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PHP - Simple Php Twitter Script
If you look at the botton of http://getminecraft.net/ you see my latest tweets. The problem is that it shows http://getminecraft.net/%22http://twitter.com/PC_Gamer%22 instead of the original twitter url, that results to a wrong url and wrong site. How can I fix it? so it shows the original twitter url. Here is the script:
<?php $username = "getminecraft"; $prefix = ""; $suffix = ""; $feed = "http://search.twitter.com/search.atom?q=from:" . $username . "&rpp=1"; function parse_feed($feed) { $stepOne = explode("<content type=\"html\">", $feed); $stepTwo = explode("</content>", $stepOne[1]); $tweet = $stepTwo[0]; $tweet = str_replace("<", "<", $tweet); $tweet = str_replace(">", ">", $tweet); return $tweet; } $twitterFeed = file_get_contents($feed); echo stripslashes($prefix) . parse_feed($twitterFeed) . stripslashes($suffix); ?> Similar TutorialsHi all, Since twitter changed the way they allow people to post, my simple php script to grab the $_POST data from an input and post it to my twitter profile has broken. I've been reading up on Oauth, but none of the documentation is clear at all. It's quite complex, in fact - they assume you are creating a full app, which I am not - I just want to flick some text to twitter. I just want to pass a simple string variable to my account - can anyone help me with how to do this? All help appreciated. WoolyG Hello all, I have followed the stop on this page to what I thought was a tee: http://www.inkplant.com/code/pull-tw...-your-site.php but I guess I was wrong because I am getting errors. I have setup the database and table properly and created all files, but when I do step 4 and place the code on my site I am getting this error Code: [Select] Fatal error: Call to undefined function dbQuery() The api pull went fine and it stored the tweets in the database, but it can't display them. Is there a missing step about connecting to the database somewhere? Thanks for any help Hey folks, looking for a twitter follow/unfollow php script that WORKS. any hints/links? thanks Im trying to make a php program that will grab all the user's tweets they have ever done.. I'm using curl to request the twitter page and scrape the html. It looks as though the maximum amount of tweets I can get is 20, which is the amount on the initial first page. There is some script that loads another 20 tweets once I scroll to the bottom of the page... Does anyone know how to make the page automatically load a certain amount so I can scrape more than the first 20 at once. Hello, im very green to php and I am having trouble creating a simple log in script. Not sure why this is not working, maybe a mysql_query mistake? I am not receiving any errors but nothing gets updated in the members table and my error message to the user displays. any help is appreciated! here is my php: <?php session_start(); $errorMsg = ''; $email = ''; $pass = ''; if (isset($_POST['email'])) { $email = ($_POST['email']); $pass = ($_POST['password']); $email = stripslashes($email); $pass = stripslashes($pass); $email = strip_tags($email); $pass = strip_tags($pass); if ((!$email) || (!$pass)) { $errorMsg = '<font color="#FF0000">Please fill in both fields</font>'; }else { include 'scripts/connect_db.php'; $email = mysql_real_escape_string ($email); $pass = md5($pass); $sql = mysql_query("SELECT * FROM members WHERE email='$email' AND password='$pass'"); $log_check = mysql_num_rows($sql); if ($log_check > 0) { while($row = mysql_fetch_array($sql)) { $id = $row["id"]; $_SESSION['id']; $email = $row["email"]; $_SESSION['email']; $username = $row["username"]; $_session['username']; mysql_query("UPDATE members SET last_logged=now() WHERE id='$id' LIMIT 1"); }//Close while loop echo "You are logged in"; exit(); } else { $errorMsg = '<font color="#FF0000">Incorrect login data, please try again</font>'; } } } ?> and the form: <?php echo $errorMsg; ?> <form action="log_in.php" method="post"> Email:<br /> <input name="email" type="text" /><br /><br /> Password:<br /> <input name="password" type="password" /><br /><br /> <input name="myBtn" type="submit" value="Log In" /> </form> Hi can someone pls help, im tryin a tutorial but keep getting errors, this is the first one i get after registering. You Are Registered And Can Now Login Warning: Cannot modify header information - headers already sent by (output started at /home/aretheyh/public_html/nealeweb.com/regcheck.php:43) in /home/aretheyh/public_html/nealeweb.com/regcheck.php on line 46 <html> <head></head> <body> My favourite bands a <ul> <?php // define arrays $morebands = array('Desturbed', 'Anthrax'); $artists = array('Metallica', 'Evanescence', 'Linkin Park', 'Guns n Roses', "$morebands"); // loop over it // print array elements foreach ($artists as $a) { if ($a != 'Array'){ echo '<li>'.$a; } Else { foreach ("${$a}" as $b){ echo '<li>'.$b; } } } ?> </ul> </body> </html> I can not figure out why this will not work:( I would like the foreach to run through the array as normal, but if it encounters a nested array, loop it as well. I know this likely is not the right, or best way to do this, but I am just learning PHP through a tutorial and I learn best by doing... So I take the lessons, make them more complicated, then figure out how to make it happen (like so). right now I am working on http://devzone.zend.com/node/view/id/635 anyhow thanks for any help! I was told that you guys could probably help me with this, so heres my situation. I use this program called Activeworlds, and me and my buddies are makeing a "tv show" if you will within the program. To do so, you take screenshots, save the screenshots, and add the image files into a directory on your domain. You need a .php script to present them as a slideshow. Now the problem is, ive searched for scripts already made from other sites, but the thing is, they are all fancy slideshow viewers, meaning they come with control buttons to cycle through the pictures and all kinds of other banners and flashy looking things. The only script im needing, is a simple script that will display and cycle through the raw images, and nothing else, within the web browser, in a slideshow format. Id also like to have a value I can edit that will change how fast the pictures cycle through, 15 seconds or so would be perfect however. If someone could refer me to this code or even make it for me, it would be soo appreciated. I know im probably asking for alot, but it would help me soo much. I wish I knew a little more about .php files to do it myself, or else I would. If you do link me to a script, please give me simple instructions on what to do with it lol because like I said, I dont know anything about the world of .php yet. Thank you all for your time. Good evening guys and gals, for some reason I cant get my head around something quite simple, basically I am trying to work out a way of simply recording referrals to my site when the potential user registers. This worded example is basically what I want: registered user a with a username of smithy invites his friend western to become a member of a site he has joined: I guess here I would basically use something like mysite.com?refid=smithy as the link he gives he's friend Now this is where my brain refuses to work, what if western decides to have a look around the site before he decides to register and clicks on a few internal pages? Obviously the referral id will no longer be in the address bar. So my 1st question is, how can I check to see if a referral is used when accessing the site? I could then store the username in a session or cookie. If I had something like this: <?php $refid = $_GET('refid') setcookie("user", $refid, time()+3600); ?> But how would I check that a refid exists in the url so it doesnt throw up a parse error? I have more questions but 1 thing at a time! Many Thanks Can someone show me a simple mail script that I can run in cli, I can enter a $to = email@email.com and then have it send to my email? just in cli.. Thanks Hiya! I need to create a simple PDF script that will always create A4 documents. I need the content to be controlled using HTML and CSS. Where do you start in creating such a script? Any help is greatly received. I've tried Googling this for a long time but I only find complete member systems with ugly code, not something i'm looking for. What I am looking for is just a simple tutorial or commented code to make a admin login. What it's going to do is just: Loading a MD5 salt hasched password from my MYSQL database. You'll get to fill in one field: Password. If it validates with the MYSQL password it'll show the hidden content; if not it'll just give a "not correct error". That's basicly it. I have only one page of secret admin stuff so yeah.. it would be awesome to have the ability to logout and I of curse want to have everything in sessions! It would be to big help! Hi all, Im coding a simple script for my website which just changes the users rank. Code: [Select] <?php session_start(); include "../includes/db_connect.php"; include "../includes/functions.php"; logincheck(); ini_set ('display_errors', 1); error_reporting (E_ALL); $username=$_SESSION['username']; $get = mysql_query ("SELECT * FROM users WHERE username = '$username'"); $fetch = mysql_fetch_object($get); if ($fetch->userlevel >= "2"){ $newrank = $_POST['newrank']; $user1 = $_POST['user']; if (strip_tags($_POST['update'])){ mysql_query("UPDATE users SET `rank` = '$newrank' WHERE username='$user1'") or die (mysql_error()); echo ("You have updated $user1's rank to $newrank !"); } } else{ echo ("Your userlevel isnt high enouth to be here!"); } ?> <html> <head> <title>Change Rank</title> <link rel="stylesheet" href="../includes/in.css" type="text/css"> <style type="text/css"> .infobg { font-family: Arial; font-weight:normal; font-size:12px; border-top: 1px solid #000000; border-right: 1px solid #000000; border-bottom: 1px solid #000000; border-left: 1px solid #000000; background: URL(textbg1.png); font-weight:300; } .button { font-size: 12px; background:url(button.png); vertical-align: middle; border-top: 1px solid #000000; border-right: 1px solid #000000; border-bottom: 1px solid #000000; border-left: 1px solid #000000; color: #FFFFCC; height:23px; font-weight:300; border-radius: 10px; padding-bottom:2px; } </style> </head> <body> <form action='' method='post' name='form1'> <table width='30%' cellpadding='0' align='center' cellspacing='0' border='1' bordercolor='#000000' bgcolor='#808080' style='border-collapse: collapse'> <tr> <td background='../header.jpg' colspan='2' align='center'>Change Rank</td> <tr> <td>Username:</td><td><input type='text' name='user'></td> </tr> <tr> <td>Rank:</td><td><input type='text' name='newrank'></td> </tr> <tr> <td> </td><td><input type="submit" name="update" value="Update Rank"></td> </tr> </form> </table> </body> </html> But there seems to be something wrong with that code, which I carnt see or work out. When I click Update submit button it does nothing, but can anyone see why it does nothing? Thanks. The attached script does everything I want it to do, but it's not very elegant. I could use some help cleaning it up. Any and all help is greatly appreciated. Thanks!!! i already have the front page that calls the script, but its not letting me login, i don't see the problem i know its returning the rows from the database but i don't understand why its not letting me login and when i do get it to login messing around with the code everybody logs in as an admin, my database has, user, pass, and role inside admin, poweruser, and reg user but when i get it to log in everybody logs in as an admin, can someone please help me ? i even tried the error thing but that doesn't seem to work either ini_set('display_errors', 1); error_reporting(E_ALL); //echo ini_set('display_errors'); session_start(); $username = $_POST['username']; $password = $_POST['password']; if (mysql_connect("localhost", "root", "")) { //echo 'connect'; } else { echo 'failure'; } if (mysql_select_db("athentication")) { //echo 'connect'; } else { echo 'no connect'; } $result = mysql_query("SELECT * FROM login WHERE user = '$username'"); $rows = mysql_num_rows($result); $role = $rows['role']; if ($rows != 0) { if ($role == 'admin') { header('Location: admin.php'); $_SESSION['username'] = $username; } elseif ($role == 'poweruser') { header('Location: poweruser.php'); $_SESSION['username'] = $username; } /*elseif ($role ==' reg') { echo "WHAT UP"; $_SESSION['username'] = $username; }*/ } else echo "enter a valid user name"; I'm very new to PhP and one of my asignments in class is to create a simple login using php and mysql. I made a simple page using html, php, and mysql and i keep getting errors. Here is my code so far: This is my index.php page: <html> <form action = 'login.php' method='POST'> Username: <input type='text' name='username'><br> Password: <input type='password' name='password'><br> <input type='submit' value='Log in'> </form> </html> This is my login.php page: <?php $username = $_POST['username']; $password = $_POST['password']; if ($username&&$password) { &connect = mysql_connect("localhost", "root", " ") or die ("Couldnt connect"); mysql_selct_db("phplogin") or die("Couldn't find db"); } else die ("Please enter a username and password"); ?> mySql file is very basic: 3 columns, id, username, password I dont think my problem is with the mySQL page that was the easiest to make but everytime I hit login in the index.php, the entire script for login.php gets outputted on screen. I would appreciate all the help. There is a sql query happening if the item is not empty, what I NEED and can not seem to figure out is to re run the rand() function. The server is PHP 4 so it is not possible to use the goto statement... That would be to easy. So any help would be great... Here is the code... the script running after the script finds a empty sql row is ot included... it works... just this one part does not. Code: [Select] <?php $connection = mysql_connect(CREDENTIALS REMOVED) or die(mysql_error()); mysql_select_db("testingblock", $connection)or die(mysql_error()); $random_num = rand(1,10); if($random_num == 1){ $query = sprintf("SELECT email FROM access_codes WHERE id='1'", mysql_real_escape_string($email)); $result = mysql_query($query); $row = mysql_fetch_assoc($result); if(!empty($row['email'])){ header('Location: http://www.thestreetbeatint.com/Testing/blah.php'); } else { echo $recipient; } } else if ($random_num == 2){ $query = sprintf("SELECT email FROM access_codes WHERE id='2'", mysql_real_escape_string($email)); $result = mysql_query($query); $row = mysql_fetch_assoc($result); if(!empty($row['email'])){ header('Location: http://www.thestreetbeatint.com/Testing/blah.php'); } else { echo $recipient; } } else if ($random_num == 3){ $query = sprintf("SELECT email FROM access_codes WHERE id='3'", mysql_real_escape_string($email)); $result = mysql_query($query); $row = mysql_fetch_assoc($result); if(!empty($row['email'])){ header('Location: http://www.thestreetbeatint.com/Testing/blah.php'); } else { echo $recipient; } } else if ($random_num == 4){ $query = sprintf("SELECT email FROM access_codes WHERE id='4'", mysql_real_escape_string($email)); $result = mysql_query($query); $row = mysql_fetch_assoc($result); echo '<br />'; if(!empty($row['email'])){ header('Location: http://www.thestreetbeatint.com/Testing/blah.php'); } else { echo $recipient; } } else if ($random_num == 5){ $query = sprintf("SELECT email FROM access_codes WHERE id='5'", mysql_real_escape_string($email)); $result = mysql_query($query); $row = mysql_fetch_assoc($result); if(!empty($row['email'])){ header('Location: http://www.thestreetbeatint.com/Testing/blah.php'); } else { echo $recipient; } } else if ($random_num == 6){ $query = sprintf("SELECT email FROM access_codes WHERE id='6'", mysql_real_escape_string($email)); $result = mysql_query($query); $row = mysql_fetch_assoc($result); if(!empty($row['email'])){ header('Location: http://www.thestreetbeatint.com/Testing/blah.php'); } else { echo $recipient; } } else if($random_num == 7){ $query = sprintf("SELECT email FROM access_codes WHERE id='7'", mysql_real_escape_string($email)); $result = mysql_query($query); $row = mysql_fetch_assoc($result); if(!empty($row['email'])){ header('Location: http://www.thestreetbeatint.com/Testing/blah.php'); } else { echo $recipient; } } else if ($random_num == 8){ $query = sprintf("SELECT email FROM access_codes WHERE id='8'", mysql_real_escape_string($email)); $result = mysql_query($query); $row = mysql_fetch_assoc($result); if(!empty($row['email'])){ header('Location: http://www.thestreetbeatint.com/Testing/blah.php'); } else { echo $recipient; } } else if ($random_num == 9){ $query = sprintf("SELECT email FROM access_codes WHERE id='9'", mysql_real_escape_string($email)); $result = mysql_query($query); $row = mysql_fetch_assoc($result); echo '<br />'; if(!empty($row['email'])){ header('Location: http://www.thestreetbeatint.com/Testing/blah.php'); } else { echo $recipient; } } else if ($random_num == 10){ $query = sprintf("SELECT email FROM access_codes WHERE id='10'", mysql_real_escape_string($email)); $result = mysql_query($query); $row = mysql_fetch_assoc($result); if(!empty($row['email'])){ header('Location: http://www.thestreetbeatint.com/Testing/blah.php'); } else { echo $recipient; } } ?> [icode] Hi everybody, my goal is to get the IP of someone accesing the site, writing the time and date along with his IP into the database. Of course, I would be adding the script to my frontpage when I make it work. But I get this error: Quote Parse error: syntax error, unexpected T_VARIABLE in D:\Program Files\xampp\xampp\htdocs\script1.php on line 8 I've checked line 8, I dont find anything in it that is out of place. Here is the code: <?php $ip = $_SERVER['REMOTE_ADDR']; $date = date("m.d.y"); $time = time(); mysql_connect ("localhost", "root", "********") or die ('Error: '. mysql_error()); mysql_select_db ("ip"); $query = "INSERT INTO ipdo (time, date, ip) VALUES ('"$time"', '"$date"', '"$ip"')"; mysql_query($query) or die ('Error updating database'); echo "Database updated with: " .$ip. "" ; ?> This is the first script I write entirely on my own, so be gentle Help? Hi there, I have a simple login script written but I get an error with it. It does work but shows an error on some pages. Let me explain. Three Files: Admin.php Login.html checklogin.php When the user has logged in they go to checklogin.php. If the username and password match 1 row in the database then it forwards the user to admin.php fine. Except I keep getting mysql warning messages: Warning: Cannot modify header information - headers already sent by (output started at /home/wormste1/public_html/tilburywebdesign/shop/templates/template1/admin/updatescompanyinformation.php:3) in /home/wormste1/public_html/tilburywebdesign/shop/templates/template1/admin/companyinfoupdated.php on line 3 At the start of each page I want password protected I put the following code: <? session_start(); if(!session_is_registered(myusername)){ header("location:login.html"); } ?> I can't work out why I am getting this error. Many Thanks, Ian |
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