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PHP - Session Times Out And Reborn After Refresh!!!
Similar TutorialsI've simply set some sessions.... $_SESSION['LoggedIn'] = 1; $_SESSION['UserID'] = $row["UserID"]; They don't seem to last very long, usually when I close my browser and go back on later, they'll expire. I want them to last permanently unless the user logs out. How do I do this? Thanks in advance. Hello, I am struggling here. Basically I have integrated a Google Maps API with a website to show the location of the next session. This script will take the next session and return its location, so the lat and long can be fetched from another table and fed into the API. Here is the timetable in a MySQL table: I am trying to do/say the following: * Show current session (if in progress) * Show next session. (Only to be fetched from db when the previous session has expired) * If there are no sessions left on today's date, show next session on next day with sessions. How could I write this as a PHP query in order to the fetch the location data? Thanks, George. I have a strange problem. When a guest visits my contact-user.php page, they get a message telling them the must login before viewing the page. After the guest logs in, they view the same page and it tells them they have to login again (keeps on looping). But if they manually refresh that page with the "you must be logged in" message, it recognizes the login and lets them in. How can I get this page to immediately recognize that the user is logged in and not require them to refresh the page manually? Here is my code for contact-user.php <?php session_start(); header("Cache-Control: private, max-age=10800, pre-check=10800"); header("Pragma: private"); header("Expires: " . date(DATE_RFC822,strtotime("+2 day"))); include("connection.php"); mysql_select_db("database"); if (isset($_SESSION['username'])) { ******** MY HTML PAGE CONTENT ******** } else { echo "<meta http-equiv='REFRESH' content='2;url=http://www.mysite.com/login.php'> <center><font color='#EE0000'><p>You must be logged in before negotiating. You will now be redirect to the login page.</p></font></center>"; } ?> Here is my code for login.php script: <?php include("connection.php"); mysql_select_db("database"); session_start(); if(isset($_POST['login'])){ $username = mysql_real_escape_string($_POST['username']); $password = mysql_real_escape_string($_POST['password']); $tUnixTime = time(); $sGMTMySqlString = gmdate("Y-m-d H:i:s", $tUnixTime); if (!$username || !$password) { print "Please fill out all fields."; exit; } $logres = mysql_num_rows(mysql_query("SELECT * FROM members WHERE username = '$username' and password = '$password'")); if ($logres <= 0) { print "Login failed. If you have not already, please signup. Otherwise, check your spelling and login again."; exit; } else { $_SESSION['username'] = $username; if (isset($_SESSION)) { echo'You are now logging in'; mysql_query("UPDATE members SET activity = '$sGMTMySqlString' WHERE username = '$username'"); } else { echo "You are not logged in!"; } echo'<html><head><meta http-equiv="REFRESH" content="1;url=http://www.mysite.com/members/' . $_SESSION['username'] . '/"></head><body></body></html>'; exit; } } ?> Hello all, I'm collecting date/time information via a form and would like to convert the info into something that I can stick in my MySql database (a timestamp???). I'm collecting the current month (variable name: month-- of the form "mm"), day (variable name: day -- of the form "dd"), year (variable name: year -- of the form "yyyy"), time of day (variable name: time -- of the form "h:00"), and before or after noon (variable name: ampm -- of the form "am" or "pm"). Any suggestions as to how to change this into a quantity that I can store as a value and then use to compare to other date/times would be appreciated. Thanks! Hi all, Thanks for reading. I'm running a script using jQuery that auto-refreshes a <div> on the index page from an external PHP script to get all the rows in a database and display them on the index page. The script works great - here it is as follows: Code: [Select] <script type="text/javascript"> $(document).ready(function() { $("#responsecontainer").fadeOut("fast").load("getrows.php").fadeIn("slow"); var refreshId = setInterval(function() { $("#responsecontainer").fadeOut("fast").load('getrows.php').fadeIn("slow"); }, 5000); $.ajaxSetup({ cache: false }); }); </script> The getrows.php script I'm working with looks like this: Code: [Select] <?php $rowsQuery = mysql_query("SELECT * FROM Happenings WHERE HappeningDate='$today'"); if (mysql_num_rows($rowsQuery) == 0) { $happeningsToday = "There are no happenings today."; } else { $allHappeningsToday = 1; while ($getHappeningsToday = mysql_fetch_array($rowsQuery)) { $happeningName = stripslashes($getHappeningsToday['HappeningName']); $happeningDate = $getHappeningsToday['HappeningDate']; $happeningDescription = $getHappeningsToday['HappeningDescription']; if ($allHappeningsToday == 1) { $happeningsToday .= " <div class=\"box\"> <p>".$happeningName." | ".$happeningDate." | ".$happeningDescription." </div>"; $allHappeningsToday = 2; } else { $happeningsToday .= " <div class=\"box\"> <p>".$happeningName." | ".$happeningDate." | ".$happeningDescription." </div>"; $allHappeningsToday = 1; } } } echo $happeningsToday; ?> This script works great as well. Currently, the auto-refresh jQuery script as you can see if getting and fading in/out all of the rows. Off of the above getrows.php script, is there a way after I could get only the newly created rows since the last refresh and only fade those in and out while leaving the others already loaded by the auto-refresh script to not fade in/out? Any ideas, thoughts or suggestions would be unbelievably helpful. Thank you very much. I am trying to create an index page which contains registration and login field the problem that i get is on successful login a warning is displayed session_start() [function.session-start]: Cannot send session cookie - headers already sent by (output started at C:\xampp\htdocs\Eventz.com\index.php:116) in C:\xampp\htdocs\Eventz.com\index.php on line 235 This is the login part of my index.php this tag is inside an html table below the login form I also have a registration form and its php code above the login form Code: [Select] <?php if (isset($_REQUEST['pass'])) { $id=$_POST['id']; $pass=$_POST['pass']; $conn =mysql_connect("localhost","root",""); if (!$conn) { die('Could not connect: ' . mysql_error()); } /* checking connection....success! */ $e=mysql_select_db('test', $conn); if(!$e) { die(''.mysql_error()); } else { echo 'database selected successfully'; } if (isset($_REQUEST['id']) || (isset($_REQUEST['pass']))) { if($_REQUEST['id'] == "" || $_REQUEST['pass']=="") { echo "login fields cannot be empty"; } else { $sql=mysql_query("Select email,password from login where email='$id' AND password='$pass'"); $count=mysql_num_rows($sql); if($count==1) /* $count checks if username and password are in same row */ { session_start(); $_SESSION['id']=$id; echo "</br>Login Successful</br>"; } else { echo "</br>invalid</br>"; echo "please try to login again</br>"; } } } } ?> Any help or suggestion would be appreciated in this page http://maximaart.com/newscp/ i have this problem Code: [Select] Warning: session_start() [function.session-start]: Cannot send session cache limiter - headers already sent (output started at /home/maximasy/public_html/newscp/index.php:1) in /home/maximasy/public_html/newscp/index.php on line 2 my source code is <?php session_start(); include_once("config.php"); include_once("functions.php"); $errorMessage = ''; if (isset($_POST['txtUserId']) && isset($_POST['txtPassword'])) { if ($_POST['txtUserId'] === "$user" && $_POST['txtPassword'] === "$pass") { // the user id and password match, $_SESSION['basic_is_logged_in'] = true; require("main.php"); exit;?> I am having trouble resolving an error. Warning: session_start() [function.session-start]: Cannot send session cache limiter - headers already sent (output started at /home/s519970/public_html/header.php:27) in /home/s519970/public_html/admin/login.php on line 2 What I can gather is I can't use "header (Location: 'admin.php')" after i've used session_start(). I have tried to replace the header (Location: 'admin.php') with this: echo "<script>document.location.href='admin.php'</script>"; echo "<script>'Content-type: application/octet-stream'</script>"; I've been trying to read up on solutions but haven't been able to get it sorted. If anyone can offer some advice that would be greatly appreciated as im new to php. Code: [Select] <?php session_start(); if(isset($_SESSION['user'])) echo "<script>document.location.href='admin.php'</script>"; echo "<script>'Content-type: application/octet-stream'</script>"; ?> <div id="loginform"> <form action="dologin.php" method="post"> <table> <tr> <td><span>Username:</span></td> <td><input type="text" name="username" /></td> </tr> <tr> <td><span>Password:</span></td> <td><input type="password" name="password" /></td> </tr> <tr> <td colspan="2" align="right"><input type="submit" name="login" value="Login" /></td> </tr> </table> </form> </div> I have tried using require_once('yourpage.php'); before my <head></head> tags in the header document where I've specified the html information but this doesn't seem to work. I've been advised to use ob_start("ob_gzhandler"); but I am not sure how to implement this. Any advice is greatly appreciated! I'm making a simple login system with MySQL and PHP (very simple, I'm just starting with PHP). The MySQL portion is done, but I need to ensure only people who are logged in can see certain content. To check if people are logged in, my website checks that they have the $_SESSION['user'] variable set. If it is set, then it lets them continue through the website, if not, it tells them to login. Is that enough security, or can people simply inject a session cookie into their browser to spoof that they are logged in? My idea was to generate a session key cookie when they login (just a random string of letters and numbers) and store that in the database, then on every page, check to make sure their session key is the same thing that's in the database. Is this necessary? It seems expensive. hi everyone. i'm wondering what the best way is to create a session variable and pass it to an iframe. i need to do something along these lines, but it doesn't seem to pass the ID. Any hints on how i should accomplish this? Code: [Select] session_start(); $_SESSION['ID']=$_GET['ID']; // id from previous page $ID=session_id(); <iframe src="iframepage.php?ID=<?php echo $ID; ?>" style="width:680px; height:200px;" noresize="noresize" frameborder="0" border="0" scrolling="Yes" allowtransparency="true" /> </iframe> Evening! I've been iffing and ahhing over this and well im not too sure, hence the post. Code: [Select] // Redirects if there is no session id selected and echos the error on the previous page if(!isset($_GET['get']) || ($_GET['getget'])){ header("Location: #.php?error"); } So it should simply check if get is set if it isnt then see if getget is set? If not redirect and show the error. Now ive tried it and even when get/getget is set it still redirects, probably something silly. Care to share anyone? Harry. Just curious how other people feel about this. I am working on an application where a lot of info is pulled from MySQL and needed on multiple pages.
Would it make more sense to...
1. Pull all data ONCE and store it in SESSION variables to use on other pages
2. Pull the data from the database on each new page that needs it
I assume the preferred method is #1, but maybe there is some downside to using SESSION variables "too much"?
Side question that's kind of related: As far as URLs, is it preferable to have data stored in them (i.e. domain.com/somepage.php?somedata=something&otherdata=thisdata) or use SESSION variables to store that data so the URLs can stay general/clean (i.e. domain.com/somepage.php)?
Both are probably loaded questions but any possible insight would be appreciated.
Thanks!
Greg
Edited by galvin, 04 November 2014 - 10:30 AM. I need help with a query.
I've got a table that stores references to calls that come in to our office. It has a datetime field, and for the purposes of the query, it's the only thing in this table that is important.
I've got another table that stores appointment information. The appointment start time is also a datetime field. For this query, this start time is the only thing in this table that is important.
I need to know how many times in the last year there was a day when we had at least 150 calls come in and made at least 1 appointment.
SELECT COUNT(*) FROM appointments a LEFT JOIN ( SELECT DATE(time) FROM calls WHERE <there are at least 150 calls on a day> ) c ON DATE(a.start_time) = c.time WHERE a.start_time >= CURDATE() - INTERVAL 1 YEARTo make things difficult, I guess the time would have to be converted to a day, because I'm looking for all days where there was an appointment, and the datetime field is too specific. I've been looking online for 30 mins or so, and was hoping somebody here could point me in the right direction. I'm not making much progress by myself. Edited by sKunKbad, 06 October 2014 - 01:17 PM. Hello friends, i'm getting error due to using an function for 3 times in same time if i've 3 results and i want to base36_encode the 3 output it only encode one and then gives me error Cannot redeclare base36_encode() (previously declared) here is the code // this is the encode function // function base36_encode($base10){ return base_convert($base10,10,36); } // i'm getting output here as 3 times (id) // $id = base36_encode($line[id]); echo "$id<br>"; the out but should be like this id1 id2 id3 all have been base36 encoded but it only show the 1st one id1 and the rest gives me the error above... so how can i make it works for all results not only the 1st one thanks everybody Hi all I am trying to edit a piece of code to change possible times for a booking system. This is the code I have: $count=0; for($b=$startTime;$b<$endTime;$b++){ if($count==$tempVar2){ $availability .= "</td><td align='left' valign='top'>"; } if(in_array($b,$reservedArray)){ $availability .= $b.":00 ".($b<12?"am":"pm")." - ".($b+1).":00 ".($b+1<12?"am":"pm")." - Booked.<br>"; } else { $availability .=$b.":00 ".($b<12?"am":"pm")." - ".($b+1).":15 ".($b+1<13?"am":"pm")."- <input type=\"checkbox\" value=\"".$b."\" name=\"time[]\" ><br>"; } $count++; } It gives me the following times: 09:00 am - 10:15 am 10:00 am - 11:15 am 11:00 am - 12:15 am 12:00 pm - 13:15 pm 13:00 pm - 14:15 pm 14:00 pm - 15:15 pm 15:00 pm - 16:15 pm 16:00 pm - 17:15 pm How can I change it so I can have the following times available: 10:00 am - 10:30 am 10:45 am - 11:15 am 11:30 am - 12:00 pm 12:15 pm - 12:30 pm etc... Many thanks for you help Pete. Hi everyone, I'm trying to add up the current time with a specified amount of seconds and insert it in a database afterwards. When I add say: 500 seconds to the current time it adds a whole lot more and I get a number few thousands higher than I want. Can anyone help me???. Gr Ryflex Hello All, I have tried to find a solution for this issue for days. The script was working fine until yesterday when all of a sudden I get this warning. Quote Warning: imagecreatefrompng(http://domain.com/images/broadcast1.png) [function.imagecreatefrompng]: failed to open stream: Connection timed out in /home/domain/public_html/logo/logo1.php on line 8 line 8 is: $image_1 = imagecreatefrompng($file_1); Where $file_1 = "http://domain.com/images/broadcast1.png"; The exact code is working perfectly fine in a different server I have, both servers are running Centos with PHP5 + GD fully enabled. The image http://domain.com/images/broadcast1.png (~5Kb) is loading very fast when open through a browser. Please please help me resolve this, I have tried many different things and even uninstall and install GD again but n luck. Thank you so much for your help. I have a string, and I have a variable $var = 5; $str = '<img src="img.jpg" />'; i want to display a $str (the image) $var amount of times (5). how can I do this? Hi guys, i got the following code i wrote which displays a small pop up on screen if the user has mail, and display a little icon. The problem is it displays a new icon for each new mail message. How can i make it so it only display 1 icon no matter how many unread mail the user has. Or even better if not too complicated display a number next too the image? Code: [Select] <? require'xxxxxxxxxxxxxxxxx.php'; mysql_select_db("membership") or die( "Unable to select database"); $sql=("SELECT * FROM user_alerts WHERE user_id = '".($_SESSION['user_id'])."'") or die (mysql_error()); if ($query=@mysql_query($sql)) { if (mysql_num_rows($query) > 0) { while ($req=mysql_fetch_array($query)) { if ($req['messageRead'] == 'NO') { ?> <div> <img src="xxxxxxxxxxxxxx.png" width="32" height="32" alt="unread mail" /> <a href="http://www.xxxxxxxxxxxx/account=account">You have Mail!</a> <div id="boxes"> <div style="top: 199.5px; left: 551.5px; display: none;" id="dialog" class="window"> <h2>You have new mail!</h2> <br /> <p>Visit your account page to read it.</p> <br> <a href="#" class="close">Close Window</a> </div> <!-- Mask to cover the whole screen --> <div style="width: 1478px; height: 602px; display: none; opacity: 0.8;" id="mask"></div> </div> </div> <? } } } } You can ignore most of the div stuff but that's pretty much it. It should check my database for any entries with the users session id in the column called 'user_id'. and only show the image if it then finds an entry with 'NO' in the 'messageRead' column. It currently shows the images for each entry it finds. Thanks for any help Hello, I am having a heck of a time trying to get time right on my website lol When a user logs in, they select what timezone they are in (UTC -1,-2,-3,-4,-5,-6....) Now this is great an all, but with daylight savings time my times are off by one hour in either direction. How do sites like this get times to work for users so easily? Thanks! weee |
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