|
PHP - Not Inserted To Mysql Table;
Code: [Select]
<?php //Register 1.0.1 include("function.php"); connect(); $num = 0; if(isset($_POST['submit'])) { if($_POST['username'] == '' || $_POST['password1'] == '' || $_POST['password2'] == '') { $num = 1; echo "Please supply all fields;"; exit(); } elseif(strlen($_POST['username']) > 25) { $num = 1; echo "Username must be under 25 characters long;"; exit(); } elseif(strlen($_POST['password1']) > 16) { if(strlen($_POST['password2']) >16) { $num = 1; echo "Password are over 16 characters long;"; exit(); } $num = 1; echo "Passwords are not equal"; exit(); } elseif($_POST['password1'] != $_POST['password2']) { $num = 1; echo "Passwords are not equal;"; exit(); } } else { if(isset($_POST['submit'])) { $username = $_POST['username']; safe($username); if($_POST['password1'] = $_POST['password2']) { $password = $_POST['password']; password($password); echo "INSERT INTO user (username, password) VALUES ('$username','$password')"; } else { echo "Passwords are not equal; Double Take";//Yes Double Take is a military term exit(); } } } ?> <HTML> <form action="register.php" method="post"> Username:<input type="text" name="username"> <br> Password:<input type="password" name="password1"> <br> Password Check:<input type="password" name="password2"> <br> <input type="submit" name="submit" value="Register!"> </HTML> Here is where I put the code: if(isset($_POST['submit'])) { $username = $_POST['username']; safe($username); if($_POST['password1'] = $_POST['password2']) { $password = $_POST['password']; password($password); echo "INSERT INTO user (username, password) VALUES ('$username','$password')"; } else { echo "Passwords are not equal; Double Take";//Yes Double Take is a military term exit(); } I used it like that to narrow it down. And I still do not understand the issue, are there any other issues? [attachment deleted by admin] Similar TutorialsI have a mysql table which will store users email addresses (each is unique and is the primary field) and a timestamp. I have added another column called `'unique_code' (varchar(64), utf8_unicode_ci)`. What I would very much appreciate assistance with is; a) Generating a 5 digit alphanumeric code, ie: 5ABH6 b) Check all rows the 'unique_code' column to ensure it is unique, otherwise re-generate and check again c) Insert the uniquely generated 5 digit alphanumeric code into `'unique_code'` column, corresponding to the email address just entered. d) display the code on screen. What code must I put and where? **My current php is as follows:** Code: [Select] require "includes/connect.php"; $msg = ''; if($_POST['email']){ // Requested with AJAX: $ajax = ($_SERVER['HTTP_X_REQUESTED_WITH'] == 'XMLHttpRequest'); try{ if(!filter_input(INPUT_POST,'email',FILTER_VALIDATE_EMAIL)){ throw new Exception('Invalid Email!'); } $mysqli->query("INSERT INTO coming_soon_emails SET email='".$mysqli->real_escape_string($_POST['email'])."'"); if($mysqli->affected_rows != 1){ throw new Exception('You are already on the notification list.'); } if($ajax){ die('{"status":1}'); } $msg = "Thank you!"; } catch (Exception $e){ if($ajax){ die(json_encode(array('error'=>$e->getMessage()))); } $msg = $e->getMessage(); } } Shouldn't the following stop a blank row from being inserted into mysql? I have a description and a date but it still keeps putting a blank row before my insert and I've tried everything.... if($myvar != ''){ mysql_query("INSERT IGNORE INTO products (description, time) VALUES('$myvar',NOW() ) ") or die(mysql_error()); Ugh. Ive been asking so many questions, betcha already know my name. Hahah. Anyways, I know I already asked a question like this, but this is different. One of the values I am trying to insert into a database is simply not working. Here is the columnes in my mysql database: c_id commet story user date_added star Every value but 'commet' is getting inserted into database. NO error, no mysql errror. I have racked my brain trying to figure out what is wrong with the script. Here is my code: Code: [Select] <?php $idget = $_GET['id']; mysqlConnect(); //submit story if(isset($_POST['submit'])) { $com_form = mysql_real_escape_string(bb($_POST['commet'])); $rat_form = $_POST['rat']; $story_form = $idget; $user = $_SESSION['user']; $date = date("Y-m-d"); $query1 = " INSERT INTO story_commets(star, story, user, date_added, commet) VALUES($rat_form, '$story_form', '$user', '$date', '$com_form') "; mysql_query($query1) or die(mysql_error()); //} } // desplay reviews $query3 = " SELECT * FROM story_commets WHERE story = '$idget' ORDER BY date_added "; $select3 = mysql_query($query3) or die(mysql_error()); //$x=1; $ratav = array(); //if(mysql_num_rows($select3) == 0) //{ echo '<div id="message"> No Reviews Yet.... <>'; //} //else //{ while($rows3 = mysql_fetch_assoc($select3)) { $commetdb = $rows3['commet']; $user_com_db = $rows3['user']; $datedb = $rows3['date_added']; $stardb = $rows3['star']; //get profile picture $query4 = " SELECT * FROM login_info WHERE user = '$user_com_db' "; $select4 = mysql_query($query4) or die(mysql_error()); $rows4 = mysql_fetch_assoc($select4) or die(mysql_error()); $profile_pic = $rows4['profile_picture']; $user_id = $rows4['id']; echo " <div class='rev_cont'> <div class='info'> <img src='$profile_pic' /> <a href=?p=profile&id=$user_id> $user_com_db </a> <> <br /> <div class='rev'> <strong> $stardb/10 </strong> <br /> $commetdb <> <div id='date'> <em> Date Added: $datedb </em> <> <> <hr /> "; $ratav[]=$stardb; } $sum = array_sum($ratav); $count = count($ratav); $av = $sum / $count; $avf = round($av, 1); echo"<div id='message'> Rating Avarage: $avf /10 <>"; //} if (isset($_SESSION['user'])) { echo" <p> Did you like this story? Did you hate it? Give it a rating and let the author know!</p> <form action='?p=review&id=$idget' method='post' target='_self'> <label> Your rating is on a scale of 1-10 </label> <select name='rat'> <option> 1 </option> <option> 2 </option> <option> 3 </option> <option> 4 </option> <option> 5 </option> <option> 6 </option> <option> 7 </option> <option> 8 </option> <option> 9 </option> <option> 10 </option> </select> <label> Commets: </label> <textarea name='commet' cols='70' rows='9'></textarea> <input name='story' type='hidden' value='$idget' /> <br /> <input type='submit' value = 'Post' name='submit' /> </form> "; } else { echo "<div id='message'> Sign in to post a review! <>"; } ?> Here are the specifics if you want it. Here is the response part of the code: Code: [Select] <?php if(isset($_POST['submit'])) { $com_form = mysql_real_escape_string(bb($_POST['commet'])); $rat_form = $_POST['rat']; $story_form = $idget; $user = $_SESSION['user']; $date = date("Y-m-d"); $query1 = " INSERT INTO story_commets(star, story, user, date_added, commet) VALUES($rat_form, '$story_form', '$user', '$date', '$com_form') "; mysql_query($query1) or die(mysql_error()); //} } ?> Here is the form part of my code: Code: [Select] <?php if (isset($_SESSION['user'])) { echo" <p> Did you like this story? Did you hate it? Give it a rating and let the author know!</p> <form action='?p=review&id=$idget' method='post' target='_self'> <label> Your rating is on a scale of 1-10 </label> <select name='rat'> <option> 1 </option> <option> 2 </option> <option> 3 </option> <option> 4 </option> <option> 5 </option> <option> 6 </option> <option> 7 </option> <option> 8 </option> <option> 9 </option> <option> 10 </option> </select> <label> Commets: </label> <textarea name='commet' cols='70' rows='9'></textarea> <input name='story' type='hidden' value='$idget' /> <br /> <input type='submit' value = 'Post' name='submit' /> </form> "; } else { echo "<div id='message'> Sign in to post a review! <>"; } ?> Its probably something really mundane. HelP! Am a newbie in php. Since I can't insert values to the database with respect to a user Id or with any other token using WHERE clause. I.e "INSERT INTO receipts(date) VALUES(example) where id="**....." If I need to fetch several values of column for a particular user, how do I go about it? Thank you!!!
create table mimi (mimiId int(11) not null, mimiBody varchar(255) );
<?php
//connecting to database
include_once ('conn.php');
$sql ="SELECT mimiId, mimiBody FROM mimi";
$result = mysqli_query($conn, $sql );
$mimi = mysqli_fetch_assoc($result);
$mimiId ='<span>No: '.$mimi['mimiId'].'</span>';
$mimiBody ='<p class="leading text-justify">'.$mimi['mimiBody'].'</p>';
?>
//what is next?
i want to download pdf or text document after clicking button or link how to do that Hello, I need some help. Say that I have a list in my MySQL database that contains elements "A", "S", "C", "D" etc... Now, I want to generate an html table where these elements should be distributed in a random and unique way while leaving some entries of the table empty, see the picture below. But, I have no clue how to do this... Any hints? Thanks in advance, Vero Hello everyone, Sorry if this has been answered but if it has I can't find it anywhere. So, from the begining then. Lets say I had a member table and in it I wanted to store what their top 3 interests are. Their$ row has all the usual things to identify them userID and password etc.. and I had a further 3 columns which were labled top3_1 top3_2 & top3_3 to put each of their interests in from a post form. If instead I wanted to store this data as a PHP Array instead (using 1 column instead of 3) is there a way to store it as readable data when you open the PHPmyadmin? At the moment all it says is array and when I call it back to the browser (say on a page where they could review and update their interests) it displays 'a' as top3_01 'r' as top3_02 and 'r' as top3_03 (in each putting what would be 'array' as it appears in the table if there were 5 results. Does anyone know what I mean? For example - If we had a form which collected the top 3 interests to put in a table called users, Code: [Select] <form action="back_to_same_page_for_processing.php" method="post" enctype="multipart/form-data"> <input name="top3_01" type="text" value="enter interest number 1 here" /> <input name="top3_02" type="text" value="enter interest number 2 here" /> <input name="top3_03" type="text" value="enter interest number 3 here" /> <input type="submit" name="update_button" value=" Save and Update! " /> </form> // If my quick code example for this form is not correct dont worry its not the point im getting at :) And they put 'bowling' in top3_01, 'running' in top3_02 and 'diving' in top3_03 and we catch that on the same page with some PHP at the top --> Code: [Select] if (isset($_POST)['update_button']) { $top3_01 = $_POST['top3_01']; // i.e, 'bowling' changing POST vars to local vars $top3_02 = $_POST['top3_02']; // i.e, 'running' $top3_03 = $_POST['top3_03']; // i.e, 'diving' With me so far? If I had a table which had 3 columns (1 for each interest) I could put something like - Code: [Select] include('connect_msql.php'); mysql_query("Select * FROM users WHERE id='$id' AND blah blah blah"); mysql_query("UPDATE users SET top3_01='$top3_01', top3_02='$top3_02', top3_03='$top3_03' WHERE id='$id'"); And hopefully if ive got it right, it will put them each in their own little column. Easy enough huh? But heres the thing, I want to put all these into an array to be stored in the 1 column (say called 'top3') and whats more have them clearly readable in PHPmyadmin and editable from there yet still be able to be called back an rendered on page when requested. Continuing the example then, assuming ive changed the table for the 'top3' column instead of individual colums, I could put something like this - Code: [Select] if (isset($_POST)['update_button']) { $top3_01 = $_POST['top3_01']; // i.e, 'bowling' changing POST vars to local vars $top3_02 = $_POST['top3_02']; // i.e, 'running' $top3_03 = $_POST['top3_03']; // i.e, 'diving' $top3_array = array($top3_01,$top3_02,$top3_03); include('connect_msql.php'); mysql_query("UPDATE members SET top3='$top3_array' WHERE id='$id' AND blah blah blah"); But it will appear in the column as 'Array' and when its called for using a query it will render the literal string. a r r in each field instead. Now I know you can use the 'serialize()' & 'unserialize()' funtcions but it makes the entry in the database practically unreadable. Is there a way to make it readable and editable without having to create a content management system? If so please let me know and I'll be your friend forever, lol, ok maybe not but I'd really appreciate the help anyways. The other thing is, If you can do this or something like it, how am I to add entries to that array to go back into the data base? I hope ive explained myself enough here, but if not say so and I'll have another go. Thanks very much people, L-PLate (P.s if I sort this out on my own ill post it all here) I know I'm doing it something right, but can someone tell me why only one table is showing up? Can you help me fix the issue? Heres my code: function showcoords() { echo"J3st3r's CoordVision"; $result=dbquery("SELECT alliance, region, coordx, coordy FROM ".DB_COORDFUSION.""); dbarray($result); $fields_num = mysql_num_fields($result); echo "<table border='1'>"; // printing table headers echo "<td>Alliance</td>"; echo "<td>Region</td>"; echo "<td>Coord</td>"; // printing table rows while($row = mysql_fetch_array($result)) { // $row is array... foreach( .. ) puts every element // of $row to $cell variable foreach($row AS $Cell) echo "<tr>"; echo "<td>".$row['alliance']."</td>\n"; echo "<td>".$row['region']."</td>\n"; echo "<td>".$row['coordx'].",".$row['coordy']."</td>\n"; echo "</tr>\n"; } echo "</table>"; mysql_free_result($result); } I have 2 rows inserted into my coords table. Just frustrated and ignorant to php. hi there, so okay i have a table named course which has 2 fields. c_id and c_name c_id here isn't unique but is indexed. okay,my problem is how to get the last inserted row in this table right after a record has been inserted. i was thinking i'd do a little query and then echo the results back to where the user fills up a form with c_id and c_name fields.. so is there a way to do this?like getting all values from the last inserted row? Wonder if someone can advise I have a script which runs on a CRON job, so every hour a script is activated. When the script runs, it INSERTS between 1 and 12 records into a database table, works a charm so far. When each QUERY is run on the script, it grabs the last ID number that was INSERTED and that is entered into another table, so if my script INSERTS a new row with an ID of 34877, then the ID number 34877 is entered into another database table. To grab the last ID number, I have always used $last_id = mysql_insert_id(); as seen on http://php.net/manual/en/function.mysql-insert-id.php which has always worked great. I now have to create another script on a CRON job, which does a similar TASK, it INSERTS a record into the same database and then grabs the last ID number. The plan is to roll about 150 of these script out, so each one is INSERTING data, and grabbing the last ID of the row just created. By 2015, they plan to have several thousand of these scripts, all being run at the same time. This is basically part of a bigger system and this is the method in which the 3rd party suppliers need data handled, so I have no option. My question is, if I have tons of scripts INSERTING data to the same database table and each time an INSERT is done, the last ID is grabbed, can PHP get overloaded and confused and then end up returning the wrong ID number of the row INSERTED. Or if I put $last_id = mysql_insert_id(); straight after each INSERT, then is it gurenteed that the right ID number is returned. Just concerned the QUERIES will end up in a que and incorrect ID numbers will be returned. Basically, is $last_id = mysql_insert_id(); flawless in getting the ID number of the row just INSERTED? Cheers everyone i have the following processing action for a form query DUMP output is: string(202) "INSERT INTO contactPO (Status, DateReceived, CustomerEmail, LastName, FirstName, PropertyID, fromdate, todate, nop) VALUES ('1', '24-08-2011', 'r', 'r', 'rrrrr', '12121', '27-10-2011', '30-10-2011','4')" but nothing is inserted Code: [Select] <?php $con = mysql_connect("localhost","international",""); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_query("SET NAMES 'utf8'"); mysql_select_db("international", $con); // check which button was clicked // perform calculation if ($_POST['send']) { $query = sprintf("INSERT INTO contactPO (Status, DateReceived, CustomerEmail, LastName, FirstName, PropertyID, fromdate, todate, nop) VALUES ('%s', '%s', '%s', '%s', '%s', '%s', '%s', '%s','%s')", mysql_real_escape_string($_POST['Status']), mysql_real_escape_string($_POST['DateReceived']), mysql_real_escape_string($_POST['CustomerEmail']), mysql_real_escape_string($_POST['LastName']), mysql_real_escape_string($_POST['FirstName']), mysql_real_escape_string($_POST['PropertyID']), mysql_real_escape_string($_POST['fromdate']), mysql_real_escape_string($_POST['todate']), mysql_real_escape_string($_POST['nop'])); var_dump($query ); //$url_success = "search-index.php?RID=".$_POST['RequestID'].""; $url_success = "search-index.php"; echo("<meta http-equiv = refresh content=6;url=".$url_success.">"); exit; mysql_close($con); } ?> Basically the following code works fine, exepct when it comes to the last result it inserts it twice, example: (3,17),(4,17),(5,17),(5,17) Any clues as to why? Thanks Code: [Select] if(count($addIDs_ary) > 0) { $str = ""; foreach($addIDs_ary as $val) { $str .= "({$val},{$playerID}),"; if(end($addIDs_ary) == $val) { $str .= "({$val},{$playerID})"; } } echo $str; // (val,val), (val,val), (val,val) etc.. $query = "INSERT INTO hitlist (hit_id,player_id) values $str"; Hi, I am making a website where the user can create a login and he's then redirected to the secured pages this is working ok. Then I want the user who's not yet completely registered to enter his full name and credentials and store this data in the table Owner. however when I am trying to do this with the below mentioned code I don't get any output on error level and I don't get any data inserted in my table what am I missing here Code: [Select] <?php //session starten session_start(); ini_set('display_errors', 'On'); error_reporting(E_ALL | E_STRICT); print_r($_SESSION['user_id']); //database verbinding maken mysql_connect("127.0.0.1", "root", "pass")or die("cannot connect"); mysql_select_db("tobysplace")or die("cannot select DB"); //kijken of de gebruikers_id al gekend is in de tabel Owner $result = mysql_query("Select gebruiker_id from Owner where gebruiker_id ='".mysql_real_escape_string($_SESSION['user_id'])"'"); If(!$result){ $gebruiker_id = mysql_insert_id(); } else { $gebruiker_id = mysql_real_escape_string($_SESSION['user_id']); } //de gegevens van de eigenaar wegschrijven in de database $Owner_query="insert into Owner( name, lastname, email, address1, town, postcode, phone, gebruiker_id)values( '" . mysql_real_escape_string($_SESSION['name']) . "', '" . mysql_real_escape_string($_SESSION['lastname']) . "', '" . mysql_real_escape_string($_SESSION['email']) . "', '" . mysql_real_escape_string($_SESSION['address1']) . "', '" . mysql_real_escape_string($_SESSION['town']) . "', '" . mysql_real_escape_string($_SESSION['postcode']) . "', '" . mysql_real_escape_string($_SESSION['phone']) . "', '" . mysql_real_escape_string($_SESSION['user_id']) ."')"; // // de query uitvoeren $result=mysql_query($Owner_query) //foutcontrole or die("<b>A fatal MySQL error occured</b>.\n<br />Query: " . $Owner_query . "<br />\nError: (" . mysql_errno() . ") " . mysql_error()); print '<p>'.$_SESSION['name'].' U bent met succes ingeschreven op tobys-place</p>'; //} ?> If the user signs up and does not have an avatar, a default will be given to them. I am checking for the avatar/image file, however, that is not working. Here is the messy code below:
if ($_SERVER['REQUEST_METHOD'] == 'POST') {
// $username = $_POST['username'];
// adds user info submitted upon registration to database
function addUser($pdo) {
$username = $_POST['username'];
$password = password_hash($_POST['password'], PASSWORD_DEFAULT);
$bio = $_POST['bio'];
$email = $_POST['email'];
$c_status = 0;
$query = $pdo->prepare("INSERT into profiles001 (username, password, email, c_status, bio) VALUES (:username, :password, :email, :cstat, :bio)");
$query->bindValue(':username', $username);
$query->bindValue(':password', $password);
$query->bindValue(':email', $email);
$query->bindValue(':cstat', $c_status);
$query->bindValue(':bio', $bio);
$file = $_FILES['userfile'];
$file_name = $file['name'];
$file_type = $file['type'];
$file_size = $file['size'];
$file_tmp_name = $file['tmp_name'];
$file_error = $file['error'];
if (!isset($_FILES['userfile'])) {
$avatar = "assets/soap.jpg";
$avatar_present_query = $pdo->prepare("INSERT into profiles001 (avatar) VALUES (:avatar) WHERE username = ':username'");
$avatar_present_query->bindValue(':avatar', $avatar);
$avatar_present_query->bindValue(':username', $username);
$avatar_present_query->execute();
$query->execute();
}
// $query->execute();
}
addUser($pdo);
I have a table like this: http://empirebuildingsestate.com/company.html How can I separate the table values into variables so I can insert them into my mySQL database? I have been trying DOMDocument but i need some help. whats wrong in here for i get query failed everytime i submit the form? Code: [Select] //Create INSERT query $qry = "INSERT INTO class_members (user_name, passwrd, f_name, l_name, email, gender, date) VALUES('$user_name','".md5($_POST['password'])."','$f_name','$l_name','$email', '$gender','gmdate($date)',)"; $result = @mysql_query($qry); //Check whether the query was successful or not if($result) { header("location: register-success.php"); exit(); }else { die("Query failed"); } I have two pages - add_product.php and show.php here is the code for add_product.php Code: [Select] <?php ini_set('display_errors',1); error_reporting(-1); require_once ('./includes/config.inc.php'); require_once (MYSQL); $add_cat_errors = array(); if ($_SERVER['REQUEST_METHOD'] == 'POST') { // Check for a name: if (empty($_POST['product'])) { $add_cat_errors['product'] = 'Please enter the name!'; } // Check for a description: if (empty($_POST['prod_descr'])) { $add_cat_errors['prod_descr'] = 'Please enter the description!'; } // Check for a category: if (!isset($_POST['cat']) || !filter_var($_POST['cat'], FILTER_VALIDATE_INT, array('min_range' => 1))) { $add_cat_errors['cat'] = 'Please select a category!'; } // Check for a price: if (empty($_POST['price']) || !filter_var($_POST['price'], FILTER_VALIDATE_FLOAT) || ($_POST['price'] <= 0)) { $add_cat_errors['price'] = 'Please enter a valid price!'; } // Check for a category: if (!isset($_POST['directory']) || !filter_var($_POST['directory'], FILTER_VALIDATE_INT, array('min_range' => 1))) { $add_cat_errors['directory'] = 'Please select a directory!'; } // Check for a stock: if (empty($_POST['stock']) || !filter_var($_POST['stock'], FILTER_VALIDATE_INT, array('min_range' => 1))) { $add_cat_errors['stock'] = 'Please enter the quantity in stock!'; } if (empty($add_cat_errors)) { $query = "INSERT INTO product (product, prod_descr, catID, price, dirID, stock) VALUES (?, ?, ?, ?, ?, ?)"; // Prepare the statement: $stmt = mysqli_prepare($dbc, $query); // For debugging purposes: // if (!$stmt) echo mysqli_stmt_error($stmt); // Bind the variables: mysqli_stmt_bind_param($stmt, 'sssssi', $name, $desc, $_POST['cat'], $_POST['price'], $_POST['directory'], $_POST['stock']); // Make the extra variable associations: $name = strip_tags($_POST['product']); $desc = strip_tags($_POST['prod_descr']); // Execute the query: mysqli_stmt_execute($stmt); if (mysqli_stmt_affected_rows($stmt) == 1) { // If it ran OK. // Print a message: echo '<h4>The product has been added!</h4>'; // Clear $_POST: $_POST = array(); // Clear $_FILES: $_FILES = array(); } else { // If it did not run OK. trigger_error('The product could not be added due to a system error. We apologize for any inconvenience.'); } } // End of $errors IF. } else { // Clear out the session on a GET request: } // End of the submission IF. require_once ('./includes/form_functions.inc.php'); ?> <form enctype="multipart/form-data" action="add_image.php?prodID={$row['prodID']}" method="post" accept-charset="utf-8"> <input type="hidden" name="MAX_FILE_SIZE" value="524288" /> Product<br /><?php create_form_input('product', 'text', $add_cat_errors); ?> Description<br /><?php create_form_input('prod_descr', 'textarea', $add_cat_errors); ?> Category<br /><select name="cat"<?php if (array_key_exists('cat', $add_cat_errors)); ?>> <option>Select One</option> <?php // Retrieve all the categories and add to the pull-down menu: $q = 'SELECT catID, cat FROM category ORDER BY cat ASC'; $r = mysqli_query ($dbc, $q); while ($row = mysqli_fetch_array ($r, MYSQLI_NUM)) { echo "<option value=\"$row[0]\""; // Check for stickyness: if (isset($_POST['cat']) && ($_POST['cat'] == $row[0]) ) echo ' selected="selected"'; echo ">$row[1]</option>\n"; } ?> </select><?php if (array_key_exists('cat', $add_cat_errors)) echo $add_cat_errors['cat']; ?> Price<br /><?php create_form_input('price', 'text', $add_cat_errors); ?> Directory<br /><select name="directory"<?php if (array_key_exists('directory', $add_cat_errors)); ?>> <option>Select One</option> <?php // Retrieve all the categories and add to the pull-down menu: $q = 'SELECT dirID, directory FROM directory ORDER BY directory ASC'; $r = mysqli_query ($dbc, $q); while ($row = mysqli_fetch_array ($r, MYSQLI_NUM)) { echo "<option value=\"$row[0]\""; // Check for stickyness: if (isset($_POST['directory']) && ($_POST['directory'] == $row[0]) ) echo ' selected="selected"'; echo ">$row[1]</option>\n"; } ?> </select><?php if (array_key_exists('directory', $add_cat_errors)) echo $add_cat_errors['directory']; ?> </select> <br /> Stock<br /><?php create_form_input('stock', 'text', $add_cat_errors); ?> <input type="submit" value="Add This Product" class="button" /> </fieldset> </form> and here is the code for show.php Code: [Select] <?php ini_set('display_errors',1); error_reporting(-1); require_once ('./includes/config.inc.php'); require_once (MYSQL); $add_cat_errors = array(); if($id = isset($_GET['prodID'])) { $q = "SELECT `prodID`, `product`, `prod_descr`, `catID`, `dirID`, `price`, `stock` FROM product WHERE `prodID`='{$_GET['prodID']}'"; $r = mysqli_query($dbc, $q); while($row = mysqli_fetch_array($r)) { echo $row['product']; echo "<br />"; echo $row['prod_descr']; echo "<br />"; echo $row['catID']; echo "<br />"; echo $row ['dirID']; echo "<br />"; echo $row['price']; echo "<br />"; echo $row['stock']; } } What I want is to try and retrieve the id of the last record inserted in add_product and pass it into show.php, but I get this error message. Quote An error occurred in script 'C:\Users\David Morgan\Desktop\WEBSITES\hairz_&_graces\site\admin\add_image.php' on line 16: mysqli_fetch_array() expects parameter 1 to be mysqli_result, boolean given I am struggling to find out where I am going wrong at the moment, if anyone could please help me that would be really appreciated. im playing around with a rating star jquery, i trying to get the value from the radio group but it is not selected??? Code: [Select] <?php require_once('Connections/international.php'); ?> <? mysql_query("SET NAMES 'utf8'")?> <!DOCTYPE html PUBLIC '-//W3C//DTD XHTML 1.0 Transitional//EN' 'http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd'> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> <head> <title>jQuery Star Rating Plugin v3.13 (2009-03-26)</title> <script src='http://jquery-star-rating-plugin.googlecode.com/svn/trunk/jquery.js' type="text/javascript"></script> <script src='http://jquery-star-rating-plugin.googlecode.com/svn/trunk/documentation.js' type="text/javascript"></script> <link href='http://jquery-star-rating-plugin.googlecode.com/svn/trunk/documentation.css' type="text/css" rel="stylesheet"/> <script type="text/javaScript" src="http://www.fyneworks.com/jquery/project/chili/jquery.chili-2.0.js"></script> <script type="text/javascript">try{ChiliBook.recipeFolder="/jquery/project/chili/"}catch(e){}</script> <script src='http://jquery-star-rating-plugin.googlecode.com/svn/trunk/jquery.MetaData.js' type="text/javascript" language="javascript"></script> <script src='http://jquery-star-rating-plugin.googlecode.com/svn/trunk/jquery.rating.js' type="text/javascript" language="javascript"></script> <link href='http://jquery-star-rating-plugin.googlecode.com/svn/trunk/jquery.rating.css' type="text/css" rel="stylesheet"/> </head> <body> <a name="top"></a> <div id="wrap"> <div id="body"> <div id="documentation" class="tabs"> <div id="tab-Testing"> <h2>Test Suite</h2> <script type="text/javascript" language="javascript"> $(function(){ $('#form1 :radio.star').rating(); $('#form2 :radio.star').rating({cancel: 'Cancel', cancelValue: '0'}); $('#form3 :radio.star').rating(); $('#form4 :radio.star').rating(); }); </script> <script> $(function(){ $('#tab-Testing form').submit(function(){ $('.test',this).html(''); $('input',this).each(function(){ if(this.checked) $('.test',this.form).append(''+this.name+': '+this.value+'<br/>'); }); return false; }); }); </script><div class="Clear"> </div> <form name="form1" id="form1" method="POST"> <strong style='font-size:150%'>Test 2</strong> - With defaults ('checked') <table width="100%" cellspacing="10"> <tr> <td valign="top" width=""> <table width="100%"> <tr> <td valign="top" width="50%"> <div class="Clear"> Rating 1: (N/M/Y, default M) </div> <div class="Clear"> <input class="star" type="radio" name="rating1" value="0" id="rating1_0" title="0"/> <input class="star" type="radio" name="rating1" value="1" id="rating1_1" title="1"/> <input class="star" type="radio" name="rating1" value="2" id="rating1_2" title="2"/> </div> <div class="Clear"> Rating 2: (10 - 50, default 30) </div> <div class="Clear"> <input class="star" type="radio" name="rating22" value="10"/> <input class="star" type="radio" name="rating22" value="20"/> <input class="star" type="radio" name="rating22" value="30" checked="checked"/> <input class="star" type="radio" name="rating22" value="40"/> <input class="star" type="radio" name="rating22" value="50"/> </div> <div class="Clear"> Rating 3: (1 - 7, default 4) </div> <div class="Clear"> <input class="star" type="radio" name="rating23" value="1"/> <input class="star" type="radio" name="rating23" value="2"/> <input class="star" type="radio" name="rating23" value="3"/> <input class="star" type="radio" name="rating23" value="4" checked="checked"/> <input class="star" type="radio" name="rating23" value="5"/> <input class="star" type="radio" name="rating23" value="6"/> <input class="star" type="radio" name="rating23" value="7"/> </div> </td> <td valign="top" width="50%"> <div class="Clear"> Rating 4: (1 - 5, default 1) </div> <div class="Clear"> <input class="star" type="radio" name="rating24" value="1" title="Worst" checked="checked"/> <input class="star" type="radio" name="rating24" value="2" title="Bad"/> <input class="star" type="radio" name="rating24" value="3" title="OK"/> <input class="star" type="radio" name="rating24" value="4" title="Good"/> <input class="star" type="radio" name="rating24" value="5" title="Best"/> </div> <div class="Clear"> Rating 5: (1 - 5, default 5) </div> <div class="Clear"> <input class="star" type="radio" name="rating25" value="1"/> <input class="star" type="radio" name="rating25" value="2"/> <input class="star" type="radio" name="rating25" value="3"/> <input class="star" type="radio" name="rating25" value="4"/> <input class="star" type="radio" name="rating25" value="5" checked="checked"/> </div> <div class="Clear"> Rating 6 (readonly): (1 - 5, default 3) </div> <div class="Clear"> <input class="star" type="radio" name="rating26" value="1" disabled="disabled"/> <input class="star" type="radio" name="rating26" value="2" disabled="disabled"/> <input class="star" type="radio" name="rating26" value="3" disabled="disabled" checked="checked"/> <input class="star" type="radio" name="rating26" value="4" disabled="disabled"/> <input class="star" type="radio" name="rating26" value="5" disabled="disabled"/> </div> </td> </tr> </table> </td> <td valign="top" width="5"> </td> <td valign="top" width="50"> <input type="submit" value="Submit" name="submit"/> </td> <td valign="top" width="5"> </td> <td valign="top" width="160"> <u>Test results</u>:<br/><br/> <div class="test Smaller"> <span style="color:#FF0000">Results will be displayed here</span> </div> </td> </tr> </table> <script> $(function(){ $('.hover-star').rating({ focus: function(value, link){ // 'this' is the hidden form element holding the current value // 'value' is the value selected // 'element' points to the link element that received the click. var tip = $('#hover-test'); tip[0].data = tip[0].data || tip.html(); tip.html(link.title || 'value: '+value); }, blur: function(value, link){ var tip = $('#hover-test'); $('#hover-test').html(tip[0].data || ''); } }); }); </script> <div class="Clear"> </div><div class="Clear"> </div> </div> </div> </div> <div id="push"></div> </div> </form> </body></html> <?php mysql_select_db($database_international, $international); $query=mysql_query("INSERT INTO ratings_tbl (Comfort) VALUES ('$_POST[rating1]'')"); $selected_radio = $_POST['rating1']; echo $selected_radio; var_dump($_POST); ;?> I have a small form, then after submit it inserts a new row with a few values (time, email) This form also sends email to the email from the form with a link. Problem, the link needs to contain an autoincrement value from the newly inserted row. How can I do this? (the form that obvioulsy doesn't work, for obviously reasons but to show what I try to accomplish:P) Code: [Select] <? if (isset($_REQUEST['Submit'])) { $time= time(); # THIS CODE TELL MYSQL TO INSERT THE DATA FROM THE FORM INTO YOUR MYSQL TABLE $sql = "INSERT INTO phpfox_invite (user_id,email,time_stamp,is_used) values ('".$b."','".mysql_real_escape_string(stripslashes($_REQUEST['email']))."','".$time."','1')"; $sql = mysql_query("SELECT invite_id FROM phpfox_invite WHERE email='".mysql_real_escape_string(stripslashes($_REQUEST['email']))."'"); $result = mysql_fetch_array( $sql ); $inviteid = $result['invite_id']; if($result = mysql_query($sql)) { $modtager = "".mysql_real_escape_string(stripslashes($_REQUEST['email'])).""; $emne = "Please complete Your registration"; $besked = "Click the link below to complete your registration: \n http://domain.com/invite/id_".$inviteid." "; $header = "from:system@domain.com"; mail($modtager, $emne, $besked, $header); echo 'Check Your Email!'; } else { echo "ERROR: ".mysql_error(); } ?> Everything works ok, but ofcourse I cannot get the 'invite_id' before the form is submitted and therefor cannot send the value I have tried to run my code and it works. I am not getting any error message but when I checked my database nothing was added. Code: [Select] <?php session_start(); include '../Database/connection.php'; if ($_FILES["file"]["error"] > 0) { echo "Error: " . $_FILES["file"]["error"] . "<br />"; } $filename = $_FILES["file"]["tmp_name"]; $fd = fopen ($filename, "r"); $data = fread ($fd,filesize ($filename)); fclose ($fd); $delimiter = "\n"; $output = explode($delimiter, $data); foreach($output as $var) { $tmp = explode(".", $var); $question = $tmp[0]; $choice1 = $tmp[1]; $choice2 = $tmp[2]; $choice3 = $tmp[3]; $choice4 = $tmp[4]; $answer1 = $tmp[5]; $answer2 = $tmp[6]; $answer3 = $tmp[7]; $answer4 = $tmp[8]; $sql = "INSERT INTO question SET Que_Question='$question', Que_Choice1='$choice1', Que_Choice2='$choice2', Que_Choice3='$choice3', Que_Choice4='$choice4', Que_Answer1='$answer1', Que_Answer2='$answer2', Que_Answer3='$answer3', Que_Answer4='$answer4', Tes_ID='$_SESSION[Tes_ID]'"; mysql_query($sql); } ?> My text file holds Quote What is the sky.where.how.wen.one.0.0.1.0 What colour.where.what.how.more.0.0.1.0 |
|||||||