PHP - Webcam Clicking A Picture When The Page Submits

How do I do I prevent a broken image icon if there is no image? Here is my code:
Code: [Select]
<?php
  if ($_POST){

$county = $_POST['county'];
}
$con = mysql_connect("localhost","","");
if (!$con)
  {
   die('Could not connect: ' . mysql_error());
   }

mysql_select_db("", $con);
$imageLocation = $row['imageurl1'];

$result = mysql_query("SELECT * FROM places WHERE `county` = '".mysql_real_escape_string($county)."' order by `date_created` DESC");
if ( mysql_num_rows($result) > 0 )
{
echo "<strong>Click Headers to Sort</strong>";
echo "<table border='0' align='center' bgcolor='#999969' cellpadding='3' bordercolor='#000000' table class='sortable' table id='results'> 
<tr>
<th> Title </th> 
<th> Borough </th> 
<th> Town </th> 
<th> Phone </th> 
<th> Rooms </th> 
<th> Bath </th>
<th> Fees </th> 
<th> Rent </th>
<th> Image </th>
</tr>";

while($row = mysql_fetch_array($result))
  {
echo "<tr>
<td bgcolor='#FFFFFF' style='color: #000' align='center'>
   <a href='classified/places/index.php?id=".$row['id']."'>" . $row['title'] . "</a></td>
<td bgcolor='#FFFFFF' style='color: #000' align='center'>" . $row['county'] . "</td> 
<td bgcolor='#FFFFFF' style='color: #000' align='center'>" . $row['town'] . "</td> 
<td bgcolor='#FFFFFF' style='color: #000' align='center'>" . $row['phone'] . "</td> 
<td bgcolor='#FFFFFF' style='color: #000' align='center'>" . $row['rooms'] . "</td> 
<td bgcolor='#FFFFFF' style='color: #000' align='center'>" . $row['bath'] . "</td> 
<td bgcolor='#FFFFFF' style='color: #000' align='center'>" . $row['feeornofee'] . "</td>
<td bgcolor='#FFFFFF' style='color: #000' align='center'>" . $row['rent'] . "</td>
<td bgcolor='#FFFFFF' style='color: #000' align='center'><img src=user/". $row['imageurl1'] ." width='50'></td>
</tr>"; 
}
echo "</table>";
print_r($apts);
}
else
{
echo "<p>&nbsp;</p><p>&nbsp;</p> No Results <br /><p>&nbsp;</p><FORM><INPUT TYPE='button' VALUE='Go Back' onClick='history.go(-1);return true;'></FORM> and Refine Your Search <p>&nbsp;</p><p>&nbsp;</p>";
}
?>
Thanks in advance

Hello.

I hope one of the PHP/HTML gurus here can help me. I have a web page that has been altered a bit to add some Google Analytics stuff and I've moved it to a 2nd directory. The original one works fine, the 2nd one won't post the form when I click the submit button.

1st URL https://www.theneutralizer.info/neutralizer
2nd URL: https://www.theneutralizer.info/neutralizer2

I have changed the action property to the correct script, and it does exist. But the problem is when clicking the button nothing happens.

Anyone have any ideas? I can send the PHP code if needed, but since it's HTML output, it should work the way it is displayed in the browser.

David

i have a chat room where i've created using AJAX n i wonder how can i add a webcam for my chatroom?? Is there anything i mean software to be added or installed??

Any guides?? thanks

This topic has been moved to Third Party PHP Scripts.

http://www.phpfreaks.com/forums/index.php?topic=343384.0

I'm using jQuery webcam to capture a photo of the client. I need to send it to the server just when the form is submitted (It's a form with information, and I need to have the photo attached to it).

I have everything working except the part of saving the image encoded with base64 to the database like blob.

Here is what I have so far:

Code: [Select]
    <script type="text/javascript">
    var pos = 0;
    var ctx = null;
    var cam = null;
    var image = null;
   
    jQuery("#webcam").webcam({
   
    width: 320,
    height: 240,
    mode: "callback",
    swffile: "/../../js/jscam_canvas_only.swf",
   
    onTick: function(remain) {
   
    if (0 == remain) {
    jQuery("#status").text("Sorria!");
    } else {
    jQuery("#status").text(remain + " segundo(s) restante(s)...");
    }
    },
   
    onSave: function(data) {
   
        var col = data.split(";");
        var img = image;
   
        for(var i = 0; i < 320; i++) {
            var tmp = parseInt(col[i]);
            img.data[pos + 0] = (tmp >> 16) & 0xff;
            img.data[pos + 1] = (tmp >> 8) & 0xff;
            img.data[pos + 2] = tmp & 0xff;
            img.data[pos + 3] = 0xff;
            pos+= 4;
        }
   
        if (pos >= 4 * 320 * 240) {
            ctx.putImageData(img, 0, 0);
            var canvas = document.getElementById("canvas");
            var save_image = canvas.toDataURL("image/png");
            save_image = save_image.replace(/^data:image\/(png|jpeg);base64,/, ""); 
            $('input[name=save_image]').val(save_image);
            pos = 0;
        }
    },
   
    onCaptu function () {
               
    jQuery("#flash").css("display", "block");
    jQuery("#flash").fadeOut(100, function () {
    jQuery("#flash").css("opacity", 1);
    });
                    jQuery("#canvas").show();
                    webcam.save();
    },
   
    onLoad: function () {
               
    var cams = webcam.getCameraList();
    for(var i in cams) {
    jQuery("#cams").append("<li>" + cams[i] + "</li>");
    }
                    jQuery("#canvas").hide();
    }
    });
   
    function getPageSize() {
   
    var xScroll, yScroll;
   
    if (window.innerHeight && window.scrollMaxY) {
    xScroll = window.innerWidth + window.scrollMaxX;
    yScroll = window.innerHeight + window.scrollMaxY;
    } else if (document.body.scrollHeight > document.body.offsetHeight){ // all but Explorer Mac
    xScroll = document.body.scrollWidth;
    yScroll = document.body.scrollHeight;
    } else { // Explorer Mac...would also work in Explorer 6 Strict, Mozilla and Safari
    xScroll = document.body.offsetWidth;
    yScroll = document.body.offsetHeight;
    }
   
    var windowWidth, windowHeight;
   
    if (self.innerHeight) { // all except Explorer
    if(document.documentElement.clientWidth){
    windowWidth = document.documentElement.clientWidth;
    } else {
    windowWidth = self.innerWidth;
    }
    windowHeight = self.innerHeight;
    } else if (document.documentElement && document.documentElement.clientHeight) { // Explorer 6 Strict Mode
    windowWidth = document.documentElement.clientWidth;
    windowHeight = document.documentElement.clientHeight;
    } else if (document.body) { // other Explorers
    windowWidth = document.body.clientWidth;
    windowHeight = document.body.clientHeight;
    }
   
    // for small pages with total height less then height of the viewport
    if(yScroll < windowHeight){
    pageHeight = windowHeight;
    } else {
    pageHeight = yScroll;
    }
   
    // for small pages with total width less then width of the viewport
    if(xScroll < windowWidth){
    pageWidth = xScroll;
    } else {
    pageWidth = windowWidth;
    }
   
    return [pageWidth, pageHeight];
    }
   
    window.addEventListener("load", function() {
   
    jQuery("body").append("<div id=\"flash\"></div>");
   
    var canvas = document.getElementById("canvas");
   
    if (canvas.getContext) {
    ctx = document.getElementById("canvas").getContext("2d");
    ctx.clearRect(0, 0, 320, 240);
   
    var img = new Image();
    img.onload = function() {
    ctx.drawImage(img, 320, 240);
    }
    image = ctx.getImageData(0, 0, 320, 240);
    }
    var pageSize = getPageSize();
    jQuery("#flash").css({ height: pageSize[1] + "px" });
   
    }, false);
   
    window.addEventListener("resize", function() {
   
    var pageSize = getPageSize();
    jQuery("#flash").css({ height: pageSize[1] + "px" });
   
    }, false);
    </script>
Then I have just a normal form that the customer has to fill it in, followed by this:

Code: [Select]
    <div id="webcam">
    </div>
    <p style="width:250px;text-align:center; "><input type="button" value="Tirar Fotografia" onclick="webcam.capture(3);void(0);"/></p></td><td><p><canvas id="canvas" height="200" width="200"></canvas></p>
in php i have:

Code: [Select]
$image=file_get_contents(base64_decode($_POST['save_image']));

Please, take a look to the following code.After clicking Next it goes to overview.php.Why when I click back on my browser to return to this page again, it is not returning back? When I click back I receive "Confirm Form Resubmission" message. After refreshing page it loads page.
I guess problem is in "session_start();" part. Something to do with cookies.
Please, help me it is very urgent for me.

<?php
session_start();

echo "<html>
<head>
<title>Hello World</title>
<meta http-equiv='Content-Type' content='text/html; charset=Windows-1252'/>
</head>";

require_once ('functions.inc');

if(!isset($_POST['userid'])) {
echo "<script type='text/javascript'>";
echo "window.location = 'index.php'";
echo "</script>";

exit;
}else{

session_register("userid", "userpassword");
$username = auth_user($_POST['userid'], $_POST['userpassword']);

if(!$username) {
$PHP_SELF = $_SERVER['PHP_SELF'];
session_unregister("userid");
session_unregister("userpassword");
echo "Authentication failed " .
"Please, write correct username or password. " .
"try again ";
echo "<A HREF=\"index.php\">Login</A><BR>";
exit;
}
}


function auth_user($userid, $userpassword){
global $default_dbname, $user_tablename;
$user_tablename = 'user';
$link_id = db_connect($default_dbname);
mysql_select_db("d12826", $link_id);

$query = "SELECT username FROM $user_tablename WHERE username = '$userid' AND password = '$userpassword'";
$result = mysql_query($query) or die(mysql_error());

if(!mysql_num_rows($result)){
return 0;
}else{
$query_data = mysql_fetch_row($result);
return $query_data[0];
}
}

echo "hello";
echo "<form method='POST' name='myform' action='overview.php'>";
echo "<input type='submit' value='Next'>";
echo "</form>";

?>

Hi,

I am making login page with database and php. I need to be able when the person clicks theogin button to take photo of the person and add it to that same database based on the info entered.

 

I am doing this to know if that person that logged in is the person in reality.

 

Is it possible 

I tried both of these articles, I have a windows 8.1 tablet and both of the different "codes" worked but I tried my friend's iPhone and the camera viewport is just a black square or doesn't show at all... the problem seems to be that the pop up where you push "allow" or "deny" doesn't show up at all, this makes me think the trigger isn't "triggered".   These are the sites   I'm using HTML5 and Javascript, didn't do much modifcation yet, I just needed the basic web cam access, cropping, saving functions at the moment.     http://davidwalsh.name/browser-camera     http://mycodingtrick...ipt/webcam-api/

have a form with three list/menu items. Each one when selected acts a filter. I would like to submit the form when the user changes the value on each list.menu: I have tried adding an onchange="this.form.submit()" command on each list/menu but only the first one works. I guess the form only recognises one submit item.
 
Is there a way to get the form to submit on each of the three list/menu items ?
 
Many thanks,
 
 
code ...
 
<body>
<form id="form1" name="form1" method="post" action="">
  <label>Team
    <select name="myTeam" id="myTeam" onchange="this.form.submit()">
      <?php
do {
?>
      <option value="<?php echo $row_myTeam['title']?>"<?php if (!(strcmp($row_myTeam['title'], $_POST['myTeam']))) {echo "selected=\"selected\"";} ?>><?php echo $row_myTeam['title']?></option>
      <?php
} while ($row_myTeam = mysql_fetch_assoc($myTeam));
  $rows = mysql_num_rows($myTeam);
  if($rows > 0) {
      mysql_data_seek($myTeam, 0);
  $row_myTeam = mysql_fetch_assoc($myTeam);
  }
?>
    </select>
  </label>
  <label>Qct
    <select name="myQCT" id="myQCT" onchange="this.form.submit()">
      <?php
do {
?>
      <option value="<?php echo $row_chooseQCT['name']?>"<?php if (!(strcmp($row_chooseQCT['name'], $_POST['myQCT']))) {echo "selected=\"selected\"";} ?>><?php echo $row_chooseQCT['name']?></option>
      <?php
} while ($row_chooseQCT = mysql_fetch_assoc($chooseQCT));
  $rows = mysql_num_rows($chooseQCT);
  if($rows > 0) {
      mysql_data_seek($chooseQCT, 0);
  $row_chooseQCT = mysql_fetch_assoc($chooseQCT);
  }
?>
    </select>
  </label>
  <label>Year
    <select name="myYear" id="myYear" onchange="this.form.submit()">
      <?php
do {
?>
      <option value="<?php echo $row_myYear['year']?>"<?php if (!(strcmp($row_myYear['year'], $_POST['myYear']))) {echo "selected=\"selected\"";} ?>><?php echo $row_myYear['year']?></option>
      <?php
} while ($row_myYear = mysql_fetch_assoc($myYear));
  $rows = mysql_num_rows($myYear);
  if($rows > 0) {
      mysql_data_seek($myYear, 0);
  $row_myYear = mysql_fetch_assoc($myYear);
  }
?>
    </select>
  </label>
</form>
</body>

i cant find any working stuff on this
i cant just start learning as3 and flash development for a small feature :\

i found this two guides:
http://www.marchawkins.com/2010/03/17/capture-and-upload-a-webcam-still-with-flash/
dont work for me do error couldnt make it work :|

http://www.endseven.net/?p=9#
didnt work for me to...


im beggin you guys i really need this script

just a simple snap from webcam and it upload to the site thats it.

Hello, I've looked around at some previous posts and can't seem to get them to work for me.
I'm occasionally receiving blank emails from my contact form,
i.e.
Name:
Email:
Subject:
Message:
with no fields filled out.
No doubt the cause is my form.
It has validation, and I'm aware that with JS turned off, the validation won't work, but I find it hard to believe that people are just submitting blank forms, I'm confused, and am worried that I'm getting emails and not realizing it!

My code is below, if you can point me in the right direction or point out the problem area that would be great!
website is:    www.ed-yu.com

Code: [Select]
    <div id="contact_box">
<h3>Questions?<br />Comments?<br />Just get in touch.</h3><p>(use the form below, or email edward@ed-yu.com)</p>
<form id="contact" method="post" class="form" action="js/contactengine.php">
<p class="name">
<input type="text" name="Name" id="Name" />
                <label for="Name">Name</label>
</p>
                <p class="email">
<input type="text" name="Email" id="Email" />
<label for="Email">Email</label>
</p>
                <p class="Subject">
        <select name="Subject" id="Subject">
                <option value="000" selected="selected"> - Choose -</option>
                <option value="General Question">General Question</option>
                <option value="Photography Inquiry">Photography Inquiry</option>
                <option value="Web-design Inquiry">Web-design Inquiry</option>
                <option value="Love Letter">Love Letter</option>
                <option value="Hate Mail">Hate Mail</option>
                <option value="Website Feedback">Website Feedback</option>
        </select>
                <label for="Subject">Subject</label>
</p>
                <p class="Message">
<label for="Message"> </label><br />
<textarea name="Message" rows="20" cols="20" id="Message"></textarea>
</p>
                <p class="Submit">
<input type="Submit" name="Submit" value="Send Email" class="submit-button" />
                </p>
</form>
</div><!--contact_box-->

Code: [Select]
<?php

$EmailFrom = "ED-YU.com";
$EmailTo = "eddytheflow@gmail.com";
$Subject = "A new ".mb_strtolower($_POST['Subject'])." from ".$_POST['Name']." ";
$Name = Trim(stripslashes($_POST['Name'])); 
$Tel = Trim(stripslashes($_POST['Tel'])); 
$Email = Trim(stripslashes($_POST['Email'])); 
$Message = Trim(stripslashes($_POST['Message'])); 


// validation
$validationOK=true;
if (!$validationOK) {
  print "<meta http-equiv=\"refresh\" content=\"0;URL=error.htm\">";
  exit;
}

// prepare email body text
$Body = "";
$Body .= "Name: ";
$Body .= $Name;
$Body .= "\n";
$Body .= "Email: ";
$Body .= $Email;
$Body .= "\n";
$Body .= "Subject: ";
$Body .= $Subject;
$Body .= "\n";
$Body .= "Message: ";
$Body .= $Message;
$Body .= "\n";

// send email 
$success = mail($EmailTo, $Subject, $Body, "From: <$EmailFrom>");

// redirect to success page 
if ($success){
  print "<meta http-equiv=\"refresh\" content=\"0;URL=contactthanks.php\">";
}
else{
  print "<meta http-equiv=\"refresh\" content=\"0;URL=error.htm\">";
}
?>

So I posted something like this a while ago but i didn't get any particularly good answers so I redid it. this is what I have now. It takes clicking the reply three times before it changes changes the form but then after that initial session of reply button clicks it only takes two which is what I want. This is the last thing on my forum (at least till I find some other bug :p) and I need it fixed but I can't figure it out. IT\t wouldn't be a huge issue but the thing is that the first reply you make someone would fill it all in and then press reply then they would lose all their stuff and have to start over before it was submitted, Help please! thanks!
Code: [Select]
<form action="<?php  if ($_SESSION['logged_in'] == '1') {
if ((isset($_POST['reply_to_thread'])) && ($_SESSION['reply_has_been_clicked'] != '1')) { echo $this_thread_path; } elseif ((isset($_POST['reply_to_thread'])) && ($_SESSION['reply_has_been_clicked'] == '1')) { $_SESSION['reply_has_been_clicked'] = '0'; $_SESSION['came_from_a_page'] = '1'; echo 'thread_redirect.php'; }}?>" method='post'>
<?php
if ($_SESSION['logged_in'] == '1') {
if ((isset($_POST['reply_to_thread'])) && ($_SESSION['reply_has_been_clicked'] != '1')) {
echo '<textarea name="reply_body" cols="75" rows="10" style="resize:none; onKeyUp="limitText(this.form.reply_body,this.form.countdown,5000); onKeyDown="limitText(this.form.reply_body,this.form.countdown,5000);">Enter your reply here...</textarea><br><br><font size="1">(Maximum characters: 5000)<br>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;You have <input readonly type="text" name="countdown" size="3" value="5000"> characters left.</font><br>';
$_SESSION['reply_has_been_clicked'] = '1';
}
}
?>
<input type='submit' name='reply_to_thread' value="Reply">
<?php
if (isset($_POST['reply_to_thread'])) {
if ($_SESSION['logged_in'] != '1') {
echo 'You need to be logged in!';
}
}
?>
</form>

I generated a table from the database, and at the end of each row there are two submits, one for save and another for delete. The values are generated as either text and select box input.

Right now, I have all the submits named differently (ends a number), so I can loop through all available submits based on the number to check which row needs to be updated, and to retrieve the values during form processing, then only perform the query.  I have also hidden input in each row to send the "primary key" that is used during query.

Is there a better approach than to have so many different names for the buttons, not having to loop through all of them each time, and still keep a similar layout? I'm trying to avoid anything else than PHP.

The table looks something like:
col1____| col2_______| col3____|__________________
txt input | select input  | txt input |save bttn | delete bttn
txt input | select input  | txt input |save bttn | delete bttn

Hello, I am having an issue where PHP nulls the donation amount after multiple form submits. Here is a synopsis of what is happening.

1: User enters donation amount and clicks 'submit'
2: Is taken to a confirmation page where they must agree to terms
3: User fails to agree to the terms, the page is reloaded with an error message, and the donation amount is set to null

I want to make the donation amount display despite multiple confirm page reloads. How would I do this?

Here is the site to test it yourself. Ignore the steamid input and check "do not change my rank upon donation" to test.

http://forums.stgdarkrp.org/donate2/check.php

Please note: If you use IE, the formatting is messed up, that is a problem I will look into later