PHP - List All Files In A Directory Including Sub-folders

Hello. I have a directory with files that look like this:

priceguide_20100809.pdf
priceguide_20100808.pdf
priceguide_20100807.pdf
priceguide_20100806.pdf

I am trying to come up with a function that will grab and save the filename with the biggest date .. ie: priceguide_20100809.pdf.

Any assistance would be greatly appreciated!!

Hi, I have coded a site, whereby users can log in, and depending on their group, view all files within their group directory:
Code: [Select]
if ($handle = opendir("storage/Admin/$group")) {
while (false !== ($file = readdir($handle))) {
        if ($file != "." && $file != "..") {
            echo "<a target=\"_blank\" href=\"storage/Admin/$group/$file\">$file</a> <br />";
        }
}
closedir($handle);
}
In this example, a user can click on their file, and it will let them download it, but if there is a folder (directory) in there, once clicked on, it will open a  index of the directory.

Is there a way instead, to let it open a custom page and list the files within it there?

i have some questions on how folders and files permissions work. say i have users directories outside 'protected' as below..

Code: [Select]
users
 -- usera
   -- docs
 -- userb
   -- docs
protected

i do not want user B who does not have the rights, to access anything in user A directories. also, i do not want any person to access the directories directory via url links. basically i just want users to be able to access their own directories, and no one else. how can it be done?

thanks!

Suppose, i have created a sub.domain.com and i want to include a file 'config.php' from root directory i.e domain.com . While i tried include("../config.php"); i wasn't successful. Anyone can help me please??
I need the solution very urgently, so please help me soon.
pracasify@yahoo.com
facebook.com/agptj

hello, I have implemented a snippet that reads images in
I create folders dynamically from admin and makes them see
lightbox style .. the same works fine but it shows all
images in all folders and not those relating to
folder clicked ..
The result you can see it he
aires-restauro.org/beta/gallery2.php

code:
<?php
$folder = opendir('gallery/');
echo "<gallery>";
while ($file = readdir($folder)) {
if($file != '.' && $file != '..'){
echo "<album path='gallery/$file/' name='$file'>";
$subfolder="gallery/".$file."/";
$subfolderdir = opendir($subfolder);
while ($subfile = readdir($subfolderdir)) {
if($subfile != '.' && $subfile != '..'){
echo "<a href='$subfolder$subfile' class='pirobox_gall'>$file</a>";
}
}
echo "</album>";
}
}
echo "</gallery>";
?>


repeats the same directory as I would like to see that by clicking the directory do see the images of that directory

sorry but I do not speak English well and I thank you in advance

hi all

i am looking for the quickest way to zip all files and folder of a website i am currently using the followning.

<?php
$date = date("F-j-Y-g-ia");

if(exec("cd /home/isd/public_html/bk/files;tar -cvpzf backup-$date.tar /home/isd/public_html")) {

echo "done";

 
 

}  

?>

This works but was just wondering if anyone can give me and insight on a better solution??

Thanks

i have made an delete files script which works for only one directory but not sub directory so i want to delete files of same extention from directory and subdirectory.

My current code is

Code: [Select]

<?

$dir = 'hmm/';

function scanr($dir){

$arr = glob($dir.'/*.jpg');
foreach($arr as $vv){



//check if $vv is a file
if(is_file($vv)){

//if file, get the filename
$vx=explode('/',$vv);
$file=$vx[count($vx)-1];


// if no extension delete the file
unlink($vv);
// print the deletion message
echo $vv." deleted!<br>";}else{
// if $vv is a dir then scan it again for files
scanr($vv);
}}
}

scanr($dir);
?>

Hi all, I've got two scripts for my website which I would like to display on one page, but what i've got is, The Menu on one php file, and the content on a different php file. Ive tryed the include, include_once, require, require_once, but for which ever one I use it just displace a blank page with nothing on it.

Both of the files work on there on, but when I include the menu to the content page it just dont show anything. This is what ive tryed:


<?php
include ("crewtop.php");
if ($crewstuff->boss == $username || $crewstuff->coowner == $username || $crewstuff->underboss == $username){
?>
<table width='80%' align='center' class='table' cellpadding='0' cellspacing='0' border='1'>
<tr>
<td class='header' colspan='4' align='center'>Current Crew Members</td>
</tr>
<tr>
<td class='omg' align='center' width='25%'>Username</td><td class='omg' align='center' width='25%'>Rep</td><td class='omg' align='center' width='25%'>Rank</td><td class='omg' width='25%' align='center'>Kick</td>
</tr>


This seems a easy thing to sort, just I carnt see why it isnt displaying the other file.. Anyone see why?

Thanks.

(if more code is needed i'll display more)

I have a class which loads language files and adds the content(which is an array) into a phrases array. It's performed perfectly when i included common_lang.php and login_lang.php. However when i include common_lang.php and profiles_lang.php something weird happens.

I have a blank space at the top of the profile pages. And firebug reports that the content of <head> is now empty and its shifted all of it to the <body>.

Like i say this only happens when including profiles_lang.php but works with other files like login_lang.php.

The content of each language file is the same apart from the data in the array.


$l = array(
'USERNAME'    => 'Username',
);


this is the language class which is being called in profiles.php like Asf_Language::loadFile('profiles'); The same call is used in other pages replacing 'profiles' with the name of the language file to call.


<?php
/* ASF A Simple Forum
 * (c) ASF A Simple Forum 2010 - 2011
 * 
 * @licence        http://www.asimpleforum.co.uk/licence
 * 
 * $page        includes/languageClass.php
 * $author         Carl Markham
 * $created        14/06/2011
 */
 
class Asf_Language
{
    public static $lang;
    
    public static $phrases = array();
    
    public static $loaded_langs = array();
    
    public function __construct($default)
    {
        $this->setLang($default);
        self::loadFile('common');
    }
    
    public static function setLang($lang)
    {
        self::$lang = $lang;
    }
    
    public static function getLang()
    {
        return $lang;
    }
    
    public static function loadFile($file)
    {
        $include = dirname(dirname(dirname(__FILE__))).'/languages/'.self::$lang.'/'.$file.'_lang.php';
        
        if(file_exists($include))
        {
            include($include);
            
            self::$loaded_langs[] = $file;
            
            foreach($l as $key => $val)
            {
                self::$phrases[$key] = $val;
            }
        }
        else
        {
            echo 'File '.$include.' does not exist';
        }
        
        return;
    }
    
    public static function getLoadedLanguages()
    {
        return implode(', ',self::$loaded_langs);
    }
}


Anyone have any ideas why the head is being emptied when this file is being included?

I am making a framework for my site, and I have a folder which defines some things. One thing it defines is the location of the frame work:
define('FRAMEWORK', '../../../framework');

Next I include a specific class that I include:
include FRAMEWORK.'/commons/Music.php';

This class extends the main framework
include '../Weblyize.php';
class Music extends Weblyize{
// Some code
}

This issue I am currently having is Warning: include(../Weblyize.php) the file Weblyize.php is a directory above Music.php

So, here is where the webpage is located:
http://96.42.108.211:3333/templates/music/music1/about.php

Here is where the two classes are located (sub classes are in commons)
http://96.42.108.211:3333/framework/Weblyize.php
http://96.42.108.211:3333/framework/commons/Music.php

What is a good way to link the files together with out this breaking no matter where the framework directory is located?

Hello everyone,

This is a fairly simple question, but the explanation of the question isn't... I'll do my best.

I have a site where my folders/sub-folders/files are arranged similar to this:
                     _                       
Root Folder -| Root-IncludeFile1.php
                    | Root-IncludeFile2.php
                    |                         _
                    |  Sub-Folder 1 -| Sub1-File1.php
                    |                        |_Sub1-File2.php
                    |                        _
                    | Sub-Folder 2 -| Sub2-File1.php
                    |                       |_Sub2-File2.php
                    |                         _
                    |_Sub-Folder 3 -| Sub3-IncludeFile1.php
                                             |_Sub3-IncludeFile2.php

Hopefully that makes sense to everyone.  Anyway, I know that to include a file that is in the root folder in file in a sub-folder, I can do this - include("../includefile1.php"); -but I'm trying to include a file that is in a sub folder in a file that is in another sub-folder.  For example, I'm trying to include "Sub3-IncludeFile1.php" in "Sub-File1.php"  I'm lost on this because I can't get it to work.  I'm not getting any error messages except to say that the variables located in the file that should be included are not found.

I've tried to do this: include("http://www.mysite.com/Sub-Folder3/Sub3-IncludeFile1.php"); and it doesn't work.  Can someone please point me in the right direction?  Thanks in advance for your help.

I am developing a CMS for my clients where the login to administrate their website is through my own website. This unified back-end allows me to develop the functionality and user experience without the issue of updating each site manually with the new files or running a complicated macro etc and then uploading them all individually too.

I would also like to combine as much of the "client side" CMS code too, i.e. as many of the php files that are stored on the clients website as possible.

All of the websites (and the backend website) are located on the same VPS, running PHP V5.3, allow_url_include is not available, I could have it turned on but this causes security issues if I understand correctly?

I figure my main options a

- Turn on allow_url_include and just include via IP/Domain.

- Use a FTP system similar to the way Wordpress allows remote install of plugins and system updates.

or

- Include the files using a different /home/username/cmsincludes/ path? Is it possible to use another VPS account to include from? I have tested and it gives me a "failed to open stream" error.
Example:

Client xyz Website
Website located: /home/xyz/public_html/
CMS Included: /home/mainsite/cms/

Client 123 Website
Website located: /home/123/public_html/
CMS Included: /home/mainsite/cms/

Client xxx Website
Website located: /home/xxx/public_html/
CMS Included: /home/mainsite/cms/

Hello


I have a simple question about file handling...


Is it possible to list all files in directories / subdirectories, and then read ALL files in those dirs,
and put the content of their file into an array?

Like this:

array:
[SomePath/test.php] = "All In this php file is being read by a new smart function!";
[SomePath/Weird/hello.txt = "Hello world. This is me and im just trying to get some help!";

and so on, until no further files exists in that rootdir.

All my attempts went totally crazy and none of them works... therefore i need to ask you for help.


Do you have any ideas how to do this?
If so, how can I be able to do it?


Thanks in Advance, pros

Hi guys,
I am using a MySQL table to store if a user has access permisisons to a file.

The files are stored outside the webdirectory in drive F:\

So I have this code I have been playing around with in order to display the file I access and check permissions for:
<?php
$file = $_GET['file'];

$myfile = 'F:\files\/'.$file.'.jpg';

echo "<img src='$myfile' />";
?>


So a sample case would be say on index.php
<img src="http://somedomain.com/files?file=abcdefghijkl" />
and only if the current user had permissions to view that file would they see it.

Any help on how I can do this is greatly appreciated.

I do understand all my above code is probably totally wrong.

Cheers

I almost have it but can't figure why the code below only shows one file per folder.

I think it is showing the last file.

I need $ul somehow looping to show all the files in $file.


<?php
$year = date('Y');

if ($handle = opendir("results/$year/Boys")) {

while (false !== ($file = readdir($handle))) {

if ($file != "." && $file != "..") {

if ($handle2 = opendir("results/$year/Boys/$file")) {

while (false !== ($file2 = readdir($handle2))) {

if ($file2 != "." && $file2 != "..") {
$ul = "<li><a href=\"#\">$file2</a></li>";

$li =  "<li><a target=\"_blank\" href=\"javascript:void(0)\">$file</a>
<ul>
$ul
</ul>
</li>";

} // close if file2
}echo $li;
}
}
}
}closedir($handle);closedir($handle2);
?>