PHP - Copy Directory And Sub-directories Using File Names As .txt Files
Hello I have a problem.
I have been trying to copy my music folders structure but not copying the mp3s; instead using the file names as a file name for a .txt file and inserting the URL to the file in the .txt file. Eg. E:\My Music folder 1 folder 1.1 file.mp3 folder 2 folder 3 to G:\My Music folder 1 folder 1.1 file.txt folder 2 folder 3 and inside "file.txt" would be one line saying "http://www.xxx.com/my_music/file.mp3 Similar TutorialsI must be brain dead...I've searched everywhere and can't seem to find a snippet for this. I'm just looking for some code to show a directory listing, but only certain files (by extension) and I don't want to show any sub-directories. I thought I might have been able to do this in the .htaccess file, but I can't find anything that will get rid of the sub-directories. So, I figure there must be a way to get a file listing, check the extension, add it to the page, or skip it if it's a sub-directory or doesn't match the extension. Or, I could just be totally, way off...anyway, any help would be greatly appreciated...I'm fairly new to php. I have used the following script to correctly display the first file from the array across the selected directory and its sub-directories. Does anyone know how to modify this code to only echo the most recent file based on filemtime across the directory/subdirectories? Code: [Select] function ListFiles($dir) { if($dh = opendir($dir)) { $files = Array(); $inner_files = Array(); while($file = readdir($dh)) { if($file != "." && $file != ".." && $file[0] != '.') { if(is_dir($dir . "/" . $file)) { $inner_files = ListFiles($dir . "/" . $file); if(is_array($inner_files)) $files = array_merge($files, $inner_files); } else { array_push($files, $dir . "/" . $file); } } } closedir($dh); return $files; } } echo array_shift(ListFiles('media/media/images')); Seems this should be easy, but I'm not finding the solution. Functions like scandir, readdir, and glob that I've been looking at all seem to need me to actually know more about my directory path than I can ahead of time. Here's what I want to do: 1. expand a .tar file (consists of directory, subdirectories, files, and is variable) that I've uploaded to the server 2. look through that expanded directory for a subdirectory named ".pn" -- (note that all my .tar files will have this folder deep in several subdirectories that will be variable in number and have different names depending on the original .tar file) 3. copy the entire contents of the .pn folder to another folder already on my server The hosting company, no doubt, has likely blocked some of the functions I'll need as well, but if someone can point me in the right direction to start, it would be greatly appreciated. Thanks! Satre Hi Gusy, Would be great if you can help me to sort this out and Thank you in advance. I would like to hide all files with "swf" extension from my file and folder directory, I know how to hide one specific file but not ll files with same extension. For example: *.swf. Here is my code which is work for full file names but not all files with same extension. <?php $filearray = array(); if ($handle = opendir('.')) { while (false !== ($file = readdir($handle))) { if ($file != "." && $file != ".." && $file != ".htaccess" && $file != "index.php" && $file != "style.css" && $file != "Images" && $file != "*.swf" && $file != "index.html") { $filearray[] = $file; } } closedir($handle); natcasesort($filearray); foreach($filearray as $f) { $thelist .= '<img width="15" height="15" alt="[DIR]" src="/Images/folder.jpg"> <a href="'.$f.'">'.$f.'</a> '; } } ?> As you can see I have "&& $file != "*.swf"" which need your advise in this part. I just want people not seeing all .SWF files in the index directory of my server. I have already have index.html inside my folder as well which has been hided because of "$file != "index.html"". But this is not hiding my ".SWF" files. Many Thanks. i am getting this as a echo, Code: [Select] Directory handle: Resource id #2 Files: . ..why? Code: [Select] <? if ($handle = opendir('images')) { echo "Directory handle: $handle\n"; echo "Files:\n"; /* This is the correct way to loop over the directory. */ while (false !== ($file = readdir($handle))){ if (is_dir($file)){ echo "$file\n"; } } closedir($handle); } ?> Hello everyone, This is a fairly simple question, but the explanation of the question isn't... I'll do my best. I have a site where my folders/sub-folders/files are arranged similar to this: _ Root Folder -| Root-IncludeFile1.php | Root-IncludeFile2.php | _ | Sub-Folder 1 -| Sub1-File1.php | |_Sub1-File2.php | _ | Sub-Folder 2 -| Sub2-File1.php | |_Sub2-File2.php | _ |_Sub-Folder 3 -| Sub3-IncludeFile1.php |_Sub3-IncludeFile2.php Hopefully that makes sense to everyone. Anyway, I know that to include a file that is in the root folder in file in a sub-folder, I can do this - include("../includefile1.php"); -but I'm trying to include a file that is in a sub folder in a file that is in another sub-folder. For example, I'm trying to include "Sub3-IncludeFile1.php" in "Sub-File1.php" I'm lost on this because I can't get it to work. I'm not getting any error messages except to say that the variables located in the file that should be included are not found. I've tried to do this: include("http://www.mysite.com/Sub-Folder3/Sub3-IncludeFile1.php"); and it doesn't work. Can someone please point me in the right direction? Thanks in advance for your help. Hey I have this code which works fine, it echos the file names from a directory into a dropdown box how can I change it to include more then one directory <?php $dirname = "../images/staff"; $dir = opendir($dirname); echo '<select name="file2">'; echo '<option value="">none</option>'; while(false != ($file = readdir($dir))) { if(($file != ".") and ($file != "..")) { echo "<option value=".$file.">$file</option>"; } } echo '</select>'; ?> I tried this but it didnt work any help <?php $dirname = "../images/staff"; $dirname .= "../images/boarddirectors"; $dir = opendir($dirname); echo '<select name="file2">'; echo '<option value="">none</option>'; while(false != ($file = readdir($dir))) { if(($file != ".") and ($file != "..")) { echo "<option value=".$file.">$file</option>"; } } echo '</select>'; ?> How do I get directory names to display with spaces. My script sticks them into arrays just fine, but when trying to echo from a checkbox selection, it only displays the first word. How would I fix this? i have made an delete files script which works for only one directory but not sub directory so i want to delete files of same extention from directory and subdirectory. My current code is Code: [Select] <? $dir = 'hmm/'; function scanr($dir){ $arr = glob($dir.'/*.jpg'); foreach($arr as $vv){ //check if $vv is a file if(is_file($vv)){ //if file, get the filename $vx=explode('/',$vv); $file=$vx[count($vx)-1]; // if no extension delete the file unlink($vv); // print the deletion message echo $vv." deleted!<br>";}else{ // if $vv is a dir then scan it again for files scanr($vv); }} } scanr($dir); ?> Okay, so I'm kind of a PHP noob.
But out of context, for this site that I'm designing, it's easiest if I make a directory in the temporary folder PHP uses. In my case, /tmp/ because I am on Linux.
I want to use rand() to generate a random name for the page. But I then realized something, rand() could produce duplicates. How do I prevent PHP from trying to make the same directory at the same time? I know there are functions that will check if a file exists but I'm assuming it'll fail if that directory is currently being created, right?
How do I assure thread safety?
I willing to change my idea and not use rand(). Is there a way to get a unique key for each anonymous user on my site?
hey, can some one provide a code to help me copy a folder called contents with files in it to another folder called items cheers I know this code works
INSERT INTO archive_table SELECT * FROM original_table WHERE id = 1But i want to also add the current date whenever i copy the data into a new table. Thanks in advance How would I copy an array of selected files? I know how to list them using a 'for' loop, and how to separate them using a 'foreach' loop, but I am unable to get a checkbox array to copy to a destination folder. Help is appreciated. How do I include a file that is located two directories above the file that I want to include the file into? My absolute hosting path is /home/content/52/8840652/html if this would be of any use. I'm not quite sure about the PHP include functions. Any help would be greatly appreciated, Thanks! I need to copy php files from remote linux (apache) server to windows usb drive.
I am using php windows but the files were created in php under linux.
Do I just download them or do I need to do something to make this work
hi all, i have this music website and i have to upload every album under this folder "newsongs" ... in AlbumName folder i have normal quilty songs and HQ folder..under HQ folder i have High Quilty songs for each album. i have this coding which moves Album folder and normal quilty songs to other folder "songs" but i also want to move subfolder "HQ" and High Quilty songs with AlbumName folder for($i=0;$i<=$ct;$i++) { $alb=$alname[$i]; $cat=$catname[$i]; $albids=$albid[$i]; $fon=$folder_name[$i]; $tmp_name=$doc_root."newsongs/$fon"; $uploads_dir=$doc_root."songs/$cat/$fon"; if ($handle = opendir($tmp_name)) { /* This is the correct way to loop over the directory. */ while (false !== ($file = readdir($handle))) { //echo "$file\n <br>"; if($file !=='..' and $file !=='.') { $song_path="songs/$cat/$fon/$file"; if(!is_dir("$tmp_name/$file") and (!is_dir("$uploads_dir/$file"))) { if(copy("$tmp_name/$file", "$uploads_dir/$file")) { $cp=1; $ext=substr($file,-4); if($ext=='.mp3') $insqry=mysql_query(" insert into tbl_songs set song_name='$file', album_id='$albids', artist_id='$artid', song_path='$song_path' "); unlink($tmp_name.'/'.$file); } else { echo "could not move songs "; } } } if($insqry) $msg="songs Added to the database"; else $msg="songs Not Added to the database"; } closedir($handle); thnx in advnce I have created a table called directories. Now basically I have two fields; dirID (INT) directory (VARCHAR) now I am fully aware this might sound like more of an SQL question but I have three physical directories: db/images/web1 db/images/web2 db/images/web3 I have inputted them into the database but I was just wondering, how could I created a page which links those records to a directory. I want to have each row hyperlinked, with the output page displaying list of contents for each directory. How can I possibly achieve this please? hmm im having some trouble tackling this problem i have a database table with topicname then 3 columns with 3 pdfs in each one all the files are stored in a directory called topicfiles in the server so like 3 topicnames with 3 files in each one with this page i want to make i want to display each topic name with the files under it calling it from the server like Code: [Select] topic 1 file1.pdf file2.pdf file3.pdf topic 2 file4.pdf file5.pdf file6.pdf topic 3 file71.pdf file8.pdf file9.pdf i tried using dhandler to access all files in the folder and only managed to display all of the files in rows using foreach loop was thinkin of using mysql query to access the topic name and then each file for that topic but not sure hmmm |