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PHP - Drop Table Using Variable
Hi,
I'm trying to drop a table form a database using the table name as a variable. This variable is set within a session. I am using a form where you input the table name, then the DROP TABLE procedure is executed in the next page. I know that the variable gets passed because it prints the table name variable out when I "echo". The execution is simple (code found in deletetable.php) $temp = $_POST['temp']; $query = "DROP TABLE $temp"; if(mysql_query($query)){ echo "<h1 style='color:green;'>Table $temp deleted</h1>";} else{ echo "<h1 style='color:red;'>Deletion of table '$temp' failed!</h1>";} Here's my code for the two pages: delete_table.php <?php include("includes/header.html"); session_start(); $hostname = $_SESSION['hostname']; $user = $_SESSION['user']; $passwd = $_SESSION['passwd']; $database = $_SESSION['database']; $tblname = $_SESSION['table']; $conn = mysql_connect($hostname, $user, $passwd, $database); /*if(! $conn ) { die('Could not connect: ' . mysql_error()); }*/ ?> <div id="container"> <div id="header">Create DB</div> <div id="breadcrumbs"> <?php function check_port($port) { $conn = @fsockopen("127.0.0.1", $port, $errno, $errstr, 0.2); if ($conn) { fclose($conn); return true; } } function server_report() { $report = array(); $svcs = array('3306'=>'MySQL'); foreach ($svcs as $port=>$service) { $report[$service] = check_port($port); } return $report; } $report = server_report(); ?> <div id="server"><p>Server is <?php echo $report['MySQL'] ? "running" : "offline"; ?></p></div> <?php if(!$_SESSION['hostname']){ echo "<font color='red'>Not connected to server!</font>"; } else { echo "<font color='green'>Server: ".$_SESSION['hostname']."</font>"; } if(!$_SESSION['database']){ echo ""; }else{ echo "<br><font color='green'>Database: ".$_SESSION['database']."</font>"; } ?> </div> <div id="nav"> <p><a href="#" onclick="javascript:window.open('connect_db.php','_self');"><img src="server_conn_ico.png" align="left" />Server Connection</a></p> <p><a href="databases.php"><img src="databases_ico.png" align="left" />View Database</a></p> <p><a href="create_db.php"><img src="server_folder_ico.png" align="left" />Create Database</a></p> <p><a href="drop_db.php"><img src="drop_ico.png" align="left" />Drop Database</a></p> <p><a href="create_table.php"><img src="status_ico.png" align="left" />Add Table</a></p> <p><a href="add_fields.php"><img src="server_ico.png" align="left" />Add Fields</a></p> <p class="active"><a href="delete_table.php"><img src="status_delete_ico.png" align="left" />Delete Table</a></p> <p><a href="view_tables.php"><img src="user_admin_ico.png" align="left" />View Tables</a></p> <p><a href="view_data.php"><img src="user_admin_ico.png" align="left" />View Table Data</a></p> <p><a href="http://localhost/phpmyadmin/" target="_blank"><img src="phpmyadmin_ico.png" align="left" />phpMyAdmin</a></p> <p><a href="connect_info.php"><img src="health_ico.png" align="left" />System Info</a></p> <p><a href="error_log.php"><img src="logs_ico.png" align="left" />Server Log</a></p> <p><a href="bug_report.php"><img src="bugs-icon.png" align="left" />Bug Reports</a></p> </div> <div id="controls"><a href="javascript:self.close()"><img src="controls.png" /></a></div> <div id="main"> <div id="content"> <!--<h1>Delete Database Table</h1>--> <?php if(empty($database)) { echo "<p>You must be connected to a database in order to delete a table.</p>"; }else{ //echo 'Connected successfully to \''.$database.'\''; // Check tables $sql = "SHOW TABLES FROM $database"; $result = mysql_query($sql); if (mysql_num_rows($result) > 0) { echo "<p style='text-align:left;padding-left:24px;'>Available tables:</p>\n"; echo "<pre style='text-align:left;padding-left:24px;font-size:1.2em;'>\n"; while ($row = mysql_fetch_row($result)) { echo "{$row[0]}\n"; } echo "</pre>\n"; } ?> <form action="deletetable.php" method="post"> Enter table you'd like to delete from '<?php echo $database; ?>' database: <input name="temp" type="text" /><br/> <input name="Submit" type="submit" value=" Delete Table " /> <input type='button' value=' Cancel ' onclick="javascript:window.location='connect_db.php';"></p> </form> <?php } include("includes/footer.html"); ?> Executing file deletetable.php: <?php include("includes/header.html"); session_start(); $hostname = $_SESSION['hostname']; $user = $_SESSION['user']; $passwd = $_SESSION['passwd']; $database = $_SESSION['database']; //$tblname = $_SESSION['table']; $conn = mysql_connect($hostname, $user, $passwd, $database); ?> <div id="container"> <div id="header">Create DB</div> <div id="breadcrumbs"> <?php function check_port($port) { $conn = @fsockopen("127.0.0.1", $port, $errno, $errstr, 0.2); if ($conn) { fclose($conn); return true; } } function server_report() { $report = array(); $svcs = array('3306'=>'MySQL'); foreach ($svcs as $port=>$service) { $report[$service] = check_port($port); } return $report; } $report = server_report(); ?> <div id="server"><p>Server is <?php echo $report['MySQL'] ? "running" : "offline"; ?></p></div> <?php if(!$_SESSION['hostname']){ echo "<font color='red'>Not connected to server!</font>"; } else { echo "<font color='green'>Server: ".$_SESSION['hostname']."</font>"; } if(!$_SESSION['database']){ echo ""; }else{ echo "<br><font color='green'>Database: ".$_SESSION['database']."</font>"; } ?> </div> <div id="nav"> <p><a href="#" onclick="javascript:window.open('connect_db.php','_self');"><img src="server_conn_ico.png" align="left" />Server Connection</a></p> <p><a href="databases.php"><img src="databases_ico.png" align="left" />View Database</a></p> <p><a href="create_db.php"><img src="server_folder_ico.png" align="left" />Create Database</a></p> <p><a href="drop_db.php"><img src="drop_ico.png" align="left" />Drop Database</a></p> <p><a href="create_table.php"><img src="status_ico.png" align="left" />Add Table</a></p> <p><a href="add_fields.php"><img src="server_ico.png" align="left" />Add Fields</a></p> <p class="active"><a href="delete_table.php"><img src="status_delete_ico.png" align="left" />Delete Table</a></p> <p><a href="view_tables.php"><img src="user_admin_ico.png" align="left" />View Tables</a></p> <p><a href="view_data.php"><img src="user_admin_ico.png" align="left" />View Table Data</a></p> <p><a href="http://localhost/phpmyadmin/" target="_blank"><img src="phpmyadmin_ico.png" align="left" />phpMyAdmin</a></p> <p><a href="connect_info.php"><img src="health_ico.png" align="left" />System Info</a></p> <p><a href="error_log.php"><img src="logs_ico.png" align="left" />Server Log</a></p> <p><a href="bug_report.php"><img src="bugs-icon.png" align="left" />Bug Reports</a></p> </div> <div id="controls"><a href="javascript:self.close()"><img src="controls.png" /></a></div> <div id="main"> <div id="content"> <?php $temp = $_POST['temp']; $query = "DROP TABLE $temp"; if(mysql_query($query)){ echo "<h1 style='color:green;'>Table $temp deleted</h1>";} else{ echo "<h1 style='color:red;'>Deletion of table '$temp' failed!</h1>";} include("includes/footer.html"); ?> Your help is greatly appreciated!! Similar Tutorialsguys i have this dropdown menu echo "<form method=\"post\" action=\"\">"; echo "<center><select name=\"mydropdown\" size=\"0\" style=\"height:4em; width:15em;\">"; echo "<option value=\"Milk1\">{$_SESSION['tem1']}</option>"; echo "<option value=\"Milk2\">{$_SESSION['tem2']}</option>"; echo "<option value=\"Milk3\">{$_SESSION['tem3']}</option>"; echo "</select></center>"; echo "</form>"; and i wand to update a variable every time i select one of the contents... how can i done this??? hey all so I have this bit down: Code: [Select] $query="SELECT `2010 Region Code` AS codes FROM locations"; $results = mysql_query($query); $options=""; $options = "<select location='codes'>"; while($nt=mysql_fetch_assoc($results)) { $thing=$nt["codes"]; $options.="\r\n<option value ='{$nt['codes']}'> {$nt['codes']}</option>"; } $options .="\r\n</select>"; echo $options; what I'm trying to do is grab the selection from the drop down and display it as a table (the sql query would be extended should we manage to figure this one out I've tried Code: [Select] echo"<form name='LOCATIONS' action='".$_SERVER['PHP_SELF']."' target='iframe' method='post'>"; any ideas? Ok here is what im trying to do: 1. drop down list pulled from mysql database.( working ) 2. after you select the name in the drop down list 3. Use selected name to another page. here is code Code: [Select] <?php include('include/db_connection.inc'); $table = "truck_master"; $result = mysql_query( "SELECT driver_name FROM $table" ); $options=""; while ($row=mysql_fetch_array($result)) { $driver_name=$row["driver_name"]; $options.="<OPTION VALUE=\"driver_name\">".$driver_name.'</option>'; } ?> <html> <head> </head> <body> <table align="center"> <form name="form1" method="GET" align="center" action="issue.php"> <tr> <td>Driver Name :</td> <td><SELECT name="driver_name"><OPTION VALUE=''>Choose<?php echo $options?></SELECT> </td> </tr> <tr> <td><input type="submit" name="Submit" value="Submit"> </td> </tr> </form> </table> </body> <html> Second Code IS Code: [Select] $driver = $_GET['driver_name']; Hi all I am trying to get my drop down menu to use a session variable as the selected menu option. Here's my code: echo "<option value=\"\">Delivery Area</option>"; $selected = ""; if(isset($_SESSION['postal_area']) && $_SESSION['postal_area'] == "England") { $selected = "selected"; } elseif(isset($_SESSION['postal_area']) && $_SESSION['postal_area'] == "Wales") { $selected = "selected"; } elseif(isset($_SESSION['postal_area']) && $_SESSION['postal_area'] == "Scotland") { $selected = "selected"; } else { $selected = ""; } echo " <option value=\"England\" selected=\"".$selected."\">England</option>"; echo "<option value=\"Scotland\" selected=\"".$selected."\">Scotland</option>"; echo "<option value=\"Wales\" selected=\"".$selected."\">Wales</option>"; echo "</select>"; However, this shows the 'Wales' one all the? Please help! Many thanks Pete the same page? User clicks on a url, ie: example.com/AEQ438J When I perform this in the code below: Code: [Select] $referrer = $_GET['_url']; // echo $referrer displays the referrer ID contents correctly as "AEQ438J" if ( ! empty($referrer)) { $mysqli->query("UPDATE coming_soon_emails SET clicks = clicks + 1 WHERE code='" . $referrer ."'"); } // this also updates the database correctly as it should if (!empty($_POST['email'])){ // echo $referrer displays the referrer ID contents as BLANK. It should display "AEQ438J"! ..... $referrer displays correctly BEFORE if($_POST['form']), however during the if($_POST['form']) $referrer is empty. How can I fix my code so that $referrer is not empty during the time the user posts their email address in the form? Thank you! Complete PHP and HTML Code: [Select] <?php require "includes/connect.php"; //var_dump($_GET);die; function gen_code($codeLen = 7) { $code = ''; for ($i=0; $i<$codeLen; $i++) { $d=rand(1,30)%2; $code .= $d ? chr(rand(65,90)) : chr(rand(48,57)); } return $code; } function add_code($email_id) { global $mysqli; $code = gen_code(7); $mysqli->query("UPDATE coming_soon_emails SET code='" . $code ."' WHERE email_id='" . $email_id . "'"); if($mysqli->affected_rows != 1) { add_code($email_id); } else return $code; } $msg = ''; $referrer = $_GET['_url']; // echo $referrer displays the referrer ID contents correctly if ( ! empty($referrer)) { $mysqli->query("UPDATE coming_soon_emails SET clicks = clicks + 1 WHERE code='" . $referrer ."'"); } if (!empty($_POST['email'])){ // echo $referrer displays the referrer ID contents as BLANK // Requested with AJAX: $ajax = ($_SERVER['HTTP_X_REQUESTED_WITH'] == 'XMLHttpRequest'); try{ if(!filter_input(INPUT_POST,'email',FILTER_VALIDATE_EMAIL)){ throw new Exception('Invalid Email!'); } $mysqli->query("INSERT INTO coming_soon_emails SET email='".$mysqli->real_escape_string($_POST['email'])."'"); if($mysqli->affected_rows != 1){ throw new Exception('This email already exists in the database.'); } else { $email_code = add_code($mysqli->insert_id); } $msg = "http://www.example.com/" . $email_code; //the following doesn't work as referrer is now empty :( if ( ! empty($referrer)) { $mysqli->query("UPDATE coming_soon_emails SET signup = signup + 1 WHERE code='" . $referrer ."'"); } if($ajax){ die(json_encode(array('msg' => $msg))); } } catch (Exception $e){ if($ajax){ die(json_encode(array('error'=>$e->getMessage()))); } $msg = $e->getMessage(); } } ?> <!DOCTYPE html> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title></title> <link rel="stylesheet" type="text/css" href="css/styles.css" /> </head> <body> <div id="launch"> <form id="form" method="post" action=""> <input type="text" id="email" name="email" value="<?php echo $msg;?>" /> <input type="submit" value="Submit" id="submitButton" /> </form> <div id="invite"> <p style="margin-top:20px;">The ID of who referred you: <?php echo $referrer; //this displays correctly?>)</p> <p style="margin-top:20px;"><span id="code" style="font-weight:bold;"> </span></p> </div> </div> <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.3/jquery.min.js"></script> <script src="js/script.js"></script> </body> </html> script.js Code: [Select] $(document).ready(function(){ // Binding event listeners for the form on document ready $('#email').defaultText('Your Email Address'); // 'working' prevents multiple submissions var working = false; $('#form').submit(function(){ if(working){ return false; } working = true; $.post("./index.php",{email:$('#email').val()},function(r){ if(r.error){ $('#email').val(r.error); } else { $('#email').val(r.msg); // not needed but gets hidden anyways... $('#launch form').hide(); $("#code").html(r.msg); $("#invite").fadeIn('slow'); } working = false; },'json'); return false; }); }); // A custom jQuery method for placeholder text: $.fn.defaultText = function(value){ var element = this.eq(0); element.data('defaultText',value); element.focus(function(){ if(element.val() == value){ element.val('').removeClass('defaultText'); } }).blur(function(){ if(element.val() == '' || element.val() == value){ element.addClass('defaultText').val(value); } }); return element.blur(); } htaccess Code: [Select] RewriteEngine on RewriteCond %{HTTP_HOST} ^my-url.com RewriteRule (.*) http://www.my-url.com/$1 [R=301,L] RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteRule ^([a-z0-9]+)$ /index.php?_url=$1 [NC,L,QSA] table.sql Code: [Select] CREATE TABLE IF NOT EXISTS `coming_soon_emails` ( `email_id` int(11) NOT NULL auto_increment, `email` varchar(64) collate utf8_unicode_ci NOT NULL, `code` char(7) collate utf8_unicode_ci DEFAULT NULL, `clicks` int(64) collate utf8_unicode_ci DEFAULT 0, `signup` int(64) collate utf8_unicode_ci DEFAULT 0, `ts` timestamp NOT NULL default CURRENT_TIMESTAMP, PRIMARY KEY (`email_id`), UNIQUE KEY `email` (`email`), UNIQUE KEY `code` (`code`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci; Code: [Select] $q = mysqli_query($mysqli, "DROP TABLE IF EXIST 'airline_survey'"); if($q){echo "deleted the table airline_survey....<br>";} else{echo "damm... ".mysqli_error($mysqli);} $mysqli is my connection and it works I had no trouble creating the table but I decided to add these few lines in front of the code to create the table and I get this error. damm...You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'EXIST 'airline_survey'' at line 1 I gotta believe this is really simple but it's got me stumped. Hey guys, I made in php an sql droplist. But I need some help. I want it to work like this. When I select something from the list and click Add To Cart, that also the product gets send to the cart and not only the quantity. you can check it out here : http://fhcs.be/cart-demo2/index.php I also added my index.php as an attachment Greets Hey, I have a mysql table for my setups, it contains basically three fields: 'id','variable','value'. i want to create/name a variable from a result from the database and then from another field it should give the newly created variable its value The table is already filled with the variables i want to use, now i just want my index page to get the different variable out of the table with the value as its value. Is that even possible? so lets say i have a variable in my table called 'header_color' the value in that table row is 'FFF' i want my index to get all variable from the database (through a while??) with again its value as a value. This is my thought: $sql = mysql_query("SELECT * FROM setup"); while ($res = mysql_fetch_array($sql)){ $res[variable]; = $??my_variable??; $myvariable = $res[value]; } and so when i have my div for my header i want it to be <div style="background-color:#<?=$header_color?>"> resulting in <div style="background-color:#FFF> in my table under variable it has the name "header_color" and under value "FFF" maybe i need to create an array or something i have no idea. Hope you guys can help me. Name says it all. I have a form and 2 tables that are going to have to be linked with each other. Although what I'm trying to do now is very basic and I'm struggling haha Though this is my first php project Basicly I got a form with a drop down menu, which I want to display the contents of my table (course) which the user then selects from and submits to another table (student) Here is my code for this part <?php Code: [Select] <?php $q = "SELECT cname FROM course "; $result = mysql_query($q); $course = mysql_fetch_array($result); ?> <div id="apdiv3"> <FORM action = "demo.php" method ="post"> <p>Course name:</p> <select name="cname"> <OPTION> <?php echo $course['cname']; ?> </option> </SELECT>?> It only displays 1 item from my course table. What am I doing wrong? And also please explain so I can learn from my mistakes Hi, I wonder if I somebody can help me I have three drop down lists which are populated from data thats stored in my sql database. I also have a table which is echoed from the database all on the same page. What i want to do is allow users to select values in the drop down lists which will then echo different results below in the table. Is this possible. So on page load it will show all of the info in the html table. Then when the user changes the drop downs and clicks submit it will change the query to something SELECT dropdown1 value FROM users where Dropdown2 = 1 AND Dropdown3 = 2 etc. Is this possible to display this information on the same page using the dropdown list or does it need to load a different page as the client side is trying to edit a server side script? If its possible please can someone give me an example. Thanks in advance Edd <?php function money($amount,$separator=true,$simple=false){ return (true===$separator? (false===$simple? number_format($amount,2,'.',','): str_replace('.00','',money($amount)) ): (false===$simple? number_format($amount,2,'.',''): str_replace('.00','',money($amount,false)) ) ); } $income = 5000000000; $daily = money($income*24,true,true); $weekly = money(($income*24)*7,true,true); $monthly = money((($income*24)*7)*30,true,true); ?> </center> <center> <table border="1"> <tr> <td>Daily</td> <td><?php echo $daily ?></td> </tr> <tr> <td>Weekly</td> <td><?php echo $weekly ?></td> </tr> <tr> <td>Monthly</td> <td><?php echo $monthly ?></td> </tr> </table> </form> </center> What am I doing wrong? Im fairly new to this I have a dropdown menu <td width="148" height="35" valign="top"><b>Type: </b> </td> <td><select name ="tabledrop"> <option value="goggles">goggles</option> <option value="headbands">headbands</option> <input type='hidden' id='tabledrop' name='tabledrop' value = ''/> </select> </td> those 2 options are actually names of my tables. I tried this and got some syntax error. $type = $_POST['tabledrop']; $item = $_POST['goggles_name']; $price = $_POST['goggles_price']; $file = $_FILES['goggles_image']['name']; $query = "INSERT into $type SET [$type]_name = '$item' , [$type]_price = '$price' , [$type]_image = '$file'"; Hello, I'm working on a PHP register form, all I want to do, is to be able to insert an extra variable into the database: Code: [Select] // now we insert it into the database $insert = " INSERT INTO users (username, password) VALUES ('".$_POST['username']."', '".$_POST['pass']."') "; $add_member = mysql_query($insert); right, so I have the username and password variable being passed. But I also want to pass a variable into a column called 'weaponAttachments', all I want for this variable to be is 5000. So, in other words, something like this: 5000['weaponAttachments'] Thanks Hi, i cant seem to get something working, should be simple but its not working for me. I just need to only display a table if a variable in my table = a certain value. The column in the table is called 'option1_available' and if its value is set to 'Y' i want it to display a table. Appreciate any help, Thanks This is what i have.. I basicly need to take the Make and Model And Year Not the TYPE that needs to be left out and combine them into a drop down list. So example below would be like this Yamaha WR450F 2003-2006 Yamaha YZ450F 2003-2005 Code: [Select] <table> <tr> <th>Type</th> <th>Make</th> <th>Model</th> <th class='tar'>Year</th> </tr> <tr class='even'> <td>Offroad</td> <td>Yamaha</td> <td>WR450F</td> <td class='tar'>2003-2006</td> </tr> <tr class='odd'> <td>Offroad</td> <td>Yamaha</td> <td>YZ450F</td> <td class='tar'>2003-2005</td> </tr> </table> I am working on a project that uses a drop down list to chose the category when inserting new data into the database. What I want to do now is make the drop down list default to the chosen category on the list records page and the update page. I have read several tutorials, but they all say that I have to list the options and then select the default. But since it is possible to add and remove categories, this approch won't work. I need the code to chose the correct category on the fly. There are two tables, one that has the category ID and category name. The second table has the data and the catid which is referenced to the category id in the first table. Code: [Select] -- -- Table structure for table `categories` -- DROP TABLE IF EXISTS `categories`; CREATE TABLE IF NOT EXISTS `categories` ( `id` int(11) NOT NULL AUTO_INCREMENT, `categories` varchar(37) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=40 ; -- -------------------------------------------------------- -- -- Table structure for table `links` -- DROP TABLE IF EXISTS `links`; CREATE TABLE IF NOT EXISTS `links` ( `id` int(4) NOT NULL AUTO_INCREMENT, `catid` int(11) DEFAULT NULL, `name` varchar(255) NOT NULL DEFAULT '', `url` varchar(255) NOT NULL DEFAULT '', `content` varchar(255) NOT NULL DEFAULT '', PRIMARY KEY (`id`), KEY `catid` (`catid`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=35 ; Then is the list records file, I have Code: [Select] <?php include ("db.php"); include ("menu.php"); $result = mysql_query("SELECT categories FROM categories") or die(mysql_error()); while ($row = mysql_fetch_array($result)) { $categories=$row["categories"]; $options.= '<option value="'.$row['categories'].'">'.$row['categories'].'</option>'; }; $id = $_GET['id']; $query="SELECT * FROM links ORDER BY catid ASC"; $result=mysql_query($query); ?> <table width="65%" align="center" border="0" cellspacing="1" cellpadding="0"> <tr> <td> <table width="100%" border="1" cellspacing="0" cellpadding="3"> <tr> <td colspan="7"><strong>List data from mysql </strong> </td> </tr> <tr> <td align="center"><strong>Category ID</strong></td> <td align="center"><strong>Category ID</strong></td> <td align="center"><strong>Name</strong></td> <td align="center"><strong>URL</strong></td> <td align="center"><strong>Content</strong></td> <td align="center"><strong>Update</strong></td> <td align="center"><strong>Delete</strong></td> </tr> <?php while($rows=mysql_fetch_array($result)){ ?> <tr> <td> <SELECT NAME=catid> <OPTION>Categories</OPTION> <?php echo $options; ?> </SELECT> </td> <td><? echo $rows['catid']; ?></td> <td><? echo $rows['name']; ?></td> <td><a href="<? echo $rows['url']; ?>"><? echo $rows['url']; ?></a></td> <td><? echo $rows['content']; ?></td> <td align="center"><a href="update.php?id=<? echo $rows['id']; ?>">update</a></td> <td align="center"><a href="delete.php?id=<? echo $rows['id']; ?>">delete</a></td> </tr> <?php } ?> </table> </td> </tr> </table> <?php mysql_close(); ?> So, how do I get this code Code: [Select] $result = mysql_query("SELECT categories FROM categories") or die(mysql_error()); while ($row = mysql_fetch_array($result)) { $categories=$row["categories"]; $options.= '<option value="'.$row['categories'].'">'.$row['categories'].'</option>'; }; <SELECT NAME=catid> <OPTION>Categories</OPTION> <?php echo $options; ?> </SELECT> to give me an output that will be something like if catid exactly matches categories.id echo categories.categorie ??? so far everything I have done produces either a default category of the last category, the catid (which is a number), all of the categories (logical since catid will always be = id, or nothing. How do I get just the category name? I will keep reading and try to figure this out, but any help would be greatly appreciated. Thanks in advance Good evening,
I am working on a program that takes images, and casts them into an associated array, I then want to display thumbnails of those images into a 3 column by 4 row table...
[image][image][image]
[image][image][image]
[image][image][image]
[image][image][image]
(For my visual friends)
here is my current, pardon for the mess, but right now, functionality is more important.
<!DOCTYPE html>
<html>
<head>
<title>Zodiac Gallery</title>
</head>
<body>
<h2 style="text-align:center">Zodiac Gallery</h2>
<p>Click a thumbnail image to see enlarged view.</p>
<?php
$ZodiacArray = array (
"Images/rat.jpg" => "Rat",
"Images/ox.jpg" => "Ox",
"Images/tiger.jpg" => "Tiger",
"Images/rabbit.jpg" => "Rabbit",
"Images/dragon.jpg" => "Dragon",
"Images/snake.jpg" => "Snake",
"Images/horse.jpg" => "Horse",
"Images/goat.jpg" => "Goat",
"Images/monkey.jpg" => "Monkey",
"Images/rooster.jpg" => "Rooster",
"Images/dog.jpg" => "Dog",
"Images/pig.jpg" => "Pig");
foreach ($ZodiacArray as $image => $zodiac)
{
echo "<table>
<tr>
<td><img src="$image" alt="$zodiac" style="width:68px;height:65px"></td
<td><img src="$image" alt="$zodiac" style="width:68px;height:65px"></td>
<td><img src="$image" alt="$zodiac" style="width:68px;height:65px"></td>
</tr>
<tr>
<td><img src="$image" alt="$zodiac" style="width:68px;height:65px"></td>
<td><img src="$image" alt="$zodiac" style="width:68px;height:65px"></td>
<td><img src="$image" alt="$zodiac" style="width:68px;height:65px"></td>
</tr>
<tr>
<td><img src="$image" alt="$zodiac" style="width:68px;height:65px"></td>
<td><img src="$image" alt="$zodiac" style="width:68px;height:65px"></td>
<td><img src="$image" alt="$zodiac" style="width:68px;height:65px"></td>
</tr>
<tr>
<td><img src="$image" alt="$zodiac" style="width:68px;height:65px"></td>
<td><img src="$image" alt="$zodiac" style="width:68px;height:65px"></td>
<td><img src="$image" alt="$zodiac" style="width:68px;height:65px"></td>
</tr>
</table>";
?>
Help is welcome, thank you.
Hello guys, I do not know if anyone work or have worked with the "elFinder (file manager)" .. I incorporate "elFinder" to my platform .. and have the following question .. Have its connector: Code: ------------------------------------- //za screen imeto function clean($string) { $string = str_replace(' ', '-', $string); // Replaces all spaces with hyphens. $string = preg_replace('/[^A-Za-z0-9\-]/', '', $string); // Removes special chars. return preg_replace('/-+/', '-', $string); // Replaces multiple hyphens with single one. } //end $srvname = mysql_real_escape_string(trim($_POST['servername'])); //ime na servera $port = (int)$_POST['ports']; //port na servera $ip = mysql_real_escape_string(trim($_POST['serverip'])); //serverip $screen = clean($srvname).$port.'_'.uniqid(); //screen imeto mysql_query("INSERT INTO server (screen) VALUES('$screen')") or die(mysql_error()); $opts = array( 'locale' => 'en_US.UTF-8', 'bind' => array( // '*' => 'logger', 'mkdir mkfile rename duplicate upload rm paste' => 'logger' ), 'debug' => true, 'roots' => array( array( 'driver' => 'LocalFileSystem', 'path' => ''.$screen.'', 'startPath' => ''.$screen.'', 'URL' => dirname($_SERVER['PHP_SELF']) . ''.$screen.'', // 'treeDeep' => 3, // 'alias' => 'File system', 'mimeDetect' => 'internal', 'tmbPath' => '.tmb', 'utf8fix' => true, 'tmbCrop' => false, 'tmbBgColor' => 'transparent', 'accessControl' => 'access', 'acceptedName' => '/^[^\.].*$/', // 'disabled' => array('extract', 'archive'), // 'tmbSize' => 128, 'attributes' => array( array( 'pattern' => '/\.js$/', 'read' => true, 'write' => false ), array( 'pattern' => '/^\/icons$/', 'read' => true, 'write' => false ) ) // 'uploadDeny' => array('application', 'text/xml') ), -------------------------------------- It doesn't work.. I need help for connect to the variable "$screen".. How can call the "table $screen" ? "table $screen": folders are automatically created by users Regards, Joob Hello, I am working on a project and I cant seem to get this to work. I have a database (Kingsbury) that stores a contact list. I am trying to make an page were a user can search the database by state. The code from the HTML site is: Code: [Select] <form action = "sqlllist.php" method="post"><br /> Please enter the state you would like to search: <input type="text" name="state" /><br /> <p><input type="submit" value="Enter" /></p> </form> And then from the .php file Code: [Select] <?php $DBConnect = mysql_connect("*****", "*****", "********"); if ($DBConnect===FALSE) echo "<p>Connection Failed!.</p>\n"; else { $State == $_POST['state']; $Result = mysql_select_db("Kingsbury", $DBConnect); $queryresult = @mysql_query("SELECT * FROM contacts WHERE State = $State'", $DBConnect); echo "<table width='100%' border='1'>\n"; echo "<tr><th>User ID</th> <th>First Name</th> <th>Last Name</th> <th>Address</th> <th>State</th> <th>City</th> <th>Zip Code</th> <th>Area Code</th> <th>Phone Number</th>\n"; While (($Row = mysql_fetch_row($queryresult)) !== FALSE) { echo "<tr><td>{$Row[0]}</td>"; echo "<td>{$Row[1]}</td>"; echo "<td>{$Row[2]}</td>"; echo "<td>{$Row[3]}</td>"; echo "<td>{$Row[4]}</td>"; echo "<td>{$Row[5]}</td>"; echo "<td>{$Row[6]}</td>"; echo "<td>{$Row[7]}</td>"; echo "<td>{$Row[8]}</td>"; } echo "</table>\n"; mysql_free_result($queryresult); mysql_close($DBConnect); } ?> This, to me seems like it should be working, but it outputs the entire database. |
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