PHP - How To Url Link To Files Outside Of Webroot
So i have a file uploader that allows people to upload files to the server and then download them via a URL.
I want to store uploaded files outside of the Root. (One level up from the root in a folder called Uploads) Code snippet Code: [Select] $server = "http://www.mysite.com"; $name = $_FILES['file']['name']; $temp = $_FILES['file']['tmp_name']; $size = $_FILES['file']['size']; $destination = '../uploads/'. $random; mkdir($destination); move_uploaded_file($temp, $destination."/".$name); $final = $server."/".$destination."/".$name; This... Code: [Select] $destination = '../uploads/' . $random ; Didn't work, any tips? Similar TutorialsI know basically nothing about PHP but i have a few websites i manage that are built with PHP. I plan to learn PHP but for the time being learning Javascript has a wider range of usability for me. That being said, Im trying to link to an XML sitemap using php. in html i would use Code: [Select] <link href="sitemap.xml" /> how can i do this in PHP? I have searched google and such for how to do this but was unable to find an explanation that i could understand as relating to my need. So say i have this: Code: [Select] <link rel="stylesheet" media="all" type="text/css" href="_css/styles.css" /> now the file that is linking to that is 3 directories deep, besides using a rel or absolute link, could i define the path by using something like this Code: [Select] <link rel="stylesheet" href="<?php require($_SERVER['DOCUMENT_ROOT'] . "/_css/portfolio-styles.css"); ?>" type="text/css" /> but this is actually opening the CSS in the header thanks for any explanation on how to do this So far I have managed to create an upload process which uploads a picture, updates the database on file location and then tries to upload the db a 2nd time to update the Thumbnails file location (i tried updating the thumbnails location in one go and for some reason this causes failure) But the main problem is that it doesn't upload some files Here is my upload.php <?php include 'dbconnect.php'; $statusMsg = ''; $Title = $conn -> real_escape_string($_POST['Title']) ; $BodyText = $conn -> real_escape_string($_POST['ThreadBody']) ; // File upload path $targetDir = "upload/"; $fileName = basename($_FILES["file"]["name"]); $targetFilePath = $targetDir . $fileName; $fileType = pathinfo($targetFilePath,PATHINFO_EXTENSION); $Thumbnail = "upload/Thumbnails/'$fileName'"; if(isset($_POST["submit"]) && !empty($_FILES["file"]["name"])){ // Allow certain file formats $allowTypes = array('jpg','png','jpeg','gif','pdf', "webm", "mp4"); if(in_array($fileType, $allowTypes)){ // Upload file to server if(move_uploaded_file($_FILES["file"]["tmp_name"], $targetFilePath)){ // Insert image file name into database $insert = $conn->query("INSERT into Threads (Title, ThreadBody, filename) VALUES ('$Title', '$BodyText', '$fileName')"); if($insert){ $statusMsg = "The file ".$fileName. " has been uploaded successfully."; $targetFilePathArg = escapeshellarg($targetFilePath); $output=null; $retval=null; //exec("convert $targetFilePathArg -resize 300x200 ./upload/Thumbnails/'$fileName'", $output, $retval); exec("convert $targetFilePathArg -resize 200x200 $Thumbnail", $output, $retval); echo "REturned with status $retval and output:\n" ; if ($retval == null) { echo "Retval is null\n" ; echo "Thumbnail equals $Thumbnail\n" ; } }else{ $statusMsg = "File upload failed, please try again."; } }else{ $statusMsg = "Sorry, there was an error uploading your file."; } }else{ $statusMsg = 'Sorry, only JPG, JPEG, PNG, GIF, mp4, webm & PDF files are allowed to upload.'; } }else{ $statusMsg = 'Please select a file to upload.'; } //Update SQL db by setting the thumbnail column to equal $Thumbnail $update = $conn->query("update Threads set thumbnail = '$Thumbnail' where filename = '$fileName'"); if($update){ $statusMsg = "Updated the thumbnail to sql correctly."; echo $statusMsg ; } else { echo "\n Failed to update Thumbnail. Thumbnail equals $Thumbnail" ; } // Display status message echo $statusMsg; ?> And this does work on most files however it is not working on a 9.9mb png fileĀ which is named "test.png" I tested on another 3.3 mb gif file and that failed too? For some reason it returns the following Updated the thumbnail to sql correctly.Updated the thumbnail to sql correctly. Whereas on the files it works on it returns REturned with status 0 and output: Retval is null Thumbnail equals upload/Thumbnails/'rainbow-trh-stache.gif' Failed to update Thumbnail. Thumbnail equals upload/Thumbnails/'rainbow-trh-stache.gif'The file rainbow-trh-stache.gif has been uploaded successfully. Any idea on why this is? Hello I have a simple question about file handling... Is it possible to list all files in directories / subdirectories, and then read ALL files in those dirs, and put the content of their file into an array? Like this: array: [SomePath/test.php] = "All In this php file is being read by a new smart function!"; [SomePath/Weird/hello.txt = "Hello world. This is me and im just trying to get some help!";and so on, until no further files exists in that rootdir. All my attempts went totally crazy and none of them works... therefore i need to ask you for help. Do you have any ideas how to do this? If so, how can I be able to do it? Thanks in Advance, pros I am using WPSQT plugin in my blog site .I code some files in PHP also.how to add that files in plugin files.
Hello.
I have a bit of a problem. When I fetch the link field from the database.i don't see an actual link on the page.
One more thing, what type of field should I use to store the link in the database? Probably there is where I went wrong.
All help is
Hi I've got this database I created with fields ProductId ProductName Image I've managed to get it to list the ID,productname, and Image urls in a list. My next step is to have the image field actually display an image and make it clickable: heres what I've done so far: Code: [Select] <?php $con = mysql_connect("localhost","root",""); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("productfeed", $con); $result = mysql_query("SELECT * FROM productfeeds"); echo "<table border='0'> <tr> <th>Firstname</th> <th>Lastname</th> <th>Image</th> </tr>"; while($row = mysql_fetch_array($result)) { echo "<tr>"; echo "<td>" . $row['ProductID'] . "</td>"; echo "<td>" . $row['ProductName'] . "</td>"; echo "<td>" . $row['ImageURL'] . "</td>"; echo "</tr>"; } echo "</table>"; mysql_close($con); ?> Heres what I want to do: Code: [Select] while($row = mysql_fetch_array($result)) { echo "<tr>"; echo "<td>" . $row['ProductID'] . "</td>"; echo "<td>" . $row['ProductName'] . "</td>"; // my changes beneath echo "<td>" . <a href="<?php echo $row['ImageURL'];?>"> <img src="<?php echo $row['LinkURL']; ?>"> </a>. "</td>"; echo "</tr>"; } echo "</table>"; mysql_close($con); ?> Can you guys point me in the right direction? Many thanks Hi Support, I have a form, where it collects user description input. I can collect the inputs and store it with newline. The issue is - how to collect the http link to actual hyperlink ref during display. The following is my code: <textarea name="description" cols="50" rows="10" id="description"><?php echo str_replace("<br>", "\n", $description);?></textarea></td> For example, User input: Hi, Check it out - http://www.google.com/ I would like to display google link as href so that Viewers can click the link and go to the page. Right now, it is not href and user need to copy the link to new tabs or pages and then it can come. Thanks for your help. Regards, Ahsan hi hope you all are fine. i have been working on a Email Form (like user fills up the form which send the information to our email) but i was having problem with (URL field i created) link of form is (http://services.shadowaura.com/allquotations/static.php) field which is not working is "Inspirational Website:" when i submit the form it says (Forbidden You don't have permission to access /allquotations/staticworking.php on this server. Additionally, a 404 Not Found error was encountered while trying to use an ErrorDocument to handle the request.) Can some one help me out ????????????? code behind this form is: Code: [Select] <?php /* Email Variables */ $emailSubject = 'Shadow Aura Contact Info!'; $webMaster = '*****@shadowaura.com'; /* Data Variables */ $Name = $_POST['Name']; $email = $_POST['email']; $Cell = $_POST['Cell']; $Phone = $_POST['Phone']; $CompanyName = $_POST['CompanyName']; $TypeOfBusiness = $_POST['TypeOfBusiness']; $Address = $_POST['Address']; $YourBudget = $_POST['YourBudget']; $HaveDomain = $_POST['HaveDomain']; $RunningWeb = $_POST['RunningWeb']; $WebLink = $_POST['WebLink']; $Inspiration1 = $_POST['Inspiration1']; $Inspiration2 = $_POST['Inspiration2']; $NumberPages = $_POST['NumberPages']; $UseFlash = $_POST['UseFlash']; $TimeFrame = $_POST['TimeFrame']; $Provided = $_POST['Provided']; $Comments = $_POST['Comments']; $body = <<<EOD <h1> Static Website Quotation </h1> <br> <b>Name of Client:</b>$Name<br> <b>Your Email:</b>$email<br> <b>Cell Number:</b>$Cell<br> <b>Line Phone Number:</b>$Phone<br> <b>Company Name:</b>$CompanyName<br> <b>Type of Business:</b>$TypeOfBusiness<br> <b>Address:</b>$Address<br> <b>Your Budget:</b>$YourBudget <br> <b>Do you have Domain:</b>$HaveDomain<br> <b>Your Site is Running:</b>$RunningWeb <br> <b>Website Link:</b><a href="$WebLink">$WebLink</a><br> <b>Inspiration:</b>$Inspiration1<br> <b>2nd Inspiration:</b>$Inspiration2<br> <b>Number of Pages:</b>$NumberPages<br> <b>Use Flash:</b>$UseFlash <br> <b>Time Frame:</b>$TimeFrame<br> <b>You will provide:</b>$Provided<br> <b>Comments:</b>$Comments<br> EOD; $headers = "From: $email\r\n"; $headers .= "Content-type: text/html\r\n"; $success = mail($webMaster, $emailSubject, $body, $headers); /* Results rendered as HTML */ $theResults = <<<EOD <html> <head> <title>sent message</title> <meta http-equiv="refresh" content="3;URL=http://services.shadowaura.com/"> <style type="text/css"> <!-- body { background-color: #8CC640; font-family: Verdana, Arial, Helvetica, sans-serif; font-size: 20px; font-style: normal; line-height: normal; font-weight: normal; color: #fec001; text-decoration: none; padding-top: 200px; margin-left: 150px; width: 800px; } --> </style> </head> <div align="center">Your email will be answered soon as possible! You will return to <b>Shadow Aura Services</b> in a few seconds !</div> </div> </body> </html> EOD; echo "$theResults"; ?> here's my code that i've used to send an email. Code: [Select] $link = "<a href=\"http://www.example.com/" . $num . "\">" . $num . "</a>"; $query = "SELECT content FROM emails"; $result = mysql_query($query) or die(); $email_content = mysql_result($result, 0); $email = sprintf($email_content, $first, $name, $from, $link, $record, $rec, $inc, $max); $email_body = stripslashes(htmlentities($email, ENT_QUOTES, 'UTF-8')); // this is sent to another php script via post.... $subject = $_POST['subject']; $message = nl2br(html_entity_decode($_POST['email_body'])); $to = "me@whatever.com"; $charset='UTF-8'; $encoded_subject="=?$charset?B?" . base64_encode($subject) . "?=\n"; $headers="From: " . $userEmail . "\n" . "Content-Type: text/html; charset=$charset; format=flowed\n" . "MIME-Version: 1.0\n" . "Content-Transfer-Encoding: 8bit\n" . "X-Mailer: PHP\n"; mail($to,$encoded_subject,$message,$headers); in the db, emails.content is of the text type and contains several lines of text with %4$s which inserts the value of $link into the body. when the email arrives, there is a link and it appears fine, with the value of $num hyperlinked. however when you click on it it doesn't go anywhere. when copying the link location from the email it gives me x-msg://87/%22http://www.example.com/16 what is x-msg? how can i get this to work properly? Hi guys, I'm using a twitter script that grabs the title and publishings it like so: "Title - Read More at..." I was wondering how i would be able to post the direct link into twitter.. like news.php?id=1 for example. Code: [Select] $tweet->post('statuses/update', array('status' => ''.$_POST[title].' - more at MY URL')); This part is in the script to publish automatically when the users adds to the news database. How am i able to get the ID just after the posting of the news? Thanks! I have a line like this it prints text link but I prefer image link how should i edit it I would appreciate some feedback Code: [Select] $templates['etiket'] = array('name' => t('ETİKET'), 'module' => 'uc_invoice_pdf', 'path' => $templates_uc_invoice_pdf_path, 'pdf_settings' => $pdf_settings); lets say I own a file, and you own a file, both these files are the exact same file, the only difference is the filename. So lets say we both have The Gimp 2.6 but one is named TG2.6.exe and the other is named the_Gimp-2.6.exe. What would be the best way to count the files that are the same even if they have a different file name? Another example would be: I have a file called me.jpg and someone else has a file me.jpg but they are two completely different pictures. What would I do to tell that? I have told that the php files I was working on contains BOM by default cause of the editor I m using. I have installed other editor that can create php files without BOM. So my question is what's the difference between 2 files, one with BOM and other without BOM ? Any problems I may face for long term usage ? Which one is better to use ? Hey, Trying to learn to generate PDF files, something apparently WAAAAYYY more complex than I thought. Can someone please give me an explanation on '$optlist' from this function..... PDF_load_image ( resource $pdfdoc , string $imagetype , string $filename , string $optlist ) What is it? PHP.net doesn't have any info at all. Thanks, IceKat. BTW - Any (recent) tutorials or pages would be appreciated. Everything I find is out of date or doesn't work. first of all...its good to see the site back .
my question guys is i'm wondering is there a way of getting the column number when reading a .cvs file?
ie. a, b, c, d, aa, ab etc?
$row = 1; if (($handle = fopen($file, "r")) !== FALSE) { while (($data = fgetcsv($handle, 1000, ",")) !== FALSE) { $num = count($data); echo "<p> $num fields in line $row: <br /></p>\n"; $row++; for ($c=0; $c < $num; $c++) { //echo $data[$c] . "<br />\n"; } } fclose($handle); }now $num counts the columns...but i want to convert that into a alphabetical column...is there a easy solution? thanks guys I have a small form which executes a php file, and the executable php file. is there anyway to have it just using the 1 php file? form code: Code: [Select] <form enctype="multipart/form-data" action="upload-exec.php" method="POST"> Please choose a file: <input name="uploaded" type="file" /><br /> <input type="submit" value="Upload" /> </form> uploader.php Code: [Select] <?php $target = "upload/"; $target = $target . basename( $_FILES['uploaded']['name']) ; $ok=1; //This is our size condition if ($uploaded_size > 350000) { echo "Your file is too large.<br>"; $ok=0; } //This is our limit file type condition if ($uploaded_type =="text/php") { echo "No PHP files<br>"; $ok=0; } //Here we check that $ok was not set to 0 by an error if ($ok==0) { Echo "Sorry your file was not uploaded"; } //If everything is ok we try to upload it else { if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target)) { echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded"; } else { echo "Sorry, there was a problem uploading your file."; } } ?> i did try using: Code: [Select] if (isset($_POST['submit'])) { with no luck. Many thanks Hi, I have a script which uses a connect file but I am struggling to get files in other folders to read and for the "$loggedIn = checkLogin();" code to work. If I connect to the database within the same script it works straight away. If I change my password then I have to change every file but otherwise I cannot include the connect file as I have to link to it locally. So if the connect file is in: www.domain.co.uk/php/login/connect.php then www.domain.co.uk/php/login/index.php -- this works www.domain.co.uk/php/logout.php -- this doesn't regardless of how I link to the connect file. Hi, (Just wanna say thanks to the guy who helped me earlier as i cannot find the topic) I have a game, it has 3 frames, menu, header & the main content, it WAS fine until i deleted a 4th frame, now when i click a link from the menu, instead of showing the link in the 'Main' content area, it takes you to the actual page with no menu, header etc. Thanks in advance! Can you include a file and append info to be grabbed by using GET? For example, can you have an include file like this... Code: [Select] include('file.php?id=1'); And then in the file "file.php" I would use $_GET['id'] to do other things in the code. I tried it and it's not working. I'm getting this error... "Warning: include(file.php?id=1) [function.include]: failed to open stream: No such file or directory in..." Just want to find out if this should be doable before I continue testing why it's not working for me. If it should work, should I be using something other than include maybe? (like require or require_once?) |