PHP - How Do I Fetch A Current Visitors Ip Address, And Turn It Into A Variable?

Hello! Once again, I find myself in the need of help regarding PHP.

What I have is a URL that looks like this:
http://domain.com/gallery/?album=3&gallery=65

What I need is to extract the number that comes after "album=". In this case, it would be the number 3.

I currently have this:
<?php $url=getPageURL(); $var=explode('album=',$url); $var=explode('?',$var[1]); ?>

My problem is that it doesn't result in anything.

Can anyone lend a hand? :) It would be much appreciated.

Morning all,

I am wondering whether there is a way (I am sure there is!) to extract the full website address with any GET variables in it also.

Basically, I am trying to extract the website address and add another $_GET['var'] to it.

Something like.

example web address:  http://www.website.com/index.php?type=abc

<?php
$address = // Extract the current website address here.
$newvar = "?model=123";
$link = $address.$newvar;

echo '<a href="$link">Click here to add a variable</a>';
?>

This topic has been moved to MySQL Help.

http://www.phpfreaks.com/forums/index.php?topic=342459.0

i wanting users to be able to update there email address and check to see if the new email already exists. if the email is the same as current email ignore the check.
i have no errors showing up but if I enter a email already in the db it still accepts the new email instead of bringing the back the error message.
Code: [Select]
// email enterd from form //
$email=$_POST['email'];


$queryuser=mysql_query("SELECT * FROM members WHERE inv='$ivn' ") or die (mysql_error());
 while($info = mysql_fetch_array( $queryuser )) {
  $check=$info['email'];
 // gets current email //
}


if($check!=$email){
// if check not equal to $email check the new email address already exists//
$queryuser=mysql_query("SELECT * FROM members WHERE email='$email' ");
//$result=mysql_query($sql);
$checkuser=mysql_num_rows($queryuser);
if($checkuser != 0)
{
$error= "0";
header('LOCATION:../pages/myprofile.php?id='.$error.'');


}
}

cheers

I have a form with PHP validation and also a mysqli query checking for duplicates in the database for mailing address and email address in mysql.     It works fine but the customers are adding spaces in the mailing address for example  111 mailing address A V  E, 1 1 1 ma iling address A V  E etc.  and my sql query doesn't see that as an address that's a duplicate.    Their alslo adding email address like my@emailaddress.com and m.y@emailaddress.com, m.y.2@emailaddress.com etc to bypass that comparision also.    Is there anyway to stop this from happening?        

Hi,

I'm wanting to find rows whose date is within the next week of the current month of the current year. The format of the date is, for example: 2010-10-28

Any ideas guys?

Thanks lots!

Hi i have this drop down list current the year is 2010 and downwards but i want to change the list to 2010 upwards u can notice on the 50-- so shows current year minus so current is 2010 to 61 how can i change 2010 to 2030 or sunfin??

echo '<select name="year_of_birth">',"\n";
    $year = date("Y");
    for ($i = $year;$i > $year-50;$i--) {
      if($i == $thisYear) { 
        $s = ' selected'; 
      } else { 
        $s='';
      }
      echo '<option value="' ,$i, '"',$s,'>' ,$i, '</option>',"\n";
    }
  echo '</select>',"\n";

Is there any way to only log real visitors, and not get robots?

<?php
    define("DATE_FORMAT","m-d-Y - H:i:s");
    define("LOG_FILE","/full_path/logs.shtml");

    $logfileHeader='DATE - IP - HOSTNAME - BROWSER - URI - REFERRER'."\n";

    $userAgent = (isset($_SERVER['HTTP_USER_AGENT']) && ($_SERVER['HTTP_USER_AGENT'] != "")) ? $_SERVER['HTTP_USER_AGENT'] : "Unknown";
    $userIp    = (isset($_SERVER['REMOTE_ADDR'])     && ($_SERVER['REMOTE_ADDR'] != ""))     ? $_SERVER['REMOTE_ADDR']     : "Unknown";
    $refferer  = (isset($_SERVER['HTTP_REFERER'])    && ($_SERVER['HTTP_REFERER'] != ""))    ? $_SERVER['HTTP_REFERER']    : "Unknown";
    $uri       = (isset($_SERVER['REQUEST_URI'])     && ($_SERVER['REQUEST_URI'] != ""))     ? $_SERVER['REQUEST_URI']     : "Unknown";

    $hostName   = gethostbyaddr($userIp);
    $actualTime = date(DATE_FORMAT);

    $logEntry = "$actualTime - $userIp - $hostName - $userAgent -  <A HREF='http://www.domain.org$uri' TARGET='_blank'>http://www.domain.org$uri</a> - <A HREF='$refferer'>$refferer</a>\n";

    if (!file_exists(LOG_FILE)) {
        $logFile = fopen(LOG_FILE,"w");
        fwrite($logFile, $logfileHeader);
    }
    else {
        $logFile = fopen(LOG_FILE,"a");
    }

    fwrite($logFile,$logEntry);
    fclose($logFile);
?>

This topic has been moved to MySQL Help.

http://www.phpfreaks.com/forums/index.php?topic=349293.0

hey guys,

I am looking for a way to find out information about the referring site a user clicked through to get to my site.  Is that possible and if so, How?

Ideally, I am looking for:
Site Domain Name
The referral URL
Meta information of the page

I believe I can get this stuff from analytics software, but I am trying to think of a way to do it in my own script.  Is it possible and does anyone have any ideas to point me in the right direction?

thanks

Hi, I want to show one image for the new visitors of my website and another for the returning visitors. What I want to do is that after the visitor reload the page he will see another image instead of the first one.  

Hello to all!   I ask myself the following question: Is there a way that is better to calculate the number of members / guests online 

Hello PHPers,

One more help I think may be wrong.  I currently have code as $_GET['width'] . "x" . $_GET['height'];.  This provides continually with 640 * 480. 

 believe this to be incorrect as I do not think that everyones screen is set to this.  Neither is my screen resolution and is still capturing these figures.

Is there something wrong with the variable that should be changed so that it can pick up the visitors screen resolution.
Thank you kindly,
HJ

I'm assuming this has something to do with cookies, which I am not to familiar with as I am pretty new to this PHP world and have mostly worked with wordpress... but this question was brought up to me, and I don't know where to start.

If a user is signed up for the mailing list on a site, we would like the home page the user lands on to be different than the page a new visitor who isn't signed up for the mailing list would see. I have tried to google this, but maybe I am using the wrong choices of words?

Any advice, links, etc would be so so soooo appreciated.   

Thanks
V