PHP - Retrieving Contents From A Page That You're Probably Not Meant To

Hi dear community

i want to run a Curl  to get the contents of a remote web page into a PHP variable



<?php
//
// The PHP curl module supports the received page to be returned in a variable
// if told.
//
$ch = curl_init();

curl_setopt($ch, CURLOPT_URL,"http://www.myurl.com/");
curl_setopt($ch, CURLOPT_RETURNTRANSFER,1);
$result=curl_exec ($ch);
curl_close ($ch);
?>

I declare this variable:($ch)

Well - can i work with this variable - eg. to parse this with a parser!?

look forward to hear from you

$result=curl_exec ($ch);

gretings

I have a basic table where I am trying to retrieve records that are filtered by a form request. Here is the code I have...

$ps = $pdo->prepare("SELECT * FROM `Products` Where `Vendor` LIKE concat('%',?,'%');
$ps->execute(array($_POST['Vendor']));;
echo "post=" . $_POST['vendor']; ////Displays correct data from form request
$count = $ps->rowCount();
echo "Count=" . $count; ////Count = 0 although I know for a fact that there is 1 record that should be in there

////Used for display of records
foreach ($ps as $row){
echo $row, PHP_EOL . "xxx<br>";
}

Where is the incorrect code? I am new to php and pdo. Thank you in advance

K

i am trying to retrieve messages with some code.  It seems to be a bit more complicated that i thought it would be.  so here it goes:

Code: [Select]
$query = "SELECT * FROM memberMail WHERE userIDFrom='92' AND unread='1'"; 
$result = mysql_query($query) or die(mysql_error());
if (mysql_num_rows($result) > 0) {
$row = mysql_fetch_array($result) or die(mysql_error());

$num_rows = mysql_num_rows($result);

echo "You have (" . $num_rows . ") unread message(s).";

$i = 0;
for($i; $i<$num_rows; ++$i) {
if($row[$i[unread]] == "1") {
echo $row[$i[message]] . "<p>";
}
}

}
what i am trying to do, is print out the messages from the records that are unread, and are from a certain user.  i don't think this for statement will pick up the record numbers that got matches though.  and i am not entirely sure about the $row statements in the for statement either.

Hi,

so i have a problem. I'm using a script to enable and disable checkboxes, and i'm id-ing them fetching values from a database:

while($data = mysqli_fetch_array($sql))
{
  if ($count % 5 == 0) {
    echo '</tr><tr>';
    $count = 0;
  }
  echo '<td><input name="subject_level[]" class="subject_a" disabled="disabled" type="checkbox" id="subject_level_'.$data['subject_level_id'].'" value="'.$data['subject_level_id'].'"/>';
  echo '<label for="subject_level_'.$data['subject_level_id'].'" class="subject_1">'.$data['subject_name'].'</label></td>';
  $count++; //Increment the count
}

The names of the checkboxes come out fine, just that, is there any way to retrieve the values of the checkboxes into an array of some sort so that i could build a search query later?

if($_POST(subject_level)) or if($_POST(subject_level[]))  doesn't return true. does it make sense? im new to php so please forgive my ignorance. Help appreciated. Thanks!

In my script, users login with their Username & Password. However, I'd like to be able to echo the email address used on their account. I've tried adding the email to the session
I'm not having much luck... Here's a piece of the login code(untouched);

                $username = $_POST['name'];
                $passwd = $_POST['passwd'];
                $query = "SELECT name,passwd FROM users WHERE CONCAT('0x', hex(passwd)) = '{$salt}'";
		$result = mysql_query($query);
		$login_ok = false;
		if(mysql_num_rows($result) > 0) {
		    $login_ok = true;
		}
		if($login_ok)
		{
		    $row = mysql_fetch_array($result, MYSQL_NUM);
		    $_SESSION['user'] = $row;

I've also tried messing around with this piece below in a few different ways but still nothing.

<?php echo htmlentities($_SESSION['user']['email'], ENT_QUOTES, 'UTF-8'); ?>

Any help is greatly appreciated..

Hi,
I need to get data from an XML file, like the format below:
Code: [Select]
<ISBNdb server_time="2011-05-31T19:19:42Z">
<BookList total_results="1" page_size="10" page_number="1" shown_results="1">
<BookData book_id="build_your_own_database_driven_web_site_using_php_mysql_4th_" isbn="0980576814" isbn13="9780980576818">
<Title>
Build Your Own Database Driven Web Site Using PHP & MySQL, 4th Edition
</Title>
<TitleLong/>
<AuthorsText>Kevin Yank, </AuthorsText>
<PublisherText publisher_id="sitepoint">SitePoint</PublisherText>
<Details change_time="2009-04-02T00:30:10Z" price_time="2011-05-31T17:46:10Z" edition_info="Paperback; 2009-06-15" language="" physical_description_text="360 pages" lcc_number="" dewey_decimal_normalized="5" dewey_decimal="005"/>
</BookData>
</BookList>
</ISBNdb>
I need to know how you get the details from <title>,<AuthorsText><PublisherText> and Bookdata. Tried using the example on W3C, using simplexml_load_file but it only returns:
Code: [Select]
ISBNdb
BookList:
Code I'm currently using is:
Code: [Select]
$xml = simplexml_load_file("http://isbndb.com/api/books.xml?access_key=----&results=details&index1=isbn&value1=".$isbn);
echo $xml->getName() . "<br />";

foreach($xml->children() as $child)
  {
  echo $child->getName() . ": " . $child . "<br />";
  }

i have this script called view.php
Code: [Select]
<?php
  include 'db.inc';

  $file = clean($file, 4);

  if (empty($file))
     exit;

  if (!($connection = @ mysql_pconnect($hostName,
                                       $username,
                                       $password)))
     showerror();

  if (!mysql_select_db("Php_test", $connection))
     showerror();

  $query = "SELECT mime, data FROM file 
            WHERE id = $file";

  if (!($result = @ mysql_query ($query,$connection)))
     showerror();  

  $data = @ mysql_fetch_array($result);

  if (!empty($data["data"]))
  {
    // Output the MIME header
     header("Content-Type: {$data["mime"]}");
    // Output the image
     echo $data["data"];
   }
?>after i have db.inc
Code: [Select]
<?php

// These are the DBMS credentials
$hostName = "localhost";
$username = "root";
$password = "oxioxi";

// Show an error and stop the script
function showerror()
{
   if (mysql_error())
      die("Error " . mysql_errno() . " : " . mysql_error());
   else
      die("Could not connect to the DBMS");
}

// Secure the user data by escaping characters 
// and shortening the input string
function clean($input, $maxlength)
{
  $input = substr($input, 0, $maxlength);
  $input = EscapeShellCmd($input);
  return ($input);
}

?>and i have my page witch part of it is  this
Code: [Select]
   <?php
  include 'db.inc';
  
  $query = "SELECT id, name, mime FROM file";

  if (!($connection = @ mysql_pconnect($hostName, 
                                    $username,
                                    $password)))
     showerror();

  if (!mysql_select_db("php_test", $connection))
     showerror();
        
  if (!($result = @ mysql_query ($query, $connection)))
     showerror();
?>
    <h1>Image database</h1>


<?php 


  if ($row = @ mysql_fetch_array($result))
  {
?>

    <table>
    <col span="1" align="right">
    <tr>
       <th>Short description</th>
       <th>File type</th>
       <th>Image</th>

    </tr>
<?php
   do 
   {
?>
    <tr>
       <td><?php echo "{$row["name"]}";?></td>         
       <td><?php echo "{$row["mime"]}";?></td>
       <td><?php echo "<img src=\"view.php?file={$row["id"]}\">";?></td>
    </tr>
<?php
   } while ($row = @ mysql_fetch_array($result));
?>
    </table>
<?php
  } // if mysql_fetch_array()
  else
     echo "<h3>There are no images to display</h3>\n";
?>i have do it right but for some reason it doesnt displays the pictures the type and the name are displayed normally but not the picture!! instead of them there are small icons of not existing pictures.. please i want help i really need to do it

$qID = '';
$question = 'Question not set';
$answerA = 'unchecked';
$answerB = 'unchecked';
$answerC = 'unchecked';
$answerD = 'unchecked';
$answerE = 'unchecked';



?>

<html>
<head>
<script type="text/javascript">
function show_alert()
{
alert("Please Click OK to proceed!");
                 
}
</script>
</head>
<form action="Process1.php" method="POST">
<table>
<tr>
<td>
<?php

$SQL = "SELECT stu_satisfaction_tblquestions.question_id, stu_satisfaction_tblquestions.question, answer_type.answer1, answer_type.answer2, answer_type.answer3, answer_type.answer4, answer_type.answer5 FROM stu_satisfaction_tblquestions INNER JOIN answer_type ON stu_satisfaction_tblquestions.answers_id=answer_type.answers_id
";
$result = mysql_query($SQL);
while($db_field = mysql_fetch_assoc($result)){

   $qID = $db_field['question_id'];
   $question = $db_field['question'];
   $A = $db_field['answer1'];
   $B = $db_field['answer2'];
   $C = $db_field['answer3'];
   $D = $db_field['answer4'];
   $E = $db_field['answer5'];
   print $question;
?>
</td>
</tr>
<tr>
<td>
<INPUT TYPE = 'Radio' Name ='q'  value= 'A' <?PHP echo $answerA; ?>><?PHP echo $A; ?>
<INPUT TYPE = "Hidden" Name = "h"  VALUE = <?PHP print $qID; ?>>
<?php echo $qID;?>
</td>
</tr>
<tr>
<td>
<INPUT TYPE = 'Radio' Name ='q'  value= 'B' <?PHP echo $answerB; ?>><?PHP echo $B; ?>
<?php echo $qID;?>
</tr>
</td>
<tr>
<td>
<INPUT TYPE = 'Radio' Name ='q'  value= 'C' <?PHP echo $answerC; ?>><?PHP echo $C; ?>
</tr>
</td>
<tr>
<td>
<INPUT TYPE = 'Radio' Name ='q'  value= 'D' <?PHP echo $answerD; ?>><?PHP echo $D; ?>
</tr>
</td>
<tr>
<td>
<INPUT TYPE = 'Radio' Name ='q'  value= 'E' <?PHP echo $answerE; ?>><?PHP echo $E; ?>
<br>
<?php }  mysql_close(); ?>
</tr>
</td>
<tr>
<td>


Please add any comments you may have:</br>
 <textarea rows="3" cols="60" name="comments" id="comments">
 </textarea>

</td>
</tr>


</table>

<input type="submit" onclick="show_alert()" value="Submit" />
</form>

</html>

I ran to some problems here. After filling every question up with the answers. When i process the form, i only managed to get QID of 20 and the answer of 1st question as my database have only 20questions. How do i go about in solving, so that i'm able to retrieve all result and update my database correctly

      $selected_radio = $_POST['q'];
      
      
      $qID = $_POST['h'];

      echo $selected_radio;
      
      echo $qID;
         
         $SQL = "UPDATE answers SET $selected_radio = $selected_radio + 1 WHERE question_id='$qID'";
         $result = mysql_query($SQL);
         mysql_close();
         print "Thanks for voting!";


?>
THis is my process page, and i echo out the answer to be B and qid as 20.

I'm making a game I have finished but have spent days and still can't figure out this part or how it should be done:

Gamer will type in keyword on the form box on my page then click submit

the page will connect to yahoo search then save/put the address bar URL search result of the keywords into a variable onto my page but the gamer will never have his page directed to yahoo but continue staying on my page while this all happens.


Any Help in the right direction or some code would be appreciated? 

Hi there

I am trying to use cURL to retrieve XML from a gateway. The code I am using works (ie. returns the HTTP response) for any URL that I use except the one that I need!  The URL is below, and when using that I get a blank response every time. I've tested and can telnet to that IP address on that port from my server.

I'm not sure if it is because of the format/structure of the URL? Could it have something to do with the port of the gateway? Any assistance would be much appreciated.

http://196.11.120.190:8080/mtnusa/client.jsp?command=<usareq NODE="tHTTP" USERNAME="HTTP" PASSWORD="1234" TRANSFORM="SMPP"><command><submit_sm><a_number>278200703520709</a_number><b_number>27824411926</b_number><service_type/><message>Test</message><registered_delivery/></submit_sm></command></usareq>

The function I am using (from http://davidwalsh.name) is:

/* gets the data from a URL */
function get_data($url)
{
   $ch = curl_init();
   $timeout = 5;
   curl_setopt($ch,CURLOPT_URL,$url);
   curl_setopt($ch,CURLOPT_RETURNTRANSFER,1);
   curl_setopt($ch,CURLOPT_CONNECTTIMEOUT,$timeout);
   $data = curl_exec($ch);
   curl_close($ch);
   return $data;
}

$returned_content = get_data('http://196.11.120.190:8080/mtnusa/client.jsp?command=<usareq NODE="HTTP" USERNAME="HTTP" PASSWORD="1234" TRANSFORM="SMPP"><command><submit_sm><a_number>278200703520709</a_number><b_number>27824411926</b_number><service_type/><message>Test</message><registered_delivery/></submit_sm></command></usareq>');

i have had a difficult time trying to work this out.I need to do some pattern matching for certain urls and retrieve information from it.
For example,
$url=http://www.test.com/showpic.php?do=showpic&u=89165&a=34933

if $url contains the value showpic.php,then i need to retrieve the following
{
  $u=value of u(i.e. 89165 in this case)
  $a=value of a(i.e. 34933 in this case)
}
else do nothin..

the format of the url will always be the same as above if it contains showpic.php

There's many options available for downloading a URL - but I'm stuck.

I've looked through all the ones I know, but none seem to pay attention to partial content.

I'm trying to retrieve a URL that gives the following header:
HTTP/1.1 206 Partial Content
Content-Range:   bytes 0-100000/631723

As you can see it dishes out the file in 100,000 byte chunks.

Trouble is, when I use any method in PHP, ie file_get_contents, fopen, or even cURL, none of these continue on after retrieving the 100,000 bytes.

End result, I have a 100,000 byte file.

What I need is to get the PHP script to grab all the data, in the example above, all 631,723 bytes.

How can I do this?

ok im back quicker than i thought....

i got my drop box sorted and i got it reloading the page. so it all works correctly.

but how do i get the page to display information regarding the film i have selected in the drop box.? i have no code for this at the mo.

also i would like the drop box to display the selected item at top of box when it refreshes

code for drop box:

Code: [Select]
<FORM>
<?php $result = mysql_query( "SELECT * FROM movie_info ORDER BY title ASC ")
;
echo "<select name= Film onChange='submit()' >film name</option>";
while
($nt=mysql_fetch_array($result)){
?>
<?php
  echo "<option value='$nt[id]'>$nt[title] </option>";
}
?>
</select>
</FORM>



any help would be great

Hi, i have a transaction table which includes following fields.
 
    tran_ID,account_number,account_type,transaction_type,amount,Date

I want to know how these data can be retrieved and display in another table. The table is filled with several records.

Thanks,
Heshan

Hi Everyone!  Just learning php.  Hope someone can help with this.  Trying to design a product page of photo images with price, description, etc.  At this point I am ignoring the design and just trying to get the fields to populate.  They all work through my "while" loop except I cannot find the syntax for the image and am just getting the placeholder.  My images are just "image".jpg in my root folder.  Ex. building.jpg. And my table column is "picture_image".

Appreciate any help.  Here is the pertinent code which works fine except for the image $ROW.  I have bolded the trouble block.  Thanks!

while($row = mysqli_fetch_assoc($result))           
 {
   
   // display row for each picture
   echo "<tr>\n";
   echo " <td>{$row['Picture_ID']}</td>\n";
   echo " <td style='font-weight: bold;
            font-size: 1.1em'>{$row['Picture_name']}</td>\n";
   echo " <td>{$row['Picture_description']}</td>\n";
   echo " <td>{$row['Picture_price']}</td>\n";
   
       
   echo "<td><a href={$row['picture_image']}'
                          border='0'>
                  <img src='{$row['picture_image']}'
                   border='0' width='100' height='80' />
                </a></td>\n";