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PHP - Table With Connection Mysql Database
Similar TutorialsHello guys. Trying to connect php with mysql database and then display results on the screen. This is my code: Code: [Select] <?php $dbhost = "localhost"; $dbuser = "username1"; $dbpass = "password1"; $db = "username1_myDB"; $connection = mysql_connect($dbhost, $dbuser, $dbpass) or die ("Could not connect"); mysql_select_db($connection, $db); $show = "SELECT Name, Description FROM people"; $result = mysql_query($show); while($show = mysql_fetch_array($result)){ $field01 = $show[Name]; $field02 = $show[Description]; echo "id: $field01<br>"; echo "description: $field02<p>"; } ?> However im getting this: Warning: mysql_select_db() expects parameter 1 to be string, resource given in /home/pain33/public_html/index.php on line 20 Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in /home/pain33/public_html/index.php on line 26 Any ideas how to fix this? Thank you. Hi there, I am having a bit of trouble understanding what I am doing, basically all I want at the moment is to be able to make a very basic introductory guide for myself on my own Database class implementation. I know there are some around on the web but I thought for my own education I would create one of my own, just to see if I can fully understand what it is I am doing. It won't at this present moment involve anything more than a standard class, with 3 properties: protected $_connect This will be the basis for mysql_connect stuff. protected $_query As you probably would have guessed the basis for the mysql_query strings this application will do. protected $_error Then finally any errors that occur will go through this function, right thats the properties done for now (please feel free to add any should you feel I should need them though, why I am asking for your help ). Right here is my code, it is all on the same file, say class.db.php or something simple, just to see how I can get this working firstly, then I will segregate (or more split the new Db class into its own file), then have my actual form generation going from another class file and then do a real implement of the whole thing. Again this is only for my own education, nothing else! Here is my class file for the database: class Db { protected $_connect; // dont allow credentials in here yet! protected $_query; // holds the query info? protected $_error; // raises an error message when needed! public function __construct($host,$username,$password) { $this->_connect = mysql_connect($host,$username,$password); } } $newDatabase = new Db("localhost","dbuser","password"); echo "<pre>"; print_r($newDatabase); echo "</pre>"; What it's bringing up though is along the lines of this: Quote Db Object ( [_connect:protected] => Resource id #2 [_query:protected] => [_error:protected] => ) Is there any obvious error I am doing to not allowing the properties to fill up or something? I cant seem to get this working, again any helps appreciated, Jeremy. I was wondering what the users at phpfreaks recommend as far as persistent database connections. Is it better to save the connection, or to open up a new connection for each page? Also, how would you have a persistent connection? Is there an alert method for the MySQL database or something similar?
What is the proper way to check if the MySQL database connection is working?
I mean other than "creating" and "retrieving" with "insert" and "select".
after cloasing connection of database i still got the values form database. Code: [Select] <?php session_start(); /* * To change this template, choose Tools | Templates * and open the template in the editor. */ require_once '../database/db_connecting.php'; $dbname="sahansevena";//set database name $con= setConnections();//make connections use implemented methode in db_connectiong.php mysql_select_db($dbname, $con); //update the time and date of the admin table $update_time="update admin set last_logged_date =CURDATE(), last_log_time=CURTIME() where username='$uname'limit 3,4"; //my admin table contain 5 colums they are id, username,password, last_logged_date, last_log_time $link= mysql_query($update_time); // mysql_select_db($dbname, $link); //$con=mysql_connect('localhost', 'root','ijts'); $result="select * from admin where username='a'"; $result=mysql_query($result); mysql_close($con); //here i just check after closing data baseconnection whether i do get reselts but i do, why? echo "after the cnnection was closed"; if(!$result){ echo "cont fetch data"; }else{ $row= mysql_fetch_array($result); echo "id".$row[0]."usrname".$row[1]."passwped".$row[2]."date".$row[3]."time".$row[4]; } // echo "<html>"; //echo "<table border='1' cellspacing='1' cellpadding='2' align='center'>"; // echo "<thead>"; // echo"<tr>"; // echo "<th>"; // echo ID; // echo"</th>"; // echo" <th>";echo Username; echo"</th>"; // echo"<th>";echo Password; echo"</th>"; // echo"<th>";echo Last_logged_date; echo "</th>"; // echo "<th>";echo Last_logged_time; echo "</th>"; // echo" </tr>"; // echo" </thead>"; // echo" <tbody>"; //while($row= mysql_fetch_array($result,MYSQL_BOTH)){ // echo "<tr>"; // echo "<td>"; // echo $row[0]; // echo "</td>"; // echo "<td>"; // echo $row[1]; // echo "</td>"; // echo "<td>"; // echo $row[2]; // echo "</td>"; // echo "<td>"; // echo $row[3]; // echo "</td>"; // echo "<td>"; // echo $row[4]; // echo "</td>"; // echo "</tr>"; // } // echo" </tbody>"; // echo "</table>"; // echo "</html>"; session_destroy(); session_commit(); echo "session and database are closed but i still get values from doatabase session is destroyed".$_SESSION['admin']; ?> session is destroyed but database connection is not closed. thanks Ok, I got someone to help me fix this but he had no idea what the error was... I have 2 tables, one called points and the other called members. In members i have got: id name In points i have got: id memberid promo I have the following code: Code: [Select] <?php $con = mysql_connect("localhost","slay2day_User","slay2day"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("slay2day_database",$con); $sqlquery="SELECT Sum(points.promo) AS score, members.name, members.id = points.memberid Order By members.name ASC"; $result=mysql_query($sqlquery,$con); while ($row = mysql_fetch_array($result)) { //get data $id = $row['id']; $name = $row['name']; $score = $row['score']; echo "<b>Name:</b> $name<br />"; echo "<b>Points: </b> $score<br />" ; echo "<b>Rank: </b>"; if ($name == 'Kcroto1'): echo 'The Awesome Leader'; else: if ($points >= '50'): echo 'General'; elseif ($points >= '20'): echo 'Captain!'; elseif ($points >= '10'): echo 'lieutenant'; elseif ($points >= '5'): echo 'Sergeant'; elseif ($points >= '2'): echo 'Corporal'; else: echo 'Recruit'; endif; endif; echo '<br /><br />'; } ?> I am getting the following error when i do the query in mysql: Code: [Select] #1109 - Unknown table 'points' in field list And when i open the webpage i get the following error: Code: [Select] Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in /home/slay2day/public_html/points/members.php on line 18 Please Help me? For the last few days I have been trying to work out why my code does not update the MySQL database table. Having tried several variation I have the below but cannot see anything wrong. The rest of the program produces the correct results (displaying what is currently on the table) showing it is connecting to the correct table but altering the table is not working. Any help greatly appreciated. The few lines in question a Code: [Select] // Update the profile data in the database if (!$error) { if (!empty($name)&& !empty($phone) && !empty($address1) && !empty($address2)) { // Only set the picture column if there is a new picture if (!empty($new_picture)) { //if (!empty($postcode)){ $query = "UPDATE antique SET name = '$name', phone = '$phone', address1 = '$address1', address2 = '$address2', postcode = '$postcode', " . " email = '$email', webadd = '$webadd', picture = '$new_picture', username = '" . $_SESSION['username'] . "' WHERE name = '" . $row['name'] ."'"; }} else { $query = "UPDATE antique SET name = '$name', phone = '$phone', address1 = '$address1', address2 = '$address2', postcode = '$postcode', " . " email = '$email', webadd = '$webadd', username = '" . $_SESSION['username'] . "' WHERE name = '" . $row['name'] ."'"; } mysqli_query($dbc, $query) or die("<br>Query $query<br>Failed with error: " . mysqli_error($dbc) . '<br>On line: ' . __LINE__); The whole program is below Code: [Select] <?php error_reporting(E_ALL); session_start(); ?> <?php require_once('appvars.php'); require_once('connectvars1.php'); // Connect to the database $dbc = mysqli_connect(DB_Host, DB_User, DB_Password, DB_Name); if (!isset($_GET['user_id'])) { $query = "SELECT * FROM antique WHERE user_id = '" . $_SESSION['user_id'] . "'"; } else { $query = "SELECT * FROM antique WHERE user_id = '" . $_GET['user_id'] . "'"; } $data = mysqli_query($dbc, $query); if (mysqli_num_rows($data) == 1) { // The user row was found so display the user data $row = mysqli_fetch_array($data); echo '<table>'; if (!empty($row['name'])) { echo '<tr><td class="label">Name:</td><td>' . $row['name'] . '</td></tr>'; } if (!empty($row['phone'])) { echo '<tr><td class="label">Phone:</td><td>' . $row['phone'] . ' </td></tr>'; } if (!empty($row['address1'])) { echo '<tr><td class="label">Address1:</td><td>' . $row['address1'] . ' </td></tr>'; } if (!empty($row['address2'])) { echo '<tr><td class="label">Address2:</td><td>' . $row['address2'] . ' </td></tr>'; } if (!empty($row['postcode'])) { echo '<tr><td class="label">Postcode:</td><td>' . $row['postcode'] . ' </td></tr>'; } if (!empty($row['webadd'])) { echo '<tr><td class="label">Web address:</td><td>' . $row['webadd'] . ' </td></tr>'; } if (!empty($row['email'])) { echo '<tr><td class="label">Email:</td><td>' . $row['email'] . ' </td></tr>'; } if (!empty($row['username'])) { echo '<tr><td class="label">Username:</td><td>' . $row['username'] . ' </td></tr>'; } if (!empty($row['user_id'])) { echo '<tr><td class="label">User ID:</td><td>' . $row['user_id'] . ' </td></tr>'; } echo '</table>'; //echo '<class = "label">USER ID: ' . $_SESSION['user_id'] . ''; if (!isset($_GET['postcode']) || ($_SESSION['postcode'] == $_GET['postcode'])) { echo '<p>Would you like to <a href="index5.php">Go to Homepage</a>?</p>'; } } // End of check for a single row of user results else { echo '<p class="error">There was a bit of a problem accessing your profile.</p>'; } ?> <hr> <?php require_once('appvars.php'); require_once('connectvars1.php'); // Make sure the user is logged in before going any further. if (!isset($_SESSION['user_id'])) { echo '<p class="login">Please <a href="login1.php">log in</a> to access this page.</p>'; exit(); } // Connect to the database $dbc = mysqli_connect(DB_Host, DB_User, DB_Password, DB_Name); if (isset($_POST['submit'])) { // Grab the profile data from the POST $name = mysqli_real_escape_string($dbc, trim($_POST['name'])); $phone = mysqli_real_escape_string($dbc, trim($_POST['phone'])); $address1 = mysqli_real_escape_string($dbc, trim($_POST['address1'])); $address2 = mysqli_real_escape_string($dbc, trim($_POST['address2'])); $postcode = mysqli_real_escape_string($dbc, trim($_POST['postcode'])); $webadd = mysqli_real_escape_string($dbc, trim($_POST['webadd'])); $email = mysqli_real_escape_string($dbc, trim($_POST['email'])); $old_picture = mysqli_real_escape_string($dbc, trim($_POST['old_picture'])); $new_picture = mysqli_real_escape_string($dbc, trim($_FILES['new_picture']['name'])); $new_picture_type = $_FILES['new_picture']['type']; $new_picture_size = $_FILES['new_picture']['size']; $username = mysqli_real_escape_string($dbc, trim($_POST['username'])); $user_id = mysqli_real_escape_string($dbc, trim($_POST['user_id'])); if (!empty($_FILES['new_picture']['tmp_name'])) {list($new_picture_width, $new_picture_height) = getimagesize($_FILES['new_picture']['tmp_name']); } //list($new_picture_width, $new_picture_height) = getimagesize($_FILES['new_picture']['tmp_name']); $error = false; // Validate and move the uploaded picture file, if necessary if (!empty($new_picture)) { if ((($new_picture_type == 'image/gif') || ($new_picture_type == 'image/jpeg') || ($new_picture_type == 'image/pjpeg') || ($new_picture_type == 'image/png')) && ($new_picture_size > 0) && ($new_picture_size <= MM_MAXFILESIZE) && ($new_picture_width <= MM_MAXIMGWIDTH) && ($new_picture_height <= MM_MAXIMGHEIGHT)) { if ($_FILES['new_picture']['error'] == 0) { // Move the file to the target upload folder $target = MM_UPLOADPATH . basename($new_picture); if (move_uploaded_file($_FILES['new_picture']['tmp_name'], $target)) { // The new picture file move was successful, now make sure any old picture is deleted if (!empty($old_picture) && ($old_picture != $new_picture)) { } } else { // The new picture file move failed, so delete the temporary file and set the error flag @unlink($_FILES['new_picture']['tmp_name']); $error = true; echo '<p class="error">Sorry, there was a problem uploading your picture.</p>'; } } } else { // The new picture file is not valid, so delete the temporary file and set the error flag @unlink($_FILES['new_picture']['tmp_name']); $error = true; echo '<p class="error">Your picture must be a GIF, JPEG, or PNG image file no greater than ' . (MM_MAXFILESIZE / 1024) . ' KB and ' . MM_MAXIMGWIDTH . 'x' . MM_MAXIMGHEIGHT . ' pixels in size.</p>'; } } $error = false; // Update the profile data in the database if (!$error) { if (!empty($name)&& !empty($phone) && !empty($address1) && !empty($address2)) { // Only set the picture column if there is a new picture if (!empty($new_picture)) { //if (!empty($postcode)){ $query = "UPDATE antique SET name = '$name', phone = '$phone', address1 = '$address1', address2 = '$address2', postcode = '$postcode', " . " email = '$email', webadd = '$webadd', picture = '$new_picture', username = '" . $_SESSION['username'] . "' WHERE name = '" . $row['name'] ."'"; }} else { $query = "UPDATE antique SET name = '$name', phone = '$phone', address1 = '$address1', address2 = '$address2', postcode = '$postcode', " . " email = '$email', webadd = '$webadd', username = '" . $_SESSION['username'] . "' WHERE name = '" . $row['name'] ."'"; } mysqli_query($dbc, $query) or die("<br>Query $query<br>Failed with error: " . mysqli_error($dbc) . '<br>On line: ' . __LINE__); // Confirm success with the user echo '<p>Your profile has been successfully updated. Would you like to <a href="viewprofile4.php">view your profile</a>?</p>'; mysqli_close($dbc); exit(); } else { echo '<p class="error">You must enter all of the profile data (the picture is optional).</p>'; } } // End of check for form submission else { // Grab the profile data from the database $query="SELECT * FROM antique WHERE user_id= '" . $row['user_id'] . "'"; $data = mysqli_query($dbc, $query); $row = mysqli_fetch_array($data); if ($row != NULL) { $name = $row['name']; $phone = $row['phone']; $address1 = $row['address1']; $address2 = $row['address2']; $postcode = $row['postcode']; $email = $row['email']; $webadd = $row['webadd']; $old_picture = $row['picture']; $username = $_SESSION['username']; $user_id = $row['user_id']; } else { echo '<p class="error">There was a problem accessing your profile.</p>'; } } mysqli_close($dbc); ?> <form enctype="multipart/form-data" method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>"> <input type="hidden" name="MAX_FILE_SIZE" value="<?php echo MM_MAXFILESIZE; ?>" /> <fieldset> <legend>Personal Information</legend> <label for="name">Name:</label> <input type="text" id="name" name="name" value="<?php if (!empty($name)) echo $name; ?>" /><br /> <label for="phone">Phone:</label> <input type="text" id="phone" name="phone" value="<?php if (!empty($phone)) echo $phone; ?>" /><br /> <label for="address1">Address1:</label> <input type="text" id="address1" name="address1" value="<?php if (!empty($address1)) echo $address1; ?>" /><br /> <label for="address2">Address2:</label> <input type="text" id="address2" name="address2" value="<?php if (!empty($address2)) echo $address2; ?>" /><br /> <label for="postcode">Postcode:</label> <input type="text" id="postcode" name="postcode" value="<?php if (!empty($postcode)) echo $postcode; ?>" /><br /> <label for="email">Email:</label> <input type="text" id="email" name="email" value="<?php if (!empty($email)) { echo $email; } else { echo 'No email entered';} ?>" /><br /> <label for="webadd">Web address:</label> <input type="text" id="webadd" name="webadd" value="<?php if (!empty($webadd)) { echo $webadd; } else { echo 'No web address entered';} ?>" /><br /> <input type="hidden" name="old_picture" value="<?php if (!empty($old_picture)) echo $old_picture; ?>" /> <label for="new_picture">Pictu </label> <input type="file" id="new_picture" name="new_picture" /> <?php if (!empty($old_picture)) { echo '<img class="profile" src="' . MM_UPLOADPATH . $old_picture . '" alt="Profile Picture" style: height=100px;" />'; } ?> <br /> <label for="username">Username:</label> <input type="text" id="username" name="username" value="<?php if (!empty($username)) echo $username; ?>" /><br /> <label for="user_id">User ID:</label> <input type="text" id="user_id" name="user_id" value="<?php echo '' . $row['user_id'] . '' ; ?>" /><br /> </fieldset> <input type="submit" value="Save Profile" name="submit" /> </form> <?php echo('<p class="login">You are logged in as ' . $_SESSION['username'] . '. <a href="logout3.php">Log out</a>.</p>'); echo '<class = "label">USER ID: ' . $row['user_id'] . ''; ?> <p><a href="index.php">Return to homepage</a></p> <?php require_once('footer.php'); ?> </body> </html> Hi friends i need a small help in importing csv files into mySQL database table i tried all possible options but i am no where... here is the example for what i am trying to do Mysql DB name = raw Table name is = dump +--------------------+--------------------+ + Account + Bal + +--------------------+--------------------+ + + + +--------------------+--------------------+ CSV Format 50************13, 11095 When they upload the file it should automatically get inserted into appropriate fields any help would be great i tried all possible scripts found in the net could nothing is happening Hi, here's my problem: I am trying to make a simple online buying website and I want to display a table with all the fields for each item. So I got that part down which is to just use mysql_fetch_assoc("SELECT * FROM myTable") and use the html table tags stuff, but now I want to display my images in the table, so here's my code to display my mysql database table in html's table tag along w/ php: <html> <head> <title>My Online buying website project</title> </head> <body> <?php mysql_connect("localhost","root"); mysql_select_db("myTable"); $imagesArray=array("Apple_iPhone3GS.jpg","Apple_iPhone4.jpg","product3.jpg","product4.jpg","product5.jpg"); $result=mysql_query("SELECT Name, Manufacturer, Price, Description, SimSupport FROM myTable"); if(mysql_num_rows($result))//if there is at least one entry in bellProducts, make a table { print "<table border='border'>"; print "<tr> <th>Name</th> <th>Manufacturer</th> <th>Price</th> <th>Description</th> <th>SimSupport</th> </tr>"; //NB: now output each row of records while($row=mysql_fetch_assoc($result)) { extract($row); print "<tr> <td>$Name</td> <td>$Manufacturer</td> <td>$Price</td> <td>$Description</td><td>$SimSupport</td> </tr>"; }//END WHILE }//END IF ?> </table> </body> </html> *So how do I go about adding my images in this table? well I know the standard way of retrieving mysql data was through the following codes: Code: [Select] $query = "SELECT * FROM {$tablename} WHERE columnmame = '{$var}'"; $result = mysql_query($query); $row = mysql_fetch_array($result); This will return all properties inside a table row by an associative array indexed by column names. I am, however, wondering if there is an easier way to retrieve database info from more than one table. For now, what I am doing is: Code: [Select] $result = mysql_query( "SELECT * FROM {$tablename} WHERE columnmame = '{$var}'"); $row = mysql_fetch_array($result); $result2 = mysql_query( "SELECT * FROM {$tablename2} WHERE columnmame2 = '{$var2}'"); $row2 = mysql_fetch_array($result2); which is a bit tedious and can cause problems when two or more coders work on the same project(it will be difficult to tell what is $row1, $row2 and $row3...). Is there away to write a simpler code than the one above? I mean, if it is possible to run mysql_fetch_array only once and retrieve database info from multiple tables? Hello I have an array with data from `mysql` that I would like to output it in a table using twig. The image is an example of want i want to achieve but without any luck. `print_r` of the array data Array ( [Administrator] => Array ( [0] => Array ( [RoleName] => Administrator [PermissionName] => Catalog-View [PermissionId] => 1 ) [1] => Array ( [RoleName] => Administrator [PermissionName] => Catalog-Edit [PermissionId] => 2 ) [2] => Array ( [RoleName] => Administrator [PermissionName] => Catalog-Delete [PermissionId] => 3 ) ) [Moderator] => Array ( [0] => Array ( [RoleName] => Moderator [PermissionName] => Catalog-View [PermissionId] => 1 ) ) ) The `HTML` code:
<table>
<tr>
<thead>
<th>Controller - Action</th>
{% for permission in permissions %}
{% for item in permission %}
<th>{{item.RoleName}}</th>
{% endfor %}
{% endfor %}
</thead>
</tr>
{% for permission in permissions %}
{% for item in permission %}
<tr>
<td>{{item.PermissionName}}</td>
<td>{{item.PermissionId}}</td>
</tr>
{% endfor %}
{% endfor %}
</table>
OUTPUT: <table> <tbody> <tr></tr> </tbody> <thead> <tr> <th>Controller - Action</th> <th>Administrator</th> <th>Administrator</th> <th>Administrator</th> <th>Moderator</th> </tr> </thead> <tbody> <tr> <td>Catalog-View</td> <td>1</td> </tr> <tr> <td>Catalog-Edit</td> <td>2</td> </tr> <tr> <td>Catalog-Delete</td> <td>3</td> </tr> <tr> <td>Catalog-View</td> <td>1</td> </tr> </tbody> </table> Later Edit MySQL Query: SELECT t3.PermissionName, t1.PermissionId, t2.RoleName FROM tbl_user_role_perm AS t1 INNER JOIN tbl_user_roles AS t2 ON t1.RoleId = t2.RoleId INNER JOIN tbl_user_permissions AS t3 ON t1.PermissionId = t3.PermissionId MySQL Dump: -- Dumping structure for table tbl_user_permissions CREATE TABLE IF NOT EXISTS `tbl_user_permissions` ( `PermissionId` int(11) NOT NULL AUTO_INCREMENT, `PermissionName` varchar(50) NOT NULL, `PermissionDescription` varchar(100) NOT NULL, PRIMARY KEY (`PermissionId`) ) ENGINE=InnoDB AUTO_INCREMENT=4 DEFAULT CHARSET=latin1; -- Dumping data for table tbl_user_permissions: ~2 rows (approximately) DELETE FROM `tbl_user_permissions`; /*!40000 ALTER TABLE `tbl_user_permissions` DISABLE KEYS */; INSERT INTO `tbl_user_permissions` (`PermissionId`, `PermissionName`, `PermissionDescription`) VALUES (1, 'Catalog->View', 'View Catalog Method'), (2, 'Catalog->Edit', 'Edit Catalog Method'), (3, 'Catalog->Delete', 'Delete Catalog Method'); /*!40000 ALTER TABLE `tbl_user_permissions` ENABLE KEYS */; -- Dumping structure for table tbl_user_role CREATE TABLE IF NOT EXISTS `tbl_user_role` ( `UserRoleId` int(10) NOT NULL AUTO_INCREMENT, `UserId` int(10) NOT NULL, `RoleId` int(10) unsigned NOT NULL, PRIMARY KEY (`UserRoleId`), KEY `FK_tbl_user_role_tbl_user_roles` (`RoleId`), KEY `UserId` (`UserId`) ) ENGINE=InnoDB AUTO_INCREMENT=3 DEFAULT CHARSET=latin1; -- Dumping data for table tbl_user_role: ~2 rows (approximately) DELETE FROM `tbl_user_role`; /*!40000 ALTER TABLE `tbl_user_role` DISABLE KEYS */; INSERT INTO `tbl_user_role` (`UserRoleId`, `UserId`, `RoleId`) VALUES (1, 13, 22), (2, 14, 22); /*!40000 ALTER TABLE `tbl_user_role` ENABLE KEYS */; -- Dumping structure for table tbl_user_roles CREATE TABLE IF NOT EXISTS `tbl_user_roles` ( `RoleId` int(10) unsigned NOT NULL AUTO_INCREMENT, `RoleName` varchar(50) NOT NULL, `CreatedDate` datetime NOT NULL, `ModifiedDate` datetime DEFAULT NULL ON UPDATE CURRENT_TIMESTAMP, PRIMARY KEY (`RoleId`) ) ENGINE=InnoDB AUTO_INCREMENT=29 DEFAULT CHARSET=utf8; -- Dumping data for table tbl_user_roles: ~7 rows (approximately) DELETE FROM `tbl_user_roles`; /*!40000 ALTER TABLE `tbl_user_roles` DISABLE KEYS */; INSERT INTO `tbl_user_roles` (`RoleId`, `RoleName`, `CreatedDate`, `ModifiedDate`) VALUES (22, 'Administrator', '2014-10-28 09:53:08', NULL), (23, 'Moderator', '2014-10-28 09:53:13', NULL), (24, 'Admin', '2014-10-28 12:22:05', '2014-10-28 12:22:06'), (25, 'User', '2014-10-29 15:10:36', '2014-10-29 15:10:37'), (26, 'SuperUser', '2014-10-29 15:10:45', '2014-10-29 15:10:46'), (27, 'Accountant', '2014-10-29 15:10:53', '2014-10-29 15:10:54'), (28, 'God', '2014-10-29 15:11:02', '2014-10-29 15:11:02'); /*!40000 ALTER TABLE `tbl_user_roles` ENABLE KEYS */; -- Dumping structure for table tbl_user_role_perm CREATE TABLE IF NOT EXISTS `tbl_user_role_perm` ( `RoleId` int(10) unsigned NOT NULL, `PermissionId` int(10) unsigned NOT NULL, KEY `RoleId` (`RoleId`), KEY `PermissionId` (`PermissionId`) ) ENGINE=InnoDB DEFAULT CHARSET=utf8; -- Dumping data for table tbl_user_role_perm: ~3 rows (approximately) DELETE FROM `tbl_user_role_perm`; /*!40000 ALTER TABLE `tbl_user_role_perm` DISABLE KEYS */; INSERT INTO `tbl_user_role_perm` (`RoleId`, `PermissionId`) VALUES (22, 2), (22, 1), (23, 1), (22, 3); /*!40000 ALTER TABLE `tbl_user_role_perm` ENABLE KEYS */; /*!40101 SET SQL_MODE=IFNULL(@OLD_SQL_MODE, '') */; /*!40014 SET FOREIGN_KEY_CHECKS=IF(@OLD_FOREIGN_KEY_CHECKS IS NULL, 1, @OLD_FOREIGN_KEY_CHECKS) */; /*!40101 SET CHARACTER_SET_CLIENT=@OLD_CHARACTER_SET_CLIENT */;Can you help me to make the coding required so that the correct column have the correct permissions? thank you in advance. Hi, I'm a researcher (and complete coding noob), and am planning a longitudinal study that requires e-mail follow-up with subjects taking an initial survey. For purposes of ethics/anonymity due to sensitive survey data, I'd like the acquired e-mails to be saved uncoupled from the survey responses; this is simple to deal with, and I use a basic PHP e-mail form, which injects the email address in a table in MySQL in a different server than the one used for the survey. The issue is that the e-mails are saved in the MySQL database in order of injection, thus it is still theoretically possible for me to link the e-mails back to the survey responses (which have a time stamp that I cannot remove). Ideally I would like not to be able (at all) to link the e-mails to the survey responses, and one way to do that (since I don't save the e-mail injection timestamps in MySQL) might be to have the e-mails saved in MySQL in a random order. Not sure if this is possible, and not even sure if this would be via PHP or MySQL side of things. The server is on godaddy and uses Starfield interface for MySQL but I cannot find an option for random insert/saving of table items (emails). They are saved in order of injection. Any solution for this? Thanks, Not really sure how to get the images I have stored in MySQL into a html form. I can call-up the text fields from the database but it cannot seem to find the index for the images. Here is my code:- <?php session_start(); mysql_connect("localhost","root","abc") or die ("Error! Cannot connect to database"); mysql_select_db("theimageworks") or die ("Cannot find database"); $query = "SELECT * FROM jobs"; $result = mysql_query($query) or die (mysql_error()); ?> <?php //display data in html table echo "<table>"; echo "<tr><td>Username</td><td align='center'>Message</td><td>Product Image</td></tr>"; while($row = mysql_fetch_array($result)) { echo "</td><td>"; echo $row['username']; echo "</td><td>"; echo $row['message']; echo "</td></tr>"; echo $row['image']; } echo "</table>"; ?> The error message I get is "Notice: Undefined index: image in....." Thanks in advance! hey i need help im tryig to get information from my user and then process it in my database so i can use it to log them to a different web site im trying to use this method to get the information from the user but need help to get it please help me. Code: [Select] //make the database connection. $conn = mysql_connect("localhost", "Black Jack"); mysql_select_db("chaper7", $conn); //create a query $sql = "SELECT * FROM hero"; $result = mysql_query($sql, $conn); On some occasions I need to connect to a second and third database in the same script (maybe 5% of scripts have at least a second connection). Usually I would just select the new database. However, my host requires different users to be created for each database. What is the best way to do this? Close current connection (say db1) and open new (say db2) OR keep all open, creating 2nd and 3rd connections. I am happy with the design of my database, and don't want to merge all these tables into one db. Overall I am still happy with my host, so I'd rather not change. <?php class UserQuery { public function Adduser($id,$username,$email,$password) { $conn = new Config(); $sql =("INSERT INTO test.user (id, username, email, password) VALUES ('$id', '$username', '$email',$password)"); $conn->exec($sql); } }
getting an "exec doesnt exist " error, saying exec doesnt exist in my db file. it doesnt need to exist does it ? anyone any idea why ?
Hey,
I'm really new to PHP and having some difficulties with $_SESSION and getting userid from the database. I've managed to put content to my database and also a login script. Though, adding sessions has been a pain. Here's what I got so far:
$sql = "SELECT username, password FROM users WHERE username = '$username' and password = '$pas'";
$query_login = $db->prepare($sql);
$query_login->execute(array('userid' => $userid, 'username' => $username, 'password' => $pas));
$result = $query_login->rowcount();
if ($result>0)
{
session_start();
$_SESSION['username'] = $username;
$_SESSION['logged'] = 1;
$_SESSION['userid'] = $result['userid'];
header('Location: ../user/user.php');
}
Hi guys, The Script:
pdo_connect.php:
<?php $dsn = "mysql:host=localhost;dbname=2354"; $db = new PDO($dsn, "root", ""); ?>pdo_test.php:
<?php
try{
require_once("pdo_connect.php");
}catch(Exception $e){
$error = $e->getMessage();
}
?>
<!DOCTYPE html>
<html>
<head>
<title>Database Connection with PDO</title>
</head>
<body>
<h1>Connection with PDO</h1>
<?php
if($db){
echo "<p>Connection successful.</p>";
}elseif(isset($error)){
echo "<p>$error</p>";
}
?>
</body>
</html>
I have just watched a tutorial and tried out this script. The issue is that I am getting the following notice alongside with the error message:
Notice: Undefined variable: db in C:\xampp\htdocs\oophp\pdo_test.php on line 18 SQLSTATE[HY000] [1049] Unknown database '2354'By the way this notice does happen in the tutorial as well. My question is: How to have this in ways, where the notice does not occur? Through out my program I have used global $mysqli; as a connection to my database - this has worked fine so far. Now I have called $sql_statement = "SELECT * FROM items WHERE name='$itemName'"; $itemStats = mysqli_fetch_array(mysqli_query($mysqli, $sql_statement), MYSQLI_ASSOC); via a function and I get the following warnings - Quote Warning: mysqli_query() expects parameter 1 to be mysqli, null given in /functions/getdata.php on line 27 Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, null given in /functions/getdata.php on line 27 it still works though and returns the correct information. If I take the code out of the function and use it normally then I get no Warnings - but this defeats the whole purpose of having functions! How do I get rid of the warnings? (and no, I don't mean turn the warnings off ) |
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