PHP - Show Table Info On Page

Hi,

How can I get others informations on another page by clicking on one row's value

I have this code, but it doesn't work:


while($row = mysql_fetch_array($result))
  {
 echo "<tr><p>";
 
  echo "<th><p>" . $row['fname'] . "&nbsp;&nbsp;&nbsp;" . $row['lname'] . "</p></th>";
  echo"<th><p><a href='student.php?id='".$row['topic']."'\'>".$row['topic']."</p></a></th>";

  echo "</tr>";
  }
echo "</table>";


Student.php


<?php
$con = mysql_connect("localhost","root","");
if (!$con)
  {
  die('Could not connect: ' . mysql_error());
  }

mysql_select_db("college", $con);

$result = mysql_query("SELECT * FROM students");
$topic = $_Get['topic'];
while($row = mysql_fetch_array($result))
  {
  
 echo "<tr><p>";
  echo "<th><p>" . $row['month']."&nbsp;" .$row['datetime']."</p></th>";
  echo"<th><p>". $row['topic'] ."</p></th>"; 
  echo "<th><p>" . $row['gender'] . "</p></th>";
  echo "<th><p>" . $row['fname'] . "&nbsp;&nbsp;&nbsp;" . $row['lname'] . "</p></th>";
  echo "<th ><p>" . $row['id'] . "</p></th>";
  echo "</tr>";
  
echo "</table>";

mysql_close($con);
  }
?> 

Quesion: Show each movie in the database on its own page, and give the user links in a "page 1, Page 2, Page 3" - type navigation system. Hint: Use LIMIT to control which movie is on which page. I have provided 3 files: 1st: configure DB, 2nd: insert data, 3rd: my code for the question. I would appreciate the help. I am a noob by the way.

First set up everything for DB:

<?php
//connect to MySQL
$db = mysql_connect('localhost', 'root', '000') or
    die ('Unable to connect. Check your connection parameters.');

//create the main database if it doesn't already exist
$query = 'CREATE DATABASE IF NOT EXISTS moviesite';
mysql_query($query, $db) or die(mysql_error($db));

//make sure our recently created database is the active one
mysql_select_db('moviesite', $db) or die(mysql_error($db));

//create the movie table
$query = 'CREATE TABLE movie (
        movie_id        INTEGER UNSIGNED  NOT NULL AUTO_INCREMENT,
        movie_name      VARCHAR(255)      NOT NULL,
        movie_type      TINYINT           NOT NULL DEFAULT 0,
        movie_year      SMALLINT UNSIGNED NOT NULL DEFAULT 0,
        movie_leadactor INTEGER UNSIGNED  NOT NULL DEFAULT 0,
        movie_director  INTEGER UNSIGNED  NOT NULL DEFAULT 0,

        PRIMARY KEY (movie_id),
        KEY movie_type (movie_type, movie_year)
    )
    ENGINE=MyISAM';
mysql_query($query, $db) or die (mysql_error($db));

//create the movietype table
$query = 'CREATE TABLE movietype (
        movietype_id    TINYINT UNSIGNED NOT NULL AUTO_INCREMENT,
        movietype_label VARCHAR(100)     NOT NULL,
        PRIMARY KEY (movietype_id)
    )
    ENGINE=MyISAM';
mysql_query($query, $db) or die(mysql_error($db));

//create the people table
$query = 'CREATE TABLE people (
        people_id         INTEGER UNSIGNED    NOT NULL AUTO_INCREMENT,
        people_fullname   VARCHAR(255)        NOT NULL,
        people_isactor    TINYINT(1) UNSIGNED NOT NULL DEFAULT 0,
        people_isdirector TINYINT(1) UNSIGNED NOT NULL DEFAULT 0,

        PRIMARY KEY (people_id)
    )
    ENGINE=MyISAM';
mysql_query($query, $db) or die(mysql_error($db));

echo 'Movie database successfully created!';
?>



********************************************************************
***********************************************************************

second file to load info into DB:



<?php
// connect to MySQL
$db = mysql_connect('localhost', 'root', '000') or
    die ('Unable to connect. Check your connection parameters.');

//make sure you're using the correct database
mysql_select_db('moviesite', $db) or die(mysql_error($db));

// insert data into the movie table
$query = 'INSERT INTO movie
        (movie_id, movie_name, movie_type, movie_year, movie_leadactor,
        movie_director)
    VALUES
        (1, "Bruce Almighty", 5, 2003, 1, 2),
        (2, "Office Space", 5, 1999, 5, 6),
        (3, "Grand Canyon", 2, 1991, 4, 3)';
mysql_query($query, $db) or die(mysql_error($db));

// insert data into the movietype table
$query = 'INSERT INTO movietype
        (movietype_id, movietype_label)
    VALUES
        (1,"Sci Fi"),
        (2, "Drama"),
        (3, "Adventure"),
        (4, "War"),
        (5, "Comedy"),
        (6, "Horror"),
        (7, "Action"),
        (8, "Kids")';
mysql_query($query, $db) or die(mysql_error($db));

// insert data into the people table
$query  = 'INSERT INTO people
        (people_id, people_fullname, people_isactor, people_isdirector)
    VALUES
        (1, "Jim Carrey", 1, 0),
        (2, "Tom Shadyac", 0, 1),
        (3, "Lawrence Kasdan", 0, 1),
        (4, "Kevin Kline", 1, 0),
        (5, "Ron Livingston", 1, 0),
        (6, "Mike Judge", 0, 1)';
mysql_query($query, $db) or die(mysql_error($db));

echo 'Data inserted successfully!';
?>



**************************************************************
****************************************************************

MY CODE FOR THE QUESTION:


<?php
$db = mysql_connect('localhost', 'root', '000') or
die ('Unable to connect. Check your connection parameters.');

mysql_select_db('moviesite', $db) or die(mysql_error($db));

//get our starting point for the query from the URL
if (isset($_GET['offset'])) {
   $offset = $_GET['offset'];
} else {
   $offset = 0;
}

//get the movie
$query  = 'SELECT
   movie_name, movie_year
FROM
   movie
ORDER BY
   movie_name
LIMIT ' . $offset . ' , 1';
$result = mysql_query($query, $db) or die(mysql_error($db));
$row = mysql_fetch_assoc($result);
?>
<html>
<head>
<title><?php echo $row['movie_name']; ?></title>
</head>
<body>
<table border = "1">
<tr>
<th>Movie Name</th>
<th>Year</th>
</tr><tr>
<td><?php echo $row['movie_name']; ?></td>
<td><?php echo $row['movie_year']; ?></td>
</tr>
</table>
<p>
<a href="page.php?offset=0">Page 1</a>,
<a href="page.php?offset=1">Page 2</a>,
<a href="page.php?offset=2">Page 3</a>
</p>
</body>
</html>

I want to show a cookie of a referral's username on a sign up page. The link is like this, www.mysite.com/signup?ref=johnsmith.

The cookie doesn't show if I go to that url page. But it does show up once I reload the page.  So I'm wondering if it's possible to show the cookie the first time around, instead of reloading the page?

Here is my code.

// This is in the header
$url_ref_name = (!empty($_GET['ref']) ? $_GET['ref'] : null);

if(!empty($url_ref_name)) {

  $number_of_days = 365;
  $date_of_expiry = time() + 60 * 60 * 24 * $number_of_days;
  setcookie( "ref", $url_ref_name, $date_of_expiry,"/");

} else if(empty($url_ref_name)) {
  if(isset($_COOKIE['ref'])) {
    $user_cookie = $_COOKIE['ref'];
  }
} else {}

// This is for the sign up form
if(isset($_COOKIE['ref'])) {
  $user_cookie = $_COOKIE['ref'];
  ?>
  <fieldset>
    <label>Referred By</label>
    <div id="ref-one"><span><?php if(!empty($user_cookie)){echo $user_cookie;} ?></span></div>
    <input type="hidden" name="ref" value="<?php if(!empty($user_cookie)){echo $user_cookie;} ?>" maxlength="20" placeholder="Referrer's username" readonly onfocus="this.removeAttribute('readonly');" />
  </fieldset>
  <?php
}

 

I have two different tables and I am trying to condense them into one table.   The structure of the tables is   cc -- ci -- cc -- cn -- alpha_2   countries -- id -- cn -- alpha_2 -- alpha_3   What I want to do is place the info from the column alpha_2 in the countries table into the alpha_2 column in the cc table. I have tried inner joins, left joins, Insert and Select index. Everything that I have tried gives me an error message. I do not know what I am doing wrong and I was hoping that someone would be able to give me a hand.   I forgot to mention that I want the placement of the alpha_2 column to be based on the cn columns in both tables. So that the information in the alpha_2 column lines up with the right name in the cn column
Edited by mdmartiny, 09 August 2014 - 01:07 PM.

Hello, me again.

I have created a little forum - very very basic.

main_forum.php :

Code: [Select]
<?php
$host="localhost"; // Host name 
$username="yvonnedp"; // Mysql username 
$password="yvonne"; // Mysql password 
$db_name="forum"; // Database name 
$tbl_name="forum_question"; // Table name 

// Connect to server and select databse.
mysql_connect('localhost', 'yvonnedp', 'yvonne')or die("cannot connect"); 
mysql_select_db("$db_name")or die("cannot select DB");

$sql="SELECT * FROM $tbl_name ORDER BY id";
// OREDER BY id DESC is order result by descending 
$result=mysql_query($sql);
?>
<table width="90%" border="0" align="center" cellpadding="3" cellspacing="1" bgcolor="#CCCCCC">
<tr>
<td width="6%" align="center" bgcolor="#E6E6E6"><strong>#</strong></td>
<td width="53%" align="center" bgcolor="#E6E6E6"><strong>Topic</strong></td>
<td width="15%" align="center" bgcolor="#E6E6E6"><strong>Views</strong></td>
<td width="13%" align="center" bgcolor="#E6E6E6"><strong>Replies</strong></td>
<td width="13%" align="center" bgcolor="#E6E6E6"><strong>Date/Time</strong></td>
</tr>

<?php
while($rows=mysql_fetch_array($result)){ // Start looping table row 
?>
<tr>
<td bgcolor="#FFFFFF"><? echo $rows['id']; ?></td>
<td bgcolor="#FFFFFF"><a href="view_topic.php?id=<? echo $rows['id']; ?>"><? echo $rows['topic']; ?></a><BR></td>
<td align="center" bgcolor="#FFFFFF"><? echo $rows['view']; ?></td>
<td align="center" bgcolor="#FFFFFF"><? echo $rows['reply']; ?></td>
<td align="center" bgcolor="#FFFFFF"><? echo $rows['datetime']; ?></td>
</tr>

<?php
// Exit looping and close connection 
}
mysql_close();
?>
create_topic.php :

Code: [Select]
<table width="400" border="0" align="center" cellpadding="0" cellspacing="1" bgcolor="#CCCCCC">
<tr>
<form id="form1" name="form1" method="post" action="add_topic.php">
<td>
<table width="100%" border="0" cellpadding="3" cellspacing="1" bgcolor="#FFFFFF">
<tr>
<td colspan="3" bgcolor="#E6E6E6"><strong>Create New Topic</strong> </td>
</tr>
<tr>
<td width="14%"><strong>Topic</strong></td>
<td width="2%">:</td>
<td width="84%"><input name="topic" type="text" id="topic" size="50" /></td>
</tr>
<tr>
<td valign="top"><strong>Detail</strong></td>
<td valign="top">:</td>
<td><textarea name="detail" cols="50" rows="3" id="detail"></textarea></td>
</tr>
<tr>
<td><strong>Name</strong></td>
<td>:</td>
<td><input name="name" type="text" id="name" size="50" /></td>
</tr>
<tr>
<td>&nbsp;</td>
<td>&nbsp;</td>
<td><input type="submit" name="Submit" value="Submit" /> <input type="reset" name="Submit2" value="Reset" /></td>
</tr>
</table>
</td>
</form>
</tr>
</table>
add_topic.php :

Code: [Select]
<?php
$host="localhost"; // Host name 
$username="yvonnedp"; // Mysql username 
$password="yvonne"; // Mysql password 
$db_name="forum"; // Database name 
$tbl_name="forum_question"; // Table name 

// Connect to server and select database.
mysql_connect('localhost', 'yvonnedp', 'yvonne')or die("cannot connect"); 
mysql_select_db("$db_name")or die("cannot select DB");

// get data that sent from form 
$topic=$_POST['topic'];
$detail=$_POST['detail'];
$name=$_POST['name'];

$datetime=date("d/m/y h:i:s"); //create date time

$sql="INSERT INTO $tbl_name(topic, detail, name, datetime)VALUES('$topic', '$detail', '$name', '$datetime')";
$result=mysql_query($sql);

if($result){
echo "Successful<BR>";
echo "<a href=main_forum.php>View your topic</a>";
 
 $email_from = "forums@thenewme.co.za";
     $email_to = "info@thenewme.co.za";
     $email_subject = "The New Me - New Forum Topic";

     $email_message = "A new topic has been posted on the Forum!\n";
     $email_message .= "Check it out : http://www.thenewme.co.za/forum/main_forum.php";
     
     $headers = 'From: '.$email_from."\r\n";
 'Reply-To: '.$email_from."\r\n" . 'X-Mailer: PHP/' . phpversion();
  @mail($email_to, $email_subject, $email_message, $headers);


}
else {
echo "ERROR";
}
mysql_close();
?>
add_answer.php :

Code: [Select]
<?php
 
$host="localhost"; // Host name 
$username="yvonnedp"; // Mysql username 
$password="yvonne"; // Mysql password 
$db_name="forum"; // Database name 
$tbl_name="forum_answer"; // Table name 

// Connect to server and select databse.
mysql_connect('localhost', 'yvonnedp', 'yvonne')or die("cannot connect"); 
mysql_select_db("$db_name")or die("cannot select DB");

// Get value of id that sent from hidden field 
$id=$_POST['id'];

// Find highest answer number. 
$sql="SELECT MAX(a_id) AS Maxa_id FROM $tbl_name WHERE question_id='$id'";
$result=mysql_query($sql);
$rows=mysql_fetch_array($result);

// add + 1 to highest answer number and keep it in variable name "$Max_id". if there no answer yet set it = 1 
if ($rows) {
$Max_id = $rows['Maxa_id']+1;
}
else {
$Max_id = 1;
}

// get values that sent from form 
$a_name=$_POST['a_name'];
$a_answer=$_POST['a_answer']; 

$datetime=date("d/m/y H:i:s"); // create date and time 

// Insert answer 
$sql2="INSERT INTO $tbl_name(question_id, a_id, a_name, a_answer, a_datetime)VALUES('$id', '$Max_id', '$a_name', '$a_answer', '$datetime')";
$result2=mysql_query($sql2);

if($result2){
echo "Successful<BR>";
echo "<a href='view_topic.php?id=".$id."'>View your answer</a>";

// If added new answer, add value +1 in reply column 
$tbl_name2="forum_question";
$sql3="UPDATE $tbl_name2 SET reply='$Max_id' WHERE id='$id'";
$result3=mysql_query($sql3);

 $email_from = "forums@thenewme.co.za";
     $email_to = "info@thenewme.co.za";
     $email_subject = "The New Me - New Forum Answer";

     $email_message = "A new answer to a forum topic has been posted on the Forum!\n";
     $email_message .= "Check it out : http://www.thenewme.co.za/forum/main_forum.php";
     
     $headers = 'From: '.$email_from."\r\n";
 'Reply-To: '.$email_from."\r\n" . 'X-Mailer: PHP/' . phpversion();
  @mail($email_to, $email_subject, $email_message, $headers);

}
else {
echo "ERROR";
}

mysql_close();
?>
view_topic :

Code: [Select]
<?php
$tbl_name2="forum_answer"; // Switch to table "forum_answer" 

$sql2="SELECT * FROM $tbl_name2 WHERE question_id='$id'";
$result2=mysql_query($sql2);

while($rows=mysql_fetch_array($result2)){
?>
<table width="400" border="0" align="center" cellpadding="0" cellspacing="1" bgcolor="#CCCCCC">
<tr>
<td><table width="100%" border="0" cellpadding="3" cellspacing="1" bgcolor="#FFFFFF">
<tr>
<td bgcolor="#F8F7F1"><strong>ID</strong></td>
<td bgcolor="#F8F7F1">:</td>
<td bgcolor="#F8F7F1"><? echo $rows['a_id']; ?></td>
</tr>
<tr>
<td width="18%" bgcolor="#F8F7F1"><strong>Name</strong></td>
<td width="5%" bgcolor="#F8F7F1">:</td>
<td width="77%" bgcolor="#F8F7F1"><? echo $rows['a_name']; ?></td>
</tr>
<tr>
<td bgcolor="#F8F7F1"><strong>Answer</strong></td>
<td bgcolor="#F8F7F1">:</td>
<td bgcolor="#F8F7F1"><? echo $rows['a_answer']; ?></td>
</tr>
<tr>
<td bgcolor="#F8F7F1"><strong>Date/Time</strong></td>
<td bgcolor="#F8F7F1">:</td>
<td bgcolor="#F8F7F1"><? echo $rows['a_datetime']; ?></td>
</tr>
</table></td>
</tr>
</table><br>

<?
}

$sql3="SELECT view FROM $tbl_name WHERE id='$id'";
$result3=mysql_query($sql3);

$rows=mysql_fetch_array($result3);
$view=$rows['view'];

// if have no counter value set counter = 1
if(empty($view)){
$view=1;
$sql4="INSERT INTO $tbl_name(view) VALUES('$view') WHERE id='$id'";
$result4=mysql_query($sql4);
}

// count more value
$addview=$view+1;
$sql5="update $tbl_name set view='$addview' WHERE id='$id'";
$result5=mysql_query($sql5);

mysql_close();
?>
the problem is. With add_answer, I am not able to insert an answer. This has worked for the very first question, but all subsequent questions, I am unable to add answers. It keeps telling me ERROR.

This is where the live forum is : http://www.thenewme.co.za/forum/main_forum.php

Can it be an issue with the field that gets autmatically incremented? i have echo'd the data which get entered in when someone types in an answer, and everything is perfect!

Can anyone help me?