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PHP - A Simple Way Writing To A Specific Line
Is there a simple way getting PHP to open a single file and write to a specific line?
Like: fwrite (line = 102) {"bla bla bla"}; fclose; Similar TutorialsIs this possible? Could the following code be replaced with one .txt consisting of two digits? Code: [Select] $myFile = "offerrotation.txt"; $myFile2 = "lprotation.txt"; $fh = @fopen($myFile, 'r'); $offerNumber = @fread($fh, 5); @fclose($fh); $fh = @fopen($myFile2, 'r'); $lpNumber = @fread($fh, 5); @fclose($fh); Many thanks Does anyone know how I can make fwrite() write to a new line? I tried the following, but it didn't work. fwrite($fp, "".$_POST['feedback']."\n"); fwrite($fp, "".$_POST['feedback']."\r\n"); What is the correct way to echo this line??? Quote <php? echo "proceed to <a href= <?php echo urldecode($_GET['url']); ?>> <?php echo urldecode($_GET['title']); ?> </a>"; ?> My Parse error says: Quote Parse error: parse error, expecting `T_STRING' or `T_VARIABLE' or `T_NUM_STRING' in C:\Program Files\EasyPHP5.3.0\www\URL_tester\page2.php on line 16 Hi guys. im using this line to log any users that log into my site. It writes to the log correctly however it doesn't leave a new a line. Can anyone see what ive done wrong with my code. thanks. Code: [Select] fwrite($fh, $_SESSION['username'] . ' at ' . strftime('%c') . "\n"); Hey, I'm trying to work out how I can have a simple script that will work like this: Page 1 - Heading, Paragraph, Image read from database. Page 2 - Has text boxes allowing you to change heading, paragraph and image (url) with each edit using a different text box. (Admin panel) The database connection would be in a separate file. So far I've got the database connection sorted. Code: [Select] <?php //Database Information $dbtype = "mysql"; $db_host = "localhost"; $db_user = ""; $db_pass = ""; $db_name = ""; $db_port = ""; $db_table_prefix = "userCake_"; ?> At the top of each of the other pages this is what I've got. Code: [Select] <?php require_once("models/config.php"); ?> Let's say I give each bit stored in the database a page ID and an object ID. If the page selected is index.php how can we give it a page ID of 1 and give then include all the separate 'objects' throughout the page? Hopefully this makes sense? Cheers, Jack The title says it all,..well as all u can see, there are many methods to accomplish this done but not before undergoing through a heavy tasking process. For instance, 1. Open the file 2. Reads the content of the file into array. 3. Find out the desire line of text that we want to replace. 4. Make that line of text as variable and assigns with the new data(that we want to replace) as its values. 5.open another file. 6.Write the whole contents to the file opened in 5. 7. Put the contents back to the file of original. Can anyone contributes a better way to get this done? Like replace/delete a specific line without affecting other characters or anything therein? Thanx. P.S reading and using str_replace to make the alteration always ends up in giving some kind of result beyond desired after the first round of code execution. I need to add these lines to my .htaccess file via PHP Code: [Select] RewriteCond %{REQUEST_URI} checkout RewriteRule ^(.*)$ https://myurl.com/checkout/$1 [R,L] RIGHT after this line: Code: [Select] RewriteBase / AND before this line: Code: [Select] RewriteCond %{REQUEST_FILENAME} !-f This is how the current file looks w/o the new line addition: Code: [Select] RewriteEngine On RewriteBase / RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteRule ^(.+)$ index.php [L,QSA] It needs to look like this when the new lines are added(extra line breaks not necessary): Code: [Select] RewriteBase / RewriteCond %{REQUEST_URI} checkout RewriteRule ^(.*)$ https://myurl.com/checkout/$1 [R,L] RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteRule ^(.+)$ index.php [L,QSA] The line numbers may not match up, so I cannot use the line number. Hi all, I have a question. How do I put a new line in a script? I've tried everything. <?php $con = mysql_connect("localhost","*","*"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("my_db", $con); $sql="SELECT * FROM People WHERE FirstName='Borko' AND LastName='Borkov'"; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } echo "Found!"; echo($sql); mysql_close($con) ?> I wrapped it in <html> and so on, <br /> doesn't work. Saved it in html, <br /> still doesn't work and the script doesn't execute. The output I get right now is Quote Found!SELECT * FROM People WHERE FirstName='Borko' AND LastName='Borkov' I want it to display Quote Found! SELECT * FROM People WHERE FirstName='Borko' AND LastName='Borkov' And another question - how can I see what the sql variable is searching for from the browser? For now, as you have seen, I just use the echo($sql) but it doesn't quite cut it - is there a way to see just FirstName and LastName without the whole code? I tried echo($sql [FirstName] [LastName], as you've already guessed it didn't work... A hint would also be greatly appreciated! Any help on these two issues? Hi All, I'm trying to debug my first few lines of PHP where I have all my "checks" to make sure someone is logged in. I have this code all by itself and it is still not executing. This is the only page that I'm having trouble with. header('Location: login.php?logout=1'); Hello -- I'm trying to work through a very simple CMS that I found on the web (just for learning purposes). I need some help understanding this line: <table> <form method="POST" action="account.php?mode=save<?=( isset($_REQUEST['id']) ? "&id={$_REQUEST['id']}" : null )?> <? I understand the Method = "POST", but not the "action = " line. Thanks for any help. PHP = 5.5.14
MySQL = 5.2.17
I've cloned a mysqli_connect() statement in a 'require' file placed in a non-public access location on the server. It's the same format (and location) currently working fine with another application, EXCEPT i changed the database name to what I need to use for this application, AND added the $con= part on the front end to substitute for the commented out $con= line in the example code I'm modifying to insert data into a new MySQL DB Table.
The dB Table is fine and I have Inserted data via myPHPAdmin with no problems. Only two form variables are in the simple PHP script thus far just to test if it will work before proceeding.
I've used pseudonames for the actual /home/.... location and filename, and am now Baffled about the Line 2 Error Message I'm getting (below the code).
<?php
require '/home/myusername/domains/mydomain.com/myclonedrequire.php';
//$con=mysqli_connect("example","uid","pwd","my_db");
// Check connection
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
// escape variables for security
$year = mysqli_real_escape_string($con, $_POST['year']);
$callsign = mysqli_real_escape_string($con, $_POST['callsign']);
$sql="INSERT INTO `lqplogs` (`year`, `callsign`)
VALUES ('$year', '$callsign');
if (!mysqli_query($con,$sql)) {
die('Error: ' . mysqli_error($con));
}
echo "1 record added";
mysqli_close($con);
?>
ERROR Message:
Warning: Unexpected character in input: '\' (ASCII=92) state=1 in (above file & location) on line 2
There are NO '\' characters in any of my files.
Here is the simple Form file code:
<?php ?> <html: <head><title></title></head> <body> <form action="insert.php" method="post"> YEAR: <input type="text" name="year"> CALLSIGN: <input type="text" name="callsign"> <input type="submit"> </form> </body> </html> <?php ?>Thanks for any assistance! -FreakingOUT I use the Wholesale Suite Premium Prices plugin with WooCommerce. I have 6 specific wholesale roles out of 15 that I wish to hide two specific shipping methods from being selected for the 6 exceptions. I'm just trying this on my staging server at this time using a code snippet example that I found and modified for my specific conditions. Would the following work for this purpose?
/* Hide specific shipping methods for specific wholesale roles */
add_filter( 'woocommerce_package_rates', function( $shipping_rates ) {
// User role and shipping method ID to hide for the user role
$role_shipping_method_arr = array(
'ws_silvia_silver' => array( 'Silvia Premium Standard Shipping (Tracking Service)'),
'ws_silvia_silver_pst_exempt' => array( 'Silvia Premium Standard Shipping (Tracking Service)'),
'ws_silvia_silver_tax_exempt' => array( 'Silvia Premium Standard Shipping (Tracking Service)'),
'ws_silvia_silver' => array( 'Silvia Union Standard Shipping (Tracking Service)'),
'ws_silvia_silver_pst_exempt' => array( 'Silvia Union Standard Shipping (Tracking Service)'),
'ws_silvia_silver_tax_exempt' => array( 'Silvia Union Standard Shipping (Tracking Service)'),
'ws_silvia_gold' => array( 'Silvia Premium Standard Shipping (Tracking Service)'),
'ws_silvia_gold_pst_exempt' => array( 'Silvia Premium Standard Shipping (Tracking Service)'),
'ws_silvia_gold_tax_exempt' => array( 'Silvia Premium Standard Shipping (Tracking Service)'),
'ws_silvia_gold' => array( 'Silvia Union Standard Shipping (Tracking Service)'),
'ws_silvia_gold_pst_exempt' => array( 'Silvia Union Standard Shipping (Tracking Service)'),
'ws_silvia_gold_tax_exempt' => array( 'Silvia Union Standard Shipping (Tracking Service)'),
);
// Getting the current user role
$curr_user = wp_get_current_user();
$curr_user_data = get_userdata($current_user->ID);
// Wholesale Suite Roles
if (isset($current_user) && class_exists('WWP_Wholesale_Roles')) {
$wwp_wholesale_roles = WWP_Wholesale_Roles::getInstance();
$wwp_wholesale_role = $wwp_wholesale_roles->getUserWholesaleRole();
// Loop through the user role and shipping method pair
foreach( $role_shipping_method_arr as $role => $shipping_methods_to_hide ) {
// Check if defined role exist in current user role or not
if( in_array( $role, $current_user->roles) ) {
// Loop through all the shipping rates
foreach( $shipping_rates as $shipping_method_key => $shipping_method ) {
$shipping_id = $shipping_method->get_id();
// Unset the shipping method if found
if( in_array( $shipping_id, $shipping_methods_to_hide) ) {
unset($shipping_rates[$shipping_method_key]);
}
}
}
}
}
return $shipping_rates;
});
Any insights as to how to accomplish this would be greatly appreciated. Lyse what im trying to do is take a youtube embed code find the URL code for that video and remove all other parts of the code keeping only the URL of the video after i get the URL by it self then replace the http://www.youtube.com/ part of the URL with http://i2.ytimg.com/vi/ to do this i know that i need something like this to get the URL of the video http://www.youtube.com/((?:v|cp)/[A-Za-z0-9\-_=]+) but how to only return just the URL is something idk how to do then use str_replace http://www.youtube.com/(?:v|cp)/" with http://i2.ytimg.com/vi/ so in the end im asking if anyone know how to remove all other codes i dont want and only keep the URL this may have to be done using "regex" im not sure as i dont know to much about regex and what it can do but does sound like it would help lol i have to read a single line from a csv, its a really big file and i only need one column.
i need the response to be a string ,i made a search and found the following code but i dont have any idea how to get a single line from a single string per run .
<?php
$row = 1;
//open the file
if (($handle = fopen("file.csv", "r")) !== FALSE)
{
while (($data = fgetcsv($handle, 0, ",")) !== FALSE)
{
$num = count($data);
echo "<p> $num fields in line $row: <br /></p>\n";
$row++;
for ($c=0; $c < $num; $c++)
{
echo $data[$c] . "<br />\n";
}
}
fclose($handle);
}
?>
Edited by bores_escalovsk, 16 May 2014 - 06:38 PM. Dear All Good Day, i am new to PHP (a beautiful server side scripting language). i want to send a mail with line by line message i tried with different types like by placing the things in table and using <br /> but the thing is the tags are also visible in the message of the mail. Here is my code: $message1 = "Name :". $_REQUEST['name']."<br />"; $message1 .= "Surname :". $_REQUEST['surname']."<br />"; $message1 .= "Cellphone :". $_REQUEST['mobileno']."<br />"; $message1 .= "Telephone :". $_REQUEST['landno']."<br />"; $message1 .= "Fax :". $_REQUEST['fax']."<br />"; $message1 .= "Company :". $_REQUEST['company']."<br />"; $message1 .= "Email :". $_REQUEST['email']."<br />"; $message1 .= "Country :". $_REQUEST['country']."<br />"; $message1 .= "Enquity :". $_REQUEST['enquiry']."<br />"; $message1 .= "Date&Time :". $date."<br />"; For this code if try to print/echo it it is working fine it is displaying line by line, but using this variable ($message1) in the mail these <br /> are also visible. Can any one guide me to resolve(to remove these tags from the message part) this issue. Thanks in Advance. :confused: Hi. I want a simple textbox, that when submited, will replace very every new line, with the <br> tag. What will happen, when it submits, it will take the contents of a textbox, add the <br> tag where a new line is suposed to be, and save the string to a MySQL Database. I think this is the easiest way of allowing a user to edit what appears on a website when logged in, but if there is a easier way, then please tell me. What I am trying to do, is a login page, and once logged in, you enter new text into the textbox, click submit, and on the website homepage, the main text will change to what was submitted. But if there is a new line, I think the only way in HTML to make one is to put a <br> tag, so I want the PHP to but that tag wherever there is a new line. Sorry if I am confusing, I am not that advanced at PHP, but I would be very happy if you could supply me with the correct code. Time is running out... If you do not understand me, please tell me -- PHPLeader (not) How to get this echo line to display as one line? No matter what I have done it displays as two lines. I even tried <nobr></nobr> Teachers Name: John Jones $userid = mysql_real_escape_string($_GET['user_id']); $sql = "select * from users where `id`='$userid' "; $rs = mysql_query($sql); while($row = mysql_fetch_array($rs)) { echo "<h3>Teachers Name: </h3>" . $row["first_name"] . " " . $row["last_name"] ; } Thanks for your help. I have a script that reads a .gz file into an array and prints the name of each record but will not work on larger files. Is there a way to read 1 line at a time? Here is the code I have so far. Code: [Select] <?php if ($handle = opendir('.')) { print "<ol>"; while (false !== ($file = readdir($handle))) { if($file != '..' && $file!="." && $file!="start_update.php" && $file!="sharons_dbinfo.inc.php" && $file!="root.php" && $file!="read_directory.php" && $file!="read_dir.php" && $file!="new_category.php" && $file!="index.php" && $file!="file_count.php" && $file!="dir_loop2.php" && $file!="dir_loop1.php" && $file!=".htaccess" && $file!="Answer.txt" && $file!="Crucial_Technology-Crucial_US_Product_Catalog_Data_Feed.txt"){ $filename = $file; $go = filesize($filename); if($go >= 1){ $filename2 = explode("-", $filename); $filename2 = $filename2[0]; echo str_replace("_"," ",$filename2) . ' | Filesize is: ' . filesize($filename) . ' bytes<br>'; $gz = gzopen($filename, 'r'); $lines = gzfile($filename,10000); foreach ($lines as $line) { $line2 = explode(",", $line); $line2 = str_replace("," , "-" , $line2); echo "<li>".str_replace("," , "-" , $line2[4])."</li><br>"; } } } } closedir($handle); } ?> </ol> I have written some code to past information from one page to a diffrent page however all the variables are sent over but they are not writting to the database could anyone help me out please .... $ud_P_Id = $_POST['ud_P_Id']; $ud_LastName = $_POST['ud_LastName']; $ud_FirstName = $_POST['ud_FirstName']; $ud_GroupCode=$_POST['ud_GroupCode']; $ud_P_Unit1=$_POST['ud_P_Unit1']; $ud_P_Unit2=$_POST['ud_P_Unit2']; $ud_P_Unit3=$_POST['ud_P_Unit3']; $ud_P_Unit6=$_POST['ud_P_Unit6']; $ud_P_Unit14=$_POST['ud_P_Unit14']; $ud_P_Unit20=$_POST['ud_P_Unit20']; $ud_P_Unit27=$_POST['ud_P_Unit27']; $ud_P_Unit28=$_POST['ud_P_Unit28']; $ud_P_Unit42=$_POST['ud_P_Unit42']; $ud_P_Unit10=$_POST['ud_P_Unit10']; $ud_P_Unit11=$_POST['ud_P_Unit11']; $ud_P_Unit12=$_POST['ud_P_Unit12']; $ud_P_Unit13=$_POST['ud_P_Unit13']; $ud_P_Unit1454=$_POST['ud_P_Unit1454']; $ud_P_Unit15=$_POST['ud_P_Unit15']; $ud_P_Unit16=$_POST['ud_P_Unit16']; $ud_P_Unit17=$_POST['ud_P_Unit17']; $ud_P_Unit18=$_POST['ud_P_Unit18']; $con = mysql_connect('localhost', 'lccstude_progre', '********'); $db= "lccstude_pro"; if (! $con) die("Couldn't connect to MySQL"); mysql_select_db($db , $con) or die("Couldn't open $db: ".mysql_error()); mysql_query("UPDATE BTECL31113 SET FirstName='$ud_FirstName' , LastName='$ud_LastName' , GroupCode='$ud_GroupCode' , Unit1='$ud_P_Unit1' , Unit2='$ud_P_Unit2' , Unit3='$ud_P_Unit3' , Unit6='$ud_P_Unit6' , Unit14='$ud_P_Unit14' , Unit20='$ud_P_Unit20' , Unit27='$ud_P_Unit27' , Unit28='$ud_P_Unit28' , Unit42='$ud_P_Unit42' , Unit10='$ud_P_Unit10' , Unit11='$ud_P_Unit11' , Unit12='$ud_P_Unit12' , Unit13='$ud_P_Unit13' , Unit1454='$ud_P_Unit1454' , Unit15='$ud_P_Unit15' , Unit16= $ud_P_Unit16' , Unit17='$ud_P_Unit17' , Unit18='$ud_P_Unit18' WHERE P_Id='$ud_P_Id'"); echo "Record Updated"; mysql_close($con); Please any help would be great |
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