PHP - Passing String Through A Function Using Return
Hello everyone,
Pretty much what I am trying to do is run a query and based of the queries result, return a string - as of now it is turning up blank and cant seem to pass any strings through the function. Current function: function addNewBookmark($hash,$url,$title,$username){ Code: [Select] $query = "INSERT INTO bookmarks (hash,url,title,username) VALUES '".md5($hash)."', '".$url."', '".$title."', '".$username."')"; $result = mysql_query(query, $this->connection); $message = ''; if(mysql_affected_rows($this->connection)!=1) { $message = 'This URL already exists in the database!'; return $message; } else $message = 'The URL was shared!'; return $message; } The above code seems to run fine, just cant seem to pass a string...read that you can possibly use a __toString function? but that keeps throwing errors when I try to work with it. Thanks all! Similar TutorialsHello all, I'm trying to change the end of a javascript call based on the end of the url string. The common part of all the url strings is sobi2Id=, I'm trying to do this with strstr but am having no luck. I'm new to php so my syntax knowledge is terrible! at the moment i've got Code: [Select] <?php $url = $_SERVER['REQUEST_URI']; $tag = strstr ($url, 'sobi2Id='); echo $tag; ?> but this returns an unexpected T_STRING, expecting ',' or ';' Can anyone debug this? I may well be being really silly! Hi! So what I'm trying to do is split a multi dimensional array of strings ( each containing 3 strings inside of 1 array ) so I can write the results to a file. So say I had a bunch of strings inside 1 array : class File { function WriteFile ( $filename, $content ) { $list = [ $content ]; $delimiters = File :: checkDelimiter ( $content, true, false ); $fp = fopen ( $filename, 'w' ); foreach ( $list as $fields ) { $fields = File :: SplitFileByDelimiter ( $fields, ",", 3 ); file_put_contents ( $filename, $fields ); } fclose ( $fp ); } } $file-> File :: WriteFile ( $filepath . $filename, "TEST!, TEST!, TEST!, " . "TEST!, TEST!, TEST!, " . "TEST!, TEST!, TEST!" ); Instead of writing : TEST!, TEST!, TEST!, TEST!, TEST!, TEST!, TEST! ,TEST!, TEST!, TEST! to the file in a straight line, it should write it like this : TEST!, TEST!, TEST!, TEST!, TEST!, TEST!, TEST!, TEST!, TEST! Any help is ABSOLUTELY appreciated! Edited May 22 by AquariaXI Hi there
I have started using php excell and getting most of it right. But i am struggling to search active sheet and return what cell the string is in. below is my code.
<?php ini_set('display_errors', 1); ini_set('display_startup_errors', 1); error_reporting(E_ALL); set_time_limit(0); $directory = "/var/www/html/csvex/xls/"; $formatdirectory = "/var/www/html/csvex/toformat/"; $finishedformatdirectory = "/var/www/html/csvex/formatted/"; $savanadirectory = "/var/www/html/iretire/files/upload/1/"; $main = "/var/www/html/csvex/"; $files = scandir($directory, SCANDIR_SORT_DESCENDING); $newest_file = $files[0]; echo $newest_file; echo "<br>"; $oldfile = $directory.$newest_file; $newfile = $formatdirectory.$newest_file; $changedfile = $finishedformatdirectory.$newest_file; $crmfile = $savanadirectory.$newest_file; echo $oldfile; echo "<br>"; echo $newfile; echo "<br>"; if( !rename($oldfile, $newfile) ) { echo "File can't be moved!"; } else { echo "File has been moved!"; } //format the file date_default_timezone_set('Europe/London'); set_include_path(get_include_path() . PATH_SEPARATOR . './Classes/'); include 'PHPExcel/IOFactory.php'; $fileType = 'Excel5'; $fileName = $newfile; // Read the file $objReader = PHPExcel_IOFactory::createReader($fileType); $objPHPExcel = $objReader->load($fileName); //change font $objPHPExcel->getActiveSheet()->getStyle('a1:a6')->applyFromArray( $styleArray = array( 'font' => array( 'bold' => true ) ) ); $objPHPExcel->getActiveSheet()->getStyle('a6:aa6')->applyFromArray( $styleArray = array( 'font' => array( 'bold' => true ) ) ); $objPHPExcel->getActiveSheet()->getStyle('n16:aa16')->applyFromArray( $styleArray = array( 'font' => array( 'bold' => true ) ) ); //get INACTIVE MEMBERS $foundInCells = array(); $searchValue = 'INACTIVE MEMBERS'; foreach ($objPHPExcel->getActiveSheet() as $worksheet) { $ws = $worksheet->getTitle(); foreach ($worksheet->getRowIterator() as $row) { $cellIterator = $row->getCellIterator(); $cellIterator->setIterateOnlyExistingCells(true); foreach ($cellIterator as $cell) { if ($cell->getValue() == $searchValue) { $foundInCells[] = $ws . '!' . $cell->getCoordinate(); } } } } echo "<br>"; echo "<br>"; echo "this is where - - "; var_dump($foundInCells); echo "<br>"; echo "<br>"; // $objPHPExcel->getActiveSheet()->getStyle('a20')->applyFromArray( $styleArray = array( 'font' => array( 'bold' => true ) ) ); its located at //Get inactive members. another one i am struggling with is to see if file exists if not then do nothing if it does run the code. I have the following code and it always says it's a string! How do I make it see it as a json object? Code: [Select] <?php //We'll return a json object from post request if ( !empty( $_POST ) ) { $arr = array ('status'=>1,'message'=>'Some message'); echo json_encode($arr); } else { ?> <input type="button" value="submit" id="submit" /> <script type="text/javascript" src="/scripts/jquery-1.4.2.js"></script> <script> var submit = document.getElementById( "submit" ); submit.onclick = function() { $.post( "test.php", function(data) { /* * This always prints as: * {"status":1,"message":"Some message"} * string * Code: undefined * Message: undefined */ alert( data + "\n" + typeof( data ) + "\nCode: " + data.status + "\nMessage: " + data.message ); } ); } </script> <? } ?> What do I do to make it a json object? hello, i seem to be stuck again and this bug is difficult for me to solve.
if(isset($_POST['boards'])) $boards[] = $_POST['boards']; $allboards = implode("",$boards[0]); echo $allboards;outputs (browser source)... hello world I have a combobox with the "multiple" property. when two items are selected, the combobox "name" property has an array that passes to the $_POST variable. what i would like is those two words to be displayed on the same line. I have tried rtrim($var, "\r\n") but that does nothing. the reason i need them on the same line is because i would change then to "hello, world" and then add them as a mysql query, for example... $query = "SELECT hello, world FROM table... I have a web server which contains a public site and a private site. I want to be able to test for public or private using the page title and return the appropriate header which contains a different banner, css etc. Firstly - the syntax below seems to be incorrect because it doesnt work correctly. More importantly how do I add all the values to an array and than iterate through it to check for a matching page title? Code: [Select] public function publicSite() { if ($this->getTitle()== 'Home' || 'About Us'||'Registration' || 'Sitemap' || 'Contact Us' || 'Useful Links' || 'Feedback') { return true; } return false; } Then later on I would have: Code: [Select] if ($this->publicSite()) { require($ROOT.'interface/pages/publicheader.php'); } else { require($ROOT.'interface/pages/privateheader.php'); } Thanks heaps! Pretty simple I would think but I'm unsure on the syntax. I have a variable, $ename. It's actually data from a form that I pass to said variable. What I want is to then in turn use this string in a mkdir() function. Something like Code: [Select] mkdir("dir/folder/$ename/"); Obviously that doesn't work. I'd imagine I have to use some sort of . syntax. let say i have a function function checkme($x) { if(strlen($x)>10) { return $x; } else { return false; } } $variable=checkme("5"); so two questions i wish to ask... 1. If i wish to get the empty string for the $variable, then is it correct to have return false there? 2. If it is true that return shall not be used twice in a function as it will somehow reduce bytes space or something like that?? thanks in advance Hi, i got this function to get the wordCount that i store in a tabel: Code: [Select] function getWordCount($word) { $query = "SELECT count FROM uniqueWords WHERE word='$word'"; $data = execQuery($query); return $data; } Only it returns an array, what i want is to have it return a integer, how can i do that? Hi all, can you give me suggestion how to return value from function like this Code: [Select] function returnArray(){ for($i=1; $i<=3; $i++){ return $i; //how to return this as array?? } } when I code "echo" inside the function then call the function it give me output => 123 but when I code "return" inside the function, it will give output => 1 Can you suggest me how to output it as array? Hello Everyone,
I have below datetime string 2021-05-06T13:48:19.2064951+05:30 i need to get the server timezone name by passing this string to date_default_timezone_set(). here is it valid? can somebody please help me i need the timezone name with above datetime string Thanks, Krish I am trying to pass in a $string variable into my query like so but it is returning a warning: Code: [Select] $string = "clientName == '$input'"; $input = "Sam"; $table_id = 'booking'; $query ="SELECT * FROM booking WHERE. '$string' "; $test = mysql_query($query); echo $test; Hi,Dear Frnds...........................I Hope U r all fine. I am using php.Here is the problem in the Return array from function. This is the code. Code: [Select] <?php $store = array(); $test = get_my_links(); print_r($store); function get_my_links() { $my_array = array('e','f','g'); foreach($my_array as $key=> $list) { $store[] = $list; } return $store; } ?> Suppose the array is maked dynamically. please help me..THANKS... I am retrieving a rowfrom a table and when I post the row variable it doesnt read it. ___ $query = "SELECT * FROM $tbl_name"; $result = mysql_query($query) or die(mysql_error()); while($row = mysql_fetch_array($result)){ echo $row['name']; echo "<br />"; $postinfo = 'p_doctor_name=' . $row .'&p_name_type=A&p_search_type=BEGINS'; __ This outputs p_entity_name=&p_name_type=A&p_search_type=BEGINS Note that it is missing $row Do I need to put it in an array? I have a php string variable that is created by php code within an html form ($answer). I need to pass this string variable along with all the html form input data to another php script specified with the form "action" (post method). All the html form input data is coming thru fine but not the variable ($answer). How do I do this? Here is the php code for importing html form data at the script called in the form action: $languages = $_POST['languages']; $answergiven = $_POST['answergiven']; $problemanswer = $_POST['$answer']; 'languages' and 'answergiven' are form inputs and come thru fine. '$answer' does not get passed to the second script. How do I do this? Here is the php code within the first html form <?php // OPEN DATABASE $username="servics3_sample"; $password="sample"; $database="servics3_sample"; mysql_connect(localhost,$username,$password); @mysql_select_db($database) or die( "Unable to select database"); // GENERATE RANDOM PROBLEM NUMBER $probnum = (rand ( 1 , 9 )); echo $probnum; // RETRIEVE ANTI-SPAM PROBLEM $query="SELECT * FROM liasantispam WHERE `problem number` LIKE '%$probnum%' "; $result=mysql_query($query) or die("Error: ". mysql_error(). " with query ". $query); $firstnum=mysql_result($result,0,"first number"); $operator=mysql_result($result,0,"operator"); $secondnum=mysql_result($result,0,"second number"); $answer=mysql_result($result,0,"answer"); echo $firstnum," ",$operator," ",$secondnum," = "; mysql_close(); ?> not sure if this is possible but i do not know how to return multiple values and read them where the call was made. Code: [Select] $string = "clause1"; func1($string); // somehow read the response and use the return values seperately. // both $string2 and $string3 Code: [Select] function func1($input) { if ($input == "clause1") { $string2= "value2"; $string3= "value6"; } if ($input == "clause2") { $string2= "value3"; $string3= "value7"; } if ($input == "clause3") { $string2= "value4"; $string3= "value8"; } if ($input == "clause4") { $string2= "value5"; $string3= "value9"; } return ($requesttype, $messagetitle); } I hate array... 😞 So I had a block of code inside my photo-gallery.php script that took the path to my photos directory, and went to that directory, and then read all of the photo filenames into an array. Then in my HTML, I iterate through this array to display all of the photos for my gallery. Now I would like to move that code to an included file so multiple scripts can access it and always be working with the same array. It seems to me that I need to encapsulate my code inside a function? Then I could call my getPhotoFilesArray back to my callings cript, and use that array for whatever. I haven't coded PHP in like 4 years and I am struggling to return the entire array back to my caling script. This is what I have so far... function getPhotoFilesArray($photoPath){ $photoFiles = array(); <code to find corresponding files> $photoFiles gets populated in a loop return $photoFiles; }
Then in my calling script, I have... <?php require_once('../../../secure_outside_webroot/config.php'); require_once(WEB_ROOT . 'utilities/functions.php'); getPhotoFilesArray($photoPath); var_dump($photoFiles);
I get some error...
Notice: Undefined variable: phtoFiles in photo-gallery.php line 133 (which is my var_dump).
<br> Would appreciate help getting this to work!
Edited December 6, 2019 by SaranacLake Hi, I have some strange issues with my code: Code: [Select] <?PHP session_start(); $loginid = $_SESSION["valid_id"]; // First check if we are guest or user. if (!$_SESSION["valid_email"]) { $visitor = "yes"; } else { $visitor = "no"; $email = $_SESSION['valid_email']; $userid = $_SESSION['valid_id']; } //Load Header (blue menu) require("./inc/header.php"); //Load Sub-acc (silver account menu) require("./inc/sub-group.php"); //Load nav-group (Tabs) require("./inc/nav-group.php"); //Load Config file require("./inc/config.php"); //Set & get profile ID $getid = $_GET["id"]; //check ID $result = mysql_query("SELECT * FROM profiles WHERE id=('$getid') LIMIT 1"); $row = mysql_fetch_array($result); IF (mysql_num_rows($result) != 1) { exit("Invalid ID"); } //If we are guest, do we allow anon access to the profile IF ($row["privacy"] <= 10 && $visitor = "yes") { exit("You may not view this profile as a visitor, due to the users privacy settings"); } //Let's check if we are friends ELSEIF ($visitor = "no") { $result2 = mysql_query("SELECT * FROM profiles_friends WHERE user=('$getid') AND target=('$loginid') LIMIT 1"); $row2 = mysql_fetch_array($result2); $friends = $row2["status"]; if (mysql_num_rows($result2) = 0) { $friends = "no"; } } //If we are friend, do we allow access to the profile IF ($row["privacy"] >= 9 && $friends != 1) { exit("You may not view this profile because of the privacy settings."); } $row = mysql_fetch_array($result); $memgroup = $row["group"]; IF ($row["activated"] != 1) { exit("This account is suspended and cannot be viewed."); } //Check what group member is in. $result2 = mysql_query("SELECT * FROM profiles_groups WHERE id=('$memgroup') LIMIT 1"); $row2 = mysql_fetch_array($result); ?> Alright, so the error: Fatal error: Can't use function return value in write context in C:\xampp\htdocs\prog\profile.php on line 45 Code: [Select] 42. $result2 = mysql_query("SELECT * FROM profiles_friends WHERE user=('$getid') AND target=('$loginid') LIMIT 1"); 43. $row2 = mysql_fetch_array($result2); 44. $friends = $row2["status"]; 45. if (mysql_num_rows($result2) = 0) Alright, this is one thing that bothers me, the other is: Code: [Select] //check ID $result = mysql_query("SELECT * FROM profiles WHERE id=('$getid') LIMIT 1"); $row = mysql_fetch_array($result); IF (mysql_num_rows($result) != 1) { exit("Invalid ID"); I tried to put an invalid ID, and already here the script should have died/exited before executing the parts of the code that doesn't work. I tested my code on another page and it works flawlessly, perhaps this error is just generated before it actually exists i dunno.. Any way, any help is much appreciated } This is object programming right? Is there a performance issue with this? for example: $notfications = ( blah blah ) ? : ''; then if ($notificatiosn != blabla){ echo 'hey'; }or.... $notifications = function(){ do my stuff here then return 'hey'; }Which way is faster or slower? Reason I Ask this is because I've been doing some object orientated programming in javascript, and didn't know you could do it in php. I'd rather do the objective way so I don't have to use so many freaking variables above the regular way, lol. Edited by Monkuar, 22 January 2015 - 12:22 PM. |