PHP - No Ending Delimiter ''' Found In
Hi New to php code, been trown in at the deep end.
Keep getting error message Warning: preg_replace(): No ending delimiter it is to do with these 3 lines only $is_sera = preg_replace("'","\"", $is_sera); $is_sera = preg_replace("%","", $is_sera); $is_sera = preg_replace("\?","", $is_sera); can any one tell me what the ending delimiter error means/is thanks in advance Similar TutorialsI'm having trouble with a role in a wordpress site that I made I think the script was that I installed another version, so I some adjustments in it, among those changes have modified this function Quote if (@$_GET['src'] && !@$PHPTHUMB_CONFIG['allow_local_http_src'] && eregi('^http://'.@$_SERVER['HTTP_HOST'].'(.+)', @$_GET['src'], $matches)) { $phpThumb->ErrorImage('It is MUCH better to specify the "src" parameter as "'.$matches[1].'" instead of "'.$matches[0].'".'."\n\n".'If you really must do it this way, enable "allow_local_http_src" in phpThumb.config.php'); } for this: Quote (@$_GET['src'] && !@$PHPTHUMB_CONFIG['allow_local_http_src'] && preg_match('^http://'.@$_SERVER['HTTP_HOST'].'(.+)', @$_GET['src'], $matches)) { $phpThumb->ErrorImage('It is MUCH better to specify the "src" parameter as "'.$matches[1].'" instead of "'.$matches[0].'".'."\n\n".'If you really must do it this way, enable "allow_local_http_src" in phpThumb.config.php'); } It was supposed to make some images appear as thumbnails on the home page my site, but they do not appear and I got the following error: Quote Warning: preg_match() [function.preg-match]: No ending delimiter '^' found in /home/pontocom/public_html/wp-content/themes/Comfy/scripts/phpThumb/phpThumb.php on line 160 Is there some way that I can take to fix this error? Hi All, I am trying to create a PHP code that will run a form, however i keep getting the error message Warning: preg_match() [function.preg-match]: No ending delimiter '^' found in D:\xampp\htdocs\HFCC\Scripts\mailprocess.php on line 55 Invalid email address entered. Go Back and try again attached is the complete copy of the code i am using, i have an email text box and label with the id 'email' also my method is POST and my action is Scripts/mailprocess.php. Please let me know if you need any additional details. Any help will be much appreciated. Thanks Please help me with this code. It keep appear in my website. "Warning: preg_match() [function.preg-match]: No ending delimiter '.' found in /home/kengsite/public_html/wp-content/plugins/statpress/statpress.php on line 1184" And this is how the line look like. if (!preg_match(".ico$", $urlRequested)) { return ''; } This topic has been moved to PHP Regex. http://www.phpfreaks.com/forums/index.php?topic=320039.0 hi i have got the following issues i am using the following code. Code: [Select] <?php //DB CONNECTION $ROWS = "id,firstname,lastname"; // explode at the comma and insert into an array $test = explode("," , $ROWS); //adds array test to the var sam $sam = array($test); // querys the database $new = mysql_query("SELECT * FROM {$DB_TABLE}"); // while loop to loop through selected fields while ($row = mysql_fetch_array($new)) { foreach ($sam[0] as $v) { echo $row[$v] . $DELIMITER . "<br />"; } echo "<br />"; } ?> This will output the following . Code: [Select] 834(|)Step(|)Thompson(|) 835(|)Lucy(|)kim(|) 836(|)Iwan(|)Will(|) 837(|)Sarah (|)Good(|) what i am struggling with is i want to get rid off the last delimiter so it would be Code: [Select] 834(|)Step(|)Thompson 835(|)Lucy(|)kim 836(|)Iwan(|)Will 837(|)Sarah (|)Good i have tried using Code: [Select] // while loop to loop through selected fields while ($row = mysql_fetch_array($new)) { foreach ($sam[0] as $v) { $test = $row[$v] . $DELIMITER; echo substr($test, 0, -1); } echo "<br />"; } but this gets rid off the delimiter for all off them??? This will output the following . Code: [Select] 834Stephompson 835Lucykim 836IwanWill 837SarahGood ideally i would like each row to be its own stored together. Any Help Please I am trying to split a variable only if it has an integer. Here is what I want to do: $id = 1234-54678; should be split into and then placed into two variables: $id1 = 54678; $id2 = 1234; Sometimes the variable may not have a delimiter in which case I would like it to be $id1 example: $id = 54678; should go directly to $id1 = 54678; I am a php rookie and don't know which way is best to do this (explode, split, etc.) so I would appreciate any help you can give me. I am working on taking out the Deprecated functions from my site so while replacing ereg with preg_match I get the below error. Per a message I found on the internet it says to replace ereg with preg_match and everything should work. Can anyone assist me with fixing this error? Error: Warning: preg_match() [function.preg-match]: Delimiter must not be alphanumeric or backslash Part where error is contained if (preg_match('enum.(.*).', $row['Type'], $match)) { $opts = explode(',', $match[1]); foreach ($opts as $item) $finalResult[] = substr($item, 1, strlen($item)-2); } Full Function function getEnumOptions($table, $field) { global $db; $finalResult = array(); if (strlen(trim($table)) < 1) return false; $query = "show columns from " . $db['tickets_slave']->escapeSimple($table); $res =& $db['tickets']->query($query); if (PEAR::isError($res)) { throw new TixException($_SERVER['SCRIPT_NAME'] . ":", TixExceptionCodes::UNKNOWN_ERROR); } else { try { while ($res->fetchInto($row)) { if ($field != $row["Field"]) { } else { //check if enum type if (preg_match('enum.(.*).', $row['Type'], $match)) { $opts = explode(',', $match[1]); foreach ($opts as $item) $finalResult[] = substr($item, 1, strlen($item)-2); } } } } catch (TixException $ex) { throw new TixException($_SERVER['SCRIPT_NAME'] . ":", TixExceptionCodes::UNKNOWN_ERROR); } } return $finalResult; } Hey guys. I am trying to strip everything between a key phrase and ending tag but for some reason it is not working. I always get blank data. I've tried many different ways but no luck.
basically I have a script that connect to imap and store emails into MySQL as service tickets. works great but I am trying to strip everything except for user reply because currently if a user reply to an email it re-inserts the entire email into MySQL. I added a key phrase at the top of all outgoing emails .
1. structure looks like this.
--Reply below this line to respond--
------------------------------------------------------------------------------------------------
Email body message...
2. When replying to the message it becomes
New Message reply......
--Reply below this line to respond--
old message body.
3. so I would only like to insert the new reply message only.
This is what I got so far.
$message=strip_tags($message, "<br><div><p><u><hr></section>");
$message=preg_replace("</p>", "br /", $message); $message=preg_replace('#--REPLY above this line to respond--(.*?)</section>)#s', ' ', $message); $message=clean("<br/><hr><u>Received On $rep_date / $from_email</u><br><br/>$message"); it inserts the "Received On date and From but $message is blank. If i remove $message=preg_replace('#--REPLY above this line to respond--(.*?)</section>)#s', ' ', $message); it inserts the entire email Any suggestion on what i am doing wrong? thank you all very much. Hello, I have the $_session code working, but after I destroy the session and I am asked to log in again, my browser doesn't ask me for my password and just logs me in. I don't understand because I have destroyed my session and I have deleted the data in $_SESSION and I have deleted the info in the cookie so it shouldn't log me in automatically. I thought it was something in my browser, but I erased my history and I never saved any password. Here's my code: This is the welcome page <?php require_once 'login.php'; $connection = new mysqli($db_hostname, $db_username, $db_password, $db_database); if ($connection->connect_error) die($connection->connect_error); if (isset($_SERVER['PHP_AUTH_USER']) && isset($_SERVER['PHP_AUTH_PW'])) { $un_temp = mysql_entities_fix_string($connection, $_SERVER['PHP_AUTH_USER']); $pw_temp = mysql_entities_fix_string($connection, $_SERVER['PHP_AUTH_PW']); $query = "SELECT * FROM users WHERE username='$un_temp'"; $result = $connection->query($query); if (!$result) die($connection->error); elseif ($result->num_rows) { $row = $result->fetch_array(MYSQLI_NUM); $result->close(); $salt1 = "qm&h*"; $salt2 = "pg!@"; $token = hash('ripemd128', "$salt1$pw_temp$salt2"); if ($token == $row[3]) { session_start(); $_SESSION['username'] = $un_temp; $_SESSION['password'] = $pw_temp; $_SESSION['forename'] = $row[0]; $_SESSION['surname'] = $row[1]; echo "$row[0] $row[1] : Hi $row[0], you are now logged in as '$row[2]'"; die("<p><a href=continue.php>Click here to continue</a></p>"); } else die("Invalid username/password combination"); } else die("Invalid username/password combination"); } else { header('WWW-Authenticate: Basic realm="Restricted Section"'); header('HTTP/1.0 401 Unauthorized'); die("Please enter your username and password"); } $connection->close(); function mysql_entities_fix_string($connection, $string) { return htmlentities(mysql_fix_string($connection, $string)); } function mysql_fix_string($connection, $string) { if (get_magic_quotes_gpc()) $string = stripslashes($string); return $connection->real_escape_string($string); } ?> and this is the other page: <?php session_start(); if(isset($_SESSION['username'])) { $username = $_SESSION['username']; $password = $_SESSION['password']; $forename = $_SESSION['forename']; $surname = $_SESSION['surname']; destroy_session_and_data(); echo "Welcome back $forename. <br> Your full name is $forename $surname.<br> Your username is '$username' and your password is '$password'."; } else echo "Please <a href='authenticate2.php'>Click here</a> to log in."; function destroy_session_and_data() { $_SESSION = array(); setcookie(session_name(), '', time() - 2592000,'/'); session_destroy(); } ?>
When I type the website in i first get prompt to enter my password, when I am authenticated the webpage says: You are now logged in click here to continue. When I do I am directed to another page which confirms that I am still logged in. Then I press refresh and the webpage asks me to "Click here to log in". I do, but it doesn't ask me for my password again. Why? My personal info should be destroyed. Thank you for responding. It's greatly appreciated
Hi, I am trying to figure out how to stop my script from offering a discount when the date that is listed passes by. It seems to always 'reset' itself even after the 15th of the month...I want it to stop after April 15...This is what I had, can anyone assist? Thank you in advance for your help! Jennifer Code: [Select] } if(date("n") < 15) { $before = $cost*.05; $before = round($before,2); $cost = $cost-$before; } Hi Everyone, I wonder if somebody could help me. I have been at this for hours and am really struggling. I have a timer which I have set up for a quiz. The quiz opens in a javascript shadow box. When the quiz is opened a session variable for the timer is set up to keep track of the time. What I need is for this session variable to end when the shadow box is closed. I have a onClose hook to peform actions when the shadow box is closed which is in javascript. Obviously I cannot end the session variable in the javascript function due to js being client side and php being server side. Has anyone any suggestions how I can resolve this issue. I need to end this session variable as if the user exits the quiz and then selects another quiz to do the timer uses the current time session rather than assigning the new time value for that particular quiz. Thanks in advance. Edd Part of my page is taken from external webpages by preg_match. Since It is a partial section, it contains incomplete tags such as <div>, <span>, etc. Thus, they mix up with my entire page and my </div>, </span> are used for the incomplete tags in the borrowed section. How I can end such tags? or separate this section from the main codes (I mean having an isolated section)? Hello happy codes, I have an image as such; http://storage.canoe.ca/v1/dynamic_resize/?src=http://www.torontosun.com/specialsections/2011/03/10/248x186_mb.jpg&size=40x30 getimagesize doesn't work with this image. Any ideas or links? I have looked through this site and can't find anyone having this problem. Am I missing something? Thank you, V. preg_replace() asks that "Delimiter must not be alphanumeric or backslash" in the pattern. So I changed $new_text = preg_replace($_POST['withthis'] ,$_POST['withthis'],$_POST['text']); to this $replacethis = $_POST['replacethis']; $new_text = preg_replace("/$replacethis/",$_POST['withthis'],$_POST['text']); It works fine, but out of curiosity, is there any way to have the POST variable as a parameter directly, and why does it not work? Just to try it, I attempted: "/$_POST['withthis']/" and $_POST["/'withthis'/"] and both do not work. str_replace is a better option I think, but I am just trying to get a better understanding of this delimiter rule. Thanks for your time! Hi Guys I've been trying to work on my OS Commerce site, but for some reason I'm getting this error on the main index.php page. Welcome Guest! Would you like to log yourself in? Or would you prefer to create an account? Feel free to click any of the links below to access the main categories. Warning: strpos() [function.strpos]: Empty delimiter. in /var/www/vhosts/XXXXXX.co.uk/httpdocs/shop/index.php on line 319 319 shows this: if (isset($cPath) && strpos('_', $cPath)) { Any ideas where this error comes from? Hello, i have two fields. a beginning year and an ending year. How can i make new fields out of the years in between the beginning and ending years. i hope that makes sense. I am making login system using codeigniter. When I run my code i get this error. Code: [Select] The requested URL /ci_login/user/login was not found on this server. here is my code so far user.php file which is in controller folder Code: [Select] <?php if ( ! defined('BASEPATH')) exit('No direct script access allowed'); class User extends CI_Controller { function __construct() { parent::__construct(); } function index() { } function login() { if($this->form_validation->run() == FALSE) { $this->load->view('view_login'); } else { echo "Successfull"; } } } view_login.php file which is in view folder Code: [Select] <html> <head> <title>Login</title> </head> <body> <h1>Please Login!</h1> <p>Use the login form below to login.</p> <div id="login_form"> <?php echo form_open(base_url(). 'user/login' ) ?> <label>Username:</label> <div> <?php echo form_input(array('id' => 'username', 'name' => 'username')); ?> </div> <label>Password:</label> <div> <?php echo form_password(array('id' => 'password', 'name' => 'password')); ?> </div> <div> <?php echo form_submit(array('name' => 'submit'),'Login'); ?> </div> <?php echo form_close(); ?> </div> </body> </html> help please how can I solve this error? Hi every1, I am quite a newbie in php so please bear with ma silly questions.. I use IIS 6.0 . I have a php file named try.php . content is as folows <html> <head>......</head> <body>........som html code here... <?php if (flag==0) { some html code } ?> ...some html code </body> </html> when i open the file it says Error Summary HTTP Error 500.0 - Internal Server Error The page cannot be displayed because an internal server error has occurred. Can anybody tell me what am i doing wrong... It happen with me almost every now and then.. Is there some conceptual mistake am doing? Please clarify.. If the same question has been discussed thousand times before, than do direct me to the proper link... Regards, Dwayne Hi Folks! New to php and introduced into it by a new found friend who is really into php. Been learning and learning and learning but not so much I am afraid. I guess books and youtubes and other tutorials are not enough so here I am, fearlessly venturing into this forum and I hope to learn much more to all ya pros out there err I mean in here. Be gentle to me please. I am not a coder but I do have logical thinking attitude and habit. I am a slow learner and close to the resignation age. But who cares, I wanna learn php, yeah!
This code works without problems:
<?php namespace NamespaceA; class A extends \NamespaceB\B {} namespace NamespaceB; class B {} But why the following code cause Fatal error: Class 'NamespaceB\B' not found in ...file? <?php namespace NamespaceA; class A extends \NamespaceB\B {} namespace NamespaceB; class B extends \NamespaceC\C {} namespace NamespaceC; class C {}And this code also works without problems: <?php namespace NamespaceA; class A extends \NamespaceB\B {} namespace NamespaceC; class C {} namespace NamespaceB; class B extends \NamespaceC\C {}Without any namespace, also Fatal error: Class 'B' not found in ...file: <?php class A extends B {} class B extends C {} class C {}Works without problems: <?php class A extends B {} class B {}And yes everything is in the same PHP file.... |