PHP - Replacing One Word For Entire Site Depending On The Url.

Hello everyone,

I have a general question about something that I've been thinking about doing but have not tried yet.  It involves including entire php pages rather than a short snippet of code.  Here's my situation:

I've created a website that caters to many different schools, each of which is assigned a sub-domain so that they have "their own" web site instead of going to one site and then clicking a link to get to their page.  Every site is identical with the exception of a few images.  The way I'm currently doing things is to upload every page of code into each folder the each website.  Doing it this way, I'm using a lot of disk space and each time I edit one page of code, I have to upload that page to every folder in my directory.  It's not too bad with only a few folders, but as more schools use my site, it could become a nightmare!

What I'm thinking about doing is to upload all my pages to the parent directory, then on each page in my folders for the sub-domains just include the corresponding page in the parent directory.  I will just keep the images for each sub-domain in the corresponding folder.  For example, the actual code for the index page in each of my sub-domain folders would be this:

Code: [Select]
<?php
include("../indexpage.inc.php");
?>


This way, I use less disk space and if I need to edit some code, I do it once, and upload it once to the parent directory, instead of having to upload it to each and every folder.

Does anyone see any problem with doing this?  Thanks for your opinion.

This topic has been moved to Apache HTTP Server.

http://www.phpfreaks.com/forums/index.php?topic=320065.0

Is it possible to extract all links from a website (not a single webpage) by php? I am asking about the general idea, as I wish to customize: e.g. from a specified directory and certain domains only.

Thanks 

I hate array...   😞

So I had a block of code inside my photo-gallery.php script that took the path to my photos directory, and went to that directory, and then read all of the photo filenames into an array.  Then in my HTML, I iterate through this array to display all of the photos for my gallery.

Now I would like to move that code to an included file so multiple scripts can access it and always be working with the same array.

It seems to me that I need to encapsulate my code inside a function?

Then I could call my getPhotoFilesArray back to my callings cript, and use that array for whatever.

I haven't coded PHP in like 4 years and I am struggling to return the entire array back to my caling script.

This is what I have so far...

	function getPhotoFilesArray($photoPath){
	     $photoFiles = array();
	     <code to find corresponding files>
	     $photoFiles gets populated in a loop
	     return $photoFiles;
	}
	

 

Then in my calling script, I have...

	<?php
	     require_once('../../../secure_outside_webroot/config.php');
	     require_once(WEB_ROOT . 'utilities/functions.php');
	     getPhotoFilesArray($photoPath);
	     var_dump($photoFiles);
	

 

I get some error...

	Notice: Undefined variable: phtoFiles in photo-gallery.php line 133 (which is my var_dump).
	

 

<br>

Would appreciate help getting this to work!

 

 

Edited December 6, 2019 by SaranacLake

When i pass entire url in a get variable as
 
http://www.example.com/index.php?url=http://www.yahoo.com/

I am getting the following error

Forbidden

You don't have permission to access /index.php on this server.

Additionally, a 404 Not Found error was encountered while trying to use an ErrorDocument to handle the request.

But there is no problem when i use the following

http://www.example.com/index.php?url=www.yahoo.com/
http://www.example.com/index.php?url=yahoo.com/
http://www.example.com/index.php?url=yahoo&value=1

I am getting "Forbidden-error" only when i include "http://"(even if it is urlencoded) in get variables.
Can any one help me...

I'm trying to find a way to back up an entire servers file through PHP. I have a script that can take selected files into a zip file but I'm not sure how to make sure that when I loop through directory and files that I get every single file.

I was thinking of just foreach(glob('*') as $file up to 10 times but I'm hoping there's something more definite then that method...

Thanks

Hello again,

I'm trying to scrape a table from another website using preg_match, especifically, using this code:
Code: [Select]
<?php 
$data = file_get_contents('http://tvcountdown.com/index.php');
$regex = '/[color=red]<table class="episode_list_table">[/color] (.+?) [color=red]</table>[/color]/';
preg_match($regex,$data,$match);
var_dump($match); 
echo $match[0];
?>
Heres the thing. It doesnt work   
I think it's because the first and second anchors are html tags, 'cause if I parse some other stuff without any tag, there's no problemo.

Any hints, mates?
Thanks

i hav dis checkstatus.php page where the user enters a random number sms to him..but after tht he shud be able to see d reply given by admin ..d problem over here is d user only views half of the field called 'anything'
(my database is named "proj")
heres my code
jst cant understand why dis is happening...pls help

This is my preg_match code: preg_match("/(\d+)|(T)|(A)/", $link, $matches, PREG_OFFSET_CAPTURE, ($off-30) It works and matches the number I want, except it only returns the first character in the $matches array. For instance, if the number it finds is 10, it only returns 1. Now I understand that is what preg_match does, but how would I make that regex ungreedy? I tried adding a *, but it just made an error, and preg match all would keep searching for strings after the first one. All I want is for the first number, regardless of the length of it, to be returned in full. Thanks for any help.

I actually asked a question here yesterday and decided to try a different route with it.  What I am doing is passing an email variable entered from my home page on to www.dollapal.com/offerlist.php.  I'm wanting this page to be a complete list of all of my entries in my surveys table.  The email variable needs to be appended to the end of every link.  I got that to work, but what I want to do now is display that information for every record in my 'surveys' table.

Right now I am using the random function, which I'm sure is wrong, but I'm not sure what function to be looking for.

Is it possible to use a foreach function here to echo each record?  If so, I'm not sure how exactly to call the foreach() function in this case.

I believe my two problems lie in the random and foreach functions, but I'm not sure how to correct them.  I've attached a little chunk of code that I'm working with.  I'm not sure if I'm completely off base here, or if I'm close to achieving my desired result.  Please let me know if you require more information.

This forum has been amazing to me so far.  Thank you all for your help!

Please help.  I am trying to replace parenthesises () in a string with <>.  I tried preg_replace and str_replace, but was not success.

Here is what I have for str_replace:
$word = "(test)";

$word = str_replace('(', '<', $word);

$word = str_replace(array('(', ')'), array('<','>'), $word);

 

hi freaks,

still working on my email bot.
im currently trying to escape <>-tags to be displayed- but not the browser wont exectute it (i.e. xls-tags) i want them as chars.

so whin my
$content is like <xsl:stylesheet> <xsl:template match="/"> <more xls...> it shows a stylesheet.
i just want the chars.

Here is what ive been trying so far: but its bad

Code: [Select]
<?php

$string='<tag> > < asdasf';

$bomb=array(
'<',
'>',
);
$defusal=array(
'-',
'!',
);
$string= preg_replace($bomb,$defusal,$string);
echo $string;
?>

error:
Warning: preg_replace() [function.preg-replace]: No ending matching delimiter '>' found in C:\xampp1\htdocs\code.php on line 13

donno any further now

Hey guys, I have a quick question.

Im going to be making a script that will output the name of a news article along with the poster's name beside it.

There is only a certain amount of space where that stuff can go so I want to know how I can make it so that say after 20 characters, it ends and puts "..." beside it.

Is this possible with php? How would I do it?

Hello,

Is str_replace the best way to go about this?

In MYSQL, a html template is stored, such that:

Quote

<table width="{$width}">lots of other ........</table>


This is extract from the database, and stored in a string. I would use eval(), but, any user can update this template, so I need to be able to set which variables will be replaced with what the variable is.

Thanks!