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PHP - Clear Variable Php
Hi All,
I am developing PHP website. In my initial stage I wanted to accept some information from user... after that I wanted to display that information in different div but on same page... Lets say My page is having two div tags. First div for simple HTML form which will help user to enter data, second div to display info entered by user. I am doing this because I wanted to hide second div until user enter info into form and hit submit button. Its working fine when page load first time. second div is hidden, user add info and hit submit button then second div comes with info added by user. But when i refresh, its showing second div with previous info. As I am new to php and javascript I am not sure what to do.. Let me knw if some have any idea to solve this, Thanks in advance. Similar TutorialsFriends, suppose iam copying 1 to 100 files using a loop in php & when the copy process reach at 50th file my browser went offline. My doubt is will it copy all 100 files ?? OR it will terminate at 50th file ? if i want to get all files copied if the browser went offline then what i want to do ?? Please clear This topic has been moved to HTML Help. http://www.phpfreaks.com/forums/index.php?topic=356851.0 index.php <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en" > <head> <meta http-equiv="Content-type" content="text/html; charset=utf-8" /> <meta http-equiv="Content-language" content="en" /> <link type="text/css" rel="stylesheet" href="css/reset.css" /> <link type="text/css" rel="stylesheet" href="css/960.css" /> <link type="text/css" rel="stylesheet" href="css/custom.css" /> <title>BAY AREA REMOTE CONTROL SOCIETY</title> </head> <body> <div id="wrapper" class="container_12"> <div id="header" class="grid_12"> <div id="left-header" class="grid_5 alpha"></div> <div id="newsflash" class="grid_7 omega"><?php include('content/newsflash.php'); ?></div> </div> <div id="leftmenu" class="grid_3"><?php include('content/menu.php'); ?></div> <div id="maincontent" class="grid_9"><?php include('content/maincontent.php'); ?></div> <div id ="footer" class="grid_12"><?php include('content/footer.php'); ?></div> </div><!-- end wrapper --> </body> </html> menu.php <?php ?> <div class="content"> <ul id="menu"> <li><a href="index.php?page=testpage"><span>Home</span></a></li> <li><a href="index.php?page=about"><span>About us</span></a></li> <li><a href="index.php?page=schedule"><span>Schedule</span></a></li> <li><a href="index.php?page=media"><span>Media</span></a></li> <li><a href="index.php?page=products"><span>Products</span></a></li> <li><a href="index.php?page=misc"><span>Miscellaneous</span></a></li> </ul> </div> When I click HOME on the Menu program it works fine but it does not clear the content of maincontent.php. How do I do that? I was wondering if anyone knows a way where you can submit a form but content of the input fields will not be cleared? The reason why I want to achieve this effect is because I have a form and I want to user to be able to preview the results before properly submitting the form. Therefore I will have two submit buttons, one to preview and one to submit. Thanks for any help. Hi: I am using this code for my contact us feedback form: Code: [Select] <?php $error = NULL; $myDate = NULL; $FullName = NULL; $Address = NULL; $City = NULL; $State = NULL; $Zip = NULL; $Phone = NULL; $Email = NULL; $Website = NULL; $Comments = NULL; if(isset($_POST['submit'])) { $myDate = $_POST['myDate']; $FullName = $_POST['FullName']; $Address = $_POST['Address']; $City = $_POST['City']; $State = $_POST['State']; $Zip = $_POST['Zip']; $Phone = $_POST['Phone']; $Email = $_POST['Email']; $Website = $_POST['Website']; $Comments = $_POST['Comments']; if(empty($FullName)) { $error .= '-- Enter your Full Name. <br />'; } if(empty($Email)) { $error .= '-- Enter your Email. <br />'; } if($error == NULL) { $sql = sprintf("INSERT INTO myContactData(myDate,FullName,Address,City,State,Zip,Phone,Email,Website,Comments) VALUES ('%s','%s','%s','%s','%s','%s','%s','%s','%s','%s')", mysql_real_escape_string($myDate), mysql_real_escape_string($FullName), mysql_real_escape_string($Address), mysql_real_escape_string($City), mysql_real_escape_string($State), mysql_real_escape_string($Zip), mysql_real_escape_string($Phone), mysql_real_escape_string($Email), mysql_real_escape_string($Website), mysql_real_escape_string($Comments)); if(mysql_query($sql)) { $error .= 'Thank you for contacting us.'; mail( "d@direct.com", "Contact Request", "Date Sent: $myDate\n Full Name: $FullName\n Address: $Address\n City: $City\n State: $State\n Zip: $Zip\n Phone: $Phone\n Email: $Email\n Website: $Website\n Comments: $Comments\n", "From: $Email" ); } else { $error .= 'There was an error in our Database, please Try again!'; } } } echo '<span class="textError">' . $error . '</span>'; ?> <form name="myform" action="" method="post"> <input type="hidden" name="myDate" size="45" maxlength="50" value="<?php echo date("F j, Y"); ?>" /> <div id="tableFormDiv"> <fieldset><span class="floatLeftFormWidth"><span class="textErrorItalic">* - Required</span></span> <span class="floatFormLeft"> </span></fieldset> <fieldset><span class="floatLeftFormWidth"><span class="textErrorItalic">*</span> Full Name:</span> <span class="floatFormLeft"><input type="text" name="FullName" size="45" maxlength="50" value="<?php echo $FullName; ?>" /></span></fieldset> <fieldset><span class="floatLeftFormWidth">Address:</span> <span class="floatFormLeft"><input type="text" name="Address" size="45" maxlength="50" value="<?php echo $Address; ?>" /></span></fieldset> <fieldset><span class="floatLeftFormWidth">City:</span> <span class="floatFormLeft"><input type="text" name="City" size="45" maxlength="50" value="<?php echo $City; ?>" /></span></fieldset> <fieldset><span class="floatLeftFormWidth">State:</span> <span class="floatFormLeft"><input type="text" name="State" size="45" maxlength="50" value="<?php echo $State; ?>" /></span></fieldset> <fieldset><span class="floatLeftFormWidth">Zip:</span> <span class="floatFormLeft"><input type="text" name="Zip" size="45" maxlength="50" value="<?php echo $Zip; ?>" /></span></fieldset> <fieldset><span class="floatLeftFormWidth">Phone:</span> <span class="floatFormLeft"><input type="text" name="Phone" size="45" maxlength="50" value="<?php echo $Phone; ?>" /></span></fieldset> <fieldset><span class="floatLeftFormWidth"><span class="textErrorItalic">*</span> Email:</span> <span class="floatFormLeft"><input type="text" name="Email" size="45" maxlength="50" value="<?php echo $Email; ?>" /></span></fieldset> <fieldset><span class="floatLeftFormWidth">Website:</span> <span class="floatFormLeft"><input type="text" name="Website" size="45" maxlength="50" value="<?php echo $Website; ?>" /></span></fieldset> <fieldset><span class="floatLeftFormWidth">Comments:</span> <span class="floatFormLeft"><textarea name="Comments" cols="40" rows="10"><?php echo $Comments; ?></textarea></span></fieldset> </div> <input type="submit" name="submit" value="Submit" class="submitButton" /><br /> </form> I the only thing I can't figure out is, how do I clear the form fields AFTER the form has been submitted and the message "Thank you for contacting us." appears ?? I haven't been able to figure it out with JavaScript/PHP, so I posted my original code in hopes that someone will have an idea. Anyone? Thanks! What is the PROPER way to clear out an array? I have an array getting created as part of a loop process, and for each loop, I want the array to be emptied and start from scratch? I googled it and see some ways but the people offering the solutions don't seem too sure of themselves, so I just want to know if there is one, widely accepted and proper/efficient way to do this? Is there any way to have html output and then clear the output to allow for headers to be changed? This is still while the php file is executing. The reason I ask is that I am trying to output a progress bar of an excel file being created. So while the file is being created by php, I want to output to the browser a progress bar and then once it is complete, I need to set headers so that it downloads it as an excel file. Is this possible or does anyone else have any ideas? Should I maybe save the file on the web server temporarily and then redirect to the file afterwards? Any help would be appreciated. Thanks, -JC So I have a page that has profile images basically, but these images cache and when someone clicks on anything, like rotate image, since my script rotates the image and saves it correctly, I can hit Ctrl+F5 and the image then shows up correct, but the page loading itself after running my script using a get method and then using the header coming back to the same page the image looks like it wasn't reloaded. Noones gonna hit Ctrl+F5, so how do I get this to cache the image completely when the page reloads? I've tried <meta http-equiv="pragma" content="no-cache" /> But this doesn't work, well nothing seems to work really. Hi all, I have a table... id | Name | Downloads | 01 | tom | 5 02 | thomas | 2 03 | tommy | 15 I need a button in my page whcih on submit would resent the 'downloads' column so all values are set to 0, Is this possible and how if it is? Thanks for any advice I am trying to allow the user to update a variable he chooses by radio buttons, which they will then input text into a box, and submit, to change some attributes. I really need some help here. It works just fine until I add the second layer of variables on top of it, and I can't find the answer to this question anywhere. <?PHP require('connect.php'); ?> <form action ='' method='post'> <select name="id"> <?php $extract = mysql_query("SELECT * FROM cars"); while($row=mysql_fetch_assoc($extract)){ $id = $row['id']; $make= $row['make']; $model= $row['model']; $year= $row['year']; $color= $row['color']; echo "<option value=$id>$color $year $make $model</option> ";}?> </select> Which attribute would you like to change?<br /> <input type="radio" name="getchanged" value="make"/>Make<br /> <input type="radio" name="getchanged" value="model"/>Model<br /> <input type="radio" name="getchanged" value="year" />Year<br /> <input type="radio" name="getchanged" value="color" />Color<br /><br /> <br /><input type='text' value='' name='tochange'> <input type='submit' value='Change' name='submit'> </form> //This is where I need help... <?PHP if(isset($_POST['submit'])&&($_POST['tochange'])){ mysql_query(" UPDATE cars SET '$_POST[getchanged]'='$_POST[tochange]' where id = '$_POST[id]' ");}?> Hello all. I am very new to PHP, and I am not sure where to look or what I'm looking for in my current assignment. My task is to take in two numbers between 0-100. Once I take in that number, it should state beside it "The __ was accepted." The program should not accept any numbers greater than 100 or any characters. Once I do this, I must take a second number and do a similar thing. Finally, I must have a statement show up at the bottom stating which number is greater. Essentially, I need help in determining what I should use to place parameters, and how I can keep the program from echo ing any statement until input has been taken and tested for parameters. Any help you can provide will be greatly appreciated! In drive.php
public function insert($postBody, $optParams = array()) I have just re-installed Xampp and suddenly my sites are now displaying lots of: Notice: Use of undefined constant name - assumed 'name' in ... Notice: Use of undefined constant price - assumed 'price' in ... this is an example of the line its refering too: $defineProducts[1001] = array(name=>'This is a product', price=>123); My login script stores the user's login name as $_SESSION[ 'name'] on login. For some unapparent reason, i'm getting errors stating that $user and $priv are undefined variables, though I've attempted to define $user as being equal to $_SESSION['name'], using $user to look up the the user's privilege level (stored as the su column ) in the SQL table, and then where the result of the sql query is $priv which is then evaluated in an if statement. I can't seem to figure out why this might not be working. The code I'm using:
<?php
session_start();
function verify() {
//verify that the user is logged in via the login page. Session_start has already been called.
if (!isset($_SESSION['loggedin'])) {
header('Location: /index.html');
exit;
}
//if user is logged in, we then lookup necessary privleges. $_SESSION['name'] was written with the login name upon login. Privleges // are written in db as a single-digit integer of of 0 for users, 1 for administrators, and 2 for special users.
$user === $_SESSION['name'];
//Connect to Databse
$link = mysqli_connect("127.0.0.1", "database user", "password", "database");
if (!$link) {
echo "Error: Unable to connect to MySQL." . PHP_EOL;
echo "Debugging errno: " . mysqli_connect_errno() . PHP_EOL;
echo "Debugging error: " . mysqli_connect_error() . PHP_EOL;
exit;
}
//SQL Statement to lookup privlege information.
if ($result = mysqli_query($link, "SELECT su FROM accounts WHERE username = $user", MYSQLI_STORE_RESULT)) {
//LOOP TO CYCLE THROUGH SQL RESULTS AND STORE Privlege information as vairable $priv.
while ($row = $result->fetch_assoc()) {
$priv === $row["su"];
}
}
// close SQL connection.
mysqli_close($link);
// Verify privleges and take action. Only a privlege of "1" is allowed to view this page. A privlege of "2" indicates special
//accounts used in other scripts that have certain indermediate additional functions, but are not trusted administrators.
if ($priv !== 1) {
echo $_SESSION['name'];
echo "you have privlege level of $priv";
echo "<br>";
echo 'Your account does not have the privleges necessary to view this page';
exit;
}
}
verify();
?>
Hello everyone, I can get Test 2 to successfully operate the if statement using a variable variable. But when I try the same method using a session variable (Test 1) the if statement is not executed. Please could you tell me why the if statement in Test 1 is not being executed? Code: [Select] <?php # TEST 1 $_SESSION[test_variable] = "abcd"; $session_variable_name = "_SESSION[test_variable]"; if ($$session_variable_name == "abcd") { echo "<br>line 373, abcd<br>"; } # TEST 2 $test_variable = "efgh"; $test_variable_name = "test_variable"; if ($$test_variable_name == "efgh") { echo "<br>line 379, efgh<br>"; } ?> Many thanks, Stu I have a script that adds points together based upon the placing. This is the actual script: Code: [Select] <? $points = 0; if($place === '1st') {$points = $points + 50;} elseif($place === '2nd') {$points = $points + 45;} elseif($place === '3rd') {$points = $points + 40;} elseif($place === '4th') {$points = $points + 35;} elseif($place === '5th') {$points = $points + 30;} elseif($place === '6th') {$points = $points + 25;} elseif($place === '7th') {$points = $points + 20;} elseif($place === '8th') {$points = $points + 10;} elseif($place === '9th') {$points = $points + 10;} elseif($place === '10th') {$points = $points + 10;} elseif($place === 'CH') {$points = $points + 50;} elseif($place === 'RCH') {$points = $points + 40;} elseif($place === 'TT') {$points = $points + 30;} elseif($place === 'T5') {$points = $points + 30;} elseif($place === 'Champion') {$points = $points + 50;} elseif($place === 'Reserve Champion') {$points = $points + 40;} echo "Total HF Points: $points"; ?>What it *should* do (my friend's script works the same way and it works) it starts at points = 0, than if there is a first place, it adds 50, and so forth until it reaches the end. It is included into a file, in this area: Code: [Select] <div class="tabbertab"> <h2>Records</h2> <? $query92 = "SELECT * FROM THISTABLE WHERE VARIABLE='$id' OR VARIABLE = '$name' ORDER BY ABS(VARIABLE), VARIABLE"; $result92 = mysql_query($query92) or die (mysql_error()); echo "<table class='record'> <tr><th>Show</th> <th>Class</th> <th>Place</th></tr> "; while($row92 = mysql_fetch_array($result92)) { $class = $row92['class']; $place = $row92['place']; $entries = $row92['entries']; $race = $row92['show']; $purse = number_format($row92['purse'],2); echo "<tr><td>$race</td> <td>$class</td> <td>$place</td></tr>"; } ?> <tr><td colspan='3'><div align='right'><? include('includes/points.php'); ?></div></td></tr> </table> </div> This is the code that is relevant. When ended here, it echoes the last place that appears in the results (such as a 5th place echoing 30 points). When I move it to be included in the while loop, it shows Total Points: 50 Total Points: 25 Total Points: 10 (depending on the results displayed on that page). What am I doing wrong? I have a form that creates rows of data input textboxes depending on a user input number of things. I have a naming convention for all these textboxes that basically just keeps incrementing a number suffix for each row. All this is working fine. My problem is I need to get the data inserted into this table of textboxes into an array. Here's my code where I attempt to to this (it does not work): Code: [Select] $temp = $_SESSION['Num_Part']; $count = 1; while ($count <= $temp){ $temp2[$count] = "'Participant_P".$count."'"; //echo $temp2[$count]."<br/>"; $temp3[$count]=$_POST[$temp2[$count]]; //here's the problem $temp4[$count] = "'Result_P".$count."'"; $temp5[$count]=$_POST[$temp4[$count]]; //here's the problem //echo $temp4[$count]."<br/>"; $count++; } The problem is that the $_POST does not work with the variable in the argument position - even though the argument is formatted with single quotes. Can a variable be used in a POST argument and if so what is the correct syntax? If not, is there some other simple solution to harvest the data into an array. I understand I can harvest by explicitly accessing each key in the post assoc array. But this could be dozens of rows of input fields. Thanks in advance for your help here. I couldn't find anything online re this topic. Probably something simple but I have searched high and low and can't figure this one out. I have a variable that is of the datetime format. I have another variable that is of the time format. I need to add them together. Example: $var1 = 2012-02-24 06:38:22 $var2 = 02:00:00 $var3 = $var1 + $var2 = 2012-02-24 08:38:22 Thanks for the help! I have a function that get's a quick single item from a query:
function gimme($sql) {
global $mysqli;
global $mytable;
global $sid;
$query = "SELECT ".$sql." FROM ".$mytable." WHERE sid = ".$sid; $result = $mysqli->query($query);
$value = $result->fetch_array(MYSQLI_NUM);
$$sql = is_array($value) ? $value[0] : "";
return $$sql; // this is what I've tried so far
$result->close();
}
It works great as:
echo(gimme("name"));
Then I realized that I could use that as a variable ('$name' in this case) elsewhere. However, I can't figure out how get that new, variable variable 'outside' of the function. As such, echo($name); isn't working outside the function. Is there a way to return a variable variable? In other words, is there a way to make a function that creates a variable variable that will available outside of the function?
Thanks
Quote i need to store a variable from database like if i have "copies" in one of my column in my database then i have to store a particular value for copies store it to $copies here i want that i can store value of copies into $copies $update_book="update book set copies=copies-1 where bookid='$bookid'"; $result=mysql_query($update_book,$linkID1); if($result) { print "<html><body background=\"header.jpg\"> <p>book successfully subtracted from database</p></body></html>"; } else { print "<html><body background=\"header.jpg\"> <p>problem occured</p></body></html>"; } } |
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