PHP - Call Public Function In Another Public Function
How can I call a public function inside of another public function? The get_primary_edge() says it's undefined, but it's just another public function in the class so shouldn't this work?
Code: [Select] public function get_dynamic_edge($uid) { $uid = (int)$uid; $sql = "( SELECT `users`.`id` FROM partners INNER JOIN `users` ON `partners`.`user_id` = `users`.`id` WHERE partners.friend_id = '${uid}' AND `approved` = 1 ) UNION ALL ( SELECT `users`.`id` FROM `partners` INNER JOIN `users` ON `partners`.`friend_id` = `users`.`id` WHERE `partners`.`user_id` = '${uid}' AND `approved` = 1 )"; $result = mysql_query($sql) or die(mysql_error()); $i = 0; while (($row = mysql_fetch_assoc($result)) !== false) { $dynamic[$i] = array( 'uid' => $row['id'], 'score' => get_primary_edge($row['id']), ); $i++; } print_array($dynamic); } Similar TutorialsI have the following static method: public static function query($query){ self::$num_queries++; return mysql_query($query)or die(mysql_error()); } I then call it like this: $oql = Mysql::query("SELECT first FROM members WHERE member_id = '{$this->owner}'"); $rql = mysql_fetch_assoc($oql); I then get the following error: Quote Warning: mysql_fetch_assoc(): supplied argument is not a valid MySQL result resource in /incl/php/classes/Photo.php on line 13 Why am I getting this error? I'm learning MVC and getting a bit confused with the accessibility of variables in classes... Code: [Select] class Load { public $load2; } Does this mean that the variable $load2 will be accessible just by all functions within the class Load? or: Does that mean that the variable $load2 will be accessible by all other classes, eg model, controller...etc inc all the functions within? Hi i created a website where you cam view ip webcams via php. I want to make it so people can make the camera private and public. I made two fields in mysql called "Username" and "Puborprivate" I tried to make the "Puborprivate" have two numbers "0" would be private and "1" would be public. How could I do this? My site is cwuforum.com/live/ Hi folks, I had a working, editable profile but it wasn't visible to other users. So I'm trying to make that conversion now. Here's the current 'myprofile' code: <?php session_start(); include('config.php'); include('date.php'); $id = $_GET['id']; $sql = mysql_query("SELECT * FROM members WHERE id = '$id' LIMIT 1"); $check = mysql_num_rows($sql); $check = mysql_query($sql_user_verify) or die('Cannot Execute:'. mysql_error()); if ($check > 1) { echo "No one matches that id number!"; exit(); } if($check == 1) { while($row = mysql_fetch_array($sql)) { $user = $id; echo "<h2>Profile</h2> <table>"; $row = mysql_fetch_array($sql); echo "<tr><th>ID#:</th><td>".$user."</td></tr> <tr><th>Name: </th><td>".$row['callname']."</td></tr> <tr><th>Email: </th><td>".$row['email']."</td></tr> <tr><th>Password: </th><td><input type='password' value='".$row['password']."' disabled='true' /></td></tr> <tr><th>Registered: </th><td>".$row['registered']."</td></tr> <tr><th>Last Login: </th><td>".$row['lastlogin']."</td></tr>"; echo "</table><br />"; } if($id = $_SESSION['id']) { echo "<h2>Profile</h2> <form method='post' action='editprofile.php'> <table>"; $row = mysql_fetch_array($sql); echo "<tr><th>ID#:</th><td>".$user."</td></tr> <tr><th>Name: </th><td>".$row['callname']."</td></tr> <tr><th>Email: </th><td>".$row['email']."</td></tr> <tr><th>Password: </th><td><input type='password' value='".$row['password']."' disabled='true' /></td></tr> <tr><th>Registered: </th><td>".$row['registered']."</td></tr> <tr><th>Last Login: </th><td>".$row['lastlogin']."</td></tr>"; echo "</table><br /> <input type='submit' value='edit profile' /> </form>"; } } else { die (); } ?> <?php include('footer.php'); ?> Here's the link to the user's own profile: <a href=myprofile.php?id='.$id.'>Profile</a> And here's the edit profile link, which works fine: <?php include('config.php'); include('date.php'); if(isset($_POST['btnedit'])){ $callname = $_POST['callname']; $email = $_POST['email']; $password = $_POST['password']; $sql = mysql_query( "UPDATE users SET callname='".$callname."', email='".$email."', password='".$password."' WHERE id='".$_SESSION['id']."'" ); if($sql){ echo "<script>alert('profile updated');window.location='myprofile.php'</script>"; }else{ echo "<script>alert('updating profile failed!');</script>"; } } $sql = mysql_query( "SELECT * FROM users WHERE id='".$_SESSION['id']."'" ); $row = mysql_fetch_array($sql); $userfinal = $_SESSION['id']; $user = $userfinal; echo "<h2>Edit profile</h2> <form method='post'> <table><tr><th>ID#:</th><td>".$user."</td></tr> <tr><th>Name:</th><td><input type='text' name='callname' value='".$row['callname']."'/></td></tr> <tr><th>Email:</th><td><input type='text' name='email' value='".$row['email']."'/></td></tr> <tr><th>Password:</th><td><input type='password' name='password' value='".$row['password']."'/></td></tr> <tr><th>Registered:</th><td>".$row['registered']."</td></tr> <tr><th>Last Login:</th><td>".$row['lastlogin']."</td></tr> </table><br /> <input type='submit' name='btnedit' value='update' /> </form>"; ?> <?php include('footer.php'); ?> It fails, it says the query was empty, even though there are user accounts created and information is being stored (as it worked fine before I tried editing the code to make it public. What am I doing wrong? ../ tells the php program to go up a level. Code: [Select] require_once '../directory/somefile.php'; Is there a shortcut to go to the public web folder? For example. The following file is placed 3 folders deep: "var/www/deep/deeper/verydeep/index.php" and it requires a file with location: "var/www/thisfile.php" I there a short cut/ quicker method to?? Code: [Select] require_once '../../../thisfile.php'; I am writing a script which will be dependent on the client's public ip address. e.g.
if the client is using ip address 203.122.55.124 script A should run and if else then script B should run. Now I know that the If and else will be used but cant guess how will the public ip be captured.
Please help
<? for ($i = 1; $i <= $first_day_of_month-1; $i++) { $days_so_far = $days_so_far + 1; $count_boxes = $count_boxes + 1; echo "<td width=\"125\" height=\"100\" class=\"beforedayboxes\"></td>\n"; } for ($i = 1; $i <= $days_in_month; $i++) { $days_so_far = $days_so_far + 1; $count_boxes = $count_boxes + 1; IF($_GET['month'] == $todays_month+1){ IF($todays_date == $day){ $class = "publicholidayhighlightedboxes"; } ELSE { $class = "dayboxes"; } } ELSE { IF($i == $todays_date){ $class = "highlighteddayboxes"; } ELSE { $class = "dayboxes"; } } The problem is I can only display one highlighted box in one month. For example, in November, there are two public holidays, but only 1 public holiday box is highlighted. Would appreciate if someone can help me out asap. Thank you I am modifying someones existing coldfusion web app. I am adding php processing pages to do various tasks. Up to this point I have just been calling the php pages, and interacting with the web app by passing variables via the url. Current usage: Code: [Select] public.cfm calls processing.php?id=69 Then processing will do what it has too, then ultimately: Code: [Select] header("Location: $publichome?id=$id&importantstuff=$stuff"); exit(); And the webapp will pick up where it has too. But now one of my scripts has to send a JSON object back instead of simple variables. I don't know how to get this done. I tried doing a post with cURL but that wasn't working because I need the public facing coldfusion page to take over and curl returns to the php script (I know I can echo the body of the curl result but this keeps me on the php script domain which I dont want). Is there a way to do the above header location and send an object because thats what I need - the php script to stop and the coldfusion page to be served up with the object to work with. Do I have to create some sort of JSON service in php, that the coldfusion page will call an retrieve the result? If so how? This topic has been moved to Miscellaneous. http://www.phpfreaks.com/forums/index.php?topic=316783.0 I have searched around and found this code that suggests that I should be able to read an image file and echo it directly in to the page without hyperlinking to the file that is outside the public folder, but i get the error message that it is not there even though the file is. Warning: getimagesize() [function.getimagesize]: Unable to access "/home/****/upload/AAABBBCCC.JPG" in /home/****/public_html/client.php on line 40 Code: [Select] $image = "AAABBBCCC.JPG"; $path= "/home/****/upload/"; $details = getimagesize($path . $image); header ('Content-Type: ' . $details['mime']); echo file_get_contents($path . $image); edited: please note all wmv files are not more than 10 or 20 seconds long. also their size is no more than 500kb. I have this following code that works for photos, but wish to alter this slightly so it will work for video files (wmv) getFtpImage.php Code: [Select] <? header('Content-Type: image/jpg'); $imgdir = '/home/mysite/ftpfolder'; readfile($imgdir . '/' . $_GET['file']); ?> index.php Code: [Select] $imgdir = '/home/mysite/ftpfolder'; // the directory, where your images are stored $allowed_types = array('png','jpg','jpeg','gif'); // list of filetypes you want to show $dimg = opendir($imgdir); while($imgfile = readdir($dimg)) { if(in_array(strtolower(substr($imgfile,-3)),$allowed_types)) { $a_img[] = $imgfile; sort($a_img); reset ($a_img); } } $totimg = count($a_img); // total image number for($x=0; $x < $totimg; $x++) { $size = getimagesize($imgdir.'/'.$a_img[$x]); // do whatever $halfwidth = ceil($size[0]/2); $halfheight = ceil($size[1]/2); ?><img src="getFtpImage.php?file=<? echo ($a_img[$x]); ?>" height="180"><? // echo 'name: '.$a_img[$x].' width: '.$size[0].' height: '.$size[1].'<br />'; } i have the images show to fill the screen and wish for the video page to do the same and with the videos you click the [play] in the center of the video image to play it like most videos play, not like the flash. I tried these below, Code: [Select] class Site extends Controller { function Site() { public $data = Array(); } } but it fail? Thanks in advanced. Hi, I am making a dating site where I have made the user profile edit page visible to the user when they log in, and I think I can get away with not showing the user their "public" profile view. But I definitely need to show other users on the site the "public" non editing profile page view. But I don't know how to do this. I have yet to create the search, search results, thumbnails with optional descriptions of the possible dating results. But I first want to just get 2 versions of the user profile page view. One that the user sees that I have already done. (The editable one). And the other I need to make which is the page the other users will see, (The public profile) Please if anyone has any idea how to do this I would greatly appreciate it, especially if you have any pseudocode ideas. thank you. Hi, I want to create a simple online buying site. I have an admin site with login where admin can add items to the database table, and change other fields such as price and description of product and I want to make a public html page to display the updates made in my admin page. I appreciate it if someone give me some suggestions on how to get started. My admin php scripts is working fine (so SQL queries for UPDATE, DELETE, INSERT) but I don't know how to 'sync' it with the an nice html table of products the user can checkbox off to purchase on the public website. Let me know, thanks. Hi all, I want to call a javascript function from a php function like this: public function Buscar() { $HoraInicio = $_POST['edtHoraInicio']; $HoraFin = $_POST['edtHoraFin']; $FechaInicio = $_POST['edtFec1']; $FechaFin = $_POST['edtFec2']; $FechaMax = $FechaFin." ".$HoraFin.":00"; $FechaMin = $FechaInicio." ".$HoraInicio.":00"; $_GET["FechaMax"] = $FechaMax; $_GET["FechaMin"] = $FechaMin; echo $FechaMin; echo "<script language=javascript>alert('Hi.')</script>"; } but the function Buscar never show the alert but shows the $FechaMin I hopu u guys can help me out with this probem Thanks, Siddhartha Hi I have a table class and functions I want to call in another function but can't get it working. Some help will be very welcome. It seesm that the new table class is not working in this function if I pass the values to it, I have tested the class, it does get the post values I post to it so $_POST['id'] are being received as well as all the other $_POST's but the table class and find function is not working, it works fine if I don't put it in a function.. function edit() { if (isset($error)){ $error.="Please fix the error(s) above";} else { if ($_POST['id'] <> "") { $update =& new table($db, 'publisher'); $update->find($_POST['id']); $update->name = $_POST['name']; $update->url = $_POST['url']; $update->contact = $_POST['contact']; $update->address = $_POST['address']; $update->phone = $_POST['phone']; $update->email = $_POST['email']; $update->save(); $error = "The Publisher has been edited"; } } } This topic has been moved to Other Libraries and Frameworks. http://www.phpfreaks.com/forums/index.php?topic=319682.0 I can call the following function successfully as a single php program // Acknowledge and clear the orders function ack($client, $merchant, $id) { $docs = array('string' => $id); $params = array('merchant' => $merchant, 'documentIdentifierArray' => $docs); $result = $client->call('postDocumentDownloadAck', $params); return $result; } with $result = ack($t, $merchant,'2779540483'); successful output [documentDownloadAckProcessingStatus] => _SUCCESSFUL_ [documentID] => 2779540483 I'm trying to figure out how to call this function as an object from another program. Trying the following gives error ***Call to a member function call() on a non-object*** function postDocumentDownloadAck($t, $merchant, $id) { $this->error = null; $docs = array('string' => $this->id); $params = array('merchant' => $this->merchant, 'documentIdentifierArray' => $docs); ** I've tried the following which does nothing $result = $this->soap->call('postDocumentDownloadAck', $params); ** I've tried the following - which gives error "Call to a member function call() on a non-object" $result = $this->t->soap->call('postDocumentDownloadAck', $params); if($this->soap->fault) { $this->error = $result; return false; } return $result; } *** calling program snippet for above function $merchant= array( "merchant"=> $merchantid, "merchantName" => $merchantname, "email"=> $login, "password"=> $password); $t = new AmazonMerchantAPI($merchantid, $merchantname, $login, $password); $documentlist= $t->GetAllPendingDocumentInfo('_GET_ORDERS_DATA_'); $docid = $documentlist['MerchantDocumentInfo'][$i]['documentID']; $docs = array('string' => $docid); $ackorders = $t->postDocumentDownloadAck($t, $merchant,$docs); Any ideas of what I'm doing wrong are greatly appreciated. <?php class Post{ private $user_obj; private $con; public function __construct($con, $user){ $this->con = $con; $this->user_obj = new User($con,$user); } public function submitPost($body,$user_to){ $body = strip_tags($body);////Removing HTML TAGS $body = mysqli_real_escape_string($this->con,$body); $check_empty = preg_replace('/\s+/', '', $body);//delte all spaces if($check_empty != ""){ //Current Date and time $date_added = date("Y-m-d H:i:s"); //get username $added_by = $this->user_obj->getUsername(); //if user have not a profile send to the none if($user_to == $added_by){ $user_to = "none"; } ////insert query $query = mysqli_query($this->con,"INSERT INTO posts VALUES('','$body','$added_by','$user_to','$date_added','no','no','0')"); $retured_id = mysqli_insert_id($this->con); //insert notification //Update post count for user $num_post = $this->user_obj->getNumPosts(); $num_post++; $update_query = mysqli_query($this->con,"UPDATE users SET num_post = '$num_post' WHERE username = '$added_by'" ); } public function loadPostsFriends(){ $str = ""; //string to return $data = mysqli_query($this->con,"SELECT * FROM posts where deleted = 'no' ORDER by id DESC"); while($row = mysqli_fetch_array($data)) { $id = $row['id']; $body = $row['body']; $added_by = $row['added_by']; $date_time = $row['date_added']; /// Creating user post on other user profile if($row['user_to'] == "none"){ user_to = ""; else { $user_to_obj = new User($con,$row['user_to']); $user_to_name = $user_to_obj->getFirstandLastname(); $user_to = "to <a href='" . $row['user_to'] . "'>" .$user_to_name . "</a>"; } // check if user account was closed $added_by_obj = new User($this->con,$added_by); if($added_by_obj ->isClosed()){ continue; } $user_details_query = mysqli_query($this->con,"SELECT first_name,last_name,profile_pic FROM users where username = '$added_by'"); $user_row = mysqli_fetch_array($user_details_query); $first_name = $user_row['first_name']; $last_name = $user_row['last_name']; $profile_pic= $user_row['profile_pic']; ///time stamp $date_time_now = date("Y-m-d H:i:s"); $start_date = new Date_Time($date_time);////Time_of_post $end_date = new Date_Time($date_time_now);///Current_time $intervel = $start_date->diff($end_date); if($intervel->y >< 1 ){ if($intervel ==1 ) $time_message = $intervel->y . " year ago";/// 1 Year Ago else $time_message = $intervel->y . " years ago"; //1+ year ago } else if($intervel-> m >= 1 ){ if($intervel->d == 0){ $days = " ago"; } else if($intervel->d == 1){ $days = $intervel->d."day ago"; } else { $days = $intervel->d."day ago"; } if($intervel->m == 1){ $time_message = $intervel->m." month".$days; } else $time_message = $intervel->m." months".$days; } } else if($intervel->d >= 1){ if($intervel->d == 1){ $days = "Yesterday"; } else { $days = $intervel->d."days ago"; } } else if($intervel->h >= 1){ if($intervel->h == 1){ $time_message = $intervel->h." hour ago"; } else { $time_message = $intervel->h." hours ago"; } } else if($intervel->i >= 1){ if($intervel->i == 1){ $time_message = $intervel->i." minute ago"; } else { $time_message = $intervel->i." minutes ago"; } } else{ if($intervel->s < 30){ $time_message = "Just Now"; } else { $time_message = $intervel->s." seconds ago"; } } $str .= "<div class='status_post'> <div calss='post_profile_pic'> <img src='$profile_pic' width='50'> </div> <div calss='posted_by' style='color#ACACAC;'> <a href = '$added_by'> $first_name $last_name </a> $user_to ; ; $time_message </div> <div id = 'post_body'$body<br></div> </div> " } echo $str; } } ?> When i run this code this show me the error Parse error: syntax error, unexpected 'public' (T_PUBLIC) in C:\xampp\htdocs\social\Classes\Post.php on line 39 the line 39 is public function loadPostsFriends() I check the code again and again but i cant find the error please help in this error I'm writing a program that allows users to input a stock and view a historical price chart. Code is straight out of libchart charting library. Problem is, user is supposed to enter the stock symbol from a form handler (index.php) which then passes the symbol as a variable to the charting function, which doesn't get called at all:
<? php
function index() { chart($_POST['userinput']};
} ?> .
<?php
function chart($stock)
{
$prices=getdata($stock); //returns array of prices from yahoo finance
$data=analyzer($prices); //produces metrics to be charted
graph($data); } ?> //plots the metrics, outputs .html
chart.php works on its own, as I've verified by hardcoding $argv='ibm'; in its code body. But index.php can't seem to call chart.php, as I've verified by including an echo/var_dump line in chart.php (doesn't get executed at all). It doesn't have anything to do with form handling either, as chart('ibm'); doesn't call chart.php either. I don't understand how a 6-line piece of code can be so problematic. All files are in the same folder, btw.
Thanks.
|