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PHP - Find The Min Price From Database Array
I have a list of products in database and some have the same itemid but a different price depending on size
What i want to do i if the itemid has more than one size, take the smallest price and then add the word "From" at the beginning. I've tried using the MIN() function but can't get it to do what i want. If there is only one size it works fine but if there is more than one it just says "From 0.00" Code: [Select] while ($row = $result->fetch()) { if(!isset($items[$row['itemid']])) { $items[$row['itemid']] = $row; } $items[$row['itemid']]['sizes'][$row['size']] = $row['price']; ### CHANGED ### } foreach($items AS $subitem) { list($prodid, $itemid, $item, $size, $description, $shortdesc, $image, $price) = $subitem; //Create field for item name based upon record count if(count($subitem['sizes']) > 1) { /*$item_name_field = "<ul>\n"; foreach($subitem['sizes'] as $size => $price) ### CHANGED ### {*/ //} //$item_name_field .= "<ul>\n"; $myprice = explode(".",number_format(min($subitem['price']),2)); $item_name_field .= "<li>From ".$myprice[0].".".$myprice[1]." {$size}</li>\n"; } else { $myprice = explode(".",number_format($subitem['price'],2)); $item_name_field .= "<li><span class=\"ucprice\">£".$myprice[0]."<?span><span class=\"lcprice\">.".$myprice[1]."</span></li>\n"; } Similar TutorialsSay I have two functions that convert from Dollar to Cents and Cents to Dollar.
function convertToDollar($value) {
$amount = $value / 100;
return $amount;
}
function convertToCents($value) {
$amount = $value * 100;
return $amount;
}
Currently I convert all the Dollar amounts to cents and store the cents in the mysql database column. When I showcase those amounts on a page, I simply convert the Cents back to Dollar. Am I doing this correctly or is there a better way to store product pricing in mysql table? I am currently building (for my first time) a shoppingcart. Its an multidimensional array in a session that looks like this. Code: [Select] Array ( [23] => Array ( [0] => 23 [1] => 11.32.097. [2] => 635 [3] => 2 [4] => 89 ) [800] => Array ( [0] => 800 [1] => 20.40.017. [2] => 100 [3] => 1 [4] => 125 ) ) The 4th key contains the price value. What i am trying to do is get all the sub-array's 4th key value and count them together to get a total price. I tried doing this with a foreach loop but its not my strong point, sadly. I you have some time can you please take a look how to solve this? Thanks in advance, Roy This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=343372.0 Say i have an array (called $myarray) and it has 10 numbers in it like this... 1 2 4 8 9 10 12 14 15 18 Now in my code, I get a number and lets say for this example it is "5". I need to see if that number is in the array --easy enough using in_array()--, but if it is NOT in the array, I need to find the next available number in the array that is greater than my starting number of 5 (which would be "8" in this example). But what is the best way to find this number (i.e. 8 in this example)? I imagine I need to somehow loop through but i'm not sure which loop is the best to use and i'm generally confusing the hell out of myself (which is frustrating because this is probably rather simple to do ). Can anyone help guide me in the right direction? I'm sure this is possible, but I'm not having any luck. Code: [Select] $array = array("11:23", "12:46", "13:34", "14:34", "14:85"); if (in_array('12', $array)) { echo "yes"; } else { echo "no"; }} Hi all, i have this array $str = array("apple is red", "banana is yellow", "pineaple is tropical fruit", "coconut is also tropical fruit", "grape is violet"); i want to find string "coconut" inside $str and put the whole string "coconut is also tropical fruit" into variable $coconut. can i do this? i don't want to use the this code Code: [Select] <? $coconut = $str[3]; echo "$coconut"; ?> can someone help? Thank you, Best Regards Good Evening, I'm having no luck in something that I'm sure is incredibly simply... If I have an array like the following... Code: [Select] $array = array(15,22,0,43,0,6);How can I find and replace all the zeros with a one? Regards, Ace I need help this problem seem too tricky for me right now. I got an array with decimal numbers and behind it says Yes/No. The min() function works magically and still is able to correctly give me the lowest value. But how do i make a while loop that loops until it pops a value that is lowest and has Yes behind it? For example: Array => ('11,64|No', '209,81|Yes', '533,42|Yes', '27,90|No', '93,01|Yes') So this function should return '93,01|Yes' I need to find the earliest and latest times, but there must be at least 3 to count it. $array[] = "09:00 - 15:00" $array[] = "09:00 - 15:00" $array[] = "09:00 - 15:00" $array[] = "09:00 - 17:00" $array[] = "09:00 - 15:30" $array[] = "07:30 - 15:00" $array[] = "07:00 - 12:00" So the above would return 09:00 - 15:00 I thin would need to ensure that a maximum 4 hours inbetween, so I then get something like 10:00 - 14:00 returned okay I am using a jquery plugin to re-arrange images which are in mysql and they have their own "order_number" ... when i re-arrange stuff the new order is put into a hidden field in a form and i have it along with another hidden field with their current order... when submitted I combine these two fields in an array so the key is the original order and the value is the new order ....i have 12 images... Array ( [1] => 1 [2] => 2 [3] => 3 [4] => 4 [5] => 5 [6] => 6 [7] => 7 [8] => 8 [9] => 9 [10] => 10 [11] => 11 [12] => 12 ) this is what is what the array looks like... i have a foreach loop with a mysql query but things get kind of weird when you try to do it this way $num = $_POST['old_num']; $num = unserialize($num); $sort = $_POST['sortOrder']; $sort = explode(',', $sort); if ($_POST){ $combine = array_combine($num, $sort); foreach($combine as $key => $value){ mysql_query("UPDATE shirts SET order_number='$value' WHERE order_number='$key' ") or die(mysql_error()); } when you do this lets say for example we have the image with order number "1" get switched with the image order number "2"..... the database first updates with number 1 which becomes 2... then when it goes to number "2"... at this point... the first image gets switched back to number 1.... so 1 becomes 2 then the new 2 becomes 1 again and the other 2 becomes 1 also. I can not think of another way I could update mysql with the correct order numbers... If anyone has any ideas or other solutions I am open to all suggestions... thank you! Hi I am trying to search an array that comes from a power shell script, the array of strings that returns is ever changing as it receives variables from the script. Therefore I need to use preg_grep to search for the word "not" I am also using another array which inverts this I then need to compare these new two arrays to the original and separate the results $working and not working into a table. I would be most grateful for any advice/solutions. The preg_grep aren't displaying anything.
<?php
//phpinfo();
ini_set('display_errors', 'On');
error_reporting(0);//E_ALL
echo '<html>
<style>
body
{
font-family:Calibri,Helvetica,sans-serif;
font-size:100%;
}
</style>
<head>
<link rel="stylesheet" type="text/css" href="style.css">
<script type="text/javascript">
function uploadJS(){
String.prototype.trim = function() { return this.replace(/^\s+|\s+$/g, ""); };
var textAreaValue=document.getElementById(\'ServerList\').value;
var trimmedTextAreaValue=textAreaValue.trim();
if(trimmedTextAreaValue!="") {
document.myForm.submit();
} else{
alert("Server List Text Area is Empty");
}
};
var input=document.getElementById(\'fileSelect\').value;
if(input!="") {
document.myForm.submit();
} else{
alert("You have not selected a file, please select one to proceed.");
}
var handleFileSelect = function(e) {
var files = e.target.files;
if(files.length === 1) {
document.forms.myForm.filecsv.value = files[0].name;
}
}
};
</script>
</head>';
#Upload Code
$target = "D:\Web\Upload/";
$target = $target . basename( $_FILES['uploaded']['name']) ;
$ok=1;
if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target))
{
echo "The file ". basename( $_FILES['uploadedfile']['name']). "
has been uploaded";
}
else {
}
if ($uploaded_size > 150000)
{ echo "Your file is too large.<br>";
$ok=0;
}
if ($uploaded_type =="text/php")
{
echo "No PHP files<br>";
$ok=0;
}
if (!($uploaded_type=="text/csv")) { echo "<br>";
$ok=0;
}
$target = "upload/"; $target = $target . basename( $_FILES['uploaded']['name']) ; $ok=1; //This is our size condition
if ($uploaded_size > 350000)
{
echo "Your file is too large.<br>";
$ok=0;
}
//This is our limit file type condition
if ($uploaded_type =="text/php")
{ echo "No PHP files<br>";
$ok=0;
}
//Here we check that $ok was not set to 0 by an error
if ($ok==0)
{
}
//If everything is ok we try to upload it
else {
if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target))
{
echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded";
} else
{
}
}
#Start of scripts to check Servers in textbox
if(isset($_POST['ServerList']))
{
//$arry=explode( "\r\n", $_POST['ServerList'] );
$txttrim = trim($_POST['ServerList']);
//$textAr = explode("\n", $text);
//$textAr1 = array_filter($text, 'trim'); // remove any extra \r characters left behind
$txtarea = explode("\n",$txttrim);
$txtarea = array_filter($txtarea,'trim');
foreach ($txtarea as $line => $servername)
{
//$line => $servername;
##check if querying itself....
}
echo '<pre>';
$target="D:/Web/Upload/"; $target= $target . basename( $_FILES['uploaded']['name']) ;
$csv = $target;
//$filename= $_FILES['uploaded']['name'];
$output=shell_exec("powershell -Command D:/Web/scripts/PHPfwrules.ps1 $csv < NUL");
echo '<h6>';
print_r($output);
$nomatch=preg_grep('/^not/i',$output);
echo $nomatch;
$match=preg_grep("/not/",$output,PREG_GREP_INVERT);
echo $match;
if ($working1= array_intersect($output,$match))
{
echo"<link rel=stylesheet type=text/css href=style.css>
<table class=results>
<tr>
<th>Server Name</th>
<th>Working</th>
</tr>
<tr>
<td>".$servername."</td>
<td>".$working1."</td>
</tr></table>
";
}
else if ($notworking1= array_intersect($output,$nomatch))
{
echo"<link rel=stylesheet type=text/css href=style.css>
<table class=results>
<tr>
<th>Server Name</th>
<th>Not Working</th>
</tr>
<tr>
<td>".$servername."</td>
<td>".$notworking1."</td>
</tr></table>
";
}
}
echo' <link rel=stylesheet href=dhtmlwindow.css type=text/css />
<link rel=stylesheet type=text/css href=style.css>
<script src=js/dhtmlwindow.js></script>
<hr />
<table class=results>
<tr>
<th>Server Name</th>
<th>Working</th>
<th> Not Working</th>
</tr>
<tr>
<td>'.$servername.'</td>
<td>'.$working1.'</td>
<td>'.$notworking1.'</td>
<td></td>
';
echo '</pre>';
echo '
<h3>Firewall Implementation </h3>
<h4>Please enter the server below, you can only select one server at a time. </h4>
<!--The form-->
<form action="fw2.php" method="post" name="myForm" id="myForm" enctype="multipart/form-data">
<textarea name=ServerList id=ServerList>
</textarea>
<h5>Please select a CSV file.</h5>
<input name="uploaded" type="file" /><br />
<input type="submit" value="Submit" />
<br>
</html> '
;
?>
Hi all, This is a piece of code of my php page and what I need is that $n1 till $n4 is filled. Somehow only $n1 is filled. Can anyone tell me what I'm doing wrong here. Thnx Ryflex $sql = "SELECT name FROM unittype WHERE type = 1"; $result = mysql_fetch_array(mysql_query($sql)) or die("Could not find units"); $n1 = $result[0]; $n2 = $result[1]; $n3 = $result[2]; $n4 = $result[3]; echo "$n1 <BR> $n2 <BR> $n3 <BR> $n4"; I'm trying to figure out how to post an array into my database. I am able to post single entries without a problem, but trying to post several entries at once is causing me some headaches. Can anyone check this code and hopefully give me some insight as to where I'm going wrong? Here's the form: Code: [Select] <?php include("opendatabase.php"); ?> <FORM Method = "POST" action ="insert_spreads.php"> <?php $weekID = $_POST[Week]; echo "<h2>Enter Spreads for Week $weekID</h2>"; print ("<br /><br />"); $result = mysql_query(" SELECT S.game_id, TH.team_name AS HomeTeam, TA.team_name AS AwayTeam FROM schedule AS S JOIN teams AS TH ON S.H_team = TH.team_id JOIN teams AS TA ON S.A_team = TA.team_id WHERE S.week_id = '$weekID' ORDER BY S.game_id;"); while ($row = mysql_fetch_array($result)) { printf('<input type="text" size="4" name="w%dg%dAspread">', $weekID, $row['game_id']); printf(" %s vs. %s ", $row['AwayTeam'], $row['HomeTeam']); printf('<input type="text" size="4" name="w%dg%dHspread">', $weekID, $row['game_id']); print("<br /><br />"); } mysql_close($con); ?> <br /><br /> <input type="Submit" value="Submit Spreads"> </FORM> And here's the "insert_spreads.php Code: [Select] <?php header("Location: admin_main_entry.php"); include("opendatabase.php"); $aspread=$_POST['w%dg%dAspread']; $hspread=$_POST['w%dg%dHspread']; $row=$_POST[$row['game_id']; $sql=" UPDATE schedule SET A_pt_spread= '$aspread',H_pt_spread= '$hspread' WHERE week_id = '$weekID' AND game_id = '$row'"; $result = mysql_query($sql); mysql_close($con) ?> Thanks! Hi Guys I was just wondering if their is a function to randomize an array pulled from database is it possible i know their is array_rand() but it doesnt seem to work for me can someone show me where i am going wrong or do i have to do it from the actual SELECT statemant i.e ORDER_RAND(); ? Here is what my array prints out. $user_list = get_users_by_specialism($specialism); print_r($user_list); outputs. Array ( [0] => 129 [1] => 46 [2] => 57 [3] => 109 [4] => 92 [5] => 137 [6] => 238 [7] => 101 [8] => 60 [9] => 90 [10] => 112 [11] => 133 [12] => 121 [13] => 220 [14] => 275 [15] => 278 ) I basically need to make this array output in a random order everytime not by ID incrementing. Any help Please Cheers. Hi I was just wondering would it be possible to create a database from a input statement and array, if so would it be also possible to create a table with fields the same way? There is a "PHP ajax cascading dropdown using MySql" at codestips.com/php-ajax-cascading-dropdown-using-mysql/ I want to use this technique but with a XML or array file instead of mysql database, but my knowledge about mysql is very low. How I can modify this code to catch the categories and products from an array, instead of mysql database? Code: [Select] $connect=mysql_connect($server, $db_user, $db_pass) or die ("Mysql connecting error"); echo '<table align="center"><tr><td><center><form method="post" action="">Category:<select name="category" onChange="CategoryGrab('."'".'ajaxcalling.php?idCat='."'".'+this.value);">'; $result = mysql_db_query($database, "SELECT * FROM Categories"); $nr=0; while($row = mysql_fetch_array($result, MYSQL_ASSOC)) { $nr++; echo "<option value=".'"'.$row['ID'].'" >'.$row['Name']."</option>"; } echo '</select>'."\n"; echo '<div id="details">Details:<select name="details" width="100" >'; $result = mysql_db_query($database, "SELECT * FROM CategoriesDetails WHERE CategoryID=1"); while($row = mysql_fetch_array($result, MYSQL_ASSOC)) { echo "<option value=".$row['ID'].">".$row['Name']."</option>"; } echo '</select></div>'; echo '</form></td></tr></table>'; mysql_close($connect); ajaxcalling.php is Code: [Select] include("config.php"); $ID=$_REQUEST['idCat']; $connect=mysql_connect($server, $db_user, $db_pass); echo 'Details:<select name="details" width="100">'; $result = mysql_db_query($database, "SELECT * FROM CategoriesDetails WHERE CategoryID=".$ID); while($row = mysql_fetch_array($result, MYSQL_ASSOC)) { echo "<option value=".$row['ID'].">".$row['Name']."</option>"; } echo '</select>'; mysql_close($connect); Hello all! I'm having a problem inserting an array into my database. My database is connected when I run the script but my table isn't being populated. Please help! Here's my table structure followed by the php: CREATE TABLE `demographic` ( `uid` bigint(20) unsigned NOT NULL, `first_name` varchar(50) default NULL, `last_name` varchar(50) default NULL, `email` varchar(200) default NULL, `link` varchar(255) default NULL, `affiliations` varchar(255) default NULL, `birthday` varchar(50) default NULL, `current_location` varchar(200) default NULL, `education_history` varchar(500) default NULL, `work` mediumtext, `hometown_location` varchar(400) default NULL, `interests` varchar(200) default NULL, `locale` varchar(50) default NULL, `movies` varchar(500) default NULL, `music` varchar(500) default NULL, `political` varchar(200) default NULL, `relationship_status` varchar(100) default NULL, `sex` varchar(10) default NULL, `tv` varchar(200) default NULL, `status` tinyint(4) default NULL, `created` datetime default NULL, `updated` datetime default NULL, PRIMARY KEY (`uid`) ) ENGINE=InnoDB DEFAULT CHARSET=utf8; <?php $link = mysql_connect('host', 'user', 'pass'); if (!$link) { die('Could not connect: ' . mysql_error()); } $db_selected = mysql_select_db('database'); if (!$db_selected) { die ('Can\'t use beta : ' . mysql_error()); } echo 'Connected successfully'; mysql_close($link); include_once "fbmain.php"; $config['baseurl'] = "baseurl"; //if user is logged in and session is valid. if ($fbme){ //collect some data using legacy api $param = array( 'method' => 'users.getinfo', 'uids' => $fbme['id'], 'fields' => 'birthday_date, interests, locale, political, relationship_status, affiliations', 'callback' => '' ); try{ $info = $facebook->api($param); } catch(Exception $o){ error_log("Legacy Api Calling Error!"); } //using graph api //array data $workInfo = getWorkInfoAsString($fbme); $education = getEducationAsString($fbme); $moviesArr = $facebook->api("/me/movies"); $musicArr = $facebook->api("/me/music"); $televisionArr = $facebook->api("/me/television"); //format some api data $movies = getArrayDataAsString($moviesArr['data']); $music = getArrayDataAsString($musicArr['data']); $television = getArrayDataAsString($televisionArr['data']); //data from legacy api $networks = ''; if (!empty($info[0]['affiliations'])){ $flag = true; foreach ($info[0]['affiliations'] as $item){ if (!$flag) $networks.= ' # '; $networks .= $item['name']; $flag = false; } } $now = date("Y-m-d G:i:s"); $insData = array( 'uid' => $fbme['id'], 'first_name' => $fbme['first_name'], 'last_name' => $fbme['last_name'], 'email' => isset($fbme['email']) ? $fbme['email'] : '', 'link' => $fbme['link'], 'affiliations' => $networks, 'birthday' => $info[0]['birthday_date'], 'current_location' => isset($fbme['location']['name']) ? $fbme['location']['name'] : '', 'education_history' => $education, 'work' => $workInfo, 'hometown_location' => isset($fbme['hometown']['name']) ? $fbme['hometown']['name'] : '', 'interests' => $info[0]['interests'], 'locale' => $info[0]['locale'], 'movies' => $movies, 'music' => $music, 'political' => $info[0]['political'], 'relationship_status' => $info[0]['relationship_status'], 'sex' => isset($fbme['gender']) ? $fbme['gender'] : '', 'tv' => $television, 'status' => '0', 'created' => $now, 'updated' => $now, ); $this->db->insert('demographic', $insData); } function getWorkInfoAsString($fbme, $delim = '#', $partDelim = ' | '){ $info = ""; $flag = false; if (empty($fbme['work'])) return ''; foreach($fbme['work'] as $item){ if ($flag) $info .= $partDelim; $flag = true; $info .= (isset($item['employer']['name']) ? $item['employer']['name'] : '' ). $delim . (isset($item['location']['name']) ? $item['location']['name'] : '' ). $delim . (isset($item['position']) ? $item['position']['name'] : '' ). $delim . (isset($item['start_date']) ? $item['start_date'] : '' ). $delim . (isset($item['end_date']) ? $item['end_date'] : '' ); } return $info; } function getEducationAsString($fbme, $delim = '#', $partDelim = ' | '){ $info = ""; $flag = false; if (empty($fbme['education'])) return ''; foreach($fbme['education'] as $item){ if ($flag) $info .= $partDelim; $flag = true; $info .= (isset($item['school']['name']) ? $item['school']['name'] : '' ). $delim . (isset($item['year']['name']) ? $item['year']['name'] : ''); } return $info; } function getArrayDataAsString($data, $delim = '#', $partDelim = ' | '){ $info = ""; $flag = false; foreach($data as $item){ if ($flag) $info .= $partDelim; $flag = true; $info .= $item['name']; } return $info; } ?> Hello, I am developing a PayPal IPN interface which works fine, all is passed for verification and comes back 'VALID'. After validation with PayPal I update a users subscription and do the rest I want to do, but there is one thing really really irritating me. It seems to be that this one particular table in the database does not want to accept anything I throw at it through PHP. Here's the code: Code: [Select] $query = "INSERT INTO `ipn_txn_logs` ( `date` , `payment_reason` , `pp_txn_id` , `pp_amount` , `pp_txn_charge` , `pp_txn_net_amount` , `ltj_txn_id` , `description` , `failsafe` , `member` ) VALUES ( '$date', 'subscribe', '$txn[txn_id]', '$txn[payment_amount]', '$txn[payment_charges]', '$txn[net_payment]', '$txn[custom]', '$desc', 'yes', '$fname $lname')"; $query = mysql_query($query); The array is set on the IPN return using all values from PayPal. The database will insert when all variable and arrays are left out of the INSERT and replaced with just the number 1.. I am unable to see a PHP error as it's done in the background after a PayPal response... is there anyway to collect this error? Also, any suggestions on this fault? George.[/code] |
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