PHP - Help With Date/time Fetch
Okay, I have this form system/processor I have programmed and I am having a minor issue. When the form data is sent via email I want the date/time the user submitted the information included in the email, mainly for records. Now, I thought using $_SERVER['REQUEST_TIME'] would work, but it is returning a value of "1320019222" in the email, any tips on how to fix this??
Thanks!! Similar TutorialsHey guys, How would I go about subtracting Today from a previous day to find the difference? For example, I want to subtract TODAY from a previous date in my database, to determine if the difference is greater than 1 day. Any ideas? I tried doing the subraction in TIMESTAMPS, but when I convert the date back to Y-m-d H:i:s, I got some weird year and time. PHP date and time function is not showing correct time on my local system I have the following php code date_default_timezone_set("Africa/Lagos"); $date = date('d-m-y h:i:s'); echo "Server Time ".$date ."<br>"; echo "The time is " . date("h:i:sa")."<br>"; $current_datetime = date("Y-m-d") . ' ' . date("H:i:s", STRTOTIME(date('h:i:sa'))); echo "Current time1: ".$current_datetime . "<br>";
Output
Server Time 21-05-21 09:55:39
Expected Output
Server Time 21-05-21 10:55:39
Any help would be appreciated. Edited May 21 by Ponel OK So I've got a datepicker that sends a date in d/m/y format. My DB stores the data in Unix Timestamp Which I can convert the date to with strtotime however this does the exact date & time. All I want is the actual day. I've spent hours trying to convert this with just the day with mixed results... Thanks. I am having a problem with PHP displaying the correct date and time. It updates as it should, but is fast by 4min and is always displaying a date in 2004. I ran a basic php script to make sure the application im using itself is not wrong. go to lunenburgledger.com/time.php Anybody had any ideas on where to check? The system time on the Windows Server 2003 is correct. The only thing I can think of is that it was converted to a virtual machine on vmware esxi, but the system time stayed right. Any ideas? Thanks! Hi! The below dropdown will show dates/times every 15 minutes from 12am to 11:45pm for only 1 day. I want it to show for 5 days, anyway I can do this? Below code: Code: [Select] $start = strtotime('12:00am'); $end = strtotime('11:45pm'); echo '<select name="time">'; for ($i = $start; $i <= $end; $i += 900) { echo '<option>' . date('F j, Y, \a\t g:i a', $i); } echo '</select>'; Thanks for any help. What is the best way to insert this time stamp into mysql? This is the info I want... Example: Sunday, 28.1.11, 9:56 How would I also select time from the database using mysql? I have a field set as datetime and want to compare that field to see if it is older then ten minutes. Can anyone help I am having a brain fart? Hey, I need help with my date & time string. I need to edit it do show in a string + also use it for calculating things like when the date has passed. The string is like this: Code: [Select] <?php $string = '2011-01-01 00:00 AM'; ?> So i wanted to check if there was a function that can automatically convert it, so it would say for example: Quote Sunday, 1st of January 2011 00:00 AM But at the same time compare $string against server time to see if the date has expired? Hope you can help Hey, I need help with date, I have stored dates in my table in this format: i.e. 22.10.2011 but now use timestamp to store dates. Problem is with this query the WHERE clause will find dates in the old format and I want to change that to the new format. Code: [Select] for($i = $count; $i > 0; $i--) { $day = date("d.m.Y", mktime(0, 0, 0, date("m"), date("d") - $i, date("Y"))); $tmp = mysql_fetch_array(safe_query("SELECT count FROM ".PREFIX."counter_stats WHERE dates LIKE '%".$day."'")); $array[] = $tmp['count'] ? $tmp['count'] : 0; } Am I making sense ? I have a batch script that reads from a timestamp.txt file to determine the last time it ran and I need to modify that by two hours. What happens is the script will run to look for changes in the county records and their server time is two hours different from mine. Code: [Select] $fr=fopen("xml/timestamp.txt",'r'); $mydate=fread($fr, 50); if ($incremental_updates == 1){ $default_template_file="xml/incremental_template.xml"; $default_config_name="xml/incremental.xml"; $contest=file_get_contents($default_template_file); $contest=str_replace("{DATE_TAG}", $mydate, $contest); $f=fopen($default_config_name,'w+'); fwrite($f, $contest); fclose($f); fclose($fr); $fw=fopen("xml/timestamp.txt",'w'); fwrite($fw, substr(date('c'), 0, 19)); fclose($fw); }else{ $default_config_name = "xml/full_update.xml"; } I tried making a time stamp update look like $cur_timestamp=date("Y-m-d H:i:s", time() +14400); which is correct but it doesn't write to the text file properly. Using the above fwrite($fw, substr(date('c'), 0, 19)); I get the correct results in the timestamp.txt file for my server time. I need it to be +14400 2011-05-25T08:27:51 would essentially become 2011-05-25T10:27:51 when it writes to the timestamp.txt I hope that makes sense. J Is it possible to convert time(); to date();? how to calculate the difference between the current datetime from the stored one(ie date_field = 2020-08-09 23:13:06) in order to compare with 15min, i mean if the resulted time exceed 15 min and not the same day(date) the provided link will show expire message. i.e $some_variable = $date_in_db - current_date; if((time() - $some_variable > 15*60) && not the same day or the same day){ echo 'the link has expired'; }
Hi, I'm preparing a code for an automated email, but the date time is not working correctly. I wanted to do a cron scheduler that emails people twice a day - 9am and 9pm. 9am sends email about records logged starting 9pm yesterday to 9am, while 9pm sends email about records logged from 9:01am to 9:00pm. The database uses date/time, so I was doing an if statement of date time, but I wasn't getting the result I wanted. Sometimes the $now time is not within the yesterday 9pm to the 9pm today range. I don't know what I'm doing wrong, but I'm sure that it has something to do with the if statement, as the some of the $now time enters the else statement Here is my code: <?php $today = date('Y-m-d 00:00:00'); $nineyesterday = date('Y-m-d H:i:s', mktime(date("H") - (date("H") + 6), date("i") - date("i"), date("s") - date("s"), date("m") , date("d"), date("Y"))); $now = date('Y-m-d H:i:s', mktime(date("H") + 13, date("i"), date("s"), date("m") , date("d"), date("Y"))); $nineam = date('Y-m-d 09:00:00'); $nine30 = date('Y-m-d 09:30:00'); $ninepm = date('Y-m-d 18:00:00'); echo '9pm yesterday: '.$nineyesterday; echo '<br/>'; echo '9am: '.$nineam; echo '<br/>'; echo '9pm: '.$ninepm; echo '<br/>'; echo 'now: '.$now; echo '<br/>'; if ((strtotime($now) > strtotime($nineyesterday)) and (strtotime($now) <= strtotime($nineam))) { //count the answers by yes or no echo 'am'; } elseif ((strtotime($now) > strtotime($nineam)) and (strtotime($now) <= strtotime($ninepm))) { //count the answers by yes or no echo 'pm'; } else { echo 'error'; } ?> Thanks in advance I have a form that has this: Code: [Select] <input type="text" name="notes_date" size="10" value="<?php echo date("m/d/Y");?>" /> I enter into the database after processing the variable like this: Code: [Select] $notes_date=date ("Y-m-d H:i:s", strtotime($_POST['notes_date'])); However, it gets stored at 2012-03-15 00:00:00 How do I fix this so that the current time gets stored instead of 00:00:00? I'm trying to make $time be a variable with the current time and I want it to have the same format as mysql. I can't figure out what I am doing wrong here Wrror: Warning: date_format() expects parameter 1 to be DateTime, integer given Code: [Select] $time = date_format(time(),'Y-m-d H:i:s'); Hi there, what I have been trying to do is add some additional logic.. My problem is I want to stop displaying the month and day after the year 2000? I know I need to add an if and else statement but this is my first actual project and I am a little stuck.. here is the page, it's a plugin for a timeline http://www.llandover...oject-timeline/
And the file is attached below.. any help would be appreciated. The plugin code was too long to just post in here, didn't want to cause any slow loading issues for people on a slow connection.. Thanks and I appreciate any help.
Attached Files
annual_archive.php 18.15KB
5 downloads hi, I have some code that deals with sending out reminders for appointments due the following day. So if today is the 21/3 then only reminders for appointments due on the 22/3 should be sent. Currently this isn't happening... If reminders are sent on 21/3 at 9.50 am, my code adds 24 hours to this datetime and sends reminders due for all appointments that fall bewteen 21/3 9.50am and 22/3 9.49 am. What I want to do is simply send all reminders for appointments that are on the 22/3 exclusive of time. I'm not sure how do this in php, which uses the unix datetime format to mildy complicate issues anhy help or solutions would be massive, thanks.how to Code: [Select] $days = time() + (1 * (60 * 60 * 24)); $apts = $db->fetch_all('status = 1 AND time > ? AND time < ?', array(time(), $days)); I just recalled using date(); time() for lots of things in my database, including post times etc. At first I simply assumed this used server time or something, but when I changed my PC's time, it changed ! Now, shortly after this I simply assumed this was because of me using a localhost? But I am not certain anymore.. If I would place this online, would date() and time() return you server time or user time? I couldnt find it on google =-( I'm having some trouble understanding how to use date and time when updating my database. The table is already populated with Date and Time fields in date and time format. I need to update the table based on the date and time, but I can't make it work. I tested all the variables and they are being sent correctly. I'm pretty sure the problem lies in how I'm trying to match the Date and Time fields with $dateID and $timeID in the WHERE part of the query, but I'm not sure how to fix that! Code: [Select] <?php include("opendatabase.php"); $size = count($_POST['player1']); $i=0; $thisyear = date("Y"); while ($i < $size) { $dateID = $_POST['date'][$i]; $timeID = $_POST['time'][$i]; $player1 = ($_POST['player1'][$i]); $player2 = ($_POST['player2'][$i]); $player3 = ($_POST['player3'][$i]); $player4 = ($_POST['player4'][$i]); $player5 = ($_POST['player5'][$i]); mysql_query(" UPDATE Daysheets$thisyear SET Player1='$player1', Player2='$player2', Player3='$player3', Player4='$player4', Player5='$player5' WHERE Date = '$dateID' AND Time = '$timeID' "); $i++; } header("Location: /teetimes/publicteetimes.php?teetimedate=$dateID"); mysql_close($con) ?>Any help appreciated! I should also mention that whenever I run this query it erases anything that was previously entered in the database except the date and time columns... |