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PHP - Two Sum's, One Query
Hi, I am trying to get two SUM's into one query, one to show the overall total, and the other to show the total of the 5 most recent. Is it possible to put it into one query? I have tried but so far can't seem to get it to work, below I have the code that currently displays only the overall total, in the last column is where I am trying to put the total from the last 5 games. Any help would be very much appreciated. Thanks
Code: [Select] <table width="500" border="0" cellpadding="0" cellspacing="0"> <tr class="title"> <td width="250">Team Name</td> <td width="100">Total Points</td> <td width="100">last 5 games</td> </tr> <?php $query = "SELECT test_teams.team, SUM(test_team_points.points) AS total FROM test_teams, test_team_points WHERE test_teams.selectiongroup = '$group' AND test_teams.teamid = test_team_points.teamid GROUP BY test_teams.teamid ORDER BY test_teams.teamid ASC"; $result = mysql_query($query) or die(mysql_error()); while($row = mysql_fetch_assoc($result)) { ?> <tr class="teams"> <td width="250"><?php echo $row['team']; ?></td> <td width="100"><?php echo $row['total']; ?></td> <td width="100"></td> </tr> <?php } ?> </table> Similar TutorialsHere is my code: // Start MySQL Query for Records $query = "SELECT codes_update_no_join_1b" . "SET orig_code_1 = new_code_1, orig_code_2 = new_code_2" . "WHERE concat(orig_code_1, orig_code_2) = concat(old_code_1, old_code_2)"; $results = mysql_query($query) or die(mysql_error()); // End MySQL Query for Records This query runs perfectly fine when run direct as SQL in phpMyAdmin, but throws this error when running in my script??? Why is this??? Code: [Select] You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '= new_code_1, orig_code_2 = new_code_2WHERE concat(orig_code_1, orig_c' at line 1 Hello all,
Based on the suggestion of you wonderful folks here, I went away for a few days (to learn about PDO and Prepared Statements) in order to replace the MySQLi commands in my code. That's gone pretty well thus far...with me having learnt and successfully replaced most of my "bad" code with elegant, SQL-Injection-proof code (or so I hope).
The one-and-only problem I'm having (for now at least) is that I'm having trouble understanding how to execute an UPDATE query within the resultset of a SELECT query (using PDO and prepared statements, of course).
Let me explain (my scenario), and since a picture speaks a thousand words I've also inlcuded a screenshot to show you guys my setup:
In my table I have two columns (which are essentially flags i.e. Y/N), one for "items alreay purchased" and the other for "items to be purchased later". The first flag, if/when set ON (Y) will highlight row(s) in red...and the second flag will highlight row(s) in blue (when set ON).
I initially had four buttons, two each for setting the flags/columns to "Y", and another two to reverse the columns/flags to "N". That was when I had my delete functionality as a separate operation on a separate tab/list item, and that was fine.
Now that I've realized I can include both operations (update and delete) on just the one tab, I've also figured it would be better to pare down those four buttons (into just two), and set them up as a toggle feature i.e. if the value is currently "Y" then the button will set it to "N", and vice versa.
So, looking at my attached picture, if a person selects (using the checkboxes) the first four rows and clicks the first button (labeled "Toggle selected items as Purchased/Not Purchased") then the following must happen:
1. The purchased_flag for rows # 2 and 4 must be switched OFF (set to N)...so they will no longer be highlighted in red.
2. The purchased_flag for row # 3 must be switched ON (set to Y)...so that row will now be highlighted in red.
3. Nothing must be done to rows # 1 and 5 since: a) row 5 was not selected/checked to begin with, and b) row # 1 has its purchase_later_flag set ON (to Y), so it must be skipped over.
Looking at my code below, I'm guessing (and here's where I need the help) that there's something wrong in the code within the section that says "/*** loop through the results/collection of checked items ***/". I've probably made it more complex than it should be, and that's due to the fact that I have no idea what I'm doing (or rather, how I should be doing it), and this has driven me insane for the last 2 days...which prompted me to "throw in the towel" and seek the help of you very helpful and intellegent folks. BTW, I am a newbie at this, so if I could be provided the exact code, that would be most wonderful, and much highly appreciated.
Thanks to you folks, I'm feeling real good (with a great sense of achievement) after having come here and got the great advice to learn PDO and prepared statements.
Just this one nasty little hurdle is stopping me from getting to "end-of-job" on my very first WebApp. BTW, sorry about the long post...this is the best/only way I could clearly explaing my situation.
Cheers guys!
case "update-delete":
if(isset($_POST['highlight-purchased']))
{
// ****** Setup customized query to obtain only items that are checked ******
$sql = "SELECT * FROM shoplist WHERE";
for($i=0; $i < count($_POST['checkboxes']); $i++)
{
$sql=$sql . " idnumber=" . $_POST['checkboxes'][$i] . " or";
}
$sql= rtrim($sql, "or");
$statement = $conn->prepare($sql);
$statement->execute();
// *** fetch results for all checked items (1st query) *** //
$result = $statement->fetchAll();
$statement->closeCursor();
// Setup query that will change the purchased flag to "N", if it's currently set to "Y"
$sqlSetToN = "UPDATE shoplist SET purchased = 'N' WHERE purchased = 'Y'";
// Setup query that will change the purchased flag to "Y", if it's currently set to "N", "", or NULL
$sqlSetToY = "UPDATE shoplist SET purchased = 'Y' WHERE purchased = 'N' OR purchased = '' OR purchased IS NULL";
$statementSetToN = $conn->prepare($sqlSetToN);
$statementSetToY = $conn->prepare($sqlSetToY);
/*** loop through the results/collection of checked items ***/
foreach($result as $row)
{
if ($row["purchased"] != "Y")
{
// *** fetch one row at a time pertaining to the 2nd query *** //
$resultSetToY = $statementSetToY->fetch();
foreach($resultSetToY as $row)
{
$statementSetToY->execute();
}
}
else
{
// *** fetch one row at a time pertaining to the 2nd query *** //
$resultSetToN = $statementSetToN->fetch();
foreach($resultSetToN as $row)
{
$statementSetToN->execute();
}
}
}
break;
}
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If you also have any feedback on my code, please do tell me. I wish to improve my coding base. Basically when you fill out the register form, it will check for data, then execute the insert query. But for some reason, the query will NOT insert into the database. In the following code below, I left out the field ID. Doesn't work with it anyways, and I'm not sure it makes a difference. Code: Code: [Select] mysql_query("INSERT INTO servers (username, password, name, type, description, ip, votes, beta) VALUES ($username, $password, $name, $server_type, $description, $ip, 0, 1)"); Full code: Code: [Select] <?php include_once("includes/config.php"); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title><? $title; ?></title> <meta http-equiv="Content-Language" content="English" /> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" /> <link rel="stylesheet" type="text/css" href="style.css" media="screen" /> </head> <body> <div id="wrap"> <div id="header"> <h1><? $title; ?></h1> <h2><? $description; ?></h2> </div> <? include_once("includes/navigation.php"); ?> <div id="content"> <div id="right"> <h2>Create</h2> <div id="artlicles"> <?php if(!$_SESSION['user']) { $username = mysql_real_escape_string($_POST['username']); $password = mysql_real_escape_string($_POST['password']); $name = mysql_real_escape_string($_POST['name']); $server_type = mysql_real_escape_string($_POST['type']); $description = mysql_real_escape_string($_POST['description']); if(!$username || !$password || !$server_type || !$description || !$name) { echo "Note: Descriptions allow HTML. Any abuse of this will result in an IP and account ban. No warnings!<br/>All forms are required to be filled out.<br><form action='create.php' method='POST'><table><tr><td>Username</td><td><input type='text' name='username'></td></tr><tr><td>Password</td><td><input type='password' name='password'></td></tr>"; echo "<tr><td>Sever Name</td><td><input type='text' name='name' maxlength='35'></td></tr><tr><td>Type of Server</td><td><select name='type'> <option value='Any'>Any</option> <option value='PvP'>PvP</option> <option value='Creative'>Creative</option> <option value='Survival'>Survival</option> <option value='Roleplay'>RolePlay</option> </select></td></tr> <tr><td>Description</td><td><textarea maxlength='1500' rows='18' cols='40' name='description'></textarea></td></tr>"; echo "<tr><td>Submit</td><td><input type='submit'></td></tr></table></form>"; } elseif(strlen($password) < 8) { echo "Password needs to be higher than 8 characters!"; } elseif(strlen($username) > 13) { echo "Username can't be greater than 13 characters!"; } else { $check1 = mysql_query("SELECT username,name FROM servers WHERE username = '$username' OR name = '$name' LIMIT 1"); if(mysql_num_rows($check1) < 0) { echo "Sorry, there is already an account with this username and/or server name!"; } else { $ip = $_SERVER['REMOTE_ADDR']; mysql_query("INSERT INTO servers (username, password, name, type, description, ip, votes, beta) VALUES ($username, $password, $name, $server_type, $description, $ip, 0, 1)"); echo "Server has been succesfully created!"; } } } else { echo "You are currently logged in!"; } ?> </div> </div> <div style="clear: both;"> </div> </div> <div id="footer"> <a href="http://www.templatesold.com/" target="_blank">Website Templates</a> by <a href="http://www.free-css-templates.com/" target="_blank">Free CSS Templates</a> - Site Copyright MCTop </div> </div> </body> </html> I'm trying to update every record where one field in a row is less than the other. The code gets each row i'm looking for and sets up the query right, I hope I combined the entire query into one string each query seperated by a ; so it's like UPDATE `table` SET field2= '1' WHERE field1= '1';UPDATE `table` SET field2= '1' WHERE field1= '2';UPDATE `table` SET field2= '1' WHERE field1= '3';UPDATE `table` SET field2= '1' WHERE field1= '4';UPDATE `table` SET field2= '1' WHERE field1= '5'; this executes properly if i run the query in phpMyAdmin, however when I run the query in PHP, it does nothing... Any advice? I was just wondering if it's possible to run a query on data that has been returned from a previous query? For example, if I do Code: [Select] $sql = 'My query'; $rs = mysql_query($sql, $mysql_conn); Is it then possible to run a second query on this data such as Code: [Select] $sql = 'My query'; $secondrs = mysql_query($sql, $rs, $mysql_conn); Thanks for any help Say I have this query: site.com?var=1 ..I have a form with 'var2' field which submits via get. Is there a way to produce: site.com?var=1&var2=formdata I was hoping there would be a quick way to affix, but can't find any info. Also, the query could sometimes be: site.com?var2=formdata&var=1 I would have to produce: site.com?var2=updatedformdata&var=1 Is my only option to further parse the query? What would be the correct way to close a mysql query? At current the second query below returns results from the 1st query AND the 2nd query The 3rd query returns results from the 1st, 2nd and 3rd query. etc etc. At the moment I get somthing returned along the lines of... QUERY 1 RESULTS Accommodation 1 Accommodation 2 Accommodation 3 QUERY 2 RESULTS Restaurant 1 Restaurant 2 Restaurant 3 Accommodation 1 Accommodation 2 Accommodation 3 QUERY 3 RESULTS Takeaways 1 Takeaways 2 Takeaways 3 Restaurant 1 Restaurant 2 Restaurant 3 Accommodation 1 Accommodation 2 Accommodation 3 Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <?php include($_SERVER['DOCUMENT_ROOT'].'/include/db.php'); ?> <title>Untitled Document</title> <style type="text/css"> <!-- --> </style> <link href="a.css" rel="stylesheet" type="text/css" /> </head><body> <div id="listhold"> <!------------------------------------------------------------------------------------------------------------------------------------------------------> <div class="list"><a href="Placestostay.html">Places To Stay</a><br /> <?php $title ="TITLE GOES HERE"; $query = mysql_query("SELECT DISTINCT subtype FROM business WHERE type ='Accommodation' AND confirmed ='Yes' ORDER BY name"); echo mysql_error(); while($ntx=mysql_fetch_row($query)) $nt[] = $ntx[0]; $i = -1; foreach($nt as $value) {$i++; $FileName = str_replace(' ','_',$nt[$i]) . ".php"; $FileUsed = str_replace('_',' ',$nt[$i]); echo "<a href='" . str_replace(' ','_',$nt[$i]) . ".php?title=$title&subtype=$FileUsed'>" . $nt[$i] . "</a>" . "<br/>"; $FileHandle = fopen($FileName, 'w') or die("cant open file"); $pageContents = file_get_contents("header.php"); fwrite($FileHandle,"$pageContents");} fclose($FileHandle); ?> </div> <!------------------------------------------------------------------------------------------------------------------------------------------------------> <div class="list"><a href="Eatingout.html">Eating Out</a><br /> <?php $title ="TITLE GOES HERE"; $query = mysql_query("SELECT DISTINCT subtype FROM business WHERE type ='Restaurant' AND confirmed ='Yes' ORDER BY name"); echo mysql_error(); while($ntx=mysql_fetch_row($query)) $nt[] = $ntx[0]; $i = -1; foreach($nt as $value) {$i++; $FileName = str_replace(' ','_',$nt[$i]) . ".php"; $FileUsed = str_replace('_',' ',$nt[$i]); echo "<a href='" . str_replace(' ','_',$nt[$i]) . ".php?title=$title&subtype=$FileUsed'>" . $nt[$i] . "</a>" . "<br/>"; $FileHandle = fopen($FileName, 'w') or die("cant open file"); $pageContents = file_get_contents("header.php"); fwrite($FileHandle,"$pageContents");} fclose($FileHandle); ?> </div> <!------------------------------------------------------------------------------------------------------------------------------------------------------> <div class="list"><a href="Eatingin.html">Eating In</a><br /> <?php $title ="TITLE GOES HERE"; $query = mysql_query("SELECT DISTINCT subtype FROM business WHERE type ='Takeaways' AND confirmed ='Yes' ORDER BY name"); echo mysql_error(); while($ntx=mysql_fetch_row($query)) $nt[] = $ntx[0]; $i = -1; foreach($nt as $value) {$i++; $FileName = str_replace(' ','_',$nt[$i]) . ".php"; $FileUsed = str_replace('_',' ',$nt[$i]); echo "<a href='" . str_replace(' ','_',$nt[$i]) . ".php?title=$title&subtype=$FileUsed'>" . $nt[$i] . "</a>" . "<br/>"; $FileHandle = fopen($FileName, 'w') or die("cant open file"); $pageContents = file_get_contents("header.php"); fwrite($FileHandle,"$pageContents");} fclose($FileHandle); ?> </div> <!------------------------------------------------------------------------------SKILLED TRADES BELOW---------------------------------------------------> <div class="list"><a href="Skilledtrades.html">Skilled Trades</a><br/> <?php $title ="TITLE GOES HERE"; $query = mysql_query("SELECT DISTINCT subtype FROM business WHERE type ='Skilled Trades' AND confirmed ='Yes' ORDER BY name"); echo mysql_error(); while($ntx=mysql_fetch_row($query)) $nt[] = $ntx[0]; $i = -1; foreach($nt as $value) {$i++; $FileName = str_replace(' ','_',$nt[$i]) . ".php"; $FileUsed = str_replace('_',' ',$nt[$i]); echo "<a href='" . str_replace(' ','_',$nt[$i]) . ".php?title=$title&subtype=$FileUsed'>" . $nt[$i] . "</a>" . "<br/>"; $FileHandle = fopen($FileName, 'w') or die("cant open file"); $pageContents = file_get_contents("header.php"); fwrite($FileHandle,"$pageContents");} fclose($FileHandle); ?> </div> here's the code: Code: [Select] $companyName = 'big company'; $address1 = 'big bay #8'; $address2 = 'some big warehouse'; $city = 'big city'; $province = 'AB'; $postalCode = 'T1T0N0'; $phone = '0123456789'; $email2 = 'bigKahuna@bigKahuna.edu'; $query = "INSERT INTO clients ( companyName, address1, address2, city, province, postalCode, phone, email) VALUES ( ". $companyName.",".$address1.",".$address2.",".$city.",".$postalCode.",".$phone.",".$email2.")"; $result = mysql_query($query, $connexion); if ($result) { // Success! echo "Fabulous! check the DB, we did it! :D<br>"; ?> <pre> <?php print_r($result); ?> </pre> <?php } else { // Fail! echo"CRAAAAAPP! something went wrong. FIX IT! :P<br>"; echo mysql_error(); } if (isset($connexion)) { mysql_close($connexion); } i copied it over from an old *working* file to illustrate how a simple INSERT works. this is the error i get: Code: [Select] You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'company,big bay #8,some big warehouse,big city,T1T0N0,0123456789,bigKahuna@bigKa' at line 4 looks completely valid to me. all the database table elements are set to VARCHAR(80), so it can't be a space/type issue... halp! WR! I'm restarting this under a new subject b/c I learned some things after I initially posted and the subject heading is no longer accurate. What would cause this behavior - when I populate session vars from a MYSQL query, they stick, if I populate them from an MSSQL query, they drop. It doesn't matter if I get to the next page using a header redirect or a form submit. I have two session vars I'm loading from a MYSQL query and they remain, the two loaded from MSSQL disappear. I have confirmed that all four session vars are loading ok initially and I can echo them out to the page, but when the application moves to next page via redirect or form submit, the two vars loaded from MSSQL are empty. Any ideas? I am trying to create a query which reads and uses a previous query which could go on for upto four queries. For example: Query: $carcolour(red), Query: $carmodel(ford), Query: $enginesize(1600), Query: $carlocation(New York) This displays all red cars, which are Ford, which 1600CC, which are located in New York. or Query: $enginesize(1600), Query: $carcolour(red), Query: $carmodel(ford), Query: $carlocation(New York) This displays all 1600CC cars, which red car, which are Ford, which are located in New York. (Same result as above) I have found this guide but Im not sure it what I am looking for. I have also come across the Join function. However this seems to be based on joining two seperate queries. http://www.suite101.com/content/how-tor-run-multiple-mysql-queries-with-php-a105672 Can anyone advise on the best way to create a set of queries which reads and uses the results of the previous query? Good Day Guys
I have a bit of a urgent problem.
Here is my Query:
$query = "SELECT distinct Img.propertyId as PropertyId, Title, ImageUrl, Location, Bedrooms, Bathrooms, Parking, Price FROM PROPERTIES as Prop LEFT JOIN IMAGES as Img ON Img.PropertyId = Prop.PropertyId WHERE 1=1 AND Price >=1000 AND Price <=5000 "; I'm having trouble with listing a query with while loops... What am I doing wrong? $user = $database->escape_value($_SESSION['username']); while($row = mysql_fetch_assoc($database->query("SELECT * FROM project WHERE user = '{$user}'"))){ echo $row['name']; } THank you I have a query which displays statuses from users:
$result = mysql_query("SELECT * FROM stream ORDER BY stream_id DESC");
while($row = mysql_fetch_array($result)) {
$tha = $row['stream_time'];
$time = strtotime($tha);
echo "<tr><td><b>" . $row['stream_username'] . "</b></tr></td>" . " <tr><td>" . $stream_pp . "</td><td>" . $row['stream_status'] . " " . humanTiming($time) . $msg;
echo "<br></tr></td>";
}
echo "</table>";
I want to get the profile picture of each user, how would I add this code?$query = "SELECT `profile_picture` FROM `users` WHERE `user_username` = '$status_username'"; $result = mysql_query($query) or die($query."<br/><br/>".mysql_error()); $stream_pp = mysql_result($result, 0, 0);By simply just adding it within it only displays one result. Any ideas? Thanks Hello there, i have a database for a video store where there's a table for movies, a movie_actor table and an actors table. The movie_actor table holds the id of a movie and the id of an actor. What i want to do is display the actors for each movie (can be more than 1). Here is what i have done up to now. Code: [Select] $sql="SELECT m.movie_ID, m.name, c.category_name, mm.medium_name, rp.period, rp.price, m.total_stock, m.current_stock FROM movies AS m INNER JOIN categories AS c ON m.category = c.category_ID INNER JOIN movie_medium AS mm ON m.medium = mm.medium_ID INNER JOIN rental_period AS rp ON m.rental_time = rp.medium_ID"; //This is the main query, no probs with this one $pager = new PS_Pagination($link, $sql, 10, 3); //pager is a script for pagination i'm using, not relevant to the problem i think. $rs = $pager->paginate(); while ($row = mysql_fetch_array($rs, MYSQL_NUM)) { ?> <tr> <td><?php echo $row[1]; ?></td> <td><?php echo $row[2]; ?></td> <td> <?php $result_actor = mysql_query("SELECT a.name, a.surname FROM movie_actor AS ma WHERE ma.movie_ID = $row[0] INNER JOIN actors AS a ON ma.actor_ID = a.actor_ID") or die("Query failed: " . mysql_error()); while ($row_actor = mysql_fetch_array($result_actor, MYSQL_NUM)) { ?> <?php echo $row_actor[0] . " " . $row_actor[1]; ?><br /> <?php } ?> </td> <td><?php echo $row[3]; ?></td> <td><?php echo $row[4]; ?></td> <td><?php echo $row[5]; ?></td> <td><?php if(($row[6] - $row[7]) > 0) { echo "available"; } else { echo "all copies are rented"; } ?></td> </tr> <?php } ?> The error i'm getting is this one: Query failed: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'INNER JOIN actors AS a ON ma.actor_ID = a.actor_ID' at line 1 I'm pretty sure the fields are correct its not a matter of a typo. I'm using wamp server, mysql version 5.1.36 if someone could tell me whats wrong with my second query i would really be grateful. P.S. If i remove the inner join part and just leave it with the where, the query works properly it returns the id's of the actors that are associated with that movie, so my problem is displaying the actor name and surname. Thanks in advance and if u need any more info please just ask! $set = mysql_query("UPDATE comments SET matserviewed='yes' WHERE threadid='$t' AND matserviewed='no' AND originalpostby='$username'"); is there any reason why this wont work?? how would i fix this? check your syntax near "LIMIT 0,10" $sql = "SELECT cam_systems.id, GROUP_CONCAT(system_disks.system_disks_qty) AS system_disks_qty, GROUP_CONCAT(DISTINCT system_disks.system_disks_make) AS system_disks_make, GROUP_CONCAT(DISTINCT system_disks.system_disks_model_no) AS system_disks_model_no, GROUP_CONCAT(DISTINCT system_disks.system_disks_size) AS system_disks_size, GROUP_CONCAT(DISTINCT system_memory.system_memory_qty) AS system_memory_qty, GROUP_CONCAT(DISTINCT system_memory.system_memory_serial_no) AS system_memory_serial_no, GROUP_CONCAT(DISTINCT system_memory.system_memory_manf) AS system_memory_manf, GROUP_CONCAT(DISTINCT system_memory.system_memory_part_no) AS system_memory_part_no, GROUP_CONCAT(DISTINCT system_memory.system_memory_size) AS system_memory_size, COUNT(*) FROM cam_systems, system_disks, system_memory WHERE cam_systems.location_id = '1' OR system_disks.system_id = 'cam_systems.id' AND system_memory.system_id = 'cam_systems.id' GROUP BY cam_systems.id DESC LIMIT 10"; Hi, This is my code $query = mysql_query("SELECT id, username, lastname FROM users ORDER BY username ASC"); echo '<h1>Add Rota</h1> <table> <tr> <td><b>Presenter 1:</b></td> <td> <select name="presenter1"> <option value="0">Pick presenter</option> '; while ($row = mysql_fetch_array($query, MYSQL_NUM)) { echo "<option value=\"{$row['0']}\">{$row['1']} {$row['2']} </option>\n"; } echo ' </select> </td> <td></td> <td></td> <td></td> </tr> <tr> <td><b>Presenter 2:</b></td> <td> <select name="presenter2"> <option value="0">Pick presenter</option> '; while ($row = mysql_fetch_array($query, MYSQL_NUM)) { echo "<option value=\"{$row['0']}\">{$row['1']} {$row['2']} </option>\n"; } echo ' </td> I am trying to define the $query to use in a dropdown twice although I cannot re use it and this doesnt work for the second dropdown. I was trying to only write the query out once to save on resources. Any suggestions would be great Thanks Is there a peramiter or way one can write something like this? and if so whats the proper way. if ($test1 != "Select One") { $test1=$_Post['']; // i know syntax is wrong but this isnt my problem } else { $test="*"; // This is where i am having problems. If the user doesnt select a option on my dropdown it pretty much removes all the data from query results because they have input. } $dlquery = "SELECT * FROM Whatever WHERE test1='$test1' AND test2='$test2'"; ?> that way when someone doesnt select a peramiter for test one it just includes any entry in the datafield in the quarry. I would appreciate the help. BTW ive only been doing this for about 3 weeks and this is first real snag ive had that just browsing you guys and w3 hasnt gotten me my answers. I have phone numbers (field name:telephone / varchar) in a table. "555-444-3333" "717-333-3211" I want to count the amount that have the same area code: "SELECT COUNT(*) FROM table GROUP BY the first three digits of telephone field" Is it possible? Hi All, I have a several hundred "quizzes" in a database that I need to go through. All of the quizzes are multiple choice and based on a video. Typically I go through these one by one. Over the past few months I haven't been as diligent and the quizzes have piled up for moderation. I was going through this morning and quickly saw that most of these (they are User Generated) don't have more than 2 questions. That is, quite a few of them appear to be 'test' quizzes by users.. just to see how the quiz builder works. Anyhow, if they are good quizzes / quality content I push them to the site. If not I disable them. I need help with a sql query -- I'd like to run this in php my admin and view all quizzes with 2 questions or less and with a "pass text" set to "new_quiz". Then I plan to update the "new_quiz" value to "disabled" to remove them from the moderation cue. Here's how I pull the video from the database: "SELECT * FROM video, registered_users WHERE video.id = '$_GET[id]' AND video.user_id = registered_users.id"; Here's how I pull quizzes/questions from the database: $display = mysql_query("SELECT * FROM quiz WHERE quiz.video_id = '$_SESSION[get]' ORDER BY id ASC"); Questions are in the quiz table in a row called "question" Could you please offer some help as to the best way to write this query? In plain speak I think it ought to be: select * from table-video and table-quiz where video.id = quiz.video_id and video.pass_text= "new_quiz" and there are equal to or less than 2 questions related to this video. What is the best way to write this? Please help and I'll test the query on backup db. thanks so much! Ryan |
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