PHP - Defining A Variable

Hello Guys   I need help.   I found one PHP script for simple auto update of "system" (automatic updating of website for example)

http://maxmorgandesign.com/simple_php_auto_update_system/

I want to adjust this script for my project,  and In this code there is a line (on line 10):

 echo '<p>CURRENT VERSION: '.get_siteInfo('CMS-Version').'</p>';

which variable should write in my page to define curent version of CMS?   I try to googleit but unsuccessful :-/   Many thanks

I need to define a query in a PHP script that will check a MySQL db - based on six variables (the six variables are statically defined
 within the script based on another snippet of code reading the new file that's being prepared for insertion into the db.)

Objective: if the six variables, from the new records, does not produce an exact match already within the db based on ($rcheck)
then insert the new record into the db. Note: I have the INSERT statement working correctly but having issues with the query ($rcheck).

As for the records being checked by ($rcheck) in the MySQL db: they are all UNIQUE records based on the six fields
I'm trying to build the query around to ensure no DUPLICATE entries are made with new insertions.
-------------------

Issue: I can't get the query ($rcheck) to fire correctly to check the queued (new records' data) against the db - based on six fields of data.
Error: Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource.

FYI: if I just do a standard "SELECT * FROM information"; the quey works as it should but I need to check the db based on the six fields as shown in below code:



$rcheck = "SELECT docno,fdate,ftime,vegregno,direction,grossmass FROM information where docno = $docnoNew 
AND fdate = $fdateNew AND ftime = $ftimeNew AND vegregno = $vegregnoNew AND direction = $directionNew 
AND grossmass = $grossmassNew;";

$duplicate = mysql_query(rcheck);    // Execute query to check for duplicate transaction in table

        while ($row = mysql_fetch_array($duplicate)) {

            echo $row['docno']."<br/>";
            echo $row['fdate']."<br/>";
            echo $row['ftime']."<br/>";
            echo $row['vegregno']."<br/>";
            echo $row['direction']."<br/>";
            echo $row['grossmass']."<br/>";
}



I know the problem rests with trying to use multiple "AND" clauses but I'm not sure how to get around this issue.
Any advice on how to define this query to check based on all six fields surely appreciated to get ($rcheck) working!

thanks

Can someone help me out, I had a guy make some great changes to a script. works perfectly - however I want to modify it further and he's unavailable till tomorrow to discuss.

Hopefully someone will be able to guide me:

define('TBL_PROFILE_COUNTRY_FILTER', '`country_id` = \'IE\'');

This line is based on users in a database from Ireland (IE) but what I need to do is make it so that this TBL_PROFILE_COUNTRY_FILTER doesnt just filter Ireland members but also those from Northern Ireland (Ni) as well.

So my question is this - can I (and if so how) - can I add Ni to this define statement.

Grateful for any guidance (php isn't my thing at all but I'm trying to pick up what I need when I need it).

Thanks again.

// does the product exist ?
$sql = "SELECT pd_id, pd_qty
        FROM tbl_product
WHERE pd_id = $productId";
$result = dbQuery($sql);

if (dbNumRows($result) != 1) {
// the product doesn't exist
header('Location: cart.php');
} else {
// how many of this product we
// have in stock
$row = dbFetchAssoc($result);
$currentStock = $row['pd_qty'];

if ($currentStock == 0) {
// we no longer have this product in stock
// show the error message
setError('The product you requested is no longer in stock');
header('Location: cart.php');
exit;
}

}

// current session id
$sid = session_id();
session_register("size");
$size = $_SESSION['size'];
// check if the product is already
// in cart table for this session
$sql = "SELECT pd_id
        FROM tbl_cart
WHERE pd_id = $productId AND ct_session_id = '$sid'";
$result = dbQuery($sql);

if (dbNumRows($result) == 0) {
// put the product in cart table
$sql = "INSERT INTO tbl_cart (pd_id, ct_qty, size, ct_session_id, ct_date) " .
"VALUES ($productId, 1, '$size', '$sid', NOW())";
$result = dbQuery($sql);
} else {
// update product quantity in cart table
$sql = "UPDATE tbl_cart 
        SET ct_qty = ct_qty + 1
WHERE ct_session_id = '$sid' AND pd_id = $productId";

$result = dbQuery($sql);
}



This is just a piece of my cartfunctions.php (which is an include() once you add an item to the cart).
I've been trouble shooting this all day and finally got it to stop giving me error messages. Im trying to allow the user to pick a size between 4 options, after that it is added to the cart and I can easily find out what size shirt the customer wants before I ship it. but now it wont update the $size variable to the DB. Am I defining this wrong or maybe my whole approach is messed up? If you would like to see the setup you can go to rbcrime.com/newshop/newshop/ .

Hi,
I my first problem is hashing passwords to md5.
My second problem is defining session on value from db.
There is my code but not working.
Code: [Select]
mysql_connect("$host", "$username", "$password")or die("cannot connect");
mysql_select_db("$db_name")or die("cannot select DB");

 
$username=$_POST['username'];
$password=$_POST['password'];
$hash = md5($password);


$username = stripslashes($username);
$password = stripslashes($password);
$username = mysql_real_escape_string($username);
$password = mysql_real_escape_string($password);

$sql="SELECT * FROM $tbl_name WHERE where username = '$username' and password = '$hash'";
$result=mysql_query($sql);

$count=mysql_num_rows($result);

if($count==1){
$sql2="SELECT access FROM $tbl_name WHERE username='$username' and password='$password'";
$access=mysql_query("$sql2");
session_register("username");
session_register("password");
session_register("access");
$_SESSION["access"]=$access;
header("location:success.php");
}
else {
echo "Invalid Username or Password";Thanks for any answers.

I have a search code for my site and I want to narrow the scope of the search with a drop down that will allow users to pick a state, ( the sql table includes a state field ) or set the script so that i will only search for results for a particular state.
In the sql select I have tried every way of using WHERE venue_state='NY' but it will not work.
I would really rather allow the users to select a state from a dropdown and then enter the search term - city, zip or venue name.
Thank you for looking

Code: [Select]
<?php
include('config.db.php');
$find  = trim($_GET['find']);
$field = $_GET['field'];


if($find && $field) { // we have search form submitted
   // check for values to prevent sql injection
   $valid_fields = array("venue_zip", "venue_city" , "show_name");
   if(!in_array($field, $valid_fields)) die("Error: Invalid field!");
   
   $rpp = 10; // results per page
   $adjacents = 4;
   
   $page = intval($_GET["page"]);
   if(!$page) $page = 1;
   
   $reload = $_SERVER['PHP_SELF'] . "?find=" . urlencode($find) . "&amp;field=" . urlencode($field);
   
   echo "<h4>Search Results for $find</h4>\n";
   
   
   $find = addslashes($find);
     $result = mysql_query("SELECT *, DATE_FORMAT(`start_date`, '%b %e, %Y') AS s_date FROM craft_shows WHERE $field LIKE '%$find%'");
   if(mysql_num_rows($result) == 0) {
      echo "<p>0 matches found.</p>";
   } else {
      echo "<table class='table7' cellpadding='2'>";
      echo "<tr><td>&nbsp;</td><td><strong>Date</strong></td><td><strong>Show Name</strong></td><td><strong>City</strong></td><td><strong>Attendance</strong></td></tr>";
      echo "<tr><td colspan='5'><hr class=\"hr2\"></td></tr>";
      
      // count total number of appropriate listings:
       $tcount = mysql_num_rows($result);
      
      // count number of pages:
      $tpages = ($tcount) ? ceil($tcount/$rpp) : 1; // total pages, last page number
      
      $count = 0;
      $i = ($page-1)*$rpp;
      while(($count<$rpp) && ($i<$tcount)) {
         mysql_data_seek($result,$i);
         $row = mysql_fetch_array($result);
         $id = $row['id'];
         echo "<tr><td>";
         echo "<a href=\"/show_submits/show_detail.php?id=$id\">Details</a>";
         echo "</td><td>";
         echo $row['s_date'];
         echo "</td><td>";
         echo $row['show_name'];
         echo "</td><td>";
         echo $row['venue_city'];
         echo "</td><td>";
         echo $row['venue_state'];
         echo "</td></tr>";
echo "<tr><td colspan='5'><hr class=\"hr3\"></td></tr>";
         $i++;
         $count++;
      }

      echo "</table><br>";
      
function paginate_one($reload, $page, $tpages) {
   
   $firstlabel = "First";
   $prevlabel  = "Prev";
   $nextlabel  = "Next";
   $lastlabel  = "Last";
   
   $out = "<div class=\"pagin\">\n";
   
   // first
   if($page>1) {
      $out.= "<a href=\"" . $reload . "\">" . $firstlabel . "</a>\n";
   }
   else {
      $out.= "<span>" . $firstlabel . "</span>\n";
   }
   
   // previous
   if($page==1) {
      $out.= "<span>" . $prevlabel . "</span>\n";
   }
   elseif($page==2) {
      $out.= "<a href=\"" . $reload . "\">" . $prevlabel . "</a>\n";
   }
   else {
      $out.= "<a href=\"" . $reload . "&amp;page=" . ($page-1) . "\">" . $prevlabel . "</a>\n";
   }
   
   // current
   $out.= "<span class=\"current\">Page " . $page . " of " . $tpages . "</span>\n";
   
   // next
   if($page<$tpages) {
      $out.= "<a href=\"" . $reload . "&amp;page=" .($page+1) . "\">" . $nextlabel . "</a>\n";
   }
   else {
      $out.= "<span>" . $nextlabel . "</span>\n";
   }
   
   // last
   if($page<$tpages) {
      $out.= "<a href=\"" . $reload . "&amp;page=" . $tpages . "\">" . $lastlabel . "</a>\n";
   }
   else {
      $out.= "<span>" . $lastlabel . "</span>\n";
   }
   
   $out.= "</div>";
   
   return $out;
}
   echo paginate_one($reload, $page, $tpages, $adjacents);
   }
}
?>

echo "bitches" . "<br />";

class classname

{

function _contruct($param)
{
echo "Contructor called with parameter ".$param;
}

}

$a = new classname("First");
$b = new classname("Second");



I'm trying to run this code but it's not giving me any output.

Output should be very simple, e.g, Constructor called with parameter First.

Please help.

Hello,

I'm using the below code to determine whether fields have been left blank, however, it only a standard sentence, i'd like to customise it, like: "Email has been left blank" or The email and message has been left blank. My best preference would be to bullet point each line. IE:

Email has been left blank. Message has been left blank.

$name = $_POST['name'];
$visitor_email = $_POST['email'];
        $user_message = $_POST['message'];
if(empty($name)|| empty($visitor_email)|| empty($user_message))
{
$errors .= "\n Some of the above fields have not been filled in.<br><br> ";
}


Many thanks.

Hey Guys. I came across this code example below assigns array values to a private property. However the private property is not defined as an array. It was a bit confusing to me because I always thought you need to define  the property as an array first. If someone can please help me understand this concept I would really appreciate it.   Below is the code.

<?php 


class Product {

	public $name; 
	public $price; 

	function __construct($name, $price){
		$this->name = $name; 
		$this->price = $price;

	}


}


class ProcessSale {
	private $callbacks; // This holds an array but is not defined as an array?


	function registerCallback($callback) {
		if(!is_callable($callback)) {
			throw new Exception("Callback Is Not Callable");
			
		}
		$this->callbacks[] = $callback;
	}


	function sale($product) {
		print "{$product->name}: processing \n";
		foreach ($this->callbacks as $callback) {
			call_user_func($callback, $product);
		}
	}
}


$logger = function($product) {
	print "logging ({$product->name})\n";
};


$processor = new ProcessSale();
$processor->registerCallback($logger);

$processor->sale(new Product("shoes", 6));
echo  "\n";
$processor->sale(new Product("coffee", 6));

i am building a reservation system
i have special date blocks which have different price tags

for example reservation for
01/12/2011-07/12/2011

where
03/12/2011-06/12/2011 prices +15%

how would i define the range for special dates?

$poststart = "<!-- Begin -->"; $poststop = "<!-- End -->";   $parsedpost1 = explode($poststart, $contenu); $parsedpost2 = explode($poststop, $parsedpost1[1]); $contenu = $parsedpost1[0] . $poststart . $newpost . $poststop . $parsedpost2[1];   The above code will set 2 markers and replace whatever inside by $newpost, which is defined elsewhere in the page. But what if $newpost is so long that I'd be more comfortable storing it in a separate file?    How would I go about calling said file on that last line? (I'm referring to the specific syntax.)   Thx

I am trying to allow the user to update a variable he chooses by radio buttons, which they will then input text into a box, and submit, to change some attributes. I really need some help here.  It works just fine until I add the second layer of variables on top of it, and I can't find the answer to this question anywhere.

<?PHP require('connect.php'); ?>

<form action ='' method='post'> <select name="id">

<?php
$extract = mysql_query("SELECT * FROM cars");
   
   while($row=mysql_fetch_assoc($extract)){
   $id = $row['id'];
   $make= $row['make'];
   $model= $row['model'];
   $year= $row['year'];
   $color= $row['color'];

echo "<option value=$id>$color $year $make $model</option>
";}?>

</select>

Which attribute would you like to change?<br />
<input type="radio" name="getchanged" value="make"/>Make<br />
<input type="radio" name="getchanged" value="model"/>Model<br />
<input type="radio" name="getchanged" value="year" />Year<br />
<input type="radio" name="getchanged" value="color"   />Color<br /><br />

   <br /><input type='text' value='' name='tochange'>
   <input type='submit' value='Change' name='submit'>

</form>

//This is where I need help...

<?PHP
if(isset($_POST['submit'])&&($_POST['tochange'])){
mysql_query("
   UPDATE cars
   SET '$_POST[getchanged]'='$_POST[tochange]'
   where id = '$_POST[id]'
         ");}?>

Hello all. I am very new to PHP, and I am not sure where to look or what I'm looking for in my current assignment.

My task is to take in two numbers between 0-100. Once I take in that number, it should state beside it "The __ was accepted."
The program should not accept any numbers greater than 100 or any characters.

Once I do this, I must take a second number and do a similar thing.

Finally, I must have a statement show up at the bottom stating which number is greater.

Essentially, I need help in determining what I should use to place parameters, and how I can keep the program from echo ing any statement until input has been taken and tested for parameters.

Any help you can provide will be greatly appreciated!

My login script stores the user's login name as $_SESSION[ 'name'] on login. For some unapparent reason, i'm getting errors stating that $user  and $priv are  undefined variables, though I've attempted to define $user as being equal to $_SESSION['name'], using $user to look up the the user's privilege level (stored as the su column ) in the SQL table, and then where the result of the sql query is $priv which is then evaluated in an if statement. I can't seem to figure out why this might not be working.

The code I'm using:

<?php
session_start();
function verify() {
	//verify that the user is logged in via the login page. Session_start has already been called. 
	if (!isset($_SESSION['loggedin'])) {
	header('Location: /index.html'); 
	exit;
	}
	//if user is logged in, we then lookup necessary privleges. $_SESSION['name'] was written with the login name upon login. Privleges   // are written in db as a single-digit integer of of 0 for users, 1 for administrators, and 2 for special users. 
        $user === $_SESSION['name'];
    //Connect to Databse
	$link = mysqli_connect("127.0.0.1", "database user", "password", "database");
	if (!$link) {
  	  echo "Error: Unable to connect to MySQL." . PHP_EOL;
    	echo "Debugging errno: " . mysqli_connect_errno() . PHP_EOL;
    	echo "Debugging error: " . mysqli_connect_error() . PHP_EOL;
    	exit;
        }
        //SQL Statement to lookup privlege information. 
       if ($result = mysqli_query($link, "SELECT su FROM accounts WHERE username = $user", MYSQLI_STORE_RESULT)) {
         //LOOP TO CYCLE THROUGH SQL RESULTS AND STORE Privlege information as vairable $priv.
            while ($row = $result->fetch_assoc()) {
           $priv === $row["su"];
            }
        }
        // close SQL connection.
        mysqli_close($link);

 // Verify privleges and take action. Only a privlege of "1" is allowed to view this page. A privlege of "2" indicates special 
//accounts used in other scripts that have certain indermediate additional functions, but are not trusted administrators. 

        if ($priv !== 1) {
        echo $_SESSION['name'];
        echo "you have privlege level of $priv";
        echo "<br>";
        echo 'Your account does not have the privleges necessary to view this page';
        exit;
        }
        
}
verify();
?>

 

I have just re-installed Xampp and suddenly my sites are now displaying lots of:

Notice: Use of undefined constant name - assumed 'name' in ...
Notice: Use of undefined constant price - assumed 'price' in ...

this is an example of the line its refering too:

$defineProducts[1001] = array(name=>'This is a product', price=>123);