PHP - Curl Dynamic Url Get Variable
hi guys I just could not find the answer on forum. I have a url like this http://www.example.com/deal.php?id=367 and my question is : how can i use curl function to get the html and the id value which is 367
thanks Similar TutorialsHi I can get this to work can you point me in the right direction curl_setopt( $ch, CURLOPT_URL, "http://website.com/action=%22getcontent%22%20shipid=%22\"$content\"%22%20/%3E%3C/request%3E"); I want to include the variable $content in the url thanks Hi dear community i want to run a Curl to get the contents of a remote web page into a PHP variable <?php // // The PHP curl module supports the received page to be returned in a variable // if told. // $ch = curl_init(); curl_setopt($ch, CURLOPT_URL,"http://www.myurl.com/"); curl_setopt($ch, CURLOPT_RETURNTRANSFER,1); $result=curl_exec ($ch); curl_close ($ch); ?> I declare this variable:($ch) Well - can i work with this variable - eg. to parse this with a parser!? look forward to hear from you $result=curl_exec ($ch); gretings I'm a new PHP users needing some help. I've got two code snippets that run a CURL post to a syslog server grabbing specific records that I then parse with regex. Both are similar differing in the specific CURL URL and Regex. One works does not. The failing program seems to fail the regex parse creating a null array. What I've done thus far. Tested the regex on regex101 (works fine, using PCRE). Dumped and echoed the CURL created variable and then rechecked against regex101. ( again all good) Created a static variable in the code of the CURL return string (regex works fine). So the CURL is working, the variable string is working appearing as expected and the regex works. But the variable feels like's it null when passed directly from the CURL to the regex. No error logs, but this is where I'm stuck I don't know what to pick at next. Here's a version of the code. Appreciate any thoughts. <?php
$str = curl_exec($ch); // curl steps ends
//$str = '_bkt _cd _indextime _kv _raw _serial _si _sourcetype _time dhcp_type host index linecount source sourcetype splunk_server Configuration initialization for /opt/splunk/etc took 17ms when dispatching a search (search ID: 1591198882.902292) Your search was restricted by ( ( index=nat OR index=network OR index=radius ) OR ( source=/data/syslog/security/ipblocker ) ) base lispy: [ AND 66 82 8a 9c dhcpack e4 f8 sourcetype::infoblox:dhcp [ OR index::nat index::network index::radius source::/data/syslog/security/ipblocker ] ] search context: user="testuser", app="search", bs-pathname="/opt/splunk/etc" Your timerange was substituted based on your search string network~978~07708B5A-37B1-4315-8EFA-70B96D12856C 978:118251396 1591198398 1 Jun 3 11:33:15 128.230.100.36 dhcpd[21353]: DHCPACK on 10.1.0.19 to e4:f8:9c:82:66:8a (ITS-NDD-BOA-T01) via bond0 relay bond0 lease-duration 7200 0 its-splunk-idx2.syr.edu network infoblox:dhcp 2020-06-03 11:33:15.000 EDT DHCPACK 128.230.100.36 network 1 /data/syslog/network/dhcp infoblox:dhcp its-splunk-idx2.syr.edu'; when I send a post variable to another page for processing using cURL and then I echo the variable I am getting extra slashes and periods this is where I set the fields to send. Code: [Select] curl_setopt($ch, CURLOPT_POSTFIELDS,"name='. $name .'&email='. $email .'&serial='. $serialnumber .'"); this is what happens when I echo $serial on the processing page. Code: [Select] \'. SLNM7IV6ZM98YJRXO8D5 .\' it should look like Code: [Select] SLNM7IV6ZM98YJRXO8D5 Hi ! I'd like to count all occurences in "$thiscodestring" into a "dynamic?" array and print it out after the end of the loop, how do I assign the variablenames dynamically ? $query = "SELECT codes, status FROM table"; while ($row = mysql_fetch_assoc($result)) { $thiscodestring = $row[codes]; // looks like "a1 c2 d3 10 15 1 a1 a1"; $singlecodes = explode(" ", $thiscodestring); foreach($singlecodes as $thiscode) { $$thiscode[count] = $$thiscode[count] + 1; } } After all Mysql-Stuff is done I'd like to print out the counted codes, for example the code "a1" was found 100 times in all querys then $$a1[count] should be 100, c2 was found 15 times, then $$c2[count] should be 15 and so on. Question: How do I tell php to assign a "dynamic" variable with the name of the found string which was exploded (in this example a1, c2, d3... ) before ?! $$ does not seem to work. And how can I then print_r() the value if I dont know the name ? Thanks ! I have a form that inserts information into a mysql, the only prolem is I need to add different surrounding html to the information when entering it into the database depending what the value is...(essentially I want to store font color around different levels) How would I define the same variable with different information depending on the value? The information is called using: if ($_SERVER['REQUEST_METHOD'] == 'POST') { $editLEVEL=$_POST['level']; I want it so if 'Level1' is the posted value then $editLEVEL would be '<color=1>$editLEVEL</color>' but if 'Level2' is the posted value the $editLEVEL would be '<color=2>$editLEVEL</color>' If you dont understand just let me know I'll try explain best I can. <?php $foo = 5; $too = 7; ${"foo"}++; ${"too"}++; echo $foo; echo '<br />' . $too; $my_var_name = "foo"; ${$my_var_name}++; echo $foo; ?> I understand the part that $my_var_name is going to increment $foo. But I don't understand that when we used ${"foo"} we did not add the $ sign with it. But when we use ${$my_var_name} we have to add another $ sign. why is that? OK, what I am trying to do is generate a dynamic variable name. I want to setup a foreach statement that will generate variable names based on an array of data. $numbers = array('one', 'two', 'three', 'four', 'five', 'six', 'seven'); foreach ($numbers as $number) { } What I need, is for a bunch of variables to be generated and filled with content. $variable_one_label = "Blah"; $variable_two_label = "Blah Again"; How can I generate the dynamic variable based on the array value? Hello. I want to create some variables dynamically. I have this so far: for($i = 1; $i <= 4 ; $i++){ $a = 'member' . $i; $$a = array(); } Does that give me this 4 arrays?: $member1, $member2, $member3 and $member4? Of course I want some process inside of the loop, but that would depend on the variables. Would that work? thanks! Hi I'm trying the following code: Code: [Select] $t = '12<-- AB_C -->'; $AB_C = 'abc'; echo preg_replace('/\<-- ([A-Z_]+) --\>/', "$$1", $t);I want to get "12abc" , but it outputs: 12$AB_C , so, it not recognize the replacement as dynamic variable. Is it any way to use the matched word in preg_replace() as a variable, or dynamic variable? Hello, I'm working on a dynamic text form (I guess thats what its called). Basically, I have a html page that echos in some PHP code. What the PHP code does is show different strings of text depending on a variable: Code: [Select] <PHP? $brief1_info = "brief info goes here"; $brief1 = 0; if (isset($_POST['brief1Go'])) { $brief1 = $brief1 + 1; } else if (isset($_POST['brief1Back'])) { $brief1 = $brief1 - 1; } $breif1Controller = " <form action=\"".$_SERVER['PHP_SELF']."\" method=\"post\"> <input type=\"submit\" name=\"brief1Back\" id=\"brief1Back\" value=\"BACK\" /> </form> <form action=\"".$_SERVER['PHP_SELF']."\" method=\"post\"> <input type=\"submit\" name=\"brief1Go\" id=\"brief1Go\" value=\"CONTINUE\" /> </form>"; if($brief1 == 0){ $brief1_info = "<b>Welcome Commander,</b> you are currently viewing the Mission Control Brief page, here you can view all your missions that you need to complete in order to advance through your prestiges. You will need to follow your briefs carefully in order to succeed. <br /><br /> "; } else if($brief1 == 1){ $brief1_info = "Okay, let me show you around the place ..."; } else if($brief1 == 2){ $brief1_info = "brief is on 2"; } ?> The problem is, the BACK and CONTINUE buttons don't work. If $brief1 equals 0, and the user presses continue, the is should go to 1, and the brief1_info string is changed (so some different text shows in my html). It actually works when brief1 is on '0', but when its on 1 and the user pressed continue, the brief1 is changed to 1, but because the submit button refreshes the page, the variable is re-read again, and thus is reset back to 0. Is there a way around this? Or is there a better method than what I'm doing? Thanks Hi all, here's my code: Code: [Select] <?php foreach ($_SESSION['topping'] as $value) { echo "<tr><td width='30%'>Topping</td><td width='50%'>$value</td><td width='20%'><select name='notopping'>"; foreach ($_SESSION['cupcake'] as $number) { '<option name="notoppings[]" value="'.$number.'">".$number."</option>'; } echo "</select></td></tr>"; } ?> $_SESSION['cupcake'] is a value from either 6, 12, 24 or 36. What I want to do is put them into a drop down box (second foreach) as the value and the displayed value - counting up from 1 (so 1,2,3,4,5,6 or up to 12,24 etc). Also by creating this as an array, does this mean than for each topping (say Vanilla and Chocolate) the value dynamically created can be used on the next page by using $_POST['notoppings'] to display each type (two different numbers - one for Vanilla and one for Chocolate). Does that make sense? Thanks! Jason good day dear community, i am workin on a Curl loop to fetch multiple pages: i have some examples - and a question: Example: If we want to get information from 3 sites with CURL we can do it like so: $list[1] = "http://www.example1.com"; $list[2] = "ftp://example.com"; $list[3] = "http://www.example2.com"; After creating the list of links we should initialize the cURL multi handle and adding the cURL handles. $curlHandle = curl_multi_init(); for ($i = 1;$i <= 3; $i++) $curl[$i] = addHandle($curlHandle,$list[$i]); Now we should execute the cURL multi handle retrive the content from the sub handles that we added to the cURL multi handle. ExecHandle($curlHandle); for ($i = 1;$i <= 3; $i++) { $text[$i] = curl_multi_getcontent ($curl[$i]); echo $text[$i]; } In the end we should release the handles from the cURL multi handle by calling curl_multi_remove_handle and close the cURL multi handle! If we want to another Fetch of sites with cURL-Multi - since this is the most pretty way to do it! Well I am not sure bout the string concatenation. How to do it - Note I want to fetch several hundred pages: see the some details for this target-server sites - /(I have to create a loop over several hundred sites). * siteone.example/?show_subsite=9009 * siteone.example/?show_subsite=9742 * siteone.example/?show_subsite=9871 .... and so on and so forth Question: How to appy this loop into the array of the curl-multi? <?php /************************************\ * Multi interface in PHP with curl * * Requires PHP 5.0, Apache 2.0 and * * Curl * ************************************* * Writen By Cyborg 19671897 * * Bugfixed by Jeremy Ellman * \***********************************/ $urls = array( "siteone", "sitetwo", "sitethree" ); $mh = curl_multi_init(); foreach ($urls as $i => $url) { $conn[$i]=curl_init($url); curl_setopt($conn[$i],CURLOPT_RETURNTRANSFER,1);//return data as string curl_setopt($conn[$i],CURLOPT_FOLLOWLOCATION,1);//follow redirects curl_setopt($conn[$i],CURLOPT_MAXREDIRS,2);//maximum redirects curl_setopt($conn[$i],CURLOPT_CONNECTTIMEOUT,10);//timeout curl_multi_add_handle ($mh,$conn[$i]); } do { $n=curl_multi_exec($mh,$active); } while ($active); foreach ($urls as $i => $url) { $res[$i]=curl_multi_getcontent($conn[$i]); curl_multi_remove_handle($mh,$conn[$i]); curl_close($conn[$i]); } curl_multi_close($mh); print_r($res); ?> I look forward to your ideas. Folks, I need help (Php code ) to generate a Dynamic Text on a Base Image. What i want to do is, to make this Image as header on my Site and to make this Header Specific to a Site, i want to Add the Domain Name on the Lower Left of the Image. Got the Idea? Here is the Image link: Quote http://img27.imageshack.us/i/shoppingheader1.jpg/ PHP Variable that holds the Domain name is: $domain All i need the Dynamic PHP Codes that i can put on all my sites to generate this Text on Image (Header) Dynamically... May Anyone Help me with this Please? Cheers Natasha T. Hi all I need to combine these two scripts: Firstly, the following decides which out of the following list is selected based on its value in the mySQL table: <select name="pack_choice"> <option value="Meters / Pack"<?php echo (($result['pack_choice']=="Meters / Pack") ? ' selected="selected"':'') ?>>Meters / Pack (m2)</option> <option value="m3"<?php echo (($result['pack_choice']=="m3") ? ' selected="selected"':'') ?>>Meters / Pack (m3)</option> <option value="Quantity"<?php echo (($result['pack_choice']=="Quantity") ? ' selected="selected"':'') ?>>Quantity</option> </select> Although this works OK, I need it also to show dynamic values like this: select name="category"> <?php $listCategories=mysql_query("SELECT * FROM `product_categories` ORDER BY id ASC"); while($categoryReturned=mysql_fetch_array($listCategories)) { echo "<option value=\"".$categoryReturned['name']."\">".$categoryReturned['name']."</option>"; } ?> </select> I'm not sure if this is possible? Many thanks for your help. Pete Hello all. I am very new to PHP, and I am not sure where to look or what I'm looking for in my current assignment. My task is to take in two numbers between 0-100. Once I take in that number, it should state beside it "The __ was accepted." The program should not accept any numbers greater than 100 or any characters. Once I do this, I must take a second number and do a similar thing. Finally, I must have a statement show up at the bottom stating which number is greater. Essentially, I need help in determining what I should use to place parameters, and how I can keep the program from echo ing any statement until input has been taken and tested for parameters. Any help you can provide will be greatly appreciated! I am trying to allow the user to update a variable he chooses by radio buttons, which they will then input text into a box, and submit, to change some attributes. I really need some help here. It works just fine until I add the second layer of variables on top of it, and I can't find the answer to this question anywhere. <?PHP require('connect.php'); ?> <form action ='' method='post'> <select name="id"> <?php $extract = mysql_query("SELECT * FROM cars"); while($row=mysql_fetch_assoc($extract)){ $id = $row['id']; $make= $row['make']; $model= $row['model']; $year= $row['year']; $color= $row['color']; echo "<option value=$id>$color $year $make $model</option> ";}?> </select> Which attribute would you like to change?<br /> <input type="radio" name="getchanged" value="make"/>Make<br /> <input type="radio" name="getchanged" value="model"/>Model<br /> <input type="radio" name="getchanged" value="year" />Year<br /> <input type="radio" name="getchanged" value="color" />Color<br /><br /> <br /><input type='text' value='' name='tochange'> <input type='submit' value='Change' name='submit'> </form> //This is where I need help... <?PHP if(isset($_POST['submit'])&&($_POST['tochange'])){ mysql_query(" UPDATE cars SET '$_POST[getchanged]'='$_POST[tochange]' where id = '$_POST[id]' ");}?> I have just re-installed Xampp and suddenly my sites are now displaying lots of: Notice: Use of undefined constant name - assumed 'name' in ... Notice: Use of undefined constant price - assumed 'price' in ... this is an example of the line its refering too: $defineProducts[1001] = array(name=>'This is a product', price=>123); My login script stores the user's login name as $_SESSION[ 'name'] on login. For some unapparent reason, i'm getting errors stating that $user and $priv are undefined variables, though I've attempted to define $user as being equal to $_SESSION['name'], using $user to look up the the user's privilege level (stored as the su column ) in the SQL table, and then where the result of the sql query is $priv which is then evaluated in an if statement. I can't seem to figure out why this might not be working. The code I'm using: <?php session_start(); function verify() { //verify that the user is logged in via the login page. Session_start has already been called. if (!isset($_SESSION['loggedin'])) { header('Location: /index.html'); exit; } //if user is logged in, we then lookup necessary privleges. $_SESSION['name'] was written with the login name upon login. Privleges // are written in db as a single-digit integer of of 0 for users, 1 for administrators, and 2 for special users. $user === $_SESSION['name']; //Connect to Databse $link = mysqli_connect("127.0.0.1", "database user", "password", "database"); if (!$link) { echo "Error: Unable to connect to MySQL." . PHP_EOL; echo "Debugging errno: " . mysqli_connect_errno() . PHP_EOL; echo "Debugging error: " . mysqli_connect_error() . PHP_EOL; exit; } //SQL Statement to lookup privlege information. if ($result = mysqli_query($link, "SELECT su FROM accounts WHERE username = $user", MYSQLI_STORE_RESULT)) { //LOOP TO CYCLE THROUGH SQL RESULTS AND STORE Privlege information as vairable $priv. while ($row = $result->fetch_assoc()) { $priv === $row["su"]; } } // close SQL connection. mysqli_close($link); // Verify privleges and take action. Only a privlege of "1" is allowed to view this page. A privlege of "2" indicates special //accounts used in other scripts that have certain indermediate additional functions, but are not trusted administrators. if ($priv !== 1) { echo $_SESSION['name']; echo "you have privlege level of $priv"; echo "<br>"; echo 'Your account does not have the privleges necessary to view this page'; exit; } } verify(); ?>
Hello everyone, I can get Test 2 to successfully operate the if statement using a variable variable. But when I try the same method using a session variable (Test 1) the if statement is not executed. Please could you tell me why the if statement in Test 1 is not being executed? Code: [Select] <?php # TEST 1 $_SESSION[test_variable] = "abcd"; $session_variable_name = "_SESSION[test_variable]"; if ($$session_variable_name == "abcd") { echo "<br>line 373, abcd<br>"; } # TEST 2 $test_variable = "efgh"; $test_variable_name = "test_variable"; if ($$test_variable_name == "efgh") { echo "<br>line 379, efgh<br>"; } ?> Many thanks, Stu |