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PHP - Sessions And Get Variables
Can someone tell me why this wont work... I just cant see it .
I ahve a Session valiable that contains info like (example) : $_SESSION[vars] ='a=1&b=2&c=3'; etc etc No matter how I format it the session varsiables will not pass as get variables when called this way if[isset](goback){ header("Location: myURL.php?$_SESSION[vars];exit; } <a href=phpself?gobak=1>goback</a> (Coding is for example only) Any help is greatly appreciated Cheers Similar TutorialsI have a search page that then submits to a php page that queries the database. I've been struggling to figure out how to paginate it, but I think I've narrowed down the problem. I didn't realize $_POST results didn't pass through when people clicked the pagination links at the bottom. I verified this by replacing the LIKE variable with a specific word and it worked. I'm trying to learn how to set up sessions, thinking this might solve my problem. Doesn't seem to be working. Can I get some suggestions on how to do this? What's happening now is that it's pulling a random 8 pages that have nothing to do with the original query. I start my entire page with: Code: [Select] <?php session_start(); $_SESSION['leafshape'] = $_post['select1']; $_SESSION['leafcolor'] = $_post['select2']; $_SESSION['leafvein'] = $_post['select3']; $_SESSION['leafmargin'] = $_post['select4']; $leafshape = $_SESSION['leafshape']; $leafcolor = $_SESSION['leafcolor']; $leafvein = $_SESSION['leafvein']; $leafmargin = $_SESSION['leafmargin']; and I'm setting up the queries like this: Code: [Select] $query = "SELECT COUNT(*) as num FROM descriptors JOIN plantae ON (descriptors.plant_id = plantae.plant_name) WHERE descriptors.leaf_shape LIKE '{$_SESSION['leafshape']}' AND descriptors.leaf_venation LIKE '{$_SESSION['leafvein']}' AND descriptors.leaf_margin LIKE '{$_SESSION['leafmargin']}'"; I also tried replacing the '{$_SESSION['leafshape']}' in the query with the assigned variable $leafshape does anyone know how to decode this XML variable value into string values? I also need to know the oposite way: creating variable values into xml. I've tried several code examples but they did filter the requested data. Code: [Select] $xml='<?xml version="1.0" encoding="utf-8"?> <elements> <text identifier="ed9cdd4c-ae8b-4ecb-bca7-e12a5153bc02"> <value/> </text> <textarea identifier="a77f06fc-1561-453c-a429-8dd05cdc29f5"> <value><![CDATA[<p style="text-align: justify;">Lorem ipsum dolor sit amet, consetetur sadipscing elitr, sed diam nonumy eirmod tempor invidunt ut labore et dolore magna aliquyam erat, sed diam voluptua. At vero eos et accusam et justo duo dolores et ea rebum. Stet clita kasd gubergren, no sea takimata sanctus est Lorem ipsum dolor sit amet.</p>]]></value> </textarea> <textarea identifier="1a85a7a6-2aba-4480-925b-6b97d311ee6c"> <value><![CDATA[<p style="text-align: justify;">Lorem ipsum dolor sit amet, consetetur sadipscing elitr, sed diam nonumy eirmod tempor invidunt ut labore et dolore magna aliquyam erat, sed diam voluptua. At vero eos et accusam et justo duo dolores et ea rebum. Stet clita kasd gubergren, no sea takimata sanctus est Lorem ipsum dolor sit amet.</p>]]></value> </textarea> <image identifier="ffcc1c50-8dbd-4115-b463-b43bdcd44a57"> <file><![CDATA[images/stories/red/cars/autobedrijf.png]]></file> <title/> <link/> <target/> <rel/> <lightbox_image/> <width><![CDATA[250]]></width> <height><![CDATA[187]]></height> </image> <text identifier="4339a108-f907-4661-9aab-d6f3f00e736e"> <value><![CDATA[Kramer 5]]></value> </text> <text identifier="ea0666d7-51e3-4e52-8617-25e3ad61f8b8"> <value><![CDATA[6000 RS]]></value> </text> <text identifier="90a18889-884b-4d53-a302-4e6e4595efa0"> <value><![CDATA[Eindhoven]]></value> </text> <text identifier="410d72e0-29b3-4a92-b7d7-f01e828b1586"> <value><![CDATA[APK Pick up and return]]></value> </text> <text identifier="45b86f23-e656-4a81-bb8f-84e5ea76f71f"> <value><![CDATA[15% korting op grote beurt]]></value> </text> <text identifier="3dbbe1c6-15d6-4375-9f2f-f0e7287e29f3"> <value><![CDATA[Gratis opslag zomerbanden]]></value> </text> <text identifier="2e878db0-605d-4d58-9806-8e75bced67a4"> <value><![CDATA[Gratis abonnement of grote beurt]]></value> </text> <text identifier="94e3e08f-e008-487b-9cbd-25d108a9705e"> <value/> </text> <text identifier="73e74b73-f509-4de7-91cf-e919d14bdb0b"> <value/> </text> <text identifier="b870164b-fe78-45b0-b840-8ebceb9b9cb6"> <value><![CDATA[040 123 45 67]]></value> </text> <text identifier="8a91aab2-7862-4a04-bd28-07f1ff4acce5"> <value/> </text> <email identifier="3f15b5e4-0dea-4114-a870-1106b85248de"> <value/> <text/> <subject/> <body/> </email> <link identifier="0b3d983e-b2fa-4728-afa0-a0b640fa34dc"> <value/> <text/> <target/> <custom_title/> <rel/> </link> <relateditems identifier="7056f1d2-5253-40b6-8efd-d289b10a8c69"/> <rating identifier="cf6dd846-5774-47aa-8ca7-c1623c06e130"> <votes><![CDATA[1]]></votes> <value><![CDATA[1.0000]]></value> </rating> <googlemaps identifier="160bd40a-3e0e-48de-b6cd-56cdcc9db892"> <location><![CDATA[50.895711,5.955427]]></location> </googlemaps> </elements>'; Basically I am trying to make a login with sessions but its just not working. Can someone look and see for any errors in what I wrote or snippet suggestions? <?php //Start session session_start(); //Include database connection details require_once('config.php'); //Array to store validation errors $errmsg_arr = array(); //Validation error flag $errflag = false; //Connect to mysql server $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD); if(!$link) { die('Failed to connect to server: ' . mysql_error()); } //Select database $db = mysql_select_db(DB_DATABASE); if(!$db) { die("Unable to select database"); } //Function to sanitize values received from the form. Prevents SQL injection function clean($str) { $str = @trim($str); if(get_magic_quotes_gpc()) { $str = stripslashes($str); } return mysql_real_escape_string($str); } //Sanitize the POST values $username = clean($_POST['username']); $password = clean($_POST['password']); //Input Validations if($username == '') { $errmsg_arr[] = 'Username missing'; $errflag = true; } if($password == '') { $errmsg_arr[] = 'Password missing'; $errflag = true; } //If there are input validations, redirect back to the login form if($errflag) { $_SESSION['ERRMSG_ARR'] = $errmsg_arr; session_write_close(); header("location: login.php"); exit(); } //Create query $qry="SELECT * FROM users WHERE AND username='$username' AND password='$password'"; $result=mysql_query($qry); //Check whether the query was successful or not if($result) { if(mysql_num_rows($result) == 1) { //Login Successful session_regenerate_id(); $member = mysql_fetch_assoc($result); $_SESSION['SESS_MEMBER_ID'] = $member['member_id']; $_SESSION['SESS_USERNAME'] = $member['username']; $_SESSION['SESS_EMAIL'] = $member['email']; $_SESSION['SESS_BETAKEY'] = $member['betakey']; $_SESSION['SESS_PIN'] = $member['pin']; session_write_close(); header("location: member-index.php"); exit(); }else { //Login failed $errmsg_arr[] = 'Username/Password Invalid'; $_SESSION['ERRMSG_ARR'] = $errmsg_arr; session_write_close(); header("location: login.php"); exit(); } }else { die("Query failed"); } ?> Hi, I have an admin area to update users detials etc.. I want this area to be secure so only admins can access it, Currently anyone and everyone can access the page. Code: [Select] <?PHP session_start(); /* really need to use a session variable to insure authorized to be here */ include ('db.php'); /* ======================================== 99% of the time it is better to put your query in a string. It makes debugging much easier ======================================== */ $query = "SELECT * FROM companies"; $result = mysql_query($query ) or die("SELECT Error: ".mysql_error()); $num_rows = mysql_num_rows($result); /* ======================================== I find it easier to locate problems if I indent code properly and drop out of PHP if there are large sections of html ======================================== */ ?> <br><br><br>There are <?PHP echo $num_rows; ?> removalspace users so far.<P> <table width="819" height="114"> <tr> <th>Company Name</th> <th>Contact Name</th> <th>Contact Number</th> <th>Email</th> <th>Address Line 1</th> <th>Address Line 2</th> <th>Location</th> <th>Postcode</th> <th>Basic Members</th> <th>Upgraded Users</th> <th>Company Logo</th> <th>Approved</th> </tr> <tr> <td colspan="6"></td> </tr> <?PHP while ( $row = mysql_fetch_array($result, MYSQL_ASSOC )) { ?> <tr> <td><?PHP echo $row['company_name']; ?></td> <td><?PHP echo $row['contact_name']; ?></td> <td><?PHP echo $row['phone']; ?></td> <td><?PHP echo $row['email']; ?></td> <td><?PHP echo $row['street1']; ?></td> <td><?PHP echo $row['street2']; ?></td> <td><?PHP echo $row['location']; ?></td> <td><?PHP echo $row['postcode']; ?></td> <td><?PHP echo $row['basicpackage_description']; ?></td> <td><?PHP echo $row['premiumuser_description']; ?></td> <?PHP /* ======================================== I presume you want to show the thumb version here ======================================== */ ?> <td><img src="images/thumbs/<?PHP echo $row['upload']; ?>" alt="logo"/></td> </tr> <tr> <td colspan="10"> <table> <tr> <td>Current level = <?PHP echo $row['approved']; ?></td> <td><a href="admin02.php?id=<?PHP echo $row['id']; ?>&level=1">Level 1 - Free</a></td> <td><a href="admin02.php?id=<?PHP echo $row['id']; ?>&level=2">Level 2 - Basic</a></td> <td><a href="admin02.php?id=<?PHP echo $row['id']; ?>&level=3">Level 3 - Premium</a></td> <td><a href="admin02.php?id=<?PHP echo $row['id']; ?>&level=0">Level 0 - Do Not Display</a></td> </tr> </table> </tr> <?PHP } echo "</table>"; ?></table> i know it's something like: <?php session_start(); if(isset($_SESSION " but dont know how to finish it correctly? " ?> hi im new to php i am making shopping cart i made a session variable to add products in cart when i run it gives this warning Notice: Undefined index: cart in C:\wamp\www\cart\public\views\layouts\shop.php on line 15 Notice: Undefined index: total_items in C:\wamp\www\cart\public\views\layouts\shop.php on line 16 Notice: Undefined index: total_price in C:\wamp\www\cart\public\views\layouts\shop.php on line 17 but when i click on add to cart it add product price and quanitity kindly help me my shop.php code is <head> <title> Shopping Cart</title> <link href="stylesheets/cool_style.css" media="screen" rel="Stylesheet" type="text/css" /> </head> <body> <h1> products</h1> <div class="cart"> <p><b> Shopping Cart</b></p> print_r($_SESSION['cart']); echo $_SESSION['total_items']; echo number_format($_SESSION['total_price'],2); </div> <hr /> </body> </html> and my index file is where i set session variables are include('db_fns.php'); include("cart_functions.php"); session_start(); if(isset($_SEESION['cart'])) // if change this conditon if(!isset($_SEESION['cart'])) it gives not warning but does not //add products to the cart it does not do anything { $_SESSION['cart']=array(); $_SESSION['total_items']=0; $_SESSION['total_price']=0.00; } $view=empty($_GET['view'])?'index':$_GET['view']; $controller='shop'; switch ($view){ case "index"; $products = find_product(); break; case "add_to_cart"; $id=$_GET['id']; $add_item=add_to_cart($id); $_SESSION['total_items']=total_items($_SESSION['cart']); $_SESSION['total_price']=total_price($_SESSION['cart']); header('Location: index.php'); break; case "update_cart"; break; case "checkout"; break; } if change this conditon if(!isset($_SEESION['cart'])) it gives not warning file run correctly with no warning but does not add products to the cart and does not do anything kindly help me please I haven't used sessions much until now, so this is probably due to my ignorance. I have a page that sets the session variable, and if I print from that page, the session variable (an array) is correct. But when I move to the next page, the same session variable has old, old, wrong data. The $arrAttendeeList is an exploded list from a textarea on a form turned into an array. Example: This page, let's call it page1.php, sets the variable: Code: [Select] <?php $_SESSION['arrAttendeeList'] = $arrAttendeeList; foreach ($_SESSION['arrAttendeeList'] as $temp) { print "$temp <br />"; } exit; ?> Results: Smithers, Waylon Bouvier, Selma Brockman, Kent But the next page, page2.php, when I call the same variable: Code: [Select] <?php foreach ($_SESSION['arrAttendeeList'] as $temp) { print "<br />$temp <br>"; } ?> I get yesterday's data: Smithers, Waylon Bouvier, Selma I've tried setting the session var to null but with the same results. Do I need to kill the session var before setting it to something else? Thanks - So I'm trying to understand Sessions and how to store a variable within a session. What I want to t do, is start a session, check if variable is set, if not, set the variable. So with the code below, I start the session, i check the variable, if not set, i set it. But when i refrsh the page, it has the same session id but it didn't store the session variable from the previous load. Please, what am I missing? Code: [Select] <?php session_start(); echo "Session ID: ".session_id()."<br>"; echo "<br>chktrack P ".$_session['chktrack'].""; if ($_session['chktrack'] != 1){ $_session['chktrack']=1; } echo "<br>chktrack Post: ".$_session['chktrack'].""; echo "<br><a href='index.php'>Index</a>"; ?> Thanks in advance for your help. Hi Something strange is happening and I can't understand it. A user can access an availability page of accommodation and book ita room, this works fine, and goes from availability to the booking form and back quite well, carrying the room id of the accommdation and room/s selected in a session. If they close the browser down and open the availability page again all the rooms are there as before, but when they select a room and go to the booking form the session of the room id and the rooms selected are empty. If I do a session destroy and open the browser up again everything works fine again. I have tried this in Chrome and Firefox and it seems to work fine Any help would be appreciated I am new to SESSIONS and have a quick question about them. I want to use sesssions on my site but was wondering if they would work for the follow senario. Say a customer visits my url: http://www.mysite.com/?id=2 Now what i am doing is taking the id out of the URL using sessions and redirecting the user to http://www.mysite.com while my session ($_SESSION['id']) holds the value 2 in it. I have this working great, i believe it just looks better. Now if my customer decides to buy my product via paypal and is directed off my site while he/she is paying for said item on paypal when they return could i still use some of the information that i stored in my session?? I know i could use post and get to pass through paypal but unfortunately i have to use sessions for what i am trying to do. I have this (display_items.php) script which should not be accessed directly . user will be directed to a login page, the login checked by a check_login.php file then successful authentication will direct the user to the display_items.php page. it works perfectly on windows server but not on linux. the display_items.php script can be accessed directly on the linux server. It may have something to do with sessions but i cannot pin point the issue at the moment . i have attaced the php script files. Grateful if someone could point me in the right direction
check_login.txt display_items.txt login.txt I am trying to create a blog and visitor log, where I should be able to log in as admin and add the item and see the visitor log. I want a password protected administration section and I want to use sessions on the administration section. When I for example click on add post, I want it to log in and go to page addpost.php where I can enter my text. This is what I've done so far. I would like to know what I have done wrong and how I should do to accomplish what I have mentioned above. <?php session_start(); if(isset($_POST['btnLogin']) || isset($_POST['addpost'])){ $txtUserId = $_REQUEST['txtUserId']; $txtPassword = $_REQUEST['txtPassword']; if (isset($_POST['txtUserId']) && isset($_POST['txtPassword'])) { if ($_POST['txtUserId'] === 'admin' && $_POST['txtPassword'] === 'abc123') { //$_SESSION['basic_is_logged_in'] = true; echo "you are logged in"; } elseif (empty($txtUserId) || empty($txtPassword)) { echo "fill in username and password"; } elseif ($_POST['txtUserId'] != 'admin'){ echo "wrong username"; } elseif ($_POST['txtPassword'] != 'abc123'){ echo "wrong password"; } } } ?> <?php //if (!isset($_SESSION['basic_is_logged_in']) // || $_SESSION['basic_is_logged_in'] !== true) ?> <html> <head> <title>Main User Page</title> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1"> </head> <body> <form method="post" name="frmLogin" id="frmLogin" action="main.php"> <table width="400" border="1" align="center" cellpadding="2" cellspacing="2"> <tr> <td width="150">User Id</td> <td><input name="txtUserId" type="text" id="txtUserId"></td> </tr> <tr> <td width="150">Password</td> <td><input name="txtPassword" type="password" id="txtPassword"></td> </tr> <tr> <td><input type="submit" name="btnLogin" value="Login"></td> </tr> <tr> <td><input type="submit" name="addpost" value="add post" /></td> </tr> <tr> <td><input type="submit" name="showstat" value="Show visitors log" /></td> </tr> <tr> <td><input type="submit" name="blogg" value="To blog (logout)" /></td> </tr> </table> </form> </body> </html> I have a simple php script that starts sessions. On every page, I include : if(isset($_SESSION['sessionname'])){ //The rest of the page } else { die("Not logged in"); } I always include the session start and always regenerate the session id after <?php. The code works fine withevery browser except for a certain version of Internet Explorer 8. Even though the browser does enable cookies, it doesn`t seem to allow the ones in my script. In fact, every time I change page, it ives the error message "Not logged in". I have tried it on two different compters with the exact same version of IE and the result was the same. Thank you for your time! i have an upload form and a posting form on the same page. when you upload a file it is uploaded to the server. what i am then trying to do is add the name of the file to $_SESSION['attachment'] so i can use it later. When the user posts their form i want the session to be inserted into the database but the session always comes up empty. this is what happens when they upload their file Setting the session and moving the file: session_start(); $_SESSION['attachment'] = "EXAMPLE"; move_uploaded_file($_FILES['Filedata']['tmp_name'], "../attachments/" . time() . $_FILES['Filedata']['name']); and then when they submit their form(textarea) it uploads the contents to the database and the contents of the session aswell. Why is this session always empty? Hi all, What is the best practice when using Sessions for guest users? hey i think i may have stored session variables incorrectly Code: [Select] $_SESSION['tel'] = $_GET['Lat']; $_SESSION['Lon'] = $_GET['Lon']; $_SESSION['Lat'] = $_GET['Lat']; is what i used to set the session variables with the data i then enter these into a table and they enter the correct information but two pages down the line i try to access them however i just get undefined variable when i set the variable is equal to the session. Code: [Select] $MyLon = $_SESSION['Lon']; $MyLat = $_SESSION['Lat']; the following is the errorr Quote Notice: Undefined index: Lat in Kind of a n00b here. on my main table (users) i named a column as "id", set it to auto-increment and as the primary key and created it like this: CREATE TABLE `users` ( `id` int(20) NOT NULL auto_increment, `full_name` varchar(200) collate latin1_general_ci NOT NULL default '', `user_name` varchar(200) collate latin1_general_ci NOT NULL default '', `user_pwd` varchar(200) collate latin1_general_ci NOT NULL default '', `user_email` varchar(200) collate latin1_general_ci NOT NULL default '', `activation_code` int(10) NOT NULL default '0', `joined` date NOT NULL default '0000-00-00', `country` varchar(100) collate latin1_general_ci NOT NULL default '', `user_activated` int(1) NOT NULL default '0', PRIMARY KEY (`id`) ) On the second table i created it like this: CREATE TABLE about_me ( about_id int NOT NULL, nick_name varchar(255), descript varchar(255), aim varchar(255), cell varchar(255), school varchar(255), music varchar(255), aspire varchar(255), City varchar(255), id int, PRIMARY KEY (about_id), FOREIGN KEY (id) REFERENCES users(id) ) I believe i imported the key correctly into my new table (about_me). Well I expected the id column to cascade down into this new table automatically which it didn't. RIght now if you log into my site and use the about me form, it posts to the new table "about_me" but it doesn't identify the user on the table with the primary key assigned to him from the first table (users). How do I use PHP sessions to identify the user by his/her id from the primary key in the table. I attached the whole site. The php for the log in is a prefab and I'm attempting to do the about me part on my own, I'm having alot of trouble with the whole sessions thing. I'm not really sure if I'm doing this correctly. so yeah any point in the right direction would be awesome! -Mike hey on my page a list of people get listed by a category u choose if u choose a category and click ok, u are sent to the same page, and i get the category with POST if(isset ($_POST['type'])) { $gameholder = $_POST['game']; $typeholder = $_POST['type']; } this works ... the list of people is 30 members / page when u click on page 2, the post doesnt work anymore, and i get errors, logic ... now i want to get around this with making a session emediatly when the vars get out of POST if(isset ($_POST['type'])) { $gameholder = $_POST['game']; $typeholder = $_POST['type']; $_session['gameholder'] = $gameholder; $_session['typeholder'] = $typeholder; print $_session['gameholder']; } this also works now i want when people click on page 2, the needed vars will come out of the Sessions, and not out of POST so i did this if(!isset ($_POST['type'])) { $gameholder = $_session['gameholder']; $typeholder = $_session['typeholder']; } but this is not working theres nothing in $gameholder also when i move the print session out of the if, it should show when someone clicks page 2 but its not ... any suggestions on this? thanks! So I am trying to set my session length, but it doesn't seem to be working. session_set_cookie_params("84600"); session_start(); Im makigna simple login system for a sight but i only want them to have to login if they want to go to the shopping cart i have t implement a session_start() on every page before the cart page so the home page products page etc etc and then on the cart page ive a simple function that checks if their logged in if not then it will direct them to the login page if they are they should just continue is this the correct way to do it ? thanx Hi, is two people or more sitting on the same local network and sharing the same public ip address will have the same session if they browse all of them into the same website or same php script that create session ?
Edited by Issam, 16 November 2014 - 05:18 PM. |
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