PHP - Replace "." In The Text
In the text,
Code: [Select] It will eventually go away.Once the carriers merge, the combined airline, will operate as Southwest. It has its logo and colors. 2.3 AirTran brand will no longer be used. In the above text, how to replace "." with ". " and not in 2.3. how to add space after "." only if it has alphabets and not to replace after numeric characters. Similar TutorialsHi, bit stuck on how to find and replace "<" and ">" with "<" and ">". I basically have a database record that outputs to screen and I need the code in the <code> tags to be rendered to the screen. I therefore need it to go through the whole array variable from the db and change the symbols just inside the code tags. Please be aware that the code tags might happen more than once here's an example below Code: [Select] <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1> </code> <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1> </code> the desired output would be: <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1 </code> <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1 </code> help on this would be great Cheers Rob Hi guys I'm struggling a bit, I need to replace a word that occurs multiple times in text with an array("up","down","forward","backwards") of words. $find = "left"; $replace = array("up","down","forward","backwards"); $text = "left left left left"; echo str_replace($find,$replace,$text); The Output is: array array array array Did try this with a foreach statement as well, but no luck. Is there a better way of doing this? Thanks Can someone please help me with an array problem i can not figure out. I need the array to be numbered from 1 to how ever many fields that are needed in the form and have a mysql field name and the title of the field also in the array. 1, "mysql_field_name", "Title of form field" 2, "", "" and so on then the form will be shown based on the array. I have the following draft code which I am working with. any suggestions on how i may do this array ? Code: [Select] <?php $options = array( '1'=> array('fieldtext'=>'option1', 'mysqlfield'=>'option1'), '2'=> array('fieldtext'=>'option2', 'mysqlfield'=>'option2'), '3'=> array('fieldtext'=>'option3', 'mysqlfield'=>'option3'), '4'=> array('fieldtext'=>'option4', 'mysqlfield'=>'option4'), ); // $options = array(1 => "option1", "option2", "option3", "option4"); // the line above works but i want to include the name of the mysql field as well. $userid = 1; ?> <div style="align: center; margin: 12px; font-family:Tahoma;"> <br><br><?php if ($_POST['Update'] != "Update") { // check if form submitted yet, if not get data from mysql. $res = db_query("SELECT * FROM `users` WHERE `userid` = '" . $userid . "'"); foreach($options as $key => $value) { $_POST[$key] = mysql_result($res, 0, $value); } $ok_to_update = "no"; } elseif ($_POST['Update'] == "Update") { // check if form submitted yet, if so get POST data. // error checking // foreach($options as $key => $value) { // $_POST[$i] = ""; // } $ok_to_update = "yes"; } if ($_POST['Update'] == "Update" && $ok_to_update == "yes") { // $res = db_query("INSERT INTO `users` () VALUES ()"); // add user details to database. ?><p><br><br><br>Thank you for updating</p><?php } else { ?><form name="form1" method="post" action=""> <?php foreach($options as $key => $value) { ?><p><?php echo($value); ?>: <input type="text" name="<?php echo($key); ?>" value="<?php echo($_POST[$key]);?>"></p> <?php } ?> <input name="Update" type="submit" value="Update"> </form> <?php } ?> </div> So I wanted to create stickers on my forum where people type in say ":Blobby-Tired" and then instead of the comment showing ":Blobby-Tired" it shows an html image tag displaying a picture of Blobby in the comment box So I created the following page CommentUpload.php However my sql fails to insert it despite the fact when I "echo $new" it shows the image on the page correctly And it can't be my sql insert code as if I change $new variable for "$BodyText" int he SQL query it it inserts ":Blobby-Tired" OK?
<?php include 'dbconnect.php'; session_start(); if(isset($_POST["submit"]) && !empty($_POST["CommentText"])){ $id = intval($_SESSION['id']); echo $_SESSION['id'] . '<p> </p>' ; $BodyText = $conn -> real_escape_string($_POST['CommentText']) ; $User = $_SESSION['username']; //Replace flairs with <img> tags /*not working currently) */ $new = str_replace(":Blobby-Tired","<img src='flairs/Blobby-Tired.jpg'> </img>","'$BodyText'"); echo "$new"; /************************/ $sql = "INSERT INTO Posts (User, CommentText, IdOfThread) VALUES ('$User','$new','$id')"; if (mysqli_query($conn, $sql)) { echo "New record has been added successfully !"; } else { echo "Error: " . $sql . ":-" . mysqli_error($conn); } mysqli_close($conn); } ?> Edited April 28 by Fishcakes I have a website that has definitions and articles. I need a code that craws the php content pulled from my database, finds a specified word and replaced that word with a link. For example If "car" appears replace with <a href="http://www.website.com/car.php">car</a> Thanks Todd Im dealing with html links in a database where I need to execute a small piece of php code. Well mysql doesnt execute php code thats held in a table. The easiest way for me to do this is just add the links without the code, & set up a function that will replace anything I set to for example in my case a link lookin like this: http://mysite.com/index.php?page=offers&blah=blah&sid= needs to look like this; http://mysite.com/index.php?page=offers&blah=blah&sid=<?php echo $_SESSION['login']; ?> so I would need a function like <?php $replace('sid=','sid=<?php echo $_SESSION['login'];?> ?> something like that. And I know its possible & I could create a function like this but honestly right now I am so tired after working 12 hours im lazy dont want to think to hard while I know there are a lot of people out there that have a function like this already. If you dont have one & dont feel like writing one for me could you atleast point me in the right direction so I dont have to think to hard?! Thanks!! Hi guys I am a newbie with PHP and I have been trying to solve this problem for 3 days.. Ive set up a booking form on my website to be sent directly to my email once the client clicked on the send button.. The problem I am having while checking these pages on wamp is that the booking form is ok but when I click on the send button the following message error appears "Warning: mail() [function.mail]: Failed to connect to mailserver at "localhost" port 25, verify your "SMTP" and "smtp_port" setting in php.ini or use ini_set() in C:\wamp\www\fluffy_paws\booking_form2.php on line 27" When I check online I have this message "500 - Internal server error. There is a problem with the resource you are looking for, and it cannot be displayed." Are my codes wrong??? My webhosting is Blacknight.com , Im on Windows Vista, my internet is a dongle with O2 ireland Thanks for your help! Hi everyone!! I just started learning PHP two weeks ago and I hope someone can help me!! I need to do a find and replace on a string, and each replace needs to have an unique id, and if that unique id exists in a table then return the value on the table. Make sense? So like "find all the Xs in the string, replace with "X1, X2, X3...", then if "X3' exists on TableB, return value "X3 is on the table and has a value of Y3". I actually got this to work already but it takes a long time to do it so I'm hoping someone could give me some advice on how to make it more EFFICIENT: // PART ONE, find all "X" and replace with unique_id for ($count = 1; $count <= strlen($string); $count++) // do this loop as many times as there are characters in $string { $unique_id = "replacement_" . $count; // give each replacement an unique id (replacement_1, replacement_2, replacement_3, etc..) $string = preg_replace("X", $unique_id, $string , 1); // find X and replace it with the $unique_id in $string, and only do this ONCE } $count_replacements = substr_count($string,"replacement_"); // count how many replacements occured in total // PART TWO, find all unique_ids in tableB and echo the unique_id_value for ($count = 1; $count <= $count_replacements; $count++) // do this loop as many times as there were replacements { $unique_id = "replacement_" . $count; // set the unique_id of each replacement $show_tableB = mysqli_query($link, 'SELECT * FROM tableB'); // select the unique_ids and the unique_id_values in TableB while ($row = mysqli_fetch_array($show_tableB)) { $tableBs[] = array('unique_id' => $row['unique_id'], 'unique_id_value' => $row['unique_id_value']); } foreach($tableBs as $tableB): // for each entry in TableB, if the unique_id in TableB matches the unique_id of the replacement, return the unique_id_value if ($tableB['unique_id'] == $unique_id) { echo $unique_id . " is on TableB and it has a value of ". $tableB['unique_id_value'] } endforeach; } The problem with this is: its not very efficient. If $string has 500 charachters, it does the "PART ONE" 500 times. Then, say it found 300 Xs, it does "PART TWO" 300 more times. And every time it does "PART TWO", it checks all entries in TableB (which could be 200 or more). So, that's it. Anyone has a better idea of how to do this?? Thanks!!!! cant work out this mysql syntax error "operation":"medupdate","medid":"","name":"ibo","medyear":"5","medmonth":"21","medday":"1","recuser":1,"SuccFail":"fail","SuccFailMessage":"error occured You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '''WHERE med_id=' at line 2","ResultData":""} Code: [Select] $sql="update metodology set med_description='".$req['name']."', med_year='".$req['medyear']."', med_month='".$req['medmonth']."', med_day='".$req['medday']."', med_recorddate= now(), med_recorduserid= 1'"; $sql.= " WHERE med_id=".$req['medid']; I am getting the following error when using composer: "continue" targeting switch is equivalent to "break". Did you mean to use "continue 2"? Just started. I am pretty sure composer.json wasn't changed. journalctl doesn't show anything. Maybe Doctrine related, however, nothing seems to help.
Any ideas? [michael@devserver www]$ php -v PHP 7.3.4 (cli) (built: Apr 2 2019 13:48:50) ( NTS ) Copyright (c) 1997-2018 The PHP Group Zend Engine v3.3.4, Copyright (c) 1998-2018 Zend Technologies with DBG v9.1.9, (C) 2000,2018, by Dmitri Dmitrienko [michael@devserver www]$ composer -V Composer version 1.4.2 2017-05-17 08:17:52 [michael@devserver www]$ yum info composer Loaded plugins: fastestmirror Loading mirror speeds from cached hostfile * base: mirror.us.oneandone.net * epel: mirror.rnet.missouri.edu * extras: mirror.us.oneandone.net * remi-php73: mirror.bebout.net * remi-safe: mirror.bebout.net * updates: mirror.us.oneandone.net Installed Packages Name : composer Arch : noarch Version : 1.8.4 Release : 1.el7 Size : 1.8 M Repo : installed From repo : epel Summary : Dependency Manager for PHP URL : https://getcomposer.org/ License : MIT Description : Composer helps you declare, manage and install dependencies of PHP projects, : ensuring you have the right stack everywhere. : : Documentation: https://getcomposer.org/doc/ [michael@devserver www]$ composer update Loading composer repositories with package information Updating dependencies (including require-dev) [ErrorException] "continue" targeting switch is equivalent to "break". Did you mean to use "continue 2"? update [--prefer-source] [--prefer-dist] [--dry-run] [--dev] [--no-dev] [--lock] [--no-custom-installers] [--no-autoloader] [--no-scripts] [--no-progress] [--no-suggest] [--with-dependencies] [-v|vv|vvv|--verbose] [-o|--optimize-autoloader] [-a|--classmap-authoritative] [--apcu-autoloader] [--ignore-platform-reqs] [--prefer-stable] [--prefer-lowest] [-i|--interactive] [--root-reqs] [--] [<packages>]... [michael@devserver www]$
This topic has been moved to Linux. http://www.phpfreaks.com/forums/index.php?topic=318175.0 This topic has been moved to PHP Installation & Configuration. http://www.phpfreaks.com/forums/index.php?topic=347922.0 Hi, I currently have an if, elseif, else program that starts off with Code: [Select] if( $v_name == "" || $v_msg == "" ) echo "something" how do I turn this into a switch? but the very next elseif I have Code: [Select] elseif( strcspn( $_REQUEST['msg'], '0123456789' ) == strlen( $_REQUEST['msg'] ) ) echo "something" is it possible to turn this into a switch with 2 different strings like that to evaluate? I have a registration form on my website and after Registration I want the user to activate first his account. I don't have problem on sending this email to the user. What I want to appear is like this.. GoodDay "username", Blah Blah! how can you actually do that? I know that you can do that through session variables but the thing is email's can't accept scripts on sending emails. how can I get the value from a session variable for example and convert it to plain html text so that i can OUTPUT it to the email.. HELP PLEASE! hello, I was wondering what is the point of writing for a dropdown: <?php if ($_POST[inputfieldID] == "value") { echo "selected"; } ?> or for a checkbox/ radio button: <?php if ($_POST['cb/radioID'] == "value") { echo "checked"; } ?> I guess it's for after submit, if there is any error, the values filled will still be echoed in the inputfield, or am i wrong? But then if that is true, i have a php search box where i use AJAX object to to send all the input they filled in after submit. But after pushing submit the inputted values remain. I guess when using AJAX to send the information i don't need <?php if ($_POST[inputfieldID] == "value") { echo "selected"; } ?> in my html forms? Little confused Can maybe somebody bring clearness Hey guys! I have the following doubt: I have a php file that does the following alongside with other code not displayed he $fp = fopen("emails.txt", "w"); It opens a txt file called emails.txt that is in the same folder where the php is saved but how do I tell $fp = fopen("/folderbefore/emails.txt", "w"); ?? In other words, how do I write the path on the script that the emails.txt is located in a previous folder where the php file is located?? Thanks in advance for your help Cheers! Hi all, Using a form with check boxes divided into different categories, I collect data selected by the user. I now want to combine each choice in each category with each choice in the other categories and list the combinations to the user. If the user chooses one or more options in each category, it is relatively easy to nest foreach loops, since the number of categories will always be the same. For example, if the form contains three categories of options, the code will be: Code: [Select] foreach ($form['cat_1'] as $k1 => $val1) { foreach ($form['cat_2'] as $k2 => $val2) { foreach ($form['cat_3'] as $k3 => $val3) { echo $val1.' _ '.$val2.' _ '.$val3.'<br/>'; } } } Things get complicated if the user does not select options within a given category. More generally, I want to be able to generate the list regardless of the number of categories in which the user selects options. Thank you in advance for your advice. Hi. I have just one question (I have searched for an answer for this but have not been able to locate one): How do you go about changing the text on a "Submit Query" button to display simply "Submit"? Below is the current code for the page that displays said button. Thank-you in advance for any help or direction. <?php include 'connection.php'; $query = "SELECT * FROM people"; $result = mysql_query($query) or die(mysql_error()); while ($person = mysql_fetch_array($result)){ echo $person ['name']; echo $person ['descrip']; } ?> <H1>Add Your Review:</H1> <form action="create.php" method="post"> Subject <input type="text" name="inputName" value=""/> </br > Review <textarea cols="50" rows="4" name="inputDesc" value=""/></textarea> </br > <input type= "submit" name= "submit"/> </form> <html> <head></head> <body> <p>The current second is <span style='font-size:16px;font-weight:bold;color:red;position:absolute;right:25px;'><?php echo time(); ?></span> on this computer.</p> </body> </html> Hi.. I used this code for displaying formatted number and I notice that instead comma(,) it become point(.): Code: [Select] $P28_maxdoz = $row['P28_maxdoz']; $P28_maxdoz = number_format($P28_maxdoz, 2, '.', ','); <table> <tr> <td><input type='text' name='P28_maxdoz' value="<?php echo $P28_maxdoz;?>"></td> </tr> </table> the output is : 22.782.20 i need output is : 22,782.20 Thank you I have a text file that contain something like this : question.txt ------------------------ 12/10/2010 Quest : Was a web designer really care about your web security other than thinking so hard to design your web just based on how the web will looks like?. >>from:sombody@somwhere.com,opinion=not at all,comment:your site are cool 11/10/2010 Quest : Was a web designer really love his girl friend in other side they r almost got no time dating with her? >>from:sombody@somwhere.net,opinion=he loves computer,comment:your site are waste. ------------------------- All i need to do is, grabing all informations after the char ">>" and write it to another text file name "output.txt" that will contain : output.txt --------------------- from:sombody@somwhere.com,opinion=not at all,comment:your site are cool from:sombody@somwhere.net,opinion=he loves computer,comment:your site are waste. --------------------- can some one show me the way? thanks. |