PHP - Php Login Out Every Half An Hour Help!
Hi guys,
I have a PHP Script were user would enter a username and password to get access, but the problem I keep having is every half n hour or so user have to sign in again cause the keeps logging them out for some reason. Please I need your help and advice to make this stop. Similar TutorialsUnfortunately I do not know how to go about doing this in php any simple examples of time and date will be great. So what I am trying to do is, display to minutes until the next half hour as well as the seconds until the next minute. Eg. Code: [Select] <?php echo $minutes; ?>:<?php echo $seconds; ?> Any help using the time and or date functions in this case will be great. Thank you for your stupendous help. Brian Hi all,
Having an issue with some of my php code. The goal is to have two drop-down menus, one that pulls from "ahevents_scenarios". The second pulls the "sides" involved, however it does not go into dropdown. The other issue is that even though there are only 3 sides specified, all 5 show up on the webpage. This is in Joomla.
Here is my code...I think I've looked over this way too much and just can't find my errors anymore.
<?php if (! $my->id) { // shouldn't even get here since menu is viewable only through logged in status print "<b>Sorry, you must be registered and logged into this site to continue</b>\n"; } else { // include standard functions and db info require_once($_SERVER['DOCUMENT_ROOT'] . "/inc/admin_functions.php"); require_once($_SERVER['DOCUMENT_ROOT'] . "/inc/db_admin_functions.php"); // which scenario we doing? -- replace with table lookup in future opendb('ahevents_scenarios'); if(!isset($_POST['action'])) { // display form $sqlstr2 = "select id, name from scenarios order by name"; $result2 = mysql_query($sqlstr2) or die("Error: ".mysql_error()."<br>Query: $sqlstr2"); // display form ?> <form name="edit_reg" method="post" action="<? echo $_SERVER[ 'REQUEST_URI' ]; ?>" <table> <tr> <td>Select Scenario: </td> <td> <select name="id"> <? while ( $row = mysql_fetch_array($result2)) { printf("<option value=\"%s\">%s</option>\n",$row['id'], $row['name']); } ?> </td></tr> <tr> <td>Which Side?</td> <td><select name="side"> <option value="side_1">side_1</option> <option value="side_2" >side_2</option> <option value="side_3" >side_3</option> <option value="all" selected>All</option> </select> </td></tr> </table> <p> <input type="submit" name="action" value="Get Registrants"> <input type="reset" value="Reset"> <input type="button" name="" value="Back" onClick="history.back()"> </form>The goal is to download the registrants into a .csv file, which it does, however due to not being able to select a "side", the .csv is blank with only headers, no content. Thanks for your time Rob Hi guys, So here is the deal. We have a list of brands that excists in a database. There are also images associated with the names. But not all the brands have images. So in the script i read if the file excists. Well this all works fine but it looks horrible. So i want to break the list in half (or limit it to 24). But i cant limit the sql query. Is there a way to "limit" a while loop and let it resume on the same page, just to change the layout (multiple collumns)? (I hope i am clear on this... i confuse even myself) $host = 'localhost'; $user = 'qwerty'; $pass = 'qwerty'; $db = 'qwerty'; $query = "SELECT * FROM ros_brands"; $result = mysql_query($query) or die(mysql_error()); $filename = "/resources/images/mm_files/" . $row['image_file_id'] . ".gif"; while($row = mysql_fetch_array($result)){ $filename = "/var/www/vhosts/test.nl/httpdocs/resources/images/mm_files/" . $row['image_file_id'] . ".gif"; if (file_exists($filename)) { echo "<a href='#'><img src='/resources/images/mm_files/" . $row['image_file_id'] . ".gif' /><span>". $row['name'] ."</span></a>"; } else { // echo "The file $filename does not exist"; } } I am just helping out a friend with his online store that he would like to add multiple currencies to. I made this script to help him out: $price = 99.95; $default_currency = 20; // displays all the file nodes if(!$xml=simplexml_load_file('http://www.ecb.int/stats/eurofxref/eurofxref-daily.xml')){ trigger_error('Error reading XML file',E_USER_ERROR); } else { $array['currency'][1] = 'EUR'; $array['value'][1] = 1.00; $i = 2; foreach ($xml->Cube->Cube->children() as $node) { $arr = $node->attributes(); // returns an array $array['currency'][$i] = $arr['currency']; $array['value'][$i] = $arr['rate']; $i++; } } if (isset($_POST['currency'])){ $currency = $_POST['currency']; } else { $currency = $default_currency; } $price = $array['value'][$currency] / $array['value'][$default_currency] * $price; $price = round($price, 2); $currency_name = $array['currency'][$currency]; echo '<p>Price is '.$currency_name.$price.'<br /> To change currency, select from dropdown box below.</p>'; echo '<form action="currency.php" method="post"><select name="currency">'; $i = 1; foreach ($array['currency'] as $value){ echo '<option value="'.$i.'">'.$value.'</option>'; $i++; } echo '</select><br /><input type="submit" /></form><br />'; $i = 1; foreach ($array['currency'] as $value){ echo '<p>'.$value.' = '.$array['value'][$i].'</p>'; $i++; } But for some reason it only works some of the time and I can't work out why for the life of me. If I could get some help in the matter, that would be greatly appreciated. A link to the above example can be found here. Regards, I. I am trying to display date and time below code display date correctly but when it come to display time it display 3 hour behind. eg. when it is 12:47 PM in my system it display 9:47 PM Code: [Select] <?php $todaydate=date("j - F - Y g:i:s a"); echo $todaydate; ?> $time="19:00:00"; how to do i output one hour later from the variable above? Hi, i'm trying to create some detailed statistics about customer activity, i have entries in my mysql db when the customer has been active for the last time and want to create some statistics about that, basically a "online last 24 hours" but from specific countries. Now i've tried this: Code: [Select] $time = date('Y-m-d H:i:s'); $time24 = date("Y-m-d H:i:s", time()-((60*60)*24)); $query = "SELECT COUNT(*) as Anzahl FROM customers WHERE country = 'de' AND time BETWEEN '$time' AND '$time24' "; to get the current date and select all customers that have been available from the current date minus 24 hours, what's my mistake here, as this doesn't seem to work! Thanks Hello, I am trying to load an external image from a NOAA site directory. This image refreshes every three hours, starting with 0 and then 3,6,9,12.....21 in a 24 hour calendar, and are stored for days in advance. The date/time is in the file name. Originally I had written the script to refresh on the hour, and then realized the tri-hourly spacing. This is what I have: Code: [Select] <?php date_default_timezone_set('Etc/GMT-1'); $today = date("YmdH"); $pattern = '/WaveHeight_'.$today.'_mic.png'; $base_url = 'http://www.crh.noaa.gov/images/greatlakes/ndfd/MIC/dynamic2'; print '<a href="http://www.crh.noaa.gov/greatlakes/?c=map&l=lm&p=a"><img src="'.$base_url.$pattern.'" width= "237" hieght= "314" " ></a>'; ?> I am not fluent in php, but I assume I need a "If H=1,4,7,10,13,16,19,22; Then H+2 ; along with If H=2,5,8,11,14,17,20,23; Then H+1" to keep the images relatively current. I just can't quite wrap my head around how to express this. Any help is appreciated. Thank you. Hi I want to make something like this - My Sites index.php will be avail avail to user after he has clicked in a link that will come after every 24 Hour in my site. Means when a user first enters the site it will come and clicking in there the site will be avail avail. again after 24 Hour it will come again. But i am not getting how to do it. So need help SaKIB Hello, I have a very simple table... DAY (Y-m-d) / TIME (00:00:00) / POWER (INT) I am using a Jquery datepicker to select the date on the page, and that POST to the PHP file. I am trying to select values from Mysql to make 3 HighCharts Graphs using the selected day of the datepicker. I have started with the DAY graph PHP to get the values for each hour of a 24 hour day. I need to get the values for each hour... 23,12,15,35 etc... , and then I need for the 31 days of a month for the month graph, and 12 months of the year for the month graph all in the same way so the HighCharts can use the values to make the chart (3 php files, one for each graph) Here is the PHP I have for the 1 day that should get the 24 individual hour data, but it does not seem to work... <?php $choice = (isset($_POST['choice'])) ? date("Y-m-d",strtotime($_POST['choice'])) : date("Y-m-d"); $con = mysql_connect("localhost","root","mackie1604"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("inverters", $con); $sql = "SELECT HOUR(time), COUNT(power) FROM feed WHERE time = '".$choice."' GROUP BY HOUR(time) ORDER BY HOUR(time) "; $res = mysql_query($sql) or die('sql='.$sql."\n".mysql_error()); $row = mysql_fetch_assoc($res); echo $row['choice'].'<br />'; ?> What have a written wrong in the sql query ??? Alan So I am trying to check if the current time is one hour before a variable time: Code: [Select] $date_game=$dt->format('Y n j'.$pieces[2]); echo $date_game; echo date('Y n j H'); if (date('Y n j H') < $date_game) { echo "The time is before the stored time"; } This displays 2012 1 21 17:30 2012 1 21 16 i.e $pieces[2] = 17:30. and $dt formatted Y n j = 2012 1 21. The current Y n j H is 2012 1 21 16. I want to know if it is more than one hour until the date/time stored in $date_game. At the moment it just tells me that it is before that time. Can I do something like Code: [Select] $data_game - 1->format('H'); or something? Thanks guys Hi,
I have a blog which records the amount of views on each article. I now want to be able to work out the average number of views per hour.
How can I work out the number of hours passed from a datetime format?
From there I can just do views divided by hours passed.
Thanks in advance!
Hi all, I have a loop that is modifying a DateTime object. It goes through X number of times and adds 1 day to the date time object and stores the modified object in an array. I use ->add(new DateInterval('P1D')); For some reason it is losing an hour each time that I add a day. I start out at 19:00 and each iteration through the loop adds a day, but loses an hour. 2010-09-19 19:00:00 2010-09-20 18:00:00 2010-09-21 17:00:00 I can correct for this by doing ->add(new DateInterval('P1DT1H'));, but adding 25 hours instead of 24 hours doesn't make any sense to me. I am using PHP Version 5.3.1. Any ideas? Thanks, W I insert a time value using the following code
$ti= ( !empty($_POST['time']) ) ? "'{$_POST['time']}'" : 'NULL';
I want to insert a second time value into a differen column which would be the same time minus 1 hour
something along the lines of :
$ti2= ( !empty($_POST['time']) ) ? "'{$_POST['time'] -1 hour}'" : 'NULL';
What would be the correct way to do it
My site allows users to vote once per hour, and it checks the next time they vote if it's been 3600 seconds (1 hour) since their last vote. But, it always returns the value 0. $grab = mysql_fetch_assoc($has_voted); $calc = strtotime($grab['date']) - strtotime(date("M-d-Y")); if($calc > 3600) { mysql_query("DELETE FROM votes WHERE ip = '". $_SERVER['REMOTE_ADDR'] ."'"); header("location:votes.php?id=". $id .""); } else { echo echo "You've voted within the last hour. Please wait ". $calc ." seconds."; } This topic has been moved to PHP Freelancing. http://www.phpfreaks.com/forums/index.php?topic=332844.0 Hi, I am creating a date string using the following: $curDate = date("Y-m-d H:i:s"); However, what I want to do is take one hour off this so that $curDate now becomes the current date and time minus one hour. Thanks for your help. Hey guys only thing i can find online is examples of showing how much time is left until a predetermind time. but what I need is how many minutes are left until the next hour hits anyone have any ideas on this? Im wanting to do it in UNIX time When I echo the current time, the hour is what it is plus one: echo date("h:i:s:A"); Real time is 3:46:33 Would display 4:46:33 What is wrong here? Hello, Im trying to work out some code. On my site between Thursday 12th July and Sunday 15th July between the hours of 22:00 and 23:00 I want to display some code. I've done this so far, but am having trouble. Anyone please help? $the_date = date("H:i:s"); $timesep = explode(":",$the_date); // $hour = $timesep[0]; if (($the_date > 2010-08-12 && < 2010-08-15) && ($hour >= 22) && ($hour <= 23)) { //Code } |