PHP - Basic Oop Question

probably a very stupid question, but i pose it because it's counterintuitive for me to write it:

i find in alot of wordpress code if statements like:

if ( false === $var)

i suppose it's the same as if ( $var === false) ? why would one right it in the first way?

I'm guessing this is more of a hosting/mail question than specifically php, but here goes...

I have this very basic code to send a test email:


<?php
$to = 'me@mydomain.com';
$subject = 'Test email'; 
$message = "Hello World!"; 
$mail_sent = mail( $to, $subject, $message);
echo $mail_sent ? "Mail sent" : "Mail failed";
?>


and the following in my php5.ini:

Quote

[mail function]
SMTP = relay-hosting.secureserver.net
sendmail_from = admin@malvernaquarium.com




When the mail is received, it's showing as coming from "auserid@p3nlh263.shr.prod.phx3.secureserver.net".

How can I get this to show as something more reasonable and related to my domain?  Ideally something more like admin@malvernaquarium.com.

Thanks in advance!

Greg

sorry guys its been a long day and this is an extreme newbie question but for whatever reason right now I cant wrap my head around the concept right now...
say for instance one wanted to make a db for job postings, where one could go and see many different categories etc etc. Would you create a table "jobs" and then create rows for the types ie) Accounting, Business, Customer Service, etc. - or would those be all seperate tables as well? Cause im just thinking of the INSERT INTO query, and say I wanted to add a job but I only wanted to add one to the Customer service portion of the jobs table...thats why im curious if everything should be different tables so you could just do INSERT INTO customer_service etc etc and then have all of the persons names/creditials there? OR is it possible to create a table within a table? or am I simply going nuts here? lol. thanks

I just want to ask the logic of making a chatroom.
Is it correct if i prepare a table in MYSQL, php script to submit whatever words typed and use AJAX to refresh every second to be sure that all input displayed

thanks

I have several fields in a database in which some could be blank. I'd like to echo out 'Not Assigned' if that's the case. Based on my limited experience with PHP this is the way I'm going about it:

Code: [Select]
if ($tech == "") {
$tech = "Not Assigned";
}

if ($crew == "") {
$crew = "Not Assigned";
}

if ($number == "") {
$number = "Not Assigned";
}

I'm pretty certain there is a way to simply place all of the variables into an array to determine if they are empty or not - Followed by changing the variable to 'Not Assigned' one time rather then repeating code over and over again. The way I'm doing it will work, however, something tells me there is a much more efficient way.

Hello!   I'm newbie in PHP(started 3 days ago), and i have two questions about the same topic, i hope you can answer me.   1- Is there methods in php for interaction with webpages as javascript, as they simulate a user interacting with these pages? For example, the method click () or the getElementsByClassName () for you to find something specific on the page. There are methods that do this in php?   2- To interact with a website using a sript (to click on links or save the url of pictures in an array) i start "JavaScript Scratchpad" Firefox with Shift + f4 and then it runs the script there, is just be on the page i want. If i want to do something similar in php, how can i run this script on my browser or is it done another way?   Thanks!

I have inherited some pages from someone else who wrote them and as I am a newbie and the code is quite old I suspect it needs to be updated in order to work.

I have two variables $p and $service that were passed from page 1 to page 2 via the URL.  On page 2 I have updated the code for echo $_GET['$p'] etc and I am happy with that.

Lower down on page 2 within an HTML form the author has

Code: [Select]
<input type="hidden" name="service" value="<?
echo $service;
?>" />

<input type="hidden" name="p" value="<?
echo $p;
?>" />
with the intention of putting these variables in the URL for page 3 I have to assume.

Page 3 begins with this code

Code: [Select]
"completeyourorder.php?p=" . $p . "&service=" . $service;
but the variable values are not showing up in the URL and I can not seem to use them on page 3.  In other words they don't seem to be available to me.

I'd appreciate help to change the page 3 code above or the page 2 code so that it works as intended.  I found some posts and researched tutorials but all that I have tried has not worked.

Thanks
Glenn

Hi,

I just started learning PHP... Below is my first programme infact..

Out put is not coming when i type some thing in input boxes...

Can somebody suggest where is the error...

Index.php

<html>
<head>
<title>Welcome to our site</title>
</head>
<body>

<form method="POST" action="submit.php">
<label for ="business_name">Business name</label>
<input type="text" id="business_name" \><br/>
<label for ="contact_person">Contact person</label>
<input type="text" id="contact_person" \><br/>
<label for ="Telephone">Telephone</label>
<input type="text" id="Telephone" \><br/>
<label for ="FAX">FAX</label>
<input type="text" id="FAX" \><br/>
<label for ="Mobile">Mobile</label>
<input type="text" id="Mobile" \><br/>
<label for ="Addres_line_1">Addres_line_1</label>
<input type="text" id="Addres_line_1" \><br/>
<label for ="Addres_line_2">Addres_line_2</label>
<input type="text" id="Addres_line_2" \><br/>   
<label for ="Addres_line_3">Addres_line_3</label>
<input type="text" id="Addres_line_3" \><br/>
<label for ="Addres_line_4">Addres_line_4</label>
<input type="text" id="Addres_line_4" \><br/>
<label for ="City">City</label>
<input type="text" id="City" \><br/>
<label for ="Pin_code">Pin_code</label>
<input type="text" id="Pin_code" \><br/>
<label for ="State">State</label>
<input type="text" id="State" \><br/>
<label for ="email">email</label>
<input type="text" id="email" \><br/>
<input type="submit" value="Please submit the details" name="submit"/>
</form>


</body>
</html>   

submit.php



<head><title>Your submission details</title></head>
<body>
<H3>YOU HAVE SUBMITTED THE FOLLOWING DETAILS</H3>
<?php

$business_name= $_POST["business_name"];
$contact_person = $_POST["contact_person"];
$Telephone = $_POST["Telephone"];
$fax = $_POST["FAX"];
$mobile = $_POST["Mobile"];
$address1 = $_POST["Addres_line_1"];
$address2 = $_POST["Addres_line_2"];
$address3 = $_POST["Addres_line_3"];
$address4 = $_POST["Addres_line_4"];
$city = $_POST["City"];
$pincode = $_POST["Pin_code"];
$state = $_POST["State"];
$email = $_POST["email"];

echo "Your business name".$business_name.'<br/>';
echo "Contact person".$contact_person.'<br/>';
echo "Telephone no.".$Telephone.'<br/>';
echo "Fax No.".$fax.'<br/>';
echo "Mobile No.".$mobile.'<br/>';
echo "Address line one".$address1.'<br/>';
echo "Address line two".$address2.'<br/>';
echo "Address line three".$address3.'<br/>';
echo "Address line four".$address4.'<br/>';
echo "Your City".$city.'<br/>';
echo "Your Pincode".$pincode.'<br/>';
echo "Your State".$state.'<br/>';
echo "Your email".$email.'<br/>';
?>
<a href=index.php>Home</a>
</body>
</html>

<?php
if (!isset($_GET['register'])) {
echo "register stuff here"; 
}
elseif (!isset($_GET['login'])) {
echo "login stuff here";
}
elseif (!isset($_GET['forgotpassword'])) {
echo "password recovery stuff here"; 
}
else {
echo "default page stuff here"; 
}
?>

you get what i'm going for, but it kinda messes up this way with different contents on different places? help

OK, I think this is easy, but I just can't seam to get it figured out.

I have this piece of code

echo '<img src="maps/' . $map . '.jpg" />';

And what I want to do is if that $map is not in the directory I want it to display a standard image that I know is in the directory.

So basically I want the alt tag to be a image instead of text.

I got a script that receive info from paypal "ipn" when someone is making a payment from my shop. I wanted to edit the script a bit as i am adding a bonus system to it.
After i added

Quote

// Bonus system vars

                    if ($item_name == '301') { $point == "1"; }
                   elseif  ($item_name == '302') { $point == "2"; }
                   elseif  ($item_name == '303') { $point == "3"; }
                   elseif  { $point == "0"; }




And
Quote

                        $bonus1 = "update Bonus set points=points+'$points' where username='$username'";
                        mysql_query("$bonus1");
                        
                        $bonus2 = "update Bonus set points_total=points_total+'$points' where username='$username'";
                        mysql_query("$bonus2");
                        
                        $bonus3 = "update Bonus set $item_name=$item_name+1 where username='$username'";
                        mysql_query("$bonus3");
 


The script wont work. But it does when i remove those things. I think my problem is at the if,elseif i just dont know why.  Do i need to put it in some kind of while loop?


Here is the full php code

Code: [Select]

mysql_connect('xxxxx', 'xxxx', 'xxxxxx');
$notify_email =  "xxxx@xxxx";

// read the post from PayPal system and add 'cmd'
$req = 'cmd=_notify-validate';

foreach ($_POST as $key => $value) {
        $value = urlencode(stripslashes($value));
        $req .= "&$key=$value";
}

// post back to PayPal system to validate
$header = "POST /cgi-bin/webscr HTTP/1.0\r\n";
$header .= "Content-Type: application/x-www-form-urlencoded\r\n";
$header .= "Content-Length: " . strlen($req) . "\r\n\r\n";
$fp = fsockopen ('www.paypal.com', 80, $errno, $errstr, 30);

// assign posted variables to local variables
$item_name = $_POST['item_name'];
$item_number = $_POST['item_number'];
$payment_status = $_POST['payment_status'];
$payment_amount = $_POST['mc_gross'];
$payment_currency = $_POST['mc_currency'];
$txn_id = $_POST['txn_id'];
$receiver_email = $_POST['receiver_email'];
$payer_email = $_POST['payer_email'];
$buyer_firstname = $_POST['first_name'];
$buyer_lastname = $_POST['last_name'];
$timestamp = $_POST['payment_date'];
$address_street = $_POST['address_street'];
$address_city = $_POST['address_city'];
$address_state = $_POST['address_state'];
$address_zip = $_POST['address_zip'];
$username = $_POST['custom'];


// Bonus system vars

     if ($item_name == '301') { $point == "1"; }
elseif  ($item_name == '302') { $point == "2"; }
elseif  ($item_name == '303') { $point == "3"; }
elseif  { $point == "0"; }


mysql_select_db('redlite');

if (!$fp) {
        // HTTP ERROR
} else {
        fputs ($fp, $header . $req);
        while (!feof($fp)) {
                $res = fgets ($fp, 1024);
                if (strcmp ($res, "VERIFIED") == 0) {
                        if ($payment_status == 'Completed') {
                                $sql = "insert into tblMail values ('','$txn_id','$payer_email',' $item_name','$timestamp','','','','$payment_amount $payment_currency','$buyer_firstname $buyer_lastname','$address_street  $address_city , $address_state $address_zip','','','$username')";
                                mysql_query("$sql");
                               



$bonus1 = "update Bonus set points=points+'$points' where username='$username'";
mysql_query("$bonus1");

$bonus2 = "update Bonus set points_total=points_total+'$points' where username='$username'";
mysql_query("$bonus2");

$bonus3 = "update Bonus set $item_name=$item_name+1 where username='$username'";
mysql_query("$bonus3");

                                $ttlpay_sql = "update totalpay set total=total+'$payment_amount' where id='1'";
                                mysql_query("$ttlpay_sql");
                                mail($notify_email, "CLVerified", "$res\n $req");
                        } else {
                                mail($notify_email, "CLVerified - But not completed". "$res\n $req");
                        }
                }
                else if (strcmp ($res, "INVALID") == 0) {
                        mail($notify_email, "CLINVALID IPN", "$res\n $req");

                }
        }
        fclose ($fp);
}
?>

Hello there,

I'm very new to PHP and I need some help (please!)

Basically I'm writing an actionscript application and I am using a php file to save an image to the server, the problem is I define a name in actionscript before I send the information to the php and it continuously saves over the same file..

Ideally I would like to attach the (jpg) image to an email, send the mail and delete the image ready for a new image to be created.. is this possible ?

At least, I would like to add a +1 to each filename to stop the file being saved over continuously !

Thanks in advance for any help


<?php
   
   $fileName = $_GET['filename'];
   
   $fp = fopen( $fileName, 'wb' );
   
   fwrite( $fp, $GLOBALS['HTTP_RAW_POST_DATA'] );    
   
   fclose( $fp );
  
?>

Hey y'all,

I'm trying to write a PHP script for a login function. There are three elements, two text fields (username and password) and a button which calls the script.

Segment from index.php file:
<form action = "login.php" method = "POST">
Admin Login: <br>
   Username: <input type = "text" name = "usernameField"/><br> <!-- Password field-->
   Password: <input type = "password" name = "passwordField"/><br> <!-- Username field -->
           <input type = "button" value = "Login"  name = "submitButton"/> <!-- Login button -->
</form>

Segment from login.php file:
<?php
$connect = mysql_connect("localhost", "root", "root");

if(!$connect){//If user can't connect to database
   die('Could not connect: ' . mysql_error()); //Throw an error
}

mysql_select_db("colin_db", $connect);
//Get given username and password from username field and password field
$givenUsername = $_POST["usernameField"];
$givenPassword = $_POST["passwordField"];


$myQuery = "SELECT * FROM ADMINS
         WHERE USERNAME = '$givenUsername'
         AND PASSWORD = '$givenPassword'";

$queryResult = mysql_query($myQuery);
$numRows = mysql_num_rows($queryResult);

if($numRows == 1){ //If the details are correct...
//Reload the page and login
echo "<script type = 'text/javascript'> window.location.reload() </script>";
}
elseif($numRows == 0){    //Else if the details are not found
//Display error accordingly
echo "Details not correct!";
}
mysql_close($connect);
?>

The problem is, when I click the login button, it doesn't do anything. What am I missing? (The information in the database is correct)

Thanks,

Jake

Hi, Im learning php, but Im a bit confused on this basic problem.

I have the following code:

<?php
include "tax.php";
$price = 95;
echo "Price before tax: $price <br>";
echo "Price after tax: ";
echo add_tax ($price);
?>


Which uses the function below

<?php
function add_tax ($amount) {
     $total = $amount * 1.09;
     return $total;
}
?>

When I execute the code I can see that it does work, but I do not understand why this part works!

echo add_tax ($price);   

There is no multiplier symbol here, so is the function performed on the ($price) variable simply because of where it is located on this line of code?   Thanks

Okay,

So I'm trying to write a query that will update a certain value in my database, but I want it to update only when 3 conditions are met.  Basically, I want to update a column of ints in my DB (mysql) from 0 to a 1, if these criteria are met.  0 and 1 are the only values that are valid in this particular column. 

dbquery("UPDATE times SET approval = '1' WHERE id = '$id' AND time <= '$currentTime' AND project = '$project'");

that is my query.  Now, I'm not even sure if THIS part works.  It is however, slightly more complicated in that this query is actually embedded in a foreach loop:

$result = $_REQUEST["projects"];
$delimiter - ",";
$projectArray = explode($delimiter, $result);

foreach($projectArray as $project){
    dbquery("UPDATE times SET approval = '1'
                   WHERE id = '$id'
                   AND time <= '$currentTime'
                   AND project = '$project'");
}

If you can make any sense of that, and if you can point out any glaringly obvious mistakes here, I would appreciate it.  If you need any other information let me know.  Thank you all for your help.