user ? Code: [Select] $offset_result = mysql_query( " SELECT FLOOR(RAND() * COUNT(*)) AS `offset` FROM `users` "); $offset_row = mysql_fetch_object( $offset_result ); $offset = $offset_row->offset; $user1b = mysql_query( " SELECT * FROM `users` LIMIT $offset, 1 " ); $user1= mysql_fetch_array($user1b); Also, would it be easy to modify it so it picks a second random user that isnt the same as the first user ? so I end up with 2 random females ( $user1 and $user2 ) Many thanks, Scott Similar TutorialsI need to add likes_username to this query and use a DISTINCT on it.
It currently counts how many likes a status has but in the table there are some statuses with multiple likes from the same username.
SELECT s.*, COUNT(l.likes_location_id) AS likeCount FROM stream AS s LEFT JOIN likes AS l ON ( l.likes_location_id = s.stream_id ) GROUP BY s.stream_id ORDER BY s.stream_id DESC LIMIT 50Many thanks, If ($_GET['CODE'] == '1') { $ThreadID = mysql_escape_string($_GET['threadid']); $ForumID = mysql_result(mysql_query("SELECT forum_id FROM ".FORUM_THREADS." WHERE thread_id='{$ThreadID}'", $db), 0, 'forum_id'); $PostText = mysql_escape_string($_POST['replytext']); $IP = $_SERVER['REMOTE_ADDR']; $PostQuery = "INSERT INTO ".FORUM_POSTS." (`user_id`, `thread_id`, `post_text`, `forum_id`, `ip_address`, `timestamp`) VALUES ('{$memid}', '{$ThreadID}', '{$PostText}', '{$ForumID}', '{$IP}' , CURRENT_TIMESTAMP)"; $PostRes = mysql_query($PostQuery, $db); For some reason whenever this query goes through, it also adds a blank result using all the same information but without any $PostTest so essentially it does query: Code: [Select] INSERT INTO ".FORUM_POSTS." (`user_id`, `thread_id`, `post_text`, `forum_id`, `ip_address`, `timestamp`) VALUES ('{$memid}', '{$ThreadID}', '', '{$ForumID}', '{$IP}' , CURRENT_TIMESTAMP) This is the only query that does this part of the code and I can't see why it is adding 2 queries. FORUM_POSTS = constant containing table name. So I have this snippet of code: Code: [Select] $row['ratings'] = ""; $ratingsSQL = $this->ipsclass->DB->query( "SELECT `pid` , `rating` , COUNT(`rating`) as ratings FROM `ibf_ratings` WHERE `pid` = '" . $row['pid'] . "' GROUP BY `rating` "); $i = 0; $ratingshtml = ""; if( $this->ipsclass->DB->get_num_rows( $ratingsSQL ) ) { while( $rrow = $this->ipsclass->DB->fetch_row( $ratingsSQL ) ) { $ratingshtml .= "<div class=\"rate_it_display\" style=\"background-image: url( 'style_images/rate/" . str_replace( ' ' , '' , strtolower( $this->ratings[$rrow['rating']] ) ) . ".png' ) \"> " . $rrow['ratings']. " x " . $this->ratings[$rrow['rating']] . "!</div>"; $i++; } $ratingshtml .= "<a href=\"#\" onclick=\"return RateItExpand( {$row['pid']} );\" style=\"color: #999;\">(list)</a>"; } $row['ratings'] = $this->ipsclass->compiled_templates['skin_topic']->ratings( $row['pid'] , $row['author_id'] , $ratingshtml ); I want to add an if statement to the code so that the ratings won't load unless a user clicks a button at the top of the screen. Can anyone help me with this? I'd be very appreciative. Thanks in advance. Greetings, I need a bit of php coding help. I have a query that gives me results. What I need to do is take those results and, I think, use php to compare the results and add a 1 to the correct section. Example: 3 tables table name- retail_sales id sales_id amount week table name- online_sales id sales_id amount week table name- sales_person sales_id name I have the query that breaks down results by week: week 1 | retail_sales.amount | online_sales.amount What I need is some php code that will then compare the two together and: if retail_sales.amount > online_sales.amount +1 to retail OR if retail_sales.amount < online_sales.amount +1 to online so you would end up with a result like a sports record (6-2) Any ideas Thank you for any help Hello, The query below works well. It pulls information from 3 MySQL tables: login, submission, and comment. It creates a value called totalScore2 based on calculation of values pulled from these three tables. The MySQL tables "comment" and "submission" both have the following fields: Code: [Select] loginid submissionid In the table "submission," each "submissionid" has only one entry/row, and thus only one "loginid" associated with it. In the table "comment," the field "submissionid" could have several entries/rows, and could be associated with multiple "loginid"s. Each time one of the "submissionid"s in "comment" is associated with the same "loginid" that it has in the table "submission," I would like to add this as a factor to the equation below. I would like to multiple instances like this times (-10). How could I do this? Thanks in advance, John $sqlStr2 = "SELECT l.loginid, l.username, l.created, DATEDIFF(NOW(), l.created) + COALESCE(s.total, 0) * 5 + COALESCE(scs.total, 0) * 10 + COALESCE(c.total, 0) AS totalScore2 FROM login l LEFT JOIN ( SELECT loginid, COUNT(1) AS total FROM submission GROUP BY loginid ) s ON l.loginid = s.loginid LEFT JOIN ( SELECT loginid, COUNT(1) AS total FROM comment GROUP BY loginid ) c ON l.loginid = c.loginid LEFT JOIN ( SELECT S2.loginid, COUNT(1) AS total FROM submission S2 INNER JOIN comment C2 ON C2.submissionid = S2.submissionid GROUP BY S2.loginid ) scs ON scs.loginid = l.loginid GROUP BY l.loginid ORDER BY totalScore2 DESC LIMIT 25"; Is it possible to add a query string for example some_var=jk84 to any sort of link be it, http://www.website.com , http://www.website.com/?some_id=4, or http://www.website.com/post=45&category=9 or http://www.website.com/somepost/ ? While adding that extra query string how can I make sure I'm not affecting the website's content or causing some script error? mysql_query("update pupils set record='running' where pid !='$testing[0]' Say I do a query from a database that only asks for one field in return (which always has a number in it). How do you write the PHP to take the first number returned and add it to the next number returned (NOTE: There may be more than two numbers returned, but for now, I'm always dealing with two) For example, say I do a query that returns the number 27 first and then the number 10 second. FYI, these numbers will be available in the variable $diff['result']. So the code after the query would look something like this, but obviously i'm struggling with the part in comments... Code: [Select] if (!$numbers) { die("Database query failed: " . mysql_error()); } else { while ($diff = mysql_fetch_array($numbers)) { //this would bring back 27 first, in the variable $diff['result'] and then on the 2nd loop through, it would bring back 10 in the $diff['result'] variable //ultimately, i just want the difference between the numbers (which in the case would be 17). It's just a simple addition, so Im obviously an idiot because I can't figure out the syntax for adding the first returned number to the next returned number:) } } HI. I have written a mysql database query to add up invoice totals. It seems to be automatilaly adding .01 to the result when I run a group by. Let me explain more ..
When I do a select on the field that I am adding up the result is $132.25 - the query is as follows
select ttl_invoice_due from 65_it where st_id = 96011;
When I run the following query that uses sum and group by - the $132.25 becomes $132.26 - the sum query is
SELECT 65_st.job_compid, 65_client.uid_client, 65_client.comp_name, Sum(65_it.ttl_invoice_due) AS SumOftotal_due, Sum(65_it.ttl_invoice) AS SumOftotal_invoice, Sum(65_it.ttl_invoice_payments) AS SumOftotal_amnt_paid FROM 65_client INNER JOIN (65_st INNER JOIN 65_it ON 65_st.st_id = 65_it.st_id) ON 65_client.uid_client = 65_st.uid_client WHERE 65_st.uid_client = 1905 and 65_st.job_compid = 1 and 65_st.sales_date<=curdate() GROUP BY 65_st.job_compid, 65_client.uid_client HAVING (((Sum(65_it.ttl_invoice_due))<>0)) order by 65_client.comp_name;
The 65_it.ttl_invoice_due field is defined in the table as Double(12,2)
I dont know why the sum is returing $132.26 where it should be $132.25 as in the simple query ?.
So I'm querying my database to add the results (mapID's) into a PHP array. The MySQL query I used in the below code would usually return 10 values (only 10 mapID's in the database) Code: [Select] while($data = mysql_fetch_array(mysql_query("SELECT mapID FROM maps"))){ $sqlsearchdata[] = $data['mapID']; } Instead the page takes ages to load then gives this error: Quote Fatal error: Allowed memory size of 8388608 bytes exhausted (tried to allocate 16 bytes) It says the error begins on the first line of the above code. I'm assuming this is not the right way to add the value from the MySQL array into a normal PHP array. Can anyone help me? Hello all,
Based on the suggestion of you wonderful folks here, I went away for a few days (to learn about PDO and Prepared Statements) in order to replace the MySQLi commands in my code. That's gone pretty well thus far...with me having learnt and successfully replaced most of my "bad" code with elegant, SQL-Injection-proof code (or so I hope).
The one-and-only problem I'm having (for now at least) is that I'm having trouble understanding how to execute an UPDATE query within the resultset of a SELECT query (using PDO and prepared statements, of course).
Let me explain (my scenario), and since a picture speaks a thousand words I've also inlcuded a screenshot to show you guys my setup:
In my table I have two columns (which are essentially flags i.e. Y/N), one for "items alreay purchased" and the other for "items to be purchased later". The first flag, if/when set ON (Y) will highlight row(s) in red...and the second flag will highlight row(s) in blue (when set ON).
I initially had four buttons, two each for setting the flags/columns to "Y", and another two to reverse the columns/flags to "N". That was when I had my delete functionality as a separate operation on a separate tab/list item, and that was fine.
Now that I've realized I can include both operations (update and delete) on just the one tab, I've also figured it would be better to pare down those four buttons (into just two), and set them up as a toggle feature i.e. if the value is currently "Y" then the button will set it to "N", and vice versa.
So, looking at my attached picture, if a person selects (using the checkboxes) the first four rows and clicks the first button (labeled "Toggle selected items as Purchased/Not Purchased") then the following must happen:
1. The purchased_flag for rows # 2 and 4 must be switched OFF (set to N)...so they will no longer be highlighted in red.
2. The purchased_flag for row # 3 must be switched ON (set to Y)...so that row will now be highlighted in red.
3. Nothing must be done to rows # 1 and 5 since: a) row 5 was not selected/checked to begin with, and b) row # 1 has its purchase_later_flag set ON (to Y), so it must be skipped over.
Looking at my code below, I'm guessing (and here's where I need the help) that there's something wrong in the code within the section that says "/*** loop through the results/collection of checked items ***/". I've probably made it more complex than it should be, and that's due to the fact that I have no idea what I'm doing (or rather, how I should be doing it), and this has driven me insane for the last 2 days...which prompted me to "throw in the towel" and seek the help of you very helpful and intellegent folks. BTW, I am a newbie at this, so if I could be provided the exact code, that would be most wonderful, and much highly appreciated.
Thanks to you folks, I'm feeling real good (with a great sense of achievement) after having come here and got the great advice to learn PDO and prepared statements.
Just this one nasty little hurdle is stopping me from getting to "end-of-job" on my very first WebApp. BTW, sorry about the long post...this is the best/only way I could clearly explaing my situation.
Cheers guys!
case "update-delete": if(isset($_POST['highlight-purchased'])) { // ****** Setup customized query to obtain only items that are checked ****** $sql = "SELECT * FROM shoplist WHERE"; for($i=0; $i < count($_POST['checkboxes']); $i++) { $sql=$sql . " idnumber=" . $_POST['checkboxes'][$i] . " or"; } $sql= rtrim($sql, "or"); $statement = $conn->prepare($sql); $statement->execute(); // *** fetch results for all checked items (1st query) *** // $result = $statement->fetchAll(); $statement->closeCursor(); // Setup query that will change the purchased flag to "N", if it's currently set to "Y" $sqlSetToN = "UPDATE shoplist SET purchased = 'N' WHERE purchased = 'Y'"; // Setup query that will change the purchased flag to "Y", if it's currently set to "N", "", or NULL $sqlSetToY = "UPDATE shoplist SET purchased = 'Y' WHERE purchased = 'N' OR purchased = '' OR purchased IS NULL"; $statementSetToN = $conn->prepare($sqlSetToN); $statementSetToY = $conn->prepare($sqlSetToY); /*** loop through the results/collection of checked items ***/ foreach($result as $row) { if ($row["purchased"] != "Y") { // *** fetch one row at a time pertaining to the 2nd query *** // $resultSetToY = $statementSetToY->fetch(); foreach($resultSetToY as $row) { $statementSetToY->execute(); } } else { // *** fetch one row at a time pertaining to the 2nd query *** // $resultSetToN = $statementSetToN->fetch(); foreach($resultSetToN as $row) { $statementSetToN->execute(); } } } break; }CRUD Queston.png 20.68KB 0 downloads Here is my code: // Start MySQL Query for Records $query = "SELECT codes_update_no_join_1b" . "SET orig_code_1 = new_code_1, orig_code_2 = new_code_2" . "WHERE concat(orig_code_1, orig_code_2) = concat(old_code_1, old_code_2)"; $results = mysql_query($query) or die(mysql_error()); // End MySQL Query for Records This query runs perfectly fine when run direct as SQL in phpMyAdmin, but throws this error when running in my script??? Why is this??? Code: [Select] You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '= new_code_1, orig_code_2 = new_code_2WHERE concat(orig_code_1, orig_c' at line 1 If you also have any feedback on my code, please do tell me. I wish to improve my coding base. Basically when you fill out the register form, it will check for data, then execute the insert query. But for some reason, the query will NOT insert into the database. In the following code below, I left out the field ID. Doesn't work with it anyways, and I'm not sure it makes a difference. Code: Code: [Select] mysql_query("INSERT INTO servers (username, password, name, type, description, ip, votes, beta) VALUES ($username, $password, $name, $server_type, $description, $ip, 0, 1)"); Full code: Code: [Select] <?php include_once("includes/config.php"); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title><? $title; ?></title> <meta http-equiv="Content-Language" content="English" /> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" /> <link rel="stylesheet" type="text/css" href="style.css" media="screen" /> </head> <body> <div id="wrap"> <div id="header"> <h1><? $title; ?></h1> <h2><? $description; ?></h2> </div> <? include_once("includes/navigation.php"); ?> <div id="content"> <div id="right"> <h2>Create</h2> <div id="artlicles"> <?php if(!$_SESSION['user']) { $username = mysql_real_escape_string($_POST['username']); $password = mysql_real_escape_string($_POST['password']); $name = mysql_real_escape_string($_POST['name']); $server_type = mysql_real_escape_string($_POST['type']); $description = mysql_real_escape_string($_POST['description']); if(!$username || !$password || !$server_type || !$description || !$name) { echo "Note: Descriptions allow HTML. Any abuse of this will result in an IP and account ban. No warnings!<br/>All forms are required to be filled out.<br><form action='create.php' method='POST'><table><tr><td>Username</td><td><input type='text' name='username'></td></tr><tr><td>Password</td><td><input type='password' name='password'></td></tr>"; echo "<tr><td>Sever Name</td><td><input type='text' name='name' maxlength='35'></td></tr><tr><td>Type of Server</td><td><select name='type'> <option value='Any'>Any</option> <option value='PvP'>PvP</option> <option value='Creative'>Creative</option> <option value='Survival'>Survival</option> <option value='Roleplay'>RolePlay</option> </select></td></tr> <tr><td>Description</td><td><textarea maxlength='1500' rows='18' cols='40' name='description'></textarea></td></tr>"; echo "<tr><td>Submit</td><td><input type='submit'></td></tr></table></form>"; } elseif(strlen($password) < 8) { echo "Password needs to be higher than 8 characters!"; } elseif(strlen($username) > 13) { echo "Username can't be greater than 13 characters!"; } else { $check1 = mysql_query("SELECT username,name FROM servers WHERE username = '$username' OR name = '$name' LIMIT 1"); if(mysql_num_rows($check1) < 0) { echo "Sorry, there is already an account with this username and/or server name!"; } else { $ip = $_SERVER['REMOTE_ADDR']; mysql_query("INSERT INTO servers (username, password, name, type, description, ip, votes, beta) VALUES ($username, $password, $name, $server_type, $description, $ip, 0, 1)"); echo "Server has been succesfully created!"; } } } else { echo "You are currently logged in!"; } ?> </div> </div> <div style="clear: both;"> </div> </div> <div id="footer"> <a href="http://www.templatesold.com/" target="_blank">Website Templates</a> by <a href="http://www.free-css-templates.com/" target="_blank">Free CSS Templates</a> - Site Copyright MCTop </div> </div> </body> </html> Say I have this query: site.com?var=1 ..I have a form with 'var2' field which submits via get. Is there a way to produce: site.com?var=1&var2=formdata I was hoping there would be a quick way to affix, but can't find any info. Also, the query could sometimes be: site.com?var2=formdata&var=1 I would have to produce: site.com?var2=updatedformdata&var=1 Is my only option to further parse the query? I'm trying to update every record where one field in a row is less than the other. The code gets each row i'm looking for and sets up the query right, I hope I combined the entire query into one string each query seperated by a ; so it's like UPDATE `table` SET field2= '1' WHERE field1= '1';UPDATE `table` SET field2= '1' WHERE field1= '2';UPDATE `table` SET field2= '1' WHERE field1= '3';UPDATE `table` SET field2= '1' WHERE field1= '4';UPDATE `table` SET field2= '1' WHERE field1= '5'; this executes properly if i run the query in phpMyAdmin, however when I run the query in PHP, it does nothing... Any advice? I was just wondering if it's possible to run a query on data that has been returned from a previous query? For example, if I do Code: [Select] $sql = 'My query'; $rs = mysql_query($sql, $mysql_conn); Is it then possible to run a second query on this data such as Code: [Select] $sql = 'My query'; $secondrs = mysql_query($sql, $rs, $mysql_conn); Thanks for any help here's the code: Code: [Select] $companyName = 'big company'; $address1 = 'big bay #8'; $address2 = 'some big warehouse'; $city = 'big city'; $province = 'AB'; $postalCode = 'T1T0N0'; $phone = '0123456789'; $email2 = 'bigKahuna@bigKahuna.edu'; $query = "INSERT INTO clients ( companyName, address1, address2, city, province, postalCode, phone, email) VALUES ( ". $companyName.",".$address1.",".$address2.",".$city.",".$postalCode.",".$phone.",".$email2.")"; $result = mysql_query($query, $connexion); if ($result) { // Success! echo "Fabulous! check the DB, we did it! :D<br>"; ?> <pre> <?php print_r($result); ?> </pre> <?php } else { // Fail! echo"CRAAAAAPP! something went wrong. FIX IT! :P<br>"; echo mysql_error(); } if (isset($connexion)) { mysql_close($connexion); } i copied it over from an old *working* file to illustrate how a simple INSERT works. this is the error i get: Code: [Select] You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'company,big bay #8,some big warehouse,big city,T1T0N0,0123456789,bigKahuna@bigKa' at line 4 looks completely valid to me. all the database table elements are set to VARCHAR(80), so it can't be a space/type issue... halp! WR! What would be the correct way to close a mysql query? At current the second query below returns results from the 1st query AND the 2nd query The 3rd query returns results from the 1st, 2nd and 3rd query. etc etc. At the moment I get somthing returned along the lines of... QUERY 1 RESULTS Accommodation 1 Accommodation 2 Accommodation 3 QUERY 2 RESULTS Restaurant 1 Restaurant 2 Restaurant 3 Accommodation 1 Accommodation 2 Accommodation 3 QUERY 3 RESULTS Takeaways 1 Takeaways 2 Takeaways 3 Restaurant 1 Restaurant 2 Restaurant 3 Accommodation 1 Accommodation 2 Accommodation 3 Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <?php include($_SERVER['DOCUMENT_ROOT'].'/include/db.php'); ?> <title>Untitled Document</title> <style type="text/css"> <!-- --> </style> <link href="a.css" rel="stylesheet" type="text/css" /> </head><body> <div id="listhold"> <!------------------------------------------------------------------------------------------------------------------------------------------------------> <div class="list"><a href="Placestostay.html">Places To Stay</a><br /> <?php $title ="TITLE GOES HERE"; $query = mysql_query("SELECT DISTINCT subtype FROM business WHERE type ='Accommodation' AND confirmed ='Yes' ORDER BY name"); echo mysql_error(); while($ntx=mysql_fetch_row($query)) $nt[] = $ntx[0]; $i = -1; foreach($nt as $value) {$i++; $FileName = str_replace(' ','_',$nt[$i]) . ".php"; $FileUsed = str_replace('_',' ',$nt[$i]); echo "<a href='" . str_replace(' ','_',$nt[$i]) . ".php?title=$title&subtype=$FileUsed'>" . $nt[$i] . "</a>" . "<br/>"; $FileHandle = fopen($FileName, 'w') or die("cant open file"); $pageContents = file_get_contents("header.php"); fwrite($FileHandle,"$pageContents");} fclose($FileHandle); ?> </div> <!------------------------------------------------------------------------------------------------------------------------------------------------------> <div class="list"><a href="Eatingout.html">Eating Out</a><br /> <?php $title ="TITLE GOES HERE"; $query = mysql_query("SELECT DISTINCT subtype FROM business WHERE type ='Restaurant' AND confirmed ='Yes' ORDER BY name"); echo mysql_error(); while($ntx=mysql_fetch_row($query)) $nt[] = $ntx[0]; $i = -1; foreach($nt as $value) {$i++; $FileName = str_replace(' ','_',$nt[$i]) . ".php"; $FileUsed = str_replace('_',' ',$nt[$i]); echo "<a href='" . str_replace(' ','_',$nt[$i]) . ".php?title=$title&subtype=$FileUsed'>" . $nt[$i] . "</a>" . "<br/>"; $FileHandle = fopen($FileName, 'w') or die("cant open file"); $pageContents = file_get_contents("header.php"); fwrite($FileHandle,"$pageContents");} fclose($FileHandle); ?> </div> <!------------------------------------------------------------------------------------------------------------------------------------------------------> <div class="list"><a href="Eatingin.html">Eating In</a><br /> <?php $title ="TITLE GOES HERE"; $query = mysql_query("SELECT DISTINCT subtype FROM business WHERE type ='Takeaways' AND confirmed ='Yes' ORDER BY name"); echo mysql_error(); while($ntx=mysql_fetch_row($query)) $nt[] = $ntx[0]; $i = -1; foreach($nt as $value) {$i++; $FileName = str_replace(' ','_',$nt[$i]) . ".php"; $FileUsed = str_replace('_',' ',$nt[$i]); echo "<a href='" . str_replace(' ','_',$nt[$i]) . ".php?title=$title&subtype=$FileUsed'>" . $nt[$i] . "</a>" . "<br/>"; $FileHandle = fopen($FileName, 'w') or die("cant open file"); $pageContents = file_get_contents("header.php"); fwrite($FileHandle,"$pageContents");} fclose($FileHandle); ?> </div> <!------------------------------------------------------------------------------SKILLED TRADES BELOW---------------------------------------------------> <div class="list"><a href="Skilledtrades.html">Skilled Trades</a><br/> <?php $title ="TITLE GOES HERE"; $query = mysql_query("SELECT DISTINCT subtype FROM business WHERE type ='Skilled Trades' AND confirmed ='Yes' ORDER BY name"); echo mysql_error(); while($ntx=mysql_fetch_row($query)) $nt[] = $ntx[0]; $i = -1; foreach($nt as $value) {$i++; $FileName = str_replace(' ','_',$nt[$i]) . ".php"; $FileUsed = str_replace('_',' ',$nt[$i]); echo "<a href='" . str_replace(' ','_',$nt[$i]) . ".php?title=$title&subtype=$FileUsed'>" . $nt[$i] . "</a>" . "<br/>"; $FileHandle = fopen($FileName, 'w') or die("cant open file"); $pageContents = file_get_contents("header.php"); fwrite($FileHandle,"$pageContents");} fclose($FileHandle); ?> </div> I'm restarting this under a new subject b/c I learned some things after I initially posted and the subject heading is no longer accurate. What would cause this behavior - when I populate session vars from a MYSQL query, they stick, if I populate them from an MSSQL query, they drop. It doesn't matter if I get to the next page using a header redirect or a form submit. I have two session vars I'm loading from a MYSQL query and they remain, the two loaded from MSSQL disappear. I have confirmed that all four session vars are loading ok initially and I can echo them out to the page, but when the application moves to next page via redirect or form submit, the two vars loaded from MSSQL are empty. Any ideas? I am trying to create a query which reads and uses a previous query which could go on for upto four queries. For example: Query: $carcolour(red), Query: $carmodel(ford), Query: $enginesize(1600), Query: $carlocation(New York) This displays all red cars, which are Ford, which 1600CC, which are located in New York. or Query: $enginesize(1600), Query: $carcolour(red), Query: $carmodel(ford), Query: $carlocation(New York) This displays all 1600CC cars, which red car, which are Ford, which are located in New York. (Same result as above) I have found this guide but Im not sure it what I am looking for. I have also come across the Join function. However this seems to be based on joining two seperate queries. http://www.suite101.com/content/how-tor-run-multiple-mysql-queries-with-php-a105672 Can anyone advise on the best way to create a set of queries which reads and uses the results of the previous query? |