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PHP - Add Up Table Values From Specific Date
Hi there,
i'm trying to sum up values from mysql based on their date, specifically only values from entries with the same date should be added together, my db looks like this: id, codes, value, date now i'm building a statistics page, the value field is always 50, for showing the total for all the entries i'm just doing Code: [Select] $totalincome = $codes * 50; and print that on the statistic, i want to have statistics for each day, the date is saved in this format: YYYY-MM-DD how could i do that ? Thanks ! Similar Tutorials
Table Issue - Multiple Location Values For User Pushes Values Out Of Row Instead Of Wrapping In Cell
Hi guys, i was having an issue with dates and although it leans a bit more into MYSQL I was hoping i could get some help ive searched all over the net for this so I dont know if im not thinking on how to ask this correctly or can't find it, but ill be as detailed as possible and hope that helps.
Ok I have a table that shows when payment was received on past invoices dating back to say 1995; The company processes 'ALL' invoices every month on the 9th, so if anything comes in from the first to the ninth it will be processed that month on the ninth. If it comes in from the tenth to the thirtieth or thirty-first it will be processed the following month.
The table already has a "Received" date filed and now I want to create a column on the table called "Processed Date" (adding the column is no problem don't need help with that part) that shows me the date we processed the invoice.
I know i have to use the "Received" field (because it shows what day the invoice was put into the system) but im not sure how to format the "Processed Date" field, so say the "Received" field shows an invoice came in on '1995-05-11', I want the "Processed Date" field to display it was payed on '1995-06-09' (notice that is the following month).
I thought i would put in a visual of what I was trying to do below:
So if I pull the two columns in MYSQL from that table I would see something like this:
Received Processed Date
1996-02-03 1996-02-09
1996-03-03 1996-03-09
1996-04-11 1996-05-09
1996-05-20 1996-06-09
1996-07-13 1996-08-09
If i could get some guidance/help on this i would really appreciate it.
thanks in advance!!
JL
This topic has been moved to PHP Regex. http://www.phpfreaks.com/forums/index.php?topic=315388.0 SELECT * FROM `booking_tbl` WHERE booking_status = 'Check In' AND departure_date_time = NOW()"I use the datetime datatype for the departure_date_time so i can get data from that data because it checking the date and time but i want it to check on the date from the datetime datatype So how can i get the data only with that date without the time in the mysql datetime datatype i have a register and login page where the users can perform register and login task and their detail gets saved in the database. my requirement is that when the user enters his/her account, they should be redirected to their profile page, where they can view all their profile details. Till now i have been able to make the user login and dislay a part of their profile page, for this purpose the code that i am using is
<code>
<?php Hi, My company has 240+ locations and as such some users (general managers) cover multiple sites. When I run a query to pull user information, when the user has multiple sites to his or her name, its adds the second / third sites to the next columns, rather than wrapping it inside the same table cell. It also works the opposite way, if a piece of data is missing in the database and is blank, its pull the following columns in. Both cases mess up the table and formatting. I'm extremely new to any kind of programming and maybe this isn't the forum for this question but figured I'd give it a chance since I'm stuck. The HTML/PHP code is below: <table id="datatables-column-search-select-inputs" class="table table-striped" style="width:100%"> <thead> <tr> <th>ID</th> <th>FirstName</th> <th>LastName</th> <th>Username</th> <th>Phone #</th> <th>Location</th> <th>Title</th> <th>Role</th> <th>Actions</th> </tr> </thead> <tbody> <?php //QUERY TO SELECT ALL USERS FROM DATABASE $query = "SELECT * FROM users"; $select_users = mysqli_query($connection,$query);
// SET VARIABLE TO ARRAY FROM QUERY while($row = mysqli_fetch_assoc($select_users)) { $user_id = $row['user_id']; $user_firstname = $row['user_firstname']; $user_lastname = $row['user_lastname']; $username = $row['username']; $user_phone = $row['user_phone']; $user_image = $row['user_image']; $user_title_id = $row['user_title_id']; $user_role_id = $row['user_role_id'];
// POPULATES DATA INTO THE TABLE echo "<tr>"; echo "<td>{$user_id}</td>"; echo "<td>{$user_firstname}</td>"; echo "<td>{$user_lastname}</td>"; echo "<td>{$username}</td>"; echo "<td>{$user_phone}</td>";
//PULL SITE STATUS BASED ON SITE STATUS ID $query = "SELECT * FROM sites WHERE site_manager_id = {$user_id} "; $select_site = mysqli_query($connection, $query); while($row = mysqli_fetch_assoc($select_site)) { $site_name = $row['site_name']; echo "<td>{$site_name}</td>"; } echo "<td>{$user_title_id}</td>"; echo "<td>{$user_role_id}</td>"; echo "<td class='table-action'> <a href='#'><i class='align-middle' data-feather='edit-2'></i></a> <a href='#'><i class='align-middle' data-feather='trash'></i></a> </td>"; //echo "<td><a href='users.php?source=edit_user&p_id={$user_id}'>Edit</a></td>"; echo "</tr>"; } ?>
<tr> <td>ID</td> <td>FirstName</td> <td>LastName</td> <td>Username</td> <td>Phone #</td> <td>Location</td> <td>Title</td> <td>Role</td> <td class="table-action"> <a href="#"><i class="align-middle" data-feather="edit-2"></i></a> <a href="#"><i class="align-middle" data-feather="trash"></i></a> </td> </tr> </tbody> <tfoot> <tr> <th>ID</th> <th>FirstName</th> <th>LastName</th> <th>Username</th> <th>Phone #</th> <th>Location</th> <th>Title</th> <th>Role</th> </tr> </tfoot> </table>
Hello again, guys! I have a couple of questions that I hope anyone can answer. I am making a form that is storing the information in a database, and in this form I also want images to be uploaded. I want to make a function that allows the user to upload as many images as they would like to have in their ad on my website, and I also need something that can handle the upload process, and see how many images the user is trying to upload. Any easy solutions for this? I also have another question: As you can see on the example image underneath this text, I have a form with multiple inputs where the user is suppose to choose how many inputs they want to fill in themself. How should I store this information in the database, and how can I make a script that detects how many of the forms the user actually filled? I hope you guys understood what I was trying to say, and I thank you all anyways. Underneath you can see an image of my forms. Example image: Cheers, Marius Hi All,
I want to copy into a table values from another table that partially match a given value, case-insensitively. So far I do as follows but I wonder whether there is a quicker way.
$input_table=array('1'=>'toto','2'=>'tota','3'=>'hello','4'=>'TOTO','5'=>'toto');
$input_table_2 = array_map('strtolower', $input_table);
$value_to_look_for='Tot';
$value_to_look_for_2=strtolower($value_to_look_for);
$output_table=array();
foreach ($input_table_2 as $k=>$v)
{
if(false !== strpos($v, $value_to_look_for_2))
{
$output_table[]=$input_table[$k];
}
}
One drawback is that $input_table_2 is 'foreached' whereas there might be no occurrences, which would lead to a loss of time/resources for big arrays.
Thanks.
Hello, I need some help. Say that I have a list in my MySQL database that contains elements "A", "S", "C", "D" etc... Now, I want to generate an html table where these elements should be distributed in a random and unique way while leaving some entries of the table empty, see the picture below. But, I have no clue how to do this... Any hints? Thanks in advance, Vero Hi All ,
I have a small table with 4 fields namely Day_ID, Dues, Last_Visit, Points. where Day_ID is an auto-increment field. The table would be as follows:
Day_ID -- Dues --- Last_Visit --- Points.
1 --------- 900 -------- 1/12 -------- 6
2 --------- 700 -------- 4/12 -------- 7
3 --------- 600 -------- 7/12 -------- 5
4 --------- 600 -------- 9/12 -------- 6
5 --------- 600 -------- 10/12 ------- 6
6 --------- 600 -------- 14/12 ------- 6
So this is the record of a person's visit to say a club. The last row indicates the last date of his visit to the club. His points on this date are 6. Based on this point value of 6 in the last row I want to retrieve all the previous BUT adjoining all records that have the same Points i.e. 6.
So my query should retrieve for me, based on the column value of Points of the last row (i.e. Day_ID - 6 ), as follows:
4 --------- 600 -------- 9/12 -------- 6
5 --------- 600 -------- 10/12 ------- 6
6 --------- 600 -------- 14/12 ------- 6
This problem stated above had been completely resolved, thanks to a lot of help from Guru Barand by this following query :-
$query = "SELECT cv.day_id, cv.dues, cv.last_visit, cv.points FROM clubvisit cv WHERE last_visit >= ( SELECT MAX(last_visit) FROM clubvisit WHERE points <> ( SELECT points as lastpoints FROM clubvisit JOIN ( SELECT MAX(last_visit) as last_visit FROM clubvisit ) as latest USING (last_visit) ) )";I am using this and it works perfectly except that now there is a slight change in the table because the criteria for points is now dependent on more than one column cv.points and is more like cv.points1, cv.points2, cv.points3 etc. So now I need to make a selection based on each of these cv.points columns. As of now I can still get the results by running the query multiple times for each of the cv.points columns ( seperately for cv.points1, cv.points2, cv.points3) and it works correctly. However I am wondering if there is a better way to do this in just one go. This not only makes the code repetitive but also since the queries are interconnected, involves the use of transactions which I wish to avoid if possible. The values that I require for each of the cv.point columns is 1. day_id of the previous / old day on which the cv.points value changed from the current day value, and 2. cv.points on that old/ previous day. So for example if the table is as below: Day_ID -- Dues --- Last_Visit --- Points1 --- Points2. 1 --------- 900 -------- 1/12 ----------- 9 ------------ 5 2 --------- 600 -------- 4/12 ----------- 6 ------------ 6 3 --------- 400 -------- 7/12 ----------- 4 ------------ 7 4 --------- 500 -------- 9/12 ----------- 5 ------------ 8 5 --------- 600 -------- 10/12 ---------- 6 ------------ 8 6 --------- 600 -------- 11/12 ---------- 6 ------------ 8 7 --------- 600 -------- 13/12 ---------- 6 ------------ 7 8 --------- 500 -------- 15/12 ---------- 5 ------------ 7 9 --------- 500 -------- 19/12 ---------- 5 ------------ 7 Then I need the following set of values : 1. day_id1 -- Day 7, points1 ---- 6, days_diff1 -- (9-7 = 2) . // Difference between the latest day and day_id1 2. day_id2 -- Day 6, points2 ---- 8, days_diff2 -- (9-6 = 3) 3. day_id3 -- .... and so on for other points. Thanks all ! Hello, I have a datepicker that when a date is selected, the post to a php file will get the sum values for that selected day, month, and year. I have the "by day" working with this... <?php $choice = (isset($_POST['choice'])) ? date("Y-m-d",strtotime($_POST['choice'])) : date("Y-m-d"); $con = mysql_connect("localhost","root","xxxxxxxxxx"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("inverters", $con); $sql = "SELECT sum(power/1000) AS choice FROM feed WHERE date = '".$choice."' group by date"; $res = mysql_query($sql) or die('sql='.$sql."\n".mysql_error()); $row = mysql_fetch_assoc($res); echo $row['choice'].'<br />'; ?> But by month and year are not clicking... Help Please Alan Hi, I have a table set up with 10 items in it, I want to allow users to customize the order of the items when they are logged in. How can I call the items from the table in the order set by the user? Thanks for any help. I am trying to get specific data from a MySQL table but cannot seem to find a proper command. Code: [Select] $link = mysqli_connect('#####', '########', '########'); $user = $_SESSION['username']; $email = mysqli_query($link,"select email from members where username='$user'"); echo $email; Specifically, I am trying to get the email address stored for the user specified by the session, and display that address. However, I do not get any output with the current code, and am not sure what to try next. I have tried mysqli_fetch_row() but it only returns an error. Hi guys, How do I call the 2nd row of 'TSuperQuestion'? Code: [Select] <?PHP $con = mysql_connect("localhost","ph6theo", "xxxx"); if (!$con) { die('Could not connect: ' . mysql_error("oop")); } mysql_select_db("ph6theo_testDB") or die(mysql_error()); $result = mysql_query("SELECT * FROM QANDATable "); $row = mysql_fetch_array($result); echo $row['TSuperQuestion']; ?> Hello,
I've been going about reading different posts on here and other forums but so far I haven't been able to come across something that works for my purpose so after all the reading I thought I'd finally just ask. I'm rather new at php/sql queries so please bare with me.
First what I'm trying to accomplish.
I need a form with several fields (options) to fetch information from a table that will then display the results based on the options selected.
- from date
- to date
- employee name
- department
- branch
- product line
In other words, the purpose is to be able to choose a date range (from one day to up to a year or more) and then to be able to choose either ONE employee name to view statistics invididually from a given department and branch or to select a department to view all the statistics for everyone under that given department and/or brach and/or product line.
Now the tricky part is that besides fetching the records, calculations need to be made before the records are displayed and that part right here is what is giving me a huge headache.
This is the query that I have.
SELECT report_daily_id, report_date, emp_id, emp_fullname, emp_dept, emp_branch prod_line calls, tk_time, hld_time, ac_time, tran_calls, work_time, tran_rate, ah_time FROM daily_report GROUP BY emp_id, emp_fullname, emp_branch, emp_dept, prod_lineThe calculations based on the date range and one or more of the other options need to give me the following results. SUM(calls) AS 'Total Calls' SUM(tk_time) / SUM(calls) AS 'Talk Time' SUM(hld_time) / SUM(calls) AS 'Held Time' SUM(ac_time) / SUM(calls) AS 'AC Time' SUM(tran_calls) AS 'Total Trans' SUM(tran_calls) / SUM(calls) AS 'Tran Rate' SUM(ah_time) / SUM(calls) AS 'AH Time'I don't know how else to explain myself past this point but if you have any questions, perhaps I can answer it and give more details. Thank you, Hi i have this drop down list for date which contain 3 selects DAY MONTH YEAR hwo can i make so that when update form select keeps the same value has before help please <?php $months = array('','January','February','March','April','May','June','July','August','September','October','November','December'); echo '<select name="month_of_birth">'; for ($i=1;$i<13;++$i) { echo '<option value="' . sprintf("%02d",$i) . '">' . $months[$i] . '</option>'; } echo '</select>'; echo '<select name="day_of_birth">'; for ($i=1;$i<32;++$i) { echo '<option value="' . sprintf("%02d",$i) . '">' . $i . '</option>'; } echo '</select>'; echo '<select name="year_of_birth">'; $year = date("Y"); for ($i = $year;$i > $year-50;$i--) { $s = ($i == $year)?' selected':''; echo '<option value="' . $i . '" ' . $s . '>' . $i . '</option>'; } echo '</select>'; ?> Hello, i am coding a backend portal, this portal will have staff members lets call them 'M1' and each staff member will have a client 'C1' What is the best way to put this into a database? do i have a table for Staff? then a seperate table for Members? or one table consisting of staff, with the members details written into the staff's row? I am not sure if the title is correct; I tried my best.
I'm a PHP/MySQL beginner and I really need some help.
I have a small script that I am using for sending SMS. I recently added a phonebook. The problem with the phonebook right now is that it's available to all users, i.e. they can all update and delete all rows. What I would like to do is make it so that each user can update and delete only their own contacts.
I have a table call contacts. Inside that table there is first name, last name, company and phonenumber.
How can I accomplish this with PHP & MySQL?
CREATE TABLE IF NOT EXISTS `contacts` ( `contact_id` int(10) NOT NULL AUTO_INCREMENT, `firstname` varchar(255) NOT NULL, `lastname` varchar(255) NOT NULL, `company` varchar(255) NOT NULL, `cell_no` text NOT NULL, PRIMARY KEY (`contact_id`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=8 ; CREATE TABLE IF NOT EXISTS `users` ( `user_id` int(11) NOT NULL AUTO_INCREMENT, `users_name` varchar(30) NOT NULL, `uname` varchar(30) NOT NULL, `u_pass` varchar(60) NOT NULL, `utype` varchar(30) NOT NULL, `timezone` varchar(30) NOT NULL, `uapi_user` varchar(30) NOT NULL, `uapi_pass` varchar(60) NOT NULL, PRIMARY KEY (`user_id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=20 ;
<?php
if (isset($_POST['submit'])){
//form has been submitted1
$firstname = trim($_POST['firstname']);
$lastname = trim($_POST['lastname']);
$company = trim($_POST['company']);
$cellno = trim($_POST['cell_no']);
if($firstname == ''){
echo '<div class="alert alert-danger">First Name is not Valid!</div>';
exit;
}elseif($lastname == ''){
echo '<div class="alert alert-danger">Last Name is not Valid!</div>';
exit;
}elseif($company == ''){
echo '<div class="alert alert-danger">Company is not Valid!</div>';
exit;
}elseif($cellno == ''){
echo '<div class="alert alert-danger">Cellphone Number is not Valid!</div>';
exit;
}else{
$query = "Select cell_no from contacts where cell_no = '".$cellno."' ";
$result = mysql_query($query);
if (!mysql_num_rows($result)) {
$sql = "INSERT INTO contacts(firstname, lastname, company, cell_no)
values('{$firstname}','{$lastname}', '{$company}', '{$cellno}')";
$result = mysql_query($sql);
confirm_query($result);
//echo '<div class="alert alert-success">Successfully added.</div>';
//exit;
?>
<script type="text/javascript">
window.location = "contact_list.php";
</script>
<?php
}
else{
echo '<div class="alert alert-danger">Username. already exist!.</div>';
echo '<p><a href="new_contact.php" class="btn btn-success"> Back </a></p>';
exit;
}}
}else{
$firstname = "";
$lastname = "";
$company = "";
$cellno = "";
}
?>
I have the following array structu Code: [Select] [0] => Array ( [id] => Array ( [$t] => http://www.google.com/mate/ ) [updated] => Array ( [$t] => 2011-08-31T11:43:05.942Z ) [category] => Array ( [0] => Array ( [scheme] => http://schemas.google.com/g/ [term] => http://schemas.google.com/contact/ ) ) [title] => Array ( [type] => text [$t] => Name ) [link] => Array ( [0] => Array ( [rel] => http://schemas.google.com/contacts/2008/rel#edit-photo [type] => image/* [href] => https://www.google.com/mate/feeds/photos/media/ ) [1] => Array ( [rel] => self [type] => application/atom+xml [href] => https://www.google.com/mate/feeds/contacts ) [2] => Array ( [rel] => edit [type] => application/atom+xml [href] => https://www.google.com/mate/feeds/ ) ) [gd$email] => Array ( [0] => Array ( [rel] => http://schemas.google.com/g/2005#other [address] => email_address@gmail.com [primary] => true ) ) ) I am tried to display name and email address. I am using following method, can anyone tell me is there any better way? Thank u 4u help. NAME $name=( $emp_det[0]['title'][t]); $email =( $emp_det[0]['gdemail'][0][address]); I have a table with a list of towns and cities with their postcode and latitude and longitude. Since a lot of small towns in an area have the same postcode. I have a search which I want to return all towns that have the same postcode. the table is set up as: postcode:::::::town::::::::lat:::::::::long |
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