PHP - Not Retrieving $_get Correctly

i am trying to retrieve messages with some code.  It seems to be a bit more complicated that i thought it would be.  so here it goes:

Code: [Select]
$query = "SELECT * FROM memberMail WHERE userIDFrom='92' AND unread='1'"; 
$result = mysql_query($query) or die(mysql_error());
if (mysql_num_rows($result) > 0) {
$row = mysql_fetch_array($result) or die(mysql_error());

$num_rows = mysql_num_rows($result);

echo "You have (" . $num_rows . ") unread message(s).";

$i = 0;
for($i; $i<$num_rows; ++$i) {
if($row[$i[unread]] == "1") {
echo $row[$i[message]] . "<p>";
}
}

}
what i am trying to do, is print out the messages from the records that are unread, and are from a certain user.  i don't think this for statement will pick up the record numbers that got matches though.  and i am not entirely sure about the $row statements in the for statement either.

ok im back quicker than i thought....

i got my drop box sorted and i got it reloading the page. so it all works correctly.

but how do i get the page to display information regarding the film i have selected in the drop box.? i have no code for this at the mo.

also i would like the drop box to display the selected item at top of box when it refreshes

code for drop box:

Code: [Select]
<FORM>
<?php $result = mysql_query( "SELECT * FROM movie_info ORDER BY title ASC ")
;
echo "<select name= Film onChange='submit()' >film name</option>";
while
($nt=mysql_fetch_array($result)){
?>
<?php
  echo "<option value='$nt[id]'>$nt[title] </option>";
}
?>
</select>
</FORM>



any help would be great

i have this script called view.php
Code: [Select]
<?php
  include 'db.inc';

  $file = clean($file, 4);

  if (empty($file))
     exit;

  if (!($connection = @ mysql_pconnect($hostName,
                                       $username,
                                       $password)))
     showerror();

  if (!mysql_select_db("Php_test", $connection))
     showerror();

  $query = "SELECT mime, data FROM file 
            WHERE id = $file";

  if (!($result = @ mysql_query ($query,$connection)))
     showerror();  

  $data = @ mysql_fetch_array($result);

  if (!empty($data["data"]))
  {
    // Output the MIME header
     header("Content-Type: {$data["mime"]}");
    // Output the image
     echo $data["data"];
   }
?>after i have db.inc
Code: [Select]
<?php

// These are the DBMS credentials
$hostName = "localhost";
$username = "root";
$password = "oxioxi";

// Show an error and stop the script
function showerror()
{
   if (mysql_error())
      die("Error " . mysql_errno() . " : " . mysql_error());
   else
      die("Could not connect to the DBMS");
}

// Secure the user data by escaping characters 
// and shortening the input string
function clean($input, $maxlength)
{
  $input = substr($input, 0, $maxlength);
  $input = EscapeShellCmd($input);
  return ($input);
}

?>and i have my page witch part of it is  this
Code: [Select]
   <?php
  include 'db.inc';
  
  $query = "SELECT id, name, mime FROM file";

  if (!($connection = @ mysql_pconnect($hostName, 
                                    $username,
                                    $password)))
     showerror();

  if (!mysql_select_db("php_test", $connection))
     showerror();
        
  if (!($result = @ mysql_query ($query, $connection)))
     showerror();
?>
    <h1>Image database</h1>


<?php 


  if ($row = @ mysql_fetch_array($result))
  {
?>

    <table>
    <col span="1" align="right">
    <tr>
       <th>Short description</th>
       <th>File type</th>
       <th>Image</th>

    </tr>
<?php
   do 
   {
?>
    <tr>
       <td><?php echo "{$row["name"]}";?></td>         
       <td><?php echo "{$row["mime"]}";?></td>
       <td><?php echo "<img src=\"view.php?file={$row["id"]}\">";?></td>
    </tr>
<?php
   } while ($row = @ mysql_fetch_array($result));
?>
    </table>
<?php
  } // if mysql_fetch_array()
  else
     echo "<h3>There are no images to display</h3>\n";
?>i have do it right but for some reason it doesnt displays the pictures the type and the name are displayed normally but not the picture!! instead of them there are small icons of not existing pictures.. please i want help i really need to do it

$qID = '';
$question = 'Question not set';
$answerA = 'unchecked';
$answerB = 'unchecked';
$answerC = 'unchecked';
$answerD = 'unchecked';
$answerE = 'unchecked';



?>

<html>
<head>
<script type="text/javascript">
function show_alert()
{
alert("Please Click OK to proceed!");
                 
}
</script>
</head>
<form action="Process1.php" method="POST">
<table>
<tr>
<td>
<?php

$SQL = "SELECT stu_satisfaction_tblquestions.question_id, stu_satisfaction_tblquestions.question, answer_type.answer1, answer_type.answer2, answer_type.answer3, answer_type.answer4, answer_type.answer5 FROM stu_satisfaction_tblquestions INNER JOIN answer_type ON stu_satisfaction_tblquestions.answers_id=answer_type.answers_id
";
$result = mysql_query($SQL);
while($db_field = mysql_fetch_assoc($result)){

   $qID = $db_field['question_id'];
   $question = $db_field['question'];
   $A = $db_field['answer1'];
   $B = $db_field['answer2'];
   $C = $db_field['answer3'];
   $D = $db_field['answer4'];
   $E = $db_field['answer5'];
   print $question;
?>
</td>
</tr>
<tr>
<td>
<INPUT TYPE = 'Radio' Name ='q'  value= 'A' <?PHP echo $answerA; ?>><?PHP echo $A; ?>
<INPUT TYPE = "Hidden" Name = "h"  VALUE = <?PHP print $qID; ?>>
<?php echo $qID;?>
</td>
</tr>
<tr>
<td>
<INPUT TYPE = 'Radio' Name ='q'  value= 'B' <?PHP echo $answerB; ?>><?PHP echo $B; ?>
<?php echo $qID;?>
</tr>
</td>
<tr>
<td>
<INPUT TYPE = 'Radio' Name ='q'  value= 'C' <?PHP echo $answerC; ?>><?PHP echo $C; ?>
</tr>
</td>
<tr>
<td>
<INPUT TYPE = 'Radio' Name ='q'  value= 'D' <?PHP echo $answerD; ?>><?PHP echo $D; ?>
</tr>
</td>
<tr>
<td>
<INPUT TYPE = 'Radio' Name ='q'  value= 'E' <?PHP echo $answerE; ?>><?PHP echo $E; ?>
<br>
<?php }  mysql_close(); ?>
</tr>
</td>
<tr>
<td>


Please add any comments you may have:</br>
 <textarea rows="3" cols="60" name="comments" id="comments">
 </textarea>

</td>
</tr>


</table>

<input type="submit" onclick="show_alert()" value="Submit" />
</form>

</html>

I ran to some problems here. After filling every question up with the answers. When i process the form, i only managed to get QID of 20 and the answer of 1st question as my database have only 20questions. How do i go about in solving, so that i'm able to retrieve all result and update my database correctly

      $selected_radio = $_POST['q'];
      
      
      $qID = $_POST['h'];

      echo $selected_radio;
      
      echo $qID;
         
         $SQL = "UPDATE answers SET $selected_radio = $selected_radio + 1 WHERE question_id='$qID'";
         $result = mysql_query($SQL);
         mysql_close();
         print "Thanks for voting!";


?>
THis is my process page, and i echo out the answer to be B and qid as 20.

I have a basic table where I am trying to retrieve records that are filtered by a form request. Here is the code I have...

$ps = $pdo->prepare("SELECT * FROM `Products` Where `Vendor` LIKE concat('%',?,'%');
$ps->execute(array($_POST['Vendor']));;
echo "post=" . $_POST['vendor']; ////Displays correct data from form request
$count = $ps->rowCount();
echo "Count=" . $count; ////Count = 0 although I know for a fact that there is 1 record that should be in there

////Used for display of records
foreach ($ps as $row){
echo $row, PHP_EOL . "xxx<br>";
}

Where is the incorrect code? I am new to php and pdo. Thank you in advance

K

Hi,

so i have a problem. I'm using a script to enable and disable checkboxes, and i'm id-ing them fetching values from a database:

while($data = mysqli_fetch_array($sql))
{
  if ($count % 5 == 0) {
    echo '</tr><tr>';
    $count = 0;
  }
  echo '<td><input name="subject_level[]" class="subject_a" disabled="disabled" type="checkbox" id="subject_level_'.$data['subject_level_id'].'" value="'.$data['subject_level_id'].'"/>';
  echo '<label for="subject_level_'.$data['subject_level_id'].'" class="subject_1">'.$data['subject_name'].'</label></td>';
  $count++; //Increment the count
}

The names of the checkboxes come out fine, just that, is there any way to retrieve the values of the checkboxes into an array of some sort so that i could build a search query later?

if($_POST(subject_level)) or if($_POST(subject_level[]))  doesn't return true. does it make sense? im new to php so please forgive my ignorance. Help appreciated. Thanks!

Hi,
I need to get data from an XML file, like the format below:
Code: [Select]
<ISBNdb server_time="2011-05-31T19:19:42Z">
<BookList total_results="1" page_size="10" page_number="1" shown_results="1">
<BookData book_id="build_your_own_database_driven_web_site_using_php_mysql_4th_" isbn="0980576814" isbn13="9780980576818">
<Title>
Build Your Own Database Driven Web Site Using PHP & MySQL, 4th Edition
</Title>
<TitleLong/>
<AuthorsText>Kevin Yank, </AuthorsText>
<PublisherText publisher_id="sitepoint">SitePoint</PublisherText>
<Details change_time="2009-04-02T00:30:10Z" price_time="2011-05-31T17:46:10Z" edition_info="Paperback; 2009-06-15" language="" physical_description_text="360 pages" lcc_number="" dewey_decimal_normalized="5" dewey_decimal="005"/>
</BookData>
</BookList>
</ISBNdb>
I need to know how you get the details from <title>,<AuthorsText><PublisherText> and Bookdata. Tried using the example on W3C, using simplexml_load_file but it only returns:
Code: [Select]
ISBNdb
BookList:
Code I'm currently using is:
Code: [Select]
$xml = simplexml_load_file("http://isbndb.com/api/books.xml?access_key=----&results=details&index1=isbn&value1=".$isbn);
echo $xml->getName() . "<br />";

foreach($xml->children() as $child)
  {
  echo $child->getName() . ": " . $child . "<br />";
  }

In my script, users login with their Username & Password. However, I'd like to be able to echo the email address used on their account. I've tried adding the email to the session
I'm not having much luck... Here's a piece of the login code(untouched);

                $username = $_POST['name'];
                $passwd = $_POST['passwd'];
                $query = "SELECT name,passwd FROM users WHERE CONCAT('0x', hex(passwd)) = '{$salt}'";
		$result = mysql_query($query);
		$login_ok = false;
		if(mysql_num_rows($result) > 0) {
		    $login_ok = true;
		}
		if($login_ok)
		{
		    $row = mysql_fetch_array($result, MYSQL_NUM);
		    $_SESSION['user'] = $row;

I've also tried messing around with this piece below in a few different ways but still nothing.

<?php echo htmlentities($_SESSION['user']['email'], ENT_QUOTES, 'UTF-8'); ?>

Any help is greatly appreciated..

Hello all,

I'm currently working on a project and it is the first time I have had to store/retrieve an array with PHP and MySQL. Basically its a website that has a list of discounts/coupons on it. People can register and submit their discounts and such. I am storing an array for who is eligible for the discount, as well as which categories the discount falls under.

I did some googling and there seems to be tons of thoughts on the best way to do this. Some say to use implode/explode, some say to serialize/unserialize, I was just wondering if there is a common, concrete way to do this?

I will need to be able to search the array for its contents. So if children are eligible for the discount, I need to be able to store that in a database, retrieve it later, and search it for only "Children" so I can display the discounts available only to children.

If someone could please advise the best way to do this and post some examples, it would be greatly appreciated. I learn best with examples that are explained properly.

As part of a form submission, I have several textboxes   The textboxes have an array name such as text[].  I'm sending the textbox values via http request.  Sending an element value via http request is usually be done using document.getElementById, assigning the elements ID to a var and posting the var name .  Then accessing the value using $_POST.  However I'm sending an array of string values.  How do I access the array using $_POST?  Any help appreciated.

Hi, i have a transaction table which includes following fields.
 
    tran_ID,account_number,account_type,transaction_type,amount,Date

I want to know how these data can be retrieved and display in another table. The table is filled with several records.

Thanks,
Heshan

Hey Guys. I have a shopping cart script that loops through the shopping cart session  array and assigns values to the property of a class. For some weird reason the subtotal property only works when I use the self keyword. If I use the $this-> instance variable  the sub total does not get assigned the subtoal price. Its just NULL.   Does anyone have any suggestions as to why it may not be working.   Below is a quick copy and paste of my code. Please be aware that some there may be some syntax mistakes as a result to copying and pasting part of my code that is relevant to this issue. Thanks!

class CoreCartFunctions {

protected static $subtotal;
protected $menu_item_price = NULL;

public function GetMenuItem() {

//self:items is the cart session array that is initilized in a construct method
//Assign the values for each cart array
      foreach (self::$items as $menu_item_id_session) {


$this->menu_item_price = getItems($this->menu_item_id,"menu_item_price")*$this->item_qty;

self::$subtotal += $this->menu_item_price; 
//Does not work with the following ---> $this->subtotal += $this->menu_item_price; 

}




}

Hello,

I am having a problem with retrieving information from my database. I am kinda new in programming industry, and with the error message displayed, I can't pinpoint what went wrong in the code. Here is the PHP code:

<?php
include("dbconnection.php");

if(isset($_POST["btnSubmit"]))
{
$id = $_POST["id"];
$territory = $_POST["territory"];
$job_title = $_POST["job_title"];
$area_of_work = $_POST["area_of_work"];
$employer = $_POST["employer"];
$location = $_POST["location"];
$job_title = $_POST["job_title"];
$date_posted = $_POST["date_posted"];
$closing_date = $_POST["closing_date"];
$department = $_POST["department"];
$gender = $_POST["gender"];
$first_name = $_POST["first_name"];
$last_name = $_POST["last_name"];
$title = $_POST["title"];
$telephone = $_POST["telephone"];
$address_1 = $_POST["address_1"];
$address_2 = $_POST["address_2"];
$address_3 = $_POST["address_3"];
$country = $_POST["country"];
$city = $_POST["city"];
$postal_code = $_POST["postal_code"];
$website = $_POST["website"];
$email_address = $_POST["email_address"];
$cg_comment = $_POST["cg_comment"];
$date_emailed = $_POST["date_emailed"];
$mailing_comments = $_POST["mailing_comments"];
$telesales_comments = $_POST["telesales_comments"];

$query = "UPDATE contacts SET territory= '".$territory."', job_title = '".$job_title."', area_of_work = '".$area_of_work."', employer = '".$employer."', location = '".$location."', job_title = '".$job_title."', employer = '".$employer."', date_posted = '".$date_posted."', department = '".$department."', closing_date = '".$closing_date."', gender = '".$gender."', first_name = '".$first_name."', last_name = '".$last_name."', title = '".$title."', telephone = '".$telephone."', address_1 = '".$address_1."', address_2 = '".$address_2."', address_3 = '".$address_3."', country = '".$country."', city = '".$city."', postal_code = '".$postal_code."', website = '".$website."', email_address = '".$email_address."', cg_comment = '".$cg_comment."', date_emailed = '".$date_emailed."', mailing_comments = '".$mailing_comments."', telesales_comments = '".$telesales_comments."' WHERE id = '".$id."'";
mysql_query($query) or die(mysql_error());

echo "<script>
alert('You have successfully updated a record');
window.location = 'view.php';
</script>";
}

$query = "SELECT * FROM contacts WHERE id = '".$_GET["id"]."'";
$result = mysql_query($query, $connection);

if(mysql_num_rows($result) > 0)
{
$territory = mysql_result($result,0, "territory");
$job_title = mysql_result($result, 0, "job_title");
$area_of_work = mysql_result($result, 0, "area_of_work");
$employer = mysql_result($result, 0, "employer");
$status = mysql_result($result, 0, "status");
$location = mysql_result($result,0, "location");
$department = mysql_result($result,0, "department");
$date_posted = mysql_result($result,0, "date_posted");
$closing_date = mysql_result($result,0, "closing_date");
$gender = mysql_result($result,0, "gender");
$first_name = mysql_result($result,0, "first_name");
$last_name = mysql_result($result,0, "last_name");
$title = mysql_result($result,0, "title");
$telephone = mysql_result($result,0, "telephone");
$address_1 = mysql_result($result,0, "address_1");
$address_2 = mysql_result($result,0, "address_2");
$address_3 = mysql_result($result,0, "address_3");
$city = mysql_result($result,0, "city");
$country = mysql_result($result,0, "country");
$postal_code = mysql_result($result,0, "postal_code");
$website = mysql_result($result,0, "website");
$email_address = mysql_result($result,0, "email_address");
$cg_comment = mysql_result($result,0, "cg_comment");
$date_emailed = mysql_result($result,0, "date_emailed");
$mailing_comments = mysql_result($result,0, "mailing_comments");
$telesales_comments = mysql_result($result,0, "telesales_comments");
}


?>

The error I am getting is:

Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in C:\xampp\htdocs\invent-asia\edit_client.php on line 268

Line 268 in the code is:

Quote

if(mysql_num_rows($result) > 0)
{ - This one is line 68
   $territory = mysql_result($result,0, "territory");


Immediate response is well appreciated. Thank you very much!

hello, im only getting the second half of my results showing in my dropdown box.  here is my code.

Code: [Select]
if(isset($_GET['id']))
{
$uid = $_GET['id'];
}

$forward = mysql_query("SELECT * FROM players WHERE status = '1' AND position = 'forward' ORDER BY name");
$forward1="";
while($row1 = mysql_fetch_array($forward))
  {
$forwardid=$row1["id"];
$forwardname=$row1["name"];
$forwardteam=$row1["team"];
$forward1.="<OPTION TITLE=\"$forwardteam\" VALUE=\"$forwardid\">".$forwardname.'</option>';
  }

$result = mysql_query("SELECT * FROM picks WHERE uid = '$uid' AND pickid = 'forward1'");
while($row = mysql_fetch_array($result))
{
  $playerid=$row['playerid'];
}

if(isset($forwardpick1)) {
$result1 = mysql_query("SELECT * FROM players WHERE id = '$playerid'");
while($row1 = mysql_fetch_array($result1))
{
  $forwardpick1=$row1['name'];   
}
$forwardpick1="<br /><br /><font color ='#000000' size = '5'><b>$forwardpick1";
} else {
$forwardpick1="
<form method='POST' action='draftpick.php' name='forward1'>
<p><font color='#000000'><select size='1' name='player'>
<?php echo '$forward1'; ?>
</select><br><br><input type='submit' value='Submit' name='submit'></font></p>
</form>
";
}
any direction is appreciated.

Hi All, small question here. I was just playing around with a small script I made to obtain an ip-address, remove the dots and than glue the parts together. Not for any use but for practice. But I am having difficulties to accessing the array values. But maybe that because its the first time i am using explode() and print_r. If someone has a spare minute I would be pleased to be enlightened.

<?php
             $ip=$_SERVER['REMOTE_ADDR'];
             echo $ip.'<br />';
             $cleaned_ip = substr($ip,0,6);
             echo $cleaned_ip.'<br />';
             $cleaned_ip2 = print_r(explode('.', $ip, 6)).'<br />';
             // this is the point where I dont know how to get the array values.
             // echo $cleaned_ip2[0].[1].[2];   that doesnt work. ;(
         ?>