PHP - Get Value From Textbox [external Website]

Part of my page is taken from external webpages by preg_match. Since It is a partial section, it contains incomplete tags such as <div>, <span>, etc. Thus, they mix up with my entire page and my </div>, </span> are used for the incomplete tags in the borrowed section. How I can end such tags? or separate this section from the main codes (I mean having an isolated section)?
 

I tried searching on google but couldn't find any relevant information, please redirect me to relevant source or help me with the code.

I want to pass a domain name in text field which will be scanned and then the script will display entire site map.

Not external links or links on a page. Sorry it is not easy for me to explain.

Eg. if i pass abc.com

Script will display

abc.com/12/adn.php
abc.com/asd/asd/
etc

Whatever their url format is.

All the links on that domain.

hello
My database is in a same server with seperate domain name , then I want to insert from website1 mysql data on website2 mysql data.
can anyone help me?

I would appreciate if someone could figure this out or tell me the easiest way to do this. I need a count up counter that appears in a textbox so I can record the time a user is on a page. On a side note, I do have their Start and finish time timestamp recorded in myphpadmin database but I am looking for the easiest (or best) way to do this. Any advice or scripts would be very much appreciated.   Thanks in advanced.   I did find this counter that works but the numbers appear 0.0.1 if counting up. I don't want to confuse the user. I really want to display to the user how long they was on a certain page.

<script>
  $(document).ready(function() {
    var time = '00:00:00',
        parts = time.split(':'),
        hours = +parts[0],
        minutes = +parts[1],
        seconds = +parts[02],
        input = $('#timeInput');
 
    var timer = setInterval(function(){
        seconds++;
        if(seconds == 60) {
            seconds = 00;
            minutes++;
 
            if(minutes == 60) {
                minutes = 00;
                hours++;
            }
        }
        var newTime = hours + ":" + minutes + ":" + seconds;
        $('#timeInput').val(newTime);
    }, 1000);
 
});
</script>
 
<input type="text" name="time" id="timeInput"/>

I have a problem where I am unable to display a DB entry that for exampe says "John Doe".

The code I am using is:

Code: [Select]
<tr>
<td>Agent Full Name:</td>
<td><input type="text" name="fullname" value='.$agentdata['fullname'].'></td>
</tr>
The output shows "John" instead of "John Doe", have I missed something here 

Hi all

i have been trying for 6 hours to write some code that will show a text box and the user puts in there id then it provides a link with the id in the middle of it

so say the id is 111555

the link is http://example.com.au/data/users/111555/2011/1/1 i want the user to insert their id and do if the id 343034 the link is
http://example.com.au/data/users/343034/2011/1/1

can any one give me the code to this i have gotten no where
from tutorials
               
please matt                                       

Like Youtube; when submitting a video; You can insert words into a Textbox named Tags.

Each space you leave is considered the start of a new word.

How can I do this using PHP + MYSQL.

Thanks!

<INPUT TYPE = "Text" VALUE ="0"
ID = "username2" NAME = "username2">

<?php
$value1 =  $_POST['username2'];
$nine=$value1;

$codx =$characters[$nine]->name;
?>

Im tring to get '0' in username2 inputbox

readit in php $nine

$codx =$characters[$nine]->name;

as you can see in my <?php code above
I cant get the 0 from this inputbox

It only works like this

<?php
$nine='0'
$codx =$characters[$nine]->name;
?>

What i need is to get the users
input. from a textbox on my page
called username2
they would enter between 0 and 8
as you can see its set to 0 on my
textbox, the 0 - 8 is the
character location
$characters[$nine]

the $nine will hold the number
between 0 - 8
My php code i cant read my texbox
input.

How do I read the user input
into my

my textbox post pulls the input

$nine =  $_POST['username2'];
$codx =$characters[$nine]->name;

i noticed it wouldn't work

it only works this way

$nine='0';
$codx =$characters[$nine]->name;

Let me know how to read in user input
from my username2 textbox.
Thanks in advance

sorry to repeat i needed to explain
so you can see my error.

Edited December 30, 2019 by Psycho
none

I am currently writing a script, well, attempting to write a script where the user is able to add an unlimited amount of text boxes via javascript:

Code: [Select]
var i = 1;

function AddTxtBox() {

new_textbox.innerHTML = new_textbox.innerHTML +"<br />Misc Item " + i + ": <input type='text' name='prod_misc[]' placeholder='Misc Product Info' />"
i++;
}

The js code works fine adding the text boxes. My first question is: in the "name" field; the name I have is "prod_misc[]" is that correct for adding the input into an array?

Second question:

I want to input that data from the "prod_misc[]" array into SQL, namely PostgreSQL. Should I use a "for()" loop to extract each key of data from the array "prod_misc[]"? If so, what syntax do I use to input an array of data like that into SQL?


Thanks so much in advance for this help... I am in great need and it's very appreciative.

Hi,
I am working on a script that will add 3 sets of information to a MySQL table. I had a script that had the fields of username password and password2. It worked just fine when password2 was used for verification to make sure you typed it right.
But now I want to take password and turn it into a new data field that is submitted into the new row with the other information.
The problem is it wont add the row. The script says it worked just fine but i check the db and no new row.
here it is:
<?php // Connects to your Database 
 mysql_connect("//", "//", "//") or die(mysql_error()); 
 mysql_select_db("//") or die(mysql_error()); 
 //This code runs if the form has been submitted
 if (isset($_POST['submit'])) { 
 
 //This makes sure they did not leave any fields blank
 if (!$_POST['username'] | !$_POST['pass'] | !$_POST['pass2'] ) {
  die('You did not complete all of the required fields');
  }
 
 // checks if the username is in use
  if (!get_magic_quotes_gpc()) {
  $_POST['username'] = addslashes($_POST['username']);
  }
 $usercheck = $_POST['username'];
 $check = mysql_query("SELECT username FROM users WHERE username = '$usercheck'") 
 or die(mysql_error());
 $check2 = mysql_num_rows($check);
 
 //if the name exists it gives an error
 if ($check2 != 0) {
  die('Sorry, the username '.$_POST['username'].' is already in use.');
  }
 // this makes sure both passwords entered match
  if ($_POST['pass'] != $_POST['pass']) {
  die('Your passwords did not match. ');
  }
 
  // here we encrypt the password and add slashes if needed
  $_POST['pass'] = md5($_POST['pass']);
  if (!get_magic_quotes_gpc()) {
  $_POST['pass'] = addslashes($_POST['pass']);
  $_POST['username'] = addslashes($_POST['username']);
  $_POST['pass2'] = addslashes($_POST['pass2']);
  }
 
 // now we insert it into the database
  $insert = "INSERT INTO users (username, password, Human-Readable)
  VALUES ('".$_POST['username']."', '".$_POST['pass']."', '".$_POST['pass2']."')";
  $add_member = mysql_query($insert);
  ?>
 
 <h1>Registered</h1>
 <p>Thank you, you have registered - you may now login</a>.</p>
 <?php } 
 else {  ?>
 <form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post">
 <table border="0">
 <tr><td>Username:</td><td>
 <input type="text" name="username" maxlength="60">
 </td></tr>
 <tr><td>Password:</td><td>
 <input type="password" name="pass" maxlength="10">
 </td></tr>
 <tr><td>HR:</td><td>
 <input type="password" name="pass2" maxlength="10">
 </td></tr>
 <tr><th colspan=2><input type="submit" name="submit" 
value="Register"></th></tr> </table>
 </form>
 <?php
 } ?> 
And incase you want to see it here is the original:
<?php // Connects to your Database 
 mysql_connect("//", "//", "//") or die(mysql_error()); 
 mysql_select_db("//") or die(mysql_error()); 
 //This code runs if the form has been submitted
 if (isset($_POST['submit'])) { 
 
 //This makes sure they did not leave any fields blank
 if (!$_POST['username'] | !$_POST['pass'] | !$_POST['pass2'] ) {
  die('You did not complete all of the required fields');
  }
 
 // checks if the username is in use
  if (!get_magic_quotes_gpc()) {
  $_POST['username'] = addslashes($_POST['username']);
  }
 $usercheck = $_POST['username'];
 $check = mysql_query("SELECT username FROM users WHERE username = '$usercheck'") 
 or die(mysql_error());
 $check2 = mysql_num_rows($check);
 
 //if the name exists it gives an error
 if ($check2 != 0) {
  die('Sorry, the username '.$_POST['username'].' is already in use.');
  }
 // this makes sure both passwords entered match
  if ($_POST['pass'] != $_POST['pass2']) {
  die('Your passwords did not match. ');
  }
 
  // here we encrypt the password and add slashes if needed
  $_POST['pass'] = md5($_POST['pass']);
  if (!get_magic_quotes_gpc()) {
  $_POST['pass'] = addslashes($_POST['pass']);
  $_POST['username'] = addslashes($_POST['username']);
  }
 
 // now we insert it into the database
  $insert = "INSERT INTO users (username, password)
  VALUES ('".$_POST['username']."', '".$_POST['pass']."')";
  $add_member = mysql_query($insert);
  ?>
 
 <h1>Registered</h1>
 <p>Thank you, you have registered - you may now login</a>.</p>
 <?php } 
 else {  ?>
 <form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post">
 <table border="0">
 <tr><td>Username:</td><td>
 <input type="text" name="username" maxlength="60">
 </td></tr>
 <tr><td>Password:</td><td>
 <input type="password" name="pass" maxlength="10">
 </td></tr>
 <tr><td>Confirm Password:</td><td>
 <input type="password" name="pass2" maxlength="10">
 </td></tr>
 <tr><th colspan=2><input type="submit" name="submit" 
value="Register"></th></tr> </table>
 </form>
 <?php
 } ?> 

Many Thanks in advanced

hello,

i have implemented a jquery function like this: http://jsbin.com/ujuse

i need to grab the contents of the textarea to store it in a session, but without sending a form, is this possible??

thanks for looking

hey, im trying to show data in a text box thats being retrived from a database, but if there is a ' in it, it will only show the text up to that point. (ie. if it has "You're" it will only show "You")
here is the code im using


echo "<input type='text' value='$picComment'>";

sorry for posting..i already make it

Hi,   i'm trying to display db(name,email,telephone no) values in textbox.please help me.   ::HTML part::     <form class="form-signin" role="form" id="form1" action="post_user.php">

I have a text box for users to enter new text in.  The box also contains text that is determined by a variable that is created from a mysql query and some other added text.  I want to make a portion of the added text within the textbox bold.  How would I achieve this with php?

Code: [Select]

<?php

result = mysql_query("SELECT `something` FROM `table` WHERE `this` = '$that'");
row = mysql_fetch_row($result);
$variable = $row[0];

$text = "<strong>Here is the text that I want bold</strong>

$variable";

echo "<textarea name=\"textbox\">";
echo "$text";
echo "</textarea>

?>

Doing this gives me this result in the textbox:

"<strong>Here is the text that I want bold</strong>

This is what the variable text says."

Any ideas?