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PHP - Moved: Posting Comments Without Refreshing The Page?
This topic has been moved to Ajax Help.
http://www.phpfreaks.com/forums/index.php?topic=347117.0 Similar TutorialsThis topic has been moved to JavaScript Help. http://www.phpfreaks.com/forums/index.php?topic=330523.0 This topic has been moved to JavaScript Help. http://www.phpfreaks.com/forums/index.php?topic=349726.0 This topic has been moved to Miscellaneous. http://www.phpfreaks.com/forums/index.php?topic=327715.0 I have a problem with the "comments count" in the toggle link in my blog: www.albertosotophotography.com
I have this script for show/hide comments in main page:
<script type= "text/javascript">
// Show/Hide Comments
jQuery(document).ready(function() {
// Get #comments div
var uniqueAppend = 1;
var tempName = 'comments';
while(jQuery("#comments").length > 0 ){
jQuery("#comments").attr('id',tempName + uniqueAppend++).addClass('commentContainer')
}
var commentsDiv = jQuery('.commentContainer');
// Only do this work if that div isn't empty
if (commentsDiv.length) {
// Hide #comments div by default
jQuery(commentsDiv).hide();
// Append a link to show/hide
jQuery('<a/>')
.attr('class', 'toggle-comments')
.attr('href', '#')
.html('Notes')
.insertAfter(commentsDiv);
// Encase button in .toggle-comments-container div
jQuery('.toggle-comments').wrap(jQuery('<div/>', {
class: 'toggle-comments-container'
}))
// When show/hide is clicked
jQuery('.toggle-comments').on('click', function(e) {
e.preventDefault();
// Show/hide the div using jQuery's toggle()
var commentContainer = jQuery(this).parent('.toggle-comments-container').prev('.commentContainer');
jQuery(commentContainer).slideToggle('slow', function() {
// change the text of the anchor
var anchor = jQuery(commentContainer).siblings('.toggle-comments-container').children('.toggle-comments');
var anchorText = anchor.text() == 'Notes' ? 'Hide' : 'Notes';
jQuery(anchor).html(anchorText);
});
});
} // End of commentsDiv.length
}); // End of Show/Hide Comments
</script>
I use:
.html('<?php comments_number( '0 notes', '1 note', '% notes' ); ?>')
for name the "comments toggle link" with the count of comments for each single post.
The problem is that all posts shows the same count: the comments presents in the first post. Someone can help me?
Alberto
Stop posting non-PHP questions in the PHP Coding Help section. We have many sub-forums, including both a JavaScript forum and one dedicated entirely to Ajax. This topic has been moved to Ajax Help. http://www.phpfreaks.com/forums/index.php?topic=327454.0 This topic has been moved to Application Design. http://www.phpfreaks.com/forums/index.php?topic=311235.0 This topic has been moved to Other Libraries and Frameworks. http://www.phpfreaks.com/forums/index.php?topic=347050.0 This topic has been moved to JavaScript Help. http://www.phpfreaks.com/forums/index.php?topic=323252.0 This topic has been moved to PHP Applications. http://www.phpfreaks.com/forums/index.php?topic=343263.0 Hi, In the following code I'm using a combo box to select a relay and activate it. The code works but if I refresh the page, the last selected relay is activated again. How can I reset the page to default to value '0' which has no relay control? TIA
<!DOCTYPE html>
<html>
<head>
<title>Relay control</title>
<meta content="text/html; charset=utf-8" http-equiv="Content-Type" />
<meta name="apple-mobile-web-app-capable" content="yes" />
<meta name="apple-mobile-web-app-status-bar-style" content="black-translucent" />
<link rel="stylesheet" type="text/css" href="style.css" />
</head>
<body>
<h2><center>Status y control de relés</center></h2>
<?php
$arrleds = array();
if ($_SERVER["REQUEST_METHOD"] == "POST") {
$selected_val = $_POST['sel'];
if ($selected_val == '1'){
$cmd = exec("sudo ./trigger.py b 0");
}
elseif ($selected_val == '2'){
$cmd = exec("sudo ./trigger.py b 1");
}
elseif ($selected_val == '3'){
$cmd = exec("sudo ./trigger.py b 2");
}
....
else {}
}
?>
<table class="center">
<tr>
<td></td>
<td><h1>Activación de relé</h1>
<form action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]); ?>" method="post">
<select name='sel' onchange='submit();'>
<option value='0'>Sin activar</option> <!-- no action -->
<option value='1'>Secadora 1</option>
<option value='2'>Secadora 2</option>
<option value='3'>Lavadora S</option>
....
</select>
</form>
</td>
<td></td>
</tr>
<tr>
<td></td>
<td><a href="index.php">Home</a>
<td></td>
</tr>
</table>
</body>
</html>
This topic has been moved to Other Programming Languages. http://www.phpfreaks.com/forums/index.php?topic=322013.0 i have a form with two buttons, one is for submitting the form while button is for generating a random a code and placing it in a textfield. this works fine but the problem is anytime i click on the generate button, it refreshes the page thereby validating the form , which i don't want. How do i make it perform the function without refreshing the page.... This topic has been moved to HTML Help. http://www.phpfreaks.com/forums/index.php?topic=346552.0 Here is my code if(isset($_POST['pass_btn'])) { $numchars = 8; $chars = explode(',','2,3,4,5,6,7,8,9,a,b,c,d,e,f,g,h,i,j,k,m,n,p,q,r,s,t,u,v,w,x,y,z,2,3,4,5,6,7,8,9,A,B,C,D,E,F,G,H,J,K,L,M,N,P,Q,R,S,T,U,V,W,X,Y,Z,2,3,4,5,6,7,8,9'); $password=''; for($i=0; $i<$numchars;$i++) { $password.=$chars[rand(0,count($chars)-1)]; } } This is set up so when a person pressing the pass_btn, a password is provided. This works just fine. However, it refreshes the page and clears all other data that user may have entered. Suggestions? Hi, I have a "user profile" page and it has a profile image upload form. I have it so that the old profile image is deleted, and the new image is uploaded and the new image is echoed out using the name of the new file from the database. The problem is, when I click submit to add the new image, the old image still stays there and the new image does not show up. Only when I manually click refresh on my browser does the new image show up. That is going to be bad for my users. Please if anyone can help, I'd greatly appreciate it. Below is the code I am using to delete the old image, and code to upload the image as well, when the photo upload form is used. Code: [Select] if(isset($_POST['photoUpload'])) { if(file_exists("images/".$currentUser.".jpg")){ unlink("images/".$currentUser.".jpg"); clearstatcache(); } //reads the name of the file the user submitted for uploading $image=$_FILES['image']['name']; //if it is not empty if ($image) { //get the original name of the file from the clients machine $filename = stripslashes($_FILES['image']['name']); //get the extension of the file in a lower case format $extension = getExtension($filename); $extension = strtolower($extension); //if it is not a known extension, we will suppose it is an error and will not upload the file, //otherwise we will do more tests if (($extension != "jpg") && ($extension != "jpeg") && ($extension != "png") && ($extension != "gif")) { //print error message echo '<h1>Unknown extension!</h1>'; $errors=1; } } //end if here //was else here //get the size of the image in bytes //$_FILES['image']['tmp_name'] is the temporary filename of the file //in which the uploaded file was stored on the server $size=filesize($_FILES['image']['tmp_name']); //compare the size with the maxim size we defined and print error if bigger if ($size > MAX_SIZE*1024) { echo '<h1>You have exceeded the size limit!</h1>'; $errors=1; } //we will give an unique name, for example the time in unix time format $image_name= $currentUser .'.'.$extension; //$image_name=time().'.'.$extension; //the new name will be containing the full path where will be stored (images folder) $newname=$image_name; //"images/". // Connects to your Database mysql_connect("host", "user", "pass") or die(mysql_error()); mysql_select_db("database") or die(mysql_error()) ; //we verify if the image has been uploaded, and print error instead $copied = copy($_FILES['image']['tmp_name'], "images/".$newname); // update the photo name in the database $result = mysql_query("UPDATE users SET profilePhoto='$newname' WHERE username='$currentUser'") or die(mysql_error()); if (!$copied) { echo '<h1>Copy unsuccessful!</h1>'; $errors=1; } else{ $dir="images/"; echo "<p>Profile Picture Change Successful!</p>"; echo "<img src='{$dir}{$newname}' alt='{$newname}' height='200' width='200' />"; echo "<p></p>"; } } This topic has been moved to JavaScript Help. http://www.phpfreaks.com/forums/index.php?topic=354451.0 I'm using paypal PDT, so when the user has made payment he gets directed back to my site, on that page it executes a special sql query. I noticed I can refresh the page to make duplicate sql queries. How can I avoid this?? Here is my add driver button <!DOCTYPE html> <html> <head> <script> $(document).ready(function() { if($("#getPIN").click(function(){ <?php $char = 'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVW XYZ1234567890'; $generated_password = substr(str_shuffle($char), 0, 10); ?> var genNumber; $("#txtpin").val() = genNumber; return false; })); }); </script> </head> <body> <input type = "text" name = "txtpin" id = "txtpin" value = ""> <input type = "button" name = "getPIN" id = "getPIN" value = "getPIN"> </body> </html> Hey you guys need your help... Basically what im trying to do is when the user clicks the getPIN button, the value generated using php is assigned to the txtpin textfield without refreshing the page.... thanks alot guys.... i am making a website where i can submit films but i am confuse to understand the structure of that where people can also submit their views and i can diferent link of diffrent companiess for example i have some example http://tv.desitvforum.net/index.php?option=com_content&task=view&id=77865&Itemid=86 http://www.funbolo.com/more.asp?itemCode=1916 this type of page that i can easily insert links and their title and images on that page there is also one problem every time become different links of different sites in different counting so that's why m more confuse ho to set data base structure for that and how add these all details from panel and people can also post comment on that well thats simple but my bug problem is structure for this aNy Body in structure |
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