PHP - Finding Unique Values

Hello All,

I have a contact directory database. It has all the employees of my company (name, phone, email, department, building, etc).

Say on one page I have the Marketing Department, and I want to say:
"The Marketing Department Director is ________"

How would I assign that value from the database? Do I want to put in a unique "keyword" field in the database, but then how would I store all the values automatically on the page?

I see pages where I would want to list the Marketing Director, and his secretary, then another page with the Sales Director, and his secretary, etc....  all with being able to change the values in the database, and it changing across all the pages instantly.

Do I need to say on every page "select * from database where keyword = marketingdirector" and then store that result as a variable? It seems unpractical to repeat that a few times for each different person I want to list.

Is there a better way to do this then I'm thinking?

Thanks all!

Hi all,

I have a situation where I need to remember what check boxes where checked over pagination, I have managed to do this via the use of this:

http://jamesfunk.com/wordpress/?p=65

The problem is that as the code stood:

Code: [Select]
<input type="checkbox" name="compare" value="<?php echo $list['jobseeker_id'];?>" class="remember_cb"/>
It was treating one ticked checkbox as them all because they all have the same name and are in the a while loop!

I countered this by changing the code to:

Code: [Select]
<input type="checkbox" name="compare<?php echo $list['jobseeker_id']?>" value="<?php echo $list['jobseeker_id'];?>" class="remember_cb"/>
Which effectively now makes the checkbox name unique... i.e. compare{id}.

The problem with this is that I can now no longer process it. This is my processing code:

$jobseekers = $_POST['compare'];
$i = 0;
for($i; $i<count($jobseekers); $i++){
$query = "SELECT * FROM jobseekers WHERE jobseeker_id = '$jobseekers[$i]'";
$result = mysql_query($query) or die (mysql_error());

while ($row = mysql_fetch_array($result)) {
// Spit out the required data
}
}

As you can see I am trying to get the data from $_POST['compare'], which will obviously now be blank as I have had to make the name unique.... the trouble is I'm not sure how to actually process this.

Can anyone help me out here? any help or advice would be greatly appreciated!

many thanks,

Greens85

Hello,

I need some help. Say that I have a list in my MySQL database that contains elements "A", "S", "C", "D" etc... Now, I want to generate an html table where these elements should be distributed in a random and unique way while leaving some entries of the table empty, see the picture below. But, I have no clue how to do this... Any hints?



Thanks in advance,
Vero

I have a mysql table which will store users email addresses (each is unique and is the primary field) and a timestamp. 
I have added another column called `'unique_code' (varchar(64), utf8_unicode_ci)`.

What I would very much appreciate assistance with is;

a) Generating a 5 digit alphanumeric code, ie: 5ABH6 
b) Check all rows the 'unique_code' column to ensure it is unique, otherwise re-generate and check again 
c) Insert the uniquely generated 5 digit alphanumeric code into `'unique_code'` column, corresponding to the email address just entered. 
d) display the code on screen.

What code must I put and where?


**My current php is as follows:**

Code: [Select]
    require "includes/connect.php";
   
    $msg = '';
   
    if($_POST['email']){
   
    // Requested with AJAX:
    $ajax = ($_SERVER['HTTP_X_REQUESTED_WITH']  == 'XMLHttpRequest');
   
    try{
    if(!filter_input(INPUT_POST,'email',FILTER_VALIDATE_EMAIL)){
    throw new Exception('Invalid Email!');
    }
   
    $mysqli->query("INSERT INTO coming_soon_emails
    SET email='".$mysqli->real_escape_string($_POST['email'])."'");
   
    if($mysqli->affected_rows != 1){
    throw new Exception('You are already on the notification list.');
    }
   
    if($ajax){
    die('{"status":1}');
    }
   
    $msg = "Thank you!";
   
    }
    catch (Exception $e){
   
    if($ajax){
    die(json_encode(array('error'=>$e->getMessage())));
    }
   
    $msg = $e->getMessage();
    }
    }

Dear All Members

here is my table data..

(4 Columns/1row in mysql table)

id                 order_no               order_date                  miles
310                001                   02-15-2020                MI,108.53
                                                                                     Oh,194.57
                                                                                     PA,182.22
                                                                                     WA,238.57

How to split(miles) single column into (state, miles) two columns and output like following 5 columns /4rows in mysql using php code.

(5 Columns in mysql table)
------------------------------------------------------------------------------------

id                  order_no              order_date              state      miles

310                001                   02-15-2020               MI          108.53

310                001                   02-15-2020              Oh          194.57

310                001                   02-15-2020              PA          182.22

310                001                   02-15-2020             WA          238.57
 

------------------my php code -----------

 

<?php
//invoice.php  
include('../includes/config.php');

if(isset($_POST["add"]))
{
$order_no=$_GET['order_no'];
$order_date=$_GET['order_date'];
$miles=$_POST['miles'];

$miles = explode("\r\n", $_POST["miles"]);
$newdata = "'" . implode("','", $_POST["miles"]) . "'";
$sql ="INSERT INTO tble_states_miles(order_no,order_date, miles) VALUES(:order_no, :order_date, :newdata)";

$query = $dbh->prepare($sql);
$query-> bindParam(':order_no', $order_no, PDO::PARAM_STR);
$query-> bindParam(':order_date', $order_date, PDO::PARAM_STR);
$query-> bindParam(':miles', $newdata, PDO::PARAM_STR);

$lastInsertId = $dbh->lastInsertId();
if($lastInsertId)
{
echo "<script type='text/javascript'>alert('Added Sucessfull!');</script>";
echo "<script type='text/javascript'> document.location = 'ifta_miles_calculationlist_added.php'; </script>";
}
else 
{
$error="Something went wrong. Please try again";
}

if($query->execute()) {

$sql = "update tis_invoice set flag='1' where order_no=:order_no";
$query = $dbh->prepare($sql);
$query-> bindParam(':order_no', $order_no, PDO::PARAM_STR);

$query->execute();

}
}
?>

----------------- my form code ------------------

 

 <?php
                   $order_no=$_GET['order_no'];
        $sql = "SELECT * from tis_invoice where order_no = :order_no";
        $query = $dbh -> prepare($sql);
        $query->execute(
  array(
   ':order_no'       =>  $_GET["order_no"]
  )
 );
        $result = $query->fetchAll();
        foreach($result as $row)
?>
    
                    <form method="post">
                        <table align="center" style="width: 55%">
                        <tr><td>Invoice Number</td></tr>
                        <tr><td><input type="text" name="order_no" value="<?php echo $row["order_no"]; ?>" readonly=""></td></tr>
                        <tr><td>Invoice Date</td></tr>
                        <tr><td><input type="text" name="order_no" value="<?php echo $row["order_date"]; ?>" readonly=""></td></tr>
                        <tr><td>
                               <textarea name="miles" class="form-control" rows="10" placeholder="" required></textarea>
                           </td></tr>
                           <tr><td>
                         
                            <input type="submit" name="add" class="btn btn-primary" value="Add" />
                       </td></tr></table>
                    </form>

-- Can any one help how to correct my code..present nothing inserted on table

 

Thank You

Edited February 8, 2020 by karthicbabu

Hi,

My company has 240+ locations and as such some users (general managers) cover multiple sites.  When I run a query to pull user information, when the user has multiple sites to his or her name, its adds the second / third sites to the next columns, rather than wrapping it inside the same table cell.  It also works the opposite way, if a piece of data is missing in the database and is blank, its pull the following columns in.  Both cases mess up the table and formatting.  I'm extremely new to any kind of programming and maybe this isn't the forum for this question but figured I'd give it a chance since I'm stuck.

The HTML/PHP code is below:

<table id="datatables-column-search-select-inputs" class="table table-striped" style="width:100%">

                                        <thead>

                                            <tr>

                                                <th>ID</th>

                                                <th>FirstName</th>

                                                <th>LastName</th>

                                                <th>Username</th>

                                                <th>Phone #</th>

                                                <th>Location</th>

                                                <th>Title</th>

                                                <th>Role</th>

                                                <th>Actions</th>

                                            </tr>

                                        </thead>

                                        <tbody>

                                            <?php

                                            //QUERY TO SELECT ALL USERS FROM DATABASE

                                            $query = "SELECT * FROM users";

                                            $select_users = mysqli_query($connection,$query);

                                            

                                            // SET VARIABLE TO ARRAY FROM QUERY

                                            while($row = mysqli_fetch_assoc($select_users)) {

                                                $user_id = $row['user_id'];

                                                $user_firstname = $row['user_firstname'];

                                                $user_lastname = $row['user_lastname'];

                                                $username = $row['username'];

                                                $user_phone = $row['user_phone'];

                                                $user_image = $row['user_image'];

                                                $user_title_id = $row['user_title_id'];

                                                $user_role_id = $row['user_role_id'];

                                            

                                                // POPULATES DATA INTO THE TABLE

                                                echo "<tr>";

                                                echo "<td>{$user_id}</td>";

                                                echo "<td>{$user_firstname}</td>";

                                                echo "<td>{$user_lastname}</td>";

                                                echo "<td>{$username}</td>";

                                                echo "<td>{$user_phone}</td>";

                                            

                                                //PULL SITE STATUS BASED ON SITE STATUS ID

                                                $query = "SELECT * FROM sites WHERE site_manager_id = {$user_id} ";

                                                $select_site = mysqli_query($connection, $query);

                                                while($row = mysqli_fetch_assoc($select_site)) {

                                                    $site_name = $row['site_name'];

                                                    echo "<td>{$site_name}</td>";

                                                }

                                                echo "<td>{$user_title_id}</td>";

                                                echo "<td>{$user_role_id}</td>";

                                                echo "<td class='table-action'>

                                                    <a href='#'><i class='align-middle' data-feather='edit-2'></i></a>

                                                    <a href='#'><i class='align-middle' data-feather='trash'></i></a>

                                                    </td>";

                                                //echo "<td><a href='users.php?source=edit_user&p_id={$user_id}'>Edit</a></td>";

                                                echo "</tr>";

                                            }   

                                            ?>

 

                                            <tr>

                                                <td>ID</td>

                                                <td>FirstName</td>

                                                <td>LastName</td>

                                                <td>Username</td>

                                                <td>Phone #</td>

                                                <td>Location</td>

                                                <td>Title</td>

                                                <td>Role</td>

                                                <td class="table-action">

                                                <a href="#"><i class="align-middle" data-feather="edit-2"></i></a>

                                                <a href="#"><i class="align-middle" data-feather="trash"></i></a>

                                                </td>

                                            </tr>

                                        </tbody>

                                        <tfoot>

                                            <tr>

                                                <th>ID</th>

                                                <th>FirstName</th>

                                                <th>LastName</th>

                                                <th>Username</th>

                                                <th>Phone #</th>

                                                <th>Location</th>

                                                <th>Title</th>

                                                <th>Role</th>

                                            </tr>

                                        </tfoot>

                                    </table>

Hi

I have a file, that is copied from other files. All other files work perfectly.
But, for some reason this one is throwing back an error.

I've been over it so many time, but can't see whats wrong.

Error:
Fatal error: Call to undefined method stdClass::save() in /home/p/o/powtest/web/public_html/admin/lib/ajax_php/add_interests.php on line 28


add_interests.php
Code: [Select]
<?PHP
require_once("../../../includes/initialize.php");

$flag = 0;
$ID = $_POST['ID'];
$type = $_POST['type'];
$category = $_POST['category'];
$interest = $_POST['interest'];
$expInt = explode("\n", $interest);
$DMOD = date('Y-m-d');
$TMOD = date('H:i:s');

$check_entry = Admin_interest::if_exists(clean_input_value($category));
if($check_entry == 0){
$new_category = Admin_interest::make($ID, clean_input_value($category), clean_input_value($type), $DMOD, $TMOD);
if($new_category && $new_category->save()){
$CID = $new_category->id;
$flag = 1;
}
}


foreach($expInt as $expInts){

$check_entry = Admin_interests_sub::if_exists($CID, clean_input_value($expInts));
if($check_entry == 0){
$new_interest = Admin_interests_sub::make($ID, $CID, clean_input_value($expInts), $DMOD, $TMOD);
if($new_interest && $new_interest->save()){
$message = 'Thank You: Your list Has Been Saved';
}else{
$message = "Sorry, There was an error";
}
}

}

echo $message;
?>


Class:
Code: [Select]
<?PHP
require_once(LIB_PATH.DS.'database.php');

class Admin_interests_sub {

protected static $table_name="admin_interests_sub";
protected static $db_fields = array('id', 'category_id', 'interest_sub', 'dateMod', 'timeMod');
public $id;
public $category_id;
public $interest_sub;
public $dateMod;
public $timeMod;


public static function make($ID, $category_id, $interest_sub, $DMOD, $TMOD){
if(!empty($interest_sub)){
$interest = new Admin_interests_sub();
$interest->id = (int)$ID;
$interest->category_id = (int)$category_id;
$interest->interest_sub = $interest_sub;
$kw->dateMod = $DMOD;
$kw->timeMod = $TMOD;
return $kw;
}else{
return false;
}
}

protected function attributes(){
$attributes = array();
foreach(self::$db_fields as $field){
if(property_exists($this, $field)){
$attributes[$field] = $this->$field;
}
}
return $attributes;
}

protected function sanitized_attributes(){
global $database;
$clean_attributes = array();
foreach($this->attributes() as $key => $value){
$clean_attributes[$key] = $database->escape_value($value);
}
return $clean_attributes;
}

public function save(){
return !empty($this->id) ? $this->update() : $this->create();
}

public function create(){
global $database;
$attributes = $this->sanitized_attributes();
$sql = "INSERT INTO ".self::$table_name." (";
$sql .= join(", ", array_keys($attributes));
$sql .= ") VALUES ('";
$sql .= join("', '", array_values($attributes));
$sql .= "')";
if($database->query($sql)){
$this->id = $database->insert_id();
return true;
}else{
return false;
}
}

public function update(){
global $database;
$attributes = $this->sanitized_attributes();
$attribute_pairs = array();
foreach($attributes as $key => $value){
$attribute_pairs[] = "{$key}='{$value}'";
}
$sql = "UPDATE ".self::$table_name." SET ";
$sql .= join(", ", $attribute_pairs);
$sql .= " WHERE id=".$database->escape_value($this->id);
$database->query($sql);
return ($database->affected_rows() == 1) ? true : false;
}

public function delete(){
global $database;
$sql = "DELETE FROM ".self::$table_name." ";
$sql .= "WHERE id=".$database->escape_value($this->id);
$sql .= " LIMIT 1";
$database->query($sql);
return ($database->affected_rows() == 1) ? true : false;
}

}

?>


Any help finding this bug will be a big help.

Thanks

Okay I'm done with searching for answers, working on this preg_match for about 3 hours now.   I'm looking for "($0.01/$0.02 USD)" in a string. The needle might be slighty different. Possible strings that I might look for is:

(€xx.xx/€xx.xx EUR) where the EUR can be changed into USD, including its signs.

Hi all,

I'm a first time poster here and I would really appreciate some guidance with my latest php challenge! I've spent the entire day googling and reading and to be honest I think I'm really over my head and need the assistance of someone experienced to advise the best way to go!

I have a multi dimensional array that looks like (see below); the array is created by CodeIgniter's database library (the rows returned from a select query) but I think this is a generic PHP question as opposed to having anything to do with CI because it related to working with arrays.

I'm wondering how I might go about searching the array below for the key problem_id and a value equal to a variable which I would provide. Then, when it finds an array with a the matching key and variable, it outputs the other values in that part of the array too.

For example, using the sample data below. How would you recommend that I search the array for all the arrays that have the key problem_id and the value 3 and then have it output the value of the key problem_update_date  and the value of the key problem_update_text. Then keep searching to find the next occurrence?

Thanks in advance, as above, I've been searching really hard for the answer and believe i'm over my head!

Output of print_r($updates);

CI_DB_mysql_result Object
(
    [conn_id] => Resource id #30
    [result_id] => Resource id #35
    [result_array] => Array
        (
        )

    [result_object] => Array
        (
        )

    [current_row] => 0
    [num_rows] => 5
    [row_data] => 
)


Output of print_r($updates->result_array());

Array
(
    [0] => Array
        (
            [problem_update_id] => 1
            [problem_id] => 3
            [problem_update_date] => 2010-10-01
            [problem_update_text] => Some details about a paricular issue
            [problem_update_active] => 1
        )

    [1] => Array
        (
            [problem_update_id] => 4
            [problem_id] => 3
            [problem_update_date] => 2010-10-01
            [problem_update_text] => Another update about the problem with an ID of 3
            [problem_update_active] => 1
        )

    [2] => Array
        (
            [problem_update_id] => 5
            [problem_id] => 4
            [problem_update_date] => 2010-10-12
            [problem_update_text] => An update about the problem with an ID of four
            [problem_update_active] => 1
        )

    [3] => Array
        (
            [problem_update_id] => 6
            [problem_id] => 4
            [problem_update_date] => 2010-10-12
            [problem_update_text] => An update about the problem with an ID of 6
            [problem_update_active] => 1
        )

    [4] => Array
        (
            [problem_update_id] => 7
            [problem_id] => 3
            [problem_update_date] => 2010-10-12
            [problem_update_text] => Some new update about the problem with the ID of 3
            [problem_update_active] => 1
        )

)

Hi all,

Just curious why this works:

Code: [Select]
while (($data = fgetcsv($handle, 1000, ",")) !== FALSE){
$import="INSERT into $prodtblname ($csvheaders1) values('$data[0]','$data[1]','$data[2]','$data[3]','$data[4]','$data[5]','$data[6]')";
}
And this does not:

$headdata_1 = "'$data[0]','$data[1]','$data[2]','$data[3]','$data[4]','$data[5]','$data[6]'";
while (($data = fgetcsv($handle, 1000, ",")) !== FALSE){
$import="INSERT into $prodtblname ($csvheaders1) values($headdata_1)";
}it puts $data[#'s] in the database fields instead of the actual data that '$data[0]','$data[1]'... relates to.

I wrote a script to create the values in $headdata_1 based on the number of headers in $csvheaders1 but can't seem to get it working in the sql statement.

Thanks

Hello PHP freaks,   my codes dont allow me to log-in to Student Home with unique id. It says "Invalid Login or Password" this is my form

<tr bgcolor="#E1E1E1" class="stylesmall">
              <td width="35%" align="left" class="style7 style1">Learner Id : </td>
                <td width="65%" align="left"><input name="learner_id" type="text" id="learner_id" action="Student_Home.php" method="post"></td>
              </tr>
            <tr bgcolor="#E1E1E1" class="stylesmall">
              <td align="left" class="style7 style1">Password:</td>
                <td align="left"><input name="student_password" type="password" id="student_password"><
/td>

and this is my handler.

<?php
	session_start();
	include 'Connect.php';
	$flag = "";
	$learner_id = $_POST['learner_id'];
	$student_id = $_POST['student_id'];
	$student_password = $_POST['student_password'];
	$query = "select last_login_date from student_information where student_id='$student_id' and student_password='$student_password'";
	$result = mysql_query($query,$link_id);
	if(mysql_error() != null){
		die(mysql_error());
	}
	if($date = mysql_fetch_array($result))
	{
        $lastdate = $date['last_login_date'];
	$date2 = date("d-m-Y h:i A",strtotime($lastdate));
	$_SESSION["student_id"] = $_POST["student_id"];
        $_SESSION["lastlogin"] =$date2;
	$_SESSION["type"] = "Student";
	mysql_query("UPDATE student_information SET last_login_date=now() where student_id='$student_id'",$link_id);
	if(mysql_error() != null){
	die(mysql_error());
	}
	header("location:  Student_Home.php?id={$student_id}");
		 die();
	}
	else
	{
		$flag = "invalid";
		header("location:Student_login.php?flag=$flag");
		die();		
	} 	
?>

PLease help me PHP friends to correct my codes.

Howdy Colleagues,   I was wondering whether you know ways/websites/channels/magic owls to how to help find a job in USA as a programmer as in for relocating there while the company pays for the Visa and the travel expenses?   My land-lord's son found a job as a programmer in Texas and the company was generous and kind enough to pay his travelling expenses, as well for his wife and kid.    I have an account in Monster & Indeed and I send CVs very often, but no luck so far.   And I want to go there to work and live, not like some people to rely on welfare, I have worked my whole life.    Thank you!   BR, Stefany

User submits 1 or more refrerences via a form.  On the action page I want to check if any id's on the page match any values submitted in $_POST.
Code: [Select]
$Ref = $_POST['Ref'];
$source = file_get_contents( 'E:/wamp/www/Project/File.php' );
$document = new DOMDocument;
$document->validateOnParse = true;
$document->LoadHTML($source);
for($i=0; $i<count($Ref); $i++)
{
$ID = $document->getElementById('$Ref[$i]');
}
I have a table on the source page with the same id as a reference contained in $Ref, but getElementById is not seeing/recognsing it.   No idea why not.

My query is not finding the last recieptnum entry, it is finding the number 9 everytime for some odd reason. Im trying to incrementally increase this each time a reciept is created.

$getreceiptnum = mysql_query("SELECT receiptnum FROM accounting WHERE agency = '$agency' ORDER BY receiptnum DESC LIMIT 1") or die(mysql_error());
        $recieptarray = mysql_fetch_array($getreceiptnum);
        $recieptnum = $recieptarray['receiptnum'];
        echo $recieptnum;

I am trying to find the URL to a directory TWO levels above the script level (if you know what I mean).

For example.. the script sits at
Code: [Select]
http://www.domain.com/TestArea2/members/index.php
BUT I need to find the path to 
Code: [Select]
http://www.domain.com/TestArea2/

the nearest I get is...


$domain = $_SERVER['HTTP_HOST'];
$domain .=  $_SERVER['REQUEST_URI'];
echo $domain; // outputs www.domain.com/TestArea2/members/index.php 



Is there a simple method to do this or have I got to split the string and work backwards?

Many thanks