PHP - Notice: Use Of Undefined Constant Variable - Assumed 'variable' In ...
I have just re-installed Xampp and suddenly my sites are now displaying lots of:
Notice: Use of undefined constant name - assumed 'name' in ... Notice: Use of undefined constant price - assumed 'price' in ... this is an example of the line its refering too: $defineProducts[1001] = array(name=>'This is a product', price=>123); Similar TutorialsNotice: Use of undefined constant DB_DSN - assumed 'DB_DSN' in /export/SOI-50/students/m2009/abhr428/web/WebIbs/DataObject.class.php on line 32 dataobject.class.php can understand this problem has it got anything to with the config.php file which contains is this the reason for the above error or is it something else in the dataobjects.php below config.php <?php define( "DB_DSN", mysql:dbname=abhr428 ); define( "DB_USERNAME","" ); define( "DB_PASSWORD", "040010722" ); define( "PAGE_SIZE", 5 ); define( "TBL_users", "users" ); define( "TBL_accesslog", "accesslog" ); ?> dataobject.class.php <?php require_once "config.php"; abstract class DataObject { protected $data = array(); public function __construct( $data ) { foreach ( $data as $key => $value ) { if ( array_key_exists( $key, $this->data )) $this->data[$key] = $value; } } public function getValue( $field ) { if ( array_key_exists( $field, $this->data )) { return $this->data[$field]; } else { die( "field not found" ); } } public function getValueEncoded( $field ) { return htmlspecialchars( $this->getValue( $field )); } protected function connect() { try { $conn = new PDO( DB_DSN, DB_USERNAME, DB_PASSWORD ); $Conn->setAttribute( PDO::ATTR_PERSISTENT, true ); $conn->setAttribute( PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION ); } catch ( PDOException $e) { die( "connection failed: " . $e->getMessage() ); } return $conn; } protected function disconnect( $conn ) { $conn = ""; } } ?> hi, I need help really badly for my PHP-Postcard Script. Basically it sends the card out but the URL does not work, I get the following error message: The URL is not valid and cannot be loaded It also states that Notice: Undefined index: www.voluntary.awardspace.co.uk in /home/www/voluntary.awardspace.co.uk/Postcard.php on line 25 Notice: Undefined index: Postcard.php in /home/www/voluntary.awardspace.co.uk/Postcard.php on line 25 See Code below: <?php session_start(); //check error log ini_set('display_errors', 1); ini_set('log_errors', 1); ini_set('error_log', dirname(__FILE__) . '/error_log.txt'); error_reporting(E_ALL); // CHANGE PARAMETERS HERE BEGIN $senderName = " Holidays From Home "; // Eg.: John's Postcards $senderEmail = "chris01@voluntary.awardspace.co.uk"; // Eg.: john@postcard.com // Change only if you have problems with urls $postcardURL = "http://".$_SERVER["www.voluntary.awardspace.co.uk"].$_SERVER["Postcard.php"]; // CHANGE PARAMETERS HERE END $result = 0; $msg = ""; $msg1 = ""; $pic = ""; function displayPhotos() { global $pic; $columns = 5; $act = 0; $act1 = 0; // Open the actual directory if($handle = opendir("thumbs")) { // Read all file from the actual directory while($file = readdir($handle)) { if(!is_dir($file)) { if(isset($pic[1])) { if($pic[1] == $act1){$sel = "checked";} else{$sel = "unchecked";} } if($act == 0){echo "<tr>";} echo "<td align='center'><img src='thumbs/$file' alt='postcard'/><br/><input type='radio' name='selimg' value='$file,$act1' $sel/></td>"; $act++; $act1++; if($act == $columns){$act = 0;echo "</tr>";} } } echo "</tr>"; } } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "DTD/xhtml1-transitional.dtd"> <html> <head> <title>Micro Postcard</title> <link href= "style/style.css" rel="stylesheet" type="text/css" /> </head> <body> <div id="main"> <div class="style1" id="caption"> <div align="left" class="style1"></div> </div> <?php //makes sure form is correctly filled in if(!empty($_POST["submit"])) { if(empty($_POST["selimg"])){$msg = "Please select an image from above!";$result = 3;} else{$pic = explode(",",$_POST["selimg"]);} if(empty($_POST["email"]) && empty($result)){$msg1 = "You must enter an email address!";$result = 3;} $secCode = empty($_POST["secCode"]) ? "" : strtolower($_POST["secCode"]); if($secCode == $_SESSION["securityCode"] && $result != 3) { $filename = date("YmdGis"); $f = fopen("messages/".$filename.".txt","w+"); fwrite($f,$pic[0]."\n"); fwrite($f,$_POST['email']."\n"); fwrite($f,stripslashes($_POST["message"])."\n"); fclose($f); // Compose the mail $from = "From: $senderName <$senderEmail>\r\n"; $replay = "Reply-To: $senderEmail\r\n"; $params = "MIME-Version: 1.0\r\n"; $params .= "Content-type: text/plain; charset=iso-8859-1\r\n"; $mailtext = "You have just received a Virtual Postcard!\r\n\r\n You can pick up your postcard at the following web address:\r\n $postcardURL?show=$filename\r\n\r\n We hope you enjoy your postcard, and if you do, please take a moment to send a few yourself!\r\n\r\n Regards,\r\n Holidays From Home\r\n $postcardURL"; // Send email @mail($_POST["email"],"You've received a postcard",$mailtext,$from.$replay.$params); echo "<center> Your postcard was sent successfully!<br /><br /> <img src='images/$pic[0]' alt='postcard' /><br /><br /><br />".stripslashes($_POST["message"]). "</center>"; $result = 1; } else{if($result != 3){$result = 2;}} } if(!empty($_GET["show"])) { $file = $_GET["show"]; $content = file("messages/$file.txt"); $pic = $content[0]; unset($content[0]); unset($content[1]); foreach($content as $value){$main .= $value;} echo "<center> Your postcard!<br /><br /> <img src='images/$pic' alt='postcard' /><br /><br /><br />$main </center>"; } if((empty($result) || $result == 2 || $result == 3) && empty($_GET["show"])) { echo "<form action='#' method='post'> <table align='center'>"; displayPhotos(); echo "</table> <div style='color:#f00;font-size:16px;'>$msg</div> <h2>Fill in the Form and then click on Send Card!!</h2> <table width='100%'> <tr><td>Send to (email address):</td><td><div style='color:#f00;font-size:16px;'>$msg1</div><input type='text' name='email' size='30' value='".$_POST["email"]."' /></td></tr> <tr><td>Message:</td><td><textarea name='message' rows='10' cols='40'>".stripslashes($_POST["message"])."</textarea></td></tr> <tr><td colspan='2'>".($result == 2 ? "<p style='color:#f00;font-size:16px;'>Sorry the security code is invalid! Please try it again!</span></p>" : " ")."</tr> <tr> <td>Security code: <input class='text' name='secCode' type='text' size='10' /> </td><td><img src='securityCode.php' alt='security code' border='1' /></td> </tr> <tr><td colspan='2'> </tr> <tr><td colspan='2' align='left'><input type='submit' value='Send card!' name='submit'/></td></tr> </table> </form>"; } ?> Absolutely any help would be much appreciated. I want ot know is there a way round this problem? Here is the http://voluntary.awardspace.co.uk/Postcard.php I am absolutely desperate to solve this burning issue I just moved my code from Appserv to EasyPHP and it gave me this error, it was working fine on Appserv...what's with easyPHP ?? Hello! Help me please!
My site nice work on php version 5.2.12, but now php version is changed to 5.2.17 and some code is not working.
It showing error:
"Notice: Undefined variable: newCode in ....../humancheck.php on line 29"
In file humancheck.php on line 29:
for($i=0; $i<$config_max_digits;$i++) $newCode = $newCode.rand(0,9);This variable, it seems, taken from another file - humancheck_showcode.php: session_start(); $newCode = $HTTP_SESSION_VARS["newCode"];And, in index.php file at the beginning of the file written: require ('human_check/humancheck.php');And, in index.php file below is written: <IMG src="humancheck_showcode.php">When I call the index.php file it shows error. So, I think, that variable "newCode" should be taken from file humancheck_showcode.php, but it don't do that. Hello all - am looking for help with dynamic links in PHP not returning data and coughing out "Notice: Undefined variable: row in /home/jj3wg2td/public_html/Uni More Info.php on line 200" The initial search is being fed from a mysql into table of results in another page ('ViewMore' being a column in my database and 'UniversityCourses' being the trigger to search that column): echo "<td class='result'><a href='Uni More Info.php?ID={$row['UniversityCourses']}'>{$row['ViewMore']}</a></td>"; This is working fine as I can see the various links changing when you hover over them in the table. clicking the links goes to "Uni More Info.php" where my PHP code is: <?php session_start(); ini_set('display_errors', 1); ini_set('display_startup_errors', 1); error_reporting(E_ALL); //Connect to the database $mysqli = new mysqli("localhost", "jj3wg2td_wix", "MYPASSWORD", "MYDATABASE"); if(isset($_GET['post'])){ $ID=mysqli_real_escape_string($mysqli, $_GET['ID']); $sql="SELECT * FROM uni2020 WHERE UniversityCourses='$ID'"; $result=mysqli_query($mysqli,$sql) or die ("Bad Query: $sql"); $row=mysqli_fetch_array($result); if(isset($_GET['post'])){ $Website=mysqli_real_escape_string($mysqli,$_GET['Website']); $UcasPointsRequired=mysqli_real_escape_string($mysqli,$_GET['UcasPointsRequired']); $OverallScore=mysqli_real_escape_string($mysqli,$_GET['OverallScore']); $sql= "INSERT INTO UniversityCourses (Website, UcasPointsRequired) VALUES ('$Website', $UcasPointsRequired');"; $result=mysqli_query($mysqli,$sql) or die ("Bad Query: $sql"); } } ?> <content> <?php echo $row['Website']?> <?php echo $row['UcasPointsRequired']?> <?php echo $row['OverallScore']?> </content> The error codes are showing:
Notice: Undefined variable: row in /home/jj3wg2td/public_html/Uni More Info.php on line 200 Which is the section in-between the <content></content> tags. Reading up into "Undefined Variable", it suggest that I havent "Declared the variables", but isn't that this section?: if(isset($_GET['post'])){ $Website=mysqli_real_escape_string($mysqli,$_GET['Website']); $UcasPointsRequired=mysqli_real_escape_string($mysqli,$_GET['UcasPointsRequired']); $OverallScore=mysqli_real_escape_string($mysqli,$_GET['OverallScore']); I am new to PHP and am learning as I go along....but yet again...I'm stumped! Any help is very much appreciated (again)!!!!
Steven I don't know why I am getting an undefined variable when the url is define. look at the deleteid=6 it means it is defined and in the code it is written as below URL Quote http://www.ppp.com/storeprueba/storeadmin/inventory_list.php?deleteid=6 Code: [Select] <?php if(isset($_GET['deleteid'])){ //which is clearly active in the url then get it, /* line 27 ===> */ echo'Do you really want to delete pdoruct with ID of '. $GET ['deleteid'] . '? <a href="inventory_list.php?yesdelete=' . $GET ['deleteid'] . '">Yes</a> |<a href="inventory_list.php"> No</a>'; exit(); } if (isset($_GET['yesdelete'])) { // remove item from system and delete its picture // delete from database $id_to_delete = $_GET['yesdelete']; $sql = mysql_query("DELETE FROM products WHERE id='$id_to_delete' LIMIT 1") or die (mysql_error()); // unlink the image from server // Remove The Pic ------------------------------------------- $pictodelete = ("../inventory_images/$id_to_delete.jpg"); if (file_exists($pictodelete)) { unlink($pictodelete); } header("location:inventory_list.php"); exit(); } ?> the echo Code: [Select] <?php echo 'Do you really want to delete pdoruct with ID of '. $GET ['deleteid'] . '? <a href="inventory_list.php?yesdelete=' . $GET ['deleteid'] . '">Yes</a> |<a href="inventory_list.php"> No</a>'; ?> won't display the . $GET ['deleteid'] . after "Do you really want to delete product with ID of which is 6 but it won't display the number six with the actual configuration, instead it display it like Quote Notice: Undefined variable: GET in /home3/nyhungry/public_html/storeprueba/storeadmin/inventory_list.php on line 27 Notice: Undefined variable: GET in /home3/nyhungry/public_html/storeprueba/storeadmin/inventory_list.php on line 27 Do you really want to delete pdoruct with ID of ? Yes | No Notice not number in between 'ID of' and '?' I'm getting the following notice: Notice: Undefined variable: TotaalBerichten in C:\Users\Sander\Documents\**********************\index.php on line 60 Is it because it is in the IF? The code: //Aantal berichten totaal if (!$ResultTotaalBerichten = @mysql_query("SELECT COUNT(1) FROM " . $db_prefix . "berichten")) {$foutmelding .= $Taal['errorConfiguratieFromDB'];} else {$TotaalBerichten = mysql_result($ResultTotaalBerichten, 0); $TotaalPaginas = ceil($TotaalBerichten / $aantalBerichtenPerPagina);} @mysql_free_result($ResultTotaalBerichten); //Var eersteBericht is het eerste bericht if (isset($_GET['eersteBericht'])) {if (!is_numeric($_GET['eersteBericht'])) {$eersteBericht = '0';} else{$eersteBericht = $_GET['eersteBericht'];}} else{$eersteBericht = '0';} // Als er iets mis is met var eersteBericht, dan hem op 0 zetten if (($eersteBericht >= $TotaalBerichten) || ($eersteBericht < 0)) ///////////DIT IS LIJN 60 {$eersteBericht = 0;} EDIT: translated to english If i modify it to: $TotaalBerichten=0; /////////////ADDED //Aantal berichten totaal if (!$ResultTotaalBerichten = @mysql_query("SELECT COUNT(1) FROM " . $db_prefix . "berichten")) {$foutmelding .= $Taal['errorConfiguratieFromDB'];} else {$TotaalBerichten = mysql_result($ResultTotaalBerichten, 0); $TotaalPaginas = ceil($TotaalBerichten / $aantalBerichtenPerPagina);} @mysql_free_result($ResultTotaalBerichten); echo $TotaalBerichten; //////////////////////////////////////////////////////////////////////////ADDED //Var eersteBericht is het eerste bericht if (isset($_GET['eersteBericht'])) {if (!is_numeric($_GET['eersteBericht'])) {$eersteBericht = '0';} else{$eersteBericht = $_GET['eersteBericht'];}} else{$eersteBericht = '0';} // Als er iets mis is met var eersteBericht, dan hem op 0 zetten if (($eersteBericht >= $TotaalBerichten) || ($eersteBericht < 0)) ///////////DIT IS LIJN 60 {$eersteBericht = 0;} The $TotaalBerichten is '0' while there IS a message in the database??? I am pretty sure I defined these, by making it something like $blah="blah" and `blah` = ' {$blah}' So why am I getting these errors = Notice: Use of undefined constant petid - assumed 'petid' in /home/vhosts/foggyjungle.6te.net/viewpet_forum.php on line 38 Notice: Use of undefined constant adopter - assumed 'adopter' in /home/vhosts/foggyjungle.6te.net/viewpet_forum.php on line 41 Notice: Undefined variable: fulldate in /home/vhosts/foggyjungle.6te.net/viewpet_forum.php on line 44 Fatal error: Call to undefined function showpet_forum() in /home/vhosts/foggyjungle.6te.net/viewpet_forum.php on line 45 $time = mysql_query("SELECT * FROM `pets_adopted`"); $date = mysql_fetch_array($time); $fulldate = "$date[fulldate]"; $halfdate = "$date[halfdate]"; function check(){ $pid = mysql_real_escape_string($_GET['id']); $result = mysql_query("SELECT * FROM `pets_adopted` WHERE `id` = '{$pid}'"); while($row = mysql_fetch_array($result, MYSQL_ASSOC)) { $results = mysql_query("SELECT * FROM `pets_list` WHERE `id` = '{$row[petid]}'"); $pet = mysql_fetch_array($results); $results2 = mysql_query("SELECT * FROM `users` WHERE `id` = '{$row[adopter]}'"); $usercc = mysql_fetch_array($results2); There's the snippet. Thank you for any help. I am just really lost. Ik ben bezig met een gastenboek en snap de volgende foutmelding niet: Notice: Undefined variable: iCountFiles *************** regel 261 //Smilies toegestaan? if ($GetConfiguratie['smiley'] == 1) {$AfbeeldingenPerRegel = 12 ; if (!$rHandle = opendir('./images/smilies')) {$sP_Smilies = 'Geef de map "smilies" leesrechten!';} else {$sP_Smilies = ''; while (false !== ($sFile = readdir($rHandle))) {if (preg_match("/^([sa-zA-Z0-9]+){3}(:?\.gif|\.jpg)$/", $sFile)) { $sFileShort = preg_replace("/^([sa-zA-Z0-9]+)(:?\.gif|\.jpg)$/", "(\\1)",$sFile); $iCountFiles++ ; /////////////////////////////////////////////////////////////REGEL261 if ($iCountFiles % $AfbeeldingenPerRegel == 0) {$sP_Smilies .= '<img onClick="insertSmilie(\''.$sFileShort.'\')" src="images/smilies/'.$sFile.'" alt="code: '.$sFileShort.'" /><br />';} else {$sP_Smilies .= '<img onClick="insertSmilie(\''.$sFileShort.'\')" src="images/smilies/'.$sFile.'" alt="code: '.$sFileShort.'" /> ';} } } closedir($rHandle); } } hoe los ik dit het best op? code is Code: [Select] <?php $limit=12; if(isset( $_GET['page'])) $page=$_GET['page']; if($page<=0) $page = 1; else {$start=0;} $sql=mysql_query("select * from tbl_gallery where status=1 And category_name='0'"); $count=mysql_num_rows($sql); $totalcount=ceil($count/$limit);$start=($page-1)*$limit; $s=mysql_query("select * from tbl_gallery where status=1 And category_name='0' limit $start, $limit"); while($result=mysql_fetch_array($s)){ $start++; ?> please find the mistake Hello i am new to this forum and coding. I am trying to fix a auto torrent downloading script which is php and curl. I have been stucked with Undefined offset error. Your help will be very appretiated, thanks. Starting download: Mp3-data1 Notice: Undefined variable: temp in /var/www/html/torrents/bgrahul2.php on line 338 Array ( => HTTP/1.1 200 OK Server: Transmission Content-Type: application/json; charset=UTF-8 Date: Wed, 21 Sep 2011 19:58:44 GMT Content-Length: 49 {"arguments":{"torrents":[]},"result":"success"} [1] => ) Marked those lines to bold Quote $result = callTransmission(array("filename" => "/var/www/html/donofwarez/xxx/torrents/$torrentfile", "download-dir" => "/home/Downloads/$title/"), "torrent-add", $arr[1]); callTransmission(array("seedRatioLimit" => 50, "seedRatioMode" => 1), "torrent-set", $arr[1]); /* echo "<pre>"; print_r($result); echo "</pre>"; */ if (preg_match('/"percentDone":[0-9.]+/i', $result[0], $matches)) $temp = str_replace('"id":', "", $matches[0]); // $temp="hlDr1wqu2ONtM3McVGHoVzfrkp2UgUcGwDt66IuxAe0LBkru"; $id[0] = $temp; //***OMG! We need the ids as integers! *** foreach ($id as $key => $value) { $id[$key] = (int) $value; } Code: [Select] <form method="post" action=""> <input type="input" name="user_name" /> <input type="submit" name="user_name_submit" /> </form> <?php if(!empty($_POST['user_name'])) $user_name = $_POST['user_name']; if(isset($_POST['user_name_submit'])) { $user_name_submit = $_POST['user_name_submit']; } $user_name_preg_match = preg_match('/[a-zA-Z0-9]/', $user_name); if($user_name_preg_match) { echo 'true'; } else { echo 'false'; } ?> In this script I am getting the notice: Code: [Select] Notice: Undefined variable: user_name Any suggestions how to avoid the notice in this case? hello all, i have ran into another issue i get this message when i go onto my homepage Notice: Undefined variable: layout in i have the following includes on the main index page: Code: [Select] <?php // Include Main Core File. include '_class/core.php'; // Include Config File include 'config/config.php'; include 'config/db.php'; // Use Database $obj->connect(); // Include library include '_class/library.php'; // Include layout include 'layout/index.php'; ?> on the config file i have the varible it is refering too: Code: [Select] <?php $layout = $url . "layout/"; ?> the actual file i get the error on (library.php) Code: [Select] <?php class library extends core { function advert() { /* * Name your images 1.jpg, 2.jpg etc. * * Add this line to your page where you want the images to * appear: <?php include "randomimage.php"; ?> */ // Change this to the total number of images in the folder $total = "2"; // Change to the type of files to use eg. .jpg or .gif $file_type = ".png"; // Change to the location of the folder containing the images $image_folder = $layout . "layout/images/adverts"; // You do not need to edit below this line $start = "1"; $random = mt_rand($start, $total); $image_name = $random . $file_type; echo "<img src=\"$image_folder/$image_name\" alt=\"$image_name\" />"; } } $obj = new library; ?> is there a way to make it so it $layout works on any page or file as long as its in the includes? thanks again. Hi I am buidling a Blog System using OO techniques (or at least attempting to).. I keep getting an error : Notice: Undefined variable: blog_categoryName in C:\wamp\www\atkinsonsCMS\admin170976\blog_categories.php on line 13 ...And then underneath all that is is displaying 'Call Stack'. I've never come across this notification before so I guess it is an OO term, and the a list of unexpected outputs: #, time, memory, function and location....each with an associated value. I attempted to resolve the variable issue in the usual way (as you can see in my code), but still the errors/warnings persist. The purpose of this part of the code is to simply retrieve SQL data (which is a list of blog categories), allowing the user to select one and then click through to be directed to the appropriate category page (although this last requirement of the code has not yet been programmed). Could those who have experience of this please take a look at my code and let me know where I am going wrong? Thanks blog_categories.php This file calls on the the blogFunctions.php Category Class, and the displays the results. session_start(); $pageTitle = "Blog Categories"; include("../includes/admin_header.php"); include("../classes/blogFunctions.php"); echo '<div class="admin_main_body"><br /><br />'; echo "<h2>Category List</h2><br />"; $content = new Category; $content -> process(); //print_r(debug_backtrace()); echo "<a href=blog.php>$blog_categoryName</a>"; echo '</div>'; echo '</div>'; include("../includes/admin_footer.php"); blogFunctions.php This class deals with the retreaval of the SQL data, and then passes it to blog_categories.php class Category { public $errors; public $blog_categoryName = NULL; public function __construct() { $this->errors = array(); $blog_categoryName = $this->blog_categoryName; } public function getCategories(){ if(!isset($blog_categoryName)) { $blog_categoryName = 'value'; } ($GLOBALS["___mysqli_ston"] = mysqli_connect("localhost", "atkinson", "XYZ111WA")) or die(((is_object($GLOBALS["___mysqli_ston"])) ? mysqli_error($GLOBALS["___mysqli_ston"]) : (($___mysqli_res = mysqli_connect_error()) ? $___mysqli_res : false))); ((bool)mysqli_query($GLOBALS["___mysqli_ston"], "USE atkinsonscms")) or die (((is_object($GLOBALS["___mysqli_ston"])) ? mysqli_error($GLOBALS["___mysqli_ston"]) : (($___mysqli_res = mysqli_connect_error()) ? $___mysqli_res : false))); mysqli_query($GLOBALS["___mysqli_ston"], "SELECT * FROM blog_category ORDER BY ASC"); $result = @mysqli_query($GLOBALS["___mysqli_ston"], $query); if ($result) { while ($row = $result->fetch_object()) { $blog_categoryName = $row->blog_categoryName; } //need to use mysqli query to retrieve results. if(mysqli_affected_rows($GLOBALS["___mysqli_ston"])< 1) $this->errors[] = 'Could not retrieve data'; } } public function show_errors(){ echo "<h3>Errors</h3>"; foreach($this->errors as $key=>$value) echo $value."<br>"; } public function process() { $this->getCategories(); return count($this->errors)? 0 : 1; } } //Closes Category Class. I have a php page that is trying to pass a variable like this: echo "<tr><td bgcolor='white'>" . $company_id . "</td><td bgcolor='white'><a href='companyusers.php?name=" . $company_name . "'>" . $company_name . "</a></td><td bgcolor='white'>" . $company_email . "</td><td bgcolor='white'>" . $company_status . "</td></tr>"; Then when some one clicks on that link they variable with it's value should go with the url and I'm trying to assign a variable like this: $company_name = $_POST['name']; It is not working!!! I get that "Notice: Undefined index: name in 'directory of page' on line 100" Can someone help please? Code: [Select] Notice: Undefined variable: page in C:\Program Files (x86)\EasyPHP5.2.10\www\admin.php on line 119 That line is: <?php session_start(); $_SESSION['prev_page'] = $_SERVER['REQUEST_URI']; if (!session_is_registered('username')) { header("location:login.php"); } ?> <hr> <style type="text/css"> table.gridtable { color:#333333; border-width: 1px; border-color: #666666; border-collapse: collapse; width: 100%; } table.gridtable th { border-width: 1px; padding: 1px; border-style: solid; border-color: #666666; background-color: #dedede; } table.gridtable td { border-width: 1px; padding: 1px; border-style: solid; border-color: #666666; } .valid { border-width: 1px; padding: 1px; border-style: solid; border-color: #666666; background-color: transparent; } </style> </div> <div class="newsJustify"> <script type="text/javascript"> function checkall(delchk) { for (i = 0; i < delchk.length; i++) delchk[i].checked = true; } </script> <script type="text/javascript"> function uncheckall(delchk) { for (i = 0; i < delchk.length; i++) delchk.checked = false; } </script> <script language="JavaScript"> function loadPage(list) { location.href=list.options[list.selectedIndex].value } </script> <?php mysql_connect("localhost", "root", "") or die(mysql_error()); mysql_select_db("chat") or die(mysql_error()); if (isset($_POST['del'])) { for ($count = 0; $count < count($_POST["delchk"]); $count++) { $delete = $_POST["delchk"][$count]; $query = "DELETE FROM members_shouts WHERE id = '$delete'"; $result = mysql_query($query); if (!$result) { die("Error deleting accounts! Query: $query<br />Error: " . mysql_error()); } } } $data = mysql_query("SELECT * FROM `members_shouts`") or die(mysql_error()); $rows = mysql_num_rows($data); if (isset($_GET['limit'])) { $page_rows = $_GET["limit"]; if ($page_rows == '') { $page_rows = 5; // no double quotes (int) } elseif ($page_rows == 'all') { $page_rows = $rows; } else { $page_rows = $_GET['limit']; /* validate this */ } if (!isset($_GET['pagenum'])) { $page = 1; } else { $page = (int) $_GET['pagenum']; } } else { $page_rows = 10; } ?> <?php $max_pages = ceil($rows / $page_rows); $last = ceil($rows / $page_rows); $pagenum = ($page && $page > 0 && $page <= $last) ? $page : 1; $max = 'limit ' . ($pagenum - 1) * $page_rows . ',' . $page_rows; $data_p = mysql_query("SELECT * FROM members_shouts $max") or die(mysql_error()); ?> <?php $result = mysql_query("SELECT * FROM members_shouts"); if (mysql_num_rows($result) > 0) { ?> <span style="float: left;margin-left: 2px;"> <form> <select name="file" size="1" onchange="loadPage(this.form.elements[0])" target="_parent._top"> <option value="" <?php if ($page_rows == 0) { echo 'selected'; } ?>>Select Limit</option> <option value="?limit=9" <?php if ($page_rows == 9) { echo 'selected'; } ?>>9</option> <option value="?limit=15" <?php if ($page_rows == 15) { echo 'selected'; } ?>>15</option> <option value="?limit=30" <?php if ($page_rows == 30) { echo 'selected'; } ?>>30</option> <option value="?limit=all" <?php if ($page_rows == 'all') { echo 'selected'; } ?>>All</option> </select> </form> </span> <span style="float: right;margin-top: 2px;margin-right: 2px;"> <center> <?php if ($pagenum == 1) { } else { echo " <a href='{$_SERVER['PHP_SELF']}?pagenum=1&limit={$page_rows}'>First</a> "; echo " | "; echo " "; $previous = $pagenum - 1; $current = $pagenum; echo " <a href='{$_SERVER['PHP_SELF']}?pagenum=$previous&limit={$page_rows}'>$previous</a> "; echo " | "; } echo "$pagenum"; if ($pagenum == $last || $last == 0) { } else { $next = $pagenum + 1; echo " | "; echo " <a href='{$_SERVER['PHP_SELF']}?pagenum=$next&limit={$page_rows}'>$next</a> "; echo " "; echo " | "; echo " <a href='{$_SERVER['PHP_SELF']}?pagenum=$last&limit={$page_rows}'>Last</a> "; } ?> </center> </span> <style type="text/css"> .clear2 { clear:both; height:0px; overflow:hidden; } </style> <div class="clear2"></div> <hr> <?php echo "<table class=\"gridtable\"> <thead> <tr> <th align=\"center\" scope=\"col\">user</th> <th align=\"center\" scope=\"col\">message</th> <th align=\"center\" scope=\"col\">when</th> <th align=\"center\" scope=\"col\">Delete?</th> </tr> </thead> <tbody>"; echo "<form name = 'myform' action='' method='post'>"; ?> <?php while ($info = mysql_fetch_array($data_p)) { echo "<tr align=\"center\">"; echo "<td class=\"valid\" >" . $info['user'] . "</td>"; echo "<td class=\"valid\" >" . $info['message'] . "</td>"; echo "<td>" . $info['when'] . "</td>"; echo '<td><input type="checkbox" id="delchk" name="delchk[]" value="' . $info['id'] . '" /></td>'; echo "</tr>"; } echo "</tbody>"; echo "</table>"; echo "<hr>"; echo "<input type='submit' name = 'del' value='Delete Selected'></form>"; echo "<input type='button' onclick='checkall(document.myform[\"delchk\"]);' value='Select All'>"; echo "<input type='button' onclick='uncheckall(document.myform[\"delchk\"]);' value='Deselect All'>"; echo "<hr>"; ?> <?php } else { // No rows were found ... echo '<center>No logged accounts.</center><hr>'; } ?> </hr> The line its refferring too is: $pagenum = ($page && $page > 0 && $page <= $last) ? $page : 1;[/QUOTE] in this block: $max_pages = ceil($rows / $page_rows); $last = ceil($rows / $page_rows); $pagenum = ($page && $page > 0 && $page <= $last) ? $page : 1; $max = 'limit ' . ($pagenum - 1) * $page_rows . ',' . $page_rows; $data_p = mysql_query("SELECT * FROM members_shouts $max") or die(mysql_error()); [/i] I am new to php and html, I am trying to make a search function where you can search by a persons firstname or lastname but I am getting an error. the error is Notice: Undefined variable: searchq in C:\wamp\www\search2.php on line 17. Can anyone help me please cant understand this error as i seemed to have it defined in my config file...... helpppp Notice: Use of undefined constant TBL_MEMBERS - assumed 'TBL_MEMBERS' in /export/SOI-50/students/m2009/abhr428/web/WebIbs/Member.class.php on line 32 Query failed: SQLSTATE[42S02]: Base table or view not found: 1146 Table 'abhr428.TBL_MEMBERS' doesn't exist Code: [Select] <?php define('DB_DSN','mysql:host=vega.soi.city.ac.uk;dbname=abhr428' ); define( "DB_USERNAME", "abhr428" ); define( "DB_PASSWORD", "" ); define( "PAGE_SIZE", 5 ); define( "TBL_MEMBERS", "members" ); define( "TBL_ACCESS_LOG", "accessLog" ); ?> members.class.php <?php require_once "DataObject.class.php"; class Member extends DataObject { protected $data = array( "id" => "", "username" => "", "password" => "", "firstName" => "", "lastName" => "", "joinDate" => "", "gender" => "", "favoriteGenre" => "", "emailAddress" => "", "otherInterests" => "" ); private $_genres = array( "crime" => "Crime", "horror" => "Horror", "thriller" => "Thriller", "romance" => "Romance", "sciFi" => "Sci-Fi", "adventure" => "Adventure", "nonFiction" => "Non-Fiction" ); public static function getMembers( $startRow, $numRows, $order ) { $conn = parent::connect(); $sql = "SELECT SQL_CALC_FOUND_ROWS * FROM " . TBL_MEMBERS . " ORDER BY $order LIMIT :startRow, :numRows"; try { $st = $conn->prepare( $sql ); $st->bindValue( ":startRow", $startRow, PDO::PARAM_INT ); $st->bindValue( ":numRows", $numRows, PDO::PARAM_INT ); $st->execute(); $members = array(); foreach ( $st->fetchAll() as $row ) { $members[] = new Member( $row ); } $st = $conn->query( "SELECT found_rows() AS totalRows" ); $row = $st->fetch(); parent::disconnect( $conn ); return array( $members, $row["totalRows"] ); } catch ( PDOException $e ) { parent::disconnect( $conn ); die( "Query failed: " . $e->getMessage() ); } } public static function getMember( $id ) { $conn = parent::connect(); $sql = "SELECT * FROM " . TBL_MEMBERS . " WHERE id = :id"; try { $st = $conn->prepare( $sql ); $st->bindValue( ":id", $id, PDO::PARAM_INT ); $st->execute(); $row = $st->fetch(); parent::disconnect( $conn ); if ( $row ) return new Member( $row ); } catch ( PDOException $e ) { parent::disconnect( $conn ); die( "Query failed: " . $e->getMessage() ); } } public function getGenderString() { return ( $this->data["gender"] == "f" ) ? "Female" : "Male"; } public function getFavoriteGenreString() { return ( $this->_genres[$this->data["favoriteGenre"]] ); } } ?> Hello!
First of all, i would like to thank everyone in this community as this is where i post most of the problems that i can no longer fix on my own. and everytime i do, i get all the help i need and with a 100% success rate.
Anyway, i am following a tutorial, however the tutorial is based on a MAC environment and i am working on windows. I think this is a problem with the DIRECTORY_SEPARATOR but i might be wrong.
I am getting this error message "Notice: Use of undefined constant LIB_PATH - assumed 'LIB_PATH' in C:\wamp\www\beyond_basics_photogallery\includes\database.php on line 2"
i will just post the code that is relevant to this error. here is the code for database.php: (config.php is in the same folder with database.php)
require_once(LIB_PATH.DS."config.php");and this is my initialize.php where i initialized my DIRECTORY_SEPARATOR. this is also located in the same folder with database.php <?php // Define the core paths // Define them as absolute paths to make sure that require_once works as expected defined('DS') ? null : define('DS', DIRECTORY_SEPARATOR); defined('SITE_ROOT') ? null : define('SITE_ROOT', DS.'wamp'.DS.'www'.DS.'beyond_basics_photogallery'); defined('LIB_PATH') ? null : define('LIB_PATH', SITE_ROOT.DS.'includes'); // load config file first require_once(LIB_PATH.DS.'config.php'); // load basic functions next so that everything after can use them require_once(LIB_PATH.DS.'functions.php'); // load core objects require_once(LIB_PATH.DS.'session.php'); require_once(LIB_PATH.DS.'database.php'); // load database-related classes require_once(LIB_PATH.DS.'user.php'); ?>and this is the path to my project folder: C:\wamp\www\beyond_basics_photogallery I have tried everything i could but i am completely lost as to what is causing this. could it be the SITE_ROOT statement? i appreciate any help. thanks! I have 2 issues happening, first one I need to get resolved is, line 60 is giving me a 'Notice: Undefined variable: delete'. This codes had multi issues but was able to resolve all but this one and my table not filling in with the data from my database. If you need any other info please let me know, Again I am new at this.
<tr> <td colspan="5" align="center" bgcolor="#FFFFFF"><input name="delete" type="submit" id="delete value="delete"></td> </tr> <?php // Check if delete button active, start this *line 60* -----> if ($delete){ for($i=0;$i<$count;$i++){ $del_id = $checkbox[$i]; $sql = "DELETE FROM $tbl_name WHERE id='$del_id'"; $result = mysqli_query($sql); } // if successful redirect to delete_multiple.php if($result){ echo "<meta http-equiv=\"refresh\" content=\"0;URL=delete_multiple.php\">"; } } mysqli_close($con); ?> |