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PHP - Taking Results From Search And Echo() ?
Hi,
I have a searchbar which looks for a value in my tables, it works great but i want to know how i can make the results of the search clickable; go to a page relevent to that search, let me explain in more depth. User searches for a postcode, script finds and displays the postcode on the next page, user clicks the result postcode to goto the next page. What im stuck with is how to take that result and automatically display it on the clicked "final" page? Search script: Code: [Select] <?php // Get the search variable from URL $var = @$_GET['q'] ; $trimmed = trim($var); //trim whitespace from the stored variable // rows to return $limit=10; // check for an empty string and display a message. if ($trimmed == "") { echo "<p>Please enter a search...</p>"; exit; } // check for a search parameter if (!isset($var)) { echo "<p>We dont seem to have a search parameter!</p>"; exit; } //connect to your database ** EDIT REQUIRED HERE ** mysql_connect("xxxxx","xxxx","xxxx"); //(host, username, password) //specify database ** EDIT REQUIRED HERE ** mysql_select_db("removalspacelogin") or die("Unable to select database"); //select which database we're using // Build SQL Query $query = "(SELECT postcode FROM freelistings WHERE postcode like '%$trimmed%') UNION (SELECT postcode FROM basicpackage WHERE postcode like '%$trimmed%') UNION (SELECT postcode FROM premiumuser WHERE postcode like '%$trimmed%') ORDER BY postcode"; // EDIT HERE and specify your table and field names for the SQL query $numresults=mysql_query($query); $numrows=mysql_num_rows($numresults); $result = mysql_query($query) or die("<b>Query:</b> $query<br><b>Error</b>: " . mysql_error()); // If we have no results, offer a google search as an alternative if ($numrows == 0) { echo "<h4>Results</h4>"; echo "<p>Sorry, your search: "" . $trimmed . "" returned zero results</p>"; echo "<p><a href=\"http://www.google.com/search?q=" . $trimmed . "\" target=\"_blank\" title=\"Look up " . $trimmed . " on Google\">Click here</a> to try the search on google</p>"; } // next determine if s has been passed to script, if not use 0 if (empty($s)) { $s=0; } // get results $query .= " limit $s,$limit"; $result = mysql_query($query) or die("Couldn't execute query"); // display what the person searched for echo "<p>You searched for: "" . $var . ""</p>"; // begin to show results set echo "Results for $q"; $count = 1 + $s ; // now you can display the results returned while ($row= mysql_fetch_array($result)) { $title = $row['postcode']; echo " $title" ; $count++ ; } $currPage = (($s/$limit) + 1); //break before paging echo "<br />"; // next we need to do the links to other results if ($s>=1) { // bypass PREV link if s is 0 $prevs=($s-$limit); print " <a href=\"$PHP_SELF?s=$prevs&q=$var\"><< Prev 10</a>  "; } // calculate number of pages needing links $pages=intval($numrows/$limit); // $pages now contains int of pages needed unless there is a remainder from division if ($numrows%$limit) { // has remainder so add one page $pages++; } // check to see if last page if (!((($s+$limit)/$limit)==$pages) && $pages!=1) { // not last page so give NEXT link $news=$s+$limit; echo " <a href=\"$PHP_SELF?s=$news&q=$var\">Next 10 >></a>"; } $a = $s + ($limit) ; if ($a > $numrows) { $a = $numrows ; } $b = $s + 1 ; echo "<p>Showing results $b to $a of $numrows</p>"; ?> <form method="post" action="localarea.php"> <a href="localarea.php"><?php echo """ .$var. ""</p>";?></a> </form> [\code] The form at the bottom im guessing is where i should take the $var from but how exactly? or if not where should it be pulled from to display on the next page? I want this "next" page because ideally there would be lots of results in postcode, so the user can choose which one is more relevant to them and go to that specific page with all the companies within that postcode. Hope this helps for a better understanding of what im trying to achieve, its just implementing it in? Similar TutorialsThis topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=321088.0 Hello, I'm developing a website that asks the user to submit a keyword for a search. The results should display matches for this keyword, but also show matches for related keywords (in order of relevenace!). I'm planning on building up a library of which search terms users use in the same sessions (e.g. if someone searches for "it jobs" and "php jobs", I'll know the terms are correlated), and I'll also measure the click-through rates of the items on the results list. I've been spending all weekend trying to map out the design for this but it's proving incredibly complicated and I think the solution is likely to be on the internet somewhere already?! Please could someone point me in the right direction if you've come accross this problem before? Thanks a million, Stu Code: [Select] if (isset($_POST['update'])) { $signature = $_POST['signature']; $type = $_POST['type']; $name = $_POST['name']; $b=0; While ($b < $i) { echo $signature[$b]."<br>"; echo $type[$b]."<br>"; echo $name[$b]."<br><br>"; $b++; }} I did echo '<pre>'; print_r($_POST); echo '</pre>'; The results are Code: [Select] Array ( [sname] => [notes] => [signature] => Array ( [0] => 1-1 [1] => 1-2 [2] => 1-3 ) [type] => Array ( [0] => Test1 [1] => Test2 [2] => Test3 ) [name] => Array ( [0] => Testa [1] => Testb [2] => Testc ) [update] => Update ) But for some reason nothing is showing up on the screen. How do I present these documentaries like this:
0-9
10 Things You Need to Know About Sleep
20 Animals That Will Kill You
A
Ant Kingdom
Atkins Diet
B
Battle of the Brains
Body Talk
I don't even know where to start!
I'm not asking anyone to do this for me; I just need a push in the right direction.
Any help will be appreciated.
Ok, here's my code: How do i make it so that it outputs a maximum of only 5 results from the query where the img file exists. When I add LIMIT to the sql query it doesnt work so I guess its something else, but I have no clue. Can anyone help? $query = mysql_query("SELECT * FROM table WHERE date >= '$now' ORDER BY max(date) desc"); while ($row = mysql_fetch_assoc($query)) { $cid = $row['cat_id']; $title = $row['name']; $seoname = $row['seourl']; $img = 'images/'.$seoname.'.jpg'; if (!file_exists($img)) { $img = ''; } else { $img = 'images/'.$seoname.'.jpg'; } if (!empty($img)) { echo '<a href="images/'.$seoname.'/"><img src="'.$img .'" style="width:528px;" alt="" /></a>' . "\n"; } } Thanks. i have built pages that paginate with 10 rows per page (some pages show more but for the moment i want to focus on this particular page)
//Define Some Options for Pagination
$num_rec_per_page=10;
if (isset($_GET["page"])) { $page = $_GET["page"]; } else { $page=1; };
$start_from = ($page-1) * $num_rec_per_page;
$results = mysql_query("SELECT * FROM `ecmt_memberlist` WHERE toonCategory='Capital' AND oldMember = 0 ORDER BY CONCAT(MainToon, Name) LIMIT $start_from, $num_rec_per_page") or die(mysql_error());
$results_array = array();
while ($row = mysql_fetch_array($results)) {
$results_array[$row['characterID']] = $row;
}
The above sets the variables for the pagination and below the results are echo with 10 rows per page
then i show the pagination links:
<?php
$sql = "SELECT * FROM `ecmt_memberlist` WHERE toonCategory='Capital' AND oldMember = 0 ORDER BY CONCAT(MainToon, Name)";
$rs_result = mysql_query($sql); //run the query
$total_records = mysql_num_rows($rs_result); //count number of records
$total_pages = ceil($total_records / $num_rec_per_page);
?>
<table width="100%" border="0" cellspacing="0" cellpadding="0">
<tr>
<td align="center"><div style="width:100%; text-align:center;">
<ul class="pagination">
<li class="selected">
<?php
echo "<a href='capitalmember.php?page=1'>".'«'."</a> ";?>
</li>
<?
for ($i=1; $i<=$total_pages; $i++) {
echo "<li><a href='capitalmember.php?page=".$i."'>".$i."</a></li> ";
};
?>
<li class="selected">
<?
echo "<a href='capitalmember.php?page=$total_pages'>".'»'."</a> "; // Goto last page
?></li>
</ul></div>
<?php
$pageNr = $page; // Get Current Page Number
$from = $pageNr * $rowsPerPage; // 3 * 10 = 30 // 3 * 10 = 30
$to = $from + $rowsPerPage; // 30 + 10 = 40
echo $pageNr;
/* Result: From page 30 to 40 */
?></td>
</tr>
</table>
this works great and shows me 10 results per page,
what i need to work out and work on next is:
echo the number of results above the records (for example: "showing records 1 to 10" and then on page 2 "showing records 11 to 21" and page 3 "showing records 22 to 32"
how can i work out the maths for this echo?
i was thinking along the lines of;
<?php
$pageNr = $page; // Gets Current Page Number
$from = $pageNr * $rowsPerPage; // 3 * 10 = 30
$to = $from + $rowsPerPage; // 30 + 10 = 40
// Now Show Results
echo $from; // Echo from
echo $to // Echo to
?>
but i'm still working on this..
then i need to look at shortening the amount of page links on the page if for example i have 500 records it shows me links 1 to 50 and eats up the page....
Appreciate any help and light onto my problems.
Many thanks
Edited by jacko_162, 11 January 2015 - 05:43 PM. Hello community, I am working on a database of specialties in the hospital I work. The doctor's referral requests are sent to a mySQL database and I have, with the help of online guidance, produced a working php script that displays the information I need it to. However, I need it a little bit more specific. I intend to make multiple copies of this file for each specialty, so that when they open the file they only have the requests for that particular specialty. My question is, with reference to my code below, can I make echo information so that online, for instance, if 'specialty1 = gastroenterology' (as in, that particular specialty that that referral request is for), then only the rows on the database that have that particular text are displayed only? Hope that makes sense. Code below for your reference and assistance is highly appreciated.
<!DOCTYPE html>
<html>
<head>
<title>Specialty Referral Form</title>
<style>
table {
border-collapse: collapse;
width: 100%;
color: #000000;
font-family: arial;
font-size: 10px;
text-align: center;
}
th {
background-color: #588c7e;
color: white;
}
tr:nth-child(even) {background-color: #f2f2f2}
</style>
</head>
<body>
<table>
<tr>
<th>Patient Details</th>
<th>Hospital Number</th>
<th>Date of Birth</th>
<th>Referred by:</th>
<th>New/Repeat Visit to Patient</th>
<th>Specialty</th>
<th>Admission Date</th>
<th>Too Ill for Clinic?</th>
<th>Diagnosis Aware?</th>
<th>Question</th>
<th>History</th>
<th>Medications</th>
<th>Examination</th>
<th>Results</th>
<th>WorkingDiagnosis</th>
<th>Investigation(s) Requested</th>
</tr>
<?php
$conn = mysqli_connect("localhost", "view", "", "referral");
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT patientdetails, hospitalnumber, DoB, referral, admission, specialty1, admissiondate, illness, awareness, question, history, medications, examination, results, workingdiagnosis, investigations FROM referralform";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while ($row = $result->fetch_assoc()) {
echo "<tr><td>" . $row["patientdetails"]. "</td><td>" . $row["hospitalnumber"] . "</td><td>" . $row["DoB"] . "</td><td>"
. $row["referral"] . "</td><td>" . $row["admission"] . "</td><td>" . $row["specialty1"] . "</td><td>" . $row["admissiondate"] . "</td><td>"
. $row["illness"] . "</td><td>" . $row["awareness"] . "</td><td>" . $row["question"] . "</td><td>" . $row["history"] . "</td><td>"
. $row["medications"] . "</td><td>" . $row["examination"] . "</td><td>" . $row["results"] . "</td><td>" . $row["workingdiagnosis"] . "</td><td>"
. $row["investigations"]. "</td></tr>";
}
echo "</table>";
} else { echo "0 results"; }
$conn->close();
?>
</table>
</body>
</html>
I guess what I am looking for is something like echo specialty1 IF it writes a particular specialty and only that specialty. Thank you. Edited April 2, 2020 by samanjHello, im new here, and i have little experience to php and mysql as i started for 2 weeks ago. I started out with some tutorials and feeling im getting the hang of it. Enough of me, lets get to the point: <?php $con = mysql_connect('localhost',$user,$pass)or die(mysql_error()); $selectdb = mysql_select_db($selectdb)or die(mysql_error()); $sql = "SELECT * From table"; $result = mysql_query($sql); $num = mysql_num_rows($result); $myarray = array($result); $i =0; while ($i < $num){ echo $myarray[$i]; $i++; } ?> Here i have written a dummyscript that does what the original script does, it tries to fetch the keys from the table and then trying to loop it and echo out the results. The output in the browser is this: Resource id #3 I know this probably is a simple fix but i cant seem to get it sorted out. Hope some of you could help me get this baby work, or maybe have another way of doing it more "simple". Thanks in advance! Dan-Levi here is my code... please help <form method="get" action="shit3.php"> <input maxlength="50" size="50" type="text" name="q"> <input type="submit" value="SEARCH"> </form> <?php if (@$_GET['q']) { $var = $_GET['q'] ; $trimmed = trim($var); $limit=1; if ($trimmed == "") { echo "Please enter a search..."; exit; } if (!isset($var)) { echo "Container not found!"; exit; } mysql_connect("localhost", "xxx", "yyy") or die(mysql_error()); mysql_query("SET NAMES 'cp1251'"); mysql_select_db("agaexpor_container") or die("Unable to select database"); //select which database we're using $query = "select * from containertracking where vin like \"%$trimmed%\" order by vin"; $numresults=mysql_query($query); $numrows=mysql_num_rows($numresults); if (empty($s)) { $s=0; } $query .= " limit $s,$limit"; $result = mysql_query($query) or die("Couldn't execute query"); $count = 1 + $s ; while ($row= mysql_fetch_array($result)) { $vin = $row["vin"]; $container = $row["container"]; echo "$count.) VIN: $vin <br />"; echo "container is: $container <br />"; $count++ ; } } ?> What I expect: - The function to loop output all of the rows which match the search results. The problems: - Only 1 row is matched. - Notice: Undefined index: id in G:\xampp\htdocs\xampp\dsa\search_func.php on line 57 - The image is not showing Line 57: Code: [Select] $id = $_REQUEST['id']; Entire Code: Code: [Select] <?php /* return the details of an employee parameter empno - employee number eg empHTML.php?empno=7521 This is very basic e.g no error checking */ function search($dbc, $id) { if (isset($_GET['terms']) && ($_GET['terms'] != 'Search...') ) { $terms = $_GET['terms']; $dbc = mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD, DB_NAME) or die *('Error connecting to MySQL server'); $query = "SELECT * FROM stick, location, identification WHERE make LIKE '%$terms%' AND stick.sid = location.lid AND identification.stickID = stick.sid AND identification.stickID = $id"; $result=mysqli_query($dbc,$query); $num_rows = mysqli_num_rows($result); $output = Array(); $image = mysqli_fetch_object($result); if ($num_rows > 0){ if($result=mysqli_query($dbc,$query)){ $output[] = '<ul>'; $output[] = '<li> Type: '.$image->make .'<br />Size: '.$image->size .$image->type .'<br />Colour: '.$image->colour . '<br /> Street Missing in: ' .$image->street.'<br />Town missing in: '.$image->town .'<br />City missing in: '.$image->city.'</li>'; $output[] = '</ul>'; } return join('',$output); } else { echo "<h3>Sorry,</h3>"; echo "<p>your search: "" .$terms. "" returned zero results</p>"; } } else { // Tell them to use the search form. echo '<p class="error">Please use the search form at the top of the window to search this site.</p>'; } } // connect $dbc = mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD, DB_NAME); // get the id from the URL $id = $_REQUEST['id']; print search($dbc, $id); print "<img src='getPhoto.php?id=$id'/>"; // close the database mysqli_close($dbc); Hi, I have a problem if users search something which doesn't match the data in the table I'm selecting from. At the moment I'm trying this code: Code: [Select] <?php require_once('inc/global.inc.php'); # search.inc.php /* * This is the search content module. * This page is included by index.php. * This page expects to receive $_GET['terms']. */ // Redirect if this page was accessed directly: if (!defined('BASE_URL')) { // Need the BASE_URL, defined in the config file: require_once ('../includes/config.inc.php'); // Redirect to the index page: $url = BASE_URL . 'index.php?p=search'; // Pass along search terms? if (isset($_GET['terms'])) { $url .= '&terms=' . urlencode($_GET['terms']); } header ("Location: $url"); exit; } // End of defined() IF. // Print a caption: echo '<h2>Search Results</h2>'; // Display the search results if the form // has been submitted. if (isset($_GET['terms']) && ($_GET['terms'] != 'Search...') ) { $terms = $_GET['terms']; $dbc = mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD, DB_NAME) or die *('Error connecting to MySQL server'); // Query the database. $query = "SELECT * FROM product WHERE title LIKE '%$terms%'"; // Fetch the results. //$row = mysqli_fetch_array($result); // Print the results: $result=mysqli_query($dbc,$query); if ($result == 0){ echo "<h3>Sorry,</h3>"; echo "<p>your search: "" .$terms. "" returned zero results</p>"; } while($row=mysqli_fetch_assoc($result)) { $output[] = '<ul>'; $output[] = '<li>'.$row['title'] .': £'.$row['price'].'<br /><img src="'.$row['img'].'" alt="'.$row['title'].'" /></li>'; $output[] = '</ul>'; } echo join('',$output); } else { // Tell them to use the search form. echo '<p class="error">Please use the search form at the top of the window to search this site.</p>'; } ?> But I'm getting this error: Object of class mysqli_result could not be converted to int So that little if statement here doesn't work: Code: [Select] if ($result == 0){ echo "<h3>Sorry,</h3>"; echo "<p>your search: "" .$terms. "" returned zero results</p>"; } Is there another way I can display no search matched results? Thank you for reading, Andrew. I am trying to write a script that will allow me visitors to my site to search my database for items. I followed a tutorial that I had found and tweaked it to fit my needs. I am not getting any results it keeps telling that there was no search results found. Even though I have the items that I have been testing on in my database. I have two files the main search.php file and the search_func.php file Here is the search.php file Code: [Select] <form method='post' action='search.php'> <fieldset> <input type='text' name='search' id='search' value='type name here'/> <input type='submit' name='search_submit' id='search_submit' value='search'/> </fieldset> </form> <?php include('includes/search_func.php'); if(isset($_POST['search'])) { $keywords = mysql_real_escape_string(htmlentities(trim($_POST['search']))); $errors = array (); if (empty($keywords )){ $errors[] = 'Please enter a search term'; } else if (strlen($keywords ) < 3 ) { $errors[] = 'Search term must be more then three characters long'; } else if (search_results($keywords == false)) { $errors[] = 'Your search for ' .$keywords . ' showed no results'; } if (empty($errors)) { $results = search_results($keywords ); $results_num = count($results); $suffix = ($results_num != 1) ? 's' : ''; echo 'Your search for <strong>'. $keywords .'</strong> returned <strong>' .$results_num.'</strong> result'.$suffix.''; foreach($results as $result) { echo $result['first']; } } else { foreach($errors as $error){ echo $error; } } } ?> Here is the search_func.php file Code: [Select] <?php include('includes/config.php'); connect(); function search_results($keywords ) { $returned = array(); $where = ""; $keywords = preg_split('/[\s+]/', $keywords ); $total = count($keywords ); foreach($keywords as $key=>$keyword) { $where .= "`l_name` LIKE '%$keyword%'"; if($key != ($total - 1)){ $where .= "OR"; } } $results = "SELECT `l_name`,`f_name`,`image`,`item_return` FROM `ttmautos` WHERE $where"; $results_num = ($results = mysql_query($results)) ? mysql_num_rows($results): 0 ; if ($results_num === 0) { return false; } else { while($results_row = mysql_fetch_assoc($results)) { $returned_results[] = array( 'last' => $results_row['l_name'], 'first' => $results_row['f_name'], 'image' => $results_row['image'], 'item' => $results_row['item_return'] ); } return $returned_results; } } ?> If anyone could give me an idea of what I am doing wrong I would appreciate it. hey guys, i have a search bar i am implementing into my navmenu but keeping getting errors returned and im not sure why This is the code in my navmenu to display the search bar Code: [Select] echo '<form action="search.php" method="post">Search: <input type="text" name="term" /> <input type="submit" name="submit" value="Search"/>'; Code: [Select] Here is the php file that query's the search $term = $_POST['term']; $dbc = mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD, DB_NAME); $query = mysqli_query("select * from ob_listings where subject like '%$term%' or description like '%$term%' "); while ($row = mysql_fetch_array($dbc, $query)){ echo 'Subject: '.$row['subject']; echo '<br/> Date: '.$row['date']; echo '<br/> Price: '.$row['price']; echo '<br/> City: '.$row['city']; echo '<br/><br/>'; } any help is much appreciated here are the errors being returned Warning: mysqli_query() expects at least 2 parameters, 1 given in C:\vhosts\HeadFirst\ourbazzar\search.php on line 16 (line 16 is the $query) Warning: mysql_fetch_array() expects parameter 1 to be resource, object given in C:\vhosts\HeadFirst\ourbazzar\search.php on line 17 (line 17 is the while loop) Hi, I have search form which works apart from 1 part, I have set the results limit to 10 per page with a next link if there are more than 10 results, however when the next link is clicked, i get the error 'you do not have a search parameter' which comes from this code: Code: [Select] if (!isset($var)) { echo "<p>We dont seem to have a search parameter!</p>"; exit; } The next link is defined by the code below: Code: [Select] // check to see if last page if (!((($s+$limit)/$limit)==$pages) && $pages!=1) { // not last page so give NEXT link $news=$s+$limit; echo " <a href=\"$PHP_SELF?s=$news&q=$var\">Next 10 >></a>"; } Can anyone see where I have gone wrong with this code without me sending the whole search form? Any help would be very much appreciated. Thanks Okay, I'm wanting to do a search, but until return the info if it has a specific indicator in the chosen field. Let me show you: $query = doquery("SELECT * FROM `orgs` IF `type`='c' ORDER BY name", "orgs"); How do I do that "IF" bit? Obviously this doesn't work. Thanks! Good Evening, I've been in a trial and error state for the past week trying to figure out how I can put on the pre-made pagination scripts I found on the web, but of no luck. I have just started programming like two weeks ago, and is still trying to understand logics and stuffs so I can get my desired output. So far, everything is doing well except for one - I am really having a hard time to incorporate pagination scripts with my code. To rank myself as a php programmer, I can say I am lower than one, and seemingly, what I want to achieve is an advanced code. Can anyone help me on what pagination code I should try to play with and incorporate with my code? Here's my code so far: <?PHP include("dbconnection.php"); //Include database connection to file $query = "SELECT * FROM records"; if(isset($_POST["btnSearch"])) { $query .= " WHERE last_name LIKE '%".$_POST["search"]."%' OR first_name LIKE '%".$_POST["search"]."%'OR territory LIKE '%".$_POST["search"]."%'OR job_title LIKE '%".$_POST["search"]."%'OR title LIKE '%".$_POST["search"]."%'OR employer LIKE '%".$_POST["search"]."%' ORDER BY territory ASC LIMIT 0,15" ; $result = mysql_query($query, $connection) or die(mysql_error()); } ?> <!-- Start of table --> <table width="760" border="0" align="center" cellpadding="0" cellspacing="0"> <td> <table width="760" border="0" cellpadding="0" cellspacing="0"> <!-- Table data containing the Asia Logo --> <td width="199" align="center" valign="top"> <a href="login.html"> <img src="asia.gif" alt="" width="152" height="58" border="0" /> </a> </td> <!-- Table data containing Home button --> <td width="176" align="right" valign="bottom"> <a href="main.php"> <img src="Home.jpg" width="104" height="20" border="0"/> </a> </td> <!-- Table data containing View Client button --> <td width="130" align="right" valign="bottom"> <img src="View.jpg" width="104" height="20" border="0"/> </td> <!-- Table data containing the Add Client button --> <td width="146" align="right" valign="bottom"> <a href="add_client.php"> <img src="Add.jpg" width="104" height="20" border="0"/> </a> </td> <!-- Blank table data --> <td width="109" align="right" valign="bottom"> </td> </table> <!-- Table design division and body--> <table width="760" border="0" cellpadding="0" cellspacing="0"> <td width="200" height="3" bgcolor="#1B1C78"> <img src="images/topspacerblue.gif" alt="" width="1" height="3" /></td> <td width="560" bgcolor="#0076CC"> <img src="images/topspacerlblue.gif" alt="" width="1" height="3" /></td> <tr> <td height="500" colspan="2" align="center" valign="top" bgcolor="#F3FAFE"> <!-- Page contents --> <!-- Search Query --> <br> <form name="form" action="view_client.php" method="post"> <table width="351" border="0"> <tr> <td width="137" align="left" valign="middle"> SEARCH RECORD: </td> <td width="144" align="center" valign="middle"> <input type="text" name="search" /> </td> <td width="56" align="left" valign="middle"> <input type="submit" name="btnSearch" value="Search" /> </td> </tr> </table> <br> <!-- End of search query--> <!-- Start of Search Results--> <table border="0" cellpadding="3" cellspacing="1" bordercolor="38619E" > <tr> <th width="80" align="center" bgcolor="#E0E8F3">Territory</th> <th width="330" align="center" bgcolor="#E0E8F3">Employer</th> <th width="160" align="center" bgcolor="#E0E8F3">Name</th> <th width="80" align="center" valign="middle" bgcolor="#E0E8F3"> </th> </tr> <?php if($result) { for($i=0; $i<mysql_num_rows($result); $i++) { $id = trim(mysql_result($result, $i, "id")); $territory = trim(mysql_result($result, $i, "territory")); $employer = trim(mysql_result($result, $i, "employer")); $first_name = trim(mysql_result($result, $i, "first_name")); $last_name = trim(mysql_result($result, $i, "last_name")); echo "<tr>"; echo "<td>".$territory."</td>"; echo "<td>".$employer."</td>"; echo "<td>".$last_name.", ".$first_name."</td>"; echo "<td><a href='edit_client.php?id=".$id."'>edit</a> | <a href='delete_client.php?id=".$id."'>delete</a></td>"; echo "</tr>"; } } ?> </table> </form> <!-- End of page --> </td> </tr> </table> </td> <tr> <td height="38"> <table width="760" border="0" cellpadding="0" cellspacing="0"> <td width="200" height="35" align="center" bgcolor="#1B1C78" class=white> <a href="disclaimer.html"> <font color="#FFFFFF">Legal Disclaimer</font> </a> </td> <td width="560" align="center" bgcolor="#0076CC"> Copyright © 2006 - 2010 Asia. All rights reserved. </td> </table></td> </tr> </table> Thank you very much, and I am looking forward for your responses. Thanks! I'm new to php and been trying to follow along with different tutorials to try and build my own site, i followed a tutorial on making a search feature for the site and have it working perfectly, but i want to change the way how to search displays the results. I want to make it display them how there displayed on the index page. here is the index page how there displayed <div id="table"> <table> <tr class="top"> <th>Account</th> <th>Country</th> <th>Info</th> <th>Login</th> <th>Pass</th> <th>Price</th> <th>Buy</th> </tr> <?php $class = 'grey'; ?> <?php $items = getItems(); ?> <?php if(empty ($items)): ?> <h3>No Items Found</h3> <?php else: ?> <?php foreach($items as $item): ?> <?php $class = ($class == 'grey') ? 'grey2' : 'grey'; ?> <tr class="<?php echo $class; ?>"> <td><?php echo $item['item_account']; ?></td> <td><?php echo $item['item_country']; ?></td> <td><?php echo $item['item_info']; ?></td> <td><?php echo maskUser($item['item_login']); ?></td> <td><?php echo maskPass($item['item_pass']); ?></td> <td><?php echo $item['item_price']; ?> </td> <td><form method="post" action="https://sci.libertyreserve.com/"><input type="submit" name="buy" value="Buy" class="button" /></form></td> </tr> <?php endforeach; ?> <?php endif; ?> how the search is display if (strlen($search) <= 2) { echo 'Search keyword is too short.'; } else { echo "You searched for <b>$search</b><hr size='1'>"; $search_exploded = explode(" ", $search); foreach($search_exploded as $search_each) { $x++; if ($x == 1) $construct .= "item_account LIKE '%$search_each%'"; else $construct .= " OR item_account LIKE '%$search_each%'"; } $construct = "SELECT * FROM items WHERE $construct"; $run = mysql_query($construct); $foundnum = mysql_num_rows($run); if ($foundnum == 0) { echo 'No results found.'; } else { echo "$foundnum results found!</p>"; while ($numrows = mysql_fetch_assoc($run)) { $item_id = $numrows['item_id']; $itemAccount = $numrows['item_account']; $itemI = $numrows['item_info']; $itemLogin = $numrows['item_login']; $itemPass = $numrows['item_pass']; $itemPrice = $numrows['item_price']; echo " <b>$itemAccount</b><br /> $itemI <br /> " . maskUser($itemLogin) . '<br />' . maskPass($itemPass, 0) . '<br />'; } } } my question is im not sure how to edit the search code to display the results in the same format as the index page thanks Hi guys, A beginner at php/mysql here... For a project I'm doing, I would like to display search results with an image, small description, then a 'read more' link. After googling this issue, I can't find much information on it, which surprised me. Someone did mention blobs for images... (whatever they are!) I'm wondering if anyone knows of any tutorials, or has any code to do this? Your help is much appreciated. Thanks. hi, I have a search page with a checkbox $departuk that returns the value "true" if checked. I want to return search results if this returns true and the flag 'Y' is available if ($departuk == "true"){ if ($data[$i]['departuk'] == 'Y'){ $result = $obj->result; } else{ echo "do some thing else"; } else{ echo"there was a problem"; } any pointers / advice is appreciated thanks |
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