PHP - Add Variables From Functions Using A Class
I think I need to use $this, but I need to be able to add the two values returned from both of my functions. How would I do that?
Code: [Select] public function get_users_edge($uid) { $users_primary->get_users_primary_edge($uid); $users_dynamic->get_users_dynamic_edge($uid); echo $users_primary + $users_dynamic; } Similar TutorialsHi, I need to be able to call a class based on variables. E.G. I would normally do: Code: [Select] $action = new pattern1() but i would like to be able to do it dynamicaly: Code: [Select] $patNum = 1; $action = new pattern.$patNum.() Im wondering if that's possible? If so what would the correct syntax be? Many Thanks. I have a database that holds a list of companies. the database includes and ID, and name of each company. Now when an articles gets submitted to my site it can then be related to company. We a relate a company to an article its related through its ID. What I want to do is create a function that would let me easly convert my company ID into company name within having to write out the queries over and over again in my code. Only problem is I can't get it to work. I have two files, index.php and functions.php. functions.php Code: [Select] function cname($pubid) { global $db; $company= $db->query("SELECT * FROM my_database WHERE id='$pubid'") or die(mysql_error()); while($company= $db->fetch_array($company)) { $cname = $company['name']; } return $cname; } and within index.php I put Code: [Select] echo cname($companyID); Now, when I first looked at index.php I was getting an error. I know it had something to do with me using my variables within the function and after some searching I ended up getting rid of the error by adding "global $db;" to my code. Please note that I include functions.php at the top of index.php. What am I doing wrong and why wont it work? HELP PLEASE! also note that my i've rechecked and all the database info is correct and names spelt right. Just dont know what else to do. Hi,
I'm struggling to understand how to load a PHP classes for my database into a php function.
My class in on another file, which is included into my page.
I then have a function that usings the class of $database->query in the function, but for some reason this doesn't work.
However the class works on the page outside of the function, is there someway I must load the class into my function?
Thanks for reading.
hello i have some normal php functions that i want to put into a oop class. i cant seem to make the right changes to make it work. could some one help please. thanks these are the php functions Code: [Select] <?php function hasChild($parent_id) { $sql = "SELECT COUNT(*) as count FROM category WHERE parent_id = '" . $parent_id . "'"; $qry = mysql_query($sql); $rs = mysql_fetch_array($qry); return $rs['count']; } function CategoryTree($list,$parent,$append) { $list = '<li>'.$parent['name'].'</li>'; if (hasChild($parent['id'])) // check if the id has a child { $append++; $list .= "<ul class='child child".$append."'>"; $sql = "SELECT * FROM category WHERE parent_id = '" . $parent['id'] . "'"; $qry = mysql_query($sql); $child = mysql_fetch_array($qry); do{ $list .= CategoryTree($list,$child,$append); }while($child = mysql_fetch_array($qry)); $list .= "</ul>"; } return $list; } function CategoryList() { $list = ""; $sql = "SELECT * FROM category WHERE (parent_id = 0 OR parent_id IS NULL)"; $qry = mysql_query($sql); $parent = mysql_fetch_array($qry); $mainlist = "<ul class='parent'>"; do{ $mainlist .= CategoryTree($list,$parent,$append = 0); }while($parent = mysql_fetch_array($qry)); $list .= "</ul>"; return $mainlist; } ?> this is the class Code: [Select] <?PHP require_once(LIB_PATH.DS.'database.php'); class Menu extends DatabaseObject { protected static $table_name="menu"; protected static $db_fields = array( 'id', 'parent_id', 'name' ); public $id; public $parent_id; public $name; // "new" is a reserved word so we use "make"(or "build") public static function make( $id, $parent_id, $name) { if(!empty($id)) { $kw = new Menu(); $kw->id = (int)$id; $kw->parent_id = (int)$parent_id; $kw->name = $name; return $kw; }else{ return false; } } //end function make //PUT FUNCTIONS HERE...... function hasChild($parent_id) { $sql = "SELECT COUNT(*) as count FROM category WHERE parent_id = '" . $parent_id . "'"; $qry = mysql_query($sql); $rs = mysql_fetch_array($qry); return $rs['count']; } function CategoryTree($list,$parent,$append) { $list = '<li>'.$parent['name'].'</li>'; if (hasChild($parent['id'])) // check if the id has a child { $append++; $list .= "<ul class='child child".$append."'>"; $sql = "SELECT * FROM category WHERE parent_id = '" . $parent['id'] . "'"; $qry = mysql_query($sql); $child = mysql_fetch_array($qry); do{ $list .= CategoryTree($list,$child,$append); }while($child = mysql_fetch_array($qry)); $list .= "</ul>"; } return $list; } function CategoryList() { $list = ""; $sql = "SELECT * FROM category WHERE (parent_id = 0 OR parent_id IS NULL)"; $qry = mysql_query($sql); $parent = mysql_fetch_array($qry); $mainlist = "<ul class='parent'>"; do{ $mainlist .= CategoryTree($list,$parent,$append = 0); }while($parent = mysql_fetch_array($qry)); $list .= "</ul>"; return $mainlist; } ?> Hi! I have a class with many functions/methods. I want to split this into different files so I can easily edit and add functions. I want every functions to be able to call eachother and with that I mean, they have to be for example in same document. My question is: I can't have a class and include functions like this: Code: [Select] class DB { include('select_functions.php'); //Only includes function's no class include('insert_functions.php'); //Only includes function's no class include('delete_functions.php'); //Only includes function's no class function test() { } } The includes will output fatal errors... How can I solve this so I can have all functions in different files but still use ONE object to call them! Thanks! I have this function: Code: [Select] function echo_exist($pre1,$ee,$post1) { if ($ee!='') { return $pre1; return $ee; return $post1; } else { //do nothing } } But when I try to echo it Code: [Select] echo_exist("(","$row['payment_type']",")"); I get syntax error, unexpected T_ENCAPSED_AND_WHITESPACE If $row['payment_type'] exists, I want it to be displayed in parentheses like: (AUTO) I suspect it has to do with my ' characters for the associative array, but I am new with functions so perhaps it is the multiple arguments that are wrong? Still working on my project, and i have been learning a lot here! Thank you so much. But as you may have guessed, i still have problems. User registration is working, and new users are put in the database with a rank of 0. This means they can't do anything. (can there be trouble with this. I mean, a rank of "0"?) An admin needs to give access to these accounts, but that is where it becomes difficult. The following code is showing the new accounts to the admin. Code: [Select] <?php include("navbar.php"); if ($admin<2) //normal guy or not { die ("Du har ikke rettigheder til at se denne side!"); } else if(isset($_POST['submit'])) { //code to make the user able to use stuff } { $connect = mysql_connect("localhost","root",""); mysql_select_db("eksamen - phoenix"); $query = mysql_query("SELECT * FROM users WHERE rank='0'"); ?> <form action='admin.php' method='POST'> <table> <?php while($row = mysql_fetch_assoc($query)) { echo " <tr> <td> ".$row['username']." </td> <td> ".$row['email']." </td> <td> ".$row['real_name']." </td> <td> <input type=\"checkbox\" name=".$row['username']." value=\"Godkend\"> </td> </tr> ";} ?> <tr> <td> <input type='submit' name='submit' value='Register'> </td> </tr> </table> </form> <?php } ?> As you may see, there is a lot of turning php on and off. I made it work this way, but i guess there is nothing wrong with it. The problem is that the username is not stored, so i can connect to the database and change the "rank" value. Changing that value should be easy, but storing the username is as easy as i thought. Any ideas? I have a little problem. I have made a script(function) to connect to the database. this is the script: connect(php) Code: [Select] <?php $server = "localhost"; $username = "username"; $password = "password"; function connectdatabase($type,$database) { if($type == "mysql") { $mysql = mysql_connect($server, $username, $password); mysql_select_db($database, $mysql); } else if($type == "mysqli") { $mysqli = new mysqli($server, $username, $password, $database); } else if($type == "mssql") { $mssql = mssql_connect($server, $username, $password); mssql_select_db($database, $mssql); } function query($query) { if($type == "mysql") { mysql_query($query); } else if($type == "mysqli") { $mysqli->query($query); } else if($type == "mssql") { mssql_query($query); } } } ?> and aanmelden(php) Code: [Select] <?php include("config.php"); connectdatabase("mysql", "[ledensysteem]"); //example if(!empty($_POST)) { if(!preg_match('/^[A-Za-z1-9-]{'.$Minimale_Gebruikersnaam_Karakters.',}$/', $_POST['gebruikersnaam'])) { if(!isset($error)){ $error=1;}else{$error=$error+1;} echo "Je gebruikersnaam moet minimaal {$Minimale_Gebruikersnaam_Karakters} tekens bevaten en mag geen komma of andere onbedoelde tekens zijn<br>Toegestaan is <br>A t/m Z <br>a t/m z <br>1 t/m 9 <br>en -"; } else { echo "geldige gebruikersnaam(goedgekeurd)"; } if(preg_match('/^[A-Za-z1-9-]{'.$Minimale_Wachtwoord_Karakters.',}$/', $_POST['wachtwoord']) && preg_match('/^[A-Za-z1-9-]{'.$Minimale_Wachtwoord_Karakters.',}$/', $_POST['herhaalwachtwoord'])) { if($_POST['wachtwoord'] != $_POST['herhaalwachtwoord']) { if(!isset($error)){ $error=1;}else{$error=$error+1;} echo "niet hetzelfde wachtwoord"; } /*else { echo "hetzelfde wachtwoord (goedgekeurd)"; }*/ } else { if(!isset($error)){ $error=1;}else{$error=$error+1;} echo "wachtwoord moet minimaal {$Minimale_Wachtwoord_Karakters} tekens bevatten!"; } if(!preg_match("/^[A-Za-z1-9_.-]{1,}@[A-Za-z1-9-]{1,}\.[A-Za-z1-9]{2,3}$/", $_POST['email'])) { if(!isset($error)){ $error=1;}else{$error=$error+1;} echo "onjuiste email"; } else { echo "goedgekeurd!"; } if(!isset($error)) // this problem is fixed yesterday on phpfreaks.com forum! { echo "goedgedaan geen errors!"; query("SELECT username FROM phpfreaks WHERE password = private"); // example } } else { ?> <HTML> <HEAD> <TITLE>New Document</TITLE> </HEAD> <BODY> <form method="post"> <input type="text" name="gebruikersnaam" value="gebruikersnaam" maxlength="20" size="20"> <input type="password" name="wachtwoord" value="wachtwoord" maxlength="20" size="20"> <input type="password" name="herhaalwachtwoord" value="herhaalwachtwoord" maxlength="20" size="20"> <input type="text" name="email" value="voorbeeld@domeinnaam.extensie" maxlength="50" size="20"> <input type="submit" name="login" value="inloggen"> </form> </BODY> </HTML> <?php } ?> the problem is, is that i want to pass a variable between functions like $type (the database type) between connectdatabase(); and query(); in the 'aanmelden.php' file is an example of how i use the function (on line 3 and 45 the ones with //example comment) thanks for reading. please help. ps. config.php contains include("connect.php"); Learning something new here so if anyone can tell me why I this wont return a value? page1.php Code: [Select] <?php require "page2.php"; getuserid(); echo $userID; ?> page2.php Code: [Select] <?php function getuserid() { $user =& JFactory::getUser(); $userID = $user->id; global $userID; } ?> I've written the following code: Code: [Select] $mode = 'development'; // 'Development' or 'Public' // Writes a buffer to a file /** * ob_file_callback() * Writes the generated CSS to a file. * @param mixed $buffer * @return void */ function ob_file_callback($buffer) { // stylesheet-public.css is the output generated file $ob_file = fopen('stylesheet-' . $mode . '.css','w'); fwrite($ob_file, $buffer); } $buffer = 'test'; ob_start('ob_file_callback'); $mode is always empty when I run this code. Is it an issue because ob_file_callback is an overridden function? Hi, In all my classes, I need to declare globals for everything else, from site variables even to objects (other classes). I obviously don't want to as globals are horrible and I need to have functions clean without globals. I have included a list of all the global vars in the construct and it still doesn't work. Example: start.php <?php $vars = array(some values); $some = more; $variables = foo; $helper = new Helper(); $home = new Home(); This is a little bit simplistic, but for some reason, the variables just don't want to go in the main class without a global. Functions will not run if they require any of these variables. I have some questions about the scope of navigation : if i define a constant like define('constant'), php manuel says it's global, does this mean that i can use of different files also? like, i defined in define.php and used in anotherfile.php, or shoud the latter file be included then? what about file a.php includes file b.php which in turn includes file c.php. Can functions of a use variables of file c? ultimately: what about variables that are declared global inside a function but this variables is not initialized in that script, like in wordpress: function date_i18n( $dateformatstring, $unixtimestamp = false, $gmt = false ) { global $wp_locale; // more code } $wp_locale can be initialized in another script file? thanks in advance Hi, I'm having a bit of a problem understanding why I'm not able to use the class I'm extending off of functions. I have a category class that extends off my core class, inside that category class, I'm able to use the core functions and variables inside all custom functions, but not the __construct function. So, to be clear, inside class class, I'm able to call $this->core->function() inside custom functions, such as function add_parent(), but not the __construct function. Why is this happening, what is the logic behind this? This is how I'm extending the class off of the core class: Code: [Select] <?php $core = new core; $parent = new parents; $parent->core =& $core; ?> With this, like I said, I'm able to use all of my core functions inside all other classes called this way, so inside all of the other classes I can do: Code: [Select] <?php $this->core->function(); ?>everywhere besides __construct(). Do I not have the class called properly? Do I need to pass my core class through differently? How can I fix this? Thanks. I am currently building my own MVC Framework and I have run into an issue that I can't solve when attempting to use 2 methods from a single model. I know that this isn't an issue with the queries or information being return. I am unsure of the proper way that I can call 2 methods when checking to see if a user is logged in... The issue that I face is both methods are calling the DB and it throws a PDO error which I don't know how to get around the issue.. Any guidance would be nice as I have been banging my head over this issue. Thank you!
Fatal error: Uncaught Error: Call to undefined method PDO::Select() in C:\xampp\htdocs\PicWrist\app\models\user.class.php:318 Stack trace: #0 C:\xampp\htdocs\PicWrist\app\controllers\home.php(21): User->getUser('4') #1 C:\xampp\htdocs\PicWrist\app\core\app.php(36): Home->index() #2 C:\xampp\htdocs\PicWrist\app\init.php(47): App->__construct() #3 C:\xampp\htdocs\PicWrist\public\index.php(5): require('C:\\xampp\\htdocs...') #4 {main} thrown in C:\xampp\htdocs\PicWrist\app\models\user.class.php on line 318
//Controller <?php /** * Load the View */ class Controller{ public function view($view, $data = []) { if (file_exists('../app/views/' . $view . '.php')) { require_once '../app/views/' . $view . '.php'; } } public function model($model, $data = []) { if (file_exists('../app/models/' . $model . '.class.php')) { require_once '../app/models/' . $model . '.class.php'; return new $model(); } else return false; } } ?> //Home Controller <?php Class Home extends Controller { public static $user; public $errors; public function __construct() { self::$user = $this->model('user'); } public function index() { $userdata = []; $data = []; show(self::$user); $isLoggedin = self::$user->isLoggedin; show($isLoggedin); $userdata = self::$user->getUser($_SESSION['user_id']); show($userdata); $this->view('home', $data); } } ?> <?php /** * Users */ class User { private $db; private $errors = ''; public $isLoggedin = False; public $isAdmin = False; public function __construct() { $this->isLoggedIn(); } public function isLoggedIn() { if(isset($_SESSION['user_id'])){ $data['user_id'] = $_SESSION['user_id']; $db = Database::getInstance(); $query = "SELECT * FROM users WHERE user_id = :user_id LIMIT 1"; $results = $db->Select($query, $data); if (is_array($results)) { $this->isLoggedIn = True; } } } public function getUser($id) { if(isset($id)) { $data['user_id'] = intval($id); $db = Database::getInstance(); $query = 'SELECT * FROM users WHERE user_id = :user_id'; $results = $db->Select($query, $data); if (is_array($results)) { return $results; } else { return False; } } else { return False; } } //DB <?php /** * Database Connection */ class Database { private $dbHost = DB_HOST; private $dbUser = DB_USER; private $dbPass = DB_PASS; private $dbName = DB_NAME; private $statment; private static $dbHandler; private $error; public function __construct() { $conn = 'mysql:host=' . $this->dbHost . ';dbname=' . $this->dbName; $options = array( PDO::ATTR_PERSISTENT => true, PDO::ATTR_ERRMODE => PDO::ERRMODE_EXCEPTION ); try { self::$dbHandler = new PDO($conn, $this->dbUser, $this->dbPass, $options); } catch (PDOException $e) { self::$error = $e->getMessage(); echo self::$error; } } public static function getInstance() { if(self::$dbHandler) { return self::$dbHandler; } return $instance = new Self(); } public function Select($query, $data = array()) { $statement = self::$dbHandler->prepare($query); $result = $statement->execute($data); If($result) { $data = $statement->fetchAll(PDO::FETCH_OBJ); if(is_array($data)) { // show($data); return $data; } } return False; } public function Update($query, $data = array()) { $statement = self::$dbHandler->prepare($query); $result = $statement->execute($data); If($result) { return True; } return False; } } ?> Edited July 14 by avargas94 Wrong Code This is a bit of a more advanced question so I am hoping there are some advanced programmers online at this time . Anyways basically I want to be able to "queue" functions from a class in a single call and am wondering if I am doing it correctly or if there is a better way to do it. Here is my code: <?php class test { private static $one; private static $two; private static $three; public function callOne($val){ $one .= $val; return $this; } public function callTwo($val){ $two .= $val; return $this; } public function callThree($val){ $three .= $val; return $this; } public function print(){ echo $this->one.' '.$this->two.' '.$this->three; } } ?> now when I want to call this I can do: $test = new test(); $test->callOne('one')->callTwo('two')->callThree('three'); $test->callOne('another one'); $test->print(); Is there a better way to do this or is there a different method of doing this? Just wanna make sure I am doing it right lol. Was just wondering why some people choose NOT to make use of static functions when initializing objects via Factory Classes/Containers. What are the benefits of initializing the Factory class when for all intensive purposes, it's only used to initialize new classes, etc? Does this have any impact on Dependency Injection? I'm assuming that it doesn't since that would defeat the purpose. --------- Also, I've noticed that there seems to be an intense stigma within the development community in regard to singletons. Are singletons necessarily a bad thing? What about database objects? One argument I've heard is that this can often impact the flexibility of your application in the event that a new instance of said class needs to be initialized(a second completely separate connection). However, I was thinking that you could simply store these objects within a static member variable in the factory class; leaving the Database Class' __construct public in the event that you need to create that second/third/fourth connection. Wouldn't this resolve the issue? I am getting the following error: Parse error: parse error, expecting `T_OLD_FUNCTION' or `T_FUNCTION' or `T_VAR' or `'}'' in /Library/WebServer/Dev/classtest/lib/class_userdata.php on line 5 on this class code: Code: [Select] class userdata { public $name = ""; public $city = ""; public $phone = ""; function setData($n, $c, $p) { $name = $n; $city = $c; $phone = $p; } function getData() { $userdata=array('name'=>$name, 'city'=>$city, 'phone'=>$phone); return $userdata; } } I thought that was a proper way to set up some class variables. (http://www.victorchen.info/accessing-php-class-variables-and-functions/). Thanks. Does anyone know if it's possible to call a class with an arbitrary number of variables? I'll explain what I mean. Here is my class construct definition: Code: [Select] function __construct($file, $outFile = 'newpdf.pdf', $fontSize = 70, $alpha=0.6, $overlayMsg = 'N O T F O R S H O P', $degrees = 45) { I know that I have to pass over the $file variable for it to work now. But can I create the class passing just the $file var and the $overlayMsg var? Everything else I would want to leave as default. How would I do that? Thanks Mike I keep running into a bunch of error when I declare the page variable in my model. What syntax do I need to use throughout the class? Code: [Select] <?php if ( ! defined('BASEPATH')) exit('No direct script access allowed'); class Header_Model extends CI_Model{ var $page = substr(end(explode(DIRECTORY_SEPARATOR, $_SERVER['PHP_SELF'])), 0, -4); function get_page_name() { $this->load->library('common'); $page_names = $this->common->page_names(); $title = (array_key_exists($page, $page_names) !== false) ? $page_names[$page]: ''; if (array_key_exists($page, $page_names) !== false) { $title .= " | Jason Biondo"; } return $title; } function get_js_page_file() { if (file_exists("./assets/js/pages/${page}.js")) { $javascript = "<script type=\"text/javascript\" src=\"./js/pages/${page}.js\"></script>"; } return $javascript; } } I'm confused as to why assigning these variables in the class causes the page not to load... var $RootFolder = '/shyid/'; var $PagePath = str_replace($this->RootFolder, '', dirname($_SERVER['PHP_SELF'])); var $PageSections = explode('/', $this->PagePath); but when i set them on the page, everything works correctly? $head->RootFolder = '/shyid/'; $head->PagePath = str_replace($head->RootFolder, '', dirname($_SERVER['PHP_SELF'])); $head->PageSections = explode('/', $head->PagePath); Insight? Thanks. |