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PHP - Iis 5.1 Php 5.2.17, No Mysql - Html Form To Write Php With Form Data Saved
There are two pieces to this- The HTML Form and the resulting php. I can't seem to make the leap, from the code to having the form produce the php page so others can view it until the form is again submitted overwriting the php, thus generating new content.
The environment I am working in is limited to IIs 5.1 and php 5.2.17 without mySQL or other DB I'm new to php, this isn't homework,or commercialization, it's for children. I am thinking perhaps fwrite / fread but can't get my head around it. Code snipets below. Any help, please use portions of this code in hopes I can understand it Thanks Code snipet from Output.php Code: [Select] <?php $t1image = $_POST["t1image"]; $t1title = $_POST["t1title"]; $t1info = $_POST["t1info"]; $t2image = $_POST["t2image"]; $t2title = $_POST["t2title"]; $t2info = $_POST["t2info"]; ?> ... <tbody> <tr><!--Headers--> <td style="vertical-align: top; text-align: center; background-color: rgb(204, 255, 255);">Animal</td> <td style="vertical-align: top; text-align: center; background-color: rgb(204, 255, 255);">Image thumb<br> </td> <td style="vertical-align: top; text-align: center; background-color: rgb(204, 255, 255);">Date<br> </td> <td style="vertical-align: top; text-align: center; background-color: rgb(204, 255, 255);">Information<br> </td> </tr> <tr> <td style="vertical-align: top; text-align: center;">Monkey </td> <td style="vertical-align: top; text-align: center;"><img src="<?php echo $t1image.'.gif'; ?>"><!--single image presented selected from radio buttons--> </td> <td style="vertical-align: top; text-align: center;"><?php echo date("m/d/Yh:i A"); ?><!--time stamp generated when submitted form populates all fields at once--> </td> <td style="vertical-align: top; text-align: center;"><a href="#monkey" rel="facebox"><?php echo $t1title ?></a><!--Link name provided by "Title 1", that links to hidden Div generated page with content from "Info1" field--> <div id="Monkey" style="display:none"> <?php echo $t1info; ?> </div> </td> </tr> <tr> <td style="vertical-align: top; text-align: center;">Cat<br> </td> <td style="vertical-align: top; text-align: center;"><img src="<?php echo $t2image.'.gif'?>"></td> <td style="vertical-align: top; text-align: center;"><?php echo date("m/d/Yh:i A"); ?></td> <td style="vertical-align: top; text-align: center;"><a href="#Cat" rel="facebox"><?php echo $t2title ?></a> <div id="Cat" style="display:none"> <?php echo $t2info; ?> </div> </td> </tr> <tr> This replicates several times down the page around 15-20 times ( t1### - t20###) Code Snipet from HTML Form Code: [Select] <form action="animals.php" method="post"> <div style="text-align: left;"><big style="font-family: Garamond; font-weight: bold; color: rgb(51, 51, 255);"><big><big><span>Monkey</span></big></big></big><br> <table style="text-align: left; width: 110px;" border="0" cellpadding="2" cellspacing="0"> <tbody><tr> <td style="vertical-align: top;">Image thumb<br> <input type="radio" name="t1image" value="No opinion" checked><img src="eh.gif" alt="Eh"> <input type="radio" name="t1image" value="Ok"><img src="ok.gif" alt="ok"> <input type="radio" name="t1image" value="Like"><img src="like.gif" alt="Like"> <input type="radio" name="t1image" value="Dont"><img src="dont.gif" alt="Don't Like"> <input type="radio" name="t1image" value="Hate"><img src="hate.gif" alt="Hate"> <input type="radio" name="t1image" value="Other"><img src="other.gif" alt="Other"> <br> Why Title:<input type="text" name="t1title" size="45" value="..."/></td> <td style="vertical-align: top;"> Explain:<br> <textarea name="t1info" cols=45 rows=3 value="..."></textarea> </td></tr></table> <br> <!--Next--> How do I get the Form data to save to the php page for others to view? Similar TutorialsHi. Can someone show me the proper way to do a feedback form (like a "Contact US" form). I have read about SQL injections and would like to know I am protecting against it. And the proper way to store the submitted data in a database for a client's records. I have a basic form I use, but I am unable to store the data properly. Any help or a code idea would be appreciated. Thanks much. Hello Im quite confused at what filtering I should use on my data when pulling it from a MySQL database. I don't sanitize my data on input because I am using prepared statements with PHP's PDO Driver which means I don't need to use mysql_real_escape_string() at all. When I pull the data to be displayed i.e. in a HTML Table I use the below function to make it safe for HTML output. public static function htmlSafe($data) { return nl2br(htmlentities($data, ENT_QUOTES)); } However the rules change when Im using a HTML Form to edit the data, and I am unsure what I need to strip out. I.e. What would I need to do to make all data safe to insert into the following form input. <input id = "someInput" type = "text" value = "<?php echo $someVarThatNeedsFiltering ?>" /> Also, one more question, in my html attributes (Valid ones like class, name, id, style, _target) I use a mixture of double quotes(") and single quotes ('), for quoting my values. Which one should I use or which one is more valid, doubles, or singles? I have a form on our website that a user can fill out for custom product. I want the form data to be 1) stored into a mysql database AND after storing said data, 2) email the same data to our sales department. 1) The form data DOES get stored into mysql database (except for the first two fields, for some weird reason) 2) I added a "mail" section to the php file that stores the data into the database, but it is not working correctly. I have stripped the email portion down to sending just one of the fields in the "message" to make it easier for troubleshooting I have included here, both the form section of the html file, and the formdata.php file that processes the data for your analysis. I am relatively new to php so there are going to be some issues with security, but I can work on those after I get the store & email process to work correctly. Please review my code and see if anyone can be of assistance. I looked through the forums and couldn't find another issue that was the same as mine. If I just overlooked, please tell me the thread post #. Thanks THE FORM WHICH COLLECTS THE DATA ******************************* <form method=POST action=formdata.php> <table width="640" border=0 align="center"> <tr> <td align=right><b>First Name</b></td> <td><input type=text name=FName size=25></td> <td><div align="right"><b>Telephone</b></div></td> <td><input type=text name=Tel size=25></td> </tr> <tr> <td align=right><b>Last Name</b></td> <td><input type=text name=LName size=25></td> <td><div align="right"><b>Fax</b></div></td> <td><input type=text name=Fax size=25></td> </tr> <tr> <td align=right><b>Title</b></td> <td><input type=text name=Title size=25></td> <td><div align="right"><b>Email</b></div></td> <td><input type=text name=Email size=50></td> </tr> <tr> <td align=right><b>Company</b></td> <td><input type=text name=Comp size=25></td> <td> </td> <td> </td> </tr> <tr> <td align=right><b>Address</b></td> <td><input type=text name=Addr size=25></td> <td><div align="right"><b>Estimated Annual Volume</b></div></td> <td><input type=text name=EAV size=25></td> </tr> <tr> <td align=right><b>City</b></td> <td><input type=text name=City size=25></td> <td> </td> <td> </td> </tr> <tr> <td align=right><b>State/Province</b></td> <td><input type=text name=SProv size=25></td> <td><div align="right"><b>Application</b></div></td> <td><input type=text name=Appl size=25></td> </tr> <tr> <td align=right><b>Country</b></td> <td><input type=text name=Ctry size=25></td> <td><div align="right"><b>Type of System</b></div></td> <td><input type=text name=Syst size=25></td> </tr> <tr> <td align=right><b>Zip/Postal Code</b></td> <td><input type=text name=ZPC size=25></td> <td> </td> <td> </td> </tr> <tr> <td align=right> </td> <td> </td> <td> </td> <td> </td> </tr> <tr> <td align=right> </td> <td><div align="right"><strong><font color="#FFFF00" face="Arial, Helvetica, sans-serif">COIL DESIGN</font></strong></div></td> <td><font color="#FFFF00" face="Arial, Helvetica, sans-serif"><strong>PARAMETERS</strong></font></td> <td> </td> </tr> <tr> <td align=right> </td> <td> </td> <td> </td> <td> </td> </tr> <tr> <td align=right><b>Primary Resistance (ohms)</b></td> <td><input type=text name=Pres size=25></td> <td><div align="right"><b>Primary Inductance (mH)</b></div></td> <td><input type=text name=Pind size=25></td> </tr> <tr> <td align=right><b>Secondary Resistance (ohms)</b></td> <td><input type=text name=Sres size=25></td> <td><div align="right"><b>Secondary Inductance (H)</b></div></td> <td><input type=text name=Sind size=25></td> </tr> <tr> <td align=right> </td> <td> </td> <td> </td> <td> </td> </tr> <tr> <td align=right><b>Peak Operating Current (Amps)</b></td> <td><input type=text name=POC size=25></td> <td> </td> <td> </td> </tr> <tr> <td align=right> </td> <td> </td> <td> </td> <td> </td> </tr> <tr> <td align=right><b>Output Energy (mJ)</b></td> <td><input type=text name=Egy size=25></td> <td><div align="right"><b>Output Voltage (kV)</b></div></td> <td><input type=text name=Volt size=25></td> </tr> <tr> <td align=right> </td> <td> </td> <td> </td> <td> </td> </tr> <tr> <td align=right><b># HV Towers per Coil</b></td> <td><input type=text name=TPC size=25></td> <td><div align="right"><b># of Coils per Package</b></div></td> <td><input type=text name=CPP size=25></td> </tr> <tr> <td align=right> </td> <td> </td> <td> </td> <td> </td> </tr> <tr> <td align=right> </td> <td> </td> <td> </td> <td> </td> </tr> <tr> <th colspan=4><b>Please enter any additional information he </b></th> </tr> <tr> <th colspan=4><textarea name=Mess cols=50 rows=10 id="Message"></textarea></th> </tr> </table> </dl> <div align="center"> <p> <input type=hidden name=BodyTag value="<body bgcolor="#484589" text="#FFFFFF" link="#FFFF00" alink="#FFFFFF" vlink="#FF7F00">"> <input type=hidden name=FA value=SendMail> </p> <p><font color="#FFFF00" face="Arial, Helvetica, sans-serif"><strong>PLEASE MAKE SURE ALL INFORMATION<br> IS CORRECT BEFORE SUBMITTING</strong></font></p> <p> <input type=submit value="Submit Form"> </p> </div> </form> THE FILE THAT PROCESSES THE FORM DATA (formdata.php) *********************************************** <?php $con = mysql_connect("localhost","XXX","XXX"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("customform", $con); $sql="INSERT INTO formdata (Fname, Lname, Title, Comp, Addr, City, SProv, Ctry, ZPC, Tel, Fax, Email, EAV, Appl, Syst, Pres, Pind, Sres, Sind, POC, Egy, Volt, TPC, CPP, Mess) VALUES ('$_POST[Fname]','$_POST[Lname]','$_POST[Title]','$_POST[Comp]','$_POST[Addr]','$_POST[City]','$_POST[SProv]','$_POST[Ctry]','$_POST[ZPC]','$_POST[Tel]','$_POST[Fax]','$_POST[Email]','$_POST[EAV]','$_POST[Appl]','$_POST[Syst]','$_POST[Pres]','$_POST[Pind]','$_POST[Sres]','$_POST[Sind]','$_POST[POC]','$_POST[Egy]','$_POST[Volt]','$_POST[TPC]','$_POST[CPP]','$_POST[Mess]')"; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } echo "Your Information Was Successfully Posted"; mysql_close($con); $to = "recipient email address here"; $subject = "Custom Form"; $email = $_POST['Email'] ; $message = $_POST['Comp'] ; $headers = "From: $Email"; $sent = mail($to, $subject, $message, $headers) ; if($sent) {print "Your mail was sent successfully"; } else {print "We encountered an error sending your mail"; } ?> Need help ASAP. i need the following form to right to mysql table "table1" and columns "name" "email" and "comment".
<form action="sign.php" method="post" class="pure-form pure-form-stacked"> <fieldset> <label for="name">Your Name</label> <input id="name" type="text" placeholder="Your Name" name="name"> <label for="email">Your Email</label> <input id="email" type="email" placeholder="Your Email" name="email"> <label for="comment">Your Comments</label> <input id="comment" type="text" placeholder="Your Comments" name="comment"> <a href="thanks.html" button type="submit" class="pure-button">SUBMIT</button> </a> </fieldset> </form> My PHP File looks like this: <html> <body> <?php $myUser = "dbuser"; $myPassd = "********"; $myDB = "dbname"; $myserver = "192.168.1.80:3306"; $name = $_POST['name']; $email = $_POST['email']; $comment = $_POST['comment']; // Create connection $dbhandle = mysql_connect($myserver,$myUser,$myPassd) or die("Unable to connect to MySQL"); echo "Connected to MySQL<br>"; //select a database to work with $selected = mysql_select_db($myDB, $dbhandle) or die("Couldn't open database $myDB"); //if (mysqli_connect_errno()) { //echo "Failed to connect to MySQL: " . mysqli_connect_error(); //} //echo "connected"; $sql = "INSERT INTO signatures (name, comment) VALUES ( $name, $comment)"; if (!mysql_query($sql)) { die('Error: ' . mysql_error()); } echo "record added"; mysql_close($dbhandle); ?> </body> </html> I also need this to redirect to another html page after it run. Like i said any help would be great because i cant get it to work! Hi all, I have an html form that sends formdata to a php script called example.php with the POST method. example.php then has the following structu Code: [Select] <?php if(isset($_POST['var1'])) {$var1 = $_POST['var1'];} else {$var1 = 'English';} if(isset($_POST['var2'])) {$var2 = $_POST['var2'];} else {$var2 = 'French';} print" <html> <body> <form> <select id='select1'> <option>var1</option> <option>var2</option> <option>etc...</option> </select> <input type='text' id='input1'> ETC. ETC. </form> </body> </html> "; ?> So example.php has an embedded html form. How do I specify that some elements of the form should take their values from the variables retrieved at the start of the script via the POST command? For example, I want select1 to have 'var1' pre-selected and I want input1 to display var2. var1 & var2 get sent through to example.php fine, I just don't know how to get the embedded html form to use them. Please help! Thanks a lot. I've got a form on my site, with a textbox...and the info is sent to a db. How would I get the textbox info to be displayed the same as it was entered? For instance if I put in an address: 11 Street Town City PostCode It gets displayed like: 11StreetTownCityPostCode How could I have it so when I press enter it actually adds a <br> or something to the db? Thanks. Hi. I'm making a private webpage for my self where i can post news, games, music titles and movies. I'm made it so that i can post and delete them from my page. Also i wanted to have the option to edit them. So i made a action that shows me a list og the posts in each category. And then i want the option to hit UPDATE, and then it should open the form with the info's from MySQL. I've made those two options as the following: Code: [Select] elseif ( $action == "EditNews" ) { // EDIT NEWS START if ( !$_GET['id'] ) { ?> <div id="content"> <?php $sql = mysql_query("SELECT * FROM news") or die(mysql_error()); while ( $row = mysql_fetch_assoc($sql) ) { echo "<a href=\"?page=Admin&action=UpdateNews&id=" . $row['news_id'] . "\">Update</a> | " . $row['subject'] . "<br>"; } echo "</div>"; } else { $type = $_GET['type']; $id = $_GET['id']; } // EDIT NEWS END } elseif ( $action == "UpdateNews" ) { // UPDATE NEWS START if ( !$_POST['submit'] ) { $id = $_GET['id']; $sql = mysql_query("SELECT * FROM news WHERE news_id='$id'") or die(mysql_error()); $user_id = $_SESSION['uid']; $subject = $_row['subject']; $body = nl2br($_row['body']); ?> <div id="content"> <form action="?page=Admin&action=EditNews" method="post"> <div id="">Subject</div> <div id=""><input id="input" type="text" name="subject"></div> <div id="">Message</div> <div id=""><textarea id="input" name='body' cols='15' rows='4'></textarea></div> <div id=""><input id="submit" class="input" type="submit" name="submit" value="Post News"></div> </form> </div> <?php } else { ?> <div id="content">Not Working!</div> <?php } // UPDATE NEWS END } - I know i miss something, but i've tried to get to the point, where i only have the form as blank, and need some help from there. I hope someone can help me with my problem. MOD EDIT: [code] . . . [/code] tags added. This is a continuation of a previous post. I am trying to get the names of countries that are in a database table. It's not working! All I get is a Submit button, but no data. This is what I understand from the code that Psycho suggested: I am unfamiliar with the function and the use of the FOREACH constuct. looking at the PHP manual there are two syntaxes. It appears that Psyhco has used the second form where the current element's key is assigned to $key variable for each itteration. foreach (array_expression as $key => $value The 2 variables he used are $id and $label I assume that the line: $optionsHTML = ''; is the array built from the expression: $optionsHTML .= "{$label}\n"; Because I was not familiar with the PDO method, but have used mysqli, I had to rewrite the data retrival part which I believe is OK. I guess that the line : $countryOptions = buildSelectOptions($countries); is used in conjunction with the function to build the array. The HTML part that Psycho wrote puts the variable into the Form format for a selection list. Why is the $optionsHTML also inclosed in the option tags? Have I got the HTML part correct or is it the data extraction part that is incorrect? Here is the code:
<?
include("AddStats_admin_connect.php");
//connect to database
doDB();
//Function to build select options based on passed array
function buildSelectOptions($options)
{
$optionsHTML = '';
foreach($options as $id => $label)
{
$optionsHTML .= "<option value='{$id}'>{$label}</option>\n";
}
return $optionsHTML;
}
//Run query to get the ID and Name from the table
//Then populate into an array
$clist_sql = "SELECT CID, Country FROM Countries";
$clist_res= mysqli_query($mysqli, $clist_sql) or die(mysqli_error($mysqli));
if (mysqli_num_rows($clist_res) < 1) {
//this Country not exist
$display_block = "<p><em>You have selected an invalid Country.<br/>
Please try again.</em></p>";
}
$countries = array();
while($Ctry_info = mysqli_fetch_array($clist_res)) {
$countries[$Ctry_info['CID'] = $Ctry_info['Country']];
}
$countryOptions = buildSelectOptions($countries);
?>
<!DOCTYPE html> <html lang="en"> <head> <title>Stats</title> <link rel="stylesheet" href="stylesheets/style.css" /> <!--[if IE]> <script src="http://html5shim.googlecode.com/svn/trunk/html5.js"></script> <![endif]--> </head> <body> <? echo $countryOptions; ?> </br></br></br></br></br></br></br></br> <!Later in the HTML for the page <form action="Ctrystats.php" method="post"> <option name="country" value=<? echo $countryOptions;?>Country</option></br></br> <input type="submit" value="Submit Choice"> </form></p> </body> </html>I think I am nearly there so I would appreciate some help to finish this coding. Note: If you make your questions easy to read, then you have better chances of a quality answer. Use [ code ] ] tags. I am having difficulty inserting the following codes values into my database. I know that the variables contain a value as I am displaying them on the output screen. Code: [Select] $link = mysql_connect($db_host,$db_user,$db_pass) or die('Unable to establish a DB connection'); mysql_select_db($db_database,$link); mysql_query("SET names UTF8"); $usr = $userid; $golfer = $_REQUEST['golfer']; $tourney = $_REQUEST['tournament']; $backup = $_REQUEST['backup']; date_default_timezone_set('US/Eastern'); $time = date("Y-m-d H:i:s"); $t_id=1; mysql_query("INSERT INTO weekly_picks (t_id, tournament, user, player, backup, timestamp) VALUES ('$t_id', '$tournament', '$usr', '$golfer', '$backup', '$time') or die('Error, insert query failed')"); echo $t_id; echo "<br />"; echo $tourney; echo "<br />"; echo $usr; echo "<br />"; echo $golfer; echo "<br />"; echo $backup; echo "<br />"; echo $time; echo "<br />"; echo $userdetail['email']; echo "<br />"; $to = $userdetail['email']; $subject = "Weekly Tournament Pick for: $tourney"; $message = "This email is to confirm your pick for $tourney has been received. Your pick is: $golfer. Your backup pick is: $backup The time it was submitted was $time Do not reply to this email, the mailbox does not exist. Contact me with any issues at xxxxxxx@xxxxxxx.com"; $from = "noreply@chubstersgcc.com"; $headers = "From:" . $from; mail($to,$subject,$message,$headers); ?> <div> <p>This is to confirm that your pick has been submitted for the following tournament: <?php echo $tourney; ?>. A confirmation of your pick as also been emailed to you.</p> <p>Your golfer: <?php echo $golfer; ?></p> <p>Your backup: <?php echo $backup; ?></p> <p>Your pick was submitted at: <?php echo $time; ?></p> </div> Basically what I am needing is when a visitor comes to my site and request info on a product, the form sends the product id or name.
I have the site set up like product.php?Item=26 and the item number changes based on the product. The page items are being populated with info stored in the mysql databse.
I need the email being sent to say something like
Visitors Name has requested info on Item 26 Name - Visitors Name Email - email@me.com Phone - 123-456-7890 Company - Visitors Company Item info requested for Here is the products name URL to product page Basically the "item info" is being pulled from the database. I have asked on different forums and I cannot get a good answer that I can use to make this happen. I might not be explaining it right. Page the form is on is (and all other new-product.php pages) http://www.packagingequipment4sale.com/new-product.php?Item=26Any help would be greatly appreciated Hi everyone, First off thank you very kindly to anyone who can provide some enlightenment to this total php/mysql newb. I am creating my first database and while I have been able to connect to the database within my php script (or so I believe), the form data does not appear to be actually getting sent. I have development experience in other languages but this is completely new to me so if I've missed something that appears painfully obvious like a parse error of some sort, I do apologize. I am creating a website using Godaddy as the hosting account, and attempting to connect to the mysql database at the following URL (maybe this is where I'm going wrong): "pnmailinglist.db.4662743.hostedresource.com" Below is my very simple code: <?php //Verify successful connection to database. $connect = mysql_connect("pnmailinglist.db.4662743.hostedresource.com", "*********", "*********"); if(!$connect) {die("Could not connect!"); } //Initialize variables with form data. $firstname = $_POST['FirstName']; $lastname = $_POST['LastName']; $email = $_POST['Email']; $howfound = $_POST['HowFound']; //Post data to database, or return error. mysql_select_db("pnmailinglist", $connect); mysql_query("INSERT INTO mailinglist (First, Last, Email, How_Found) VALUES ($firstname,$lastname,$email,$howfound)"); mysql_close($connect); echo "Thank you for joining our mailing list! We will contact you soon with the dates and times of our upcoming events."; ?> Thank you again very much for any pointers or hints as to where I'm screwing up. I get no runtime errors, no syntax errors, and the echo message does display fine at the end -- just no data when I go to check my database! Best Regards, CL Hi, I am extracting data from a mysql db to then edit and update back into the db and use below to list items first - Code: [Select] <?php // Connect to server and select database. mysql_connect('localhost', 'xxxxxxxxx', 'xxxxxxxxxxxxx') or die("Error: ".mysql_error()); mysql_select_db("xxxxxxxxx"); $sql="SELECT * FROM properties"; $result=mysql_query($sql); ?> <table width="400" border="0" cellspacing="1" cellpadding="0"> <tr> <td> <table width="400" border="1" cellspacing="0" cellpadding="3"> <tr> <td colspan="4"><strong>List data from mysql </strong> </td> </tr> <tr> <td align="center"><strong>Name</strong></td> <td align="center"><strong>Lastname</strong></td> <td align="center"><strong>Email</strong></td> <td align="center"><strong>Update</strong></td> </tr> <?php while($rows=mysql_fetch_array($result)){ ?> <tr> <td><? echo $rows['Property_Rating']; ?></td> <td align="center"><a href="update.php?id=<? echo $rows['ID']; ?>">update</a></td> </tr> <?php } ?> </table> </td> </tr> </table> <?php mysql_close(); ?> I then go next page where I show data and allow editing - <?php // Connect to server and select database. mysql_connect('localhost', 'xxxxxxxxx', 'xxxxxxxxxxxxx') or die("Error: ".mysql_error()); mysql_select_db("xxxxxxxxx"); // get value of id that sent from address bar $id=$_GET['id']; // Retrieve data from database $sql="SELECT * FROM properties WHERE id='$id'"; $result=mysql_query($sql); $rows=mysql_fetch_array($result); ?> <table width="400" border="0" cellspacing="1" cellpadding="0"> <tr> <form name="form1" method="post" action="update_ac.php"> <td> <table width="100%" border="0" cellspacing="1" cellpadding="0"> <tr> <td> </td> <td colspan="3"><strong>Update data in mysql</strong> </td> </tr> <tr> <td align="center"> </td> <td align="center"> </td> <td align="center"> </td> <td align="center"> </td> </tr> <tr> <td align="center"> </td> <td align="center"><strong>Property_Name</strong></td> <td align="center"><strong>roperty_Rating</strong></td> <td align="center"><strong>Property_Address</strong></td> </tr> <tr> <td> </td> <td align="center"><input name="Property_Rating" type="text" id="Property_Rating" value="<? echo $rows['Property_Rating']; ?>"></td> </tr> <tr> <td> </td> <td><input name="id" type="hidden" id="id" value="<? echo $rows['id']; ?>"></td> <td align="center"><input type="submit" name="Submit" value="Submit"></td> <td> </td> </tr> </table> </td> </form> </tr> </table> <? // close connection mysql_close(); ?> And then the update page - <?php // Connect to server and select database. mysql_connect('localhost', 'xxxxxxxxx', 'xxxxxxxxxxxxx') or die("Error: ".mysql_error()); mysql_select_db("xxxxxxxxx"); // update data in mysql database $sql="UPDATE properties SET Property_Name='$Property_Name' WHERE id='$id'"; $result=mysql_query($sql); // if successfully updated. if($result){ echo "Successful"; } else { echo "ERROR"; } ?> Everything seems ok but when I edit the data and submit I get the success message but data not changed in db. Any ideas? Thanks. MOD EDIT: code tags added. I'm trying to add some data into my database through a form interface, but this form submits even when the page loads. This means the form submits regardless of the validation I have set in place, so every time the page is loaded, the database receives empty fields. Could you guys please help me with my problem? Here's my code: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.1//EN" "http://www.w3.org/TR/xhtml11/DTD/xhtml11.dtd">; <html xmlns="http://www.w3.org/1999/xhtml">; <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Form to add quotes</title> </head> <body> <?php //defining variables $genre = ""; $error_quote=""; $error_author=""; $error_date=""; $error_url=""; $error_genre=""; $quote = ""; $author=""; $q_date=""; $url=""; $output_form = true; if (isset($_POST['submit'])) { $output_form = true; if (trim($quote)=='' OR strlen(trim($quote)) < 2 OR strlen(trim($quote)) > 16) { $error_quote="Please enter a <b>Quote</b> between 2 to 16 characters long <br/>"; } if(trim($author)=='' OR strlen(trim($author)) < 2 OR strlen(trim($author)) > 16) { $error_author="Please enter an <b>Author</b> between 2 to 16 characters long <br/>"; } if(trim($q_date)=='' OR strlen(trim($q_date)) < 2 OR strlen(trim($q_date)) > 24) { $error_date="Please enter a <b>Date</b> between 2 to 24 characters long <br/>"; } if(trim($url)=='' OR strlen(trim($url)) < 2 OR strlen(trim($url)) > 246) { $error_url="Please enter a <b>URL</b> between 2 to 246 characters long <br/>"; } if(!isset($genre) OR $genre=='') { $error_genre=" - Please select a <b>Genre</b>. <br/>"; } } else { $output_form = false; } if ($output_form) { ?> <form method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>"> <table> <tr><td>Quote</td><td><input type="text" name="quote" value="<?php if (isset($quote)) echo $quote ; ?>"></td><td><?php echo $error_quote;?></td></tr> <tr><td>Author</td><td><input type="text" name="author" value="<?php if (isset($author)) echo $author ; ?>"></td><td><?php echo $error_author;?></td></tr> <tr><td>Date</td><td><input type="text" name="q_date" value="<?php if (isset($q_date)) echo $q_date ; ?>"></td><td><?php echo $error_date;?></td></tr> <tr><td>URL</td><td><input type="text" name="url" value="<?php if (isset($url)) echo $url ; ?>"></td><td><?php echo $error_url;?></td></tr> </table> <p>Gen </p><p> <input type="radio" name="genre" value="humour" <?php if (isset($genre) AND $genre=="humour") echo $genre; ?> />Humour <?php echo $error_genre;?> <input type="radio" name="genre" value="politics" <?php if (isset($genre) AND $genre=="politics") echo $genre; ?> />Politics <?php echo $error_genre;?> <input type="radio" name="genre" value = "romance" <?php if (isset($genre) AND $genre=="romance") echo $genre; ?>/>Romance <?php echo $error_genre;?> </p> <p><input type = "submit" name="submit" value = "add quote" /></p> </form> <?php } $dbhost = 'localhost'; $dbuser = '...'; $dbpass = '...'; $dbname = 'anevins'; // make a connection to the database $conn = mysql_connect($dbhost, $dbuser, $dbpass) OR die('Connection failed: '. mysql_error()); // select the database mysql_select_db($dbname) OR die('Database select failed: '. mysql_error()); // set up the query to insert the new data $query = "INSERT INTO quotes (id, quote, author, q_date, url, genre) VALUES ('', '$quote', '$author', '$q_date', '$url', '$genre')"; $result = mysql_query($query) OR die('Query failed: ' . mysql_error()); echo "<p>Thank you for adding your quote</p>"; mysql_close($conn); exit(); ?> </body> </html> I have deleted mysql info for safety reasons. Here are the two webpage's codes i'm using right now menu.php <? session_start(); if(!session_is_registered(myusername)){ header("location:login.php"); } ?> <html><title>ChronoServe - Saving Time</title> <link href="style.css" rel="stylesheet" type="text/css"> <body> <table width="100%" border="0" cellpadding="0" cellspacing="0" class="container"> <tr> <td> <table width="335px" height="50%" border="1" align="center" cellpadding="0" cellspacing="0" class="centered"> <tr> <td> <form method="post" action="insertvalues.php"> <table width="100%" border="0" align="center" cellpadding="3" cellspacing="10"> <tr> <td colspan="2"><div align="center" class="font2">Activation Information</div></td> </tr> <tr> <td colspan="2"></td> </tr> <tr> <td width="40%" class="font3">First Name :</td> <td width="60%"> <div align="center"> <input name="firstname" type="text" class="font3" id="firstname" maxlength="25" /> </div></td> </tr> <tr> <td class="font3">Last Name :</td> <td> <div align="center"> <input name="lastname" type="text" class="font3" id="lastname" maxlength="25" /> </div></td> </tr> <tr> <td height="28" class="font3">Phone Number :</td> <td> <div align="center"> <input name="pnumber" type="text" class="font3" id="pnumber" maxlength="10" /> </div></td> </tr> <tr> <td class="font3">Personnel Activated :</td> <td> <div align="center"> <input name="numberactivated" type="text" class="font3" id="numberactivated" maxlength="3" /> </div></td> </tr> <tr> <td height="37" colspan="2"></td> </tr> <tr> <td colspan="2"><div align="center"> <input name="submit" type="Submit" class="font3" value="Submit" /> </div> </td> </tr> </table> </form></td> </tr> </table> </td> </tr> </table> </body> </html> insertvalues.php <?php if(isset($_POST['Submit'])) { $firstname = $_POST['firstname']; $lastname = $_POST['lastname']; $pnumber = $_POST['pnumber']; $numberactivated = $_POST['numberactivated']; mysql_connect ("deleted", "deleted", "deleted") or die ('Error: ' . mysql_error()); mysql_select_db ("deleted"); $query = "INSERT INTO disney_database (id, firstname, lastname, pnumber, numberactivated, date) VALUES ('NULL', '".$firstname."', '".$lastname."', '".$pnumber."', '".$numberactivated."', 'NULL')"; mysql_query($query) or die('Error updating database'); header("location:menu.php"); echo "Database Updated With: ".$firstname."" - "".$lastname."" - "".$pnumber."" - "".$numberactivated.""; } else { echo "Database Error" { ?> Here is my problem. I set a one <form> on every form field I have including the submit button. Now whenever I press the submit button it redirects to insertvalues.php which it should be doing. In insertvalues i told it to query the form data and post it into my database's table. Its not doing that and tells me that it has a database error which i set it to tell me if something goes wrong. Anyone can help me? BTW I can manually query in the information using sql with phpmyadmin. so can someone please review my code for me? thanks big help! You can see what is happening. Visit www.chronoserve.com The username and password are "admin" Hey guys, New to the forum and a newer user of PHP / MySQL. I am having trouble with some code I've written up. I don't seem to get any errors when running it, but it's not updating my database the way that it should. hopefully a simple fix. I am thinking that it must be on the MySQL side of things. Couple of things to start. My html form is comprised completely of drop down list inputs. I'm the only user so I thought this would be the easiest approach. Because of that I've made my PHP as follows: Code: [Select] <?php $season = $_POST['season']; $month = $_POST['month']; $day = $_POST['day']; $year = $_POST['year']; $time = $_POST['time']; $event = $_POST['event']; $game = $_POST['game']; $buyin = $_POST['buyin']; $connect = mysql_connect('localhost','root','') or die('can not connect'); if ($connect) { echo "connected to database"; } $db = mysql_select_db('dpl') or die('can not find database'); if ($db) { echo "DPL Selected"; } $query = sprintf("INSERT INTO events (season , month , day , year , time , event , game , buyin) VALUES ('%s' , '%s' , '%s' , '%s' , '%s' , '%s' , '%s' , '%s')", $season , $month , $day , $year , $time , $event , $game , $buyin ); if ($query) { echo "Your event has been added"; } ?> My connection is working, my database is selected and I'm even now getting confirmation that my query is working, but when i go to check my database there are no entries in it? any thoughts? I've tried the drop down variables as both VARCHAR and TEXT inputs in MySQL, but I can't seem to get it to work. Any help is greatly appreciated. Hi, Is there a way to send extracted information from one (local) MySQL db, via PHP, to an external web form - having that web form submit that info to it's connected MySQL db without human interaction? Basically, I need to automate a process using the $_GET function to that form but not sure if there is a way to accomplish this from just connecting to the web form (itself); bypassing direct MySQL access which is the later option. Any input appreciated - thanks! Not sure exactly what my problem is here, but i have looked at this at least a hundred times and I just can't figure out what is going on. Everything works great except for the sending the email part. It displays the error "There was a problem sending the mail". The form field checking works fine, the insert into mysql works fine - - but it won't send the email. I have tried using double quotes and single quotes for the email information ($to, $subject, etc...) I have even eliminated the form data from the email information and it still doesn't send. I am hopelessly stuck at this point Any ideas?? Code below: <html> <body bgcolor = 'blue'> <div align = 'center'> <h1>test FORM</h1> </div> <p> <?php If ($_POST['submit']) //if the Submit button pressed { //collect form data $fname = $_POST['FName']; $lname = $_POST['LName']; $email = $_POST['Email']; $tel = $_POST['Tel']; $mess = $_POST['Mess']; $errorstring = ""; if (!$fname) $errorstring = $errorstring."First Name<br>"; if (!$lname) $errorstring = $errorstring."Last Name<br>"; if (!$email) $errorstring = $errorstring."Email<br>"; if ($errorstring !="") echo "<div align = 'center'><b>Please fill out the following fields:</b><br><font color = 'red'><b>$errorstring</b></font></div>"; else { $fname = mysql_real_escape_string($fname); $lname = mysql_real_escape_string($lname); $email = mysql_real_escape_string($email); $tel = mysql_real_escape_string($tel); $mess = mysql_real_escape_string($mess); $con = mysql_connect("localhost","user","password"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("mec", $con); $sql="INSERT INTO formtest (FName, LName, Title, Tel, Email, Mess) VALUES ('$fname','$lname','$title','$tel','$email','$mess')"; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } $to = 'myemailaddress'; $subject = 'test form'; $message = 'Hello'; $headers = 'From Me'; $sent = mail($to, $subject, $message, $headers); if($sent) {print "Email successfully sent";} else {print "There was an error sending the mail";} mysql_close($con); } } ?> <p> <form action= 'testmecform.php' method= 'POST'> <table width = '640' border = '0' align = 'center'> <tr> <td align = 'right'><b>First Name</b></td> <td><input type = 'text' name = 'FName' value = '<?php echo $fname; ?>' size = '25'></td> <td><div align = 'right'><b>Telephone</b></div></td> <td><input type = 'text' name = 'Tel' value = '<?php echo $tel; ?>' size = '25'></td> </tr> <tr> <td align = 'right'><b>Last Name</b></td> <td><input type = 'text' name = 'LName' value = '<?php echo $lname; ?>' size = '25'></td> <td> </td> <td> </td> </tr> <tr> <td align = 'right'><b>Email</b></td> <td><input type = 'text' name = 'Email' value = '<?php echo $email; ?>' size = '25'></td> <td> </td> <td> </td> </tr> <tr> <th colspan = '4'><b>Please enter any additional information he </b></th> </tr> <tr> <th colspan = '4'><textarea name = 'Mess' cols = '50' rows = '10'><?php echo $mess; ?></textarea></th> </tr> <tr> <th colspan = '4'><b>Please make sure all information is correct before submitting</b></th> </tr> <tr> <th colspan = '4'><input type = 'submit' name = 'submit' value = 'Submit Form'></th> </tr> </table> </form> </body> </html> Hi there I have a MySQL database table that has multiple records which look like (1, Which of these are your favorite color(s)?, Red||Blue||Orange||Green, question-type1 ) I have written some PHP code in extracting that data into a HTML form. (The above data looks like a question with multiple options (radio buttons/checkboxes) below it). Below is what I'm trying to achieve: When the action is Submit: store the question number, user responses of the options , time stamp and user name into a new database table. I came to know that passing arrays will do the job, but I got stuck in the middle. Please see the attached documents that has the code. TIA [attachment deleted by admin] I had this working, but when I try and get fancy and use AJAX the data doesn't display. I think this is a PHP problem though. My code for the select form including AJAX code Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en-GB"> <head> <title>AJAX Example</title> <link rel="stylesheet" type="text/css" href="Form.css" media="screen" /> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js"></script> <script type="text/javascript"> $(document).ready(function(){ $("tr:odd").addClass("odd"); }); </script> <script type="text/javascript"> function showPlayers(str) { var xmlhttp; if (str=="") { document.getElementById("DataDisplay").innerHTML=""; return; } if (window.XMLHttpRequest) {// code for IE7+, Firefox, Chrome, Opera, Safari xmlhttp=new XMLHttpRequest(); else {// code for IE6, IE5 } xmlhttp=new ActiveXObject("Microsoft.XMLHTTP"); } xmlhttp.onreadystatechange=function() { if (xmlhttp.readyState==4 && xmlhttp.status==200) { document.getElementById("DataDisplay").innerHTML=xmlhttp.responseText; } } xmlhttp.open("GET","Query.php?category_id="+str,true); xmlhttp.send(); } </script> </head> <body> <h1">AJAX Example</h1> <?php #connect to MySQL $conn = @mysql_connect( "localhost","username","pw") or die( "You did not successfully connect to the DB!" ); #select the specified database $rs = @mysql_SELECT_DB ("MyDB", $conn ) or die ( "Error connecting to the database test!"); ?> <form name="sports" id="sports"> <legend>Select a Sport</legend> <select name="category_id" onChange="showPlayers(this.value)"> <option value="">Select a Sport:</option> <?php $sql = "SELECT category_id, sport FROM sports ". "ORDER BY sport"; $rs = mysql_query($sql); while($row = mysql_fetch_array($rs)) { echo "<option value=\"".$row['category_id']."\">".$row['sport']."</option>\n "; } ?> </select> </form> <br /> <div id="DataDisplay"></div> </body> </html> Query.php <?php #get the id $id=$_GET["category_id"]; #connect to MySQL $conn = @mysql_connect( "localhost","username","pw") or die( "Error connecting to MySQL" ); #select the specified database $rs = @mysql_SELECT_DB ("MyDB", $conn ) or die ( "Could not select that particular Database"); #$id="category_id"; #create the query $sql ="SELECT * FROM sports INNER JOIN players ON sports.category_id = players.category_id WHERE players.category_id = '".$id."'"; echo $sql; #execute the query $rs = mysql_query($sql,$conn); #start the table code echo "<table><tr><th>Category ID</th><th>Sport</th><th>First Name</th><th>Last Name</th></tr>"; #write the data while( $row = mysql_fetch_array( $rs) ) { echo ("<tr><td>"); echo ($row["category_id"] ); echo ("</td>"); echo ("<td>"); echo ($row["sport"]); echo ("</td>"); echo ("<td>"); echo ($row["first_name"]); echo ("</td>"); echo ("<td>"); echo ($row["last_name"]); echo ("</td></tr>"); } echo "</tr></table>"; mysql_close($conn); ?> I think the problem is either with this part in the AJAX Code: [Select] xmlhttp.open("GET","Query.php?category_id="+str,true); or most likely in my Query.php code when I wasn't using AJAX and using POST it worked fine, but adding the AJAX stuff and GET it doesn't work. When I echo out the SQL the result is Code: [Select] SELECT * FROM sports INNER JOIN players ON sports.category_id = players.category_id WHERE players.category_id = '' so the category_id is not being selected properly and that is the primary key/foreign key in the MySQL table which connects the JOIN. |
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