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PHP - Is There A Way To Write A Code To Detect Browser Plugins?
Hi there, I've looked into the PHP superglobal array $_SERVER, but could not find a variable that stores the plugins a client has on his/her browser such as firefox and google chrome. The point here is to detect if a user has hacking addons such as firebug and inspect element installed, and displays an error message telling the user to disable such plugins in order to access site content. Is it possible to accomplish such tasks? Please help.
Similar TutorialsHello everyone, I'm in the process of creating a PHP script (will be open-source), I just need to know how to make it easy for people to add plugins? Like I don't really know much about the concept of plugins (how they should work), all I know is that there should be a function to activate / deactivate the plugin, but how can I make it possible for people to run their "code" wherever they want? I've heard about "hooks" but I don't really understand how this should work, anyone can explain please? Thank you very much in advance I have a problem, where i need to know when user leave or close tha browser tab. I tryd to make a ajax post, after unload, make a POST into kill_browser.php and after 1 minute when session_expire, php code will be execute and save time into database. But it not seems to work :/ I'm glad if some 1 can say what im doing wrong, or is there eny better way to detect it.
@home.php
var leaved = 'leaved'; $(window).unload( function(){ $.ajax({ url: 'kill_browser.php', global: false, type: 'POST', data: leaved, async: false, success: function() { console.log('leaved'); } }); }); @kill_browser.php <?php require('class/connection.php'); $conn = new connection(); session_cache_limiter('private'); $cache_limiter = session_cache_limiter(); session_cache_expire(1); $cache_expire = session_cache_expire(); session_start(); $_SESSION['leaved'] = $_POST['leaved']; if($_SESSION['leaved'] == null || $_SESSION['leaved'] == " "){ $conn->logOut($_SESSION['userID'], $_SESSION['userIP'], $_SESSION['LAST_GENERATED_ID']); session_regenerate_id(true); unset($_SESSION); session_destroy(); header('location:index.php'); } ?> Code: [Select] if ($showigiteidimage) { $igitwid_divlnk = "onclick=location.href='" . get_permalink($igitwid_result->ID) . "'; style=cursor:pointer;"; $igitwid_output .= '<li id="igit_wid_rpwt_li" style="height:' . $igitwid_height . 'px; padding-bottom: 10px;" ' . $igitwid_divlnk . '>'; $igitwid_output .= '<div id="igit_wid_rpwt_main_image" style="float:left;"> <a href="' . get_permalink($igitwid_result->ID) . '" target="_top"><img src="<?php $values = get_post_custom_values("tj_video_img_url"); echo $values[0]; ?>" id="igit_rpwt_thumb" ></a></div>'; the prb is image src cant read the php code , what to do ? please helpppppppppp i'm trying to use this code to detect if the browser of the user is IE (any version) and id true (if it is IE), then it's redirected to an error page; otherwise, it's ok and sent ot the index. I get the following error... Warning: Cannot modify header information - headers already sent by (output started at /index.php:1) in /xie.php on line 13 any ideas.. ??? <?php function ae_detect_ie() { if (isset($_SERVER['HTTP_USER_AGENT']) && (strpos($_SERVER['HTTP_USER_AGENT'], 'MSIE') !== false)) return true; else return false; } if (ae_detect_ie()) { header("Location: error.php"); } else { header("Location: index.php"); } ?> Folks, When someone click on a link on my webpage and if that Link takes the visitor off my site, then i want to make an entry in my database. But if that link goes back to some other link in my Site then i do not want to Count that link. So, is there any code that lets me detect any outgoing link Click? Cheers This topic has been moved to PHP Freelancing. http://www.phpfreaks.com/forums/index.php?topic=358545.0 I have a web site where users can gain points, when they use my site. For example, if the user spends $10.00 then the user will get 10 points. In my web site there is a list of 10 retails (name). When the user clicks the link it will redirect to retailers website, where user can buy items. How can I find out how much the user has spent on the retailer? Thank you. Can you suggest a better way to write this code (I didn't create it):
<body onload="getParameterByName('url')">
<a href="" id="urllink" >Click Here</a>
</body>
so, I don't have to change the <body> tag?
suggestions on how to write this code better I have a form that has 2 textboxes in it. The php listed below...confirms that the passwords match, confirms that there are at least 6 characters in in, confirms that there is at least 1 number. I am doing mostly if statements with it, but I was wondering if there was a better way to write. Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <title>Untitled Document</title> </head> <body> <form name="form1" method="post" action="<?PHP $_SERVER['PHP_SELF'] ?>"> <table width="100%" border="1"> <tr> <th scope="row"> <strong>New password: </strong> <input type="password" maxlength="15" name="password"></th> <th scope="row"> <strong>New password confirmed: </strong> <input type="password" maxlength="15" name="confirm_password"></th> <th scope="row"><input type="submit" name="update" value="Update Password" /></th> </tr> </table> </form> <?PHP //verify that the update button is pressed if (isset($_POST['update'])) { //verify that the passwords match if($_POST['password'] == $_POST['confirm_password']) { echo "passwords match"; echo "<br>"; } //verify that the password and password confirmation was entered elseif ((isset($_POST['password'])) && ($_POST['confirm_password'])) { echo "Password and confirm password set"; echo "<br>"; } //verify that the # of characters was entered elseif (strlen($_POST['password'])<6) { $num_char=strlen($_POST['password']); echo "Please enter more characters"; echo "<br>"; } //find out if number exsist if (strlen($_POST['password'])>5) { $subject = $_POST['password']; preg_match_all('/[0-9]/', $subject, $matches); $count = count($matches[0]); //echo $count; if ($count <=1) echo "Please enter in at least 1 number you currently have: " .$count; }//close of verification of both boxes entered }//close of $_POST ?> </body> </html> <?php $result = "SELECT * FROM portfolio"; $result = mysql_query ($result) or die (mysql_error()); $i=0; while($row = mysql_fetch_assoc($result)) { if($i==0) echo '<div class="portfolioPage">'; if($i==2) $divclass = 'portfolioProjectWrapper borderWhite'; else $divclass = 'portfolioProjectWrapper borderGray'; echo ' <div class="'.$divclass.'"> <a href="portfolioPage.html" class="image asyncImgLoad" title="img/'.$row['image290x290'].'"></a> <p class="imageDesc">'.$row['image290x290_phot'].'</p> <h3 class="title">'.$row['title'].'</h3> <p class="subtitle">'.$row['subtitle'].'</p> <p class="desc"> '.substr($row['description'], 0, 1200).' <a href="portfolioPage.html" class="commonLink">Read more</a> </p> </div> '; if($i==2) echo '</div>'; if(i==2) $i=0; else $i++; } ?> Please help me im backward at this been along time. This topic has been moved to Miscellaneous. http://www.phpfreaks.com/forums/index.php?topic=327190.0 this is an array returned after parsing YAMl file using spyc api. i want to write a code to to extract value related to key topic name and put in a separate 1d array say $topicnames Array ( [1] => Array ( [topicname] => singapore travels [rev] => 250 => Array ( [25] => Array ( ) [topicname] => airlines [rev] => 24 ) [1] => Array ( [35] => Array ( ) [topicname] => shubham [rev] => 65 ) ) [2] => Array ( [topicname] => singapore entertainment [rev] => 210 => Array ( [45] => Array ( ) [topicname] => night safari[rev] => 54 ) i tried using simple for loop but not working.. pl help me out. I am a complete newbie. I have installed xampp. I created a database and the tables but that is all. I need to create all my relationships and test my database. to do this, do I now need to write the php code to view the results in a browser or... do I do it in MySQL. If so, Can someone just point me in the direction I need to go for my next step.
Thanks
I have a small project. I have a control board that is connected to the parallel port. It controls 8 strips of LED on the LPT1 port. I can turn these on and off via the command prompt, using LPTOUT.exe ie lptout 1 turns on the 1st LED lptout 2 will turn off 1st LED and turn on 2nd, lptout 4 turns on 3rd and 2nd off, etc 1, 2, 4, 8, 16, 32, 64, 128. and combinations ie lptout 3 turns on LEDS 1 and 2, and so on. However lptout seems very unresponsive sometimes I have to do lptout 1 twice before LED 1 turns on. Is there another command I can use to write to LPT1 port. I need some PHP code to control the outputs. I want to sequence the outputs ie 1on (1second) 2on (1 second) 3 on (1 second) 4 on etc. to 8, then all off then repeat. Can anyone help me. THANK YOU. This topic has been moved to PHP Applications. http://www.phpfreaks.com/forums/index.php?topic=321270.0 Code: [Select] <?php if (eregi("MSIE",getenv("HTTP_USER_AGENT")) || eregi("Internet Explorer",getenv("HTTP_USER_AGENT"))) { Header("Location: http://mysite.com/ie_reject.html"); exit; } ?> How would i make users who are using Safari get redirected like in this example would i use this Code: [Select] <?php if (eregi("SAFARI",getenv("HTTP_USER_AGENT")) || eregi("Safari",getenv("HTTP_USER_AGENT"))) { Header("Location: http://mysite.com/safari_reject.html"); exit; } ?>If so how would i add these together in one statement to stop both accessing my site and get redirected so I am a beginner and have this very beginner-level PHP doubt. I have some basic code which is supposed to fetch the contents of a table and then display them in a table. What it's actually showing is the PHP code itself, instead of the table contents, in the browser. I'm using WAMP When I searched the net reasons given were 1. using short tags, and 2. some configuration problem. I haven't used short tags, and my wamp installation was done a long time back. Moreover this problem is not occuring all the time, even when I run the same code. Many thanks if anyone can suggest anything helpful. Sorry if I posted in the wrong place (new here). I have a form that users input user name, password, and email... all writes to csv fine. My problem is I need to concatenate a a string with a variable and some html code will preserving the html when written to the csv.. I need the csv to be this username,password,email,user,category,text with http://sub.domain..com/splash/,something,something here's what i have Code: [Select] <?php if($_POST['formSubmit'] == "Submit") $varUserName = $_POST['username']; $varPW = $_POST['PW']; $varEmail = $_POST['email']; { $fs = fopen("testcsv.csv","a"); fputcsv($fs, array($varUserName,$varPW,$varEmail,"user","title",",category","some text '<a href="http://$varUserName.url.com/splash/>site.com</a>',)); fclose($fs); exit; } ?> and of course I'm getting Parse error: syntax error, unexpected T_STRING, expecting ')' on line 9 I am trying to make a loop simply write "static" code...if that is the correct explanation.... But it seems PHP wants to "process" such things as 'IF' and other Conditions which is defeating the purpose. The problem specifically is that I NEED for a dynamic write to happen based on a variable that will put the following lines that start with IF (! isset // Make sure the checkbox arrays exist if (! isset($_POST['cp_checkbox_one'])) $_POST['cp_checkbox_one'] = array(); if (! isset($_POST['cp_checkbox_two'])) $_POST['cp_checkbox_two'] = array(); if (! isset($_POST['cp_checkbox_three'])) $_POST['cp_checkbox_three'] = array(); // here in the lines below is one way I have tried to make the the LINES ABOVE get written Dynamically // THIS PART returns the values I need, the checkbox names ---- // // foreach($_POST as $meta_key => $meta_value) { // if(cp_str_starts_with($meta_key, 'cp_checkbox')) { echo $meta_key; } // } // So that code WILL RETURN THE VALUES I NEED : // cp_checkbox_one, cp_checkbox_two, cp_checkbox_three // BASED ON THIS I WROTE THE FOLLOWING CODE-- BUT IT DOES NOT WORK AS A REPLACEMENT FOR A LINE // SUCH AS--- if (! isset($_POST['cp_checkbox_one'])) $_POST['cp_checkbox_one'] = array(); // function checkboxloop() { foreach($_POST as $meta_key => $meta_value) { if(cp_str_starts_with($meta_key, 'cp_checkbox')) { if (! isset($_POST[$meta_key])) $_POST[$meta_key] = array(); } } } // HERE I ASK FOR THE FUNCTION BUT WHILE I GET NO ERRORS I GET NO RESULTS // WHICH IS A PROPER SAVE OF UNCHECKED CHECKBOXES ON SUBMIT checkboxloop; I would very much appreciate knowing how to make the code keep looping whatever $meta_key names turn up on this page and then use those names to write the complete lines as STATIC PHP so that the IF conditions don't get "processed" while this function is called. In effect, I want to duplicate the effect of having the code lines WRITTEN, so that they perform exactly as if I had written them as PHP hard-code, as many lines as there will be $meta_keys, but not SEE the code--- just have it valid PHP. This function does NOT make the same thing happen internally. As soon as I replace the function with the HARD CODE PHP then it works...but, I have reached the stage where these lines of code have to happen dynamically. I am baffled how to get this to happen! If I use Echo then I get errors about the "IF". Thank you very much for your help! Hi, I came across this code that detects a user's browser and I don't understand parts of it. Here is the code below. Code: [Select] $agent = $_SERVER['HTTP_USER_AGENT']; if ( strpos(strtoupper($agent), 'MSIE')) { print "Internet Explorer"; } else if (strpos(strtoupper($agent), 'FIREFOX')) { print "Firefox"; } else if (strpos(strtoupper($agent), 'KONQUEROR')) { print "Konqueror"; } else if (strpos(strtoupper($agent), "LYNX")) { print "Lynx"; } else { print $agent; } and here is the part I don't understand. Code: [Select] if ( strpos(strtoupper($agent), 'MSIE')) I know that strtoupper makes all letters uppercase, and that strpos returns the position of the string within the larger string, but I don't know why they are in an if statement. Any help or explanation is greatly appreciated. Thanks. Derek |
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