PHP - Have Uninstalled Wamp To Try To Resolve Render Problem
now i am getting this error
( ! ) Warning: mysql_connect() [function.mysql-connect]: Access denied for user 'talos342c'@'localhost' (using password: YES) in C:\wamp\www\myNewweb\storescripts\connect_to_mysql.php on line 19 Call Stack # Time Memory Function Location 1 0.0008 380440 {main}( ) ..\index.php:0 2 0.0012 384880 include( 'C:\wamp\www\myNewweb\storescripts\connect_to_mysql.php' ) ..\index.php:11 3 0.0012 385528 mysql_connect ( ) ..\connect_to_mysql.php:19 Similar Tutorials<?php session_start(); if (!$_SESSION["user_name"]) { // User not logged in, redirect to login page Header("Location: login.php"); } // Member only content // ... $con = mysql_connect('localhost','root',''); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("login", $con); $result = mysql_query("select * from reference,users where reference.username=users.user_name AND reference.refid = '".$_POST['refid']."'"); while($row = mysql_fetch_array($result)) { echo $row['refid'];?><br><? echo $row['origin']; echo $row['dest']; echo $row['date']; echo $row['exdate']; echo $row['user_name']; } // ... // ... // Display Member information // echo "<p>User ID: " . $_SESSION["valid_id"]; //echo "<p>Username: " . $_SESSION["valid_user"]; //echo "<p>Logged in: " . date("m/d/Y", $_SESSION["valid_time"]); // Display logout link echo "<p><a href=\"logout.php\">Click here to logout!</a></p>"; ?> for the above code i got error Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in solve my problem Hello All,
I'm kinda new to PHP and web development and I seem to have a very wierd problem which is driving me nuts (for the last 2 days)...so I'd appreciate any and all help in getting it resolved.
Okay, so here's the problem:
In the code below, I used to have just the first statement below...which essentially accepted input as a textbox for a text field named qty_pkg (in the underlying MySQL table)...and that used to work just fine.
So then I decided to change the input type for that field to be a radio button, accepting one of two choices i.e. "UoM" or "Qty", and therefore I added the remainder of the code, whilst also commenting/remarking out the first statement.
What happens (when I added the radiobutton-related code) is that control no longer goes into the TRUE portion/logic of the "if ( !empty($_POST))" condition-check, but rather, it seems to go into the "ELSE/FALSE" portion of that conditional check. However, a record does get added to my table, even though I do not have an "INSERT INTO..." clause in the ELSE porition of that check. Also, what gets displayed on screen is as follows:
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Array()
There's something wrong somewhere!!!
Array()
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Now, if/when I comment/remark the radiobutton-related code, the "if ( !empty($_POST))" logic seems to work fine and the following is displayed on screen (which is what I expect):
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Array ( [datepicker] => 10/30/2014 [store_id] => 48 [new_store_name] => [item_id] => 5 [new_item_name] => [pkg_of] => 1 [price] => 1 [flyer_page] => 1 [limited_time_sale] => Array ( [0] => fri [1] => sat ) [nos_to_purchase] => 1 [create-and-add-more] => Create and Add More ) Notice: Undefined index: qty_pkg in /var/www/create.php on line 54 Array ( [0] => Array ( [item_id] => 5 [0] => 5 [item_name] => BD Cheese Strings [1] => BD Cheese Strings [section_id] => 7 [2] => 7 ) ) ------------------------------------------------------------------------------------------------------------------------------------ The other wierd thing is that if/when I now uncomment the first statement (which used to work just fine before) the "if ( !empty($_POST))" logic no longer seems to work the way it used to. Does/can someone see something wrong with my code somewhere? <!-- <?php echo standardInputField('Qty / Pkg', 'qty_pkg', $qty_pkg, $errors); ?> --> <div class="control-group"> <label class="control-label">Priced by:</label> <div class="priced-by-radio-container"> <div class="pb-radiobuttons-container"> <label class="indent-to-the-left"> <input class='priced-by-radiobutton' type='radio' name='qty_pkg' value='UoM' $pb1> <span class='no-highlight'>Unit of Measure</span> </label> <label> <input class='priced-by-radiobutton' type='radio' name='qty_pkg' value='Qty' $pb2> <span class='no-highlight'>Quantity</span> </label> </div> </div> </div> <?php echo standardInputField('UoM Name/Pkg. Of:', 'pkg_of', $pkg_of, $errors); ?> <?php echo standardInputField('Price:', 'price', $price, $errors); ?> <?php echo standardInputField('Flyer Page #:', 'flyer_page', $flyer_page, $errors); ?> print_r($_POST); if ( !empty($_POST)) { // keep track of $_POST(ed) values by storing the entered values to memory variables $store_id = $_POST['store_id']; $item_id = $_POST['item_id']; $qty_pkg = $_POST['qty_pkg']; $pkg_of = $_POST['pkg_of']; ... ... $sql = "INSERT INTO shoplist (store_id,item_id,qty_pkg,pkg_of,price,flyer_page,limited_time_sale,flyer_date_start,nos_to_purchase,section_id,shopper1_buy_flag,shopper2_buy_flag,purchased_flag,purchase_later_flag,no_flag_set) VALUES(?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?)"; $q = $pdo->prepare($sql); $q->execute(array($store_id,$item_id,$qty_pkg,$pkg_of,$price,$flyer_page,$limited_time_sale,$flyerDateStart,$nos_to_purchase,$section_id,$initialize_flag_N,$initialize_flag_N,$initialize_flag_N,$initialize_flag_N,$initialize_flag_Y)); } else { echo "<br />There's something wrong somewhere!!!<br />"; print_r ($_POST); $qty_pkg = ''; $pkg_of = '';;Thanks. I am trying a very simple thing , just to run an exe on local WAMP environment.The code below launches does launch notepad(can see in task manager) but doesn't show up.I want test.txt to be opened in a window. <?php $WshShell = new COM("WScript.Shell"); $oExec = $WshShell->Run("notepad.exe C:\wamp\www\test.txt", 3, true); ?> I have tried exec as well .Same problem.What modifications are needed? Haven't been here in a while but I have stumped myself at the moment or maybe I've looked at it too much LOL In the given code below I am getting this error Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in C:\xampp\htdocs\samples\getcustomers.php on line 20 WHY? Code: [Select] <?php $value = $_GET["q"]; $con = mysql_connect('localhost', 'root', ''); //db_connect(); if (!$con) { die('Could not connect: ' . mysql_error()); } $db_selected = mysql_select_db("ajaxDb",$con); $sql = "SELECT * FROM 'cutomers' WHERE Name = '".$value."'"; // echo $sql; $result = mysql_query($sql); echo "<table border='1'> <tr> <th>Name</th> <th>Address</th> <th>Country</th> </tr>"; while($row = mysql_fetch_array($result)) { echo "<tr>"; echo "<td>" . $row['Name'] . "</td>"; echo "<td>" . $row['Address'] . "</td>"; echo "<td>" . $row['Country'] . "</td>"; echo "</tr>"; } echo "</table>"; mysql_close($con); ?> Thanks for reading this. I have just begun using php, and I cannot, for my life, figure out what I am doing wrong here. I want to submit a form for a person to register with my site. It's simple, just name, email and password. I keep getting an error that the connection failed, so I will just show you what I have up until that point. My form is Post method, and it looks like: Code: [Select] <form method="post" action="signup.php" enctype="multipart/form-data"> <input name="name" type="text" id="name"> <input name="email" type="text" id="email"> <input name="pass" type="password"> <input type="submit" name="Submit" value="Submit"> </form> And the connection script is like so: Code: [Select] <?php $username="db_username"; $password="db_password"; $database="db_name"; $dbc=mysql_connect ("localhost", "$username", "$password") or die ('I cannot connect to the database.'); mysql_select_db ("$database", "$dbc"); It's the 'I cannot connect to the database.' error that I keep getting. In case it helps, the rest of the thing looks like this: Code: [Select] <?php $name= $_POST['name']; $email= $_POST['email']; $pass= $_POST['pass']; $query = "INSERT INTO table (name, email, password) VALUES ('$name', '$email', '$pass')"; mysql_query($query); mysql_close(); I have deliberately left out the php opening and closing tags (<?php...?>). Thanks so much for any help. Adam MOD EDIT: [code] . . . [/code] BBCode tags added. I've followed every piece of advice (quotes, no quotes, $...) and nothing works. Here is the snippet of code that's generating the error. This woks fine in PHP 5, but I have to upgrade to 7. Warning if for line 71, which corresponds to where query3 starts.
if($numRows == 0) { Earlier in code, I define this: $numRows = mysql_num_rows($r); Thanks in advance for any help you can lend. Edited February 7 by PoetThis is how looks bug looks : Code echo "<div align='center' class='thread'>Forum</div>"; $forum_select = mysql_query("SELECT * FROM forum") or die (mysql_error()); while ($forum_show = mysql_fetch_array($forum_select)) { $forum_name = mysql_query("SELECT * FROM forum_group"); while($forum_group_name = mysql_fetch_array($forum_name)) { if ($forum_group_name['hosting_forum_group_id'] == $forum_show['hosting_forum_group_id']) { echo "<table width='900' border='1' align='center' cellpadding='0' cellspacing='0'>"; echo "<tr><td colspan='6' style='padding: 7px;color:red'>".$forum_group_name['hosting_forum_group_name']."</td></tr>"; echo "<tr><td style='white-space: nowrap;' align='center' width='1%'>".$forum_show['hosting_forum_icon']."</td>"; echo "<td>"."<a href='/?section=forumview&id=".$forum_show['hosting_forum_id']." '>".$forum_show['hosting_forum_title']."</a><br />".$forum_show['hosting_forum_description']."</td>"; echo "<td width='230'> </td></tr>"; echo "</table><br>"; } } } I Hope to resolve the problem maybe somebody can explain where is my mistake to fix it and resolve it ! (I looked at the appropriate forums to put this in, but it seems I couldn't find a forum section specifically for this problem) Yesterday PHP on WAMP was working perfectly. So I shutdown the computer, go to sleep, and wake up and turn WAMP on. But for some odd reason, when none of my PHP files are loading properly. It just shows all the code as if it were a .txt file. Any reasons for this? I need to find a way to resolve a relative path outside the document root, in a cross-platform friendly manner. My users have a settings page where they are able to set the path to a folder where files should be included. This path may not exist at the time of saving the setting. The given path is then retrieved from the database when files are being saved, the path is checked to see if a folder needs to be created, and the file is saved to the path. Two possible paths they may use a * files (This is the webpath: http://site.com/files or absolute path /home/user/public_html/files) * ../files (This is the absolute path: /home/user/files where the webroot is /home/user/public_html/) The first path is easy to deal with. However, I'm having a rough time resolving the second path into a usable system path (i.e. /home/user/files). This needs to be cross platform compatible (windows/'Nix). I've played around with realpath(), but I'm just not finding something that works for me. Any suggestions? Hi: I have few small issues with a Contact Us form I am putting together. 1 - When quotes or apostrophes are added to the input fields, they get turned into '\ (slashes). The "myCodeLib.php" file has a function to remove the slashes. I use it in the same way in the admin area and it works fine, so I don't see what I am missing: Code: [Select] <?php //STRIP SLASHES if(get_magic_quotes_gpc()) { $_POST = array_map('stripslashes',$_POST); $_GET = array_map('stripslashes',$_GET); $_COOKIE = array_map('stripslashes',$_COOKIE); } ?> 2 - A small issuse, but the Email validation doesn't seem to work entirely. It will accept a single character (like an "a") as valid, but it looks like it's suppose to check for a format like "a@a.com" 3 - How can I properly SPAN this code that write out the error: Code: [Select] echo $error; I want to do Code: [Select] <span class="textError">echo $error;</span> to make it red but I keep getting a snytax error This is the full code: Code: [Select] include('include/myConn.php'); include('include/myCodeLib.php'); <?php $error = NULL; $myDate = NULL; $FullName = NULL; $Address = NULL; $City = NULL; $State = NULL; $Zip = NULL; $Phone = NULL; $Email = NULL; $Website = NULL; $Comments = NULL; if(isset($_POST['submit'])) { $myDate = $_POST['myDate']; $FullName = $_POST['FullName']; $Address = $_POST['Address']; $City = $_POST['City']; $State = $_POST['State']; $Zip = $_POST['Zip']; $Phone = $_POST['Phone']; $Email = $_POST['Email']; $Website = $_POST['Website']; $Comments = $_POST['Comments']; if(empty($FullName)) { $error .= '-- Enter your Full Name. <br />'; } if(empty($Email) || preg_match('~^([0-9a-zA-Z]([-.\w]*[0-9a-zA-Z])*@([0-9a-zA-Z][-\w]*[0-9a-zA-Z]\.)+[a-zA-Z]{2,9})$~',$Email)) { //<- if email is empty, or doesn't follow the expression. $error .= '-- Enter your Email. <br />'; //<- this is the error message. } if($error == NULL) { $sql = sprintf("INSERT INTO myContactData(myDate,FullName,Address,City,State,Zip,Phone,Email,Website,Comments) VALUES ('%s','%s','%s','%s','%s','%s','%s','%s','%s')", //<-database structure must be right. mysql_real_escape_string($myDate), mysql_real_escape_string($FullName), mysql_real_escape_string($Address), mysql_real_escape_string($City), mysql_real_escape_string($State), mysql_real_escape_string($Zip), mysql_real_escape_string($Phone), mysql_real_escape_string($Email), mysql_real_escape_string($Website), mysql_real_escape_string($Comments)); if(mysql_query($sql)) { $error .= 'Thank you for your comment!'; } else { $error .= 'There was an error in our Database, please Try again!'; } } } echo $error; $myDate = $_REQUEST['myDate'] ; $FullName = $_REQUEST['FullName'] ; $Address = $_REQUEST['Address'] ; $City = $_REQUEST['City'] ; $State = $_REQUEST['State'] ; $Zip = $_REQUEST['Zip'] ; $Phone = $_REQUEST['Phone'] ; $Email = $_REQUEST['Email'] ; $Website = $_REQUEST['Website'] ; $Comments = $_REQUEST['Comments'] ; mail( "email@website.com", "Contact Request", "Date Sent: $myDate\nFull Name: $FullName\nAddress: $Address\n City: $City\n State: $State\n Zip: $Zip\n Phone: $Phone\n Email: $Email\n Website: $Website\n Comments: $Comments\n", "From: $Email" ); ?> <form name="myform" action="" method="post"> <input type="hidden" name="myDate" size="45" maxlength="50" value="<?php echo date("F j, Y"); ?>" /> <div id="tableFormDiv"> <fieldset><span class="floatLeftFormWidth"><span class="textErrorItalic">* - Required</span></span> <span class="floatFormLeft"> </span></fieldset> <fieldset><span class="floatLeftFormWidth"><span class="textErrorItalic">*</span> Full Name:</span> <span class="floatFormLeft"><input type="text" name="FullName" size="45" maxlength="50" value="<?php echo $FullName; ?>" /></span></fieldset> <fieldset><span class="floatLeftFormWidth">Address:</span> <span class="floatFormLeft"><input type="text" name="Address" size="45" maxlength="50" value="<?php echo $Address; ?>" /></span></fieldset> <fieldset><span class="floatLeftFormWidth">City:</span> <span class="floatFormLeft"><input type="text" name="City" size="45" maxlength="50" value="<?php echo $City; ?>" /></span></fieldset> <fieldset><span class="floatLeftFormWidth">State:</span> <span class="floatFormLeft"><input type="text" name="State" size="45" maxlength="50" value="<?php echo $State; ?>" /></span></fieldset> <fieldset><span class="floatLeftFormWidth">Zip:</span> <span class="floatFormLeft"><input type="text" name="Zip" size="45" maxlength="50" value="<?php echo $Zip; ?>" /></span></fieldset> <fieldset><span class="floatLeftFormWidth">Phone:</span> <span class="floatFormLeft"><input type="text" name="Phone" size="45" maxlength="50" value="<?php echo $Phone; ?>" /></span></fieldset> <fieldset><span class="floatLeftFormWidth"><span class="textErrorItalic">*</span> Email:</span> <span class="floatFormLeft"><input type="text" name="Email" size="45" maxlength="50" value="<?php echo $Email; ?>" /></span></fieldset> <fieldset><span class="floatLeftFormWidth">Website:</span> <span class="floatFormLeft"><input type="text" name="Website" size="45" maxlength="50" value="<?php echo $Website; ?>" /></span></fieldset> <fieldset><span class="floatLeftFormWidth">Comments:</span> <span class="floatFormLeft"><textarea name="Comments" cols="40" rows="10"><?php echo $Comments; ?></textarea></span></fieldset> </div> <input type="submit" name="submit" value="Submit" class="submitButton" /><br /> </form> </div> Can someone please help me with this... I keep trying to install every wordpress, or php web server software I can find, the lastest being WAMP. Nothing ever works. I feel like a complete retard here being that I can't even set up a stupid program, to be ABLE to program myself. Everything I install gives me a 404 not found error when I try to load the admin index page to a browser. I honestly have no friggn clue what is going on, I know syntax pretty decently for a lot of these languages, but as far as setting them up, I might as well just shoot myself. I know they can't make it any easier with these step by step tutorials, but it just doesn't seem to work on my comp.
Each time i try to open WAMP's phpmyadmin so i can create a database it has this ERROR #1045 - Access denied for user 'root'@'localhost' (using password: NO) how do i fix it Hi guys Im looking to save the contents of 4 textboxes to a mySql db. Using wamp, phpmyadmin etc. Code: [Select] ?php $Name = $_Post('Name'); $Age = $_Post('Age'); $Sex = $_Post('Sex'); $Address_1 = $_Post('Address_1'); mysql_connect("127.0.0.1","user","") or die ('Error: ' .mysql_error()); mysql_select_db("user"); $query ="INSERT INTO users(Name,Age,Sex,Address_1) VALUES('".$Name."', '".$Age."','".$Sex."','".$Address_1."'); mysql_query($query) or die ('Error updating datadase'); mysql_Close(); ?>This is the code im using, it dosent seem to do anything to the database..... can someone point out where im going wrong... thanks I get a "No database selected" error whenever I submit information on my register.php page, which is: <?php include_once('includes/config.php'); include_once('functions.php'); $return_content = AccountRelated(null, null, 3); ?> <html> <head> <link rel="stylesheet" type="text/css" href="style/style.css" /> <title><?php echo $title; ?></title> </head> <body> <div class="logo"><a href="index.php"><img src="style/images/logo.png" border="0"></a></div> <center> <div class="background"> <div class="container"> <?php echo $return_content; ?> </div> </div> </center> </body> </html> But after I click submit, I get the "No database selected" error, but using WAMP, I include config.php which holds the following details: <?php $title = "NovaUpload - File Uploader"; mysql_connect("localhost", "", ""); mysql_select_db("data"); ?> And if functions.php is required, he <?php function AccountRelated($username, $password, $query_type) { if($query_type == 1) { $set_query = mysql_query("SELECT COUNT(d.username), u.date, u.username FROM uploads d, users u WHERE d.username = '$username' AND u.username = '$username' LIMIT 1") or die(mysql_error()); //user must not exist if(mysql_num_rows($set_query) == 0) { $content_return = 'Sorry, no information was found'; } else { $grab = mysql_fetch_assoc($set_query); //login information if($grab['COUNT(d.username)'] > 0) { $welcome_return = "You have uploaded ". $grab['COUNT(d.username)'] ." files. You've registered on ". $grab['u.date'] ."!"; } else { $welcome_return = "You have uploaded 0 files. You've registered on ".$grab['date'] . "!"; } } } elseif($query_type == 2) { $set_query = mysql_query("SELECT title,views,downloads,description,username,date FROM uploads LIMIT 20"); if(mysql_num_rows($set_query) == 0) { $content_return = "Sorry, there are currently no files uploaded to view."; } else { //display all files while($row = mysql_fetch_assoc($set_query) == 0) { echo $row['title']."<br/>"; } } } elseif($query_type == 3) { $username = mysql_real_escape_string($_POST['username']); $password = sha1(sha1(md5($_POST['password']))); if(!$username || !$password) { $return_content = "All fields are required! <table><form action='register.php' method='POST'> <tr><td>Username</td><td><input type='text' name='username' maxlength='20'></td></tr> <tr><td>Password</td><td><input type='text' name='password' maxlength='30'</td></tr> <tr><td><input type='submit' value='Register'></td></tr> </form></table>"; } else { $set_query = mysql_query("SELECT username FROM users WHERE username = '$username' LIMIT 1"); if(mysql_num_rows($set_query) == 0) { $return_content = "You have successfully registered the account ". $username ." with the password ". $_POST['password'] ."!"; mysql_query("INSERT INTO users VALUES (null, '$username', '$password', 0, 0, '". date("M-d-Y") ."', '". $_SERVER['REMOTE_ADDR'] ."')") or die(mysql_error()); } else { $return_content = "An account with this username already exists."; } } return $return_content; } else { //nothing to process } } ?> hey guy, <p>I'm kind of new to php , and I need you to help me. I have developed a website im lamp. I don't how to get that working in wamp/ xamp . <i>Please tell me how to do it.<i> </p> Hi, My program works on WAMP (PHP Version 5.5.12) running on my machine. However, the same program will not run on remote server (PHP Version 5.4.32). Basically, I'm trying to insert values obtained from a form into a database. I've checked and rechecked the table I'm inserting into and I can't find anything wrong with it. The trouble is it's hard to debug a PHP program. Unlike, say, C++ which requires a compiler, you can trace the program line by line to look for errors. That's not possible with PHP and makes it so much harder to look for faults. The relevant functions used to send data to database are shown below. insert() is returning false every time and I can't understand why! I wonder if anyone can suggest where things might be going wrong. I would be very grateful. public function insert($table, $fields = array()) { if(count($fields)) //true if $fields holds data { $keys = array_keys($fields); $values = ''; //to put inside query $x = 1; foreach($fields as $field) { $values .= '?'; if($x < count($fields)) { $values .= ', '; } $x++; } $sql = "INSERT INTO {$table} (`".implode('`, `', $keys) . "`) VALUES({$values})"; if(!$this->query($sql, $fields)->error()) { return true; } } return false; } public function query($sql, $darams = array()) { $this->_error = false; //reset error if($this->_query = $this->_pdo->prepare($sql)) { $x = 1; if(count($darams)) { foreach($darams as $param) { $this->_query->bindValue($x, $param); $x++; } } if($this->_query->execute()) { $this->_results = $this->_query->fetchAll(PDO::FETCH_OBJ); $this->_count = $this->_query->rowCount(); } else //an error has occured in SQL query { $this->_error = true; } } return $this; } public function error() { return $this->_error; } public function count() { return $this->_count; } Okay, so I keep crashing my server while trying to get a simple script to run. Firstly, here's the code. <?php $dbhost = 'localhost'; $dbuser = 'root'; $dbpass = ''; $conn = mysql_connect($dbhost, $dbuser, $dbpass) or die('Error connecting to mysql'); $dbname = 'businessletters'; mysql_select_db($dbname); $files = getFiles("parseme.txt"); for($i=0;$i<200;$i++) { $file = getReadFile($files[$i][0]); insertIntoDb($files[$i][1], $file); //echo "Inserted successfully - " . $files[$i][0] . "<br />"; } function getFiles($file) { $fh = fopen($file, "rb"); $data = fread($fh, filesize($file)); fclose($fh); $dataArr = explode("\n", $data); for($i=0;$i<count($dataArr);$i++) { $dataArr[$i] = explode(",", $dataArr[$i]); } return($dataArr); } function getReadFile($file) { $fh = fopen($file, "rb"); $data = fread($fh, filesize($file)); fclose($fh); return $data; } function insertIntoDb($title, $body) { $sql = "insert into letters values('', '".mysql_real_escape_string($title)."', '".mysql_real_escape_string($body)."')\n"; //mysql_query($sql) or die("Error inserting"); echo $sql; } mysql_close(); ?> And now, here's what it's supposed to do. Open and read File A - this file has file names and titles in a CSV file. File,Title is the format. Then the loop starts. Here I would like to do everything in one run, which could be done by counting the records in the CSV file, which I can do with count(), but even 200 is too much. I have 600. Anyway, it goes through the CSV file and opens every file referenced and pulls out the content. Then it creates a simple SQL statement where the content is entered into the database. And the problem is that Apache keeps crashing on me... There must be a better way for me to do this without having my server crash on me!
I'm currently trying to building a websocket widget, using node package manager(NPM),WAMPserver and electronjs. Code: [Select] <?php exec('java -jar/MicroChatServer.jar',$output); print_r($output); ?> Hello frds......... I have chat prg. jar file and I have to integrate this chat in a PHP website uses Wampserver.... I try above code but it display "Array()" instead of execute jar file. What should I do???? Any idea?????????????// |