PHP - Preg_replace And String

im trying to do a complex(i think) prg replace but i keep getting the error:

Code: [Select]
Failed evaluating code: $lang->showing-1,1
the code i am trying to replace is:

Code: [Select]
<asf: lang[showing-<asf: var[num_report_alerts]>,<asf: var[num_report_alerts]>]>
and the preg_replace is:

Code: [Select]
$content = preg_replace('|\<asf: lang\[(.*?)-(.*?)\]\>|e', '$lang->replace_vars($lang->//1, array(\\2))', $content);
its supposed to take everything inside <asf: lang[]> and echo \\1 which would be "showing" and then add \\2 into an array which would be "array(1,1)".

So the output would be showing 1 of 1.

Anyone know where im going wrong?

I'm trying to search a string for all occurences of a pattern, then append text after that pattern.  The example is:   SUM("foo") as "bar"   and have it display as:   SUM("foo") over() as "bar"   The "SUM" could be any SQL aggregate and be case insensitive.  So For bonus points, let's say the valid aggregates are  array('SUM', 'MAX', 'MIN', 'AVG').  My plan right now is to figure it out for SUM, then loop it replacing the aggregate.   This is what I have so far... and it is not working.   $l= 'SUM("foo") as "bar"'; $l=preg_replace('/([^"]+")/','\0 over()',$l);   Thanks,   Ryan

i have:


$msg = ereg_replace("[^A-z0-9]"," ",$msg);
$msg = ereg_replace("  "," ",$msg);
$msg = ereg_replace("    "," ",$msg);


how will i apply preg_replace please???
thank you

I am trying to pull out the image HTML tag but its not working as expected.
Here is what I am doing
   $removeimagetag='/<a href/';
   $replacwith = "illegal";
$_POST['descr']=preg_replace($removeimagetag,$replacwith,$_POST['descr']);

in the 'descr' there is a <a href="http://s635.photobucket.com......
When it post it does not strip out the <a href
So the image is displayed.

I tried a modified version to test to see if it work that looked like this.

   $removeimagetag='/goofy/';
   $replacwith = "illegal";
$_POST['descr']=preg_replace($removeimagetag,$replacwith,$_POST['descr']);

When the word goofy appears in the text then its replaced with the word illegal,

Also I would like to make it so that it replaces the entire line from the <a href....... to the </a> with a phrase that says "this feature is not allowed"  rather than just the part in the front...the <a href.

Any help you can be will be greatly appreciated.

I currently have some custom tags, similar to BBCode, to be used for comments on my site. I'm trying to create a [nobr] tag (note: I know the no break tag will work in many major browsers, but it's deprecated, so I'm trying to be compliant).

The idea is that if I encounter the [nobr] tag, I need to remove all line breaks. Here's the best I can do, but it's not working as I had hoped.

Here's what I currently use to replace line breaks with a break tag.
Code: [Select]
$str=str_replace("\r\n","<br>",$str);

Here's my attempt at introducing this new tag.
Code: [Select]
function BbToHtml($str) {

 $before=preg_replace("/(.+)\[nobr\](.+)\[\/nobr\](.+)/Usi","\\1",$str);
 $during=preg_replace("/(.+)\[nobr\](.+)\[\/nobr\](.+)/Usi","\\2",$str);
 $after=preg_replace("/(.+)\[nobr\](.+)\[\/nobr\](.+)/Usi","\\3",$str);

 $during=str_replace("\r\n","",$during);

 if($during != "") { // If the [nobr] tag was found, go with the new string.
  $str = $before.$during.$after;
 }
 else { // If the [nobr] tag was not found, go ahead like normal.
  $str=str_replace("\r\n","<br>",$str);
 }

 return $str;

I can't get that working. Any ideas on how to fix that, or a completely alternate method of doing it? Thank you!

Hi guys, this is what im trying to achieve, im trying to remove the links to the current page for all my web pages with a single script, like for example, if i am on a home page, then the home page hyperlink is disabled, and if i am on a about us page the hyperlink for about us is disabled, i have went through many forums and posts but the more i read the more confused i get, however i came up with a method of my own with many bits of code i've read about everywhere.

firstly, the script collects the current url of the page(i dont need https or any sub direct, its just for example index.php)
then it stores the page name, index.php into a variable say - $current
Then a menu.php which is the navigation file is loaded and heres the part i cant get to work, i would like to match find that <a href="index.php"> index </a> and replace that with <a> index </>
so that the link to the current page is disabled..i tried using preg_replace but failed miserably and opted to use str_replace

Heres the code:

<?php
//the function below gets the current page url or file
//i got this off webcheatsheet - http://www.webcheatsheet.com/PHP/get_current_page_url.php
function getPage(){
 return substr($_SERVER["SCRIPT_NAME"],strrpos($_SERVER["SCRIPT_NAME"],"/")+1);
}

//store the current url or the file name into a variable
$current = getPage();

echo "The current page name is ".$current;
$menu=file_get_contents("menu.php");

$string = "<a>"+$current+"</a>";
$link = "<a href="+ current +"> ";
//i could not get preg_replace to work or come up with an effective regular expression
//which is why i use str_replace instead.
$menu=str_replace("" , $string, $menu);

echo $menu;

?>

Hi, I've got a little problem at the moment with how to replace varying amounts of hyphens in a  browser url.

scenario:
I have a borwser url mydomain.com/location/foo-bar/ where "foo-bar" is actually "foo bar" in the database (no hyphen).
I also have urls where the entry in the database does have the hyphens e.g. "foo-bar"

Now im not quite sure how to go about writing these urls, and how to manipulate the GET values from them.

what I've tried

My first thought was to add a secondary hyphen to the url so that the database entires that equal "foo-bar" would be "foo--bar" in the browser url and the entries in the database that equal "foo bar" would have the single hyphen "foo-bar".

Then i would use preg_replace to deal with the single hyphens by removing them and replacing with a space, and after that finding the double hyphens and replacing them with only one.

In theory this should work (I think), but I've only recently got into using regex, this is what I've tried;

$CNE = preg_replace("/[-]{1}/", " ", $CNE);
$CNE = preg_replace("/[-]{2}/", "-", $CNE);


so I've tired to match the single hyphen and then the double, but even before I tested this I didn't think it was going to work with this code.


Can anyone correct me, or maybe suggest a better way to go about this issue.
(note: using a different character to replace spaces is NOT an option in this case)

Thanks

What I'm trying to do is replace message_tags to links and web addresses to links in facebook json data, the problem is I need to do these in 2 steps, first do the message tags then then web addresses. The message_tags need to be done first because they rely on offset and length of the message to do the replace.     To code to first replace the message_tags is

// convert message tags to links
if($post->message_tags) {
     usort($post->message_tags, 'mySort');
     foreach($post->message_tags as $message_tag) {
          foreach($message_tag as $link) {
               $post_text = substr_replace($post_text,"<a href=\"https://www.facebook.com/".$link->id."\" target=\"_blank\">".$link->name."</a>",$link->offset,$link->length);
          }
     }
}

The second part is to convert any web address (http://example.com) to a link (<a href ="http://example.com" title="http://example.com" target="_blank">http://example.com</a>)

// check if any entites exist and if so, replace them with hyperlinked versions
$post_text = preg_replace("/((http:\/\/|https:\/\/)[^ )]+)/e", "'<a href=\"$1\" title=\"$1\" target=\"_blank\">'. ((strlen('$1')>=250 ? substr('$1',0,250).'...':'$1')).'</a>'", $post_text);

So now to the problem, the second part now rewrites the first part and completely destroys the link because it just looks for http: and https: so in my preg_replace I need a way to not include anything that has already been converted, so not include anything that already has href="http

Hey, I am trying to write a sort of replace function where {user:1} is converted into a set of information from a database using preg_replace. So I have created the following preg_replace:

$patterns = array();
$patterns[1] = '/\{user:([0-9]+)\}/';

$replacements = array();
$replacements[1] = UserCredit('$1');

ksort($patterns);
ksort($replacements);

$content_show = preg_replace($patterns, $replacements, $content);

echo $content_show;


and then the function UserCredit which is just above that on the page:

function UserCredit($user_id) {
require 'connect.php';
$user_lookup = mysql_query("SELECT * FROM prop_users WHERE ID = '$user_id'");
while($row = mysql_fetch_array($user_lookup)) {
$user_name = $row['full_name'];
$user_file = $row['credit_file'];
$user_url = $row['link_url'];
$user_url_alt = $row['link_alt'];
}
if(mysql_num_rows($user_lookup)==0){
  die("An error has occured, Sorry for any Inconvenience Caused! User ID=".$user_id);
}
require 'close.php';
$output = "<li class=\"clearfix\"><div class=\"credimg\"><img src=\"".$user_file."\" width=\"75px\" height=\"75px\" alt=\"".$user_name."\" /></div><p><strong><a href=\"".$user_url."\" title=\"".$user_url_alt."\">".$user_name."</a></strong><br /><em>Writing / Code</em></p></li>";
return $output;
}


I have tested the function and it works when I echo UserCredit('1');

And the preg_replace works at simply extracting the value for the user.

The only problem is that I can't figure a way for the preg_replace to carry the value of $1 into the function it just literally carries "$1"

Is there something obvious that I am missing or am I going around this the wrong way?

Hi all.

I'm having a bit of an issue with preg_replace and I'm not sure how to solve it.  I'm having preg_replace find a "bus" (short for business) prefix in a file name and then print "Business Management" instead of "bus".  I also have another prefix of "bus_it_requests".  When preg_replace finds that prefix, it prints "Business Management It Requests" but I need it to print "Business It Requests".  How do I have preg_replace make the distinction in the prefix matches?

How come preg_replace won't traverse multiple lines?   <?php $str = '

I had this code but now I need to change it to newer preg_replace function
Can someone help me to do it please?

Here is the code:

    $newString = ereg_replace("[[:alpha:]]+://[^<>[:space:]]+[[:alnum:]/]","<a href=\"\\0\" target=\"_blank\">\\0</a>", $originalString);

Thanks in advance.

I'm working with the youtube API and the function Code: [Select]
$relatedVideo->watchURL returns a video url

However when I use Code: [Select]
preg_replace("youtube","test",$relatedVideo->watchURL); it gives me the following error
Code: [Select]
preg_replace() [<a href='function.preg-replace'>function.preg-replace</a>]: Delimiter must not be alphanumeric or backslash in <b>C:\wamp\www\site\test.php</b> on line <b>317
Help please?

I have no idea what the problem is with preg_replace and strings smaller than 3 characters. I'm writing to do a pattern search of abreviations(array) and replacements (array)... tried word boundries, which seems not to work at all. (it is VITAL that im able to match the whole word)
here is a quick example which I cannot understand maybe someone could explain to me:
1. why repitions of certain abrevs do not get replaced.
2. why '/\bs.\b/' wont get matched (where there is a space before  the b. - hense the word boundry)

here is a snippet of code could someone please explain why this happens:

Code: [Select]
<?php
  $string='de d. s. pres. div. de de d. s.';
 
//DEFINE PATTERN
$patterns = array();
$patterns[0] = '/ s. /';
$patterns[1] = '/ b. /';
$patterns[2] = '/ pres./';
$patterns[3] = '/ Ind./';
$patterns[4] = '/ Mar./';
$patterns[5] = '/ Agt./';  
$patterns[6] = '/ Agy./';  
$patterns[7] = '/ Indpls./';                            
$patterns[8] = '/ Chgo./';
$patterns[9] = '/ Corp./';
$patterns[10] = '/ U./';    
$patterns[11] = '/ Fin./';          
$patterns[12] = '/ ls./';   
$patterns[13] = '/ Pres. /';    
$patterns[14] = '/ Internat. /';   
$patterns[15] = '/ m. /';
$patterns[16] = '/ N.Y.C./';   
$patterns[17] = '/ div. /';   
$patterns[18] = '/ de /';  
$patterns[19] = '/ d. /';    


//DEFINE PATTERN REPLACE
$replacements = array();
$replacements[0] = ' son of ';
$replacements[1] = ' born in ';
$replacements[2] = ' president';
$replacements[3] = ' Indiana ';
$replacements[4] = ' March ';
$replacements[5] = ' Agent ';  
$replacements[6] = ' Agency ';  
$replacements[7] = ' Indianapolis ';                            
$replacements[8] = ' Chicago';
$replacements[9] = ' Corporation ';
$replacements[10] = ' U '; 
$replacements[11] = ' Financial ';       
$replacements[12] = ' Island';   
$replacements[13] = ' President '; 
$replacements[14] = ' International ';  
$replacements[15] = ' married to ';
$replacements[16] = ' New York City ';   
$replacements[17] = ' divorced';    
$replacements[18] = ' de '; 
$replacements[19] = ' daughter of ';    

 echo '------ Original ---------<br>'.$string.'<br>';
$data = preg_replace($patterns, $replacements, $string);
 echo '<br>------ Abbreviation Replace ---------<br>'.$data.'<br>';  
?>

OUTPUT: ------ Original ---------
de d. s. pres. div. de de d. s.

------ Abbreviation Replace ---------
de daughter of son of president divorcedde daughter of d. s.

any help is appriciated thanks.

i'm having trouble in combining the 2 preg_replace into 1.
basically i have a string witch strange chars, first i remove all except alphanumeric chars and the remaining string has 1 or 2 spaces and i replace them with dash.
Code: [Select]
strtolower(preg_replace('/\s+/', '-', preg_replace("/[^0-9a-zA-Z]/i", ' ',$a['item'])));