PHP - Need Help With Reservation Calendar

Hi Folks,

I'm creating an equipment reservation system for a client.  Every reservation has an equipmentID, ReservationDate, StartTime, EndTime.  So, basically my script searches existing records for a given date and EquipmentID.  I'm having trouble with how best to approach validation on new reservations to ensure there are no conflicts. 

Lets say two existing reservations for a given date/equipment are found.  One reservation has a startTime of 8AM and endTime of 9AM.  The second has a startTime of 12PM and endTime of 3PM.  Is there a simple way to check if the user's submitted values for StartTime and EndTime conflict with existing reservations? 

Any input would be greatly appreciated!  Thanks!

-John

Hello Guys,
My goal is to make a Php and SQL calendar. I started learning php and sql a while ago, and basically got distracted. I'm now back, with a new project in the unhelpful position of having forgotten most of what I had learnt!

I am making a project where I want to make a booking system. I have 3 rooms that are available to be booked Room 1, Room 2 and Room 3. I want to make a table that displays the current year in the top row, with the option to be able to click on a '<' or a '>' to change years. I want the same option for months and weeks. I think I am happy with how I would do this. The next bit is more tricky. I want a column for each of the days of the week. directly under this I want to display the correct date, under the correct day, starting with the current week we are on. for example it might look like this:

               -------------------------------------------
               |             <     2012      >                    |
               -------------------------------------------
               |             <      March     >                   |
               -------------------------------------------
               |             <      2     >                          |
               -------------------------------------------
               |mon | tues | wed| thur | fri  | sat | sun |
              | 5th  |  6th |  7th|  8th |9th |10th| 11th |
               ---------------------------------------------
Room 1   | yes    |        |       |       |      |     |        |
               ----------------------------------------------
Room 2   |         |        | yes  |       |      |     |        |
               ----------------------------------------------
Room 3   |         |        |       |       |yes  |     |        |
               ----------------------------------------------

Although at the moment I'm struggling with the whole flippin' thing, the main issue is getting the correct dates to line up under the correct days of the week. I'm not asking for you to do this for me- but a bit of gentle help in this, and maybe some general advice in what I'm trying to achieve would be really useful!

Regards,

AJLX

 

    Good Evening ! 
little help or a lot please ?

I have coded a calendar on my site and am now trying to input the data info from MySQL into the 
calendar by PHP for each corresponding date...the calendar code works but I cant figure out how to 
get the info that's submitted in to the specified/corresponding date in the calendar :/ but I can get 
it to the bottom of the page.

I've been at this 3 days and a million searches to find an example to follow but now I am at my wits 
end ! been about 15 years since I've done this. PLEASE help :) and thank you so much
The HTML is good I can add to it if needed but the problem area is the calendar portion and putting 
it all in the right place without an error or code issue.

I'm not sure how much more information i can provide. Like I said I am still trying to remember all 
of this stuff and trying to teach myself again and im not having much luck but i am a fast learner 
and 
can pickup by seeing how the code is written usually

Here is my code: or at least the PHP portion of it. I hope this helps.

<?php
/*MAKES THE CONNECTION*/
include 'config.php';
$conn = mysqli_connect($servername, $username, $password, $dbname);
// CHECK CONNECTION
if (!$conn) {
    die("Connection failed: " . mysqli_connect_error());
}
/*DRAWS CALENDAR*//
function draw_calendar($month,$year){

$calendar = '<table cellpadding="0" cellspacing="0" class="calendar">';

$headings = array('Sunday','Monday','Tuesday','Wednesday','Thursday','Friday','Saturday');
$calendar.= '<tr class="calendar-row"><td class="calendar-day-head">'.implode('</td><td 
class="calendar-day-head">',$headings).'</td></tr>';

$running_day = date('w',mktime(0,0,0,$month,1,$year));
$days_in_month = date('t',mktime(0,0,0,$month,1,$year));
$days_in_this_week = 1;
$day_counter = 0;
$dates_array = array();
$start_day = 

$calendar.= '<tr class="calendar-row">';

for($x = 0; $x < $running_day; $x++):
    $calendar.= '<td class="calendar-day-np"> </td>';
    $days_in_this_week++;
endfor;

for($list_day = 1; $list_day <= $days_in_month; $list_day++):
    $calendar.= '<td class="calendar-day">';
        /* add in the day number */
        $calendar.= '<div class="day-number">'.$list_day.'</div>';

        /** QUERY THE DATABASE FOR AN ENTRY FOR THIS DAY !!  IF MATCHES FOUND, PRINT THEM !! **/
        $sql = "SELECT * FROM $tablename WHERE $current_epoch BETWEEN $start_day AND $end_day";
        /** NEED TOQUERY THE DATABASE FOR AN ENTRY FOR THIS DAY !!  IF MATCHES FOUND, PRINT THEM !! 
**/
$calendar.= str_repeat('<p>'.$start_day.'</p>',2);

     $calendar.= '</td>';
    if($running_day == 6):
        $calendar.= '</tr>';
        if(($day_counter+1) != $days_in_month):
            $calendar.= '<tr class="calendar-row">';
        endif;
        $running_day = -1;
        $days_in_this_week = 0;
    endif;
    $days_in_this_week++; $running_day++; $day_counter++;
endfor;

if($days_in_this_week < 8):
    for($x = 1; $x <= (8 - $days_in_this_week); $x++):
        $calendar.= '<td class="calendar-day-np"> </td>';
    endfor;
endif;

/* final row */
$calendar.= '</tr>';

/* end the table */
$calendar.= '</table>';

return $calendar;
}
$sql = "SELECT id, name, phone, item, start_day, end_day, start_time, end_time FROM $tablename";
$result = $conn->query($sql);

if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo $calendar. "id: " . $row["id"]. " - Name: " . $row["name"]. " - Phone: " . $row["phone"]. " - 
Item: " . $row["item"]. " - Start Day: " . $row["start_day"]. " - End Day:  " . $row["end_day"]. " - 
Start Time:  " . $row["start_time"]. " - End Time:  " . $row["end_time"]. "<br>";
}
} else {
echo "0 results";
}

	
	/*END OF SHOWINGCALENDAR_________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________
*/	
	
	
$sql = "SELECT id, name, phone, item, start_day, end_day, start_time, end_time FROM $tablename";
$result = $conn->query($sql);
	
/*GETS THE RESULTS OF THE CALENDAR FROM DATABASE TABLE*/
if ($result->num_rows > 0) {
  // output data of each row
  while($row = $result->fetch_assoc()) {
    echo $calendar. "id: " . $row["id"]. " - Name: " . $row["name"]. " - Phone: " . $row["phone"]. " - Item: " . $row["item"]. " - Start Day: " . $row["start_day"]. " - End Day:  " . $row["end_day"]. " - Start Time:  " . $row["start_time"]. " - End Time:  " . $row["end_time"]. "<br>";
  }
} else {
  echo "0 results";
}

 

Edited January 18 by Isfun42ofus

Hello there!

I've been at this for too long! I've got a normal calendar at the side of my website that works fine, however i would like one that shows the next 7 days starting at today. I have an image here that kind of shows what i want...



So it will show the next 7 days starting with today, and going into the next month if todays date is the 30th etc.

Could anybody please help me? :\

hi,

i have implemented a calendar in php and added contols to display the previous and next months. How will I enhance my code to add links to display the previous and next year calendars?

My code is as follows:
Code: [Select]
<?php
 session_start();
 $_SESSION['username'];
 $_SESSION['unique_id'];
 $username = $_SESSION['username'];
 $unique_id = $_SESSION['unique_id'];
 ?>

<?php
    $host = "localhost";
    $user=""; 
    $password=""; 
    $db_name=""; 
    $tbl_name=""; 
    
    $con = mysql_connect("localhost","","");
    if (!$con)
      {
          die('Could not connect: ' . mysql_error());
      }
    mysql_select_db("$db_name", $con);
    
    // Now we need to define "A DAY", which will be used later in the script:
    define("ADAY", (60*60*24));
     
    // The rest of the script will stay the same until about line 82
     
    if ((!isset($_GET['month'])) || (!isset($_GET['year']))) {
        $nowArray = getdate();
        $month = $nowArray['mon'];  //mon - Numeric representation of a month
    $year = $nowArray['year'];
    } else {
        $month = $_GET['month'];
    $year = $_GET['year'];
    }
    $start = mktime(12,0,0,$month,1,$year);
    $firstDayArray = getdate($start);
    ?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<title><?php echo "Calendar: ".$firstDayArray['month']."" . $firstDayArray['year']; ?></title>
<link type="text/css" href="css/style_inner.css" rel="stylesheet" />
</head>

<body>
    <form method="get" action="<?php echo $_SERVER['PHP_SELF']; ?>" style="padding-top:50px">
    <?php
        /* "next month" control */
$next_month = '<a href="?month='.($month != 12 ? $month + 1 : 1).'&year='.($month != 12 ? $year : $year + 1).'" class="control" style="text-decoration:none; padding-left:50px;">Next Month&nbsp;&nbsp;></a>';

/* "previous month" control */
$previous_month = '<a href="?month='.($month != 1 ? $month - 1 : 12).'&year='.($month != 1 ? $year : $year - 1).'" class="control" style="text-decoration:none; padding-left:200px; padding-right:50px;"><&nbsp;&nbsp;Previous Month</a>';


/*$next_year = '<a href="?year='.($year != 2050 ? $year + 1 : 1).'&year='.($year != 2050 ? $year : $year + 1).'" class="control" style="text-decoration:none; padding-left:10px;">Next Year&nbsp;&nbsp;>></a>';

$previous_year = '<a href="?month='.($year != 2011 ? $year - 1 : 2050).'&year='.($year != 2011 ? $year : $year - 1).'" class="control" style="text-decoration:none; padding-left:150px;"><<&nbsp;&nbsp;Previous Year</a>';

echo $previous_year;*/
echo $previous_month;
    ?>
    <select name="month"><br/>
    <?php
    $months = Array("January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December");
     
    for ($x=1; $x<=count($months); $x++){
        echo "<option value=\"$x\"";
    if ($x == $month){
            echo " selected";
        }
        echo ">".$months[$x-1]."</option>";
    }
    ?>
    </select>
    <select name="year">
    <?php
    for ($x=2011; $x<=2050; $x++){
    echo "<option";
        if ($x == $year){
        echo " selected";
        }
        echo ">$x</option>";
    }
    ?>
    </select>
<input type="submit" name="submit" value="Go!">
<?php
    echo $next_month;
    /*echo $next_year;*/
?>
    </form>
    <br />
    <?php
    $days = Array("Sun", "Mon", "Tue", "Wed", "Thu", "Fri", "Sat");
    echo "<table border=\"1\" style=\"padding-left:100px;\"><tr>\n";
    foreach ($days as $day) {
        echo "<td style=\"background-color: #000000; width: 100px\" align=\"center\">
              <strong style=\"color:#FFFFFF;\">$day</strong></td>\n";
    }
     
    for ($count=0; $count < (6*7); $count++) {
        $dayArray = getdate($start);
        if (($count % 7) == 0) {
        if ($dayArray["mon"] != $month) {
            break;
        } else {
                echo "</tr><tr>\n";
        }
        }
        if ($count < $firstDayArray["wday"] || $dayArray["mon"] != $month) { //wday - Numeric representation of the day of the week
        echo "<td height=\"110px\"> </td>\n";
        } else { //mday - Numeric representation of the day of the month
            $chkEvent_sql = "SELECT event_title, event_shortdesc FROM calendar_events WHERE month(event_start) = '".$month."' AND dayofmonth(event_start) = '".$dayArray["mday"]."' AND year(event_start) = '".$year."' ORDER BY event_start";
       $chkEvent_res = mysql_query($chkEvent_sql, $con) or die(mysql_error($con));
 
        if (mysql_num_rows($chkEvent_res) > 0) {
            $event_title = "<br/>";
            while ($ev = mysql_fetch_array($chkEvent_res)) {
                    $event_title .= "<font color=\"#006600\">" . stripslashes($ev["event_title"])."</font><br/>";
                    //$event_shortdesc .= stripslashes($ev["event_shortdesc"])."<br/>";
            }
                mysql_free_result($chkEvent_res);
            } else {
            $event_title = "";
            $event_shortdesc = "";
            }
 
        echo "<td height=\"110px\" style=\"color : #0000CC;\">".$dayArray["mday"]."<a href=\"event.php?m=".$month."&d=".$dayArray["mday"]."&y=".$year."\" style=\"text-decoration:none;\"><img src=\"images/Add Event.jpg\" alt=\"Add Event\" title=\"Add Event\" height=\"20px\" width=\"20px\" style=\"padding-left:20px;\"/></a><br/>".$event_title."</td>\n";
         unset($event_title);
     
            $start += ADAY;
        }
    }
    echo "</tr></table>";
    mysql_close($con);
    ?>

</body>
</html>

Please help me out its urgent..


Thank you in advance...

hello all,

i currently have a daily log book that the employees fill out.  the logs are displayed in a list format.

would there be an easy way to have an actual calendar look and have any logs for the day have the title display?

i can probably take care of the output on each day, just dont know how to have a calendar display.

thanks

howdy all

         I was wondering if anyone has any Basic Event calendar or a tutorial for a basic one.. I want to get a event calendar on my site but i want a basic one so i can tweak it to fit my likings.

Thank you
SilentHunter

Hi There,

I was wondering if there is a way, or in deed if there is an off the shelf calendar that would be able to interact with an SQL database?

I want to be able to display a week's worth of dates (Mon - Fri) - and show what is on each day, for different people, say 4. If possible, I would like it to read start and end dates from the DB, and if that entry is over 3 days, display it on 3 calendar days.

Has anyone heard of anything like this, or is it easy to code up?

Thanks in advance
Matt

hi, does anyone have a way to take data from mysql and instert it into outlook or blackberry calendar?

Can anyone help me please, I am trying to place a PHP calendar into an existing DIV tag that used to hold a flash slideshow application, but we want to replace that with a calendar.

Here is my code:

Code: [Select]
echo '<div class="grid_9">
<div class="box">
<h2>'.$titleone.'</h2>
<div class="block">';
if (!defined('BLOCK_FILE'))
{
  Header('Location: ../index.php');
    die();
}

$modName = 'GCalendar';             

$blockConfig =
   array('maxTitle'     => 21,               
         'eventPrefix'  => '&bull;&nbsp;',   
         'maxEvents'    => 10,               
         'lookahead'    => 2,               
         'twoColumn'    => false,           
                                           
         'excludeCats'  => array(),
         'force_center' => false,           
        );


require_once 'modules/' . $modName . '/language.php';
gcalGetLang($modName);
require_once 'modules/' . $modName . '/gcal.inc.php';
require_once 'modules/' . $modName . '/common.inc.php';
require_once 'modules/' . $modName . '/getMonthlyEvents.php';
require_once 'modules/' . $modName . '/gcalBlock.php';

$config = getConfig();

list($year, $month, $today) = explode(',', date('Y,n,j'));
$block = new GCalBlock($year, $month, $today, $config, $blockConfig);

$content = $block->calendar();
$content .= '<br />';
$content .= $block->upcomingEvents();

echo '</div>
</div>
</div>';

When I try this above, I just get an 'Too many page loads' error, so I'm not sure what I've done wrong.

Any help appreciated.

Regards,
Tree

I am working with a site that needs some kind of calendar solution. Each user will have their own events calendar. The plan is that your events calendar could sync with google, ical, BB calendar when done.

Should I build the calendar in PHP, then worry about syncing with these other apps? Or should I use come kind of 3rd party calendar to power the one I have? Or...does anyone know of any applications that help you sync calendars if I were to create one myself?

I looked into google cals, but they have a limit on the amount of calendars per day you can create.

Any ideas as to how I should go about this? All answers appreciated!

Hi,   

I am using the backbone.js and full calendar script in my website. However, on clicking OK in the popup to add events, no action is taking place. Actually the event should be displayed on that specific date on clicking OK. the cancel button is working fine. I am using the link
http://blog.shinetech.com/2011/08/05.../#comment-2245


Help me please.

Thank you in advance

hi
i open this post so i dont open 5 new ones

ok i have a task to do an event calendar now i found some tutorial for creating simple calendar BUT all of them are on english what i need is change it to croatian - that means i have custom names for days, custom names for months, and what i also need is put sunday where it belongs... at the end because we are calculating week starts by monday... so any tips?

if you know some tutorial that works for these spec things i googled it but i only found like 2 calendars that actualy works other have some bugs in scripts and wont do thing
or just write me tips and ill try to create it

I'm trying to help someone out with their website (which is entirely in PHP) and I've come across a problem I can't seem to figure out.

On the site is a php calendar that should display as so:



However, sometimes for no apparent reason the calendar appears as so:



I cannot seem to determine what is causing this to display incorrectly. It just started happening for no discernible reason.

Anyone have any idea where I should start looking to find the issue? It is linked to a MySQL database that is somewhat wonky, could that be the issue?

Thanks for any advice you guys can give me.