|
PHP - Im Looking For A Function That Will Kind Of "find & Replace All" On A Page
Im dealing with html links in a database where I need to execute a small piece of php code. Well mysql doesnt execute php code thats held in a table. The easiest way for me to do this is just add the links without the code, & set up a function that will replace anything I set to for example in my case a link lookin like this:
http://mysite.com/index.php?page=offers&blah=blah&sid= needs to look like this; http://mysite.com/index.php?page=offers&blah=blah&sid=<?php echo $_SESSION['login']; ?> so I would need a function like <?php $replace('sid=','sid=<?php echo $_SESSION['login'];?> ?> something like that. And I know its possible & I could create a function like this but honestly right now I am so tired after working 12 hours im lazy dont want to think to hard while I know there are a lot of people out there that have a function like this already. If you dont have one & dont feel like writing one for me could you atleast point me in the right direction so I dont have to think to hard?! Thanks!! Similar TutorialsHi, bit stuck on how to find and replace "<" and ">" with "<" and ">". I basically have a database record that outputs to screen and I need the code in the <code> tags to be rendered to the screen. I therefore need it to go through the whole array variable from the db and change the symbols just inside the code tags. Please be aware that the code tags might happen more than once here's an example below Code: [Select] <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1> </code> <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1> </code> the desired output would be: <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1 </code> <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1 </code> help on this would be great Cheers Rob Hi guys I'm struggling a bit, I need to replace a word that occurs multiple times in text with an array("up","down","forward","backwards") of words. $find = "left"; $replace = array("up","down","forward","backwards"); $text = "left left left left"; echo str_replace($find,$replace,$text); The Output is: array array array array Did try this with a foreach statement as well, but no luck. Is there a better way of doing this? Thanks Hello! I am executing an external command from a PHP script, using the exec function. Since this program can take more than 1-2 minutes to run, I thought I should use a "Loading page...please wait". What I need is to be able to get the process id from the external program that is being run and, when this finishes, I'll start outputting the results. Is there a way to do this? Can someone please help me with an array problem i can not figure out. I need the array to be numbered from 1 to how ever many fields that are needed in the form and have a mysql field name and the title of the field also in the array. 1, "mysql_field_name", "Title of form field" 2, "", "" and so on then the form will be shown based on the array. I have the following draft code which I am working with. any suggestions on how i may do this array ? Code: [Select] <?php $options = array( '1'=> array('fieldtext'=>'option1', 'mysqlfield'=>'option1'), '2'=> array('fieldtext'=>'option2', 'mysqlfield'=>'option2'), '3'=> array('fieldtext'=>'option3', 'mysqlfield'=>'option3'), '4'=> array('fieldtext'=>'option4', 'mysqlfield'=>'option4'), ); // $options = array(1 => "option1", "option2", "option3", "option4"); // the line above works but i want to include the name of the mysql field as well. $userid = 1; ?> <div style="align: center; margin: 12px; font-family:Tahoma;"> <br><br><?php if ($_POST['Update'] != "Update") { // check if form submitted yet, if not get data from mysql. $res = db_query("SELECT * FROM `users` WHERE `userid` = '" . $userid . "'"); foreach($options as $key => $value) { $_POST[$key] = mysql_result($res, 0, $value); } $ok_to_update = "no"; } elseif ($_POST['Update'] == "Update") { // check if form submitted yet, if so get POST data. // error checking // foreach($options as $key => $value) { // $_POST[$i] = ""; // } $ok_to_update = "yes"; } if ($_POST['Update'] == "Update" && $ok_to_update == "yes") { // $res = db_query("INSERT INTO `users` () VALUES ()"); // add user details to database. ?><p><br><br><br>Thank you for updating</p><?php } else { ?><form name="form1" method="post" action=""> <?php foreach($options as $key => $value) { ?><p><?php echo($value); ?>: <input type="text" name="<?php echo($key); ?>" value="<?php echo($_POST[$key]);?>"></p> <?php } ?> <input name="Update" type="submit" value="Update"> </form> <?php } ?> </div> I'm a very new PHP user (as in, I just started today) and need to make a set of navigation buttons which will take the user to "next" or "previous" pages. I assume that the $_GET function is involved, but I don't know how to do it. It needs to work like this: If the URL looks like "http://website.com/page1.php" I need the "next" button (a href image) to change it to "/page2.php", and while on page 2, for the "previous" button to take the user to "/page1.php" and so forth. How can I cause the page number to increment or decrease respective to the href image being clicked? So I wanted to create stickers on my forum where people type in say ":Blobby-Tired" and then instead of the comment showing ":Blobby-Tired" it shows an html image tag displaying a picture of Blobby in the comment box So I created the following page CommentUpload.php However my sql fails to insert it despite the fact when I "echo $new" it shows the image on the page correctly And it can't be my sql insert code as if I change $new variable for "$BodyText" int he SQL query it it inserts ":Blobby-Tired" OK?
<?php
include 'dbconnect.php';
session_start();
if(isset($_POST["submit"]) && !empty($_POST["CommentText"])){
$id = intval($_SESSION['id']);
echo $_SESSION['id'] . '<p> </p>' ;
$BodyText = $conn -> real_escape_string($_POST['CommentText']) ;
$User = $_SESSION['username'];
//Replace flairs with <img> tags
/*not working currently) */
$new = str_replace(":Blobby-Tired","<img src='flairs/Blobby-Tired.jpg'> </img>","'$BodyText'");
echo "$new";
/************************/
$sql = "INSERT INTO Posts (User, CommentText, IdOfThread)
VALUES ('$User','$new','$id')";
if (mysqli_query($conn, $sql)) {
echo "New record has been added successfully !";
} else {
echo "Error: " . $sql . ":-" . mysqli_error($conn);
}
mysqli_close($conn);
}
?>
Edited April 28 by Fishcakes I have a website that has definitions and articles. I need a code that craws the php content pulled from my database, finds a specified word and replaced that word with a link. For example If "car" appears replace with <a href="http://www.website.com/car.php">car</a> Thanks Todd Hey, friends. I have some trouble on the server front. My sites have been hacked, and I need to make sure I've eradicated every trace of this exploit. I'm looking for a way to search for any and all php files contained in multiple directories with specific names. For instance, I have found a commonality in relation to where these malicious files are placed, such as: Code: [Select] /some/dir/img/somename.phpor: Code: [Select] /some/dir/js/somename.php Is there a way I can easily (e.g. using ssh and the "find" command) locate all files ending in php but only found in directories named "img"? I can't seem to find anything that would allow me to do this with find, or with a combination of find and grep. I can't go directory by directory, as some of these img directories are created many levels deep, some even in .svn directories. Any and all help is appreciated. Hackers suck. Hi guys I am a newbie with PHP and I have been trying to solve this problem for 3 days.. Ive set up a booking form on my website to be sent directly to my email once the client clicked on the send button.. The problem I am having while checking these pages on wamp is that the booking form is ok but when I click on the send button the following message error appears "Warning: mail() [function.mail]: Failed to connect to mailserver at "localhost" port 25, verify your "SMTP" and "smtp_port" setting in php.ini or use ini_set() in C:\wamp\www\fluffy_paws\booking_form2.php on line 27" When I check online I have this message "500 - Internal server error. There is a problem with the resource you are looking for, and it cannot be displayed." Are my codes wrong??? My webhosting is Blacknight.com , Im on Windows Vista, my internet is a dongle with O2 ireland Thanks for your help! I was looking over some code that someone else had written when I noticed a line with "$this->entity" in it. "Entity" is recognized as PHP syntax in my text editor but I cannot find any reference to it in any documentation that I've looked through. Where can I find more information about the "entity" class? Thanks in advanced! Hi everyone!! I just started learning PHP two weeks ago and I hope someone can help me!! I need to do a find and replace on a string, and each replace needs to have an unique id, and if that unique id exists in a table then return the value on the table. Make sense? So like "find all the Xs in the string, replace with "X1, X2, X3...", then if "X3' exists on TableB, return value "X3 is on the table and has a value of Y3". I actually got this to work already but it takes a long time to do it so I'm hoping someone could give me some advice on how to make it more EFFICIENT: // PART ONE, find all "X" and replace with unique_id for ($count = 1; $count <= strlen($string); $count++) // do this loop as many times as there are characters in $string { $unique_id = "replacement_" . $count; // give each replacement an unique id (replacement_1, replacement_2, replacement_3, etc..) $string = preg_replace("X", $unique_id, $string , 1); // find X and replace it with the $unique_id in $string, and only do this ONCE } $count_replacements = substr_count($string,"replacement_"); // count how many replacements occured in total // PART TWO, find all unique_ids in tableB and echo the unique_id_value for ($count = 1; $count <= $count_replacements; $count++) // do this loop as many times as there were replacements { $unique_id = "replacement_" . $count; // set the unique_id of each replacement $show_tableB = mysqli_query($link, 'SELECT * FROM tableB'); // select the unique_ids and the unique_id_values in TableB while ($row = mysqli_fetch_array($show_tableB)) { $tableBs[] = array('unique_id' => $row['unique_id'], 'unique_id_value' => $row['unique_id_value']); } foreach($tableBs as $tableB): // for each entry in TableB, if the unique_id in TableB matches the unique_id of the replacement, return the unique_id_value if ($tableB['unique_id'] == $unique_id) { echo $unique_id . " is on TableB and it has a value of ". $tableB['unique_id_value'] } endforeach; } The problem with this is: its not very efficient. If $string has 500 charachters, it does the "PART ONE" 500 times. Then, say it found 300 Xs, it does "PART TWO" 300 more times. And every time it does "PART TWO", it checks all entries in TableB (which could be 200 or more). So, that's it. Anyone has a better idea of how to do this?? Thanks!!!! cant work out this mysql syntax error "operation":"medupdate","medid":"","name":"ibo","medyear":"5","medmonth":"21","medday":"1","recuser":1,"SuccFail":"fail","SuccFailMessage":"error occured You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '''WHERE med_id=' at line 2","ResultData":""} Code: [Select] $sql="update metodology set med_description='".$req['name']."', med_year='".$req['medyear']."', med_month='".$req['medmonth']."', med_day='".$req['medday']."', med_recorddate= now(), med_recorduserid= 1'"; $sql.= " WHERE med_id=".$req['medid']; In the text, Code: [Select] It will eventually go away.Once the carriers merge, the combined airline, will operate as Southwest. It has its logo and colors. 2.3 AirTran brand will no longer be used. In the above text, how to replace "." with ". " and not in 2.3. how to add space after "." only if it has alphabets and not to replace after numeric characters. I am getting the following error when using composer: "continue" targeting switch is equivalent to "break". Did you mean to use "continue 2"? Just started. I am pretty sure composer.json wasn't changed. journalctl doesn't show anything. Maybe Doctrine related, however, nothing seems to help.
Any ideas? [michael@devserver www]$ php -v PHP 7.3.4 (cli) (built: Apr 2 2019 13:48:50) ( NTS ) Copyright (c) 1997-2018 The PHP Group Zend Engine v3.3.4, Copyright (c) 1998-2018 Zend Technologies with DBG v9.1.9, (C) 2000,2018, by Dmitri Dmitrienko [michael@devserver www]$ composer -V Composer version 1.4.2 2017-05-17 08:17:52 [michael@devserver www]$ yum info composer Loaded plugins: fastestmirror Loading mirror speeds from cached hostfile * base: mirror.us.oneandone.net * epel: mirror.rnet.missouri.edu * extras: mirror.us.oneandone.net * remi-php73: mirror.bebout.net * remi-safe: mirror.bebout.net * updates: mirror.us.oneandone.net Installed Packages Name : composer Arch : noarch Version : 1.8.4 Release : 1.el7 Size : 1.8 M Repo : installed From repo : epel Summary : Dependency Manager for PHP URL : https://getcomposer.org/ License : MIT Description : Composer helps you declare, manage and install dependencies of PHP projects, : ensuring you have the right stack everywhere. : : Documentation: https://getcomposer.org/doc/ [michael@devserver www]$ composer update Loading composer repositories with package information Updating dependencies (including require-dev) [ErrorException] "continue" targeting switch is equivalent to "break". Did you mean to use "continue 2"? update [--prefer-source] [--prefer-dist] [--dry-run] [--dev] [--no-dev] [--lock] [--no-custom-installers] [--no-autoloader] [--no-scripts] [--no-progress] [--no-suggest] [--with-dependencies] [-v|vv|vvv|--verbose] [-o|--optimize-autoloader] [-a|--classmap-authoritative] [--apcu-autoloader] [--ignore-platform-reqs] [--prefer-stable] [--prefer-lowest] [-i|--interactive] [--root-reqs] [--] [<packages>]... [michael@devserver www]$
This topic has been moved to Linux. http://www.phpfreaks.com/forums/index.php?topic=318175.0 Hi, I currently have an if, elseif, else program that starts off with Code: [Select] if( $v_name == "" || $v_msg == "" ) echo "something" how do I turn this into a switch? but the very next elseif I have Code: [Select] elseif( strcspn( $_REQUEST['msg'], '0123456789' ) == strlen( $_REQUEST['msg'] ) ) echo "something" is it possible to turn this into a switch with 2 different strings like that to evaluate? This topic has been moved to PHP Installation & Configuration. http://www.phpfreaks.com/forums/index.php?topic=347922.0 I have a registration form on my website and after Registration I want the user to activate first his account. I don't have problem on sending this email to the user. What I want to appear is like this.. GoodDay "username", Blah Blah! how can you actually do that? I know that you can do that through session variables but the thing is email's can't accept scripts on sending emails. how can I get the value from a session variable for example and convert it to plain html text so that i can OUTPUT it to the email.. HELP PLEASE! okay.. so I found a list of bad words on line that I want to work into my website's insert. I took the time to create a long comma-delimited list and I'm trying to use this in my page but I keep getting errors. I'm not sure what I'm supposed to be escaping because of the many numerous characters in this list. Might someone help? As I didn't want to post a bunch of foul words on this forum, I posted it he http://snipt.org/xmpgk You might not want to visit if you don't like bad words. As the list currently is, I'm getting this error: Parse error: syntax error, unexpected T_CONSTANT_ENCAPSED_STRING, expecting ')' in /home/jeffro/public_html/all/xyzman/inserttodb.php on line 114 ....right on the line where $newwords begins. $query = "SELECT * FROM School_Registrations WHERE School_Name= '$_POST[SchoolName]' "; $result2 = mysql_query($query); if (mysql_numrows($result2) > 0) { while($row = mysql_fetch_array($result2)) { echo" <h2>ERROR</h2> ...rest of the error code... ";} } else { mysql_query("INSERT INTO ``.`` (...all the variables...);") or die(mysql_error( 'Location: http://www...php' )); echo " ...success code... $url = 'http://www.mypage.com/page.php?'; $url .= 'email='.urlencode($_POST['email']); $result = getPage('', $url, '', 15); function getPage($proxy, $url, $header, $timeout) { $ch = curl_init(); curl_setopt($ch, CURLOPT_URL, $url); curl_setopt($ch, CURLOPT_HEADER, $header); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch, CURLOPT_PROXY, $proxy); curl_setopt($ch, CURLOPT_HTTPPROXYTUNNEL, 1); curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, $timeout); curl_setopt($ch, CURLOPT_REFERER, 'http://mypage.org'); curl_setopt($ch, CURLOPT_USERAGENT, 'Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.9.0.8) Gecko/2009032609 Firefox/3.0.8'); $result['EXE'] = curl_exec($ch); $result['INF'] = curl_getinfo($ch); $result['ERR'] = curl_error($ch); curl_close($ch); return $result; } } ?> Ok, so this code verifies what the name entered in the forms is not already in database. If it is it gives you the ...error code... and nothing else. If it does not it gives you ...success code... and it creates new table record, and it sends out email address entered to designated page. Bu I keep getting: Fatal error: Call to undefined function getPage() It still fully works, but no email goes out as defined. I am stuck. Help? |
|||||||